what are body building food

Answers

Answer 1

Answer:

Proteins

Explanation:

Red meat, peanut butter, protein shakes etc

Answer 2

Answer:

just go on a dirty or clean bluk

Explanation:


Related Questions

14. The elements in group_
are the most reactive metals.
15. The elements in group_
are the most reactive nonmetals.
16. The elements in group_
are very unreactive.
17. The elements in group_
react very violently with water.

Answers

Answer:

14 Hydrogen is a very reactive gas, and the alkali metals are even more reactive. In fact, they are the most reactive metals and, along with the elements in group 17, are the most reactive of all elements.

15 The halogen group of elements is the most reactive of the nonmetals. It is also the most reactive group of all chemical elements. Fluorine is the most reactive element in this group. Halogens are highly reactive because they are all electronegative.

16 Group 8A — The Noble or Inert Gases. Group 8A (or VIIIA) of the periodic table are the noble gases or inert gases: helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). The name comes from the fact that these elements are virtually unreactive towards other elements or compounds.

17 Group 1: Alkali Metals

Group 1 elements are called alkali metals because of their ability to displace H2(g) from water and create a basic solution. Alkali metals are also known to react violently and explosively with water.

the graph of the linear equetion 3x + 5y - 15 = 0 cuts the y - axis at the point full solution​

Answers

Answer:

y = \(-\frac{3}{5}x+3\)

Explanation:

3x + 5y - 15 = 0

So we want to get it in the form y = mx + b

Subtract 5y from both sides;

3x - 15 = -5y OR -5y = 3x - 15

Divide both sides by -5

y = \(-\frac{3}{5}x+3\)

Okazaki fragments become incorporated into which component of the dna replication complex?

Answers

Okazaki fragments become incorporated into the lagging strand of the DNA replication process.

In the field of Biology, DNA replication can be described as a process by which the DNA of an organism replicates and makes copies of itself.

The two strands of DNA act as template for duplication in the process of DNA replication. The DNA double helix unwinds the DNA and the DNA polymerase adds nucleotides to form the new strand of DNA.

However, for the lagging strand as DNA polymerase can not work in that direction, okazaki fragments which are short fragments of DNA are formed, to complete the replication of the lagging strand. Hence, the okazaki fragments are incorporated in the lagging strand.

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What is a benefit of using active solar energy over utility-scale solar energy for a home?

Installation costs are less with active solar systems.
Homeowner is not responsible for installation costs.
Energy comes from the active system, not a grid.
Homeowners will see less cost savings over time.

Answers

Your home's solar energy system can help you save money on you electricity bill and lessen your dependency on the grid.

Is solar power a good source of power?

In order to protect people, wildlife, and ecosystems, it is imperative that greenhouse gas emissions are reduced and climate change is mitigated. Solar energy plays a significant part in this as a renewable source of energy. Moreover, solar energy can reduce water use in energy generation and enhance air quality.

Solar panels' lifespan is how long?

Most solar panels last between 25 to 30 years, which is the industry average. A 25-year or longer production warranty is typically provided by reliable manufacturers.

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4.
The process of photosynthesis produces two very important products for most life forms on Earth. These products are --
A
glucose and oxygen, which are essential for cell respiration in plants and animals.
В.
carbon dioxide and water, which are essential for cell breathing in plants and animals.
nitrogen, which is necessary for protein synthesis.
D.
water, which is necessary to prevent an dehydration

Answers

Answer: A. glucose and oxygen, which are essential for cell respiration in plants and animals.

Explanation:

Which describes a way in which phosphorus may enter into the phosphorus cycle?
Earthquakes release phosphorus.
Phosphorus is carried in the rain that was evaporated from lakes.
Human use of fertilizers release phosphorus into the groundwater.
Phosphorus is transpired from the leaves of plants.

Answers

Answer:

Your answer would be C.) Human use of fertilizers release phosphorus into the groundwater.

Explanation:

Edge2021

The statement that best describes a way in which phosphorus may enter into the phosphorus cycle is as follows: Human use of fertilizers release phosphorus into the groundwater (option C).

