Explanation:
Weight loss and weight maintenance.
Muscle gain.
Improved mood.
Improved heart health.
Select the correct answer from each drop-down menu.
Scientific theories are always
testable
. A theory may be changed as a result of
.
Scientific theories are always testable. A theory may be changed as a result of new observations.
What are Scientific theories ?A scientific theory is a set of laws, facts and hypotheses that have a complete vision of an aspect of reality.
It is a proposed explanation for a set of observable phenomena.
It allows in this way to organize and understand the observations and to be able to predict or provoke other future observations.
Theories can be modified or improved as more information is collected.
That is, theories can continue to be tested indefinitely, and eventually rejected, if the tests lead to it.
Therefore, a scientific theory is testable by using a research method.
As mentioned, any theory can be tested or rejected as more information is collected.
This information to prove or reject theories are interpretations of observable facts, which generates new statements or allows to accept those already included in the theory.
Then, a theory may be changed as a result of new observations.
Finally, scientific theories are always testable. A theory may be changed as a result of new observations.
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Answer:
testable & new observations
Explanation:
How did the Heisenberg uncertainty principle contribute to the idea that electrons occupy “clouds,” or “orbitals”?
Conduct an inventory of hazardous chemicals in your home. Determine the proper disposal method for each item found. 4/14
Proper disposal methods vary depending on the specific chemical, so it is recommended to consult local regulations and authorities to determine the appropriate disposal methods for each hazardous item found.
As I do not have access to the specific hazardous chemicals present in your home, it is essential to conduct a thorough inventory yourself. Start by examining various areas such as the garage, kitchen, bathroom, and cleaning supplies to identify hazardous substances like old paint, pesticides, solvents, batteries, expired medications, and cleaning agents.
Once hazardous chemicals are identified, it is important to handle them with caution, following any safety instructions provided on the labels or packaging. To determine the proper disposal method for each item, consult local guidelines and regulations.
Local authorities, waste management facilities, or recycling centers can provide information on collection events, drop-off locations, or special disposal procedures. It is crucial to follow these guidelines to ensure the safe and responsible disposal of hazardous chemicals, minimizing the potential risks to human health and the environment.
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A 11.0g sample of a compound containing only oxygen and carbon produce 3.0g carbon and 8.0g oxygen. Determined the empirical formula of the compound?
Answer:
Empirical formula: CO₂
Explanation:
The empirical formula is defined as the simplest ratio of atoms present in a molecule. We must convert the mass of carbon and oxygen to moles as follows:
Carbon -Molar mass: 12.01g/mol-
3.0g * (1mol / 12.01g) = 0.250 moles C
Oxygen -Molar mass: 16g/mol-
8.0g * (1mol / 16g) = 0.50 moles O
The ratio of O:C is:
0.50mol / 0.250mol = 2
That means the empirical formula is:
CO₂Which molecule has the shortest carbon-oxygen bond length?
A. CH3COOH
B. CH3CH2OH
C. CO₂
D. CO
What makes up all of the populations in an area
Answer:
The number of people in that specific area.
Explanation:
help pls:))!!!!!!!!!!
Answer: C
Explanation:
ocean water is about 0.600 m nacl and has a densituiu of about 1.027g/ml. calculate the percent composition of alt in sea water
The percent composition of salt (NaCl) in sea water is approximately 3.41%.
To calculate the percent composition of salt (NaCl) in sea water, we'll first determine the mass of NaCl in 1 liter of sea water and then find the percentage.
1. Calculate the mass of NaCl in 1 liter of sea water:
0.600 mol NaCl/L * (58.44 g NaCl/mol) = 35.064 g NaCl
2. Calculate the total mass of 1 liter of sea water:
Density = Mass/Volume
1.027 g/mL * 1000 mL = 1027 g
3. Calculate the percent composition of NaCl in sea water:
(35.064 g NaCl / 1027 g sea water) * 100 = 3.41%
Hence. the correct answer is 3.41%
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How many atoms of neon are in 56. 22 liters of neon gas?
