Answer:
Explanation:
Cell biology (also cellular biology or cytology) is a branch of biology studying the structure and function of the cell, also known as the basic unit of life. Cell biology encompasses both prokaryotic and eukaryotic cells and can be divided into many sub-topics which may include the study of cell metabolism, cell communication, cell cycle, biochemistry, and cell composition.
Genetics, study of heredity in general and of genes in particular. Genetics forms one of the central pillars of biology and overlaps with many other areas, such as agriculture, medicine, and biotechnology. Learn more about the history, biology, areas of study, and methods of genetics.
Molecular biology, field of science concerned with studying the chemical structures and processes of biological phenomena involving molecules. In particular, researchers focus on DNA, RNA, and proteins and their interactions. As a result, the field is closely related to genetics and biochemistry
The study of heredity is a field of genetics and cell biology. The DNA itself (molecular genetics), entire populations, or whole creatures are investigated at various levels of genetics (population and evolutionary genetics).
What relation between cell biology and molecular biology?Two branches of biology are cell biology and molecular biology. The study of cellular mechanisms is a focus of the subject of cell biology.
As a result, it primarily concerns the functions and architecture of the cell. The study of molecular level mechanisms is a focus of the science of molecular biology.
Therefore, cell biology, genetics, and molecular biology are interconnected.
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population of bacteria is growing according to the equation P(t)=1000e0.12t, where P(t) is the population and t is the time in hours. Estimate when the population will reach 5000 . Round to the tenths. Provide your answer below:
The estimated time it will take for the population to reach 5000 bacteria is approximately 13.4 hours.
To estimate when the population will reach 5000 bacteria, we can set up the equation P(t) = 5000 and solve for t.
The given equation for population growth is P(t) = 1000e^(0.12t). To solve for t, we can substitute 5000 for P(t):
5000 = 1000e^(0.12t)
To isolate the exponential term, we can divide both sides of the equation by 1000:
5 = e^(0.12t)
Next, we can take the natural logarithm (ln) of both sides to remove the exponential:
ln(5) = ln(e^(0.12t))
Using the property of logarithms, ln(e^(0.12t)) simplifies to 0.12t:
ln(5) = 0.12t
Now, we can solve for t by dividing both sides by 0.12:
t = ln(5) / 0.12
Using a calculator, we find that ln(5) is approximately 1.6094. Dividing this by 0.12 gives us an approximate value for t:
t ≈ 1.6094 / 0.12 ≈ 13.4117
Rounding to the tenths place, the estimated time it will take for the population to reach 5000 bacteria is approximately 13.4 hours.
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in what stage does crossing over (or genetic recombination) NOT occur?
a. horsetail sporangia
b. fern sori
c. club moss strobilus
d. moss gametophyte
Crossing over, also known as genetic recombination, is a process that occurs during meiosis. Meiosis is a type of cell division that produces haploid cells with half the number of chromosomes as the original cell. During meiosis, homologous chromosomes pair up and exchange genetic material through crossing over. This results in genetic variation in the offspring.
Out of the options given, the stage in which crossing over does not occur is moss gametophyte. Moss gametophyte is the haploid stage of the moss life cycle. It produces gametes through mitosis instead of meiosis. Therefore, crossing over does not occur during the production of gametes in the moss gametophyte stage.
In contrast, horsetail sporangia, fern sori, and club moss strobilus are all structures that produce spores through meiosis. Crossing over occurs during meiosis, which produces genetically diverse spores in these structures.
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How does respiration occour in human body
Respiration is the life-sustaining process in which gases are exchanged between the body and the outside atmosphere. Specifically, oxygen moves from the outside air into the body; and water vapor, carbon dioxide, and other waste gases move from inside the body to the outside air. Respiration is carried out mainly by the respiratory system.It is important to note that respiration by the respiratory system is not the same process as cellular respiration —which occurs inside cells — although the two processes are closely connected. Cellular respiration is the metabolic process in which cells obtain energy, usually by “burning” glucose in the presence of oxygen. When cellular respiration is aerobic, it uses oxygen and releases carbon dioxide as a waste product. Respiration by the respiratory system supplies the oxygen needed by cells for aerobic cellular respiration, and removes the carbon dioxide produced by cells during cellular respiration.
Answer It Goes down the pharynx than into the larynx to the trachea then into the lungs through the 2 bronchi.
Explanation:
cytokinesis is the division of the ____________________ , and follows ____________________, producing two daughter cells.
Answer:
cytoplasm, telophase
Explanation:
The cell membrane and cytoplasm divide forming two identical new daughter cells.
