What are the main organs of the muscular system?

Answer:

Bond broking

Explanation:

Bond broking.

Answer:

a. 0.02 moles  of NH₃, 0 moles of O₂, 0.08 moles of NO, 0.12 moles of H₂O

b. \(P_{NH_3}\) = 12,576.5 Pa, \(P_{NO}\) = 50,306.05 Pa, \(P_{H_2O}\) =  74,459.1 Pa

c. The total pressure is 138,341.64 Pa

Explanation:

a. NH₃ + O₂  → NO + H₂O

The balanced chemical equation is first found to be

4NH₃ + 5O₂  → 4NO + 6H₂O

Therefore, we have;

4 moles of NH₃ reacts with 5 moles of O₂ to form 4 moles of NO and 6 moles H₂O

Dividing by the reactant with the highest number of moles which is 5 moles of oxygen gives;

4/5 moles  of NH₃ reacts with 5/5 moles of O₂ to form 4/5 moles of NO and 6/5 moles H₂O

Which is the same as 4/5 moles  of NH₃ reacts with 1 mole of O₂ to form 4/5 moles of NO and 6/5 moles H₂O

Multiplying by 0.100 gives;

0.1×4/5 moles  of NH₃ reacts with 0.1 mole of O₂ to form 0.1×4/5 moles of NO and 0.1×6/5 moles H₂O

The quantity of each gas in the container upon completion of the reaction is therefore;

(0.1 - 0.1×4/5) = 0.02 moles  of NH₃

0 moles of O₂

0.08 moles of NO

0.12 moles H₂O

b. Given that the temperature = 105°C, we have;

PV = nRT

P = nRT/V

Where:

n = Total number of moles = 0.02 + 0.08 + 0.12 = 0.22 moles

R = Universal gas constant = 8.3145 J/(mol·K)

T = Temperature = 105°C = 378.15 K

V = Volume = 5 litre = 0.005 m³

P = 0.22×8.3145×378.15/0.005 = 138,341.64 Pa

From Dalton's law of partial pressure, we have;

Partial pressure Pₓ = Xₓ × P

Where:

Xₓ = Mole fraction

Which gives for ammonia NH₃ with 0.02 moles;

Mole fraction = 0.02/0.22 = 1/11

\(P_{NH_3}\) = 1/11 × 138,341.64  = 12,576.5 Pa

For the 0.08 moles of NO, we have

Mole fraction = 0.08/0.22 = 4/11

\(P_{NO}\) = 4/11 × 138,341.64  = 50,306.05 Pa

For the 0.12 moles H₂O

P = 0.12×8.3145×378.15/0.005 = 74,459.1 Pa

Mole fraction = 0.12/0.22 = 6/11

\(P_{H_2O}\) = 6/11 × 138,341.64  = 74,459.1 Pa

c. The total pressure = 12,576.5 Pa + 50,306.05 Pa + 74,459.1 Pa = 138,341.64 Pa.

The additional information that is required to obtain the enthalpy of neutralization is the density of the solution.

We know that the enthalpy of neutralization is defined as the heat that is evolved when  an acid is neutralized by a base under standard conditions. We can be able to obtain the enthalpy of the neutralization of the acid and the base by performance of some simple chemical calculations.

To carry out this calculations we need the all of the pieces of information that have been listed in the question such as the masses of the solution, the temperature of the solution in the initial and final states and so on.

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The ΔH of hydration for converting solid sodium acetate to sodium acetate trihydrate refers to the enthalpy change associated with the dissolution of the solid sodium acetate in water, leading to the formation of sodium acetate trihydrate.

The specific value for ΔH of hydration can vary depending on experimental conditions and the purity of the substances involved. However, in general, the process of hydrating sodium acetate is exothermic, meaning it releases heat.

The typical value for the ΔH of hydration of sodium acetate to form sodium acetate trihydrate is approximately -47 kJ/mol. This value indicates that the process is energetically favorable, and heat is released during the hydration process.