How is phosphorus released into the atmosphere?

Phosphorus is a micronutrient needed by living organisms in the biosphere. It is also a vital component of the nucleic acid in living organisms.

The phosphorus cycle is the cyclic movement of phosphorus through the biogeochemical environment.

The way in which phosphorus is released into the phosphorus cycle is through anthropogenic activities i.e. the use of phosphorus-containing fertilizers.

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Which is the graph of the linear inequality 2*-3y<12

Answers

For the graph of the linear inequality 2*-3y<12, Based on the graph, Option 3 is the one that should be chosen.

This is further explained below.

What is graph?

Generally, The graph of the

Inequality 2 x-3 y<12

Solve for y,

2 x-12<3 y

\(y > \frac{2}{3} x-4\)

Now that we have the x-intercept and the y-intercept, we can draw the graph of the equation.

The x-intercept is when y equals zero,

2/3x-4=0

2/3 x=4

x=6

the y-intercept is when x=0

2/3(0)-4=y

y=-4

Therefore, the graph must pass between points (0,-4) and (6,0).

Now, we can determine that the area of the graph is

In conclusion,

Put x=0 and y=0

2(0)-3(0)<12

0<12

This is correct. Therefore, the area is moving toward its source.

The line is not continuous since the inequality does not contain an equal sign.

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Which is the graph of the linear inequality 2*-3y&lt;12
Which is the graph of the linear inequality 2*-3y&lt;12

why is Biology so hard?

Answers

Answer:

Imagine studying a cell. That cell has billions of things you can learn about. Now imagine 37.2 trillion cells each a little bit different but still similar. Now imagine that multiplied by all the different people there are on earth. Now then include all the other types of living animals.

That's biology

A hypothetical phylogeny for marsupial relatedness is shown here. Macropodidae is the marsupial family. Which of these statements is supported by the phylogenetic tree shown here? Select ALL that apply.
A) M. bicolor and M. parma are in the same subspecies category. Eliminate
B) M. agilis and M. eugenii share the most recent common ancestor.
C) T. thetis and P. xanthpus share the most characteristics in common.
D) T. thetis and P. xanthpus share the greatest number of taxa levels than other species.
E) M. agilis and M. eugenii share the greatest number of taxa levels than other species.

Answers

Answer: B and E

Explanation: USATESTPREP

10. takai, t. 2002. roles of fc receptors in autoimmunity. nat. rev. immunol. 2: 580–592. 11. lucas, m., x. zhang, v. prasanna, and d. m. mosser. 2005. erk activation following macrophage fcgammar ligation leads to chromatin modifications at the il-10 locus. j. immunol. 175: 469–477

Answers

Since the discovery of Fc Receptors and their purpose, it has been forty years. IgG receptors (FcR), high-affinity IgE receptors (FcRI), IgA and IgA/IgM receptors, and neonatal Fc receptor for IgG are all examples of Fc receptors (FcRn).

Particularly, the FcRs have a well-established involvement in the development of immune-mediated disorders as well as numerous biological processes connected to the response to infection and cancer. It has been suggested that Fc receptors, and FcRs in particular, which set a threshold for immune cell activation, have both positive and negative regulatory functions. When it comes to the transport of IgG through polarized epithelial barriers at mucosal surfaces and the regulation of IgG half-life, Fc receptors, like FcRn, have a new shape and function. The potential efficacy of targeting Fc receptors for medicinal purposes is highlighted by these various roles. The most recent data on this biology's therapeutic applications is compiled in this review.

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What is the correct answer to the question? Explain why you chose that answer.

What is the correct answer to the question? Explain why you chose that answer.

Answers

Answer:

I AND II

Explanation:

Answer: V and VI

Explanation:

These two species are directly from the common ancestor. They don't have as many possible changes that could've formed when I branched off. So they are more closely related because there are less differences.

Hope this helps!!! :)

In this assignment, you will conduct research to construct an explanation of how macromolecules are used in the body. You will then revise your explanation based on new information from additional research.

