Answer:
A parallel circuit has two or more paths for current to flow through.
Voltage is the same across each component of the parallel circuit.
The sum of the currents through each path is equal to the total current that flows from the source.
Explanation:
PLS HELP I WILL MARK BRAINLYIEST!!
write 5 facts about fat and calories.
Answer:
the only way to burn calories is to burn more calories than you consume
fat is very unhealthy to the body, and can cause serious issues
if you do not burn calories, they will turn into fat
eating the right amount of calories is healthy
buring fat can prevent health problems like heart disease
Explanation:
:)
if a thermometer indicates a temperature of 86F what's the equivalent temperature in Celsius scale
The equivalent temperature in Celsius scale is (86°F − 32) × 5/9 = 30°C
Take the °F temperature and subtract 32
Multiply this number by 5.
Divide this number by 9 to obtain your answer in °C.
The formula to convert °F to °C is:
T(°C) = (T(°F) - 32) × 5/9
converting 86 degrees Fahrenheit into degrees Celsius:
T(°C) = (86°F - 32) × 5/9
T(°C) = 30 °C
(86°F − 32) × 5/9 = 30°C
When doing the temperature conversion, one quick way to make certain you did the conversion right is to remember Fahrenheit temperatures are higher than the corresponding Celsius scale until you get down to -40°, which is where the Celsius and Fahrenheit scales meet. Below this temperature, degrees Fahrenheit are lower than degrees Celsius.
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will give brainliest :)Two objects having equal masses and velocities collide with each other and come to a rest. What type of a collision is this and why?
A. Elastic collision, because internal kinetic energy is conserved
B .Inelastic collision, because internal kinetic energy is not conserved
C. Elastic collision, because internal kinetic energy is not conserved
D. Inelastic collision, because internal kinetic energy is conserved
Answer:
B. lnelastic collision, because interest kinetic energy is not conserved .
I hope it helps ❤❤
The type of collision experienced by the two objects is inelastic collision, because internal kinetic energy is not conserved.
There are two types of collisions that two objects moving directly or opposite each may experience:
Elastic collision, andInelastic collision.In elastic collision, both momentum and kinetic energy of the to objects are conserved.
In inelastic collision, only momentum is conserved while kinetic energy decreases after the collision.
Thus, we can conclude that the type of collision experienced by the two objects is inelastic collision, because internal kinetic energy is not conserved.
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A force of 35 N is used to stretch a spring 15 cm beyond its normal length. What is the
increase in the spring's energy?
Answer:
5.25 J
Explanation:
W = PE = (f)(x)
PE = 35N*0.15m
PE = 5.25 N*m
1 N*m = 1 J
PE = 5.25 J
A sled's mass is 9 kg. It is held in place on a frictionless 16-degree slope by a rope attached to a stake at the top of the slope. What is the tension in the rope if it is parallel to the slope?
Answer:
The tension in the rope if it is parallel to the slope is 24.31 N.
Explanation:
Given;
mass of the sled, m = 9 kg
angle of inclination of the slope, θ = 16⁰
The tension in the rope if it is parallel to the slope is calculated from the parallel component of the tension;
\(T_|_| = mgSin \theta\\\\T_|_| = 9 \times 9.8 \times sin(16^0)\\\\T_|_| = 24.31 \ N\)
Therefore, the tension in the rope if it is parallel to the slope is 24.31 N.
0.025 kg bullet is shot out of a 0.45 m rifle barrel. The force on the bullet is 3600 N. What is the muzzle speed (the speed that the bullet leaves the gun barrel) of the bullet?
