George is playing the piano. The note A5 has a frequency of 880 hertz. If the speed of sound at 30°C is
350 meters/second, what is the wavelength of this note at that temperature?
Part A: Enter the variable symbol for the quantity you need to find.
This note's wavelength is 0.3977m at that temperature.Greek symbol is used to represent the wavelength at which the most radiation is emitted (lambda).
A temperature wavelength is defined?Greek symbol is used to represent the wavelength at which the most radiation is emitted (lambda). T stands for the item's temperature in Kelvin, and the constant is 2,897 m. (micrometers).The molecules will vibrate more quickly and at a shorter wavelength at higher temperatures, as shown by the formula max = b / T.Where b = 2.8977719 mmK is the Wien's displacement constant and max is the previously mentioned peak wavelength of light; T is the black body's absolute temperature.Explanation:
Wavelength = 350/880
= 0.3977m.
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Answer:
0.40 meters
Explanation:
When calculated out the wavelength is about 0.40 meters. Calculation is 350 / 880
An unknown sample has a mass of 38.00 g and a volume of 56.39 ml. Calculate the density in g/ml. Provide your answer with 2 decimals. Show your work
The density of the unknown sample is 0.67 g/ml.
To calculate the density, we use the formula:
Density = Mass / Volume
Mass = 38.00 g
Volume = 56.39 ml
Substituting the values into the formula:
Density = 38.00 g / 56.39 ml
Dividing the mass by the volume, we find:
Density = 0.674 g/ml
Rounding to two decimal places, the density of the unknown sample is 0.67 g/ml.
Density is a measure of how much mass is contained within a given volume. In this case, we are given the mass of the unknown sample as 38.00 g and its volume as 56.39 ml. To find the density, we divide the mass by the volume. By performing the calculation, we obtain a density of 0.674 g/ml.
When rounding the value to two decimal places, the density of the unknown sample is 0.67 g/ml. This means that for every milliliter of the sample, there is 0.67 grams of mass. Density is an important property in chemistry and materials science as it can help identify substances and determine their behavior in various applications.
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An orbiting satellite experiences no force due to the Earth's
gravity.
Answer:
false
Explanation:
The statement "An orbiting satellite experiences no force due to the Earth's gravity." is a False statement. This is further explained below.
What is Gravity?Generally, Gravity is simply defined as the force that pulls items toward the center of a planet or other entity.
In conclusion, an orbiting satellite experiences force due to the Earth's gravity.
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A closely wound, circular coil with a radius of 2.70 cm has 730 turns.(a) What must the current in the coil be if the magnetic field at the center of the coils is 0.0780 T?(b) At what distance x from the center of the coil, on the axis of the coil, is the magnetic field half its value at the center?
(a) The current in the coil must be 3.37 A.
(b) The magnetic field is half its value at the center at a distance of approximately 3.92 cm.
(a) According to the formula for the magnetic field at the center of a circular coil, B = μ₀nI, where μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current in the coil. We can rearrange this equation to solve for I, which gives I = B/(μ₀n). Plugging in the given values of B, n, and the radius of the coil, we get I = (0.0780 T)/(4π×10⁻⁷ T·m/A)(730 turns/m)(π(0.0270 m)²) ≈ 3.37 A.
(b) The formula for the magnetic field at a point on the axis of a circular coil is B = (μ₀/2)(nIR²)/((R² + x²)^(3/2)), where R is the radius of the coil and x is the distance from the center of the coil to the point on the axis. We want to find the distance x at which the magnetic field is half its value at the center of the coil, so we can set B = B/2 and solve for x. Rearranging the equation, we get x = √3R ≈ 3.92 cm. Therefore, the magnetic field is half its value at the center at a distance of approximately 3.92 cm on the axis of the coil.
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NEED HELP asap pls
How much thermal energy must be removed from 3.75 kg of
water to freeze it at its melting point? Use Q = mass x latent
heat of fusion.
Melting point
Boiling point
OA. 15.8 kJ
B. 1250 kJ
Cliquid
Latent heat of fusion.
Latent heat of vaporization
C. 3.75 kJ
Properties of water
Property
D. 8480 kJ
0°C
Value
100°C
4.18 kJ/(kg x °C)
333 kJ/kg
2260 kJ/kg
The heat that is required to freeze the water is 1250 kJ. Option B
What is the freezing point?The freezing point of water is the temperature at which liquid water turns to solid. We know that heat is withdrawn from water when it is frozen. This heat is added when the water melts.
