What are greenhouse gasses? How does carbon dioxide enter the atmosphere? (Site 1)

The velocity of a stream with a discharge of 2000 \(m^3/s\) is 2m/s. the velocity of a stream with a cross-sectional area of 300 m2 is 2m/s. the depth of a stream is 7.5 m.

a) For a stream with a discharge of 2000 m3/s, a channel width of 200 meters, and a depth of 5 meters, we can use the equation Q = AV. Rearranging the equation, we have V = Q / A. Plugging in the values, V = 2000 \(m^3/s\) / (200 m x 5 m) = 2 m/s.

b) For a stream with a cross-sectional area of 300 m2 and a discharge of 600 m3/s, we can again use the equation V = Q / A. Substituting the given values, V = 600 \(m^3/s\) / 300 m2 = 2 m/s.

c) To find the depth of a stream with a width of 400 m, velocity of 1.5 m/s, and discharge of 4500 m3/s, we rearrange the equation as D = Q / (A x V). Plugging in the values, D = 4500 \(m^3/s\) / (400 m x 1.5 m/s) = 7.5 m.

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Answer:

well i guess i can try...

Explanation:

Volcanoes are a dangerous natural occurance that can greatly effect any ecosystems. There are various effects of volcanoes such as, lava flows, volcanic landslides, mud-flows, and ash flows, which generally result in total obliteration of any ecosystem in their path, they can also have long term beneficial effects to the environment.  One of these long term effects are, the creation of some of the most nutrisous, and fertile soil on earth, causing healthy plants to grow.

Answer:

The answer is . A 46.2g

Answer:

Explanation:

1. He had the opportunity to have a chance of doing experimental research where he began to develop a theory on electromagnetism. He was then recognized in 1884 and appointed to chair of physics at Cavendish Laboratory. In 1914 there was a new type of physics that lead to more questions than there were answers for and that is when Thomson began associating himself with this new type of physics.

2. Thomson began experimenting with the cathode ray tubes that showed him that all atoms contain small negatively charged particles/electrons. His proposition to the atom was shown with is plum pudding model, which showed negatively charged electrons that were embedded in a positive charge. His discovery came before the discovery of the atomic nucleus that would be included in the electron in the atomic model.

3.His contributions to the atomic model include that all matter is made of atoms, atoms are invisible and indestructible, all atoms in a certain element are identical, two or more atoms that are combined form a compound, and a chemical reaction is the rearrangement of the atoms. His ideas of the atomic model that do not exist in the modern day atomic model include the fact that the distribution of the negative and positive particles was not uniform.

Websites:

https://socratic.org/questions/why-was-j-j-thomson-wrong

https://www.khanacademy.org/science/ap-chemistry/electronic-structure-of-atoms-ap/history-of-atomic-structure-ap/a/discovery-of-the-electron-and-nucleus#:~:text=Summary-,J.J.,positively%2Dcharged%20%22soup.%22

Answer:

7m/s²

Explanation:

Given parameters:

Velocity at the top = 1m/s

Velocity at the bottom  = 36m/s

Time  = 5s

Unknown:

Average acceleration = ?

Solution;

Acceleration is the rate of change of velocity with time. It is expressed as;

  A = \(\frac{v -u}{t}\)

v is the velocity at the top

u is the velocity at the bottom

t is the time taken

 Now, insert the parameters and solve;

  A = \(\frac{36 - 1}{5}\)   = 7m/s²

Given values:

Top velocity,

Bottom velocity,

Time,

The acceleration is:

→ \(A = \frac{v -u}{t}\)

By putting the values,

       \(= \frac{36-1}{5}\)

       \(= \frac{35}{5}\)

       \(= 7 \ m/s^2\)

Thus the answer above i.e., "option d" is correct.

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Given,

The image distance, v=17.22 cm

The focal length of the lens, f=3.05 cm

From the thin lens formula,

Where u is the object distance.

On rearranging the above equation,

On substituting the known values,

Thus the object distance should be 3.71 cm

Answer:

1. Point 2.

2. Either #1 or #4 (sorry, I'm not 100% sure).

3. I'm pretty sure #3.

I hope this helps!

Answer:

2 meters a second or 2 m/s

The answer is True. The conservation of charge, or Kirchhoff's current law, stipulates that the total current entering and leaving a junction in an electrical circuit must equal each other.

Kirchhoff's current law asserts that the algebraic sum of currents at any junction point (or node) in an electrical circuit is always zero, often known as the junction rule or the first law. This law is founded on the idea that charge cannot be created or destroyed, which is known as the conservation of charge. Any current that enters a junction must therefore be balanced by an equivalent current that exits the junction. By using current relationships at various nodes, this law serves as the basis for understanding and resolving complex electrical circuits. It is a cornerstone of circuit analysis and is frequently applied in physics and electrical engineering.

