What adjustments to an electromagnet that causes the electromagnet to lose a strength

13 N/kg The surface gravitational field is given by acceleration due to gravity on the planet (g). Let the value of it on a newly discovered planet be g'.

The gravitational force acting on a mass of one kilogram is measured in newtons. G is assumed to be 9.806 N kg-1 at the surface of the Earth. Additionally, the acceleration of an item falling freely in the gravitational field of the Earth is denoted by the letter "g".

Through the development of his theory of relativity, Albert Einstein demonstrated that gravity is a curvature in the space-time continuum rather than merely a force. Simply explained, an object's mass causes the space around it to essentially bend and curve. That may sound like it belongs in science fiction, but it's true.

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Answer:

165 kPa

Explanation:

Absolute pressure is:

P = Patm + ρgh

where Patm is the atmospheric pressure,

ρ is the density,

g is acceleration due to gravity,

and h is the depth.

P = 101,300 Pa + (1000 kg/m³) (9.8 m/s²) (6.50 m)

P = 165,000 Pa

P = 165 kPa

Answer:

Wind

Explanation:

I had this question on one of my tests, and I got it right

Answer:

(0.5x Time)²)

Explanation:

jump height = 4.9 x (0.5 x Time)2).

Answer:

Here's a list of a few reasons behind cracked or chipped walls:

Moisture-laden walls

Weather conditions

Incompatibility with the surface

Inferior-quality paints

Let’s discuss each of them one by one.

Explanation:

Lots of moisture

In a house, bathroom and kitchen are the two places where there is a lot of moisture and dampness. Therefore, you will see that these places are the first to report the problem of flaky paint. When moisture is absorbed, it passes through various coats of paint, removing the adhesive that sticks the paint to the wall. Therefore, you can spot paint coming off in the form of flakes or like a banana peel. This shows the extra moisture in the walls need to be addressed immediately.

Too much sunlight

Paint often chips off walls due to high temperatures. If direct sunlight hits the walls all day, it can cause the paint to dry out faster. The oil paints start to crack, while latex paints lose their quality to stick to the walls.

Incompatible paints

When painting, it is extremely important to use the same kind of paint on the surface that’s being coated. For instance, if it is latex paint, it isn’t compatible with oil-based paints and shouldn’t be painted on top of each other. If you are planning to use the leftover oil-paint as a second coat over the base coat of latex paint, then be prepared to see the paint coming off sooner than expected.

Also, make sure the surface on which you are about to paint is compatible with the paint you are using. For instance, smooth surfaces require a certain kind of paint and layering that keeps the coating intact. For uneven surfaces, it’s better to go for textured paint. It is important to prime and prep the surface first before applying a coat of paint to make sure the paint doesn’t come off easily.

Low-quality paints

Some paints seem good, especially to your wallet, but once you use them, you will face bad consequences. Inferior-quality paints do not adhere to the walls properly and also do not give a nice finish once the paint job is done. To avoid cracks in the walls, do not use low-quality or expired paints.

Answer:

Explanation:is the law means that the police are the law

A ball is dropped and bounces. At each rebound, the ball reaches half the height of the previous rebound. The ball must be dropped from 32H in order to reach exactly the height H after the sixth rebound.

It needs to determine how high the ball must be dropped so that it reaches exactly the height H after the sixth rebound. When the ball is dropped, let its height be H1. After the first rebound, its height will be (1/2)H1. After the second rebound, its height will be (1/2)((1/2)H1) = (1/2)² H1 = (1/4)H1. In general, after the nth rebound, its height will be (1/2)^(n-1)H1.

When the ball reaches exactly the height H after the sixth rebound, we have (1/2)^5 H1 = H. Hence, H1 = 2^5 H = 32H. Therefore, The ball must be dropped from 32H in order to reach exactly the height H after the sixth rebound.

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Answer: 1 m/s/s

Explanation: One Newton is defined as the amount of force required to give a 1-kg mass an acceleration of 1 m/s/s.

Answer: 3 Mg , 2 P , 14 O , 12H

Number of atoms of sama elements remains same

In both sides

Answer:

3 Mg, 2 P, 14 O, 12 H

Explanation:

Answer:

Igneous

Explanation:

Answer:

True

Explanation:

Electrons can be transferred between materials as in chemical reactions solid substances lose electrons while other elements gain electrons to balance the electrons in reaction.It occurs by conduction,polarization and friction.

Explanation:

4.

Given: Δd = 4 + 2 + 1 = 7km, Δt = 32 + 22 + 16 = 70mins

Required: V

Equation: V = Δd/Δt

Solution: V = 7/70

                  = 0.1km/min

Detection methods to measure the gravitational tug of a planet on its star that is allowing us to estimate planetary mass is : (c) the astrometric and doppler methods.

Method for finding extrasolar planets and brown dwarfs from radial-velocity measurements through observation of doppler shifts in the spectrum of the planet's parent star is called doppler spectroscopy.

