Answer:
Radon and helium both of which form during the decay of heavier elements in bedrock.
A 24 toy falls from 2 to 1 m. How much does the toys CPE change
GPE change:
\(\tt =24\times 9.8(2-1)=235.2~J\)
what is the likely cause of an excessive forward lean during the overhead squat assessment?
Excessive forward lean during the overhead squat assessment is likely caused by poor core stability or ankle mobility issues.
What factors can contribute to excessive forward lean during the overhead squat assessment?Excessive forward lean during the overhead squat assessment is a common problem that can be caused by a number of factors, including poor core stability, weak glutes, tight hip flexors, and ankle mobility issues.
When the core muscles are not properly engaged, the torso may lean forward to compensate, causing the individual to lose balance and stability. Similarly, when the ankle joint is restricted in its range of motion, the knees may be forced forward, which can cause the torso to lean forward as well.
Addressing these issues through targeted exercises and stretching can help improve overall movement quality and reduce the risk of injury.
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the power needed to accelerate a projectile from rest to its launch speed v in a time t is 36.0 w. how much power is needed to accelerate the same projectile from rest to a launch speed of 2v in a time of
So 144.0 W is required to accelerate the identical projectile from rest to a launch speed of 2v in time t.
What is projectile?Projectile motion is the motion of an item hurled or projected into the air that is only affected by gravity's acceleration. The item is known as a projectile, and its course is known as its trajectory. Projectile motion is a type of motion in which an item follows a parabolic path. The route taken by the item is referred to as its trajectory. When a force is applied at the start of the launch trajectory, projectile motion begins (after this the projectile is subject only to the gravity).
Here,
The power required to accelerate a projectile is given by the equation:
P = m * a²/t
where m is the mass of the projectile, a is its acceleration, and t is the time it takes to reach the desired speed. The launch speed, v, is related to acceleration, a, by the equation:
v = a * t
So we can substitute v = a * t into the first equation to get:
P = m * v²/t
If we want to find the power needed to accelerate the projectile from rest to a launch speed of 2v in a time of t, we can plug in v = 2 * v and solve for P:
P = m * (2 * v)² / t = 4 * m * v² / t
Since we know that the power needed to accelerate the projectile from rest to its launch speed v in a time t is 36.0 W, we can substitute that into the above equation to find the power needed to accelerate the projectile to a launch speed of 2v:
P = 4 * m * v² / t = 4 * 36.0 W = 144.0 W
So the power needed to accelerate the same projectile from rest to a launch speed of 2v in a time of t is 144.0 W.
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What does mass of an object depend on
Answer:
the inertia of an object
How much energy would be required to accelerate a particle of mass m from rest to a speed of
a) 0.5c
b) 0.9c
c) 0.99c
Express your anwser in multiples of the rest energy
The energy required to accelerate a particle to speeds of 0.5c, 0.9c, and 0.99c can be calculated as 1.15E₀, 2.29E₀, and 7.08E₀, respectively, where E₀ represents the rest energy of the particle.
Einstein's mass-energy equivalence states that the total energy (E) of an object is equal to its mass (m) multiplied by the speed of light (c) squared, E = mc². To calculate the energy required to accelerate a particle to a specific speed, we need to consider the relativistic effects.
To express the energy in terms of the rest energy (E₀), we divide the total energy (E) by mc², resulting in E/E₀. Thus, for speeds of 0.5c, 0.9c, and 0.99c, we can calculate the energy required as follows:
a) For a speed of 0.5c:
E/E₀ = (mc²)/(mc²) = 1E₀
The energy required is equal to the rest energy.
b) For a speed of 0.9c:
E/E₀ = γmc²/mc² = γ = 1/(1 - v²/c²)^(1/2)
Here, v = 0.9c, so γ = 2.29
The energy required is 2.29E₀.
c) For a speed of 0.99c:
E/E₀ = γmc²/mc² = γ = 1/(1 - v²/c²)^(1/2)
Here, v = 0.99c, so γ = 7.08
The energy required is 7.08E₀.