To find the number of atoms of neon in 56.22 L of neon gas, we will use the Avogadro's Law equation.Moles = Volume/22.4 liters Avogadro's number = 6.022 x 10²³ atoms/moleThe mass of a mole of neon is 20.18 g/mole.Let's find out.
How many moles of neon are in 56.22 liters of neon gas.Number of moles = 56.22/22.4 = 2.51 moles of neon atomsNow, we can calculate the number of atoms in 56.22 liters of neon atoms using the Avogadro's Law.Number of neon atoms = 6.022 x 10²³ atoms/mole × 2.51 moles of neon atoms= 15.1 x 10²³ neon atomsIn 56.22 L of neon gas, there are approximately 15.1 x 10²³ atoms of neon.
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Atoms from a heated filament impinge on a plate and stick to the surface (this is known as thermal evaporation). The atoms can be assumed to strike any area of the plate with equal probability. You can also assume that atoms do not move around after they strike the plate. Suppose that you evaporate enough metal from the filament so that the average thickness of the film covering the plate is 6 atomic layers. What fraction of the plate area is not covered by any atoms at all
The fraction of the plate area that is not covered by any atoms at all if metal from the filament so that the average thickness of the film covering the plate is 6 atomic layers is 83.33%.
To find the fraction of the plate area, we must assume that the fraction of the plate that is covered by atoms be f. It's given that the average thickness of the film covering the plate is 6 atomic layers. The area of a single atomic layer is equal to the area of the plate divided by the number of atomic layers.
The fraction of the plate that is not covered by any atoms at all can be expressed as (1-f). The total number of atomic layers that hit the plate is 6. So, the number of atomic layers that missed the plate is (6-1) = 5. Therefore, (1-f) = 5/6 = 0.8333.
Thus, the fraction of the plate area that is not covered by any atoms at all is 0.8333 or 83.33%.
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List all assumptions please.
Air is compressed in a car engine from 22 °C and 95 kPa in a reversible and adiabatic manner. If the compression ratio, V1/V2 of this piston-cylinder device is 8, determine the final temperature of the air. Assume the air is an ideal gas and: kair = 1.4, cv,air = 0.717 J/g.K, cp,air =1.004 J/g.K, Mair = 28.97 g/mol
The final temperature of the air after compression is approximately 552.67 K.
To determine the final temperature of the air when it is compressed in a car engine from 22 °C and 95 kPa in a reversible and adiabatic manner with a compression ratio \(V_1/V_2\)of 8, we need to consider the following assumptions:
1. The compression process is reversible and adiabatic. This means there is no heat transfer to or from the system and the process is carried out with no entropy generation.
2. The air is an ideal gas. This implies that the air obeys the ideal gas law (PV = nRT) and its properties depend only on temperature.
3. The specific heat capacities of air (cv,air and cp,air) and the adiabatic index (kair) are constant during the compression process.
4. The molar mass of air (Mair) is provided and constant.
Given the information and assumptions, we can use the adiabatic relation for ideal gases to calculate the final temperature ( \(T_2\)) of the air:
\(T_2\) = \(T_1\) ×\((V_1/V_2)^(k_a_i_r_ -_1)\)
Where:
\(T_1\) = Initial temperature = 22 °C = 295.15 K (converting to Kelvin)
\(V_1/V_2\)= Compression ratio = 8
kair = Adiabatic index = 1.4
Now, calculate \(T_2\):
\(T_2\) = 295.15 × \((8)^(^1^.^4 ^- ^1^)\)
\(T_2\) = 295.15×\((8)^0^.^4\)
\(T_2\) ≈ 552.67 K
Therefore, The final temperature of the air after compression is approximately 552.67 K.
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Advertisers use the
because companies hope that repeated exposure to their product will make people feel familiar with it and more likely to buy it.
Advertisers use the familiarity effect because companies hope that repeated exposure to their product will make people feel familiar with it and more likely to buy it.
What is familiarity effect ?Psychologists have even discovered that the more you see someone, the more likely you are to develop attraction for them. Even if the stimuli you are repeatedly exposed to is negative, you will find comfort in its familiarity.
