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The empirical formula can be found by dividing the molar mass of the compound by the molar mass of the empirical formula.

To find the molecular formula, you first need to determine the empirical formula, which represents the simplest whole number ratio of atoms in a compound. The empirical formula can be found by dividing the molar mass of the compound by the molar mass of the empirical formula.
Once you have the empirical formula, you can use the molar mass of the compound to determine the molecular formula. To do this, you divide the molar mass of the compound by the empirical formula mass, which gives you a number known as the "multiplying factor."
The multiplying factor represents the number of times the empirical formula must be multiplied to get the molecular formula. For example, if the multiplying factor is 2, then the molecular formula is twice the size of the empirical formula.
As for why the number 16 was used, it's possible that it represents the molar mass of a particular element or compound involved in the problem. Without more information about the specific problem you were working on, it's difficult to say for sure. However, it's important to note that the number used in the calculation is not a random variable, but rather a key component in determining the molecular formula.

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Explanation:

Review and Study Material Before Going to Class. ...

Take Good Notes. ...

Practice Daily. ...

Take Advantage of Lab Time. ...

Use Flashcards. ...

Use Study Groups. ...

Break Large Tasks Into Smaller Ones.

reading a variety of chemistry books

Answer:

An ion is an atom or molecule that carries an electric charge.

Ions are identified by the use of a superscript to show the sign and size of their electric charge.

Negatively charged ions are called anions, and positively charged ions are called cations.

Explanation:

An atom is the smallest unit of ordinary matter that forms a chemical element. Every solid, liquid, gas, and plasma is composed of neutral or ionized atoms. Atoms are extremely small, typically around 100 picometers across.

Answer:

Explanation:

Use context clues to write your own definition for each meaning of the word matter.

Example sentence

What is this gooey matter on the table?

Matter:

__________

Example sentence

Please vote! Your opinions matter.

Matter:

__________

When gases CO and H2 completely react to form CH3OH at STP, the volume of gas formed is 22.4 liters. Each mole of an ideal gas occupies 22.4 liters at STP, and the stoichiometry of the reaction indicates a 1:1 ratio.

To determine the volume of gas formed when gases are completely reacted at STP, we need to use the concept of stoichiometry. According to the balanced chemical equation:CO(g) + H2(g) → CH3OH(g)

The stoichiometry of the equation indicates that for every 1 mole of CO and 1 mole of H2, 1 mole of CH3OH is produced. At STP (Standard Temperature and Pressure), 1 mole of any ideal gas occupies 22.4 liters of volume. Therefore, the volume of gas formed when completely reacted at STP would be 22.4 liters.

In summary, when 1 mole of CO and 1 mole of H2 completely react to form 1 mole of CH3OH at STP, the volume of gas formed is 22.4 liters.

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Equilibrium: The pH of the mixture of 0.15 M HF and 0.15 M NaF is 2.96.

What is equilibrium?

In chemistry, equilibrium refers to a state in which a reversible chemical reaction appears to have stopped changing over time. This occurs when the rate of the forward reaction is equal to the rate of the reverse reaction, so that the concentrations of the reactants and products remain constant.

The solubility equilibrium for \($\text{Ag}_2\text{CrO}_4$\) can be represented as:
\(Ag_2CrO_4(s)\rightleftharpoons2Ag+(aq)+CrO_4^{2-}(aq)Ag_2CrO_ 4(s)\rightleftharpoons2Ag +(aq)+CrO_4^{2-}(aq)\)
The Ksp expression for this equilibrium is:
\(sp=[Ag^+]2[CrO_4^{2-}]K sp=[Ag + 2[CrO_4^{2-} ]\)
To bold the keywords in the main answer, you can use the \textbf command in LaTeX. Here's an example:
Therefore, the pH of the mixture of 0.15 M HF and 0.15 M NaF is:
\({pH = -log[H3O^+] = -log(1.1 \times 10^-3) = 2.96}\)

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Answer:

According to the equation below salt is produced by BaH2s

Answer:

I think b is the correct answer

Answer:19

Explanation:

Explanation:

They have to battle them dang hogs and get them burrows before them.

Answer:

2 waves

Explanation:

If Frank creates 20 waves every second then the way you solve is turn it into a proportion 20 waves/10 secs = x/1 sec which then turns into the equation of 10x=20 where x=2 hence Franks creates 2 waves every second.

Answer:

You can model a substance doing a Lewis structure

And also you can model it doing a bond-line structure.

hello

the answer to the question is C) tetrahedral

The volume of steam that could be produced at STP if 12.8 g of oxygen reacts with excess hydrogen is 17.92 L

We'll begin by obtaining the mole of steam produced. This can be obtained as follow:

2H₂ + O₂ -> 2H₂O

From the balanced equation above,

1 mole O₂ reacted to produce 2 moles of steam, H₂O

Therefore,

0.4 mole O₂ will react to produce = 0.4 × 2 = 0.8 mole of steam, H₂O

Finally, we shall determin the volume as follow:

At standard temperature and pressure (STP),

1 mole of H₂O = 22.4 L

Therefore,

0.8 moles of H₂O = (0.8 mole × 22.4 L) / 1 mole

0.8 moles of H₂O = 17.92 L

Thus, we can conclude that the volume produced is 17.92 L

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The only factor affecting the average kinetic energy of a group of gas particles is its temperature.