Therefore, the energy required to accelerate a particle to speeds of 0.5c, 0.9c, and 0.99c is 1.15E₀, 2.29E₀, and 7.08E₀, respectively, where E₀ represents the rest energy of the particle.
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when a battery is connected to a complete circuit, charges flow in the circuit almost instantaneously. explain.
When a battery is connected to a complete circuit, charges flow almost instantaneously due to the electric field established within the circuit components.
The battery acts as an energy source, creating a potential difference or voltage across its terminals. This potential difference drives the movement of charges, typically electrons, within the circuit.
Electrons experience a force from the electric field, causing them to move from the negative terminal to the positive terminal of the battery. As electrons flow through the circuit, they encounter resistance in the form of various components such as resistors, capacitors, and inductors. Despite this resistance, the charges continue to flow, allowing the circuit to function.
The flow of charges, or current, is maintained by the battery's continuous supply of energy. The speed at which charges flow is determined by the properties of the circuit, such as the resistance and capacitance. Although the flow of individual electrons may be slow, the electric field itself travels at nearly the speed of light. This allows for the almost instantaneous flow of charges within the circuit.
In summary, when a battery is connected to a complete circuit, the electric field established by the potential difference across the battery terminals causes charges to flow almost instantaneously throughout the circuit. The flow of charges encounters resistance from circuit components but is maintained by the continuous energy supply from the battery.
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If all the forces acting on an object are balanced then the net force acting on it is zero. True or, false?
Answer:
true
Explanation:
if all forces are equal then there would be no stronger force to give any net force so it would be zero
A ball starting from rest accelerates uniformly at 5.0 meters per second2 as it rolls 40. meters down an incline. How much time is required for the ball to roll the 40. meters
The time required for the ball to roll down the given distance is 4 seconds.
Given the data in the question;
Since the ball started from rest,
Initial velocity; \(u = 0\)Acceleration; \(a = 5.0m/s^2\)Distance traveled; \(s = 40m\)Time taken; \(t =\ ?\)To determine the time required for the ball to travel the given distance, we use the Second Equation of Motion:
\(s = ut + \frac{1}{2}at^2\)
Where s is distance traveled, u is initial velocity, a is acceleration and t is time taken.
We substitute our given values into the equation and solve for "t"
\(40m = [ 0*t ] + [ \frac{1}{2}\ *\ 5.0m/s^2\ *\ t^2 ]\\\\40m = 2.5m/s^2\ *\ t^2\\\\t^2 = \frac{40m}{2.5m/s^2}\\\\t^2 = 16s^2\\\\t = \sqrt{16s^2}\\\\t = 4s\)
Therefore, the time required for the ball to roll down the given distance is 4 seconds.
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The speed of sound in water is less than that in air. *
True
False
Answer:
The speed of sound in water is two times slower than that in air. Sound travels much faster in space than in water. Warmer water allows sound to travel faster so i think true
Explanation:
A thin uniform disk of mass m and radius r has a string wrapped
The magnitude of the weight of the disk is greater than the magnitude of the tension force of the string. ((c) \(F_{T} < F_{g}\))
How to analysis a rigid body on dynamical conditionA rigid body is a system whose geometry cannot be neglected and in which deformations due to external forces applied on the system are negligible.
In this question we need to establish a free body diagram with all critical forces and motion conditions. There are two external forces: (i) tension (\(F_{T}\)), (ii) weight (\(F_{g}\)), both in newtons.
The disk falls due to gravity and rotates around the string in a case of rolling, which combines rotation and translation. By Newton's laws of motion we have the following expression:
\(\sum F = -F_{g}+F_{T} = -m\cdot R\cdot \alpha\) (1)
Where:
\(m\) - Mass of the disk, in kilograms.\(\alpha\) - Angular acceleration, in radians per square second.By algebra we derive the following relationship between the two forces:
\(-F_{g} = -F_{T}-m\cdot R\cdot \alpha\)
\(F_{g} > F_{T}\)
Therefore, the magnitude of the weight of the disk is greater than the magnitude of the tension force of the string. ((c) \(F_{T} < F_{g}\)) \(\blacksquare\)
Remark
The statement is incomplete and poorly formatted. Correct and complete form is shown below:
A thin uniform disk of mass m and radius r has a string wrapped around its edge and attached to the ceiling. The bottom of the disk is at height 3R above the floor, as shown above. The disk is released from rest. The rotational inertia of a disk around its center is \(I = \frac{1}{2}\cdot M\cdot R^{2}\).