We are drawn to people who appear familiar to us because familiarity provides predictability and safety." Imprinting is one such theory that is linked with familiarity.
Thus, Advertisers use the familiarity effect because companies hope that repeated exposure to their product will make people feel familiar with it and more likely to buy it.
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the screenshts below
Answer:
yes so for example one
Explanation:
yeah so
Temperature depends on the average kinetic energy of the particles in a sample. How does this help explain why a plasma-based light does not have a high temperature? No particles in the plasma have high kinetic energy. The fastest particles have the greatest mass. Most particles in the plasma are heavy, slow, and very low density. The fastest particles transfer most of their energy through collisions.
Answer:
C: Most particles in the plasma are heavy, slow, and very low density.
Explanation:
i'm smart like dat
Answer:
C is correct
Explanation:
issued this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your etext. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon.
The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.
Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.
Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.
According to the given data;
Decomposition of carbon monoxide (CO);
Oxygen produced = 3.36 g
Carbon produced = 2.52 g
We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;
Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol
Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol
Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;
0.21 mol C / (0.21 mol O) = x
Simplifying the equation, we have;
x = 1
Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.
Decomposition of carbon dioxide (CO₂);
Oxygen produced = 9.92 g
Carbon produced = 3.72 g
Following the same calculations as before;
Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol
Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol
Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;
0.31 mol C / (0.62 mol O) = y
Simplifying the equation, we have;
y = 0.5
Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.
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--The given question is incomplete, the complete question is
"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--
GIVING BRAINLY
a balloon contains 2.5 L of air at 1.00 atm. it is taken underwater to a new pressure of 4.00 atm. what id the new volume? round to 2 decimal places
What is the pressure in atm of a 0.108mol sample of He gas at a temperature of 20.0ºC if its volume is 0.505L?
He gas therefore has a pressure of **3.47 atm** at a volume of 0.505L and a temperature of 20.0°C.
DEFINE GAS PRESSURE?The force created when gas particles strike the container wall is known as a gas's pressure. It is a gauge for a gas's moving molecules' typical linear momentum. The pressure exerted on the wall is normal to it and acts perpendicularly; the viscosity of the gas influences the force's tangential (shear) component.
Equation PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the universal gas constant, and T is temperature, expresses the ideal gas law. The pressure of He gas can be calculated by using this equation and the given values as replacements as follows:
P = nRT/V
in which n = 0.108 mol
The universal gas constant is R, which equals 0.08206 L atm mol K-1.
T (temperature in Kelvin) = 20.0 + 273.15 K
V = 0.505 L
By replacing these values in the previous equation, we obtain:
P is calculated as follows:
(0.108 mol) x (0.08206 L atm mol-1 K⁻¹) x (20.0 + 273.15 K) / (0.505 L).
P = 3.47 atm
He gas therefore has a pressure of **3.47 atm**1 at a volume of 0.505L and a temperature of 20.0°C.
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The amount of solid NaOH was doubled. Explain how the results of ∆T and ∆Hsoln would differ from the original experiment. Original Question: An aqueous solution is made using 5.25 g of solid NaOH in 75.0 g of water initially at 22.39 °C in a sealed calorimeter. Specific heat=4.184 J/g and ∆T=17
Calculate the wavelength of the electromagnetic radiation whose frequency is 6. 94 x 10^12 Hz
The wavelength of the electromagnetic radiation whose frequency is
6.94 x 10¹² Hz is 4.32 x 10⁻⁵ meters.
The electromagnetic spectrum is a set of frequencies, wavelengths, and photon energies ranging from less than one hertz to more than ten thousand hertz, with wavelengths ranging from a few kilometres to a fraction of the size of an atomic nucleus. In general, electromagnetic waves tend to move at speeds similar to light in a vacuum. They do so, however, at a wide variety of wavelengths, frequencies, and photon intensities.
The electromagnetic spectrum is a range of all electromagnetic radiation that is further divided into multiple subranges known as parts. They are further subdivided into infrared radiation, visible light, and ultraviolet radiation.