The latent heat of fusion = mL
m = 3.75 kg
L = 333kJ/Kg
Hence;
H = 3.75 kg * 333kJ/Kg
H = 1250 kJ
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When can an electric field that does not vary in time arise?
An electric field that does not vary in time can arise when the charges creating the field are stationary or are moving at a constant velocity.
In other words, if the charges are not accelerating, then the electric field they create will not vary in time. However, if the charges are accelerating or changing direction, then the electric field will vary in time. An electric field that does not vary in time, also known as a static electric field, can arise when there is a constant distribution of electric charges or when the charges are not in motion. In this scenario, the electric field remains constant over time because the charges' positions and magnitudes do not change.
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Which statement below is Gauss's Law for electric fields? Please note, we are not asking which statement is true, we are asking which statement is Gauss's Law. As an example, 2+2-4 is true but it is not a statement of Gauss's Law. O The electric flux through a surface is equal to the integral of the normal component of the electric field over the surface O 2+2-4 The electric flux through a closed surface is equal to the net charge inside the surface divided by the physical constant The electric flux is equal to the amount of charge flowing through a surface in a given time.
“The electric flux through a closed surface is equal to the net charge inside the surface divided by the physical constant. This law is a fundamental principle in electrostatics and is expressed mathematically as E.ds = Q/ε0.
Gauss’s Law for electric fields is a fundamental principle in physics, specifically in the study of electrostatics. The law describes the relationship between the electric flux and the distribution of electric charges in a given space. Simply put, it states that the electric flux through a closed surface is proportional to the total amount of electric charges inside the surface. In mathematical terms, the statement of Gauss’s Law for electric fields is as follows: E.ds = Q/ε0Here, E.ds represents the electric flux through a closed surface, Q represents the total electric charge enclosed within the surface, and ε0 is the physical constant known as the permittivity of free space. This equation can be used to calculate the electric field created by a given charge distribution, provided that the electric flux through a closed surface around the distribution is known.
Gauss’s Law for electric fields states that the electric flux through a closed surface is proportional to the net electric charge enclosed within the surface. This law is a fundamental principle in electrostatics and is expressed mathematically as E.ds = Q/ε0.
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A particle having a mass of 1mg has a velocity of 1 km/sec, calculate the wavelength of the particle
The wavelength associated with the particle of mass 1 mg and velocity
1 km/s is 6.63 x \(10^{-31}\) m.
We have a particle moving with certain velocity.
We have to calculate the wavelength associated with the particle.
What is de - Broglie wavelength?According to de - Broglie, the wavelength of the wave associated with the moving particle is -
λ = h/mv
Where -
h - Planck's constant
mv - Momentum of particle
According to the question -
Mass = 1 mg = 10⁻⁶ Kg
velocity = 1 Km/s = 1000 m/s
Using the formula for de - Broglie wavelength discussed above -
Momentum = mv = 10⁻⁶ x 10³ = 10⁻³ Kg m/s
now -
λ = h/10⁻³ = 6.63 x 10⁻³⁴/10⁻³ = 6.63 x 10⁻³¹ m
Hence, the wavelength associated with the particle is 6.63 x 10⁻³¹ m.
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what mass of bromine will be produced if a potassium bromide solution reacts with 50.0ml of a 1.20 mol/l solution of acidified naclo4(aq)
Around 9.588 g of bromine will be produced when 50.0 ml of 1.20 mol/L potassium bromide solution reacts with 50.0 ml of a 1.20 mol/L solution of acidified NaClO.
The reaction between potassium bromide (KBr) and sodium hypochlorite (NaClO) in the presence of acid is a redox reaction, which results in the formation of bromine (Br2) and sodium chloride (NaCl). The amount of bromine produced can be calculated using the stoichiometry of the reaction.
First, the number of moles of potassium bromide (KBr) can be calculated using the molarity and volume of the KBr solution:
Moles of KBr = Molarity x volume
= 1.20 mol/L x (50.0 ml / 1000 ml/L)
= 0.0600 mol
Since the reaction is 1:1 between KBr and NaClO, the same number of moles of bromine will be produced. The mass of bromine can be calculated using the moles and molar mass of bromine:
Mass of Br2 = Moles of Br2 x Molar mass of Br2
= 0.0600 mol x 159.80 g/mol
= 9.588 g
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Which of the following consists of photovoltaic cells?
