what characteristic of a star indicates whether a star is moving toward or away from the eart
Answers
Answer:
For example, if a star is moving toward us, its lines will be observed at shorter wavelengths, which is called "blueshifted". If the star is moving away from us, the lines will appear at longer wavelengths, which is called "redshifted".
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Related Questions
think critically the mendeleev and moseley periodic charts have gaps for undiscovered elements. why do you think the chart used by moseley was more accurate at predicting where new elements would be placed?
Answers
The chart used by moseley was more accurate at predicting where new elements would be placed, because Moseley's work chart based the atomic number which is definable property, measurable through experimentation not chemical properties or atomic mass as mendeleev do.
In his periodic table, Mendeleev left some notable gaps, such as the gaps just below aluminum and silicon, which covered elements as yet to be discovered. When these elements were later discovered, the properties of the new elements were found to match Mendeleev's predictions. The main difference between Mendeleev's and Moseley's arrangement of the elements on the periodic table is that Mendeleev arranged the elements in ascending order of atomic weight, whereas Moseley arranged them in ascending order of atomic number. Moseley diagrams were based on the use of atomic numbers rather than chemical properties of the elements. The similarity of products from the same period often caused problems when creating orders. Moseley's work made it possible to change atomic number from an arbitrary choice to a definable property that can be measured through experimentation.
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An excited hydrogen atom emits light with a wavelength of 397. 2 nm to reach the energy level for which n = 2. In which principal quantum level did the electron begin?.
Answers
The principal quantum level where the electron begin was 7
What is quantum level?Quantum levels can refer to energy levels, a bound particle can only take on certain discrete energy values called energy levels. Quantum domain, also known as quantum scale, is a physical term that refers to the scale at which quantum mechanical effects become significant.
To determine the principal quantum level, we would use the Rydberg equation:
\(\frac{1}{\lambda}\) \(= R(\frac{1}{n_{2} ^{2} } - \frac{1}{n_{1} ^{2} })\)
Given,
λ = Wavelength (397. 2 nm or × 10⁻⁹m)
n₁ = Initial transition
n₂ = Final transition (n = 2)
R = Rydberg constant (1.09 × 10⁷ m⁻¹)
Substitute the values in the above formula:
\(\frac{1}{ 397. 2* 10^{-9} }\) \(=1.09*10^{7} (\frac{1}^{6^{2} } } - \frac{1}{n_{1} ^{2} })\)
n₁ = 7.07
n₁ ≈ 7
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2. what percent of the original s2o82– in solution 1 should have been consumed after the fourth time interval? show your calculation or explain how you got the number.
Answers
87.56% is the percentage of the original s2o82– in solution 1 that should have been consumed after the fourth time interval.
The initial concentration of s2o82– in solution 1 was 0.025 M. The rate constant of the reaction at this temperature is 6.20 x 10-4 s-1. The reaction is first-order, hence the rate law can be represented by rate = k[s2o82–].To calculate the percentage of original s2o82– in solution 1 that should have been consumed after the fourth time interval, we will use the following formula:
t1/2 = ln(2)/k where t1/2 is the half-life of the reaction. Since the reaction is first-order, we can use the half-life formula to find out the concentration of s2o82– remaining after the fourth time interval.
half-life (t1/2) = ln(2)/k = ln(2)/6.20 x 10-4 s-1 = 1118.5 s
Converting 15 minutes to seconds: 15 minutes x 60 seconds/minute = 900 seconds
After four time intervals (4 x 900 seconds), the time elapsed is 3600 seconds. Hence, the fraction of s2o82– remaining is: fraction remaining = 1/2nwhere n is the number of half-lives. In this case, n is equal to 3600 seconds (the total time elapsed) divided by the half-life (1118.5 seconds), or n = 3.22 (rounded to two decimal places).fraction remaining = 1/2n = 1/23.22 = 0.1244
Consequently, the percentage of s2o82– consumed is: percent consumed = (1 - 0.1244) x 100% = 87.56%
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Before performing the titration of your unknown acid, your partner accidentally dilutes the sample by adding water. Consider how this error would effect the following aspects of the titration curve.1. How would this error effect the volume of base necessary to reach the equivalence point?Would it increase the volume necessary, would there would be no effect OR would it decrease the volume necessary?2. How would this error effect the pH at the half-equivalence point?Would the pH be higher, lower, or the same?3. How would this error effect the pH at the equivalence point?Would the pH be higher, lower, or the same?