Answers

Answer:

Macro-molecules are used in the body after the conversion of micro-molecules.

Explanation:

Macro-molecules such as protein, carbohydrates and fats etc are bigger in size which can not be absorbed by the cell of the body so these Macro-molecules first broken down into micro-molecules such as amino acids, glucose and fatty acids etc. Protein is converted into amino acids, carbohydrates is converted into glucose and fats is converted into fatty acids by the action of different enzymes. These micro-molecules are used by the cell in order to generate energy.

Answer:

Macromolecules are important for the body and therefore, are used frequently. For example, “macromolecules provide structural support, a source of stored fuel, the ability to store and retrieve genetic information, and the ability to speed biochemical reactions.” There are four major types of macromolecules, those of which are as follows; proteins, carbohydrates, nucleic acids, and lipids. All of these play these important roles in the life of a cell. Macromolecules such as protein, carbohydrates and fats are bigger in size which can not be absorbed by the cell or the body, so these macromolecules are first broken down into micro-molecules, such as amino acids, glucose and fatty acids, etc. Protein is converted into amino acids, carbohydrates are converted into glucose, and fats are converted into fatty acids by the action of different enzymes. Proteins use amino acids which provide cell structure, send chemical signals, and speed up chemical reactions. Nucleic acids use nucleotides that store and pass on genetic information. Carbohydrates use monosaccharides (aka simple sugars) to provide cells with quick, short-term energy and a source of dietary fiber. Lipids use fatty acids and glycerol to provide cells with long-term energy, and they make up biological membranes. That is how macromolecules are used in the body.  

Explanation:

You have to do your own revisions and works cited.

Which activities characterizes the epidemiologic approach (as opposed to the clinical approach)?

Answers

The study of cancer occurrence in populations activities characterizes the epidemiologic approach  (as opposed to the clinical approach).

A condition known as cancer is one in which a small percentage of the body cells develop out of control and spread to other bodily regions. The human body, which has trillions of cells, is almost everywhere where cancer can begin. Human cells typically divide to create new cells as the body requires them through a process known as cell growth and multiplication. Old or damaged cells die, and new ones replace them when the body regenerates them.

This systematic process can occasionally go awry, causing damaged or aberrant cells to proliferate against their intended course. Tumors, or masses of tissue, can develop from these cells. Cancerous tumors can exist or not (benign). Invading neighboring tissues or spreading to distant locations inside the body, cancerous tumors

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The simulation shows a game of tug-of-war. Place a blue team and a red team with same-sized people on each side of the rope. What can you say about the sizes of the left and right arrows?

Answers

The sizes of the left and right arrows should be the same.

In the game of tug-of-war, the sizes of the left and right arrows represent the relative strengths of the blue team and the red team. If the blue team is stronger and pulling harder, the size of the left arrow would be larger than the size of the right arrow.

Conversely, if the red team is stronger, the size of the right arrow would be larger than the size of the left arrow. The sizes of the arrows indicate the force exerted by each team and provide a visual representation of the balance of power in the game.

In tug-of-war, the objective is for one team to overpower the other and pull the rope towards their side. The larger the arrow representing a team's strength, the greater their force and ability to move the rope in their direction.

The size of the arrows serves as a visual cue for spectators to understand which team has the advantage at any given moment. It helps to create a sense of competition and excitement as the teams struggle to gain control of the rope.

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In the United States, alcoholic beverages that are sold in stores display a government warning stating that pregnant women should not drink alcoholic beverages. This is because it prevents cleavage division from occurring, so a zygote cannot become a blastocyst. if a woman drinks alcohol while she is pregnant, she may not be able to ovulate again after childbirth. studies have proven that alcohol consumption causes long-lasting disorders in the fetus. the science of chemistry has shown that alcohol is a reactive substance that may interfere with the mother’s food digestion.

Answers

Answer:

The correct answer is - studies have proven that alcohol consumption causes long-lasting disorders in the fetus.

Explanation:

Alcohol can cross the barrier that the placenta creates between the mother and fetus so the alcohol can negatively impact the fetus or newborn by various means.