The algebraic sum of currents entering every junction point (or node) in an electrical circuit must match the algebraic sum of currents exiting that junction, according to Kirchhoff's current law, sometimes referred to as the junction rule or Kirchhoff's first law. Alternatively said, the total current entering a node equals the total current leaving it. This law is based on the concept of conservation of charge, which holds that electric charge can only be moved from one place to another and cannot be created or destroyed. The entire amount of charge entering a junction must match the total amount of charge exiting that junction since electrons carry charge through a circuit.

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If the side length is 150 units, the largest number of points such that any two of them have the same distance is 6.

To find the largest number of points such that any two of them have the same distance, we can use a regular polygon.

In a regular polygon, all sides and angles are equal. The formula to find the number of points (n) in a regular polygon is n = 360 / (180 - angle), where angle is the interior angle of the polygon.

In this case, we want the distance between any two points to be the same, so we are looking for a regular polygon with equal side lengths.

Since all sides of a regular polygon are equal, we can set the distance between any two points to be the side length of the polygon.

For example, if the side length of the polygon is 150 units, we can substitute this value into the formula to find the number of points:

n = 360 / (180 - angle)

n = 360 / (180 - 360/n)

Now, we need to find the value of n that will make the equation true.

Let's start by substituting n = 3 into the equation:

n = 360 / (180 - 360/3)
n = 360 / (180 - 120)
n = 360 / 60
n = 6

Therefore, if the side length is 150 units, the largest number of points such that any two of them have the same distance is 6.

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Given:

The applied force is,

The mass of the object is,

The constant velocity of the object is,

To find:

The coefficient of friction between the object and the surface

Explanation:

The object is moving with a constant velocity which means the object is under equilibrium. So, the applied force is equal to the frictional force on the object.

If the coefficient of friction between the object and the surface is

we can write the frictional force as,

For equilibrium condition,

Hence, the coefficient of friction between the object and the surface is 0.47.

Answer: +20N

Explanation:

First we look at our given information. You are finding the sum of the forces on the ball and they already give you the magnitude and direction of the forces. This means we can disregard the mass (1kg) of the ball and what the forces are from (gravity and floor pushing on the ball). The only things that matter are magnitude and direction.

Now we have to give each force either a positive or negative sign. I am assuming we are using the ground as a frame of reference. When we move towards a frame of reference, the sign is negative. When we move away from a frame of reference. This means that the upward vector will have a positive sign (+30N) and the downward vector will have a negative sign (-10N).

Now all we have to do is add the two together:

+30 + (-10) = +20

All done!!

A system's isolated thermal energy fluctuates throughout time. According to the first law of thermodynamics, which states that a system's thermal energy can fluctuate even if its overall energy remains constant if the mechanical energy of that system is constant.

Thermal energy is the internal energy that a system has when it is in thermodynamic equilibrium due to temperature. The energy of systems that are not in a state of thermodynamic equilibrium cannot be transformed into useful work as easily as thermal energy.

The same fluid or solid in a thermodynamic equilibrium state with the same energy (as thermal energy), however, cannot do work unless it is combined with another substance at a different temperature, as in a heat engine. This is because the same fluid or solid in a thermodynamic equilibrium state has the same energy (as thermal energy), but it cannot be converted to work in a mechanical device.

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Answer:

If one were to assume a circular orbit (actually earth orbit is slightly elliptical) then theta = 29.5 / 365.25 * 360 = 29 deg

The angle of the radius of the orbit would change by 29 deg in 29.5 days

The kernel (null space) of a linear map L from a vector space V to a vector space W is a subspace of V.

To prove that the kernel (null space) of a linear map L from a vector space V to a vector space W is a subspace of V, we need to show three things: closure under vector addition, closure under scalar multiplication, and the presence of the zero vector.

1. Closure under vector addition:

Let u and v be vectors in the kernel of L, denoted as u, v ∈ ker(L). This means L(u) = 0 (the zero vector in W) and L(v) = 0. We want to show that u + v is also in the kernel of L.

Using the linearity of L, we have:

L(u + v) = L(u) + L(v) = 0 + 0 = 0

This shows that u + v is mapped to the zero vector by L, thus u + v is in the kernel of L.

2. Closure under scalar multiplication:

Let u be a vector in the kernel of L, denoted as u ∈ ker(L). This means L(u) = 0. We want to show that αu is also in the kernel of L for any scalar α.

Using the linearity of L, we have:

L(αu) = αL(u) = α0 = 0

This shows that αu is mapped to the zero vector by L, thus αu is in the kernel of L.

3. Presence of the zero vector:

The zero vector in V, denoted as 0v, is always in the kernel of any linear map because L(0v) = 0 in the codomain W.

