What causes a moving object to continue moving at the same velocity unless an unbalanced force acts on it?.

Answer:

the path the object follows is called its trajectory so A. trajectory

Answer:

3.18 Nm

Explanation:

Given that:

Radius (r) = 15cm = 15/100 = 0.15m

θ = 45°

Applied force (F) = 30 N

The Torque can be obtained using the relation :

T = rF * sinθ

T = 0.15 * 30 * sin(45)

T = 0.15 * 30 * 0.7071067

T = 3.18198015

T = 3.18 Nm

Answer:

The answer is Radiation.

Explaination:

A and B are wrong because you can't have convection or convection currents without air, and all the air has been removed from the box.

D is wrong because there is no liquid in the box.

C is correct because heat can be transmitted even through a vacuum by radiation (e.g., the Sun). You can quickly feel the heat radiated by a piece of white-hot iron.

Answer:

If this is what your asking?

Explanation:

The concept of time is self-evident. An hour consists of a certain number of minutes, a day of hours and a year of days. ... Time is represented through change, such as the circular motion of the moon around Earth. The passing of time is indeed closely connected to the concept of space

Answer:9.81 m/s2.

Explanation:

If a 2 kg object is falling at 3 m/s, at what rate is gravity working on the object ? The object is falling at 3 m/s. Gravity is working on the object at a rate of 9.81 m/s2.

Answer: Elements in the same group

Test variable in this experiment would be the type of object being tested for attraction to negatively charged balloon ; Outcome variable would be whether or not the object is attracted to negatively charged balloon ; Control variable in this experiment would be negatively charged balloon.

Test Variable: The test variable in this experiment would be the type of object being tested for attraction to negatively charged balloon. Marianne would likely test a variety of objects with different materials and shapes to see which ones are attracted to balloon.

Outcome Variable: The outcome variable would be whether or not object is attracted to negatively charged balloon. Marianne would observe each object and note whether it is attracted to balloon or not.

Control Variable: The control variable in this experiment would be negatively charged balloon. Marianne would use same balloon for each test to ensure that any differences in attraction are due to test variable (type of object) and not the balloon itself.

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Answer:

A: Wavelength  

B: Crest  

C: Trough

D: Amplitude

Answer:

A:

✔ crest

B:

✔ amplitude

C:

✔ trough

D:

✔ wavelength

Explanation:

The airplane flies at a final speed of 604.8 miles per hour while angled 2.98 degrees east of north.

We must apply vector addition to get the aircraft's flight's final speed. The speed of the aircraft can be seen as a vector with an axis going due east and a magnitude of 600 miles per hour. A vector having a magnitude of 85 miles per hour at an angle of 59 degrees west of north can be used to depict the wind's speed.

We determine that the ultimate velocity is 604.8 miles per hour with a direction of 2.98 degrees east of north using the Pythagorean theorem and trigonometry.

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Complete question - An airplane is traveling due east with a speed of 600 miles per hour. The wind blows at 85 miles per hour at an angle of 59 degrees. Determine the final speed of the airplane's flight.

the plane's final speed is approximately 650.6 mph in the direction 6.5° south of east

Hi! To calculate the final speed and direction of the plane, we need to consider both its eastward speed and the impact of the wind. Here are the given terms:

- Plane speed: 600 mph due east
- Wind speed: 85 mph at S59°E

First, let's break down the wind speed into its eastward (x) and southward (y) components using trigonometry:
- Eastward (x) component: 85 * cos(59°) ≈ 44.1 mph
- Southward (y) component: 85 * sin(59°) ≈ 73.3 mph

Now, we can find the plane's resultant speed in both directions:
- Resultant eastward speed: 600 mph (plane) + 44.1 mph (wind) = 644.1 mph
- Resultant southward speed: 0 mph (plane) + 73.3 mph (wind) = 73.3 mph

Finally, to find the final speed and direction, we can use the Pythagorean theorem and the arctangent function:
- Final speed: sqrt(644.1^2 + 73.3^2) ≈ 650.6 mph
- Final direction: arctan(73.3/644.1) ≈ 6.5° south of east

So, the plane's final speed is approximately 650.6 mph in the direction 6.5° south of east.

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The probability that less than three of the 10 students selected at random from the physics majors are from ethnic minorities is 0.676.

