What causes the release of calcium from the terminal cisternae?.

Answer:

28.01 percent

Explanation:

Iron (III) sulphate, \(Fe_2(SO_4)_3\), has 2 atoms of Fe.

One atom of Fe has a molar weight of 56. Hence, 2 atoms of Fe would have a total molar weight of 56 x 2 = 112 g/mol

Molar weight of  \(Fe_2(SO_4)_3\) = 399.88 g/mol

Percentage Fe in \(Fe_2(SO_4)_3\) = 112/399.88 x 100%

                       = 28.01%

The percentage of iron is iron (III) sulphate is, therefore, 28.01 percent.

To make an E9 mixture 8657.14 gal of E7 should be mixed with 3000 gal of E10

Given to us is the amount of ethanol in the E10 mixture is 10% of 3000 gallons:

Ethanol in E10 = 10% × 3000 gal = 0.10 × 3000 gal = 300 gal

To solve this problem, we can set up an equation based on the amount of ethanol in each mixture.

Let x represent the amount of E7 mixture (in gallons) that needs to be added to the E10 mixture to obtain the desired E9 mixture.

The amount of ethanol in the E7 mixture is 7% of x gallons:

Ethanol in E7 = 7% ×  gal = 0.07 × gal

The resulting E9 mixture will contain 9% ethanol of the total volume of 3000 + x gallons:

Ethanol in E9 = 9% × (3000 + x) gal = 0.09 × (3000 + x) gal

According to the problem, the resulting E9 mixture contains 906 gallons of ethanol:

Ethanol in E9 = 906 gal

Now we can set up the equation:

Ethanol in E10 + Ethanol in E7 = Ethanol in E9

300 gal + 0.07x gal = 906 gal

Subtracting 300 gal from both sides:

0.07x gal = 606 gal

Dividing both sides by 0.07:

x = 606 gal / 0.07

x = 8657.14

Therefore, approximately 8657.14 gallons of E7 mixture should be mixed with 3000 gallons of E10 to make an E9 mixture.

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Complete question: Ethanol fuel mixtures have "E" numbers that indicate the percentage of ethanol in the mixture by volume. For example, E10 is a mixture of 10% ethanol and 90% gasoline. How much E7 should be mixed with 3000 gal of E10 to make an E9 mixture?

The first two chemical equations are reversible while the other two are irreversible.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

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The Michael addition product is formed by the addition of the enamine to propenal, and the final product after hydrolysis of the enamine is a ketone resulting from the cleavage of the carbon-nitrogen bond.

Steps in enamine formation?

Enamine formation: The enamine is formed by the condensation of cyclohexanone with dimethylamine. The specific structure of the enamine would depend on the reaction conditions and stereochemistry.

Michael addition product: The Michael addition involves the nucleophilic addition of the enamine to the carbon-carbon double bond of propenal. The product will be a compound formed by the addition of the enamine to the propenal molecule.

Final product (after hydrolysis): Upon hydrolysis of the enamine, the carbon-nitrogen bond is broken, and a new carbon-oxygen bond is formed. The final product will be the ketone resulting from the hydrolysis of the enamine, typically with a functional group originating from the propenal molecule.

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The enol carbon or ∝-carbon  nucleophile attacks at molecular bromine in the acid-catalyzed α-bromination of a ketone

Treatment of ketones with bromine in the presence of acid will results in formation of a new C-Br bond at the alpha position. The purpose of the acid  is to catalysed formation of the enol from ketone , which is active nucleophile in the reaction. This reaction is called haloform reaction which is used to identify the methyl substituted ketone in the presence of aldehyde.

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The solubility product of the copper(II) iodate is 1.25 * 10^-7

The term solubility has to do with the amount of a substance that is dissolved in water. The solubility product is the equilibrium constant that shows the extent to which a substance is dissolved in water.

We have to convert the solubility of the  copper(II) iodate from g/mL to molarity and we have;

Number of moles = 0.13 g/413 g/mol = 3.15 * 10^-4 moles

Volume of the solution = 100 mL or 0.1 L

Molarity =  3.15 * 10^-4 moles/0.1 L

= 3.15 * 10^-3 M

We now have;

Ksp = [x] [2x]^2

Ksp = 4x^3

Ksp = 4( 3.15 * 10^-3 )^3

Ksp = 1.25 * 10^-7

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the colligative molality of seawater is approximately 1.10 m, the vapor pressure of sea water at 20 °c is 16.412 torr, the vapor pressure of pure water at 20 °c is 17.54 torr.

