What are the total balance electrons?
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Answer:

here are the answers edge2020

Explanation:

Answer:

Here is 2/5 and the next slide answers too!

Explanation:

Hope it helps!!

To prepare 100 ml of a solution with 0.5 M KMnO4 and 1 M H2SO4, we need to calculate the amount of each compound needed.

For KMnO4:
0.5 M = 0.5 mol/L
0.5 mol/L × 0.1 L = 0.05 mol
0.05 mol × 158.034 g/mol = 7.9017 g

Therefore, we need 7.9017 g of KMnO4 to prepare the solution.

For H2SO4:
1 M = 1 mol/L
1 mol/L × 0.1 L = 0.1 mol
0.1 mol ÷ 18 M = 0.00556 L = 5.56 ml

Therefore, we need 5.56 ml of 18 M H2SO4 to prepare the solution.

In conclusion, to prepare 100 ml of a solution with 0.5 M KMnO4 and 1 M H2SO4, we need 7.9017 g of KMnO4 and 5.56 ml of 18 M H2SO4.

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Colour can be changed because of the change in the ligands. Some complex exhibit colour mainly due to the crystal field splitting. Here  copper (ii) sulphate is known as blue vitriol.

In hydrated copper sulfate, four water molecules are present as ligands. In the presence of these ligands, d-orbital are no longer degenerate in energy. Hence, d-d transition takes place absorbing red wavelength. The complementary colour blue is reflected.

When concentrated HCl is added, the water ligands are replaced by chloride ligands. This forms copper chloride complex. The d-d transition takes place by absorbing violet wavelength. So yellow colour is reflected.

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Answer: Mojave grasshopper

Explanation: this is the answer because it is living

Answer:

a formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.

Hope this helped!!!

Answer:

Empirical formulas show the simplest whole-number ratio of atoms in a compound

Explanation:

Answer:

A quantity having direction as well as magnitude is called vector.

Answer:

reduce the distance by the factor of 5

Let's assume that Chris uses x milliliters of the 10% acid solution and (100 - x) milliliters of the 30% acid solution. Hence this assumption results in 16% solution of 100 milliliters.

To find the amount of acid in the resulting 16% solution, we can use the following equation:

0.1x + 0.3(100 - x) = 0.16(100)

We have got 0.16(100) and after Simplifying the equation, we will get:

0.1x + 30 - 0.3x = 16

-0.2x = -14

And the final solution would be after doing the above equation is

x = 70

Therefore, Chris needs to use 70 milliliters of the 10% acid solution and (100 - 70) = 30 milliliters of the 30% acid solution to create 100 milliliters of a 16% solution.

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Hi there,

I hope you and your family are staying safe and healthy!

The answer is: Enolase

Enolase is used to convert 2-phosphoglycerate (2PG) to phosphoenolpyruvate (PEP).

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Happy to help!

~Garebear

When the pressure of a gas is decreased from 3.40 atm to 2.60 atm, the temperature of the gas will decrease from 60.0 degree celsius to 45.88 degree celsius.

Gay -Lussac law states that the pressure and temperature is in direct proportions. Thus, pressure increases with an increase in temperature. The relation can be mathematically expressed as follows:

P/T = a constant. Hence,

P1/T1 = P2/T2

The initial pressure of the sample is given, 3.46 atm and the initial temperature is 60 °C. The final temperature of the gas when gas the expand to the lower pressure of 2.60 atm is calculated as follows:

\(T_{2} = \frac{P_{2}T_{1}}{P_{1}}\)

    = (60 °C× 2.60 atm) / 3.40 atm

    = 45.88 °C.

Hence, the final temperature of the gas which is expanded from the pressure of 3.40 atm to 2.60 atm with an initial temperature of 60 °C is  45.88  °C.

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A solution is defined as a mixture of two or more substances, usually, a solute and a solvent, and the difference between these two are in quantity, solute represents the smallest amount and solvent will represent the highest amount, and while you can have more than one solute, you can only have one solvent for a solution. Therefore the statement is true

The formula of the coordination compound lithium pentacyanocobaltate(II) is [LiCo(CN)₅]²⁻.

What is lithium pentacyanocobaltate(II) ?

Pentacyanocobaltate attracted attention as an early example of a metal complex that reacts with hydrogen. It contains low-spin cobalt(II) with a doublet ground state.

Let's break down the formula to understand its components:

The central metal ion is cobalt (Co) in the +2 oxidation state, denoted as Co(II).