The muzzle speed of the bullet = 360 m/s
Explanations:Mass of the bullet, m = 0.025 kg
Length of the rifle, d= 0.45 m
Force on the bullet, F = 3600 N
Workdone on the bullet (W) = Force on the bullet (F) x Length of the rifle(d)
W = Fd
W = 3600 x 0.45
W = 1620 Joules
Kinetic energy of the bullet, KE = 0.5mv²
where v is the speed that the bullet leaves the gun barrel
KE = 0.5 x 0.025 x v²
KE = 0.0125v²
Workdone on the bullet = Kinetic Energy on the bullet
W = KE
1620 = 0.0125v²
v² = 1620/0.0125
v² = 129600
v = 360 m/s
The muzzle speed of the bullet = 360 m/s
A gas is confined to a vertical cylinder by a piston of mass 2 kg and radius 1 cm. When 5J of heat are added, the piston rises by 2.4 cm. Find: (a) the work done by the gas; (b) the change in its internal energy. Atmospheric pressure is 105Pa
The work done by gas is 0.753 J and change in internal energy is 4.247J
So we are given that mass is 2kg , radius 1 cm and the amount of heat is 5 cm
The piston raised by 2.4cm
As we know that Work done is PΔV
Where ΔV is change in volume
Therefore ΔV = πr^2 h = π x (.01)^2 x .024 =7.53×10^(-6)m^3
Here pressure is 10^5 pa
So W = \(10^5\times7.53\times10^-(6)\)
Therefore W = 0.753 J
Now coming to change in internal energy
Change in Internal Energy = Heat Added - Energy lost in work
∴ 5J - 0.753 J = 4.247J
Hence the change in internal energy is 4.247 J
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How many nitrogen atoms are there in 4 molecules of NH3?
Answer:
There is one atom of N and three atoms of H
in total 4 atoms
Consider a Carnot heat-engine cycle executed in a closed system using 0.025 kg of steam as the working fluid. It is known that the maximum absolute temperature in the cycle is twice the minimum absolute temperature, and the net work output of the cycle is 60 kJ. If the steam changes from saturated vapor to saturated liquid during heat rejection, determine the temperature of the steam during the heat rejection process. The temperature of the steam during the heat rejection process is
Answer:
The temperature of the steam during the heat rejection process is 42.5°C
Explanation:
Given the data in the question;
the maximum temperature T\(_H\) in the cycle is twice the minimum absolute temperature T\(_L\) in the cycle
T\(_H\) = 0.5T\(_L\)
now, we find the efficiency of the Carnot cycle engine
η\(_{th\) = 1 - T\(_L\)/T\(_H\)
η\(_{th\) = 1 - T\(_L\)/0.5T\(_L\)
η\(_{th\) = 0.5
the efficiency of the Carnot heat engine can be expressed as;
η\(_{th\) = 1 - W\(_{net\)/Q\(_H\)
where W\(_{net\) is net work done, Q\(_H\) is is the heat supplied
we substitute
0.5 = 60 / Q\(_H\)
Q\(_H\) = 60 / 0.5
Q\(_H\) = 120 kJ
Now, we apply the first law of thermodynamics to the system
W\(_{net\) = Q\(_H\) - Q\(_L\)
60 = 120 - Q\(_L\)
Q\(_L\) = 60 kJ
now, the amount of heat rejection per kg of steam is;
q\(_L\) = Q\(_L\)/m
we substitute
q\(_L\) = 60/0.025
q\(_L\) = 2400 kJ/kg
which means for 1 kilogram of conversion of saturated vapor to saturated liquid , it takes 2400 kJ/kg of heat ( enthalpy of vaporization)
q\(_L\) = h\(_{fg\) = 2400 kJ/kg
now, at h\(_{fg\) = 2400 kJ/kg from saturated water tables;
T\(_L\) = 40 + ( 45 - 40 ) ( \(\frac{2400-2406.0}{2394.0-2406.0}\\}\) )
T\(_L\) = 40 + (5) × (0.5)
T\(_L\) = 40 + 2.5
T\(_L\) = 42.5°C
Therefore, The temperature of the steam during the heat rejection process is 42.5°C
A boat travels west at a speed of 20 m/s across a river that is flowing south at 9 m/s. What is the
resultant velocity of the boat?