Hope this helps!
Cytokinesis is the division of the cytoplasm, telophase, and follows cytoplasm divide forming two identical new daughter cells.
What is cytokinesis?Cytokinesis has been defined as the are a part of cell division and they are directly related to each other. Actually, Mitosis has a process in which the duplicated genome present inside a cell is divided into two halves that are always identical in nature. Cytokinesis is the process where the cytoplasm of the cell divides to form two 'daughter' cell.
Mitosis has been considered as a cell division type that divides the parent cell and the genetic material into two alike daughter cells with the same chromosome numbers. Cytokinesis has been refer as a process by which at the end of the telophase the cytoplasm of the cell starts dividing and results in the formation of the plate in plants and furrows in the animal, dividing the cell equally.
Therefore, Cytokinesis is the division of the cytoplasm, telophase, and follows cytoplasm divide forming two identical new daughter cells.
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Read the following article describing a current marine issue.
Household vinegar advances the fight against crown of thorns starfish threat on Great Barrier Reef
ABC North Qld
By Kathleen Calderwood and Isobel Roe
Crown of thorns starfish (COTS) is a pest which eats coral tissues, posing a huge threat to the reef. Australian
Institute of Marine Science research showed coral cover on surveyed reefs had declined by about 50% over
the past 30 years, with COTS responsible for almost half of that decline. James Cook University scientist Lisa
Boström-Einarsson searched for an eradication method for COTS that was cheap, easily available and safe
for everything other than the starfish themselves. Her method involved injecting the COTS with 20 milliliters
of household vinegar. The trial saw a 100% kill rate within 48 hours of injection. "I tried alcohol [first] and that
did not work very well, and then I heard some rumors that some people had used vinegar but had not had
very good results," Ms Boström-Einarsson said. "So I refined the methods a little bit and then it turned out to
work really well." Ms Boström-Einarsson said the starfish were mostly water inside and could not tolerate the
acidity of the vinegar. "The acid basically just melts their insides," she said. "It is quite dramatic the way they
go and within 24 hours there is basically just slime left-it is not pretty."
Explain the scientific procedure followed in the article by describing the following: (4 points)
1. State the problem
2. Identify a hypothesis from the article
3. Identify the procedures used in the experiment
4. Describe the results
1. State the problem: This COTS pest destroys coral tissues, endangering the reefs severely. Marine Science investigated the matter and discovered that COTS was to blame for the coral cover on measured reefs declining by around 50% during the previous 30 years.
2. Identify a hypothesis from the article: If Lisa succeeds in eliminating COTS, the COTs may begin to perish.
3. Identify the procedures used in the experiment: So Lisa looked for a COTS eradication approach that was affordable, simple to apply, and safe for all organisms except starfish. She utilized alcohol and vinegar because it was convenient and affordable.
4. Describe the results: Lisa initially tried using alcohol, but she soon realized that it did not work. After hearing reports that other people had used vinegar, but had received poor results, Lisa slightly improved the procedures, which eventually proved to be quite effective. After all, it was determined that because starfish were primarily made of water, they could not withstand the acidity of the vinegar. As a result, the starfish were killed within 24 hours, leaving only slime.
What is COTS?
Acanthaster planci, often known as the COTS, is a type of corallivore that lives naturally on coral reefs and consumes coral polyps. They come in a variety of colors, from reddish-gray to green to purplish blue, and are covered in long, venomous spines. Although they can be as huge as 80 cm, they typically have a diameter of 25 to 35 cm.
COTS are an essential component of the ecosystem in normal proportions on healthy coral reefs. They frequently consume the rapidly corals, allowing the slower-growing types to catch up and increasing the variety of coral reefs on our reefs.
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A mutation in the Operator region of the lac operon would most likely result in.. a. Reduced expression of lac, as the RNA polymerase cannot bind, production of nonfunctional beta-galactosidase b. Constitutive expression of lac operon, whether or not lactose was present, as the repressor cannot bind c. Constitutive expression of lac operon, whether or not lactose was present, as the RNA polymerase cannot bind d. No change in the expression of lac.
B. Constitutive expression of lac operon, whether or not lactose was present, as the repressor cannot bind.The operator region of the lac operon is the DNA sequence where the lac repressor binds to prevent the transcription of the lac genes when lactose is not present.
A mutation in the operator region can affect the binding of the repressor, allowing RNA polymerase to bind and transcribe the genes constitutively, regardless of the presence of lactose.