When released from rest, the disk falls and the string unwinds. The force that the string exerts on the disk is \(F_{T}\), and the gravitational force exerted on the disk is \(F_{g}\). Which of the following expression correctly relates \(F_{T}\) and \(F_{g}\) as the disk falls?
(a) \(F_{T} > F_{g}\), (b) \(F_{T} = F_{g}\), (c) \(F_{T} < F_{g}\)
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A sample of lead is heated up to a temperature of 100°C and then placed in a sample of water with an initial temperature of 5°C. If the mixture is thermally isolated from its surroundings, then it:
exchanges no thermal energy with the environment outside the system as it comes to a final temperature.
gains thermal energy from the environment outside the system as it comes to a final temperature.
both gains and loses thermal energy to the environment outside as it comes to a final temperature.
loses thermal energy to the environment outside as it comes to a final temperature.
None of these choices are correct.
If the mixture is thermally isolated from its surroundings, then it, loses thermal energy to the environment outside as it comes to a final temperature. The correct answer is d.
When the sample of lead is placed in the water, heat will flow from the lead to the water until they reach a common final temperature. Since the final temperature will be less than the initial temperature of the lead, heat must have flowed out of the lead into the surroundings, causing the lead to lose thermal energy to the environment outside the system.
Since the mixture is thermally isolated from its surroundings, no thermal energy is exchanged between the system (lead and water) and the environment during the process. However, heat can still flow within the system itself until thermal equilibrium is reached. Option d is correct.
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100 POINTS!! PLEASE HELP ASAP. WILL MARK BRANLIEST.
3.) You inspect a bottle of sunscreen to see what radiation it claims to block. You are looking for sunscreen that blocks dangerous radiation from the sun but does not make claims about other types of radiation. Which claim on a bottle would best meet these criteria?
a.Blocks all UV and infrared rays
b.Blocks harmful UVA and UVB radiation
c.Blocks the full spectrum of violet and ultraviolet radiation
d.“Blocks harmful UV and gamma rays
4.) Which description fits a type of electromagnetic radiation that could harm living cells?(1 point)
a. electromagnetic waves with very short wavelengths
b. waves with frequencies low enough that they are not visible
c. radio waves
d. blue light
5.) Which statement correctly describes how a tanning bed machine works?(1 point)
a. It gradually increases the ionizing energy of radiation to the maximum.
b. It matches the amount of sunlight that the skin can absorb..
c. It decreases production of the skin’s protective pigment, which causes damage.
d. It delivers an ionizing electromagnetic radiation called ultraviolet light.
7.) Tanning beds expose the body to a certain type of ultraviolet (UV) light. It has been claimed that this helps the body manufacture its needed vitamin D. Which evidence contradicts this claim?(1 point)
a. Both UVA and UVB light are produced by tanning beds.
b. The skin does not have the ability to absorb any type of UV light.
c. The body needs UVA light, and tanning beds deliver UVB light.
d. The body needs UVB light, and tanning beds deliver UVA light.
8.) Studies show that matter absorbs various types of electromagnetic radiation depending on the frequency and amount of energy they carry. Which sequence of types of electromagnetic radiation is arranged from that with the least to the most energetic photons?(1 point)
a. gamma rays, visible light, ultraviolet, X-rays
b. visible light, ultraviolet, X-rays, gamma rayst
c. ultraviolet, X-rays, gamma rays, visible light
d. X-rays, gamma rays, visible light, ultraviolet
Answer:
the answer is equal to visible light , ultraviolet, x-rays, gamma rayst
The sequence of types of electromagnetic radiation is arranged from that with the least to the most energetic photons will be visible light , ultraviolet, x-rays, gamma rays.
What is electromagnetic radiation?Electromagnetic radiation is a type of energy that is transmitted in incident photons as both magnetic and electric waves.