Speed of light = c = 3x10⁸ m/s
Frequency = ν = 6. 94 x 10¹² Hz
so in electromagnetic wave,
c = λν
λ = c/ν
= 3 x 10⁸ / 6.94 x 10¹²
λ = 4.32 x 10⁻⁵ meters.
Therefore, wavelength is 4.32 x 10⁻⁵ meters.
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Which of the following statements about the neuromuscular junction acetylcholine (Ach) receptor is false?
a. The probability an ACh channel will open depends on ACh concentration.
b. The synaptic current is the sum of the net ionic currents through all activated ACh receptors.
c. The opening of the ACh receptor is all-or-none.
d. The probability that an ACh channel will open depends on membrane voltage.
e. The current through a single receptor can be measured with a patch clamp technique.
The false statement about the neuromuscular junction acetylcholine (ACh) receptor is c. The opening of the ACh receptor is all-or-none.
The degree to which the ACh receptor opens is dependent on both the amount of neuromuscular junction acetylcholine (ACh) present and the level of receptor activation; it is not an all-or-nothing response. The channel opens when ACh binds to the receptor, causing a conformational shift that permits ion flow.
The following claims are accurate:
ACh concentration affects whether an ACh channel will open, with a larger ACh concentration increasing the likelihood that the channel will open and ion flow.
The net ionic currents through all activated ACh receptors add up to make up the synaptic current, which is defined as the sum of all such currents.
Membrane voltage impacts the likelihood that an ACh channel will open: Membrane voltage has an impact on the likelihood that an ACh channel will open. In general, hyperpolarization lowers and depolarization enhances the likelihood of a channel opening.
The patch clamp method allows for the measurement of the current flowing through a single receptor, including ACh receptors. This method sheds light on the characteristics and functions of individual ion channels, including ACh receptors.
As a result, c is the erroneous assertion. All or none of the ACh receptor's opening occurs.
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Consider the reaction of C6H6 + Br2 -------> C6H5Br + HBr What is the theoretical yield of C6H5Br if 42.1 g of C6H6 react with 67.5 g of Br2? Answer to 3 sig figs. (1 decimal place)
The theoretical yield of C6H5Br is 66.3 g (to 3 sig figs) when 42.1 g of C6H6 reacts with 67.5 g of Br2 after using the stoichiometry of the balanced equation.
To determine the theoretical yield of C6H5Br, we need to calculate the limiting reactant and use the stoichiometry of the balanced equation.
First, we need to find the moles of each reactant using their respective molar masses:
Molar mass of C6H6 (benzene) = 78.11 g/mol
Molar mass of Br2 = 159.81 g/mol
Moles of C6H6 = 42.1 g / 78.11 g/mol = 0.538 mol (to 3 sig figs)
Moles of Br2 = 67.5 g / 159.81 g/mol = 0.422 mol (to 3 sig figs)
Now we can compare the mole ratios between C6H6 and Br2 in the balanced equation:
C6H6 + Br2 → C6H5Br + HBr
From the equation, we see that the stoichiometric ratio is 1:1 between C6H6 and C6H5Br. Therefore, the limiting reactant is the one with fewer moles, which is Br2 in this case.
Now we can calculate the theoretical yield of C6H5Br using the mole ratio and the molar mass of C6H5Br:
Molar mass of C6H5Br = 157.02 g/mol
Theoretical yield of C6H5Br = moles of limiting reactant (Br2) × molar mass of C6H5Br
= 0.422 mol × 157.02 g/mol
= 66.3 g (to 3 sig figs)
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What is Potential energy
Answer:
energy that's waiting to happen
Explanation:
as an example if you throw a ball up in the air potential energy is going to happen when it comes down that's going to be energy basically I don't know if you get it but it's called potential energy
Answer:
Potential energy is the energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors.
Explanation:
PLEASE I REALLY NEED ANSWER REAL QUICK
1. 800g of solution of NaCl has 5% of the percent by mass. Find mass of water is required?
a. 780g
b. 760g
c. 740g
d. 720g
e. Other.. and give solution.