1. Solar panels
2. Rube Goldberg device
3. Solar oven
4. Electric generator
what is the weight of a rock with a mass of 3.6 kilograms
The weight of a rock with a mass of 3.6 kilograms will be 35.3 N. The weight of matter is found as the product of the mass and the gravitational acceleration.
What is mass?Mass is a numerical measure of inertia, which is a basic feature of all matter. It is, in effect, a body of matter's resistance to a change in speed or position caused by the application of a force.
In the International System of Units (SI), the kilogram is the unit of mass.
The given data in the problem is;
The weight of a rock is,\(\rm W\)
The mass of rock is,\(\rm m= 3.6 \ kilograms\)
The weight of matter is found as the product of the mass and the gravitational acceleration;
\(\rm W= mg \\\\ \rm W= 3.6 \times 9.81 \\\\ W=35.3 \ N\)
Hence, the weight of a rock will be 35.3 N.
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a satellite is orbiting at a distance of 4.2x10⁶ m from the surface of the Earth. The radius of the Earth is 6.4x10⁶ m. What is the ratio of gravitational force on the satellite in orbit to gravitational force on the surface of the Earth?
Answer:
372 252
Explanation:
What is the acceleration of a 25 kg box that has 50 N of force applied to the right?
1. 2m/s/s
2. 10m/s/s
3. 1,250m/s/s
Answer:
1. 2 m/s/s
Explanation:
Formula
Force = Mass x Acceleration
50 N = 25 kg x (a)a = 50/25a = 2 m/s/sInitial velocity vector vA has a magnitude of 3.00 meters per second and points 20.0o north of east, while final velocity vector vB has a magnitude of 6.00 meters per second and points 40.0o south of east. Find the magnitude and the direction of the change in velocity vector Δv (which is the vector subtraction of the two vectors: final velocity vector minus initial velocity vector).
Answer:
\(5.2\ \text{m/s}\)
\(70^{\circ}\) south of east
Explanation:
\(v_a\) = 3 m/s
\(\theta_a\) = \(20^{\circ}\) north of east
\(v_b\) = 6 m/s
\(\theta_b\) = \(40^{\circ}\) south of east = \(360-40=320^{\circ}\) north of east
x and y component of \(v_a\)
\(v_{ax}=v_a\cos \theta\\\Rightarrow v_{ax}=3\times \cos 20^{\circ}\\\Rightarrow v_{ax}=2.82\ \text{m/s}\)
\(v_{ay}=v_a\sin\theta\\\Rightarrow v_{ay}=3\times \sin20^{\circ}\\\Rightarrow v_{ay}=1.03\ \text{m/s}\)
x and y component of \(v_b\)
\(v_{bx}=v_b\cos \theta\\\Rightarrow v_{bx}=6\times \cos 320^{\circ}\\\Rightarrow v_{bx}=4.6\ \text{m/s}\)
\(v_{by}=v_b\sin\theta\\\Rightarrow v_{by}=6\times \sin320^{\circ}\\\Rightarrow v_{by}=-3.86\ \text{m/s}\)
\(\Delta v=v_b-v_a\\\Rightarrow \Delta v=(4.6-2.82)\hat{i}+(-3.86-1.03)\hat{j}\\\Rightarrow \Delta v=1.78\hat[i}-4.89\hat{j}\)
Magnitude
\(|\Delta v|=\sqrt{(-4.89)^2+1.78^2}\\\Rightarrow \Delta v=5.2\ \text{m/s}\)
Direction
\(\theta=\tan{-1}|\dfrac{-4.89}{1.78}|\\\Rightarrow \theta=70^{\circ}\)
The magnitude of the change in velocity vector is \(5.2\ \text{m/s}\) and the direction is \(70^{\circ}\) south of east.
The change in velocity will be \(\Delta V=5.2\ \frac{m}{s}\) and the direction will be \(70^o\) South to east.
What are vector quantities?Any quantity which is defined by its magnitude and direction both are called as the vector quantities.