Electromagnetic radiation has a spectrum with varying wavelengths and frequencies, which gives it different properties.
Electromagnetic radiation is a type of energy that travels in packets of energy called photons as both electrical and magnetic waves.
Wave-particle duality is the name given to this phenomenon. This is a notion that defines how a wave behaves whether it behaves like particles, waves, or both particles and waves.
Hence the sequence of types of electromagnetic radiation is arranged from that with the least to the most energetic photons will be visible light , ultraviolet, x-rays, gamma rays.
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A person walks clockwise a three-quarter circle of radius 5m from point A to point B. What distance
did the person travel?
23.55 m
7.07 m south west
7.07 m north east
7.07 m north west
Answer:
circumference of circle = 2 π R
S (distance traveled) = 3/4 * 2 π R
S = .75 * 2 * π 5 = 23.55 m
two locations have the same average wind velocity. location 1 has a wind velocity of 5 m/s for 12 hours per day and a wind velocity of 15 m/s for 12 hours per day, while location 2 has a wind velocity of 0 m/s for 12 hours per day and 20 m/s for 12 hours per day. which of the above location produces more energy per day for identical wind turbines?
Both location 1 and location 2 produces equal energy per day for identical wind turbines.
average velocity of location 1 is=wind velocity of initial 12 hours + wind velocity of final 12 hours.
It means, in initial 12 hours velocity is =5×12×60×60=216000m/sec
Similarly, velocity of wind after 12 hours =15×12×60×60=648000m/sec.
So, average velocity at location 1=(216000+648000)/24×60×60
v=864000/86400=10m/sec
Similarly, we find average velocity at location 2
In initial 12 hours velocity is =0m/sec
and in final 12 hours=20m/sec or 20×12×60×60=864000m/sec.
So average velocity of wind at location 2=(8640000)/24×60×60=10m/sec.
Since, we have velocity, and we are also given wind turbines at both of locations is identical. It means kinetic energy of wind at both locations will be equal.
Hence, both locations produces equal energy.
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12.0 V car battery has a voltage drop of 3.4 V when the starter draws 93 A of current. What is the resistance of the starter? O 88 m2 84 mg O 80 m2
Answer:
\(R_s = 0.093 \Omega\)
Explanation:
Voltage of the car battery = 12.0 V
Voltage drop in the battery = 3.4 V
The remainder of the voltage is the starter voltage, that is:
Starter voltage = Initial battery voltage - voltage drop
Starter voltage = 12.0 - 3.4
Starter voltage, \(V_{s}\) = 8.6 V
Current drawn by starter, \(I_s\) = 93 A
According to Ohm's law: \(V_s = I_s R_s\)
Starter Resistance, \(R_s\) = \(V_s/I_s\)
\(R_s = 8.6/93\\R_s = 0.093 \Omega\)
What is the momentum of a 10,000 kg railroad car moving at 0.001 m/s?
Answer:
10 kg.m/s
Explanation:
momentum: p=mv
10,000 Kg * 0.001= 10kg.m/sYou whirl a 2-kg body attached to a 1-meter cord around your head in a nearly horizontal circle with a speed of 4 m/s. the tension in the cord is:________
The tension in the cord is equal to centripetal force which is 32 newton.
We need to know about centripetal force to solve this problem. When an object moves in a circular motion, the object is experiencing centripetal force. The magnitude of centripetal force is
Fc = m . v²/R
where Fc is the centripetal force, m is mass, v is velocity and R is the radius.
From the question, we know that
m = 2 kg
v = 4 m/s
R = 1 m
The tension in the cord is equal to centripetal force
T = Fc
T = m . v²/R
T = 2 . 4² / 1
T = 32 N
Hence, the tension in the cord is 32 newton.
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It has been known for many years that ceramics can conduct electricity. In 2008, scientists found a ceramic material that can conduct electricity with no resistance at 133 K. What is the most important significance of this 2008 finding?
This is a lower temperature than Onnes’s experiment, and it will allow for a broader use of superconductors.
This is a higher temperature than Onnes’s experiment, and it will allow for a broader use of superconductors.