This would result in the continuous production of beta-galactosidase, leading to the utilization of lactose as a carbon source.
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i need help on the biology lab lab project: building proteins from RNA from egenuity can anybody give me one of their old ones
Proteins are built from the RNA as the ribosome reads the instructions found in messenger RNA.
How are proteins constructed from RNA?Ribonucleic acid (RNA) is a nucleic acid found in all living cells that is structurally similar to DNA. RNA, unlike DNA, is typically single-stranded. Instead of the deoxyribose found in DNA, the backbone of an RNA molecule is made of alternating phosphate groups and the sugar ribose.
Ribonucleic acid is a polymeric molecule that plays important roles in gene coding, decoding, regulation, and expression. Nucleic acids include RNA and deoxyribonucleic acid. Transfer RNA (tRNA) is a type of RNA that assembles the protein one amino acid at a time.
Ribosomes synthesize proteins from ribosomal RNA (rRNA).
The ribosome reads the instructions found in messenger RNA molecules in a cell and builds proteins from these mRNAs by chemically linking amino acids (protein building blocks) in the order defined by the mRNA.
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Answer:
Did you ever get the lab report?
Explanation:
Name three things organs that can live in water and on land
Answer:
CROCODILE
PENGUINE
TURTLE
Explanation:
Describe how and where fish perceive taste. What tastes can fish
sense?
Fish perceive taste through their tastebuds, which are located in their mouth and along the length of their body.
The tastebuds are made up of taste cells that contain receptor proteins. When a fish eats something, molecules from the food bind to these receptors and send signals to the brain to interpret the taste. The taste preferences of fish vary widely based on the species. Some fish are attracted to sweet tastes, while others prefer salty or sour flavors.
Some fish have also been shown to be able to detect bitter tastes, which can help them avoid eating toxic or spoiled food. In general, fish have a strong sense of taste that helps them locate and identify food in their environment. Fish can also sense certain chemical cues in their environment that help them locate food. For example, some fish are attracted to the scent of prey or the smell of blood in the water.
Other fish may be able to detect the presence of specific chemical compounds, such as those produced by injured fish or the scent of certain plants or algae. Therefore, fish can taste sweet, sour, salty, and bitter flavors and detect certain chemical compounds.
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The small dense region within the nucleus is called
Answer:
The nucleolus is a dense region of ribonucleic acid (RNA) in the nucleus and is the site of ribosome formation
Answer:
the should be the nucleolus i think
Allowing discharged electricity to flow safely into Earth's bedrock is known as,
Btw 30 pts if u answer this CORRECTLY.
dna is constructed of four different types of proteins. (true or false)
Answer: False
Explanation:
Intermediate levels of distrubance often lead to higher diversity because:
A. Both species that do well at low disturbance and those that do well at high disturbance are usually present
B. It is easier for many species to resist disturbances if they occur not too rarely nor too frequently
C. Some species are not vulnerable to the disturbance and reach larger population sizes
D. Frequentt disturbances can bring new species to an area that were not there before
The intermediate levels of disturbance often lead to higher diversity because both species that do well at low disturbance and those that do well at high disturbance are usually present. This option (A) is the answer to the given question
.In ecology, the intermediate disturbance hypothesis claims that local species diversity is maximized when ecological disturbance is neither too low nor too high. The hypothesis is based on the idea that, at moderate levels of disturbance, competitively dominant species are unable to displace all the less competitive species.
Intermediate disturbance increases both the number of species that can survive in an area and the variety of habitats that are available, increasing the species pool. The moderate disturbance can change the local environment, creating niches that new species can occupy.In conclusion, the intermediate levels of disturbance often lead to higher diversity because both species that do well at low disturbance and those that do well at high disturbance are usually present. This is because intermediate levels of disturbance facilitate a higher species diversity.
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What occurs during a decomposition reaction?
New compounds are formed by chemical bonding
The components of several molecules recombine to form new molecules,
A compound partitions into its components,
Answer:
A compound partitions into its components,
Explanation:
Decomposition reaction is a type of chemical reaction occur when compounds partition of breakdown into new components or elements.
An example is the decomposition of hydrogen peroxide. Hydrogen peroxide decomposed to water and oxygen. Another example is the decomposition or breakdown of water into hydrogen and oxygen.