Vapour pressure rises with temperature and is a measurement of a substance's propensity to transform into a gaseous or vapour state. The boiling point of a liquid is the temperature at which the pressure imposed by its surroundings equals the vapour pressure present at the liquid's surface. A liquid's thermodynamic propensity to evaporate is indicated by the equilibrium vapour pressure.

Given that-

Vapor  pressure of pure water (P₀) = 17.54 torr

Molality (m) = 1.10 m

Let, vapour pressure of sea water = P

As we know,

m = [(P₀ - P) / P₀] × (1000 / M(solute))

1.10 = [(17.54 - P) / 17.54] × (1000 / 58.44)

P = 16.412 torr    [considering NaCl in sea water]

Hence, vapour pressure of sea-water is: 16.412 torr

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During the research, the scientists collect the details and observations based on the information called data. Thus, option A is accurate.

A data is set of facts and observations including textual information, graphs, images, etc. It includes all the measurements and observations collected during the research work. The hypothesis is a thesis statement or a theory.

Observation in research is the gained information and facts during the research process that involves the recording of the data using some sort of tools. While variable is the set that can vary or change.

Therefore, the correct option is A. data.

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The most commonly used water disinfectant in the United States is:d. Chlorine

Chlorine is widely used as it is effective in eliminating harmful microorganisms, and it helps maintain water quality throughout the distribution system.Chlorine is the most commonly used water disinfectant in the United States. It is used to kill bacteria and other waterborne pathogens in public water supplies. Chlorine is typically added to water in the form of chlorine gas or a liquid solution of sodium hypochlorite. It is also used in some swimming pools and other recreational water facilities.

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Answer:

Since it has 2 valence electrons

Explanation:

The amount of energy that is required each year for the purpose of agriculture is only about 10%.

Energy is a very important part of civilization. In the current time, energy is necessary for all kinds of productions and agriculture is not an exception.

As such, the amount of energy that is required each year for the purpose of agriculture is only about 10%.

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Answer:

The right alternative is Option D (0.78 V).

Explanation:

According to the question,

The cell potential will be:

= \(E^0_{Cr_2 O_7/er^{3+}}- E^0_{Fe^{2+}/Fe}\)

By putting the values, we get

= \(1.23-0.45\)

= \(0.78 \ V\)

Thus the above is the correct option.

Answer:

D is the correct answer acidity

Explanation:

pH is the logarithmic measurement of the H3O+-concentration in water solutions.

By definition: pH = -log[H3O+]

Example: [H3O+] = 1.0*10-7 mol/L in neutral, pure water (at 25oC), so

pH = -log(H3O+) = -log(1.0*10-7) = 7.0

Answer:

grasslands ia the answer!

Answer:

133.333333333 cm^3

Explanation:

Volume = Mass/Density

Answer:

1+

Explanation:

Hope this helped!

Methanotrophs oxidize only methane completely, while methylotrophs can oxidize any compound containing a methyl group.

Methanotrophs and methylotrophs are two kinds of microorganisms that are equipped for oxidizing various sorts of mixtures.

Methylotrophs can oxidize any compound containing a methyl bunch, including methane. Interestingly, methanotrophs are a subset of methylotrophs that are explicitly adjusted to oxidize methane as their only wellspring of carbon and energy. Methanotrophs can totally oxidize methane to carbon dioxide, while methylotrophs can somewhat oxidize methane to carbon dioxide.

Methanotrophs can't oxidize different mixtures containing a methyl bunch, while methylotrophs can oxidize a more extensive scope of methyl-containing compounds. This is on the grounds that methylotrophs have a more different arrangement of chemicals that can oxidize different methyl-containing compounds. Methanotrophs, then again, have a particular arrangement of catalysts that are adjusted explicitly for the oxidation of methane.

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Answer:3 oxygen atoms.

Explanation: Each formula unit of Fe2O3 contains 2 atoms of iron and 3 atoms of oxygen (technically they are ions, but that doesn't matter).

The pH at 25^oC of a 0.19 M  solution of potassium butanoate (KC, H,CO approximately 2.96.

Given that potassium butanoate, KC, H, CO, is a weak acid with pKa of 4.82 and a solution of 0.19 M concentration is provided, we can calculate the pH at 25°C as follows:

\(Kw = Ka × Kb\)

Kb = Kw/Ka

Where, Kw = 10^-14 (at 25°C)

Ka = 10^-pKa

We have the pKa value of potassium butanoate as 4.82.