Materials that can conduct electricity with no resistance are new and can allow for new materials to be made.
Ceramic materials have been known to be able to conduct electricity prior to year 2008.
Answer:
mercury
Explanation:
edge 2020
A current filament of 4 A is along the z – axis in the direction in free space. Determine the magnetic flux passing through defined by 0. 02 < r < 0. 03 m and 0 < z < 3. Permeability of free space,
The magnetic flux passing through defined by 0.02 < r < 0.03 m and 0 < z < 3 is `8π × 10⁻⁷ Wb`
Permeability of free space is given by `μ0 = 4π × 10⁻⁷ T m A⁻¹`
Formula used to calculate the magnetic flux passing through the defined area is as follows:
`ΦB = μ0 * I * (Θ2 - Θ1) / 4π`
Where
I = current
Θ1 = lower limit of angle
Θ2 = upper limit of angle
For the given problem, current filament is along the z – axis in the direction, thus the angle Θ1 and Θ2 will be 0 and 2π respectively.
The distance between 0.02 m and 0.03 m is 0.01 m, the mean radius of the area will be`(0.03 + 0.02) / 2 = 0.025 m`
The formula for calculating the magnetic flux through the defined area is`ΦB = μ0 * I * (Θ2 - Θ1) / 4π`
From the question, we know that;:
μ0 = `4π × 10⁻⁷ T m A⁻¹`
I = 4A
Θ1 = 0
Θ2 = 2π
The formula becomes`ΦB = (4π × 10⁻⁷) * 4 * (2π - 0) / 4π``ΦB = 8π × 10⁻⁷ Wb`
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Under what condition is pressure altitude and density altitude the same value?
Pressure altitude and density altitude are same when temperature is standard.
When is the pressure altitude and density altitude the same value?Under standard atmospheric condition, air at each level in atmosphere has specific density and under standard conditions, pressure altitude and density altitude identify the same level.
As altitude increases, then the amount of gas molecules in the air decreases. Air becomes less dense than the air nearer to sea level. This is what meteorologists and mountaineers mean by thin air that exerts less pressure than air at a lower altitude.
When pressure increases, then density increases and when pressure decreases, then density also decreases.
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whats ur funniest thing u have ever done in ur life mine was me sending a picture of me and my friend at the beach to my principle
If an airplane with a mass of 4,536 kg has gravitational potential energy of 1000 kilojoules, what is its height?
Answer:
The height is 22,472.84 m
Explanation:
Gravitational potential energy is the type of energy that is stored in the gravitational field. In other words, the gravitational potential energy as the energy that a body possesses due to the fact of being under the action of gravity, that is, the energy associated with an object subjected to force, weight, and weight is called gravitational potential energy. that is at a certain height with respect to a reference level.
The greater the weight of a body, the greater the gravitational potential energy and, considering the effect of this variable together with that of the height h at which the object is, the gravitational potential energy is:
Ep = m*g*h
In this case:
Ep= 1,000 kJ= 1,000,000 J (being 1 kJ=1,000 J)m=4.536 kgg= 9.81 \(\frac{m}{s^{2} }\)h=?Replacing:
1,000,000 J=4.536 kg* 9.81 \(\frac{m}{s^{2} }\) *h
Solving:
\(h=\frac{1,000,000 J}{4.536 kg*9.81\frac{m}{s^{2} } }\)
h= 22,472.84 m
The height is 22,472.84 m
Supriya has a pre-paid electricity connection at home. On a sultry Sunday afternoon, she checks that she only has ₹9 left in the balance. She wants to use the air conditioner (AC), rated at 1.2 kW. The price of electricity is ₹10 /unit in her area. How long can she run the AC before her balance is over and the power runs out?
Answer: 0.75 hour(s) or 45 minutes
Explanation:
1 unit of electricity = 1kwh
Amount of energy consumed by 1kw load in one hour
Price per unit = ₹10
Air conditioner rating(power) = 1.2Kw
Given that balance = ₹9
Therefore, supriya's total energy cost = energy balance = ₹9
Total energy cost = power in kilowatt × time of operation (in hour) × cost per unit
₹9 = 1.2kw × time × ₹10
₹9 = 12 × time
Time = 9 / 12
Time = 0.75 hours
0.75 × 60 = 45 minutes
An object with a mass of 2.0 kg accelerates 2.0 m/s 2when an unknown force is applied to it. What is the amount of force?