It's important to note that actual experimental values may vary, and it's always advisable to refer to specific literature or experimental data for precise and accurate values of ΔH of hydration under specific conditions.

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Density =mass/volume

=6/3

=2

The cube root of a number is the reverse of the cube of a number and it can be found by prime factorization method. The cube root of 8000 is 20.

Prime Factorization is the finding which prime numbers multiply together to make the original number. A prime number is a natural number greater than 1 that is not a product of two smaller natural numbers. A natural number greater than 1 that is not prime is called a composite number.

Prime factorization of 8000 is 2 × 2 × 2 × 2 × 2 × 2 × 5 × 5 × 5

Simplifying the above expression: \(2^{6}\) * \(5^{3}\)

Simplifying further: \(20^{3}\)

Therefore, the cube root of 8000 by prime factorization is (2 × 2 × 2 × 2 × 2 × 2 × 5 × 5 × 5)1/3 = 20.

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The empirical formula of the compound is CH.

To determine the empirical formula of a compound from its composition, we need to find the simplest whole-number ratio of the atoms in the compound.

Assuming a 100 gram sample, we have:

92.3 g C

7.7 g H

To convert these masses to moles, we need to divide by their respective atomic masses:

92.3 g C / 12.01 g/mol = 7.689 mol C

7.7 g H / 1.01 g/mol = 7.623 mol H

Next, we need to find the simplest whole-number ratio of C to H. We can do this by dividing both moles by the smaller of the two:

7.689 mol C / 7.623 mol H = 1.008

This means that the ratio of C to H is approximately 1:1. Therefore, the empirical formula of the compound is CH.

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--The given question is incorrect, the correct question is

"How do you determine the empirical formula of a compound that has the following composition: 92.3 percent C and 7.7 percent H?"--

In the reaction between a monosaccharide and a ferric ion, The carbonyl carbon is oxidized to a carboxyl group, the cupric ion is reduced.

Chemical reactions often involve color changes, temperature changes, gas evolution, or precipitate formation. Simple examples of everyday reactions are digestion, combustion, and cooking. The definition of reaction is a reaction. An example of a reaction is someone stopping their car at a stop sign. noun. response to stimuli.

The five basic types of chemical reactions are combination, decomposition, single exchange, double exchange, and combustion. By analyzing the reactants and products of a particular reaction, we can classify them into one of these categories. Some responses fit into multiple categories. It is modeled after the old Italian reaction, the French response, derived from the medieval Latin response (nominative to react). It is a noun of action formed in Late Latin from the past participle stem of the Latin reader.

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Significantly, pH 7 is the neutral pH, which is also the pH of pure water.Pure water has a pH of 6.14 at 100°C, which is considered "neutral" at this high temp on the pH scale.

The pH scale determines how acidic or basic water is.The range is 0 to 14, and 7 representing neutrality.Acidity is indicated by pH values below 7, whereas baseness is shown by pH values above 7.

The pH value of pure water is 7 at room temp (25 °C).The purity of water is 6.14 at a temperature of 100 degrees Celsius, which is lower than 7, but remains neutral just on pH scale.

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Answer:

it have been already balanced

2H2 + O2 = 2H2O.

Answer: (P2/P1)=(T2/T1)

(P2/1200.0kPa)=(387/283)

P2=(387K/283K) * (1200kPa)

P2= 1641kPa

Explanation:

An Oxygen Tank has a pressure of 1200 Kpa at 283K and when temp. is increased to 378 K then pressure will be 1,602.82 kpa.

From the ideal gas equation it is clear that pressure of gas is directly proportional to the temperature, and for this question required equation will be:

P₁/T₁ = P₂/T₂, where

P₁ = initial pressure of oxygen tank = 1200 kpa

T₁ = initial temperature of oxygen tank = 283 K

P₂ = final pressure of oxygen tank = ?

T₂ = final temperature of oxygen tank = 378 K

On putting values, we get

P₂ = (1200)(378) / (283) = 1,602.82 kpa

Hence resultant pressure of the oxygen tank is  1,602.82 kpa.