In the given case, the total percentage of physics majors belonging to ethnic minorities is 20%.The probability of choosing a student who belongs to an ethnic minority is therefore:P(Ethnic Minority) = 0.20Let n be the number of students selected at random from physics majors. Then the probability that less than 3 of the students are from ethnic minorities is:P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)where X is a random variable that represents the number of students from ethnic minorities in a sample of size n.In order to find P(X = 0), P(X = 1), and P(X = 2), we will use the binomial distribution formula:P(X = k) = (n choose k) * p^k * (1-p)^(n-k)where (n choose k) is the binomial coefficient which represents the number of ways to choose k items from a set of n items, and p is the probability of success (i.e., choosing a student who belongs to an ethnic minority).Using this formula, we get:P(X = 0) = (10 choose 0) * 0.20^0 * 0.80^10 = 0.1074P(X = 1) = (10 choose 1) * 0.20^1 * 0.80^9 = 0.2684P(X = 2) = (10 choose 2) * 0.20^2 * 0.80^8 = 0.3289Therefore, P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.1074 + 0.2684 + 0.3289 = 0.676.

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A) Moving with a constant speed in the positive direction, B) Moving in the negative direction and speeding up, C) Moving in the positive direction, first fast then slow, and D) Moving with negative velocity and negative acceleration.

A) Moving with a constant speed in the positive direction: This indicates a linear motion where the object maintains a constant velocity in the positive direction. The sketch would show a straight line with a constant positive slope, indicating a steady speed.

B) Moving in the negative direction and speeding up: This suggests an object that is initially moving in the negative direction and is accelerating, or increasing its speed. The sketch would depict a line with a negative slope that becomes steeper over time, indicating an increase in velocity.

C) Moving in the positive direction, first fast then slow: This implies an object initially moving in the positive direction at a high speed and gradually slowing down. The sketch would show a line with a positive slope that becomes less steep over time, indicating a decrease in velocity.

D) Moving with negative velocity and negative acceleration: This refers to an object moving in the negative direction with decreasing speed, or decelerating. The sketch would display a line with a negative slope that becomes less steep over time, representing a decrease in velocity.

These sketches provide visual representations of the predicted actions/movements, illustrating the changes in velocity over time for each scenario.

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Answer:

the weight becomes thicker and harder to carry as the weight plottens,

Explanation:

i did this

The angle necessary to keep a 10 kg box motionless, given a coefficient of static friction of 0.55 between the box and the ramp, is 33.4°, which corresponds to Option A.

To determine the angle, we can use the relationship between the coefficient of static friction, the angle of the incline, and the gravitational force acting on the box. The maximum static friction force can be calculated using the formula:

Friction force = coefficient of static friction * Normal force

The Normal force can be found by decomposing the gravitational force acting on the box into components parallel and perpendicular to the incline. The perpendicular component (Normal force) is equal to the weight of the box (mass * gravitational acceleration).

Since the box is motionless, the friction force must be equal to the component of the gravitational force acting parallel to the incline:

Friction force = Component of weight parallel to incline

By substituting the given values and solving for the angle, we find:

coefficient of static friction = tan(angle)

angle = arctan(coefficient of static friction)

angle = arctan(0.55) ≈ 33.4°

Therefore, the correct answer is Option A, 33.4°.

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The position on the meter mark where Ari catches up with Amanda is 19.3 m.

The given parameters:

The distance between 6 m mark and 25 m mark is calculated as follows;

\(d = 25 \ m - \ 6 \ m\\\\\d = 19 \ m\)

The distance traveled by Ari before catching up with Amanda is calculated as follows;

total ratio = 7 + 3 = 10

\(distance = \frac{7}{10} \times 19 \ m\\\\distance = 13.3 \ m\)

The position of Ari from the 6 m mark is calculated as follows;

\(position = 6 \ m \ + \ 13.3 \ m\\\\position = 19.3 \ m\)

Thus, the position on the meter mark where Ari catches up with Amanda is 19.3 m.

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Answer:

The above answer is correct! The answer is 19.3 meters :)

Explanation:

adding a ss for proof!

hope this helps :D

I = 0.00744 A (Amps)

Hi there !

Ohm's law formula

I = V/R

I = 3.5V/470Ω

I = 0.00744 A

Good luck !

Answer:

there was 9 but pluto got kicked out of the solar System so 8

The new electrostatic force will be 384 units.  

