What are all of the steps to get 17=5y-3

Answer: 9/4 and -2/1 (or -2)

Step-by-step explanation: Reciprocals are just the fraction flipped

Answer:

A) 30 fish

Step-by-step explanation:

1/3 can be put into 1 three times

3 x 10 liters = 30 fish

Answer:

30

Step-by-step explanation:

10 liters of water divided by 1/3 is the equation

first you imply keep ,change ,flip

keep the 10/1 change the division sign to multiplication and flip 1/3 to 3/1

everything changed should be 10/1 times 3/1 and that equals 30

The work required to raise the bucket and the remaining grain to the top is approximately 2,400 Joules.

To calculate the work required, we need to consider two components: the work required to lift the bucket and the work required to lift the remaining grain.

The work required to lift the bucket can be calculated using the formula:

Work_bucket = force_bucket * distance,

where force_bucket is the weight of the bucket and distance is the height it is lifted.

The weight of the bucket can be calculated as the product of its mass and the acceleration due to gravity:

Weight_bucket = mass_bucket * g,

where mass_bucket is the mass of the bucket (2 kg) and g is the acceleration due to gravity (9.8 m/s^2).

Substituting the values, we have:

Weight_bucket = 2 kg * 9.8 m/s^2 = 19.6 N.

The distance the bucket is lifted is 20 m.

Therefore, the work required to lift the bucket is:

Work_bucket = 19.6 N * 20 m = 392 J.

Next, we calculate the work required to lift the remaining grain. The weight of the remaining grain can be calculated in a similar way:

Weight_grain = mass_grain * g,

where mass_grain is the mass of the remaining grain (12 kg) and g is the acceleration due to gravity (9.8 m/s^2).

Substituting the values, we have:

Weight_grain = 12 kg * 9.8 m/s^2 = 117.6 N.

The distance the remaining grain is lifted is 10 m.

Therefore, the work required to lift the remaining grain is:

Work_grain = 117.6 N * 10 m = 1176 J.

To find the total work required, we add the work required to lift the bucket and the work required to lift the remaining grain:

Total work = Work_bucket + Work_grain = 392 J + 1176 J = 1568 J.

Therefore, the total work required to raise the bucket and the remaining grain to the top is approximately 2,400 Joules.

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The graph of the parametric equations x = -2cos(t) and y = -sin(t) within the range 0 ≤ t < 2π is an ellipse centered at the origin, with the major axis along the x-axis and a minor axis along the y-axis.

To sketch the graph of the parametric equations x = -2cos(t) and y = -sin(t), where 0 ≤ t < 2π, we need to plot the coordinates (x, y) for each value of t within the given range.

1. Start by choosing values of t within the given range, such as t = 0, π/4, π/2, π, 3π/4, and 2π.

2. Substitute each value of t into the equations to find the corresponding values of x and y. For example, when t = 0, x = -2cos(0) = -2 and y = -sin(0) = 0.

3. Plot the obtained coordinates (x, y) on a graph, using a coordinate system with the x-axis and y-axis. Repeat this step for each value of t.

4. Connect the plotted points with a smooth curve to obtain the graph of the parametric equations.

The graph will be an ellipse centered at the origin, with the major axis along the x-axis and a minor axis along the y-axis. It will have a vertical compression and a horizontal stretch due to the coefficients -2 and -1 in the equations.

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Answer:

the number would be the same

Step-by-step explanation:

Answer:

10 customers

Step-by-step explanation:

16x+4y=360

x=20

16(20)=320

320+4y=360

4y=40

y=10

Answer:

Step-by-step explanation:

There's no such thing as answer for this, as this is an algebraic expression.

Answer:

4x^2-13x+4

Step-by-step explanation:

(x^2-5x+6)+(3x^2-8x-2)

Combine like terms

x^2+3x^2-5x-8x+6-2

4x^2-13x+4

Answer:

54,280

Step-by-step explanation:

In Pic

Let's start by defining some variables: Let x be the airspeed of the first plane in kilometers per hour.
Then the airspeed of the second plane is x+80 km/h.

Let t be the time in hours that the first plane flies before the second plane starts.
After two hours, the first plane has flown for t+2 hours, and the second plane has flown for t hours. To solve for the airspeeds, we need to use the formula: distance = rate x time.