Now the data given in the question will be given as:
\(V_a\) = 3 m/s
\(\theta\) = \(20^o\) north of east
\(V_b\) = 6 m/s
\(\theta\) = \(40^o\)south of east = 360-40=320 north of east
Now we will find the x and y component of \(V_a\)
\(V_{ax}=V_acos\theta\)
\(V_{ax}=3\times Cos20\)
\(V_{ax}=2.82\ \frac{m}{s}\)
\(V_{ay}=V_aSin\theta\)
\(V_{ay}=3\times Sin20\)
\(V_{ay}=1.03\ \frac{m}{s}\)
Now we will find the x and y component of \(V_b\)
\(V_{bx}=V_bcos\theta\)
\(V_{bx}=6\times cos\320\)
\(V_{bx}=4.6\ \frac{m}{s}\)
\(V_{by}=V_bSin\theta\)
\(V_{by}=6\times Sin320\)
\(V_{by}=-3.86\ \frac{m}{s}\)
Now change in velocity will be
\(\Delta V=V_b-V_a\)
\(\Delta V=(4.6-2.82)i+(-3.86-1.03)j\)
\(\Delta V=1.78i-4.89j\)
The magnitude can be find out as follows:
\(\Delta V=\sqrt{(-4.89^2+(1.78^2)}\)
\(\Delta V=5.2\ \frac{m}{s}\)
The direction of the vector will be
\(\theta= tan^{-1}(\dfrac{-4.89}{1.78})\)
\(\theta=70^o\)
Thus the change in velocity will be \(\Delta V=5.2\ \frac{m}{s}\) and the direction will be \(70^o\) South to east.
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Heat is the measurement of energy from all the particles that are in a substance.
Please select the best answer from the choices provided : T/F
Explanation:
the correct answer is (true) if am not mistaking incase am wrong sorry
rank the capacitors on the basis of the charge stored on the positive plate.
A=4cm^2 C=2nF
A=2cm^2 C=4nF
A=8cm^2 C=2nF
A=2cm^2 C=8nF A=1cm^2 C=1nF
A=4cm^2 C=1nF
Capacitors on the basis of the charge stored on the positive plate.
1. A=4cm^2 C=2nF
2. A=2cm^2 C=4nF
3. A=8cm^2 C=2nF
4. A=2cm^2 C=8nF
5. A=1cm^2 C=1nF
6. A=4cm^2 C=1nF
What is Capacitors ?Capacitors are electronic components that store electrical energy. They are made up of two conducting plates separated by an insulating material called a dielectric. When a voltage is applied to a capacitor, it stores a charge in the form of an electric field between the two conducting plates. This stored charge can then be used to provide a current when the voltage is removed. Capacitors are used in a variety of applications including power supplies, filters, oscillators, and motors. They can also be used to store energy for later use, such as providing a short burst of power to a motor or providing a reserve of energy for a power outage.
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A copper sphere with density 8900 kg/m3, radius 5. 00 cm, and emissivity e = 1. 00 sits on an insulated stand. The initial temperature of the sphere is 300 K. The surroundings are very cold, so the rate of absorption of heat by the sphere can be neglected.
a. How long does it take the sphere to cool by 1. 00 K due to its radiation of heat energy? Neglect the change in heat current as the temperature decreases.
b. To assess the accuracy of the approximation used in part A, what is the fractional change in the heat current H when the temperature changes from 300 K to 299 K?
a.The time it will take the sphere to cool by 1. 00 K due to its radiation of heat energy is 3225s.
b. The fractional change in the heat current H when the temperature changes from 300 K to 299 K is 3.18 %.
(a) The rate of cooling of a copper sphere is given by Newton's law of cooling, i.e.,
H = kA(Ts - T0),
where k is the heat-transfer coefficient, A is the surface area of the sphere, Ts is the temperature of the surroundings, and T0 is the temperature of the sphere.
Since the surroundings are very cold, Ts can be taken to be zero.The heat transfer coefficient k depends on the emissivity e of the sphere and is given by:
k = σeA,
where σ is the Stefan-Boltzmann constant.
The surface area A of the sphere is:
A = 4πr²,
where r is the radius of the sphere.
The heat transfer coefficient k is therefore k = 4πr²σe.
Substituting the values of the parameters for the copper sphere in the above equations, we get
k = 4π(0.05 m)²(5.67 × 10^-8 W/m²K⁴)(1) = 0.0562 W/m²K⁴
H = kA(Ts - T0) = 0.0562(4π(0.05 m)²)(300 K - 0) = 1.41 W.