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Answer: the mole

Explanation:

The mole is the unit of amount in Chemistry.

It provides a bridge between the atom and the macroscopic amounts of material that we work with in the laboratory.

Answer:

Iodine

Explanation:

I hope this answer will help you

Answer:

silicon. ?

Explanation:

lmk if its right.

The inorganic substance with the chemical formula BaSO4 is barium sulfate (or sulphate). It is a tasteless, crystalline white substance that is insoluble in water.

A barium cation and a sulfate anion are the two elements that make up barium sulfate. There are four oxygen atoms joined to the sulfur. A sulfate salt of barium, known as BaSO4, is present in the mineral barite. It is a white crystalline substance that is soluble in strong acids but insoluble in water and alcohol.

Elements include both barium and bromine. Barium is a metal belonging to Group 2 of the modern periodic table, and bromine is a non-metal belonging to Group 17 (halogen).

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The study of substances that lack the element carbon but may contain the element hydrogen is called inorganic chemistry.

Inorganic chemistry is a branch of chemistry that focuses on the study of compounds that do not contain carbon-hydrogen (C-H) bonds. While organic chemistry primarily deals with carbon-based compounds, inorganic chemistry explores the properties, structures, and reactions of substances that include minerals, metals, nonmetals, and compounds lacking carbon.

This field encompasses a wide range of topics, including the behavior of inorganic compounds in various chemical reactions, the properties of transition metals, the study of minerals, coordination compounds, and the understanding of the electronic structures of inorganic substances. Inorganic compounds can exhibit diverse chemical behaviors and are essential in many industrial applications, environmental processes, and biological systems. By studying inorganic chemistry, scientists gain insights into the unique properties and applications of non-carbon-based compounds, expanding our understanding of the chemical world beyond organic molecules.

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Answer:

the sun beams down on the pool and heats it up top to bottom the deeper the colder

The volume of the sample of propane at STP is 0.62 mL.

Volume is the amount of space that a substance or object occupies.

To calculate the volume of gas at STP, we apply the formula below.

Formula:

Where:

Make V' The subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, the volume of the sample of propane at STP is 0.62 mL.
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Answer:

A. The largest value is 7 and the smallest value is 1. Find the difference. 7 - 1 = 6.

Explanation:

Dipole moment is present between atoms that have differences in their electronegativity. These atoms have unequal distribution of positive and negative charges.  

CO₂, BF₃, CCl₄, and BeF₂ have zero dipole moments because the atoms present in these molecules cancel each other's dipole moments and have overall net zero dipole moments.  

CO₂ is a linear and symmetrical molecule. The molecule has two C=O bonds, which are present in opposite directions. The dipole moment of one C=O bond cancels the dipole moment of the other.  

In BF₃, all three B-F bonds have slightly negative charges on fluorine atoms. The charges are balanced in the symmetrical triangular shape of the molecule. Therefore, the dipole moments of the three bonds cancel each other.  

Similarly, CCl₄ and BeF₂ have overall zero dipole moments because these have regular symmetrical structures.

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The total time required for the decay is approximately 1416.0 hours, which is closest to the given option C. 1006.9 hours.

Option (C) is correct.

To calculate the number of half-lives required for the decay. The half-life of 140 Ba is given as 283.2 hours.

First, we calculate the fraction of the original amount remaining after each half-life. Since the half-life represents the time it takes for half of the substance to decay, the fraction remaining after each half-life is 1/2.

To find the number of half-lives required to decay from 35 mg to 1.0 mg, we can set up the following equation:

(35 mg) * (1/2)ⁿ = 1.0 mg

Where 'n' is the number of half-lives.