Therefore, we have shown that the kernel of L satisfies the three conditions to be a subspace of V: closure under vector addition, closure under scalar multiplication, and the presence of the zero vector. Hence, the kernel of L is indeed a subspace of V.

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Answer:

yes/nope

Explanation:

............... :)

Answer:

\(4ms^{-2}\)

Explanation:

F = ma

Rearrange to get acceleration on its own:

a = \(\frac{F}{m}\)

Substitute 20 for F and 5 for m:

a = \(\frac{20}{5}\) = 4 meters/second/second

In a uniformly assessing accelerating motion, the velocity of this specific object follows the law:

v(t) = v₀ + at

where v₀ is the initial velocity, followed by an acceleration and t stands for time.

In the given question statement, the robot starts from rest such that the initial speech achieved is zero where,

vi = 0

Now, the robot undergoes a free fall such that the acceleration is assumed as the gravitational acceleration given the,

g= 9.81m/s².

Therefore, along with the time t = 3.5s and the velocity is,

v(3.5) = 0 + (9.81m/s²) (3.5s) = 34.4m/s

Hence, the speech after it has fallen accounts for 34.3 m/s

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The gravitational force of a star on planet 2 orbiting it is half that of planet 1.

Newton's gravitational law formula for gravitational force between two objects

\(F = G \frac{M \: m}{r^2}\)

Given

Compare the gravitational force on two condition.

\(\frac{f1}{f2} = \frac{G \frac{M \: m_1}{r_1^2}}{G \frac{M \: m_2}{r_2^2}}\)

\(\frac{f1}{f2} = \frac{\frac{m_1}{r_1^2}}{\frac{m_2}{r_2^2}}\)

\(\frac{f1}{f2} = \frac{m_1 \: r_2^2}{m_2 \: r_1^2}\)

\(\frac{f1}{f2} = \frac{m_1 \: (2r_1)^2}{2m_1 \: r_1^2}\)

\(\frac{f1}{f2} = \frac{4r_1^2}{2r_1^2}\)

\(\frac{f1}{f2} = \frac{2}{1}\)

The ratio of gravitational force f1 : f2 = 2 : 1

2f2 = f1

\(f2 = \frac{f1}{2}\)

\(f2 = \frac{1}{2} f1\)

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The maximum kinetic energy of electrons ejected from a silver surface by ultraviolet light of wavelength 254 nm can be calculated using the difference between the energy of the incident photon and the work function of silver.

To find the maximum kinetic energy of electrons ejected from a silver surface, we can use the equation:

K_max = hν - φ

where K_max is the maximum kinetic energy of the ejected electrons, h is Planck's constant, ν is the frequency of the incident light, and φ is the work function of silver.

First, we need to find the frequency of the incident light using the equation:

c = νλ

where c is the speed of light and λ is the wavelength of the incident light.

ν = c/λ = (3.00 x 10^8 m/s)/(254 x 10^-9 m) = 1.18 x 10^15 Hz

Next, we can use the cutoff frequency to find the work function of silver using the equation:

φ = hν_c/λ_c

where ν_c is the cutoff frequency and λ_c is the cutoff wavelength.

φ = (6.63 x 10^-34 J s)(3.00 x 10^8 m/s)/(325 x 10^-9 m) = 6.08 x 10^-19 J

Finally, we can substitute these values into the first equation to find the maximum kinetic energy of the ejected electrons:

K_max = hν - φ = (6.63 x 10^-34 J s)(1.18 x 10^15 Hz) - 6.08 x 10^-19 J = 1.10 x 10^-18 J

Therefore, the maximum kinetic energy of electrons ejected from a silver surface by ultraviolet light of wavelength 254 nm is 1.10 x 10^-18 J.

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The average acceleration for that time interval will be zero because the velocity is constant.

If an object's velocity changes, it is said to have been accelerated. An object's velocity can alter depending on whether it moves faster or slower or in a different direction. A falling apple, the moon orbiting the earth, and a car stopped at a stop sign are a few instances of acceleration. Through these illustrations, we can see that acceleration happens whenever a moving object changes its direction or speed, or both.

Velocity and speed describe how quickly or slowly an object is moving. We frequently encounter circumstances when we must determine which of two or more moving objects is going faster. If the two are travelling on the same route in the same direction, it is simple to determine which is quicker. It is challenging to identify who is moving the fastest when their motion is in the other direction. The concept of velocity is useful in these circumstances. Learn about the definition of velocity in this article as well as the distinction between speed and velocity.

the velocity is constant at -20 m/s. Hence the average acceleration for that time interval will be zero because the velocity is constant.

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Answer:

0

Explanation:

i did it on khan academy