Answer:
4 N
Explanation:
mass = 2 kg
acceleration = 2 m/s^2
Force = mass * acceleration
= 2 *2
= 4 N
PLEASE HELP ASAP THIS IS DUE TMR!!!!!!!
The table for the mass of the bicyclist and kinetic energy, and Chloe's speed and kinetic energy, gives the attached graphs of kinetic energy and mass and Chloe's kinetic energy and her speed.
The relationship shown on the graph of the kinetic energy to mass shows that at constant velocity, v, the kinetic energy is directly proportional to the mass.
The relationship shown in the graph of Chloe's kinetic energy to velocity indicates that the kinetic energy varies quadratically with the velocity as the graph is shaped like half of a parabola like the graph of a quadratic equation
What is the formula that gives the relationship between kinetic energy and mass?Please find attached the graph of the kinetic energy versus mass for the bikers, showing the mass of each biker using a combination graph of a line graph and a column chart.
Please find the graph of Chloe's kinetic energy versus her speed created from the given table using a spreadsheet application
The relationship shown in each graph are as follows;
K.E. = 0.5•m•v²
Therefore, at constant velocity, v, kinetic energy is directly proportional to the mass, and as the mass increases, the kinetic energy increases proportionately
The graph of kinetic energy to mass therefore increases from left to right as mass increases forming the approximately straight red line.
Second graph (kinetic energy to mass)
The relationship between kinetic energy and Chloe's velocity, can be expressed mathematically as follows, given that her mass is constant
K.E. = 0.5•m•v²
K.E. = (0.5•m)•v²
The quantity, (0.5•m), c is a constant, therefore;
K.E. = c•v²
Given that the minimum velocity, v, of Chloe in the given direction can be taken as 0, the graph of kinetic energy to velocity increases quadratically (in the form of half of a parabola) from left to right as the velocity increases.
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The stars of the Milky Way are all near a great circle on the Celestial Sphere. This great circle?
A. is the Celestial Equator.
B. is the Ecliptic.
C. passes through the Celestial Poles.
D. is none of the other things listed here.
It is D. is none of the other things listed here. The stars of the Milky Way are all near a great circle on the Celestial Sphere. This great circle is called the milky circle
The Milky Circle is a great circle on the celestial sphere that is defined by the stars of the Milky Way. It is visible to the n_aked eye and is one of the most recognizable features of the night sky, stretching across the entire sky from horizon to horizon. It is composed of millions of stars, all of which reside in the same galactic plane and are moving in the same direction around the galactic center. The Milky Circle is a beautiful sight to behold, especially during a clear night, when it appears as a wide band of light. It is a reminder of the vastness of the universe and the beauty of the night sky. It is also a great way to orient oneself in the night sky, as its stars form a familiar pattern that can help one find constellations and other objects.
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Imagine you are running PE class. You run the first 1000 meters in 3 minutes and then get tired and run the last 600 meters in 5 minutes. What was your *average* speed?
Answer:
Va = 3.77 [m/s]
Explanation:
We know that speed is defined as the relationship between the distance traveled in a given time.
v = L/t
where:
v = speed [m/s]
L = distance = 1000 [m]
t = time = 3 [min] = 180 [s]
Therefore the first speed is:
v = 1000/180
v = 5.55 [m/s]
Now the second velocity:
t = 5 [min] = 300 [s]
v = 600/300
v = 2 [m/s]
The average speed is calculated by the sum of both speeds divided by two.
Va = (5.55 + 2) /2
Va = 3.77 [m/s]
The tires of a car make 62 revolutions as the car reduces its speed uniformly from 90.0 km/h to 59.0 km/h. The tires have a diameter of 0.86 m.(A) What was the angular acceleration of the tires? (B) If the car continues to decelerate at this rate, how much more time is required for it to stop? (C) If the car continues to decelerate at how far does it go? Find the total distance.
