The coordinates of the point on the directed line segment from (-4, 7) to (7, -4) that partitions the segment into a ratio of 6 to 5 are (2, 2).
Linear interpolation is a method of finding a point on a line segment by using its distance from the two endpoints. In this case, the point that divides the segment into a ratio of 6 to 5 is 6/11 of the distance from (-4, 7) to (7, -4) and 5/11 of the distance from (7, -4) to (-4, 7).
Using the distance formula, we can find the distance between the two endpoints:
distance = √((7 - (-4))² + (-4 - 7)²) = √(11² + (-11)²) = √(242)
Now we can find the coordinates of the point that divides the segment into a ratio of 6 to 5:
To find the x-coordinate, we need to find 6/11 of the distance from -4 to 7, which is:
-4 + (6/11)*(7 - (-4)) = -4 + (6/11)*11 = 2
So the x-coordinate of the point we are looking for is 2.
To find the y-coordinate, we need to find 5/11 of the distance from 7 to -4, which is:
7 + (5/11)(-4 - 7) = 7 + (5/11)(-11) = 2
So the y-coordinate of the point we are looking for is 2.
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HELP ME BEFORE I DIE!
Your adjacent is 3, your opposite is 4, and you have a 90 degree angle. Find the value of cos V rounded to the nearest hundredth, if necessary.
Answer:
0.6 or \(\frac{3}{5}\)
Step-by-step explanation:
Using the Pythagorean theorem (\(a^{2} +b^{2} =c^{2}\)) we get that the hypotenuse is 5.
so the cos V is adjacent over the hypotenuse. so if adjacent is 3 and hypotenuse is 5, the answer is \(\frac{3}{5}\) which equals 0.6 in decimal form.
Which expression means five times the sum of b and two
Answer:
2334
Step-by-step explanation:
hi
Ivan has already prepared 5 kilograms of dough and will continue preparing 8 kilograms of dough every hour. How many hours did Ivan work if he prepared 21 kilograms of dough?
the total dough need to prepare is 21
the dough already prepared is 5
so the remaining dough is 21 - 5 = 16 kg
the rate of dough is 8 dough per hour
so 16/8 = 2
means 16 dough will prepare in 2 hrs
so the time is 2 hrs
a study randomly assigned college students to drink either water or 2 cans of red bull. immediately afterwards, all students took the gre. the researchers concluded that red bull has little to no effect on gre scores. which result most closely matches this conclusion?
In summary, the researchers concluded that Red Bull has little to no effect on GRE scores because there was no statistically significant difference between the scores of the two groups. This indicates that Red Bull does not have a significant impact on test scores.
The result that most closely matches the conclusion that drinking two cans of Red Bull has little to no effect on GRE scores is that there was no statistically significant difference in the scores between the students who drank the Red Bull and those who drank the water. This means that the scores for both groups were about the same and there was no correlation between the two variables.
This conclusion is supported by the fact that no differences were found between the two groups. Additionally, this finding could be further supported by statistical tests such as a two-tailed t-test which would determine whether or not the difference between the two groups is statistically significant.
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Please, i need help for part b, my hw is due tomorrow, please help, any help will be appreciated,
The graph shows the speed of a vehicle during the final 50 seconds of a journey.
At the start of the 50 seconds the speed is k metres per second.
The distance travelled during the 50 seconds is 1.7 kilometres.
b) Work out the value of k.
Answer:
(a) 34 m/s
(b) k = 42.5
Step-by-step explanation:
Part (a)\(\boxed{\sf Speed=\dfrac{Distance}{Time}}\)
Given:
Distance = 1.7 km = 1700 mTime = 50 sSubstitute the values into the formula to find the average speed :
\(\implies \sf Speed = \dfrac{1700}{50}=34\;m/s\)
Part (b)The area under a speed-time graph represents the distance traveled.
Separate the area under the graph into a rectangle and a triangle, where:
The area of the rectangle represents the distance traveled in the first 30 seconds of the journey.The area of the triangle represents the distance traveled in the last 20 seconds of the journey.\(\boxed{\textsf{Area of a rectangle $=$ width $\times$ length}}\)
Therefore, the distance traveled in the first 30 seconds of the journey is:
\(\implies \sf 30k\)
\(\boxed{\textsf{Area of a triangle $=\dfrac{1}{2} \times$ base $\times$ height}}\)
Therefore, the distance traveled in the last 20 seconds of the journey is:
\(\implies \sf \dfrac{1}{2}(20)k\)
Therefore:
\(\implies \sf 30k+\dfrac{1}{2}(20)k=1700\)
\(\implies \sf 30k+10k=1700\)
\(\implies \sf 40k=1700\)
\(\implies \sf \dfrac{40k}{40}=\dfrac{1700}{40}\)
\(\implies \sf k=42.5\)
Answer:
k is 42.5 m/s
Step-by-step explanation:
we need to calculate the distance that was covered when the speed was k m/s
from the graph k m/s was travelled for 30 seconds
the entire time for the journey was 50 seconds
the entire journey was 1700 m
Alternatively the area under the graph represents the total distance covered.