The distance the planes fly in opposite directions is the sum of the distances each plane flies:
distance = (x)(t+2) + (x+80)(t), We are told that after two hours, the planes are 3165 kilometers apart, so we can set up an equation: 3165 = (x)(t+2) + (x+80)(t).

Simplifying this equation:
3165 = xt + 2x + xt + 80t + 80
3165 = 2xt + 82t + 2x + 80
3165 = 2t(x+40) + 2x + 80
3085 = 2t(x+40) + 2x

Now we can solve for x:
3085 = 2t(x+40) + 2x
3085 = 2tx + 80t + 2x
3085 = 4tx + 80t
38.5625 = tx + 20t
1.928125 = x + 20

So the airspeed of the first plane is x = 1.928125 - 20 = 18.071875 km/h.
The airspeed of the second plane is x+80 = 18.071875 + 80 = 98.071875 km/h. Let's denote the airspeed of the first plane as x km/h and the airspeed of the second plane as (x + 80) km/h.


Since the planes fly in opposite directions, the sum of the distances they travel is equal to the distance between them, which is 3165 km. Therefore, we can write the equation: 2x + 1.5(x + 80) = 3165

Now we can find the airspeed of the second plane: x + 80 = 870 + 80 = 950 km/h, So, the first plane's airspeed is 870 km/h and the second plane's airspeed is 950 km/h.

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In ∆JKL and ∆MLK

Hence

∆JKL≅∆MLK(Side-Angle-Side)

by SAS property of congruency of triangles, ΔJKL and ΔMLK are congruent.  

Given that :

JK ≅ ML

∠JKL ≅ ∠MLK

To Prove: △JKL ≅ MLK

Proof:

We know that corresponding angles formed by transversal line are congruent.

Hence ∠JKL = ∠ MLK ...(i)

Now consider triangles ΔJKL and triangles  ΔMLK

JK = LM  {Given}  , This means that Line JK is Congruent to Line LM. Two congruent lines means they are equal. Thus; JK = LM.

∠JKL = ∠ MLK { Using (i) }

KL = KL  {common sides}

Hence by SAS property of congruency of triangles, ΔJKL and ΔMLK are congruent.  

Hence proved.

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Answer:

\(\sqrt{2000}\phantom{a}yards\)

Step-by-step explanation:

For a right triangle, \(a^{2} =b^{2} +c^{2}\), if a is the hypotenuse. So, \(60^{2} =40^{2} +c^{2}\), and c is the the distance we are trying to find:

\(60^{2} =40^{2} +c^{2}\)

\(3600=1600+c^{2}\)

\(c^{2} =2000\)

\(c=\sqrt{2000}\phantom{a} yards\)

Answer:

34

Step-by-step explanation:

just divide the question substract 2

The Values of (a+b)ab are undefined.

Given that, a = 3an and db = -2We need to find the values of (a+b)

Now, we have a = 3an... equation (1)Also, we have db = -2... equation (2)From equation (1), we get: n = 1/3... equation (3)Putting equation (3) in equation (1), we get: a = a/3a = 3... equation (4)Now, putting equation (4) in equation (1), we get: a = 3an... 3 = 3(1/3)n = 1

From equation (2), we have: db = -2=> d = -2/b... equation (5)Multiplying equation (1) and equation (2), we get: a*db = 3an * -2=> ab = -6n... equation (6)Putting values of n and a in equation (6), we get: ab = -6*1=> ab = -6... equation (7)Now, we need to find the value of (a+b).For this, we add equations (1) and (5),

we get a + d = 3an - 2/b=> a + (-2/b) = 3a(1) - 2/b=> a - 3a + 2/b = -2/b=> -2a + 2/b = -2/b=> -2a = 0=> a = 0From equation (1), we have a = 3an=> 0 = 3(1/3)n=> n = 0

Therefore, from equation (5), we have:d = -2/b=> 0 = -2/b=> b = ∞Now, we know that (a+b)ab = (0+∞)(0*∞) = undefined

Therefore, the values of (a+b)ab are undefined.

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Answer:

y=-4/3x-4

Step-by-step explanation:

The equation of the line that is perpendicular to the line which has a slope of 3 / 4 and passes through the point ( 0, - 4 ) is equals to \(y= \frac{-4}{3} x-4\)

" Equation of line is defined as the equation which represents the set of points using slope."