It is also known as the radial-velocity method or the wobble method.

Method that detects the motion of a star by making precise measurements of its position on the sky is called astrometry. This technique can be used to identify the planets around a star by measuring small changes in the position of the stars.

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Answer:

A. The range of A and B are equal.

Explanation:

Let u be the initial speed of both the projectile.

The gravitational force acting in the projectile is in the downward direction, sp the speed of the projectile in the horizontal direction remains constant and equals to the initial horizontal speed.

For projectile, a projectile having initial velocity u at an angle \theta with the horizontal direction,

The speed in the horizontal direction \(= u\cos\theta\)

and the speed in the vertical direction is \(= u\sin\theta\) upward.

For A:

The speed in the horizontal direction \(= u\cos75^{\circ}\)

and the speed in the vertical direction is \(= u\sin75^{\circ}\) upward.

For B:

The speed in the horizontal direction \(= u\cos15^{\circ}\)

and the speed in the vertical direction is \(= u\sin15^{\circ}\) upward.

Let \(t_A\) and \(t_B\) are the time of flight for projectile A and B respectively.

As the range is the horizontal distance traveled by the projectile, so

The range for the projectile A \(= u\cos75^{\circ}\times t_A\cdots(i)\)

The range for the projectile B = \(u\cos15^{\circ}\times t_B\cdots(ii)\)

At the highest point, the vertical velocity is 0.

Bu using the equation of motion \(v^2=u^2 +2a s.\)

Here, the final velocity v=0, the initial velocity \(u = u \sin \theta\) , h= vertical distance up to the highest point, and \(a= -g\) (as per sign convention).

So, \(s= \frac{u^2\sin^2 \theta}{2g}\)

For projectile A: The maximum height attained.

\(s_A= \frac{u^2\sin^2 75^{\circ}}{2g}\)

For projectile B: The maximum height attained.

\(s_B= \frac{u^2\sin^2 15^{\circ}}{2g}\)

As \(\sin^2 75^{\circ} > \sin^2 15^{\circ}\), the height of A is attained by A is more than the heigHt attained by B.

Now, the times required to reach the highest point from the ground and again form the highest point to the ground are the same.

So, the total time of flight = 2 x (Time to reach the highest point)

In a similar way, by using the equation of motion v=u+at,

The time to reach the highest point \(=\frac {u\sin\theta}{g}\)

where g is the acceleration due to gravity.

So, the total time of flight

\(= 2 \times \frac {u\sin\theta}{g}\)

The total time of flight for A

\(=2 \times \frac {u\sin75^{\circ}}{g}\)

The total time of flight for A

\(=2 \times \frac {u\sin15^{\circ}}{g}\)

Now, from equations (i) and (ii),

The range for the projectile A =

\(u\cos75^{\circ}\times \frac {2u\sin75^{\circ}}{g}=\frac {u^2 \sin 150^{\circ}}{g}= \frac {u^2 \sin 30^{\circ}}{g}\)

The range for the projectile B =

\(u\cos15^{\circ}\times \frac {2u\sin15^{\circ}}{g}=\frac {u^2 \sin 30^{\circ}}{g}.\)

Both the projectile have the same range.

Hence, option (A) is correct.

The distance between screen and the lens is 14.4 cm and the height of the image is 3.6 cm, under the condition that the height of the image is 3 cm.

Given that the display is located 12.6 cm from the 12.0-cm focal length lens of the projector, the distance between the screen and the lens can be evaluated applying

1/f = 1/v + 1/u

Here

f =  considered focal length of the lens,

u =  considered object distance  between the lens and the display,

v = image distance  between the lens and the image on the screen

Now applying the formula we get  that u = 14.4 cm

Now solving the 2nd part of the question

In order to evaluate the height of the image of a person on the screen who is 3.0 cm tall on the display,

h/H = u/v

Here

h = height of the person on the display,

H = height of their image on the screen,

u =14 cm,

v = we need to find.

Rearranging this equation gives:

v = uh/H

Substituting in our values gives:

v = (3.0 cm x 14.4 cm) / 12.0 cm

= 3.6 cm

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The complete question is

If the display is located 12.6 cm from the 12.0-cm focal length lens of the projector, what is the distance between the screen and the lens?

What is the height of the image of a person on the screen who is 3.0 cm tall on the display?

