what are the 7 branches of physics

The surface density of atoms in the (1,1,1) plane of the BCC lattice is 0.16 atoms/angstrom².

To calculate the surface density of atoms in the (1,1,1) plane, we first need to determine how many atoms are in the plane. Since the plane passes through the center of the unit cell, it intersects one-eighth of each of the corner atoms and the full central atom. Therefore, the total number of atoms in the (1,1,1) plane is:

N_atoms = 1 + 8*(1/8) = 2

Next, we need to calculate the area of the (1,1,1) plane. To do this, we can consider the lengths of the sides of the unit cell. Since the BCC lattice has a cubic unit cell, all sides have length a=5 angstroms. The (1,1,1) plane passes through the center of the unit cell and intersects the sides at a 45-degree angle. The distance from the center of the unit cell to the midpoint of one of the sides is a/sqrt(2), so the length of the diagonal of the square face of the unit cell is 2a/√(2) = a√(2). The area of the square face is then (a√(2))² = 2a².

The (1,1,1) plane intersects the square face at a 45-degree angle, so its area is 2*a²/2 = a².

The surface density of atoms is the number of atoms per unit area. Dividing the number of atoms in the (1,1,1) plane by the area of the plane gives:

surface density = N_atoms / area

= 2 / a² = 2 / (5 angstroms)² = 0.16 atoms/angstrom²

Therefore, the surface density of atoms in the (1,1,1) plane of the BCC lattice is 0.16 atoms/angstrom².

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a. It is important to calibrate a measuring instrument regularly for the following reasons:

Accuracy: Over time, measuring instruments can drift from their original calibration due to factors such as environmental conditions, wear, and tear, or component aging.

Compliance: In many industries, calibration is a requirement to comply with quality standards, regulations, and certifications.

Confidence: Calibration instills confidence in the measurement results obtained from the instrument.

b. i. If the sensor for measuring the volume of fluid should not have direct contact with the fluid, a suitable sensor would be a non-contact or remote-level sensor. Examples include ultrasonic sensors, radar sensors, or laser distance sensors. These sensors can measure the distance to the fluid surface without physically touching it.

ii. To calibrate the sensor to measure the minimum and maximum volume of fluid in the tank, the following steps can be taken:

Empty Tank Calibration: With the tank completely empty, the sensor should be calibrated to read the minimum volume of fluid, which is 0 m³, or any other reference point desired.

Full Tank Calibration: The tank should be filled to its maximum capacity. The sensor is then calibrated to read the maximum volume of fluid, which is the volume when the tank is at its full capacity.

iii. The maximum volume of the tank can be calculated using its dimensions. The formula for calculating the volume of a cylinder is:

Volume = π * (radius)² * height

Given the diameter (6 m), we can calculate the radius as 6 m / 2 = 3 m.

Maximum Volume = π * (3 m)² * 40 m

iv. The volume of the fluid in the tank can be determined using the linear relationship between the output signal of the instrument and the volume. Since the signal range is from 4 mA to 20 mA, and this range corresponds to the minimum and maximum volume of the tank, we can create a linear equation or calibration curve relating the output signal to the volume.

v. To calculate the volume of the fluid in the tank when the output signal is 14 mA, we use the calibration curve or linear equation obtained during calibration.

vi. To determine the output signal when the volume of the fluid in the tank is 65% of the maximum capacity, we use the calibration curve or linear equation obtained during calibration.

vii. To determine the volume of the fluid when the sensor produces a signal of 17 mA, we use the calibration curve or linear equation obtained during calibration and express the result as a percentage of the maximum capacity of the tank.

c. Distinguishing between a capacitive type proximity sensor and an inductive switch:

Capacitive Proximity Sensor: A capacitive proximity sensor uses changes in capacitance to detect the presence or absence of an object. It works based on the principle that the capacitance between the sensor and an object changes when the object enters the sensing range.

Inductive Switch: An inductive switch, also known as an inductive proximity sensor, operates on the principle of electromagnetic induction.

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The heaviest liquid is mercury. In order to equalize the air pressure, it only climbs 76 cm. Water will rise to a 13.6 because it is 13.6 times lighter than mercury. By a factor of 13.6, mercury is 13.6 times denser than water.

Therefore, the barometer's height would be 13.6 times higher if water were employed in place of mercury. Since water expands when it freezes, the glass tube would be broken.

Because of its high density, mercury is frequently employed in barometers, allowing for a column height that is appropriate for measuring atmospheric pressure. For example, a mercury barometer would need to be 13.6 times taller than a water barometer to measure the same change in pressure.

This is the primary justification for using mercury in thermometers. Mercury will provide accurate readings in comparison to water since it lacks the condensation property that water possesses. Mercury can be used to measure both negative and positive temperatures, whereas water cannot be used to measure either.