Area of a trapezium = 1/2(a+b)h
= 1/2( 30+50)k
= 40k
we equate it to the total distance covered
1700 = 40k.
k = 42.5
Thus k is 42.5 m/s
CLASS
Joanna had four candy bars
. She wanted to find out how many people could share the bars if each person
received- of a bar. Use the candy bar picture below to help you.
What is the answer to Joanna's question?
4.
Complete question :
Joanna had four candy bars. She wanted to find out how many people could share the bars if each person received 2/3 of a bar. Use the candy bar picture below to help you.
What is the answer to Joanna's question?
Kindly find attached candy bar picture below
Answer:
6 people
Step-by-step explanation:
From the picture, each candy bar has already been divided equally into 3. Since we have 4 candy bars. The total number of divisions we have is ; (3 * 4 = 12 candy units).
Since each person is taking 2/3 of a bar, this is equal to 2 units of candy
Hence, number of people who could share the bar :
Total units or division / units person
12 / 2
= 6 people
Solve x² - 11x - 42 = 0
O x = -3 and 14
O x = -14 and 3
O x = -6 and -7
O x = 6 and 7 < Previous
Answer: a = 1, b = -11, and c = -42.
Step-by-step explanation:
The solutions to the equation x² - 11x - 42 = 0 are x = -6 and x = 7.
You can find the solutions by factoring the equation, or by using the quadratic formula: x = (-b ± √(b² - 4ac)) / 2a.
In this case, a = 1, b = -11, and c = -42.
point a is at (2,-8) and point c is at (-4,7) find the coordinates of point b on \overline{ac} ac start overline, a, c, end overline such that the ratio of ababa, b to bcbcb, c is 2:12:12, colon, 1.
The coordinates of point B on line segment AC are (8/13, 17/26).
To find the coordinates of point B on line segment AC, we need to use the given ratio of 2:12:12.
Calculate the difference in x-coordinates and y-coordinates between points A and C.
- Difference in x-coordinates: -4 - 2 = -6
- Difference in y-coordinates: 7 - (-8) = 15
Divide the difference in x-coordinates and y-coordinates by the sum of the ratios (2 + 12 + 12 = 26) to find the individual ratios.
- x-ratio: -6 / 26 = -3 / 13
- y-ratio: 15 / 26
Multiply the individual ratios by the corresponding ratio values to find the coordinates of point B.
- x-coordinate of B: (2 - 3/13 * 6) = (2 - 18/13) = (26/13 - 18/13) = 8/13
- y-coordinate of B: (-8 + 15/26 * 15) = (-8 + 225/26) = (-208/26 + 225/26) = 17/26
Therefore, the coordinates of point B on line segment AC are (8/13, 17/26).
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13. In the figure, PSR is a straight line. Find RSQ and PQS.
The angle RSQ = 105° and angle PQS = 78°
Given,
In the question:
In the figure,
PSR is a straight line .
To find the angle RSQ and angle PQS.
Now, According to the question;
In ΔQRS,
we know that :
Sum of angle of triangle is 180 degree.
Angle (SQR + QRS + RSQ) = 180°
In the figure,
Angle (23° + 52° + RSQ) = 180°
75° + ∠RSQ = 180°
∠RSQ = 180 - 75
∠RSQ = 105°
We have to find the ∠PQS
Now, PSR is a straight line
In Triangle PSQ
Find the ∠S
105 + ∠S = 180° (Linear Pair)
∠S = 75°
In ΔPQS
Angle(SPQ + PQS + QSP) = 180°
Angle(27° + PQS + 75° ) = 180°
∠PQS = 180 - 102
∠PQS = ∠78°
Hence, The angle RSQ = 105° and angle PQS = 78°
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Suppose that tuition at a state college was $3,500 per year in 1995 and has been increasing at a rate of $225 per year. Write an equation to model the cost of tuition as a function of time. Use that equation to predict the cost of tuition in the year 2007.