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0g  is the mass in grams of the excess reactant remain assuming the reaction goes to completion and that you start with 15.5.

The term "excess reactant" in chemical reactions describes a reactant that is present in a higher concentration than what is necessary for a complete reaction with the other reactants. This implies that even after the reaction has reached its end, some of the excess reactant will remain. Stoichiometry, or the study of the quantitative correlations between reactants and products, is closely related to the idea of an excess reactant in a process.

Molar mass of Na2S = 46.04 g/mol

Moles of Na2S = 15.5 g / 46.04 g/mol = 0.3362 mol

Molar mass of CuSO4 = 159.61 g/mol

Moles of CuSO4 = 12.1 g / 159.61 g/mol = 0.0759 mol

moles of Na2SO4 formed = 0.3362 mol

Molar mass of Na2SO4 = 142.04 g/mol

Grams of Na2SO4 formed = 0.3362 mol * 142.04 g/mol = 47.77 g

Excess reactant remaining in moles = 0.3362 mol - 0.3362 mol = 0 mol

Grams of the excess reactant remaining = 0 mol * 46.04 g/mol = 0 g

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Answer:

1.3155M

Explanation:

molar mass of CuSO4

=63.55+32.07+16(4)

=159.62g/mol

n=mass/molar mass

n=42.00/159.62

n=0.2631mol

volume=200mL=0.2L

molarity=mole (n)/volume (v)

molarity=0.2631mol/0.2L

molarity=1.3155M

Answer:

It will explode, I have plenty of research on this. Let me know if you want the sources. :)

Explanation:

Answer:

Explanation:

There will be no reaction when carbon tetrachloride is added to water.  This is because the two substances do not mix.  It is not due to density difference (like the case of Mercury and water) but rather carbon tetrachloride is non-polar while water is polar.  So they will separate and form two different layers with no reaction happening.

The third quantum number (m_l) of a 3s² electron in phosphorus is 0.

The third quantum number, denoted as m_l, represents the magnetic quantum number and describes the orientation of an orbital within a subshell. It can have integer values ranging from -l to +l, where l is the azimuthal quantum number.

In the electron configuration of phosphorus, we see that the 3s subshell is being filled. The azimuthal quantum number (l) for the 3s subshell is 0. Since the electron is in the 3s² subshell, there are two electrons present in the 3s orbital.

For the two electrons in the 3s orbital, they will have opposite spins due to the Pauli exclusion principle. However, the magnetic quantum number (m_l) for both electrons in the 3s orbital will be the same, which is 0.

Therefore, the third quantum number (m_l) of a 3s² electron in phosphorus is 0. This means that both electrons in the 3s orbital have the same orientation within the subshell.

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Answer:

oxidized. because oxidized number of Fe change from 0 to +3

The activity of the sample containing 3.37 x 10^14 iodine-131 nuclei is 2.92 x 10^13 Bq.

The activity of a sample is defined as the rate at which radioactive decay occurs within the sample. The unit of activity is the becquerel (Bq), which is equivalent to one decay per second.
To find the activity of a sample containing 3.37 x 10^14 iodine-131 nuclei, we need to use the following formula:
Activity = Decay Constant x Number of Nuclei
The decay constant (λ) for iodine-131 is calculated using its half-life (t1/2) as follows:
λ = ln 2 / t1/2
Substituting the values given in the question, we get:
λ = ln 2 / 8.0 days
λ = 0.0866 per day
Now, we can calculate the activity of the sample as follows:
Activity = 0.0866 per day x 3.37 x 10^14 nuclei
Activity = 2.92 x 10^13 Bq
Therefore, the activity of the sample containing 3.37 x 10^14 iodine-131 nuclei is 2.92 x 10^13 Bq.

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Answer:

List 4 functions of proteins.

1.Growth and Maintenance.

2.Balances Fluids.

3.Bolsters Immune Health.

4.Transports and Stores Nutrients.

The endpoint coordinates of the mid-segment of triangle JKL is (5.06, 4.04).

Given the triangle JKL in which mid-segment of triangle JKL is parallel to JL.

Now we need to find the endpoint coordinates of the mid-segment of triangle JKL.

Hence the midpoint of JK = M (3, 2.5) and the length of \(JK = JL/2= \sqrt{((5 - 1)^{2} + (4 - 1)^{2} )} / 2 = 4.12/2 = 2.06\)

Now we know the length of mid-segment JK = 2.06 and its midpoint, we can find the endpoint coordinates by using the slope formula

Endpoint of JK, K is(1, 3)

hence the coordinates are \((3 + 2.06, 2.5 + 1.54) = (5.06, 4.04)\)

Therefore, the endpoint coordinates of the mid-segment of triangle JKL is (5.06, 4.04).