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Hello..! :)

The time it takes to fill is 133 seconds or 2.21 minutes.

Explanation:

First we have the expense that has been 60 L/s, now the tank has a capacity of 8 m³.

C = (8 m³) • (1000 L/ 1 m³)

C = 8000 L

Then we clear the time.

t = 8000 L/ ( 60 L/s)

t = 133s

We convert to minutes.

t = (133s) • (1min/ 60s)

t = 2.21min

¿Doubts? On the comments. Greetings :D

Answer:

Thanks For the points

The result is 2.21 min

The wavelength of a wave is the distance it travels in the direction of propagation over a period of periodic time.

The distance covered by a point on the wave pattern in one unit of time is referred to as wave speed. It specifies the speed at which the wave is travelling through the medium and is frequently measured in figures like meters/second. The distance an object goes in a certain amount of time determines its speed, whether it be an object or a wave.

A wave is what? A wave is an energetic disturbance in a medium that doesn't include any net particle motion. Elastic deformation, a change in pressure, an electric or magnetic intensity, an electric potential, or a change in temperature are a few examples.

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Answer:

A high EQ (emotional intelligence)

In today's transitioning workplace, having a high EQ is the most important trait of a good boss. Bosses must be able to discern between their own personal beliefs and the thoughts and beliefs of others, and other generations (boomers, Gen X, xennials, millennials and now Gen Z).

Explanation:

hope it helps you

\({\ \textbf{\textcolor{red}{PLEASE MARK ME AS}} \\[ \textbf{\textcolor{blue}{BRAINLIEST}}}

\)

Answer:  two solid electrodes placed in an electrolyte connected together by an electrical conductor such as wire.

Explanation:

The two electrodes must be two different metals. The electrolyte can be acid solution, alkaline solution, salt solution or even a fruit such as orange or lemon.

Answer:

D. 5m

Explanation:

fλ = c, where f is frequency, λ is wavelength and c is speed.

6λ=30

λ=30/6=5

Answer:

Kinetic energy is energy an object possesses due to its motion.

Kinetic energy equation: \(KE = \frac{1}{2} mv^{2}\)

The faster and heavier an object is, the higher the kinetic energy.

Potential magnetic energy is the energy of an object that is able to do work because of its position in a magnetic field.

Explanation:

This is called the DEDUCTIBLE   .... the part you must deduct from your bill and pay....the rest insurance pays  ( although there may be co-pays)

The distance traveled by the person to come to a complete stop in 38 ms at a constant acceleration of 60 g is approximately 273.42 meters.

The distance that a person covers to come to a complete stop in 38 ms at a constant acceleration of 60 g can be calculated using the kinematic equation.

The formula is given by, d = (v^2 - u^2) / 2a, where d is the distance traveled, v is the final velocity, u is the initial velocity, and a is the acceleration given in g units.

To solve the problem, we need to first convert the acceleration given in g units to meters per second squared (m/s²). We know that 1 g is equivalent to 9.8 m/s².

Hence, 60 g is equivalent to 60 × 9.8 m/s² = 588 m/s².

Substituting the values in the above formula, we get,d = (0 - u^2) / 2a= u^2 / 2a, since the final velocity is 0 when the person comes to a complete stop= u^2 / 2 × 588= u^2 / 1176 m

The time taken, t = 38 ms = 0.038 s.

Now, we know that acceleration, a = (v - u) / t.

We can rearrange the above equation to find the final velocity, v. We get,v = u + at

Substituting the values, we get,588 = u + (588 × 0.038)u = 588 - (588 × 0.038)u = 567.816 m/s

Using the value of u, we can now find the distance traveled using the kinematic equation as, d = u^2 / 1176= (567.816)^2 / 1176≈ 273.42 m.

Therefore, the distance traveled by the person to come to a complete stop in 38 ms at a constant acceleration of 60 g is approximately 273.42 meters.

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The time interval between the man clapping and hearing his echo is approximately 1.75 seconds.

An echo is a repetition or reflection of a sound or signal. It can be caused by sound waves bouncing off a surface, signal interference, or the repetition of a message in communication.

The speed of sound in air at room temperature is approximately 343 meters per second. When a person claps, the sound waves propagate outward in all directions and reach the school building, where they bounce off and return to the person as an echo. The time it takes for the sound to travel the distance to the building and back to the person is the time interval between the clap and the echo.

To calculate the time interval, we can use the following formula:

time = distance / speed

where distance is the total distance traveled by the sound (twice the distance from the person to the school building), and speed is the speed of sound in air.

distance = 2 x 300m = 600m

speed = 343 m/s

time = 600m / 343 m/s = 1.75 seconds (rounded to two decimal places)

Therefore, the time interval between the man clapping and hearing his echo is approximately 1.75 seconds.