The rate of cooling of the sphere is therefore 1.41 W.
The heat capacity C of the sphere is given by
C = mCp,
where m is the mass of the sphere and Cp is the specific heat capacity of copper.
The mass of the sphere is m = (4/3)πr³ρ= (4/3)π(0.05 m)³(8900 kg/m³) = 0.0118 kg
The specific heat capacity of copper is Cp = 385 J/kgK.
The heat capacity of the sphere is therefore
C = 0.0118 kg × 385 J/kgK = 4.54 J/K.
The time Δt taken for the sphere to cool by ΔT = 1.00 K is given by
Δt = ΔQ/H = CΔT/H = (4.54 J/K)/(1.41 W) ≈ 3225s.
(b) The fractional change in the heat current H when the temperature changes from 300 K to 299 K is given by
ΔH/H = (dH/dT)ΔT/H,
where ΔT is the change in temperature and dH/dT is the rate of change of the heat current H with temperature.
To find dH/dT, we differentiate the equation
H = kA(Ts - T0) with respect to T and get dH/dT = -kA = -4πr²σe.
Substituting the values of the parameters for the copper sphere, we get
dH/dT = -4π(0.05 m)²(5.67 × 10^-8 W/m²K⁴)(1) = -0.0449 W/K/m².
The fractional change in the heat current is therefore:
ΔH/H = (dH/dT)ΔT/H = (-0.0449 W/K/m²)(-1 K)/(1.41 W) = 0.0318 or 3.18%.
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How is pure water different from mineral water?
Answer:
Purified water undergoes additional processes as compared to distilled or mineral water such as deionization and reverse osmosis. As purified water is free of toxins, such as bacteria, viruses, and synthetic chemicals and rich in minerals, it is the ideal form of water for daily consumption
"As long as the baseball I hit is
moving upward, there is no air resistance. Air resistance only slows it down when it is falling downward."
Answer:
Air resistance is always in play so it always has air resitance no matter what.
What happens during nuclear fission?
Answer:
During nuclear fission, a neutron collides with a uranium atom and splits it, releasing a large amount of energy in the form of heat and radiation. More neutrons are also released when a uranium atom splits. These neutrons continue to collide with other uranium atoms, and the process repeats itself over and over again.
Explanation:
In nuclear fission the nucleus of an atom breaks up into two lighter nuclei. The process may take place spontaneously in some cases or may be induced by the excitation of the nucleus with a variety of particles (e.g., neutrons, protons, deuterons, or alpha particles) or with electromagnetic radiation in the form of gamma rays. In the fission process, a large quantity of energy is released, radioactive products are formed, and several neutrons are emitted. These neutrons can induce fission in a nearby nucleus of fissionable material and release more neutrons that can repeat the sequence, causing a chain reaction in which a large number of nuclei undergo fission and an enormous amount of energy is released. If controlled in a nuclear reactor, such a chain reaction can provide power for society’s benefit. If uncontrolled, as in the case of the so-called atomic bomb, it can lead to an explosion of awesome destructive force.
Answer:
In nuclear fission, atoms are split apart, which releases energy. All nuclear power plants use nuclear fission, and most nuclear power plants use uranium atoms. During nuclear fission, a neutron collides with a uranium atom and splits it, releasing a large amount of energy in the form of heat and radiation.
what is the oxidation number of the noble gases such as xenon and argon?
what is an NS, US, UR, CS, and CR? Which occur before learning and which occur after learning?
A neutral stimulus will turn into a conditioned stimulus (CS) and cause a conditioned response (CR) that is comparable to the initial unconditioned response if it is combined with an unconditioned stimulus (US) that has already caused an unconditioned response (UR).
What is a Neutral Stimulus?A neutral stimulus is one that first merely directs attention and doesn't elicit any specific responses. When coupled with an unconditioned stimulus in classical conditioning, the neutral stimulus becomes a conditioned stimulus. The neutral stimulus will also elicit a response, known as a conditioned response, with repeated presentations of both the neutral stimulus and the unconditioned stimulus.
So, CR i.e., conditioned response is after learning while NS i.e., Neutral Stimulus is before learning.
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Calculate the centripetal force exerted on the earth by the sun. Assume that the period of revolution for the earth is 365. 25 days, the average distance is 1. 5 × 108 km and the earth’s mass is 6 × 1024 kg.