Answers
Before performing the titration of the unknown acid, if the partner accidentally dilutes the sample by adding water, it would affect the following aspects of the titration curve:
1. The volume of base necessary to reach the equivalence point will remain unaffected.
2. It would not have any effect on the pH at the half-equivalence point.
3. It would decrease the pH at the equivalence point.
Titration is a process in which a solution of known concentration (the titrant) is added to a solution of unknown concentration (the analyte) until the reaction between them is complete. When this reaction is complete, it is known as the equivalence point, and it is indicated by the titration curve.
The accidental dilution of the unknown acid by adding water to it before titration would affect only the pH at the equivalence point. Here's how:
Effect on volume of base used: The volume of base required to reach the equivalence point remain unaffected or unchanged as volume of base depends upon number of moles of acid. Here, dilution doesn't affects the number of moles, it is affecting the concentration of solution. That's why it doesn't matter that how much diluted a sample is, the thing matters is the number of moles of acid which are not changing.
Effect on pH at the half-equivalence point: It would not have any effect on the pH at the half-equivalence point. The pH at the half-equivalence point depends only on the dissociation constant (Ka) of the acid. It is also not affected by concentration of acid.
Effect on pH at the equivalence point: As the sample is diluted by adding water, the concentration of the acid decreases, and the amount of H+ ions released by it also decreases. Therefore, it would require fewer hydroxide ions (OH-) to neutralize the acid, which means that the pH of the equivalence point would decrease.
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A helium balloon has a volume of 2600 cm 3 when the temperature is 21°C. What is the
volume of the balloon when it's placed in a freezer with a temperature of -15°C?
Answers
Answer:
2,282 cm³
Explanation:
If all other variables are being held constant, you can find the new volume of the balloon using the Charles' Law equation. The equation looks like this:
V₁ / T₁ = V₂ / T₂
In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. Before you can solve for the new volume, you need to convert Celsius to Kelvin (negative values do not work in this equation). This can be done by adding 273.15 to each temperature.
V₁ = 2600 cm³ V₂ = ? cm³
T₁ = 21 °C + 273.15 = 294.15 K T₂ = -15 °C + 273.15 = 258.15 K
V₁ / T₁ = V₂ / T₂ <----- Charles' Law
(2600 cm³) / (294.15 K) = V₂ / (258.15 K) <----- Insert values
8.839 = V₂ / (258.15 K) <----- Simplify left side
2282 = V₂ <----- Multiply both sides by 258.15
13. The equation used to find acceleration is a =
1. vf- vilt
b. v/t
a.
C. Vi - vlt
d. vit vflt
Answers
Acceleration represented by the equation = Δv/Δt.
Which water sample (A, B or local sample) was more acidic to begin with.
what is your reasoning?
Answers
Answer:
B
Explanation:
Sample B takes more drops for both P- and T-alkalinity tests to reach pH 8.3 and 4.5. So it is more acidic to begin with.
pH is equal for all three.
Now look at the drops amount
21<52<25Higher the drops lower the solubility or its less acidic.
So sample A is most acidic then local then sample B
Mercury poisoning is a debilitating disease that is often fatal. In the human body, mercury reacts with essential enzymes leading to irreversible inactivity of these enzymes. If the amount of mercury in a polluted lake is 0.4 Hg/mL, what is the total mass in kilograms of mercury in the lake
Answers
Answer:
The total mass of mercury in the lake is 631,542.7 kg
Explanation:
Question: The given dimensions of the lake as obtained from a similar question posted online are;
The surface area of the lake, A = 100 mi²
The lake's average depth, d = 20 ft.