Answer:
$7384.94Step-by-step explanation:
step one:
let us calculate the percentage increase
(225/2)*100
=0.06428*100
=6.42%
We know that the expression for exponential formula is
\(y = ab^x.\)
where
a = the amount before measuring growth or decay
= $3500
r = decay rate = 6.42%= 0.0642
x = number of time intervals that have passed that is between 1995 and 2007= 12years
since this problem is on groth we are going to replace "b" with (1+r),
hence the formula to model the cost is
\(y = a(1+r)^x.\)
\(y=3500(1+0.0642)^1^2 \\\\y=3500(1.0642)^1^2 \\\\y=3500*2.109983 \\\\y=7384.94\)
The cost of tuition in the year 2007 (12 years later) would be
$7384.94
The number of ounces of soda that a vending machine dispenses per cup is normally distributed with a mean of 13.5 ounces and a standard deviation of 3.5 ounces. Find the probability that between 13 and 14.4 ounces are dispensed in a cup.
The probability that between 13 and 14.4 ounces are dispensed in a cup is approximately 0.3815 or 38.15%.
To find the probability that between 13 and 14.4 ounces are dispensed in a cup, we need to first standardize the values using the formula:
z = (x - μ) / σ Where x is the value we want to find the probability for, μ is the mean, and σ is the standard deviation.
For x = 13, we get: z = (13 - 13.5) / 3.5 = -0.14 For x = 14.4, we get: z = (14.4 - 13.5) / 3.5 = 0.26
We can then use a standard normal distribution table or a calculator to find the probability of the values falling between these two z-scores. Using a calculator, we can find: P(-0.14 < z < 0.26) = 0.3815
Therefore, the probability that between 13 and 14.4 ounces are dispensed in a cup is approximately 0.3815 or 38.15%.
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PLSS helpp
btw have a nice day
an equation of the line normal to the graph of y=x^3+3x^2+7x-1
this equation is only valid at the point (a, b) where we found the slope of the normal line. To find the equation of the normal line at a different point, we would need to repeat this process with new values of a and b.
To find the equation of the line normal (perpendicular) to the graph of y = x^3 + 3x^2 + 7x - 1 at a point (a, b), we need to determine the slope of the normal line at that point.
The slope of the tangent line to the curve at (a, b) is given by the derivative:
f'(x) = 3x^2 + 6x + 7
So the slope of the tangent line at x = a is:
m = f'(a) = 3a^2 + 6a + 7
The slope of the normal line is the negative reciprocal of the slope of the tangent line, so:
m_n = -1/m = -1/(3a^2 + 6a + 7)
Now we have the slope of the normal line at (a, b), and we just need to find the equation of the line in point-slope form, using the point (a, b):
y - b = m_n(x - a)
Substituting the expression for m_n, we get:
y - b = (-1)/(3a^2 + 6a + 7)(x - a)
Multiplying both sides by 3a^2 + 6a + 7 to eliminate the fraction, we get:
(3a^2 + 6a + 7)(y - b) = -(x - a)
Expanding and rearranging, we get the equation of the line normal to the graph of y = x^3 + 3x^2 + 7x - 1 at (a, b):
(3a^2 + 6a + 7)y = -x + (3a^2 + 6a + 7)b + a
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which of these is a factor in this expression? 7z^4-5+10(y^3+5)
(7z⁴ -5)(y³ + 5)is factor in this expression. They are all individual values or variables that contribute to the expression's overall calculation.
What is factors?Factors are numbers that can be multiplied together to create a product. Factors are two or more numbers that are multiplied to produce a product. The product of two factors is called a multiple. Examples of common factors are: 2, 3, 5, 10, and 20. A factor is any number, positive or negative, that can be divided into another number without a remainder.
Factors are used to solve equations and simplify fractions. Factors can be used to help solve problems in algebra, calculus, and other areas of mathematics. Factors are also important in understanding prime numbers and composite numbers. Knowing the factors of a number can help you identify prime and composite numbers.
⇒ 7z^4-5+10(y^3+5)
⇒ 7z⁴ -5 + 10 (y³ + 5)
⇒ 7z⁴ -5 (y³ + 5)
⇒ (7z⁴ -5)(y³ + 5)
Thus, (7z⁴ -5)(y³ + 5)is factor in this expression. They are all individual values or variables that contribute to the expression's overall calculation.
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Full question:
Which of these is a factor in this expression- 7z^4-5+10(y^3+2).
Choices-
A- 7z^4-5,
B- 10(y^3+2)
C = -5+10(y^3+2)
D= (y^3+2)
The perimeter of a train ticket is 60 centimeters. It is 17 centimeters long. How tall is it?