The ligands are pentacyanocobaltate, which means there are five cyanide ligands (CN⁻) bonded to the cobalt ion.

The coordination complex is negatively charged, with a charge of 2-, so it requires two lithium ions (Li⁺) as counter ions to balance the charge.

Therefore, the complete formula is [LiCo(CN)₅]²⁻, where the square brackets indicate the coordination complex and the superscript 2- indicates the charge.

The formula of the coordination compound pentaamminechlorocobalt(III) nitrate is [Co(NH₃)₅Cl]NO₃.

Breaking down the formula:

The central metal ion is cobalt (Co) in the +3 oxidation state, denoted as Co(III).

The ligands are pentaamminechlorocobalt, indicating there are five ammonia ligands (NH₃) and one chloride ligand (Cl⁻) bonded to the cobalt ion.

There is no need for any counter ions to balance the charge in this compound.

Thus, the complete formula is [Co(NH₃)₅Cl]NO₃, where the square brackets denote the coordination complex, and NO₃ indicates the presence of nitrate ions as the counter ions.

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\(LiNO_{3}\)There are 0.075 moles of \(LiNO_{3}\) in 250 mL of a 0.30 M solution.

To determine the number of moles of \(LiNO_{3}\) in 250 mL of a 0.30 M solution, we can use the formula:

moles of solute = concentration (M) x volume (L)

First, we need to convert the volume from milliliters (mL) to liters (L):

250 mL = 0.25 L

Next, we can substitute the given values into the formula:

moles of \(LiNO_{3}\) = 0.30 M x 0.25 L

moles of \(LiNO_{3}\) = 0.075 mol

Therefore, there are 0.075 moles of \(LiNO_{3}\) in 250 mL of a 0.30 M solution.

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Answer:

.6 M

Explanation:

.45 moles / .750 liters = .6 M

Responder:

2H2 + O2 → 2H2O

CaO + H2O → Ca (OH) 2

Fe + S → FeS

H2SO3 → SO2 + H2O

CaCO3 → CaO + CO2

Explicación:

2H2 + O2 → 2H2O

2 moléculas de hidrógeno gaseoso reaccionan con oxigente para producir 2 moléculas de agua

CaO + H2O → Ca (OH) 2

El óxido de calcio reacciona con el agua para producir hidróxido de calcio.

Fe + S → FeS

El hierro reacciona con el azufre para producir sulfuro de hierro.

H2SO3 → SO2 + H2O

Por descomposición, el ácido sulfuroso se descompone para producir dióxido de azufre y agua.

CaCO3 → CaO + CO2

El carbonato de calcio se descompone para producir óxido de calcio y dióxido de carbono.

The enthalpy change for the reaction CaCO3 (s) -> CaO (s, graphite) + O2 (g) is 571.6 kJ.

The enthalpy of the reaction CaCO3 (s) -> CaO (s, graphite) + O2 (g) can be calculated by summing the enthalpies of the individual reactions involved. The given information provides the enthalpy change for the decomposition of CaCO3 (s) and the combustion of C (s) to form CO2 (g). By combining these reactions, the enthalpy change for the overall reaction can be determined.

The given reactions are:

CaCO3 (s) -> CaO (s) + CO2 (g) (H = 178.1 kJ)

C (s, graphite) + O2 (g) -> CO2 (g) (H = -393.5 kJ)

To calculate the enthalpy change for the reaction CaCO3 (s) -> CaO (s, graphite) + O2 (g), we need to subtract the enthalpy change of reaction 2 from the enthalpy change of reaction 1. Since the enthalpy change is an extensive property, we can subtract the enthalpies directly:

ΔH = H(reaction 1) - H(reaction 2)

= 178.1 kJ - (-393.5 kJ)

= 178.1 kJ + 393.5 kJ

= 571.6 kJ

Therefore, the enthalpy change for the reaction CaCO3 (s) -> CaO (s, graphite) + O2 (g) is 571.6 kJ.

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Answer:

Answer:

200 kg

Explanation:

the 200 kg person is heavier due to gravity's force the 100 kg person has less force than the other person

Answer:

massive one that is 200kg

Explanation:

Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.

A substantial imbalance between demand and response capability under conditions in which failure has important consequences refers to STRESS. It may affect the functioning of a biological system.

Homeostasis refers to the state of internal (steady) equilibrium, which is required for the normal functioning of a biological system.