Answer:
A compound partitions into its components
Explanation:
Mini Brain ProjectDirections: Conduct research on a selected brain area or structure. Areas and structures available for research include: frontal lobe, parietal lobe, temporal lobe, occipital lobe, medulla, pons, cerebellum, reticular formation, thalamus, hypothalamus, limbic system, cerebrum, hippocampus, amygdala, corpus callosum, Broca’s area, OR Wernicke’s area. Conduct research using scholarly Internet sources, library sources, and the textbook. What are its major functions? What techniques are used to view or measure it?What other structures is it near?What other structures help or perform similar functions?
Parietal lobe is one of the main lobes in the brain which is located at the upper back area in the skull. It process sensory information that it accepted from the outside world that is associated to touch, taste, and temperature. The techniques used to view the parietal lobe are Positron emission tomography (PET) and functional magnetic resonance imaging (fMRI).
Parietal lobe is near the top and center of the cerebral cortex just at the back of the frontal lobe and at the top of the occipital and temporal lobes.
The occipital lobe help the parietal lobe in visual perception and processing including spatil navigation and reasoning.
What does the term frameshift mean in science
Answer:
A frameshift mutation is a type of mutation involving the insertion or deletion of a nucleotide in which the number of deleted base pairs is not divisible by three.
Explanation:
Answer:
A frameshift mutation is a genetic mutation caused by a deletion or insertion in a DNA sequence that shifts the way the sequence is read. A DNA sequence is a chain of many smaller molecules called nucleotides.
HOPE IT WILL HELP U!
How are recycled materials stored?
please help!! :)
Answer:
Packaging waste management is the planning and organization of activities related to the collection, transport, storage, treatment and disposal of packaging waste, including the supervision of these activities and the care of post-closure waste management facilities.
Explanation:
The most important rule of recycling is that there is no pollution in the bin itself. This means that bottles and cans must be emptied and leftover food placed in another bucket.
Sort household waste into so-called Home packaging and other waste in groups and try to dispose of it in special containers for packaging waste. It may happen that there are no such containers in your area yet, the advice is to sort and separate the packaging waste and dispose of it in a container separately, because this sort will be easier to collect and pass on to the processing process.
Which process is part of translation but not transcription?
A DNA template is used to create an mRNA strand.
A tRNA template is used to create a DNA strand.
A tRNA template is used to create an mRNA strand.
An mRNA template is used to create an amino acid chain.
Answer:
An mRNA template is used to create an amino acid chain.
Explanation:
Transcription is the process where new mRNA is created from DNA. Translation, however, is the process of creating proteins by using mRNA as a template. Proteins are made up of amino acids often in the form of an amino acid chain.
The process that is part of translation but not transcription is "mRNA template is used to create an amino acid chain"
PROTEIN SYNTHESIS:
Protein synthesis is the process that synthesizes amino acid sequence (protein) from genes. The process involves two steps namely: transcription and translation. Transcription is the process whereby a DNA molecule is used to synthesize a mRNA molecule in the nucleus of the cell. Translation is the process whereby the mRNA transcript is used to synthesize an amino acid sequence in the ribosome. Therefore, the process that is part of translation but not transcription is "mRNA template is used to create an amino acid chain"Learn more at: https://brainly.com/question/11390351?referrer=searchResults
is this true or false, Surface waves result from a combination of up-and-down plus side-to-side motion.
Answer:
yaaa you knew that air is everywhere it moves
—————. Are small round structures in cells that break down large food particles into smaller ones
Answer:
Lysosomes
Explanation:
Lysosomes also break down old cell parts and release the substances so they can be used again.
Find the solution of the given initial value problem: (a) y
′
−y=2xe
2x
,y(0)=1 (b) y
′
+(cotx)y=2cscx,y(π/2)=1
(A) The answer to the initial value problem is given by \(\(y = (x^2 + 1)e^x\)\), where \(\(y' - y = 2xe^{2x}\)\) and \(\(y(0) = 1\)\).
(B) The resolution to the initial value problem can be expressed as \(\(y = \frac{2x - (\pi - 1)}{\sin(x)}\)\), where \(\(y' + \cot(x)y = 2\csc(x)\)\) and \(\(y\left(\frac{\pi}{2}\right) = 1\)\).
(A) To solve the initial value problem:
\(\[y' - y = 2xe^{2x}, \quad y(0) = 1\]\)
We can use an integrating factor method. To begin, let us express the equation in its standard form:
\(\[y' - y - 2xe^{2x} = 0\]\)
The integrating factor \(\(I(x)\)\) is given by \(\(I(x) = e^{\int -1 \, dx} = e^{-x}\)\).
To obtain the solution, apply the integrating factor to both sides of the equation and perform the multiplication.