If the perimeter of the train ticket is 60 centimeters and it's length is 17 centimeter long it's height is 13 centimeter
What is perimeter of a rectangle?A perimeter is a closed path that encompasses, surrounds, or outlines either a two dimensional shape or a one-dimensional length.
To find the perimeter of a rectangle we add all this sides together. This means that the perimeter of a rectangle is given as ;
P = l+l+w+w
P= 2(l+w)
60 = 2( 17+w)
60 = 2( 17+w)
17+w= 60/2
17+ w = 30
w = 30-17
w = 13cm
Therefore the height of the train ticket is 13cm
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The buses in a city are driven a total of 4,426 miles each day.How many miles are the buses driven in 8 days?
Answer:
35,408 miles in 8 days.
Step-by-step explanation:
4,426 x 8 = 35,408
In order to investigate treatments for morbid obesity, obese subjects satisfying fairly strict requirements were randomly assigned to one of three groups: gastric bypass surgery; participation in a diet and exercise program; or both gastric bypass surgery and participation in the diet and exercise program. Researchers carefully observed the amount of weight lost five years after the study began. Reference: Ref 9-1 This study uses the principles of A. randomization. B. confounding. C. blocking. D. All of the above Which of the following are principles of experimental design?
A. randomization B. replication C. blinding D. All of the above
Since all three principles of experimental design are likely to have been used in the study described, Therefore option D is correct.
All of the above are principles of experimental design. Randomization helps to ensure that groups are similar in all aspects except for the treatment received, reducing the effects of confounding variables. Replication allows for assessing the variability and consistency of results. Blinding reduces the risk of bias by preventing participants or researchers from knowing which treatment was received. The study described in the question uses all of these principles of experimental design.
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All of the following are see-saw except (molecular Geometry)IF4+1IO2F2−1SOF4SF4XeO2F2
The molecular geometry of IF₄+ and IO₂F₂- are both see-saw.
However, SOF₄, SF₄, and XeO₂F₂ have different geometries - trigonal bipyramidal, square planar, and square pyramidal respectively. Therefore, the correct answer is "All of the following are see-saw except molecular geometry."
This question is testing the understanding of molecular geometry and its relationship to the number of lone pairs and bonding pairs around the central atom.
See-saw geometry has four bonding pairs and one lone pair around the central atom, while the other three compounds have different arrangements.
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complete question:
The molecular geometry of which of the following are see-saw.(molecular Geometry)
IF4+1
IO2F2−1
SOF4
SF4
XeO2F2
Gia made a garden stone shaped like a regular octagon with the dimensions shown. Find the area of the octagon.
5.5 in.
4.6 in
The area of the garden which is same as the shape of an octagon would be = 101.2in².
How to calculate the area of an octagon?To calculate the area of an octagon the formula that can be used is given below;
Area of an octagon = (number of sides × length of one side × apothem)/2
For an octagon = 8 sides
apothem = 5.5in
Length of one side = 4.6in
Area = 8×4.6×5.5/2
= 202.4/2
= 101.2in²
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What is the rule for the following geometric sequence?64,-32,16,-8
The rule for the geometric sequence is Uₙ = (-1)ⁿ⁺¹2⁷⁻ⁿ
What is a geometric sequence?A geometric sequence is a sequence in which consecutive terms are in a common ratio.
How to find the rule for the geometric sequence?Since we have the geometric sequence 64,-32,16,-8, the nth term of a geometric sequence is given by Uₙ = arⁿ⁻¹ where
a = first term and r = common ratio.Since in the geometric sequence, the first term U₁ = a = 64 and the second term U₂ = ar²⁻¹ = ar = -32, then the common ratio r is
r = U₂/U₁
= ar/a
= -32/64
= -1/2
Since a = 64 and r = -1/2
substituting these into Uₙ, we have
Uₙ = arⁿ⁻¹
Uₙ = 64(-1/2)ⁿ⁻¹
Uₙ = 64(-1/2)ⁿ/(-1/2)⁻¹
Uₙ = 64(-1/2)ⁿ/(-2)
Uₙ = -128(-1/2)ⁿ
Uₙ = (-1)(-1)ⁿ128(1/2)ⁿ
Uₙ = (-1)(-1)ⁿ2⁷(1/2)ⁿ
Uₙ = (-1)ⁿ⁺¹2⁷⁻ⁿ
So, the rule is Uₙ = (-1)ⁿ⁺¹2⁷⁻ⁿ
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When Coach Orozco opened the badminton sets he purchased, he found he had less than 48 badminton racquets. Each badminton set had 4 racquets. In the inequality
below, b represents the number of badminton sets he could have purchased.