The centripetal force exerted on the earth by the sun is 3.56775 × 10²² N.
Mass of the Earth, m = 6 × 10²⁴ kg
The average distance between the Sun and the Earth is, r = 1.5 × 10⁸ km . r = 1.5 × 10¹¹ m
The path of the Earth around the Sun is circular, with a circumference:
c = 2πr
c = 2 × 3.1416 × 1.5 × 10¹¹ m
c = 9.42478 × 10¹¹ m
The Earth takes time of T = 365.25 days to complete one revolution around the Sun, that is to travel the distance of c.
T = (365.25 days) × (24hr/1day) × (60min/1hr) × (60s/1min)
T = 3.15576 × 10 ⁷s.
Thus the velocity of the Earth is,
v = c/T
v = (9.42478 × 10¹¹ m) / (3.15576 × 10 ⁷s)
v = 2.98653 × 10⁴ m/s
The centripetal force exerted on the Earth by the Sun is given by,
F = 2mv/r
F = 2× (6 × 10²⁴ kg) × (2.98653 × 10⁴ m/s ) /(1.5 × 10¹¹ m)
F = 3.56775 × 10²² N
Therefore, the centripetal force exerted on the earth by the sun is 3.56775 × 10²² N
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The equation for free fall at the surface of some planet (s in meters, t in seconds) is s=1.33t^(2). How long does it take a rock falling from rest to reach a velocity of 27.2(m)/(s) on this planet?
To increase the boiling temperature of 2051 g of water by 1.500 °C, approximately 3.431 grams of NaCl would need to be added.
Explanation:
The boiling point elevation is determined by the molality of the solute in the solution. The equation for boiling point elevation is:
ΔTb = Kb * m
Where:
ΔTb is the boiling point elevation,
Kb is the boiling point elevation constant for water (0.5100 °C/m),
m is the molality of the solute.
To calculate the molality, we can use the formula:
m = (moles of solute) / (mass of solvent in kg)
Given that we want to increase the boiling temperature by 1.500 °C, and the Kb value is 0.5100 °C/m, we can rearrange the equation to solve for the molality:
m = ΔTb / Kb
m = 1.500 °C / 0.5100 °C/m
m ≈ 2.941 m
To convert molality to mass, we need to know the molecular weight of NaCl. The molecular weight of NaCl is approximately 58.44 g/mol.
Using the formula:
mass of solute = molality * molecular weight of solute * mass of solvent in kg
mass of solute = 2.941 m * 58.44 g/mol * 2.051 kg
mass of solute ≈ 3.431 g
Therefore, approximately 3.431 grams of NaCl would need to be added to 2051 g of water to increase the boiling temperature of the solution by 1.500 °C.
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The equation for free fall at the surface of some planet (s in meters, t in seconds) is s=1.33t^(2), the long it take a rock falling from rest to reach a velocity of 27.2(m)/(s) on this planet is 1.414 seconds.
Free fall is a type of movement that an object undergoes when it falls freely under the effect of gravity. Gravity is a force that acts on every object and makes it move towards the center of the earth or any other celestial body. The acceleration due to gravity is expressed as g, and it is equal to 9.8 m/s² on earth. The time it takes a rock falling from rest to reach a velocity of 27.2 m/s on this planet can be calculated by equating the acceleration due to gravity with the given velocity.
The formula for velocity is given by V=U+at, where V is the final velocity, U is the initial velocity, a is the acceleration, and t is the time taken to reach the final velocity. Under free fall, the initial velocity is zero; therefore, the formula can be simplified to V = at.
Substituting the given values in the formula, we get 27.2=1.33t² × g or 27.2=1.33t² × 9.8.
We can simplify this equation to t² = (27.2)/(1.33 × 9.8) or t² = 2.
The square root of 2 is 1.414. Therefore, the time taken for the rock to reach a velocity of 27.2 m/s on this planet is 1.414 seconds.
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What characteristics of the solar system would have to be known or calculated in order to send a
probe to a distant planet, such as Jupiter?
a. the effects due to the light from the distant stars
b. the effects due to the air in the solar system
c. the effects due to the gravity from the other planets
d. the effects due to the cosmic microwave background radiation
Answer:
A
Explanation:
The effects due to light from distant stars
The characteristics of the solar system would have to be known or calculated in order to send a probe to a distant planet, such as Jupiter, due to the effects of the gravity from the other planets. Hence, option C is the correct answer.