The concentration of the mercury, C = 0.4 μg Hg/mL = 0.4 × 10⁻⁶ kg Hg/L
Therefore, we have;
The volume of water mixture in the lake, V = A × d
∴ V = 100 mi² × 20 ft. = 2,787,840,000 ft.² × 20 ft. = 55,756,800,000 ft.³
1 ft³ = 28.31685 L
∴ 55,756,800,000 ft.³ = 55,756,800,000 ft.³ × 28.31685 L/ft.³ = 1.57885675 × 10¹² L
The total mass of mercury in the lake, m = C × V
∴ m = 0.4 × 10⁻⁶ kg Hg/L × 1.57885675 × 10¹² L = 631,542.7 kg
The total mass of mercury in the lake, m = 631,542.7 kg.
Helpppppp please helpppp helpppp
Answers
Compound X has the formula C8H16. X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form 2,5-dimethylhexane. Treatment of X with ozone follwed by zinc in aqueous acid gives a single product which is an aldehyde. What is the structure of X
Answers
X is 2,4,4-trimethylpentane, also known as isopentane. It is an isomer of pentane, which contains a methyl group on each of the three carbon atoms of the middle carbon atom in the molecule.
What is trimethylpentane?Trimethylpentane is an alkane hydrocarbon with the chemical formula C9H20. It is an isomer of pentane and has three methyl groups attached to the main chain of hydrocarbons. It is a colorless liquid with a pungent odor that is insoluble in water and has a boiling point of 131.5 °C. The compound is flammable and is sometimes used as a fuel for small engines. Trimethylpentane is hazardous to the environment and should be handled with caution.
When 2,4,4-trimethylpentane reacts with hydrogen in the presence of a palladium catalyst, it undergoes a hydrogenation reaction, which adds two hydrogen atoms to the molecule, resulting in 2,5-dimethylhexane (C₈H₁₈).
When 2,4,4-trimethylpentane is treated with ozone followed by zinc in aqueous acid, it undergoes an ozonolysis reaction, which cleaves the double bond and forms an aldehyde. The aldehyde product is 2,3-dimethylbutanal (C₅H₁₀O).
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What pressure must be applied to a sample of Neon gas having a volume of 325cm3 at 20 degree Celsius and 723mmHg to permit the expansion of the gas to a volume of 975cm3 at the same temperature
Answers
To solve this problem, we can use the combined gas law equation: P₁V₁/T₁ = P₂V₂/T₂
Where P₁, V₁, and T₁ are the initial pressure, volume, and temperature, and P₂, V₂, and T₂ are the final pressure, volume, and temperature. We are given V₁ = 325 cm³, T₁ = 20°C = 293 K, P₁ = 723 mmHg, and V₂ = 975 cm³ at the same temperature T₂ = 293 K. We need to find P₂. First, we need to convert the initial pressure from mmHg to atm: P₁ = 723 mmHg × 1 atm/760 mmHg = 0.9513 atm. Now we can plug in the values and solve for P₂: P₁V₁/T₁ = P₂V₂/T₂. 0.9513 atm × 325 cm³/293 K = P₂ × 975 cm³/293 K. P₂ = 0.9513 atm × 325 cm³ × 293 K / (975 cm³ × 293 K). P₂ = 0.3164 atm. Therefore, the pressure that must be applied to the neon gas to permit its expansion to a volume of 975 cm³ is approximately 0.3164 atm.
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A chemist dissolves of pure hydrochloric acid in enough water to make up of solution. Calculate the pH of the solution. Round your answer to significant decimal places.
Answers
The pH of the solution is 1.38.
Mass of HCl = 614 mg = 0.614 g
Moles of HCl = 0.614g / 36.5 gmol⁻¹
Concentration of HCl :
Concentration= moles/volume of solution in liters
On adding 0.01682 moles to 400 mL of water that 0.4 L of water.
[HCl]=0.01682 mol/0.4 L= 0.04205 M
HCl (s) + H₂O (l) → H₃O⁺ (aq) +Cl⁻
1 mole of HCl gives 1 mole of hydronium ion and 1 mole of chloride ions in an aqueous solution.