Answer:
22m/s
Explanation:
This is a vector addition problem. First identify the two vectors: 20m/s in the -x direction and 9m/s in the -y direction. Since neither vector shares an axis component you can use the formula \(\sqrt{20^2+9^2\\\) =21.93 (This is the Pythagorean Theorem where your non-hypotenuse sides are your velocity vectors). Round to 2 significant figures and you'll get 22m/s.
can a body have energy without momentum?explain
Answer:
Yes
Explanation:
Momentum is ensued when an object moves and results to kinetic energy. However a body sustain at a height h is said to possess energy equal to the mass × gravity × h
You see the object has an energy referred to as potential energy.
Which individual or group had perhaps the most profound effect on establishing social work as a specialized practice
Answer:
Which individual or group had perhaps the most profound effect on establishing social work as a specialized practice
Explanation:
Please help me with this and if I have good answer u will be marked as brilliant !!!!
what is the reaction of zinc nitrate mixed with silver. It's a lab and we are supposed to show what the difference, or any reaction including physical, that would happen.
Answer:
b
Explanation:
In Figure below, m₁=2.00kg and m₂-4.00kg. Consider the pulley to be frictionless. (a) If m₂ is released, what will its acceleration be? (b) What is the tension in the string? m₂ 55 m₂
(a) When m₂ is released, its acceleration will be approximately -3.27 m/s².
(b) The tension in the string is approximately -13.08 N.
To determine the acceleration of m₂ when it is released and the tension in the string, we need to consider the forces acting on the system.
(a) Acceleration of m₂:
Since the pulley is assumed to be frictionless, the tension in the string is the same on both sides of the pulley. We can consider the system consisting of m₁ and m₂ as one body. The net force acting on this system is the difference between the weight of m₁ and the weight of m₂:
Net force = m₁g - m₂g
Applying Newton's second law, F = ma, where F is the net force and a is the acceleration, we have:
m₁g - m₂g = (m₁ + m₂)a
Rearranging the equation to solve for the acceleration, we get:
a = (m₁g - m₂g) / (m₁ + m₂)
Substituting the given values, m₁ = 2.00 kg and m₂ = 4.00 kg, and the acceleration due to gravity, g = 9.8 m/s², we can calculate the acceleration:
a = ((2.00 kg)(9.8 m/s²) - (4.00 kg)(9.8 m/s²)) / (2.00 kg + 4.00 kg)
a = (19.6 N - 39.2 N) / 6.00 kg
a = -19.6 N / 6.00 kg
a = -3.27 m/s²
Therefore, when m₂ is released, its acceleration will be approximately -3.27 m/s². The negative sign indicates that the acceleration is in the opposite direction of the gravitational force.
(b) Tension in the string:
The tension in the string can be determined by considering the forces acting on m₂. The net force on m₂ is equal to its mass multiplied by its acceleration:
Net force = m₂a
Substituting the given values, m₂ = 4.00 kg and a = -3.27 m/s², we can calculate the tension:
Tension = (4.00 kg)(-3.27 m/s²)
Tension = -13.08 N
Therefore, the tension in the string is approximately -13.08 N. The negative sign indicates that the tension acts in the opposite direction of the weight of m₂.
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A forklift in Cleveland, OH, applies an upward force Fon a box so that the box moves upward at a constant speed. Which free-body diagram below best represents the forces) experienced by the box?
The forklift's upward force must be equal to and opposite to the force of gravity pulling the box downward because the box must move upward at a constant speed for the net force acting on it to be zero.
Therefore, option C, which depicts the forklift's upward force (labeled as F) and gravity's downward force (labeled as mg, where m is the box's mass and g is the acceleration caused by gravity), is the free-body diagram that best reflects the forces experienced by the box. The absence of any additional arrows in the diagram indicates that the box is not subject to any other forces.
What is a diagram of the free body?A free body diagram is a visual representation of the forces exerted on an object in a particular system or circumstance. It is a simplified drawing that shows all of the forces acting on the object of interest and separates it from its surroundings. Gravitational forces, normal forces, frictional forces, tension forces, and any other relevant forces are examples of these forces.