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Answer:

E = K Q / R^2     by Gauss' Law where Q is the  charge enclosed by the surface of revolution and R is the distance from the enclosed charge

Since Q = d 4 pi r^2   where d is the charge density and r the radius of the inner sphere

E = K / R^2 * (4 d pi r^2) = 4 K pi d (r / R)^2 = 4 K pi d * 1/4

E =  9 * 10E9 * 3.14 * 40 * 10E-12 = 1.13 N / C

The box accelerates to the right due to the applied force of 35 N in the +x direction.

Newton's second law states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. In this case, the net force acting on the box is 35 N in the +x direction, and its mass is 15 kg. Therefore, we can calculate the acceleration using the formula:

acceleration = net force / mass

acceleration = 35 N / 15 kg = 2.33 m/s² (rounded to two decimal places)

Since the box is not accelerating up or down, we can conclude that the force applied is only causing the box to accelerate in the horizontal direction.

Other forces such as gravity and friction are not considered in this scenario. Thus, the 15 kg box will experience an acceleration of approximately 2.33 m/s² in the +x direction due to the applied force of 35 N.

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Answer:

B.

Explanation:

To construct a semi-ellipse fireplace arch with a height of 2 feet and a base width of 6 feet, the contractor can use the following steps:

Determine the center point of the arch. Mark this point on the floor and call it point C.Measure the height of the arch, which is 2 feet. Mark this point above point C and call it point A.Measure the base width of the arch, which is 6 feet. Mark two points on either side of point C at a distance of 3 feet each. Call these points B and D.

Tie a string to a tack at point A, and loop it around two more tacks at points B and D.Adjust the length of the string until it is taut, but not too tight.Using a pencil, trace the curve of the string from point B to point D. This will create the semi-ellipse shape.

The required positions of the tacks and the length of the string will depend on the specific measurements and dimensions of the fireplace arch. By following these steps, the contractor can ensure that the semi-ellipse fireplace arch is constructed accurately and meets the desired specifications.

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Answer:

\(a\) has units of distance

\(b\)  has units of distance over time

\(c\)  has units of distance over \(time^2\)

\(d\) has units of distance over \(time^3\)

Explanation:

Since the expression for the distance is:

\(x = a+b\,t+c\,t^2+d\,t^3\)

then:

\(a\) has units of distance

\(b\)  has units of distance over time

\(c\)  has units of distance over \(time^2\)

\(d\) has units of distance over \(time^3\)

because we are supposed to be able to add all of the terms and get a distance.  So the products on each term that contains factors of time (t) should be cancelling those time units with units in the denominator of the multiplicative constant s that accompany them.

The net force on particle q₁ is 9.22 × 10^-13 N, and it points to the left.

The net force on particle q₁ due to particles q2 and q3 can be found using Coulomb's law.

Coulomb's law states that the force between two charged particles is given as

F= k * (q₁ * q₂) / r^2

Since q₁ and q₂ have the same charge, the force between them is repulsive, i.e., it points to the left. Using Coulomb's law, we can find the magnitude of this force:

F₁₂ = k * (q₁ * q₂) / r₁₂^2

F₁₂ = (9 × 10^9 Nm^2/C^2) * (-2.35 × 10^-6 C)^2 / (0.100 m)^2

F₁₂ = -4.61 × 10^-13 N

Here,  the force between q₁ and q₂ points to the left, and its magnitude is 4.61 × 10^-13 N.

The  force between q₂ and q₃ also points to the left, and its magnitude is given as

F₂₃ = k * (q₂ * q₃) / r₂₃^2

F₂₃ = (9 × 10^9 Nm^2/C^2) * (-2.35 × 10^-6 C)^2 / (0.100 m)^2

F₂₃ = -4.61 × 10^-13 N

Here,  the force between q₂ and q₃ also points to the left, and its magnitude is 4.61 × 10^-13 N.

F_net = -F₁₂ - F₂₃

F_net = -(-4.61 × 10^-13 N) - (-4.61 × 10^-13 N)

F_net = 9.22 × 10^-13 N

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Given that the mass of the ball is m1= 0.75 kg and initial velocity, u1 = 21 m/s.

This ball strikes a bottle of mass, m2= 0.5 kg, and the initial velocity of the bottle, u2 = 0 m/s.

We have to find the final velocity of the ball, v1 after collision with the bottle having final velocity, v2 = 20 m/s

Momentum is conserved during a collision. So, the equation of momentum can be written as

Substituting the values, v1 will be

Thus, the velocity of the ball is 7.67 m/s.

Answer:

Sodium and calcium

Explanation:

Answer:

Ionic bond is the name given to one of the three ways in which atoms can interact with each other. The other forms of interaction between atoms are the covalent bond, which occurs between atoms of ametals, hydrogens, or ametal and hydrogen, and the metallic bond, which occurs only between atoms of the same metal.