Then 0.04205 mol/L of HCl will give:
1x0.04205 M= 0.04205 mol/L of hydronium ions.
[H₃O⁺]= 0.04205 M
pH= -log[H₃O⁺]
pH= -log[0.04205 M]
= 1.38
The pH of the solution is 1.38.
The complete question is- A chemist dissolves 614. mg of pure hydrochloric acid in enough water to make up 400 mL of solution. Calculate the pH of the solution. Round your answer to 3 significant decimal places. X 5 ?
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Name the property of salt investigated in the above experiment
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which experiment please involve a clip
A cheetah can run 68-75 miles per hour! Would this be considered an instantaneous speed, a
constant speed, or an average speed? Explain.
Answers
Answer:
This would be considered an average speed, as it's an estimate of how fast the cheetah can run over a certain distance, taking into account variations in its speed. It's not instantaneous, which would refer to the speed at a specific moment, and it's not constant, which would refer to the same speed being maintained over a period of time.
Calculate the ph of this solution. round to the nearest hundredth. poh = 3.45 ph =
Answers
The potential of hydrogen pH of the solution with the given value of pOH to the nearest hundredth is 10.55.
What is pH of solution?
The pH of a solution is defined as the logarithm of the reciprocal of the hydrogen ion concentration [H+] of the given solution.
It is expressed as;
pH = -log[ H⁺ ]
Also,
pH + pOH = 14
Given that;
pOH = 3.45pH = ?We simply substitute our values into the expression above.
pH + pOH = 14
pH + 3.45 = 14
pH = 14 - 3.45
pH = 10.55
Therefore, the potential of hydrogen pH of the solution with the given value of pOH to the nearest hundredth is 10.55.
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Answer:
10.55
Explanation:
pH = 10.55
Hi guys . I'm having some troubles with physics and chemistry .
Do you know any sites or apps that can help me with any topic in physics and chemistry ( apart from Khan academy ) ?
Note : The site or app has to be able to teach and explain topics in Physics and Chemistry .
Answers
Explanation:
byju's ig. Cause it gives a proper concept
5) Given that the density of CO2 at the temperatures we used is 1.25 g/L, calculate the theoretical
and actual yield (based on the amount of sodium acetate produced!) for CO2, in liters, for the
experiment.
+ Hco
на
6) How many grams of sodium hydrogen carbonate would be necessary to produce 425 mL of CO₂?.
Use the density of CO2 from #5 and show your calculations.
Answers
1.596 grams of sodium hydrogen carbonate would be necessary to produce 425 mL of \(CO_{2}\) at STP.
To calculate the amount of sodium hydrogen carbonate needed to produce 425 mL of \(CO_{2}\), you can use the following steps:
Convert the volume of \(CO_{2}\) to moles using the molar volume at STP:
425 mL ÷ 1000 mL/L = 0.425 L \(CO_{2}\)
0.425 L \(CO_{2}\) ÷ 22.4 L/mol = 0.019 moles \(CO_{2}\)
Use the balanced chemical equation to determine the stoichiometry between sodium acetate and carbon di oxide:
\(NaC_{2} H_{3} O_{2}\) \(+ H_{2} O + CO_{2}\) → \(Na HC_{3} O_{2}\)\(+ CH_{3} COOH\)
For every 1 mole of sodium acetate, 1 mole of CO2 is produced. Therefore,
0.019 moles CO2 = 0.019 moles \(NaC_{2} H_{3} O_{2}\)
Calculate the mass of sodium hydrogen carbonate needed using its molar mass:
0.019 moles \(NaC_{2} H_{3} O_{2}\) × 84.01 g/mol = 1.596 g \(Na HC_{3} O_{2}\)
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HELLO EVERYONE PLEASE I NEED HELP WITH
Please I REALLY NEED A HELP WITH THIS PLEASE HELP ME
THIS HARRY POTTER LITERARY ESSAY
OUTLINE
1. Love and Friendship is a central theme in Harry Potter and the Philosopher's Stone. Prove that this statement is true using 2(two) different characters from the novel as examples.