\(\[e^{-x}(y' - y) - 2xe^{2x}e^{-x} = 0\]\)
This simplifies to:
\(\[e^{-x}y' - e^{-x}y - 2x = 0\]\)
Now, observe that the expression on the left-hand side represents the derivative of \(\((e^{-x}y)\)\) with respect to \(\(x\)\).
Using this observation, we can rewrite the equation as:
\(\[\frac{d}{dx}(e^{-x}y) - 2x = 0\]\)
Integrating both sides with respect to \(\(x\)\), we get:
\(\[e^{-x}y - \int 2x \, dx = C\]\)
where \(\(C\)\) is the constant of integration.
Integrating \(\(\int 2x \, dx\)\), we have:
\(\[e^{-x}y - x^2 + C = 0\]\)
To find the constant \(\(C\)\), we use the initial condition \(\(y(0) = 1\)\).
Substituting \(\(x = 0\)\) and \(\(y = 1\)\) into the equation, we get:
\(\[e^{0} \cdot 1 - 0^2 + C = 0\]\)
\(\[1 + C = 0\]\)
\(\[C = -1\]\)
Substituting \(\(C = -1\)\) back into the equation, we have:
\(\[e^{-x}y - x^2 - 1 = 0\]\)
Finally, we can solve for \(\(y\)\) by isolating it:
\(\[e^{-x}y = x^2 + 1\]\)
\(\[y = (x^2 + 1)e^x\]\)
(B) To solve the initial value problem:
\(\[y' + \cot(x)y = 2\csc(x), \quad y\left(\frac{\pi}{2}\right) = 1\]\)
We can use an integrating factor method. To begin, we will rewrite the equation in standard form:
\(\[y' + \cot(x)y - 2\csc(x) = 0\]\)
The integrating factor \(\(I(x)\)\) is given by:
\(\(I(x) = e^{\int \cot(x) \, dx} = e^{\ln(\sin(x))} = \sin(x)\).\)
Apply the integrating factor to both sides of the equation and perform the multiplication.
\(\[\sin(x)(y' + \cot(x)y) - 2\csc(x)\sin(x) = 0\]\)
This simplifies to:
\(\[\sin(x)y' + \cos(x)y - 2 = 0\]\)
Now, observe that the expression on the left-hand side represents the derivative of \(\((\sin(x)y)\)\) with respect to \(\(x\)\). Using this observation, we can rewrite the equation as:
\(\[\frac{d}{dx}(\sin(x)y) - 2 = 0\]\)
Integrating both sides with respect to \(\(x\)\), we get:
\(\[\sin(x)y -\)\(\int 2 \, dx = C\]\)
where \(\(C\)\) is the constant of integration. Integrating \(\(\int 2 \, dx\)\), we have:
\(\[\sin(x)y - 2x + C = 0\]\)
To find the constant \(\(C\)\), we use the initial condition \(\(y\left(\frac{\pi}{2}\right) = 1\).\)
Substituting \(\(x = \frac{\pi}{2}\)\) and \(\(y = 1\)\) into the equation, we get:
\(\[\sin\left(\frac{\pi}{2}\right) \cdot 1 - 2\left(\frac{\pi}{2}\right) + C = 0\]\)
\(\[1 - \pi + C = 0\]\)
\(\[C = \pi - 1\]\)
Substituting \(\(C = \pi - 1\)\) back into the equation, we have:
\(\[\sin(x)y - 2x + (\pi - 1) = 0\]\)
Finally, we can solve for \(\(y\)\) by isolating it:
\(\[\sin(x)y = 2x - (\pi - 1)\]\)
\(\[y = \frac{2x - (\pi - 1)}{\sin(x)}\]\)
\(\(y = \frac{2x - (\pi - 1)}{\sin(x)}\).\)
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The complete question is:
Find The Solution Of The Given Initial Value Problem:
(A) \(\(y' - y = 2xe^{2x}\)\), and \(\(y(0) = 1\)\)
(B) \(\(y' + \cot(x)y = 2\csc(x)\)\), and \(\(y\left(\frac{\pi}{2}\right) = 1\)\)
Which of the following is NOT something that both cells and virus share??
1. Which systems (2) are primarily responsible for movement of the body
Answer:
The correct answer is -muscular system and skeletal system.
Explanation:
The skeletal system and the muscular system work together to move the body or body parts. Different types of tissues form the muscular system that and their action on bones controls the movement of the body in vertebrates.
Tendons are tough muscles that attach with the bones and joints allow the movement by contraction of muscle that helps in moving bones from joint. Muscle normally acts by contracting and relaxing in pairs.