It can harm the fetus as it may result in damage to the cells of the fetus. Brain cells and spinal cord cells are prone to such kind of alcohol toxicity or syndrome. Alcohol spectrum disorder that affects the development of the baby which could be long-lasting.

Answer:

studies have proven that alcohol consumption causes long-lasting disorders in the fetus.

Explanation:

Which six of the following statements reflect angiosperm adaptations to life on land? (A) Seeds enable plant embryos to be dispersed long distances from the parent plant via wind or animals. (B) Spores contain a supply of stored food, enabling the embryo to remain dormant until conditions are suitable for germination. (C) In angiosperms, a gametophyte protects a dependent sporophyte from desiccation. (D) Floral parts of the sporophyte protect the reduced female gametophyte from drying out and from UV radiation. (E) Flowers attract animal pollinators carrying pollen from other plants of the same species. (F) Fruits aid in the dispersal of seeds by wind or by animals that carry or eat the fruits. (G) In many angiosperms, the male gametophyte contained in a pollen grain can be transported many miles away by wind or animal pollinators. (H) Seeds protect and nourish plant embryos, and fruits protect the seeds. (I) Fertilization in angiosperms is dependent on the presence of water.

Answers

The six statements that reflect angiosperm adaptations to life on land are (A), (D), (E), (F), (G), and (H).

(A) Seeds enable plant embryos to be dispersed long distances from the parent plant via wind or animals. This adaptation increases the chances of successful colonization in new habitats and reduces competition with parent plants.

(D) Floral parts of the sporophyte protect the reduced female gametophyte from drying out and from UV radiation. This protection ensures the survival of the female gametophyte, allowing for successful fertilization and seed development.

(E) Flowers attract animal pollinators carrying pollen from other plants of the same species. This mechanism facilitates cross-pollination, promoting genetic diversity and increasing the chances of successful reproduction.

(F) Fruits aid in the dispersal of seeds by wind or by animals that carry or eat the fruits. The fruits attract animals that consume them, and the seeds are later dispersed through the animal's droppings, ensuring the spread of offspring to new areas.

(G) In many angiosperms, the male gametophyte contained in a pollen grain can be transported many miles away by wind or animal pollinators. This allows for efficient fertilization and genetic mixing between different individuals.

(H) Seeds protect and nourish plant embryos, and fruits protect the seeds. This adaptation increases the survival rate of plant offspring by providing them with nutrients, protection from external factors, and a means of dispersal.

These adaptations collectively enhance the reproductive success and survival of angiosperms in terrestrial environments.

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What is true about theories?

What is true about theories?

Answers

the answers are B, C and E :)
I sure it’s B, C and E

science questions , may be out of order but please help asap ( about mitosis )

science questions , may be out of order but please help asap ( about mitosis )
science questions , may be out of order but please help asap ( about mitosis )
science questions , may be out of order but please help asap ( about mitosis )
science questions , may be out of order but please help asap ( about mitosis )
science questions , may be out of order but please help asap ( about mitosis )

Answers

Answer:

1. 2 chromatids, centromere, kinetochore

2. 56

3. It is a haploid gamete

4. Synthesis stage

5. Anaphase

6. G2

7.Cytokenesis

in seedless plants, a fertilized egg will develop into __________. see concept 29.2 (page 622)

Answers

In seedless plants, a fertilized egg will develop into a sporophyte. This is the second phase in plant reproductive life cycles, and it occurs after meiosis.

The sporophyte phase produces spores that will grow into gametophytes, which will produce the gametes that will eventually fuse to form the fertilized egg. During the sporophyte phase, the plant will produce haploid spores within specialized structures called sporangia. The spores then disperse and each spore develops into a gametophyte, which will produce haploid gametes.

These gametes will then fuse, forming the diploid fertilized egg. This process is known as alternation of generations and is characteristic of the life cycles of seedless plants. The fertilized egg will then develop into a new sporophyte. This cycle will then repeat itself, allowing for the continued reproduction of the seedless plant species.