The electrostatic force of attraction between two charges \(q_{1} \\\)(charge of object 1)  and \(q_{2}\)(charge of object 2) separated by a distance d is given by

\(F = \frac{q_{1} q_{2}}{4\pi E_{0} d^{2} } \\\)

\(E_{0} = 8.854 * 10^{-12} C^{2} N^{-1} m^{-1}\) is the permittivity of free space.

Initially, we have,

\(\frac{q_{1} q_{2}}{4\pi E_{0} d^{2} } =F_{1} = 8 units\)  

Now, if the charge of object 1 is multiplied by 1, the charge of object 2 is multiplied by 3, and the distance separating objects 1 and 2 is divided by 4, we have, \(q_{1} =q_{1}, q_{2} =3q_{2} , d=\frac{d}{4}\).

The new electrostatic force will be,

\(F_{2} = \frac{q_{1} 3q_{2}}{4\pi E_{0} (\frac{d}{4} )^{2} } \\\\\) units.

We have, \(F_{1} = 8 units= \frac{q_{1} q_{2}}{4\pi E_{0} d^{2} } \\\)

Hence,

\(F_{2} =\frac{8*3}{(\frac{1}{4}) ^{2} } units= 384 units.\)

Hence, the new electrostatic force will be 384 units.

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Answer:

A solar panel

Explanation:

The distance travelled by automobile while braking is around 7600 m, the angular speed of the tyres about their axles is 27.8 rad/s, and the magnitude of the angular acceleration of the wheels is 0.0605 rad/s2.

The formula for angular speed may be used to calculate the angular speed of the tyres after first changing the velocity from km/h to m/s:

\(v = 50.0 km/h = 13.9 m/sr = 0.500 m (radius of the tire)ω = v/r = 13.9 m/s / 0.500 m = 27.8 rad/s\)

b)The following formula can be used to determine the tyre's initial angular speed:

ω^2 = ω0^2 + 2αθ

0 = ω0^2 + 2α(70π)

α = -ω0^2 / (2θ)

α = \(- (27.8 rad/s)^2 / (2 × 70π) = -0.0605 rad/s^2\)

c)The following formula may be used to determine how far the automobile travelled when braking:

θ = ω0t + (1/2)αt^2

v = at

\(t = v/a = 13.9 m/s / 0.0605 rad/s^2 = 229 s\)

\(70π = (27.8 rad/s)(229 s) + (1/2)(-0.0605 rad/s^2)(229 s)^2\)

Simplifying:

70π = 6354 rad + 1255 m=7600 m

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The Universe in the future have two possibilities:

Universe is the whole cosmic system of matter and energy. The Earth, the Sun, the Moon, the planets, the stars along with the dust , gases, rocks forms the universe.

The big bang is the theory which explains that how the universe began. It says that the universe began with just a single point. It went on expanding and stretched to grow as large as possible. It is still now expanding.

The universe consist of fully dark matter, interstellar gases or dust. The big bang is increasing just because in universe there is abundant of hydrogen and helium. The two possibilities:

This universe is still on it way of expanding more.

Thus, the future possibilities of universe are explained.

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The ratio of the velocities of the two planets is 0.482

The velocity v of the planet in its circular orbit can be calculated using the following formula: v = 2πr/T

So, v = 2πr/ T

Where T is the time period of revolution of the planet around the star, r is the radius of the circular orbit, and v is the velocity of the planet in its orbit.

Since we can assume circular orbits, we have v ∝ r^-1/2.

Therefore, the ratio of velocities of the two planets is given as follows:

V1 / V2 = (r1 / r2)^(1/2)

Where, V1 is the velocity of the terrestrial planet orbiting at 5.00 AU, r1 is the radius of the orbit of the terrestrial planet around the star, V2 is the velocity of the giant planet orbiting at 19.00 AU, and r2 is the radius of the orbit of the giant planet around the star.

Therefore, substituting r1 = 5.00 AU, r2 = 19.00 AU, we get the ratio of the velocities of the two planets as:

V1 / V2 = (5/19)^(1/2)

V1 / V2 = 0.482

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Since unbalanced forces acts on the spheres, the aim of increasing the release distance of the spheres is to observe the effect of unbalanced forces acting on the spheres.

An experiment is a study whose objective is to study cause and effect relationships. In this case, the students had to increase the distance at which the spheres was released.

The aim of increasing the release distance of the spheres is to observe the effect of unbalanced forces acting on the spheres.

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c = √(E/m) so, speed of light equals to the square root of the emitted energy divided by mass of the object.

So, option (c) is correct.

E = mc² is an equation in Albert Einstein's theory of special relativity that expresses the fact that mass and energy are the same physical entity and can be changed into each other.

The kinetic energy of a body is equal to its increased relativistic mass multiplied by the speed of light squared in the equation. However, in special relativity, the energy of a body at rest is determined to be mc².

Given equation:

E = mc²

where:

E =  emitted energy

m = mass of the object and

c = speed of the light.

hence, c = √(E/m)

so, speed of light equals to the square root of the emitted energy divided by mass of the object.

So, option (c) is correct.

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Answer:

When the circuit breaker trips and turns off, it can shut off power to the appliance. This not only protects your home from damage, but it also protects the appliance itself.

Explanation:

What is a circuit breaker. A circuit breaker is an electrical switch designed to protect an electrical circuit from damage caused by overcurrent/overload or short circuit. Its basic function is to interrupt current flow after protective relays detect a fault.

Answer: The use of S I Unit brings uniformity in measurements.

Explanation:

The S I unit is the international system of units which are used to express the magnitudes or quantities of important natural phenomena. It is used universally as a standard for measurements thereby creating an avenue for uniformity in measurements. The base units that makes up the SI unit are:

--> Length: this is measured in meters (m)

--> Time: this is measured in seconds (s)

--> Mass: this is measured in kilogram (kg)

--> Temperature: this is measured in Kelvin (k)

--> Electric current: this is measured in ampere (A).

--> Amount of substance: this is measured in mole

--> Luminous intensity: this is measured in candela (cd)

These units are used as the standard to make our judgement of measurement more reliable and accurate. And since there is only one basic unit for each quantity (example length which is measured in meters) there is no need for further conversions.

Answer:

doubled

Explanation:

F=ma1----------(1)

2F = ma2-------(2)

Divide 2nd equation by 1st one

we get a1×2=a2

2. doubled

A force can cause an object with mass to change its velocity, i.e., to accelerate.

\(F=m*a\)

Given:

\(F=m*a_1\)..............(i)

\(2F = m*a_2\)...........(ii)

On dividing equation (ii) by (i)

\(\frac{2F}{F} =\frac{m*a_2}{m*a_1} \\\\2=\frac{a_2}{a_1} \\\\a_1=2*a_2\)

Thus, the magnitude of the acceleration of the object is doubled. Therefore, correct option is 2.

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According to the given statement The tension force in each rope is T = 14g/2Sin N, according to the information provided.

Tension is the force that is transmitted through a cable, rope, or wires when it is stretched by loads exerted from opposing sides. The bodies are put through an identical degree of strain at each end of the wire by the tension force, which is exerted all along entire of the wire's length.

Let the tension in each rope be T₁ & T₂

Also, T₁ = T₂ = T

T₁ Sinθ + T₂ Sinθ = mg

2T Sinθ = mg

2T Sinθ = 14g

T = 14g/2Sinθ

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The average velocity is a vector magnitude we can find that its value is:

           v = 3.63 10-2 m/ s

with a direction 74 to the South of the East

Giving parameters

To find

The velocity in a vector quantity that is defined as the change in displacement between time during the interval

               v = \(\frac{\Delta s}{\Delta t}\)

Where v is the veloicity, Δs and Δt are de positivo and time variation

To find the displacement let's use the Pythagoras'  theorem

           d = \(\sqrt{(\Delta x)^2 + (\Delta y)^2}\)

We assume that the displacements to the right (east) and upwards (north) are positive

          Δx = 17-14

          Δx = 3 m

          Δy = 12 -22.5

          Δy = -10.5 m

The distance traveled is

          d = \(\sqrt{3^2 + 10.5^2 }\)

          d = 10.9 m

The speed module is

          v = 10.9 / 300

           v = 3.63 10⁻² m / s

The direction of this velocity is given by the angle of this displacement can be found using trigonometry

           tan θ = \(\frac{\Delta y}{\Delta x}\)

           θ = tan⁻¹ \(\frac{\Delta y}{\Delta x}\)

           θ = tan⁻¹ \(\frac{-10.5}{3}\)

           θ = -74º

This angle is measured clockwise from the positive side of the x-axis.

Orea way to give this angle is

             θ = 74 south of East

In conclusion the average speed is

           v = 3.63 10-2 m / s

With a direction 74 to the South of the East

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