Conversely, stress can be defined as any environmental factor (e.g., excessive temperature condition) which is directly affecting the normal functioning of an organism.

Stress may lead to the loss of the homeostatic state when conditions cannot be supported by the organism.

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Answer:

46.07

Explanation:

im not 100 sure this is right almost tho

please mark brainliest

Answer:

a

Explanation:

The heat capacity of a substance is the heat energy required to rise its temperature per one degree Celsius. Hence its unit is J/°C.

Heat capacity is the amount of heat energy required to raise the temperature of a substance by 1 degree Celsius or 1 Kelvin. It is expressed in the following units:

Joules per degree Celsius (J/°C)

Joules per Kelvin (J/K)

Calories per degree Celsius (cal/°C)

Calories per Kelvin (cal/K)

Joules per gram per degree Celsius (J/(g·°C))

Joules per gram per Kelvin (J/(g·K)) etc.

If in terms of simply the energy, then, The following units are used.

Joules (J) , Calories (cal) , Degrees Celsius (°C), Kelvin (K)

The choice of unit depends on the specific application and the system of units being used. The SI unit for heat capacity is J/K, while the traditional unit is cal/°C.

The use of per gram units is common in the context of specific heat capacity, which is the amount of heat energy required to raise the temperature of a unit mass of a substance by 1 degree Celsius or 1 Kelvin.

Therefore, here, the unit of heat capacity is J/°C.

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The correct answer is option b) 8.

To determine the number of unique gametes that can be produced through independent assortment, we need to consider the number of possible allele combinations for each gene.

The individual in question has the genotype AaBbCCDdEE, where each letter represents a different gene locus.

The genotype indicates that there are two alleles (A and a) for the first gene, two alleles (B and b) for the second gene, two alleles (C and C) for the third gene, two alleles (D and d) for the fourth gene, and two alleles (E and E) for the fifth gene.

To calculate the number of unique gametes, we multiply the number of possible allele combinations for each gene:

Number of allele combinations for the first gene: 2 (A and a)

Number of allele combinations for the second gene: 2 (B and b)

Number of allele combinations for the third gene: 1 (C)

Number of allele combinations for the fourth gene: 2 (D and d)

Number of allele combinations for the fifth gene: 1 (E)

Total number of unique gametes = 2 × 2 × 1 × 2 × 1 = 8

Therefore, the correct answer is option b) 8. A total of 8 unique gametes could be produced through independent assortment by an individual with the genotype AaBbCCDdEE.

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A. Ammonia is the limiting reactant.

B. Theoretical yield of urea is 215.3 kg.

C. Percent yield for the reaction is 86.0%

D. The mass of the excess carbon dioxide left is approximately 54.1 kg.

a) To identify the limiting reactant, we should compare the amount of products formed from each reactant. The chemical equation for the formation of urea \((NH_2CONH_2)\) by combining ammonia \((NH_3)\) and carbon dioxide \((CO_2)\) is as follows:

\(2 NH_3 + CO_2 - > NH_2CONH_2 + H_2O\)

The stoichiometry of the balanced equation indicates that the ratio of ammonia to urea is 2:1.

We can find the number of moles for each reactant using the following masses:

Moles of ammonia = 122.0 kg / 17.03 g/mol = 7.17 mol

Moles of carbon dioxide = 211.4 kg / 44.01 g/mol = 4.80 mol

It takes 14.34 moles of ammonia to react completely with the available carbon dioxide because the ratio of ammonia to urea is 2:1. But the amount of ammonia we have is less than we need - only 7.17 mol. As a result, ammonia is the limiting reactant.

b. Based on the limiting reactant, it is possible to calculate the theoretical yield of urea. We can use the moles of ammonia, which is the limiting reactant, to calculate the moles of urea:

Moles of urea = 7.17 mol / 2 = 3.58 mol

We can determine the theoretical yield of urea using the molar mass of urea (60.06 g/mol) as a starting point:

Theoretical yield of urea = 3.58 mol * 60.06 g/mol = 215.3 kg

C. The actual yield (185.1 kg) is calculated by dividing it by the theoretical yield (215.3 kg), then multiplying the result by 100%.