Introductory Statement/ Hook:
Statement of Intent: reason A and B :
thesis reason A and B:
BODY PARAGRAPH
#1 Point #1: Introduce REASON A here, but use general statement
#1: Provide quotations from the novel to support Reason A
Explanation #1:
Proof #2:
Explanation #2:
BODY PARAGRAPH
#2 Point #2: Introduce REASON B here, but use general statements
#1: Provide quotations from the novel to support ReasonB
Explanation #1:
Proof #2:
Explanation #2:
CONCLUSION
Restate/ Summarize Thesis:
Restate/ Summarize Points:
Answers
Answer:
Ron and Hermoine
Explanation:
They always fought over petty things, but at the end, they did end up together!
(Answer for your question about love and friendship being a central theme in Harry Potter and the Philosopher's stone)
*ALSO, MY ANSWER MIGHT BE WRONG* so be sure to use a pencil just in case!
Argon (Ar): (Ne) 3s2 3p6
O longhand notation
O noble-gas notation
Answers
Answer:
It is Noble-gas notation
Explanation:
Just did it on Edgenuity 2020
Two or more than two atoms with different physical or chemical properties can not combine together to form an element. Therefore, the given electronic configuration represents noble-gas notation.
What is element?Element generally consist of atoms or we can atoms combine to form element. Atoms of an element is always same, means all the properties of all atoms of one type of element is same.
The systematic distribution of electrons in the various atomic orbitals is called its electronic configuration. The atomic number of argon is 18. The electronic configuration of argon is (Ne) 3s² 3p⁶. 1,2,3 represents the number of shells and s and represents the orbitals. The superscripts represents the number of electrons in each orbitals. The given electronic configuration represents noble-gas notation.
Therefore, the given electronic configuration represents noble-gas notation.
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TNT is manufactured by the reaction of toluene with nitric acid according to the following equation: C7H8 (l) + 3 HNO3 (aq) ---> C7H5(NO2)3 (s) + 3 H2O(l)
Calculate the mass of TNT expected from the reaction of 69.0 g of toluene
Answers
Answer:
170. g C₇H₅(NO₂)₃
General Formulas and Concepts:
Chemistry - Stoichiometry
Reading a Periodic TableUsing Dimensional AnalysisExplanation:
Step 1: Define
RxN: C₇H₈ (l) + 3HNO₃ (aq) → C₇H₅(NO₂)₃ (s) + 3H₂O (l)
Given: 69.0 g C₇H₈ (Toluene)
Step 2: Identify Conversions
Molar Mass of C - 12.01 g/mol
Molar Mass of H - 1.01 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of C₇H₈ - 7(12.01) + 8(1.01) = 92.15 g/mol
Molar Mass of C₇H₅(NO₂)₃ - 7(12.01) + 5(1.01) + 3(14.01) + 6(16.00) = 227.15 g/mol
Step 3: Stoichiometry
\(69.0 \ g \ C_7H_8(\frac{1 \ mol \ C_7H_8}{92.15 \ g \ C_7H_8} )(\frac{1 \ mol \ C_7H_5(NO_2)_3}{1 \ mol \ C_7H_8} )(\frac{227.15 \ g \ C_7H_5(NO_2)_3}{1 \ mol \ C_7H_5(NO_2)_3} )\) = 170.085 g C₇H₅(NO₂)₃
Step 4: Check
We are given 3 sig figs. Follow sig fig rules and round.
170.085 g C₇H₅(NO₂)₃ ≈ 170. g C₇H₅(NO₂)₃
Can you store cuso4 in an aluminum container? explain your reasoning
Answers
We can store the copper sulphate solution in alumiun container, if cover on alumiun is present.
Can you store cuso4 in an aluminum container?Aluminium is more reactive than copper so the Aluminium will displace copper sulphate from its solution by reacting with it but if there is cover on the aluminium then the alumium can't react with copper.
So we can store the copper sulphate solution in alumiun container.
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No, we cannot store CuSO₄ in an aluminum container because aluminum will displace the copper present in the solution.