When sending a probe to a distant planet, such as Jupiter, one of the critical factors that would have to be known or calculated is the effects due to the gravity from the other planets in the solar system. The gravitational interactions between the planets can significantly influence the trajectory and path of the probe during its journey. Accurate calculations are necessary to ensure that the probe's trajectory is properly planned and adjusted to reach its destination with precision. Hence, option C is the correct answer.
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An astronaut is rotated in a centrifuge of radius 5.2 m. (a) What is the speed if the acceleration is 6.8g
The given radius of the centrifuge, r = 5.2 m, Acceleration = 6.8g = 6.8 * 9.8 m/s² = 66.64 m/s²
The speed of an astronaut rotated in a centrifuge of radius 5.2 m if the acceleration is 6.8g is found out as below. The centripetal force is given by the formula
F = mv²/r,
where F is the force, m is the mass, v is the velocity, and r is the radius of the centrifuge.
F = ma
Therefore, mv²/r = ma
The velocity of an astronaut is given by the formula
v = √(ar).
v = √(66.64 * 5.2)
Speed of astronaut is v = 25.68 m/s
Thus, the speed of an astronaut when rotated in a centrifuge of radius 5.2 m with an acceleration of 6.8g is 25.68 m/s.
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Thirteen resistors are connected across points A and B as shown in the figure. If all the resistors are
accurate to 2 significant figures, what is the equivalent resistance between points A and B?
The equivalent resistance between points A and B in the diagram is 22 Ω
How do I determine the equivalent resistance?We shall begin by obtaining the equivalent resistance in parallel (i,e the three 6 Ω resistor). Details below:
Resistor 1 (R₁) = 6 ΩResistor 2 (R₂) = 6 ΩResistor 3 (R₃) = 6 ΩEquivalent resistance (Rₜ) = ?1/Rₜ = 1/R₁ + 1/R₂ + 1/R₃
1/Rₜ = 1/6 + 1/6 + 1/6
1/Rₜ = 3/6
1/Rₜ = 1/2
Rₜ = 2 Ω
Finally, we shall determine the equivalent resistance between A and B (i.e series arrangement). Details below:
Resistor 1 (R₁) = Resistor 2 (R₂) = ... = Resistor (R₁₁) = 2 ΩEquivalent resistance (R) =?R = R₁ + R₂ + R₃ + R₄ + R₅ + R₆ + R₇ + R₈ + R₉ + R₁₀ + R₁₁
R = 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2
R = 22Ω
Thus, we can conclude that the equivalent resistance is 22 Ω
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6th grade science If you answer this your the brainiest
Answer:
8. sketches and models helped the astronauts in their training program as they prepare for their missions
9. before building the Mars lander , students need to sketch their design
As cars travel, oil and gasoline leaks onto the road surface. If a light rain falls, what does this do to the control of the car
When a light rain falls after oil and gasoline have leaked onto the road surface, it can cause the car to become less responsive and more difficult to control.
This is because the oil and gasoline act as a slippery layer on the road surface, which reduces the friction between the tires and the road. The rainwater can then mix with the oil and gasoline, making the layer even more slippery and reducing the vehicle's grip on the road.
To help mitigate this issue, drivers should be aware of their surroundings and the potential for slippery surfaces, and should adjust their speed and driving accordingly. Additionally, using tires with greater tread, or using more aggressive tires designed for wet and slippery conditions, can also help increase the vehicle's grip on the road.
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17) Name two ways you could decrease the potential energy of a bucket full of water sitting on a bench.
Explanation:
The potential energy of an object has the following formula
Potential energy = mgh
where m = mass of the object
g = acceleration due to gravity
h = height of the object
This means that the potential energy of an object depends upon its mass, acceleration due to gravity, and height.
In the given situation we have a bucket full of water. If the mass and acceleration due to gravity are not changed, the only way the potential energy can be decreased is by reducing the height of the bucket full of water.
This can be done by: -
(i) Lifting the bucket full of water in such a way that you
decrease its height as compared to the bench.
(ii) Put the bucket full of water on a stool whose height is
lower than the bench.
Answer:
1.By decreasing it's contents- this decreases the weight of the bucket thus decreasing the potential energy of the bucket.
2.By decreasing the height of the bench we have decreased the amount of potential energy stored in the bucket