Percent yield = (185.1 kg / 215.3 kg) * 100% = 86.0%

D. We can calculate the amount of non-limiting reactant that has not reacted yet to determine the excess reactant. Since ammonia is the limiting reactant, we must determine how much excess carbon dioxide there is:

Moles of excess carbon dioxide = Moles of carbon dioxide initially - Moles of carbon dioxide used

= 4.80 mol - (7.17 mol / 2) = 1.23 mol

We can determine the mass of excess carbon dioxide using the molar mass of carbon dioxide (44.01 g/mol):

Excess carbon dioxide = 1.23 mol * 44.01 g/mol = 54.1 kg

Therefore, the mass of the excess carbon dioxide left is approximately 54.1 kg.

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Based on the given information, the two reactants that would give the described product via a Suzuki coupling are:

An alkyne where carbon 1 is bonded to a benzene ring and carbon 2 is bonded to hydrogen.

An alkene where carbon 1 is bonded to bromine and carbon 2 is bonded to benzene. The stereochemistry is cis.

The Suzuki coupling is a widely used cross-coupling reaction that involves the palladium-catalyzed cross-coupling of an organoboron compound (such as a boronic acid) with an organic halide or pseudo-halide. In this case, the reactants that can undergo the Suzuki coupling are the alkyne and the cis-alkene described above.

The alkene and alkyne provide the necessary carbon-carbon bond formation, while the benzene rings and hydrogens ensure the desired connectivity in the product. The palladium tetrakis triphenyl phosphine catalyst, heat, and sodium carbonate facilitate the coupling reaction, resulting in the formation of the biaryl product with the specified stereochemistry.

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The rate of production of product X is approximately 9.13 x \(10^{-6}\) mol/(L·s), indicating an increase in concentration by that amount per second.

To determine the rate of production of product X, we need to calculate the change in concentration of X divided by the change in time. The change in concentration is obtained by subtracting the initial concentration (3.40  x \(10^{-3}\) mol/L) from the final concentration (5.70x\(10^{-3}\)mol/L), resulting in a concentration change of 2.30 x \(10^{-3}\) mol/L.

Next, we divide the concentration change by the change in time, which is given as 228.9 seconds. Dividing the concentration change of 2.30 x  \(10^{-3}\) mol/L by the time of 228.9 seconds gives us the rate of production of product X.

The rate of production of X is calculated as (5.70x\(10^{-3}\) mol/L - 3.40x10-3 mol/L) / 228.9 seconds, which simplifies to approximately 9.13x\(10^{-6}\)mol/(L·s). This indicates that for every second, the concentration of product X increases by 9.13x10-6 mol/L.

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Answer:

no

Explanation:

its made of a living organisim which in this case is oats

The 95% margin of error for the mean increase in blood pressure that one would expect for cigarette smokers over the time span indicated by the experiment is ±1.98 (rounded off to two decimal places).

The mean increase in blood pressure that one would expect for cigarette smokers over the time span indicated by the experiment can be estimated by using the formula;μ = x ± z(\(a^{2}\)) * σ/√n

Where;μ is the population mean increase.x is the sample mean increase.z(\(a^{2}\)) is the z-scoreα is the level of significanceσ is the population standard deviationn is the sample size.

Substituting the given values into the formula;μ = 9.1 ± 1.96 * 5.5/√37= 9.1 ± 1.98

The mean increase in blood pressure that one would expect for cigarette smokers over the time span indicated by the experiment lies between 7.12 to 11.08.

Hence, the estimated mean increase is between 7.12 to 11.08 millimeters of mercury.

The 95% margin of error can be calculated using the formula;

Margin of error (E) = z(\(a^{2}\)) * σ/√n

Margin of error (E) = 1.96 * 5.5/√37

Margin of error (E) = 1.98 (approximated to two decimal places).

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Respuesta:

4.26 M; 12.8 N

Explicación:

Primer paso: Calcular la concentración volumétrica (Cv)

Usaremos la siguiente expression.

Cv = Cg × ρ

Cv = 30 g%g × 1.39 g/mL = 41.7 g%mL

Segundo paso: Calcular la molaridad

La concentración volumetrica es 41.7 g%mL, es decir, hay 41.7 gramos de soluto cada 100 mL de solución. Usaremos la siguiente fórmula para molaridad.

M = masa de soluto / masa molar de soluto × litros de solución

M = 41.7 g / 97.99 g/mol × 0.1 L = 4.26 M

Tercer paso: Calcular la normalidad

Usaremos la siguiente fórmula.

N = M × Z

donde Z para un ácido es igual al número de protones.

N = M × Z

N = 4.26 mol/L × 3 eq/mol = 12.8 N