A free body diagram shows the object as a dot or a small box, and the forces are shown as arrows pointing in the same direction. The force's magnitude is shown by the length of the arrow, and the force's direction is shown by the arrow's direction. The force's name is written on the labels of the arrows.
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pls help, it's due tomorrow!
An electron travels 2.68 m in 6.11 × 10−8 s. How fast does it travel in cm/s? Answer in units of cm/s.
The speed (in cm/s) of the electron, given that it travels 2.68 m in 6.11×10⁻⁸ s is 4.39×10⁵ cm/s
How to determine the speedWe'll begin by defining speed. This is given below.
Speed is defined as the distance travelled per unit.
Speed = distance / time
With the above formula, we can obtain the speed of the electron. Details below
The following data were obtained from the question give above:
Distance = 2.68 m = 2.68 / 100 = 0.0268 cmTime = 6.11×10⁻⁸ sSpeed =?Speed = distance / time
Speed = 0.0268 cm / 6.11×10⁻⁸ s
Speed = 4.39×10⁵ cm/s
Therefore, the speed is 4.39×10⁵ cm/s
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What is also know When you know both the speed and direction of an objects motion.
Answer:
When you know both the speed and direction of an object's motion, you know the velocity of the object.
A 20-g bullet is shot vertically into an 2.8-kg block. The block lifts upward 9 mm. The bullet penetrates the block and comes to rest in it in a time interval of 5 ms. Assume the force on the bullet is constant during penetration and that air resistance is negligible. What is the speed of the bullet just before the impact
Answer:
The speed of the bullet just before the impact is 701 m/s
Explanation:
Given;
mass of the bullet, m₁ = 20 g = 0.02 kg
mass of the block, m₂ = 2.8 kg
displacement of the block, d = 9 mm = 9 x 10⁻³ m
duration of motion of the bullet, t = 5 ms = 5 x 10⁻³ s
Apply the principle of conservation of energy;
The final kinetic energy of the bullet = maximum potential energy of the block
\(\frac{1}{2} m_1v^2 = m_2gh\\\\v^2 = \frac{2m_2gh}{m_1} \\\\v= \sqrt{\frac{2m_2gh}{m_1} } \\\\v = \sqrt{\frac{2 \times 2.8 \times 9.8 \times (9\times 10^{-3})}{0.02} } \\\\v = 4.97 \ m/s\)
Apply the principle of conservation of linear momentum, to determine the initial velocity of the bullet before the impact.
m₁u₁ + m₂u₂ = v(m₁ + m₂)
where;
u₁ is the initial velocity of the bullet
u₂ is the initial velocity of the block = 0
m₁u₁ + 0 = v(m₁ + m₂)
m₁u₁ = v(m₁ + m₂)
0.02u₁ = 4.97(2.8 + 0.02)
0.02u₁ = 14.02
u₁ = 14.02 / 0.02
u₁ = 701 m/s
Therefore, the speed of the bullet just before the impact is 701 m/s
PLEASE HELP!!
A box falls out of an airplane that is traveling horizontally at 100m/s. The plane is at an altitude of 300m.
Where does the box land relative to where it was dropped from?
Answer:
Explanation:
Key point: the vertical motion is free fall, the horizontal motion remains at uniform speed of 100 m/s (because there is no force in the horizontal direction if we neglect air resistance.)
The time of free fall can be calculated first:
h = 1/2 g t^2 => t = sqrt(2 h /g) = sqrt(2 * 300 m / 9.81 s) = 7.82 seconds.
In that time, the horizontal displacement will be
s = v_horizontal * t = 100 m/s * 7.82 s = 782 m.
So the box will land 782 m further than the point it was dropped from (and 300 m lower of course)
At highway speeds, a particular automobile is capable of an acceleration of about 1.6 m/s2 . At this rate, how long does it take to accelerate from 70 km/h to 110 km/h ?Express your answer to two significant figures and include the appropriate units
The time taken is obtained as 6.95 s.
What is the time taken?