Formula used

\(y=mx+c\)

m = slope of the line

c = y-intercept

Product of the Slopes of perpendicular lines  = -1

According to the question,

Slope of the given line = \(\frac{3}{4}\)

Using condition for slope of perpendicular lines we have,

Slope of the line perpendicular to the given line 'm' = \(\frac{-4}{3}\)

From given point (0, -4)

Y- intercept 'c' = -4

Substitute the value in the formula to get equation of required line,

\(y= \frac{-4}{3} x-4\)

Hence,  equation of the line that is perpendicular to the line which has a slope of 3 / 4 and passes through the point ( 0, - 4 ) is equals to \(y= \frac{-4}{3} x-4\).

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Answer:

ssa

Step-by-step explanation:

The Hillsboro Inlet Lighthouse lights up approximately 100.5 more square miles than the Jupiter Inlet Lighthouse.

To calculate the difference in area between the two lighthouses, we need to find the area of the circles that are illuminated by each lighthouse. The formula for the area of a circle is A = πr², where A is the area and r is the radius of the circle.

The Jupiter Inlet Lighthouse has a height of 18 meters, so its light can be seen up to a distance of approximately 17.5 nautical miles (NM), or 32.4 kilometers (km). The radius of the circle illuminated by this lighthouse is 17.5 NM or approximately 32.4 km. Therefore, the area illuminated by the Jupiter Inlet Lighthouse is approximately 3,310 square kilometers.

On the other hand, the Hillsboro Inlet Lighthouse has a height of 28 meters, so its light can be seen up to a distance of approximately 21.6 NM, or 40 km. The radius of the circle illuminated by this lighthouse is 21.6 NM or approximately 40 km. Therefore, the area illuminated by the Hillsboro Inlet Lighthouse is approximately 6,347 square kilometers.

To find the difference in the area, we subtract the area illuminated by the Jupiter Inlet Lighthouse from the area illuminated by the Hillsboro Inlet Lighthouse, which is approximately 3,037 square kilometers. Therefore, the Hillsboro Inlet Lighthouse lights up approximately 100.5 more square miles than the Jupiter Inlet Lighthouse.

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The side lengths 300 mm and 190 mm make a valid triangle because of the triangle inequality theorem

The side lengths are given as

300 mm and 190 mm

To solve this question, we make use of the triangle inequality theorem

The triangle inequality theorem states that

Given that the sides of a triangle are x, y and z.

The sum of any two sides of a triangle is greater than or equal to the third side;

This means that

x + y ≥ z

Using the above as a guide, we have the following inequality expressions

300 + 190 ≥ z

300 + z ≥ 190

z + 190 ≥ 300

Evaluate the inequality expressions

490 ≥ z

z ≥ -110

z  ≥ 110

Remove the negative value

490 ≥ z

z ≥ 110

Combine the inequalities

110 ≤ z ≤ 490

The above inequality is a valid inequality expression

Hence, the side lengths 300 mm and 190 mm make a valid triangle

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Answer:

E

Step-by-step explanation:

The first quadrant is the top-right one

If a point is in the first quadrant, the x- and y-values of the point are both positive

Let's go through the one by one.

A) Translating the quadrilateral right 4 units will make the new S to be \((-3+4, -7)=(1, -7)\), which is not in the first quadrant.

B) Reflection the quadrilateral across \(x=4\) will not change the y-value of any points. So, the new S will stay below the x-axis, and thus will never be in the first quadrant, because it will always have a negative y-value.

C) This one is tricky. We can prove(the proof is just taking cases of which quadrant) that if a point is in the second or fourth quadrant, it's reflection across the line \(y=-x\) will always be in the same quadrant it started in(i.e. reflect a point in the second quadrant, you get a point in the second quadrant). We know that P is in the second quadrant, so the new P will also be in the second quadrant. Therefore, the new quadrilateral will not be entirely in the first quadrant.

D) We intuitively(and can prove) that because R is right underneath Q, the new R will be directly to the left of Q, with the same distance as Q to original R. So, the new R will be \((-10, 12)\) using above method. This point is not in the first quadrant.

E) We know intuitively(and can prove) that a reflection across the line \(x=3\) will make the entire quadrilateral in the first and fourth quadrant. However, When we translate up, the new S, the lowest point on the quadrilateral, will be above the x-axis, making all the points in the first quadrant! Therefore, E works.

F) When we reflect across the x-axis, any points in the second quadrant go to the third quadrant. So, the new P will be in the third quadrant. However, when we translate up 13 units, the new P will go to the second quadrant. It will never cross the y-axis, and will always have a negative x-coordinate. Therefore, P will not be in the first quadrant.

Summing up the cases that work, we get that \(\boxed{E}\) is the only answer.

The transformations of quadrilateral PQRS which would result in the image of the quadrilateral being located only in the first quadrant of the coordinate plane is:

This refers to the axis of a two dimensional Cartesian system which is one side out of four quarters of a circle or given shape.

From the given image, we can see that the first quadrant is at the top.

With this, we can see that the transformation which would make the quadrilateral PQRS to be in the first quadrant is a reflection across x=3, then a translation up 8 units.

This is because when we translate up, then we can see that the x-y values of the point are positive and which would make the translation up 8 points.

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Answer:

Step-by-step explanation:

Together they can paint in 1 hour:

Let them complete the painting in x hours.

The expression we need is:

Answer:

1234

Step-by-step explanation:

The value of the union of sets A and B is, P(A ∪ B) is 0.64.

The union of two sets means the total elements in both the sets combined.

Given: sets P(A) = 0.38, P(B) = 0.83, and  intersection P(A ∩ B) = 0.57

We need to find the union of P(A ∪ B).

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

Let us substitute the given values in the formula.

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

=0.38+0.83-0.57

=1.21-0.57

=0.64

Therefore, the value of union of sets P(A ∪ B) is 0.64.

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Answer:

True

Step-by-step explanation:

Actually, I'm pretty sure it can also be a reflection! :) Have a good day!!!

Answer: you forgot to carry the 2

Step-by-step explanation: because i'm smart

The total volume inside the storage tank is 586 cubic meters.

What is volume?

The volume of any three-dimensional solid is just the amount of space it occupies. These solids can include a cube, cuboid, cone, cylinder, or sphere.

We are given that a storage tank is in the shape of a cylinder with a hemisphere on the top and the highest point is 13 meters above the floor of the storage tank with the diameter inside the cylinder measuring 8 meters.

Now, by applying the cylinder and hemisphere formula, we get

⇒ Volume = π\(r^{2}\)h + \(\frac{2}{3}\)π\(r^{3}\)

⇒ Volume = π * \(4^{2}\) * 9 + \(\frac{2}{3}\) * π * \(4^{3}\)

⇒ Volume = π * ((16* 9)+ (\(\frac{2}{3}\) * 64))

⇒ Volume = π * (144+ 42.67)

⇒ Volume = 33.14 * (144+ 42.67)

⇒ Volume = 33.14 * 186.67

⇒ Volume = 586.14 cubic meters

Hence, the total volume inside the storage tank is 586 cubic meters.

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Answer: 49.25

Step-by-step explanation:

ANSWER:

$148,655.8

STEP-BY-STEP EXPLANATION:

Given:

Original salary = $28,000

Increase per year = 3%

The sum of all the earnings would be the sum of the original salary, the salary after 1 year, the salary after 2 years, the salary after 3 years and the salary after 4 years.

The salary in each year is calculated by multiplying the original salary by the increase raised after n years, just like this:

Therefore, the total earnings would be as follows:

Therefore, the earnings in the first 5 years of MARla is $148,655.8

∠g and ∠h are complementary angles and ∠g and ∠h are acute angles are true statements from the given information

Two angles are given.

∠g = (2x-90)°

∠h = (180-2x)°

We have to find the statement which is true about the angles g and h.

If both angles are greater than zero.

Complementary angles add up to 90 degrees

i.e., ∠g and ∠h are complementary if ∠g + ∠h = 90°.

Substituting the given values:

∠g + ∠h

= (2x-90)° + (180-2x)° = 90°

Thus, ∠g and ∠h are complementary angles.

and both the angles are less than 90 degrees so we can tell that angles ∠g and ∠h  are acute.

So the statement ∠g and ∠h are acute angles is also true

Hence, ∠g and ∠h are complementary angles and ∠g and ∠h are acute angles are true statements

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