∴ Ka = 10^-4.82

= 1.35 × 10^-5mol/L

Now, Kb = Kw/Ka

= 10^-14/1.35 × 10^-5

= 7.41 × 10^-10M

At 25°C, we can calculate the concentration of H+ ions by using the expression given below:

Ka = [H+] × [A-] / [HA]

[H+] = Ka × [HA] / [A-]

= (1.35 × 10^-5) × √0.19 / 0.19

= 1.1 × 10^-3M

Thus, pH = -log[H+]= -log(1.1 × 10^-3)≈ 2.96

Hence, the pH of 0.19 M potassium butanoate solution at 25°C is approximately 2.96.

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Answer:

than what can i do lol

Answer: what is the size of the object

Explanation: then again though, i wouldn't carry something in my backpack that didn't taste good...

Answer:

Infrared waves have frequencies lower than red visible light.

:)

Answer:

d = 3 g/cm³

Explanation:

Given data:

Mass of stone = 27 g

Volume of water = 10 cm³

Volume of water+ stone = 19 cm³

Volume of stone = ?

Density of stone = ?

Solution:

Volume of stone = total volume - volume of water

Volume of stone = 19 cm³ -  10 cm³

Volume of stone = 9 cm³

Density of stone:

d = m/v

d = 27 g/ 9 cm³

d = 3 g/cm³

The molecular formula for the salt consistent with this experimental equivalent weight is Ni2(NH2)Br(H2O).

The exchange of one or more hydrogen ions, H +, between species that may be neutral (molecules like water, H 2 O, or acetic acid, CH 3 CO 2 H) or electrically charged (ions like ammonium, NH 4+, hydroxide, OH, or carbonate, CO 32)  is known as an acid-base reaction.

The first step to determining the equivalent weight of the salt is to calculate the number of moles of HCl that were used to neutralize the sample. This can be done by using the following formula:

moles HCl = (volume HCl) x (molarity HCl)

moles HCl = (30.00 mL) x (0.1013 mol/L) = 3.04 x 10^-2 mol

Next, we need to calculate the number of moles of NaOH that were used to neutralize the excess HCl. This can be done by using the following formula:

moles NaOH = (volume NaOH) x (molarity NaOH)

moles NaOH = (6.30 mL) x (0.1262 mol/L) = 7.97 x 10^-3 mol

We can use this number to calculate the number of moles of salt that was present in the original sample.

moles salt = (moles HCl) = 7.97 x 10^-3 mol

Now we can use this number to calculate the equivalent weight of the salt. The equivalent weight of a substance is defined as the molar mass of the substance divided by the number of moles of the substance that react with one mole of H+.

Equivalent weight of the salt = (mass of salt) / (moles of salt)

Equivalent weight of the salt = (0.185 g) / (7.97 x 10^-3 mol) = 23.2 g/mol

From the equivalent weight of the salt, we can observe that the equivalent weight is consistent with the formula Ni2 (NH)mBrn(H2O)p (where m,n,p represent coefficients in the formula).

The molar mass of Ni2 (NH)mBrn(H2O)p = 2*(Ni) + m*(NH3) + n*(Br) + p*(H2O)

2*(Ni) + m*(NH3) + n*(Br) + p*(H2O) = 23.2 g/mol

Therefore, the molecular formula for the salt consistent with this experimental equivalent weight is Ni2(NH2)Br(H2O).

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Total heat generated by 2 mole of TiO2(s) is 4.963kJ.

The amount of heat released in the reaction of 2.89 mol of TiO2(s) can be calculated using the following equation: q = nCΔT, where n is the number of moles, C is the specific heat capacity of TiO2, and ΔT is the change in temperature.

The specific heat capacity of TiO2 is 683. 697. J/kgK. and the change in temperature is is 25k. By plugging in the values and converting J to kJ,

q = 2.89 * 25 * 683.697

=> 4963.35

In brief, the amount of heat released by 2.89 mol of TiO2(s) is 4.963kJ.

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Complete question :

determine how much heat (in kj) of 2.89 mol of tio2(s) with a temperature difference of 25k

Answer:

Explanation:

Answer:

a 3atm

Explanation:

or d 40 psi because it is true and corect [b 3.0398 21oinwex id cn uerfh uh 837hf uxhoec

Answer:

i think quantitative observation

Answer:

Particles stay the same unless there is a chemical change whether the matter is solid, liquid or gas.

Explanation:

in physical changes no new materials are formed and the particles do not change apart from gaining or losing energy