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what are the similarities between dog and lion in the parts involved in taking food ​

Answers

Throat, Anus , digestive system teeth

If a diploid cell has 20 chromosomes, how many chromosomes will be in its haploid cell? If a germ cell has 10 chromosomes, how many chromosomes will be in its somatic cells? If a cell in G1 phase has 4 chromosomes, how many chromosomes will it have by the end of meiosis? If an unknown cell is going through mitosis, is it a germ cell or a somatic cell? By the time an unknown cell finishes meiosis, is it a haploid or somatic cell?​

Answers

Answer:

20

Explanation:

I'm randomly guessed

disadvantage of organic fertilizer​

Answers

Answer:

See below.

Explanation:

Organic fertilizer is more environmentally friendly and economical, but it comes at a different cost. These fertilizers are both harder to obtain and take more effort to formulate. Furthermore, these products are not created equally, meaning some of them may not work as well and have inconsistencies. Correspondingly, they are also lower in nutrients, meaning crops that rely on fertilizer will not grow as effectively and risk dying.

What form of DNA repair mechanism was most likely used for the pathway that resulted in deleting a gene? Explain how this repair mechanism works.

Answers

The most likely form of DNA repair mechanism that resulted in the deletion of a gene is non-homologous end joining (NHEJ), which involves the direct ligation of broken DNA ends without relying on a template.

Non-homologous end joining (NHEJ) is a DNA repair mechanism that occurs during the cell cycle, primarily in the G1 and early S phases. It is commonly employed to repair double-strand breaks (DSBs) in DNA, including those induced by radiation or other mutagenic agents.

NHEJ is an error-prone repair process that involves the direct ligation of broken DNA ends, without the need for a homologous template. This repair mechanism can sometimes lead to the loss or deletion of genetic material. When a DSB occurs, NHEJ is initiated by the binding of Ku proteins to the broken DNA ends.

The Ku proteins recruit other proteins, including DNA-dependent protein kinase catalytic subunit (DNA-PKcs), which facilitate the processing and alignment of the broken ends. The DNA ends are then joined together by DNA ligase IV, along with associated factors such as XRCC4 and XLF.

However, NHEJ does not require extensive homology between the DNA ends, and as a result, small insertions or deletions can occur during the repair process, leading to the loss or alteration of genetic information, such as the deletion of a gene.

The most likely form of DNA repair mechanism that results in the deletion of a gene is non-homologous end joining (NHEJ). NHEJ involves the direct ligation of broken DNA ends, without the need for a homologous template. While it is an efficient process for repairing double-strand breaks, it can also introduce errors, leading to the loss or deletion of genetic material, such as a gene.

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Please fill in!!

a. ATP
b. Light energy
C. C02
d. 02
e. Carbohydrate
f. Water

Would greatly appreciate if you answered like this:
18: ATP
19: etc..

Please fill in!! a. ATPb. Light energyC. C02d. 02e. Carbohydratef. WaterWould greatly appreciate if you

Answers

18. b

19. c

20. f

21. e

22. d

23. c

24. f

25. a

which genus is resident biota of the mouth, large intestine, and within the vagina from puberty to menopause?

Answers

Lactobacillus is the genus commonly found in the resident biota of the mouth, large intestine, and female genital tract from puberty to menopause, playing a crucial role in maintaining the body's health.

Which bacteria genus is found in the mouth, large intestine, and female genital tract from puberty to menopause?

Lactobacillus is a genus of Gram-positive, facultatively anaerobic bacteria that are commonly found in various parts of the human body, including the mouth, large intestine, and female genital tract. They are considered a part of the normal resident biota in these areas and play an important role in maintaining the body's health.

In the mouth, Lactobacillus species are involved in maintaining the natural balance of bacteria, which helps prevent the growth of harmful bacteria that can cause dental caries or gum disease. In the large intestine, they help in the digestion of food and the production of vitamins such as vitamin K, as well as preventing the overgrowth of harmful bacteria.

Within the female genital tract, Lactobacillus species are important in maintaining a healthy vaginal microbiome, which can help prevent the overgrowth of harmful bacteria that can cause infections such as bacterial vaginosis. Lactobacillus produces lactic acid, which lowers the vaginal pH and creates an acidic environment that inhibits the growth of pathogens.