Explanation

:The atoms of the chemical elements that participate in the ionic bond must present, necessarily, the nature of gaining or losing electrons, thus, the ionic bond can occur between:

a metal and an ametal;

a metal and hydrogen.

Sodium: metallic element, as it has the characteristic of losing electron; belonging to the IA family, atomic number 11, with an electron in the valence shell.

Chlorine: ametalic element, as it has the characteristic of gaining electrons; belonging to the VIIA family, with atomic number 17.

A chopper’s speed increases from 35 m/s to 60 m/s in 5 seconds. Therefore, the acceleration of this helicopter is 5m/s².

The term an acceleration is the name we supply to any process where the velocity changes.

Therefore, velocity is a speed and a direction, there are only two ways for you to accelerate is change your speed or change your direction or change both.

Given:

Initial speed = 35 m/s

Final speed = 60 m/s

Time = 5 s

v = u + at

60 = 35 + a(5)

60 - 35 = 5a

25 = 5a

a = 5

Thus, the acceleration of this helicopter is 5m/s².

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Answer:

B:A

Explanation:

because the alphabet goes

A B C D E F G

Answer: B.) A

This was a little complicated because of the answer letters LOL

The current I through the 4 kΩ resistor in the original circuit is 0.199 mA.

Thévenin's theorem states that any linear network of voltage and current sources and resistors can be replaced by an equivalent circuit consisting of a single voltage source and a single resistor. The equivalent circuit provides the same output voltage and current as the original circuit for any external load connected to it.

To find the current I in the circuit using Thévenin's theorem, we need to follow these steps:

Step 1: Find the Thévenin equivalent voltage (Vth) across the 4 kΩ resistor.

To find Vth, we need to first find the open circuit voltage (Voc) across the 4 kΩ resistor. We can do this by removing the 4 kΩ resistor and finding the voltage between its two terminals using a voltage divider:

Voc = 6 kΩ/(2 kΩ + 6 kΩ) x 2 mA = 1.2 V

Next, we need to find the Thévenin equivalent resistance (Rth) across the 4 kΩ resistor. To do this, we need to short-circuit all the independent voltage sources (in this case, there is only one) and find the equivalent resistance seen from the terminals of the 4 kΩ resistor. With the 2 mA current source shorted out, the 2 kΩ and 4 kΩ resistors are in parallel:

Rth = 2 kΩ || 4 kΩ = 1.33 kΩ

Step 2: Replace the original circuit with the Thévenin equivalent circuit.

We can now replace the original circuit with the Thévenin equivalent circuit, which consists of a voltage source Vth = 1.2 V in series with a resistor Rth = 1.33 kΩ.

Step 3: Find the current I through the 4 kΩ resistor in the Thévenin equivalent circuit.

To find the current I, we can use Ohm's law:

I = Vth/(Rth + 4 kΩ) = 1.2 V/(1.33 kΩ + 4 kΩ) = 0.199 mA

Therefore, the current I through the 4 kΩ resistor in the original circuit is 0.199 mA.

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The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.

The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;

The total voltage in loop 1 is calculated as;

2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

The current flowing in loop 2 is calculated as;

I = V/R

I₂ = ( 6 V - 4 V ) / (3 + 4)

I₂ = 0.286 A

The value of the current flowing in loop 1 is calculated as;

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0

6 - 3I₁ - 3₁ + 0.858 = 0

-6I₁ = -6.858

I₁ = 6.858 / 6

I₁ = 1.14 A

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Answer:

27.91ohms

Explanation:

From the question we are given the following

Voltage across the inductor VL = 120V

Current in the inductor I = 4.3A

Required

Inductive reactance XL

Using two formula

VL =IXL

XL = VL/I

XL = 120/4.3

XL = 27.91ohms

Hence the inductive reactance is 27.91ohms

Answer:

4.3 g/cm³ or 4.3g/cc

Explanation:

Volume(V) = Height × Length × Width

= 5cm × 3cm × 2cm

= 30cm³

Mass(m) = 129gram

So,

Density = m/V

= 129g/30cm³

= 4.3g/cc or 4.3g/cm³

DNA sequencing is the technique which allows multiple peoples DNA to be compared to look for similarities and differences in order to solve crime and is denoted as option C.

This is referred to as the deoxyribonucleic acid and contains the genetic components of organisms and is also located in the nucleus. On the other hand, DNA sequencing refers to the process of determining the nucleic acid sequence.

Each organisms has a unique DNA sequence which is why it is used to identify individuals through the use of bodily fluids such as saliva, blood etc.

It is used to compare the similarities and differences in order to solve crime thereby making it the most appropriate choice.

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The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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