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Answer:

The average velocity of the airplane for this trip is 1684.21 km/h

Explanation:

Average velocity is the rate of change of displacement with time. That is,

Average velocity = \(\frac{Displacement }{Change in time}\) = Δx / Δt = \(\frac{x2 - x1}{t2 - t1}\)

Now we will calculate the time taken by the airplane for the first motion before it encounters a wind.

From,

Velocity = \(\frac{Distance traveled}{Time taken}\)

Time = \(\frac{Distance traveled}{Velocity}\)

Therefore, Time = \(\frac{2100km }{1000km/h}\)

Time = 2.1h

This is the time taken before the airplane encounters a wind.

Hence, t1 = 2.1h

Now, For the time taken by the airplane when it encounters a wind

Also from,

Velocity = \(\frac{Distance traveled}{Time taken}\)

Time = \(\frac{Distance traveled}{Velocity}\)

Therefore, Time = \(\frac{1300km }{800km/h}\)

Time = 1.625h

Hence, t2 = 1.625h

Now, to calculate the average velocity

Average velocity = \(\frac{x2 - x1}{t2 - t1}\)

x1= 2100, x2= 1300, t1= 2.1h and t2= 1.625h

Hence, Average velocity = \(\frac{1300 - 2100}{1.625 - 2.1}\)

Average velocity = 1684.21 km/h

Answer:

The answer is on the image.

Hope it helps!

Answer:Lithium oxide is able to undergo both the processes of dissolution and dissociation.

Dissociation refers to the break down a chemical substance into its constituents. Ionization refers to the loss of electrons from a chemical specie while dissolving refers to the ability of a solid to form a solution.

Let us now look at each of the following species;

Lithium oxide undergoes dissolution and dissociation.

Magnesium nitride undergoes dissolution and dissociation.

Hydrobromic acid  undergoes dissolution and dissociation.

Explanation:

Answer:

the volume of a give gas simple is directly propotional assolute temperature at constant pressure .the volume of a gavi. amount of gass is inversely propotional ot Its pressure when temperature is help constant

An atom emits a photon with a wavelength of 260 nm, the atom’s energy change is 7.6 × 10^(-19) J.

The energy of photon is inversely proportional to the wave length and directly propositional the speed of light.

Mathematically, photon energy relationship can be given as

\(E = \frac{hc}{λ}\)

E= Energy of photon

h= Plank's constant = \(6.626\) × \(10^{-34}\)

c = 3 х \(10^{8} m/sec.\)

λ = \(260\) × \(10^{-9} m\)

\(E = \frac{hc}{λ}\)

\(E = 7.6\) × \(10^{-19} J\)

Thus, we find that the energy change is 7.6 × 10^(-19) J.

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The term "greenhouse" can refer to two different concepts: the physical structure known as a greenhouse and the greenhouse effect in the Earth's atmosphere.

Greenhouse gases are gases that trap heat in the Earth's atmosphere, contributing to the greenhouse effect and influencing the Earth's climate. They include:

1. Carbon Dioxide (CO2): This is the most significant greenhouse gas emitted by human activities. It is released through the burning of fossil fuels (such as coal, oil, and natural gas), deforestation, and other industrial processes.

2. Methane (CH4): Methane is produced by natural processes (such as wetlands and termites) as well as human activities such as agriculture (rice cultivation, livestock farming), fossil fuel production, and waste management (landfills).

3. Nitrous Oxide (N2O): Nitrous oxide is emitted through agricultural and industrial activities, including the use of synthetic fertilizers, fossil fuel combustion, and biomass burning.

4. Fluorinated Gases: This category includes hydrofluorocarbons (HFCs), perfluorocarbons (PFCs), and sulfur hexafluoride (SF6), which are synthetic gases used in various industrial applications, including refrigeration, air conditioning, and electronics.

These greenhouse gases trap heat radiated from the Earth's surface, preventing it from escaping into space and leading to a warming effect known as global warming.

Ice Age:

During the Ice Age, greenhouse gas concentrations were significantly lower compared to the present day. Unfortunately, specific measurements for carbon dioxide (CO2), methane (CH4), and nitrous oxide (N2O) concentrations during the Ice Age are not available.

1750:

In the 1750s, greenhouse gas concentrations were still relatively low, but human activities were starting to have an impact. Again, precise measurements for CO2, CH4, and N2O concentrations during this period are not available.

Today:

The current atmospheric CO2 concentration is over 410 parts per million (ppm). Methane concentrations have risen to over 1,800 parts per billion (ppb), and nitrous oxide concentrations have increased to over 330 ppb. These increased greenhouse gas concentrations have contributed to a warming effect on the Earth's climate. Global average temperatures have also risen compared to pre-industrial times, with an increase of about 1.1 degrees Celsius.

To obtain the most accurate and up-to-date information on greenhouse gas concentrations and temperature.

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Answer:

flourine

Explanation:

im not sure the answer

Answer:

-205.7 kJ

Explanation:

if ur a connexus kid i just took this too lol

Answer:

A (-205.7)

Explanation: