Answer:
A bar magnet creates a magnetic field around it. The field cannot be seen, but its effects can be observed. This is how the magnetic field around a magnet is detected. Iron fillings can be used to study the presence of magnetic field and a compass can be used to plot the field lines.
Explanation:
Choose which of the statements below is true comparing the momentum of the two-cart system before and after the collision.Choose which of the statements below is true comparing the momentum of the two-cart system before and after the collision.Cart Y experienced a larger magnitude momentum change because its direction of travel changed.Carts X and Y experienced the same magnitude change in momentum.Cart X experienced the larger magnitude change in momentum because it slowed down more than Cart Y.The total momentum of the two cart system did not remain constant because both carts ended up going slower than they were moving originally.
TRUE - When comparing the momentum of two objects, one must take into account both their mass and their velocity, as both factors play an equal role in determining the momentum.
How does a system's momentum change prior to and following a collision?Law of momentum conservation According to the law, the system's momentum is conserved in the absence of external influences. That implies that the entire amount of momentum before and after the impact is equal.
What connection exists between the momentum before and after a collision?The total momentum before a collision between two objects equals the total momentum after the impact (in the absence of external forces). The law of conservation of momentum is this. It is real.
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The activity of a radioactive material drops to 1/16 of its original value in 20 years. What is its half life?
Answer: 5 years
Explanation:
Expression for rate law for first order kinetics is given by:
\(t=\frac{2.303}{k}\log\frac{a}{a-x}\)
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant = x
a - x = amount left after decay process = \(\frac{x}{16}\)
a) for calculating k
\(20=\frac{2.303}{k}\log\frac{x}{\frac{x}{16}}\)
\(k=\frac{2.303}{20}\log{16}\)
\(k=0.138years^{-1}\)
b) for calculating half life:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
\(t_{\frac{1}{2}}=\frac{0.693}{0.138years^{-1}}\)
\(t_{\frac{1}{2}}=5years\)
Thus its half life is 5 years
What is the relation between acceleration due to gravity and radius of the earth?
Answer:
As the earth is an oblate spheroid, its radius near the equator is more than its radius near poles. Since for a source mass, the acceleration due to gravity is inversely proportional to the square of the radius of the earth, it varies with latitude due to the shape of the earth.
Formula: g = GM/r2
Dimensional Formula: M0L1T-2
Values of g in SI: 9.806 ms-2
Explanation:
Please Mark me brainliest
Answer:
♡
Explanation:
As the earth is an oblate spheroid, its radius near the equator is more than its radius near poles. Since for a source mass, the acceleration due to gravity is inversely proportional to the square of the radius of the earth, it varies with latitude due to the shape of the earth.
You are playing tennis and return a volley. Identify a force pair.
During a tennis volley, the force pair involved is the action-reaction forces.
When playing tennis and returning a volley, the force pair involved is the action and reaction forces. In the process of hitting the ball, the tennis racket exerts a force on the ball, which is the action force.
The ball, in turn, exerts an equal and opposite force on the racket, which is the reaction force.Both the racket and the ball experience the force of impact during the volley.
The force applied by the racket causes the ball to move forward, while the equal and opposite force applied by the ball pushes the racket back.
These two forces are referred to as action-reaction forces or force pairs. A force pair refers to a pair of forces that are equal in magnitude but opposite in direction.
These forces always act on different objects and occur simultaneously. In this scenario, the action force was exerted by the tennis racket while the reaction force was exerted by the ball.
Therefore, during a tennis volley, the force pair involved is the action-reaction forces.
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What is a car’s acceleration if it increases its speed from 5 m/s to 20 m/s in 3 s? 10 m/s2 –15 m/s2 15 m/s2 5 m/s2
Answer:
5 m/s²
Explanation:
Acceleration = change in speed/time taken
20-5=15
15/3= 5 m/s²
Can some help me please im confused ♀️ !!! I,ll give you BRAINLIES
Answer:
2 seconds
Explanation:
1
1) If you wanted to save money on your electric bill, all of the following would help except:
OA
using light bulbs that produce more light and less heat
OB.
using a heater that converts more energy into work
O c. lowering the temperature in your hot water
OD. leaving the refrigerator open to increase air circulation
Reset
Next
Answer:
D
Explanation:
I don't know how to explain but D is just weirdly wrong to me.
How can ground-based telescopes equipped with adaptive optics yield images as detail-rich as those from old space missions?
Ground-based telescopes equipped with adaptive optics can yield detail-rich images comparable to those from old space missions by compensating for the atmospheric distortions that degrade the image quality.
The Earth's atmosphere introduces turbulence that causes images captured by ground-based telescopes to be blurry and less detailed. Adaptive optics technology addresses this issue by actively measuring and correcting for the atmospheric distortions in real-time.
It uses deformable mirrors and wavefront sensors to analyze the distortions and make precise adjustments to the telescope's optics.
By continuously adapting to the atmospheric conditions, adaptive optics can compensate for much of the blurring effect, resulting in images that approach the clarity and resolution achieved by space-based telescopes.
This enables ground-based telescopes to capture detailed images of astronomical objects and phenomena, rivaling the quality of those obtained by older space missions.
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how far from the end of the ramp does the skateboarder touch down? express your answer with the appropriate units.
5.64 m is the distance from the end of the ramp does the skateboarder touch down.
The motion by the skateboarder can be considered a projectile motion.
In the question, the height from which he jumps = 1 m
angle of projection = 30°
u = 7m/s
Let H be the maximum height that the skateboarder reaches.
T1 be the time after leaving the ramp that is required for the skateboarder to reach height H.
T2 be the time required for the skateboarder to reach the ground from height H.
R be the distance from the end of the ramp where the skateboarder lands.
By using v = u + at
where v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
Since at the height H, the final velocity is zero
we get
0 = 7*(sin 30°) - g*T1
where g = gravitational acceleration
T1 = 0.36 (s)
Using the equation: s = \(ut + \frac{1}{2}at^2\)
where s is the displacement
t is the time
a is the acceleration
u is the initial velocity
For the movement from 1m off-ramp to height H is
H - 1 = 7*(sin 30°)*T1 - (1/2)*g*\(T1^2\)
H - 1 = 1.26 - 0.64 = 0.62
H = 1.62 (m)
For downward motion from height H,
H = 0 + (1/2)*g*\(T2^2\)
T2 = 0.57 (s)
Distance traveled is the velocity * time taken
For x component
R = (T1 + T2)*7*(cos 30°)
R = 5.64 (m)
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The complete question answered is:
A skateboarder starts up a 1.0 m high, 30-degree ramp at a speed of 7.0 m/s. The skateboard wheels roll without friction. How far from the end of the ramp does the skateboarder touch down?
What is reflection very short answer?
When a shaft of light approaches a smooth polished face and the light shaft bounces back, it's called the reflection of light. The incident light shaft which lands upon the face is said to be reflected off the face. The shaft that bounces back is called the reflected shaft.
When light is reflected on a aeroplane face the angle of reflection is equal to the angle of prevalence i.e. θr = θi.
Angle of prevalence is the angle between the incident shaft and the reflecting face.
Angle of reflection
This is the angle between the reflected shaft and the normal shaft on a reflecting face.
Angle of reflection is analogous to angle of prevalence.
Thus, the reflection of light is the shaft that hits the face and reflects back to the atmosphere.
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the air is compressed in a bicycle pump, an average force of 45N is exerted as the pump handle moves 0.24 m. During this time, 2.0J heat leaves the cylinder through the walls. What is the net change in thermal energy of the air in the cylinder?
The net change in thermal energy of the air in the cylinder is -8.8 J.
When a force is exerted on a system and it undergoes a displacement, work is done. In this case, when the pump handle moves 0.24 m, the work done on the air in the cylinder is:
Work = Force x Distance
Work = 45N x 0.24m
Work = 10.8 J
The heat leaving the cylinder through the walls is considered as heat transfer or heat loss to the surroundings.
Therefore, the net change in thermal energy of the air in the cylinder can be calculated using the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system:
ΔU = Q - W
where ΔU is the change in internal energy of the system, Q is the heat added to the system, and W is the work done by the system.
Substituting the values given in the problem:
ΔU = 2.0 J - 10.8 J
ΔU = -8.8 J
Since the value of ΔU is negative, it means that the internal energy of the air in the cylinder has decreased, which can be attributed to the heat loss to the surroundings.
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An object is located 26.0 cm froma concave lens with f = -14.0 cm.What is its magnification?(Mind your minus signs.)(Unit = cm)
Object distance, u = 26.0 cm
Focal length, f = -14.0 cm
Image distance, v = ?
The relationship between object distance, image distance, and focal length is:
\(\begin{gathered} \frac{1}{f}=\frac{1}{u}+\frac{1}{v} \\ \\ -\frac{1}{14}=\frac{1}{26}+\frac{1}{v} \\ \\ \frac{1}{v}=-\frac{1}{14}-\frac{1}{26} \\ \\ \frac{1}{v}=-0.10989010989 \\ \\ v=\frac{-1}{0.10989010989} \\ \\ v=-9.1\text{ cm} \\ \end{gathered}\)Magnigication is calculated as:
\(\begin{gathered} M=|\frac{v}{u}| \\ \\ M=|\frac{-9.1}{26}| \\ \\ M=0.35 \end{gathered}\)The magnification of the object = 0.35
in order to allow both telecommunications and power cables in a cable tray or cable runway, they must be ? , as required by the national electrical code (nec).
To accommodate both telecommunications and power cables in a cable tray or cable runway, they must be separated, as mandated by the National Electrical Code (NEC).
The National Electrical Code (NEC) sets standards for electrical installations to ensure safety and proper functioning. According to NEC guidelines, telecommunications and power cables should be physically separated when placed in a cable tray or cable runway. This separation is necessary to prevent interference and potential hazards. Telecommunications cables carry data signals, while power cables carry electrical currents. When these cables are in close proximity, there is a risk of electromagnetic interference (EMI) from the power cables affecting the data signals in the telecommunications cables. This interference can lead to signal degradation and communication errors. Additionally, power cables carry high voltage, which poses a safety hazard if there is a fault or short circuit. Therefore, by keeping telecommunications and power cables separated in cable trays or runways, the risk of interference and safety concerns is minimized, ensuring proper functionality and compliance with the NEC.
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What is equivalent resistance for a parallel circuit where R1 = 6, R2 = 36, and R3 = 12?
Answer:
Below
Explanation:
If they are all in parallel, the quivalent resistance is given by
1 = 3.6 Ω
1/R1 + 1/R2 + 1/R3
A box is lifted to a height of 6 meters in 3 seconds. If the lift required 400 watts of power, what was the weight of the box?200 N250 N300 N350 N
Given:
The height through which the box was lifted, h=6 m
The time it took to lift the box, t=3 s
The power dissipated in lifting the box, P=400 W
To find:
The weight of the box.
Explanation:
The power is described as the time rate of transfer of energy.
Thus the power is given by,
\(P=\frac{W}{t}\)Where W is the work done in lifting the box.
The work done is given by,
\(W=F\times h\)Where F is the weight of the box.
Thus the power dissipated in lifting the box is given by,
\(P=\frac{Fh}{t}\)On substituting the known values,
\(\begin{gathered} 400=\frac{F\times6}{3} \\ \Rightarrow F=\frac{400\times3}{6} \\ =200\text{ N} \end{gathered}\)Final answer:
The weight of the box is 200 N
Thus the correct answer is option A.
What is the electron emission produced when light is shone on a substance
Answer:
Biotron
Explanation:
Answer:
in this generation are electron emission is the alpha,gamma,beta rays attractive to gether
Which one of the 5W + H questions does the following statistic answer?
The world's fastest roller coaster reaches a speed of almost 150 miles per hour, requiring thrill-seekers to wear goggles when they ride!
(1 point)
How
Who
Where
When
Answer:Proven answer:: is How just did it online Connections A.
Explanation:
Answer:
How is the answer.
Explanation:
Can someone help me with this please!!!
Answer:
B. 10 m
Explanation:
f = v/λ = (20 m/s)λ / (5 m) = 4 Hz original frequency
1/2(4 Hz) = 2 Hz half the original frequency
(20 m/s) / λ = 2 Hz
λ = (20 m/s) / (2 Hz) = 10 m
The second wavelength would increase to 10 m
What types of changes occur during the erosion and deposition of sediments in a river?
Answer:
Slow-moving rivers generate extensive floodplains and meanders through erosion and deposition. Stream and river deposition can result in the formation of alluvial fans and deltas. Natural levees may be formed by floodwaters. Caves and sinkholes can arise as a result of groundwater erosion and deposition.
Explanation:
s
The erosion and deposition of sediments in a river creates broad floodplains and meanders.
What is Erosion and Deposition?Deposition occurs when sediment, a combination of soil and rock produced by weathering, is eroded and transported to a new area.
Deposition is the act of depositing silt that has been transported by the wind, water, sea, or ice.
Earthen materials are worn away during erosion, a geological process in which they are moved by wind or water.
The removal of soil, rock, or dissolved material from one area on the Earth's crust and subsequent transport to another region for deposition are known as erosional processes. Erosion differs from weathering, which is a static process.
Given data ,
Let the erosion and deposition of sediments be deposited in a river
Now , Pebbles, sand, mud, and salts that have been dissolved in water can all be used to convey sediment. Afterwards, salts may be left behind by organic action.
Now , floodplain is caused when erosion happens
And , A floodplain is a broad, level or nearly level area of land where the stream flows.
Meandering streams that wander from side to side broaden the plain by eroding it during the formation of the plain. Flooding can occur when stream flows overflow from their channel due to very excessive rainfall or quick snow-melt.
Hence , floodplain and meandering occurs due to erosion and deposition
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The 3 financial ratio analysis areas are: a. Liquidty, profitability and solvency b. Liquidity, profitability and balance sheet c. Income statement, liquidity and profitability d. Profitability, solvency and cash flows
The 3 financial ratio analysis areas are Liquidity, profitability, and solvency.
Supporting answer: The three financial ratio analysis areas commonly considered are liquidity, profitability, and solvency. These areas provide insights into different aspects of a company's financial health and performance.
Liquidity ratios assess a company's ability to meet its short-term financial obligations and its overall liquidity position. These ratios include the current ratio, quick ratio, and cash ratio, among others.
Profitability ratios measure a company's ability to generate profits relative to its sales, assets, or equity. Examples of profitability ratios include gross profit margin, net profit margin, return on assets (ROA), and return on equity (ROE).
Solvency ratios evaluate a company's long-term financial stability and its ability to meet its long-term obligations. These ratios assess the company's leverage and debt repayment capacity. Examples of solvency ratios include debt-to-equity ratio, interest coverage ratio, and debt ratio.
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(a) is it possible for the magnetic force on a charge moving in a magnetic field to be zero? (b) is it possible for the electric force on a charge moving in an electric field to be zero? (c) is it possible for the resultant of the electric and magnetic forces on a charge moving simultaneously through both fields to be zero?
a)It is possible for the magnetic force on a charge moving in a magnetic field to be zero. The force acting on the charge is zero when a charge is moving in the same or opposite direction of the magnetic field. When a is charge moving parallel in the same direction of the magnetic field, then the magnetic force is zero.
b)It is not possible for the electric force on a charge moving in an electric field to be zero. If there's a charged particle in a magnetic field, it's impossible for this force to become zero.
c)It is not possible for the resultant of the electric and magnetic forces on a charge moving simultaneously through both fields to be zero. The magnetic force can be zero but the electric force cannot be zero because it is not affected by the motion of the particles.
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How long will it take a 6000W motor to lift a 5000kg load through a height of 2.5m?
Answer:
20.4375 seconds.
Explanation:
Wattage = Work / time
Work = f * d
F = mass * acceleration
mass = 5000 kg
acceleration = force of gravity
acceleration = 9.81
Force = 5000 * 9.81
Force = 49050 N
Work = F * d
d = 2.5
Work = 49050 * 2.5
Work = 122625 Joules
Wattage = Work / time
time = work / wattage
wattage = 6000 watts
time = 122625 / 6000
time = 20.4375 seconds.
The 8-kg uniform slender bar was at rest on a frictionless horizontal plane when the force F= 16 N was applied. At the instant immediately after F was applied, find the angular acceleration of the rod and the acceleration of point A. (Partial answer: a=10 rad/s^2)
The 8-kg uniform slender bar was at rest on a frictionless horizontal plane when the force F= 16 N was applied. At the instant immediately after F was applied, the acceleration of point A is 10 rad/s^2
To find the angular acceleration and acceleration of point A, we can use the following formulas:
1. Angular acceleration (α) = Torque (τ) / Moment of Inertia (I)
2. Acceleration of point A (a) = α * radius (r)
First, we need to find the torque (τ) and the moment of inertia (I) for the bar. For a uniform slender bar, the moment of inertia is given by:
I = (1/3) * mass (m) * length^2 (L^2)
Since the bar is uniform, the force is applied at its midpoint, which is L/2 away from the pivot point A. So, the torque can be calculated as:
τ = F * (L/2)
Now, we can find the angular acceleration (α):
α = τ / I
Finally, we can find the acceleration of point A (a):
a = α * r (where r = L/2)
Using the given partial answer a = 10 rad/s^2, you can now solve for the other variables and find the angular acceleration of the rod.
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a horse competing in a race accelerated from rest for 7s, at which time the horse has traveled 160m. what were the horses average and final velocities
37.1 μs to traverse a measured distance of 11.12 km.
Determine the speed of light from the data. Express
your answer in SI units and in scientific notation,
using the appropriate number of significant digits.
The speed can be obtained as 3 * 10^8 m/s.
What is speed?The term speed is the ratio of the distance covered to the time taken. Given that both the distance covered and the time taken are both given in this problem we can now go ahead and try to solve the problem.
Distance covered = 11.12 km or 11.2 * 10^3 m
Time taken = 37.1 μs or 37.1 * 10^-6 s
Thus the speed = 11.2 * 10^3 m/ 37.1 * 10^-6 s
= 3 * 10^8 m/s
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Match the description of an object's motion with the position-time graph that represents at A. slowing down B. moving with constant speed C. not moving D. speeding up
The descriptions of object's motion with the position-time graph that represents at:
D. speeding up - Graph 1
C. not moving - Graph 2
B. moving with constant speed - Graph 2
A. slowing down - Graph 3
What is motion?Motion is the conceptual notion in which an object moves from its position with respect to time. Motion is acceptable to be described in terms of displacement, distance, velocity, acceleration, speed.
Furthermore, Motion is a change in an object's position over time. It is the result of forces acting upon an object, and can be described in terms of distance, speed, and direction.
Therefore, it is a change of position or orientation of a body with the change of time. looking at the attached graph, it can then be concluded that the correct answers are as given above
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What does your body do with nutrients during the digestion process?
Answer:
the correct answer is
Explanation:
The small intestine absorbs most of the nutrients in your food,and your circulatory system passes them on to other parts of your body to store or use. Special cells helped absorbed nutrients cross the intestinal lining into your blood stream.
hope this works out!!!!
The wheel of a certain bus are 2m apart and the bus falls over when it is tilted sideways at 45degree angle with vertical. What is the tension in each rope
Answer:
F = m g / 4, F = 12250 N
Explanation:
For this exercise we must use the rotational equilibrium relation
∑τ = 0
let's set a reference system on the wheel where the bus is turning and that the anti-clockwise rotations have been positive
-2F x_string + W x_bus = 0
x_bus =\frac{l}{2} cos 45
x_string = l cos 45
where F is the force on each wheel and W the weight of the bus ,, we assume that the center of mass is in the middle and x_bus is the perpendicular distance from the center of mass to the turning point.
2F l cos 45 = W \(\frac{l}{2}\) cos 45
F = m g / 4
to finish the calculation we must assume a mass for the bus m = 5000 kg
F = 5000 9.8 / 4
F = 12250 N
Which term best describes the motion of the rope particles in relation to the motion of the rope wave shown in the photograph?
A. Perpendicular
B. Longitudinal
C. Parallel
D. Circularn
Answer:
A. Perpendicular
Explanation:
Clarification:
The inquiry is inadequate as it does not have the picture of the rope wave movement.
From all that, we can say that;
The rope's are moving at the same time in a similar example without contacting one another.
This is hence a mechanical wave being made with the movement having motions that are opposite to the course of energy move of the ropes.
This is a meaning of cross over waves in light of the fact that the rope molecule movement is opposite to the wave movement.
Perpendicular describes the motion of the rope particles in relation to the motion of the rope wave shown in the photograph. Hence option A is Correct.
What is wave ?Wave is is a disturbance in a medium that carries energy as well as momentum . wave is characterized by amplitude, wavelength and phase.
Amplitude is the greatest distance that the particles are vibrating. especially a sound or radio wave, moves up and down. Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.
Wavelength is the distance between two points on the wave which are in same phase.
Phase is the position of a wave at a point at time t on a waveform.
There are two types of the wave longitudinal wave and transverse wave.
Longitudinal wave : in which, vibration of the medium (particle) is parallel to propagation of the wave. Sound wave is a longitudinal wave.
Transverse wave : in which, vibration of the medium (particle) is perpendicular to propagation of the wave. Light wave is a longitudinal wave.
In the picture we can see that wave is traveling in the direction out of the paper and rope particle is vibrating along Y axis perpendicular to the propagation of the wave.
Hence Perpendicular option is correct.
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Convert a density of 5.02x10^-6 g/ml to its equivalent in pounds
per cubic foot.
The equivalent density of 5.02x10^-6 g/ml in pounds per cubic foot is approximately 0.312 lb/ft^3.
To convert the density from grams per milliliter (g/ml) to pounds per cubic foot (lb/ft³), we need to use the appropriate conversion factors. 1 g/ml is equal to 62.42796 lb/ft³. By multiplying the given density by the conversion factor, we can calculate the equivalent density in pounds per cubic foot as follows: Density in lb/ft³ = (Density in g/ml) * (Conversion factor) Density in lb/ft³ = (5.02x10^-6 g/ml) * (62.42796 lb/ft³) Density in lb/ft³ ≈ 0.312 lb/ft³ Therefore, the density of 5.02x10^-6 g/ml is approximately 0.312 lb/ft³.
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