Why do different chemicals require different containers?Different chemicals are put in different containers, usually glass, plastic, dark container, or light container.
Chemicals element are reactive to different substances and to each other.
That's why they are put in separate and different types of containers according to their reactivity.
Thus, No, we cannot store CuSO₄ in an aluminum container because aluminum will displace the copper present in the solution.
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]
Consider the following intermediate chemical equations.
C(s) +
CO(g) +
O₂(g) → CO(g)
How will oxygen appear in the final chemical equation?
O O2(g) as a product
O O2(g) as a reactant
OO(g) as a product
O 20(g) as a reactant
O₂(g) → CO₂(g)
Answers
In the above intermediate chemical equation, oxygen will appear as follows: O₂(g) as a reactant (option B).
What is a chemical equation?A chemical equation in chemistry is a symbolic representation of a chemical reaction where reactants are represented on the left, and products on the right.
According to this question, an intermediate chemical equation is presented as follows:
CO(g) + O₂(g) → CO(g)C(s) + O₂(g) → CO₂(g)As observed in the above chemical equation, oxygen will react in its gaseous form i.e. as a reactant.
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How many moles of nacl are required to make 500. 0 ml of a 0. 1 m solution of nacl?.
Answers
Answer:
Therefore 500 ml of solution have 0.25 mol of NaCl .. = 14.61 g (ans.)
Explanation:
Para el elemento de Z-56 b, que formula minima tiene el compuesto que forma con 17-cl¿ c, que tipo de union hay en dicho compuesto¿ d, cual es la estructura de lewis del compuesto formado¿
Answers
Answer:
ver explicacion
Explanation:
El elemento que tiene el número atómico 56 en la tabla periódica del bario. El bario es un elemento del grupo dos.
Se combina con el cloro para formar cloruro de bario. que tiene la fórmula BaCl2 de acuerdo con la valencia de ambos elementos.
El cloruro de bario es un compuesto iónico.
Which is more highly regioselective, reaction of an alkene with BH3 or with 9-BBN?
A. the reaction of an alkene with BH3
B. the reaction of an alkene with 9-BBN
Answers
The reaction of an alkene with BH3 is generally more highly regioselective than the reaction with 9-BBN. BH3 typically adds to the least hindered carbon atom of the alkene, which results in the formation of an intermediate that is highly selective towards the anti-Markovnikov product.
This is due to the electron-deficient nature of boron, which favors the attack of the nucleophile at the less substituted carbon atom. On the other hand, 9-BBN can add to both the more and less hindered carbon atom of the alkene, resulting in the formation of both Markovnikov and anti-Markovnikov products. Therefore, BH3 is a more preferred reagent for regioselective reactions.
B. The reaction of an alkene with 9-BBN is more highly regioselective. Both BH3 (borane) and 9-BBN (9-borabicyclo[3.3.1]nonane) are used for hydroboration of alkenes, which involves the addition of a boron-hydrogen bond across a carbon-carbon double bond. However, 9-BBN offers greater steric hindrance and enhanced regioselectivity compared to BH3. This is because the bulky bicyclic structure of 9-BBN leads to a more selective addition of the boron to the less substituted carbon of the alkene, resulting in a more predictable and controlled outcome in the formation of the final product.
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the output of glycolysis is pyruvate, but the citric acid cycle uses acetyl coa. briefly explain how glycolysis and the citric acid cycle are linked.
Answers
The output of glycolysis is pyruvate, but the citric acid cycle uses acetyl CoA. Briefly glycolysis and the citric acid cycle are linked to the results of glycolysis, namely pyruvic acid is converted to acetyl Co-A for the raw material of the citric acid cycle.
Cellular respiration is a complex organic breakdown process at the cellular level that aims to produce ATP that occurs in the mitochondrial matrix. ATP is the energy used by cells to meet their needs in order to carry out various activities. The first stage of cellular respiration is glycolysis. Glycolysis is an energy-releasing reaction that breaks one molecule of glucose into two molecules of pyruvic acid, a NADH and 2 ATP.