Answer:
b. 760 g
Explanation:
The mass of the solution = 800 g
5% of NaCl by mass of the solution can be determined as follows;
5% of 800 = \(\frac{5}{100}\) × 800
= 5 × 8
= 40 g
The mass of NaCl in the solution is 40 g.
The mass of water = mass of solution - mass of NaCl
= 800 - 40
= 760 g
Therefore, the mass of water required is 760 g.
acid + water gives............
Answer:
H3O+
(aq) (the hydronium ion)
whereas weak acids dissociate only partially in water.
Explanation:
hope this helps
Answer:
Acid Rain / Acid WaterExplanation:
__________________________________________________________
According to US Water Systems,
Water that has a pH of less than 6.5 could be acidic and corrosive. Acid water has the potential to leach metal ions, including iron, manganese, copper, lead, and zinc, from aquifers, plumbing fixtures, and piping. Because of its corrosive nature, this water could contain elevated levels of toxic metals, damage metal pipes.
__________________________________________________________
Hope this helps! <3
__________________________________________________________
What was the concentration of my stock solution if I used 23mL of it to make 102 ml of 1.4 M dilution?
Answer:
formula:c1v1=c2v2
Explanation:
v1=102ml,c1=1.4mol/l
v2=?;c2=2.4mol/l
v2=v1×c1÷c2=102ml×1.4mol/l÷2.4mol/l
=59.5ml
i hope this will help you
All matter has both physical and chemical properties.
True or False
Answer:
F
Explanation:
a.
Which of the following might be affected by the loss of a plant species?
Only organisms that feed directly off the lost plant species we be affected.
b. Other plant species will be affected, but no other organisms will
c. Multiple organisms may be affected by the loss of a plant species.
d. No other organisms would be affected.
SREE
Please select the best answer from the choices provided
o >
Answer:
Multiple organisms may be affected by the loss of a plant species.
Explanation:
Organisms that feed directly off the lost plant will be affected, and because of that, organisms that feed off those organisms will be affected. This could also affect other organisms like parasites. Other plant species may be affected from the loss of a competitive species. This could affect organisms that feed off that plant, and the organisms that feed off those organisms.
Answer:
c
Explanation:
if you have 1.25 kg of a molecule with molecular (atomic) weight of 134.1 g/mol, how many moles of that molecule do you have?
We have a total of 9.27 moles of the molecule that weights 134.1 g/mol.
The molecular mass of the molecule is 134.7 g/mol.
The amount of the molecule that we have is 1.25kg.
We know,
1 kilogram = 1000 grams.
1.25 kilograms = 1250 grams.
The mass of the amount of molecule we have is 1250 grams.
The moles of a molecule are given by,
Moles = Mass that we have/molecular mass
Putting the values accordingly,
Moles = 1250/134.7
Moles = 9.27 moles.
So, we have 9.27 moles of that molecule whose molecular mass is 134.1 g/mol.
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3. A polyatomic ion is formed from more than one atom.
True or false
Answer:
true
Explanation:
why do we need to separate components of air
We need to separate components of air primarily for industrial, medical, and scientific purposes, as different industries and applications require specific components of air in concentrated or purified forms.
Air is composed of various components, including nitrogen (78%), oxygen (21%), argon (0.93%), carbon dioxide (0.04%), and trace amounts of other gases, as well as water vapor. Separating these components is essential for several reasons:
1. Industrial applications: Various industries require specific gases in their processes. For example, nitrogen is used in food packaging to preserve freshness, while oxygen is used in medical settings and combustion processes.
2. Medical purposes: Pure oxygen is needed in hospitals for patients who require supplemental oxygen due to respiratory issues or during surgery.
3. Scientific research: Separating components of air allows scientists to study individual gases and their properties, which can lead to advancements in our understanding of the atmosphere and the development of new technologies.
In summary, separating components of air is crucial for meeting the unique needs of different industries, medical purposes, and scientific research.
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