During puberty to menopause, the presence of Lactobacillus in the vaginal microbiome is particularly important, as it helps maintain the proper pH and suppresses the growth of harmful microorganisms. Hormonal changes during this time can affect the composition of the vaginal microbiome, which can lead to an overgrowth of pathogenic bacteria and the development of infections.

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I will mark you the brainiest
its only one answer
Frontal lobe
Analogous
Carbon cycle
Capillaries
ATP
Food web
Homologous
Habitat fragmentation
photosynthesis
photic zone
embryonic evidence
female reproductive system
Capillary action
stomata
Amino acid
Solvent
Endosymbiotic theory
Cerebrum
Cellular respiration
Classification
A-is a red blood cell
B-is a red blood cell
Dna evidence
Solute
Carrying capacity
carbohydrate

I will mark you the brainiestits only one answerFrontal lobeAnalogousCarbon cycleCapillariesATPFood webHomologousHabitat

Answers

it’s glycine, an amino acid.

Explain the role of
lysosomes in cells.

Answers

Lysosomes are a membrane, the roles involve degrading and recycling cellular waste.

degrading and recycling cellular waste

how can changes in experimental conditions affect enzyme-mediated reactions?

Answers

Changes in experimental conditions can have a significant impact on enzyme-mediated reactions. Enzymes are biological catalysts that facilitate chemical reactions in living organisms. Here are some ways in which changes in experimental conditions can affect enzyme-mediated reactions:

TemperaturepHSubstrate ConcentrationEnzyme ConcentrationInhibitors and ActivatorsCo-factors and Coenzymes

Temperature: Enzyme activity is affected by temperature. Increasing the temperature generally enhances the reaction rate by providing more energy for the enzyme-substrate interaction. However, excessively high temperatures can denature the enzyme, leading to a loss of activity. Lower temperatures may slow down the reaction rate.

pH: Enzymes have an optimal pH at which they exhibit maximum activity. Deviating from this optimal pH can affect the enzyme's structure and disrupt its ability to bind to the substrate. Changes in pH can lead to altered ionization states of amino acid residues in the enzyme's active site, affecting enzyme-substrate interactions.

Substrate Concentration: The concentration of the substrate can influence the rate of an enzyme-catalyzed reaction. As substrate concentration increases, the rate of the reaction typically increases until the enzyme's active sites become saturated. At this point, further increases in substrate concentration will not significantly increase the reaction rate.

Enzyme Concentration: The concentration of the enzyme itself can affect the reaction rate. Higher enzyme concentrations generally lead to faster reaction rates, assuming other factors are not limiting. More enzyme molecules mean a greater chance of collisions with the substrate.

Inhibitors and Activators: Various substances can inhibit or activate enzyme activity. Competitive inhibitors compete with the substrate for binding to the enzyme's active site, thereby reducing the reaction rate. Non-competitive inhibitors bind to the enzyme at a site other than the active site, causing conformational changes that reduce catalytic activity. Activators, on the other hand, enhance enzyme activity.

Co-factors and Coenzymes: Enzymes may require specific co-factors or coenzymes to function properly. Changes in the availability or concentration of these cofactors or coenzymes can impact the enzyme's activity. For example, some enzymes require metal ions or vitamins as co-factors for catalytic activity.

It's important to note that the specific effects of changes in experimental conditions on enzyme-mediated reactions can vary depending on the particular enzyme and reaction being studied. Experimental optimization is often necessary to determine the ideal conditions for maximizing enzyme activity and reaction efficiency.

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within a cell, DNA is housed in the blank

Answers

Answer: nucleus
Explanation

Within a cell, DNA is housed in the nucleus (in eukaryotic cells) or in the nucleoid region (in prokaryotic cells).

What is DNA?

DNA (Deoxyribonucleic acid) is a molecule that carries the genetic instructions used in the growth, development, functioning, and reproduction of all living organisms and many viruses. It is a long, double-stranded helical molecule composed of nucleotides, which are the basic building blocks of DNA.