Now, let's solve for 'n':

(1/2)ⁿ = 1.0 mg / 35 mg

(1/2)ⁿ = 0.02857

To find 'n', we can take the logarithm (base 1/2) of both sides:

n = log base 1/2 (0.02857)

Using the logarithmic property, we know that log base a (b) = log base c (b) / log base c (a):

n = log (0.02857) / log (1/2)

Using a calculator, we can find:

n ≈ 4.243

Since 'n' represents the number of half-lives, and we usually round up to the nearest whole number for half-life calculations, we get:

n ≈ 5

Therefore, it would take approximately 5 half-lives for the 35 mg sample of 140 Ba to decay to 1.0 mg.

To calculate the total time required, we multiply the half-life by the number of half-lives:

Total time = 283.2 hours * 5

Total time ≈ 1416 hours

Rounding to one decimal place, the total time required for the decay is approximately 1416.0 hours, which is closest to the given option C. 1006.9 hours.

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folic Acid

Folic acid, often known as folate, is a water-soluble B vitamin that is necessary for the generation of healthy red blood cells and the regular functioning of the brain system. Folate is present in numerous foods, including leafy green vegetables, legumes, nuts, and grains. Numerous processed goods, including breakfast cereals, breads, and rice, contain it as well. Folic acid is essential for pregnant women because it prevents birth abnormalities. It is also crucial for people of all ages since it helps maintain the health and normal operation of the body's cells. Folic acid is also essential for the production and repair of DNA, as well as the breakdown of specific proteins. Without appropriate folic acid, the body cannot produce red blood cells effectively, which can result in anemia. It is essential to consume adequate amounts of folic acid through diet or supplementation.

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Answer:

2.691*10^6 g

Explanation:

If 4. 52g of the precipitate is formed, there would be 1.8 grams of sodium chloride reacted.

First we should write the balance reaction

AgNO₃(aq)+NaCl(aq)→AgCl(s)⏐↓+NaNO₃(aq)

We can observe that there is a 1:1 reaction. As a result, producing 1 mole of the precipitate from 1 mole of sodium chloride (AgCl).

In this case,

we should find the moles of sodium chloride used by dividing the mass by the mass molar of sodium chloride.

Precipitate formed in terms of moles: 4.52g/143.32 g/mol

The amount of precipitate that produced was 0.0315 moles.

Thus, 0.0315 moles of NaCl and 0.0315 moles of precipitate were generated.

Therefore NaCl reaction mass is 0.0315 moles times 58.5 g/mol, or 1.8 g.

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In a liquid-liquid extraction (LLE) system with loratadine and pseudoephedrine sulfate, the choice of organic and aqueous phases is crucial for efficient separation.

Loratadine is a non-polar compound, while pseudoephedrine sulfate is more polar due to the presence of a sulfate group. To achieve effective separation, we need to choose a suitable organic phase and aqueous phase.

For the organic phase, a non-polar solvent such as diethyl ether, ethyl acetate, or chloroform can be used. These solvents have good solubility for loratadine. The non-polar organic phase will extract loratadine from the mixture, allowing for separation from the aqueous phase.

As for the aqueous phase, we need to choose a polar solvent that will selectively extract pseudoephedrine sulfate. Aqueous solutions of acids like hydrochloric acid (HCl) or sulfuric acid (H2SO4) can be used. The acidic conditions protonate the pseudoephedrine sulfate, making it more soluble in the aqueous phase.

To perform the extraction, the mixture of loratadine and pseudoephedrine sulfate is added to the LLE system consisting of the organic phase (non-polar solvent) and the aqueous phase (acidic solution). The mixture is then vigorously shaken to ensure thorough mixing and extraction.

After shaking, the phases are allowed to separate, with the more dense aqueous phase settling at the bottom and the less dense organic phase on top. The layers can be carefully separated, and each phase can be further processed to isolate the desired compounds.

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It is included in it's purpose or function that it will move the components at different speeds. The dyes which cover slowly. ... if two substances have similar chemical or physical properties they will behave the same as they travel through the medium and thus will not be separated.

Explanation:

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The problem is the relationship between speed and surface area

As they are moving with same speed they would have same surface area also same physical and chemical properties

This can't be separated by chromatography

Answer: Matter

Explanation:

Matter is anything that has volume and/or mass.