The time taken could be obtained from the equations of kinematics. In this case, we have to first convert the given velocities to m/s as follows;
u; 70 * 1000/3600 = 19.44 m/s
v; 110 * 1000/3600 = 30.56 m/s
Then we apply the equations of motion;
v = u + at
a = 1.6 m/s2
We now have;
v - u/a = t
t = 30.56 m/s - 19.44 m/s/ 1.6 m/s2
t = 6.95 s
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PLEASE HELP! Thank you!
Chloe and Sarah are driving bumper cars. Chloe, who is traveling west at 3.9 m/s, is behind Sarah, who is traveling west at 1.6 m/s. The total mass of Chloe’s car is 163 kg, and total mass of Sarah’s car is 179 kg. Immediately after Chloe collides with Sarah, Chloe’s velocity reduces to 0.95 m/s west. What is Sarah’s velocity immediately after the collision?
A. 5.2 m/s
B. 4.0 m/s
C. 4.3 m/s
D. 4.6 m/s
Sarah’s velocity immediately after the collision is 4.3 m/s west.
option C is the correct answer.
What is Sarah’s velocity immediately after the collision?Sarah’s velocity immediately after the collision is calculated by applying the principle of conservation of linear momentum as follows;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
m₁ is the mass of Sarah's carm₂ is the mass of Chloe's caru₁ is the initial velocity of Sarahu₂ is the initial velocity of Chloev₁ is the final velocity of Sarahv₂ is the final velocity of ChloeSarah’s velocity immediately after the collision is calculated as;
179 (1.6) + 163(3.9) = 179v₁ + 163(0.9)
922.1 = 179v₁ + 146.7
179v₁ = 775.4
v₁ = 4.3 m/s
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The speed of a cart is increased uniformly from 0.32 meters per second to 1.43 meters per second in 1.82 seconds. The cart’s acceleration is
Answer:
0.610m/s^2
Explanation:
Acceleration is defined as the ΔV/ΔT. In this case, the change in velocity is 1.43-0.32=1.11 m/s. The change in time is 1.82 seconds. Plugging in what we know, it will result in an acceleration of 0.610 m/s^2.
OMGGG PLSSS Which of the following means that a lens causes light rays to spread apart?
A. +di
B. -di
C. -f
D. +f
Answer: -f
Explanation:
Answer: -f
Explanation:
just took the test and got it right
what is one type of compact star with a mass similar to the sun but a diameter similar to earth?
Explanation:
neutron star, any of a class of extremely dense, compact stars thought to be composed primarily of neutrons. Neutron stars are typically about 20 km (12 miles) in diameter. Their masses range between 1.18 and 1.97 times that of the Sun, but most are 1.35 times that of the Sun.
Is Solar Energy renewable? Why or why not? Use in your own words.
Answer:
Solar energy is renewable.
Explanation:
If something is renewable, it is generated faster than it can be reasonably used or won't run out for longer than it would be used. Solar falls into the latter category. Using solar panels won't deplete the sun and the sun will likely be around for much longer than we will.
A book sits on a table, without moving, for two months.
In those two months:
a net force acted on the book
only gravity acted on the book
no net forces acted on the book
no forces acted on the book
Answer:
No forces acted on the book correct me if wrong please
What is the ostrich’s average acceleration from 9.0 to 18s
Answer:
Explanation:
10.00 5
It is useful to use a _________ to demonstrate how an electric circuit works
It is useful to use a model in order to demonstrate how an electric circuit works.
What is a model?In science, a model is a graphical representation that my result useful to predict the behavior of the components of a given system that works together to produce a particular outcome.
For example, an electrical circuit can be modeled by taking into account resistance, voltage, and intensity as parameters of functioning.
The electrical circuits are graphically represented by modeling the movement or flow of negatively charged electrons (e-) from the negative pole to the positive pole of a closed electric circuit.
In conclusion, it is useful to use a model (ie., a scientific model) to demonstrate how an electric circuit works.
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If a 8.1g ring is heated using 10.0 ), its temperature rises 21.7°C. Calculate the specific
heat capacity of the ring.