Each nucleotide consists of a sugar molecule (deoxyribose), a phosphate group, and a nitrogenous base (adenine, guanine, cytosine, or thymine). The sequence of these bases determines the genetic code carried by the DNA molecule.

Thus, the DNA is housed in the nucleus in eukaryotic cells and in the nucleoid region in prokaryotic cells.

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An ionic bond is formed as the result of?

A) transferring electrons
B) sharing electrons
C) transferring protons
D) sharing protons

Answers

A) transferring of electrons
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What are the differing attitudes between the colonizer and the colonized? on january 1, 2024, paradise tours borrows $47,000 by agreeing to a 6%, six-year note with the bank. loan payments of $778.93 are due at the end of each month with the first installment due on january 31, 2024. Record the issuance of the installment note payable and the first two monthly payment. Sales and purchase-related transactions using perpetual inventory system The following were selected from among the transactions completed by Essex Company during July of the current year. Essex uses the net method under a perpetual inventory system. July 3. Purchased merchandise on account from Hamling Co., list price $85,000, trade discount 25%, terms FOB shipping point, 2/10, n/30, with prepaid freight of $960 added to the invoice. 5. Purchased merchandise on account from Kester Co., $47,550, terms FOB destination, 2/10, n/30. 6. Sold merchandise on account to Parsley Co., $16,680, terms n/15. The cost of the goods sold was $9,440. 7. Returned merchandise with an invoice amount of $13,500 purchased on July 5 from Kester Co. 13. Paid Hamling Co. on account for purchase of July 3. 15. Paid Kester Co. on account for purchase of July 5, less return of July 7. 21. Received cash on account from sale of July 6 to Parsley Co. 21. Sold merchandise on MasterCard, $212,670. The cost of the goods sold was $144,350. 22. Sold merchandise on account to Tabor Co., $60,200, terms 2/10, n/30. The cost of the goods sold was $33,820. 23. Sold merchandise for cash, $38,610. The cost of the goods sold was $22,180. 28. Paid Parsley Co. a cash refund of $6,070 for returned merchandise from sale of July 6. The cost of the returned merchandise was $3,630. 31. Paid MasterCard service fee of $3,510.Instructions Journalize the transactions. A buyer entered into a written contract with a seller to purchase his commercial property for $100,000. The contract did not specify the quality of title to be conveyed, and made no mention of easements or reservations. The closing was set for November 25, three months from the signing of the contract. Shortly thereafter, the buyer obtained a survey of the property, which revealed that the city had an easement for the public sidewalk that ran in front of the store. Because this actually enhanced the value of the property, the buyer did not mention it to the seller. Subsequently, the buyer found a better location for her business. On November 1, the buyer notified the seller that she no longer intended to purchase the property. The seller told her that he intended to hold her to her contract. At closing, the buyer refused to tender the purchase price, claiming that the seller's title is unmarketable and citing the sidewalk easement as proof of that fact. In a suit for specific performance, will the seller likely prevail? A: Yes, because the contract did not specify the quality of title to be conveyed. B: Yes, because the buyer was aware of the visible easement and it enhanced the value of the property. C: No, because an easement not provided for in the contract renders title unmarketable. D: No, because the buyer gave the seller sufficient notice of her change in plans and yet he made no effort to try to find another purchaser. Is the US an open or closed economy? Finding probabilities for the t-distribution Question 5: Find P(X -2.262) where X follows a t-distribution with 9 df. Question 7: Find P(Y sketch a cylinder with radius 7 feet and height 10 feet, then find the total surface area using the formula An adequate intake rather than an RDA has been set for water because of individual differences in fluid needs based on which of the following?1. Climate. 2. Activity level. 3. Metabolism. 4. All of these are correct loyd has almost perfect episodic memory. it is likely that his ______ is larger than most individuals and is better connected with his hippocampus. If the gravity of the moon is 1/6 of Earths gravity, what is the mass of an object that has a weight of 115N on the moon? a)89 b)71.9 c)30.2 d)20