Activation energy is: The difference in energy between the products and transition state The difference in energy between the products and first intermediate The difference in energy between the starting materials and products The difference in energy between the starting materials and first intermediate The difference in energy between the starting materials and transition state Question 4 (1 point) Gibbs free energy is: The difference in energy between the products and first intermediate The difference in energy between the starting materials and first intermediate The difference in energy between the products and transition state The difference in energy between the starting materials and transition state The difference in energy between the starting materials and products
Activation energy and Gibbs free energy are both measures of the energy involved in chemical reactions. Activation energy is the energy required to start a reaction, while Gibbs free energy is the energy difference between the reactants and products.
Activation energy is the difference in energy between the starting materials and transition state. Activation energy refers to the energy that is required to initiate a chemical reaction.
This energy is needed to break the bonds in the reactants, which then allows the formation of new bonds to create the products. The activation energy is the minimum amount of energy that is required for a reaction to occur.
The activation energy can be provided through heat, light, or other forms of energy.
On the other hand, Gibbs free energy is the difference in energy between the starting materials and products. Gibbs free energy is a measure of the amount of energy that is available to do work. The Gibbs free energy change for a reaction tells us whether a reaction will be spontaneous or not.
A negative Gibbs free energy change indicates that a reaction is spontaneous, while a positive Gibbs free energy change indicates that a reaction is non-spontaneous.
In conclusion, activation energy and Gibbs free energy are both measures of the energy involved in chemical reactions. Activation energy is the energy required to start a reaction, while Gibbs free energy is the energy difference between the reactants and products.
These two concepts are important for understanding how and why chemical reactions occur.
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Which group of flasks acted as the experimental group and control group in Pasteur's experiment?
Answer: becteria
Explanation:
pasteur diveded micro-organisms in to severel group of and control groups.
Lymphatic tissue is found in the greatest quantity in.
Explanation:
The heart, lungs, intestines, liver, and skin also contain lymphatic tissue. The major lymphatic vessels are: the thoracic duct: It begins near the lower part of the spine and collects lymph from the pelvis, abdomen, and lower chest
Cấu tạo của đại não người
Answer:
Explanation:
của bạn đây:
Red blood cells _____. carry oxygen form clots carry carbon dioxide fight germs
Answer:
do
Explanation:
i took a cell class
5.8. Data are given below for two proteins. Protein Sax 1013 720 Concanavalin (jack bean) Myosin (cod) 6.40 6.43 Di. X 107 5.10 1.10 0.730 0.730 a. Calculate M for each. b. Calculate a Stokes's radius for each. c. Calculate fifo for each. d. Assuming that each is a sphere but hydrated enough to account for flfo, calculate the required hydration. e. Assuming that each is a prolate ellipsoid, hydrated to an extent of 0.2 cc H2O/cc protein, estimate al for each.
Protein Sax has a molecular weight (M) of 1013 and a Stokes's radius of 6.40. Protein Concanavalin (jack bean) has a molecular weight (M) of 720 and a Stokes's radius of 6.43. The fifo value for Protein Sax is 5.10, and for Protein Concanavalin (jack bean) it is 1.10. Assuming that both proteins are hydrated spheres, the required hydration can be calculated. Finally, assuming a prolate ellipsoid shape with a hydration level of 0.2 cc H2O/cc protein, the al value can be estimated for each protein.
Protein Sax:
M = 1013
Stokes's radius = 6.40
fifo = 5.10
Protein Concanavalin (jack bean):
M = 720
Stokes's radius = 6.43
fifo = 1.10
To calculate the required hydration for hydrated spheres, we use the formula:
required hydration = (fifo * M) / (4/3 * π * (Stokes's radius)^3)
For Protein Sax:
required hydration = (5.10 * 1013) / (4/3 * π * (6.40)^3)
For Protein Concanavalin (jack bean):
required hydration = (1.10 * 720) / (4/3 * π * (6.43)^3)
To estimate the al value for prolate ellipsoids, we multiply the hydration level (0.2 cc H2O/cc protein) by the molecular weight:
al = hydration level * M
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What are some human activities that change the environment?
Humans impact the physical environment in many ways: overpopulation, pollution, burning fossil fuels, and deforestation. Changes like these have triggered climate change, soil erosion, poor air quality, and undrinkable water
Other answers:
Overpopulation.
Pollution.
Global Warming.
Climate Change.
Genetic Modification.
Ocean Acidification.
Water Pollution.
Deforestation.