A) Angular acceleration = -2.47 rad/s²
B) 23.54 seconds
C) The total distance covered = 294.23m
Explanations:The number of revolutions = 62
Angular distance, θ = 62 x 2π
θ = 62 x 2 x 3.142
θ = 389.608 radians
Diameter, d = 0.86 m
Radius, r = d/2 = 0.86/2
r = 0.43m
Initial velocity, v₁ = 90 km/h = 90 x (1000/3600)
v₁ = 25 m/s
Angular velocity, w₁ = v₁ / r
w₁ = 25/0.43
w₁ = 58.14 rad/s
Final velocity, v₂ = 59 km/h = 59 x (1000/3600)
v₂ = 16.39 m/s
Angular velocity, w₂ = v₂ / r
w₂ = 16.39 / 0.43
w₂ = 38.12 rad/s
Using the equation of motion:
\(\begin{gathered} w^2_2=w^2_1\text{ + 2}\alpha\theta \\ 38.12^2=58.14^2\text{ + 2}\alpha(389.608) \\ 38.12^2-58.14^2=\text{ }779.216\alpha \\ 779.216\alpha\text{ = }-1927.1252 \\ \alpha\text{ = }\frac{-1927.1252}{779.216} \\ \alpha\text{ = }-2.47rad/s^2 \end{gathered}\)Angular acceleration = -2.47 rad/s²
B) Amount of time required for the car to stop if it continues to decelerate at this rate
Initial angular speed, w₁ = 58.14 rad/s
When the car stops, final angular speed, w₂ = 0 rad/s
Using the equation of motion below:
\(\begin{gathered} w_2=w_1+\text{ }\alpha t \\ 0\text{ = 58.14 + (-2.47)t} \\ -2.47t\text{ = -58.14} \\ t\text{ = }\frac{-58.14}{-2.47} \\ t\text{ = }23.54\text{ seconds} \end{gathered}\)C) The total distance
Use the equation of motion below:
\(\begin{gathered} S=v_1\text{t + }\frac{1}{2}at^2 \\ a\text{ = }\alpha r \\ a\text{ = (-2.47)(0.43)} \\ a\text{ = }-1.0621m/s^2 \end{gathered}\)\(\begin{gathered} S=v_1\text{t + }\frac{1}{2}at^2 \\ S\text{ = }25(23.54)+0.5(-1.0621)(23.54)^2 \\ S\text{ = }588.5-294.27 \\ S\text{ = }294.23\text{ m} \end{gathered}\)The total distance covered = 294.23m
A train travels at a speed of 30 m/s. The train starts at an initial position of 1000 meters and travels for 30 seconds. What is its final position?
Answer please
Answer:
1900 metres
Explanation:
Given that a train travels at a speed of 30 m/s. The train starts at an initial position of 1000 meters and travels for 30 seconds.
The parameters to be considered are:
Speed = 30 m/s
Time = 30 seconds
Speed = distance/time
Substitute the parameters into the formula
30 = distance / 30
Cross multiply
Distance = 30 × 30
Distance = 900 m
Since the train started from a position of 1000 m , the final position will be:
Final position = 1000 + 900
Final position = 1900 metres
Professor steel wants to know how infants of different ages respond when left with a stranger. The most efficient approach to explore this topic would be to conduct a:
A). Case study
B). Psychological test
C). Laboratory observation
D). Naturalistic observation
The most efficient approach for Professor Steel to explore the topic of how infants of different ages respond when left with a stranger would be to conduct a:
Option C). Laboratory observation
Laboratory observations are controlled experiments that allow researchers to closely monitor and control variables in order to study the behavior of their subjects. In this case, Professor Steel can control the age of the infants and the length of time they are left with a stranger in order to accurately assess their responses. This approach would provide more accurate and reliable data than a case study, psychological test, or naturalistic observation, which may be influenced by outside factors. By conducting a laboratory observation, Professor Steel can gain a better understanding of how infants respond to being left with a stranger and use this information to further his research.
More information about laoratory experiment here: https://brainly.com/question/12053296
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