4b < 48
Which could be the nu ber of badminton sets Coach Orozco purchased?
11
O 12
O 44
• O 47
Answer:11
Step-by-step explanation:
a skewed distribution typically has tail(s), and a normal distribution has tail(s). a. 1; 1 b. 1; 2 c. 2; 1 d. 2; 2
A skewed distribution typically has one tail, while a normal distribution has two tails. Therefore, the correct answer is option c) 2; 1.
A skewed distribution is asymmetrical, with one tail extending further in one direction than the other. This indicates that the data is not evenly distributed. On the other hand, a normal distribution is symmetrical, with both tails extending equally in opposite directions. This bell-shaped distribution is characterized by a central peak, indicating that the data is evenly spread around the mean.
It is important to note that the tails in a normal distribution represent the extreme values of the dataset, which occur with decreasing probability as they move away from the mean.
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What additional information is obtained by measuring two individuals on an ordinal scale compared to a nominal scale
The direction of the difference between the 2 measurements.
What is nominal and ordinal scale with example?Examples of data for a nominal scale include a person's gender, ethnicity, and hair color. On the other hand, an ordinal scale requires putting data in a certain order, or in relation to one another and "ranking" each parameter (variable).What is the difference nominal and ordinal?Ordinal data has a preset or natural order, whereas nominal data is categorized without a natural order or rank. A number that can be measured, however, will always be present in numerical or quantitative data.What is an example of a ordinal scale?First place would go to a student with a score of 99 out of 100; third place would go to a student with a score of 92 out of 100; and so on.Learn more about ordinal scale and nominal scale here:
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A savings account pays a 3% nominal annual interest rate and has a balance of $1,000. Any interest earned is deposited into the account and no further deposits or withdrawals are made. If interest is compounded semi-annually (every six months), what interest rate would be used for each calculation?
A. 3%
B. 2%
C. 1.5%
D. 12%
E. 18%
The answer is: C. 1.5%
how to do question 23. thanks
Answer:
put the values
Step-by-step explanation:
D= (6) Square -4(3) (2)
D=36-4(6)
D= 36-24
D= 12
M(5.9) is the midpoint ofRS. The coordinates of Sare (6,8). What are the coordinates of R?
Find the area of the circle.
25 yd
The tables show functions representing the path of two rockets launched by different science lab groups. How do the functions in the tables compare? Since the maximums occurred at the same x-value, the rockets followed the same path. Since the x-intercepts are the same for both functions, the rockets followed the same path. The rockets were in the air for the same amount of time, but the rocket for group B went higher in the air. The rockets traveled the same height in the air, but the rocket for group B was in the air for a longer time.
Answer:
C: The rockets were in the air for the same amount of time, but the rocket for group B went higher in the air.
Step-by-step explanation:
I took the test on Edge
Answer:
C
Step-by-step explanation:
Numbers 1-6 please and thank you This is really hard and I really really need help. I appreciate all the help I can get.
Area of prism = base area × altitude
1. (2x²-10)(x+4)
= 3x³-2x - 40
2. Base area = 2πr
Volume = (2πr)(r²+ 5r)
=2πr³ + 10πr²
3. Base area=½(6)(x-4)(x+3)=3(x-4)(x+3)
Volume= 3(x-4)(x+3)(⅓)
=(x-4)(x+3)= x² - x -12
4. Base circumference= 10π
Base radius = 10π/(2π) = 5
Base area = πr² = 25π
Volume = 25π(3x²-2x)
=125πx²-50πx
5. Volume = 3π√50
=15π√2
6. Base diameter = 16
Base radius = 16/2 = 8
Base area = 2πr = 16π
Volume = 16π(23a²)
=368πa²
What is the correct classification for ∠JML?
obtuse
straight
right
acute
Ray M J and Ray M L are connected at point P, forming angle J M L. A ray M K sharing the same point forms a bisector. A ray M H also sharing the same point from the diagonally down from the right. The angle J M K measure 41 degrees and angle L M H measure 132 degrees.
The correct classification for the angle JML is an acute angle.
What is an acute angle?
An acute angle has a measure, or it's smaller, than a right angle.
Therefore, the acute angle is the small angle which is less than 90°
let's find the measure of ∠JML
Hence,
∠JML = ∠JMK + ∠KML
∠KML = 180 - 132 = 48 degrees.
Therefore,
∠JML = 41 + 48 = 89 degrees.
Therefore, the correct classification for the angle JML is an acute angle.
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