The citric acid cycle is a cycle that occurs after glycolysis. In glycolysis, pyruvic acid is produced which is then converted to acetyl Co-A during oxidative decarboxylation. then acetyl co-A is used as raw material for the citric acid cycle to produce 2 ATP, 6 NADH, 2 FADH2, and 4 CO2.
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A tank contains 1500 L of argon gas. The pressure is 11690 kPa and the temperature is 35ºC. How many moles of
argon are in the tank?
Show your work
Answers
Answer: 6,847.7 moles of Argon Gas
Explanation:
For this question, you need to use the Ideal Gas Equation (PV = nRT).
P is pressure (commonly in kPa or atm)V is volume occupied by the gas (in L)n is the number of moles, aka what we're trying to find here.R is the Ideal gas constant (8.314 (kPa*L)/(mol*K), or 0.0821 (atm*L)/(mol*K)T is the temperature (in Kelvins (K). In order to convert from Celsius to Kelvin, just add 273.)We can rearrange this equation to calculate the number of moles:
n = PV/RT
Then, we can plug in the values (Caution: we have to use 8.314 for our Ideal gas constant since P is in kPa for this question)
...and we have our answer! 6,847.7 moles of Argon Gas.
Also, make sure to adjust to significant figures!
Answer:
6843.99 mol (2 d.p.)
Explanation:
To calculate the number of moles of argon in the tank, we can use the Ideal Gas Law.
Ideal Gas Law\(\boxed{PV=nRT}\)
where:
P is the pressure measured in kilopascals (kPa).V is the volume measured in liters (L).n is the number of moles.R is the ideal gas constant (8.31446261815324 kPa L mol⁻¹ K⁻¹).T is the temperature measured in kelvin (K).First convert the given temperature from Celsius to kelvin by adding 273.15:
\(\implies \sf T=35+273.15=308.15\;K\)
Therefore, the values to substitute into the equation are:
P = 11690 kPaV = 1500 LR = 8.31446261815324 kPa L mol⁻¹ K⁻¹T = 308.15 KRearrange the formula to isolate n:
\(\implies n=\dfrac{PV}{RT}\)
Substitute the values into the formula and solve for n:
\(\implies n=\dfrac{11690 \cdot 1500}{8.3144626... \cdot 308.15}\)
\(\implies n=\dfrac{17535000}{2562.10165...}\)
\(\implies n=6843.99073...\)
\(\implies n=6843.99\; \sf mol\;(2\;d.p.)\)
Therefore, there are 6843.99 moles of argon in the tank (to two decimal places).
Jocelyn and her friends put some raisins, hazelnuts,
almonds, and peanuts in a bowl to make a snack for their
hiking trip. What does this snack represent?
A. a solution
B. a new element
C. a new compound
D. a mixture
plspslsspslpsl help its revision for exam and i need it quick brainliest for the right answer :D
Answers
Answer: D. a mixture
Explanation: When you mix different types of nuts or snacks together including raisins, hazelnuts, almonds, and peanuts to make some kind of trail mix, then you are creating a mixture, specifically a heterogeneous mixture.
Which area is most likely to support a marsh ecosystem?.
Answers
Answer:
A location that is humid, would most likely support a marsh ecosystem.
Explanation:
The Florida Everglades are an example of a marsh :)
"Marshes are a type of wetland ecosystem where water covers the ground for long periods of time. Marshes are dominated by herbaceous plants, such as grasses, reeds, and sedges."
which of the given purposes is the tlc method most often used for?
Answers
Thin layer chromatography (TLC) is an affinity derived approach that works to separate compounds in a mixture. TLC is deeply versatile separation method used for both qualitative and quantitative sample analysis.
In general, Thin layer chromatography is performed by using a thin, uniform layer of silica gel or alumina coated onto a piece of glass, metal or rigid plastic. These silica gel is present in stationary phase. There are three most important industrial applications that thin layer chromatography has are clinical, pharmaceutical, and food testing approaches. One of the most common specific types of clinical tests performed with TLC is for the presence of drugs of abuse.
To learn more about Thin layer chromatography , here
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