This simple model is inadequate for the renal vessels or the arterioles in the lungs since it does not include all of the complexities related to the flow of blood in these vessels.

a) Friction in flows is generally described in fluid mechanics as a force that arises in the direction opposite to the fluid motion caused by a viscosity present in fluids. The viscosity determines the resistance of the fluid to shear or flow. In fluid dynamics, the movement of fluid is categorized into two types: laminar flow and turbulent flow.b)Assumptions for the model of gas flow through trachea: The following are the assumptions for the model of gas flow through trachea: The gas is considered as a continuum in the modeling of the gas flow through the trachea. The flow is steady, incompressible, and unidirectional. The flow of gas is considered to be laminar. There is no friction between the air and the walls of the trachea.The flow for r = 0.5 * R is: FR = 2πrlη (dvz/dr) ezThe frictional force FR = 2πrlη (dvz/dr) ez acts on its lateral surface. The compressive force Fp = πr2( p1 − p2) ez acts on its top surface. Vascular resistance is determined by a variety of factors, including the vessel's radius, length, and viscosity of the fluid. This model is crucial in blood because it aids in the comprehension of the dynamics of fluid flow through the blood vessels. This model is insufficient for the renal vessels or the arterioles in the lungs because it does not include all of the complexities associated with the flow of blood in these vessels.c) Vascular resistance is determined by the vessel's radius, length, and viscosity of the fluid. This model is crucial for blood because it aids in the comprehension of the dynamics of fluid flow through the blood vessels.

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Answer:

Mark me as brainliest as i need it ..

I will answer your questions

The further a planet is from the Sun, the colder its surface temperatures tend to be. Venus is an exception, since it has the highest surface temperature in our solar system due to its close closeness to the Sun and its thick atmosphere.

The inner planets are rocky, whereas the outer planets are gaseous, which can be attributed to the early solar system's temperature. The solar system's temperature increased as the gases came together to create a protosun. Temperatures in the inner solar system reached 2000 K, whilst in the outer solar system, it was only 50 K.

The quantity of heat received is just one of many intricate aspects that go into determining the temperature.

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The work done during the process is -36,000 Joules. The change in internal energy of the system is 11,000 Joules.

To calculate the work done during the process, we can use the formula:

Work (W) = -P * ΔV

Where P is the constant pressure and ΔV is the change in volume.

Given:

Pressure, P = 4 bar = 4 * 1\(0^{-5}\) Pa (converted to Pascal)

Initial volume, V1 = 0.06 m²

Final volume, V2 = 0.15 m²

Change in volume, ΔV = V2 - V1

Substituting the values into the equation

ΔV = 0.15 m² - 0.06 m²

ΔV = 0.09 m²

Work (W) = -P * ΔV

W = -(4 * 1\(0^{-5}\) Pa) * (0.09 m²)

W = -36,000 J

Therefore, the work done during the process is -36,000 Joules.

To determine the change in internal energy (ΔU), we can use the first law of thermodynamics:

ΔU = Q - W

Where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done on the system.

Given:

Heat rejected, Q = -25 kJ = -25,000 J (negative sign indicates heat rejection)

ΔU = Q - W

ΔU = (-25,000 J) - (-36,000 J)

ΔU = -25,000 J + 36,000 J

ΔU = 11,000 J

Therefore, the change in internal energy of the system is 11,000 Joules.

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a) The greenhouse effect refers to the process by which certain gases in the Earth's atmosphere trap and re-emit heat from the sun, leading to a warming effect on the planet's surface.

These gases, including carbon dioxide, water vapor, methane, and others, act like a blanket around the Earth, absorbing and trapping the sun's radiation and preventing it from escaping into space.

b) Atmospheric water vapor is a key component of the Earth's climate system, as it plays a crucial role in the greenhouse effect. As water vapor absorbs and re-emits radiation from the sun, it helps to trap heat in the atmosphere and keep the planet warm.

However, the amount of water vapor in the atmosphere is strongly influenced by temperature and other factors, which can in turn affect climate patterns and weather events.

c) The increased concentration of carbon dioxide in the atmosphere changes the climate because it enhances the greenhouse effect. Carbon dioxide is a particularly potent greenhouse gas, as it absorbs and re-emits radiation across a range of wavelengths, effectively trapping more heat in the atmosphere. As humans burn fossil fuels and engage in other activities that release carbon dioxide into the air, the concentration of this gas increases, leading to a buildup of heat-trapping gases and a corresponding increase in global temperatures.

d) The melting of continental glaciers and sea ice in polar regions can accelerate the rise in temperature through a process known as positive feedback. As the ice melts, it exposes more land and water, which in turn absorb more solar radiation and heat up. This leads to further melting, which exposes even more land and water, and so on.

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The statement"Mental and emotional health can be improved through exercise." is a true statement

Option A is correct

Exercise is simply defined as the act of putting patience into practice, action, or practice. Regular physical activity can help you strengthen your muscles and increase your endurance.

In conclusion, Mental and emotional health can be improved through exercise.

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Answer:   True.           Exercise is not only good for physical health but also mental and emotional health. It helps in reducing stress, anxiety, depression, and boosting self-esteem, cognitive function, and overall mood. Regular exercise can lead to the release of endorphins that promote feelings of happiness and well-being. Hence, mental and emotional health can be improved through exercise.

Explanation:

i took the test

Well, you didn't tell us what the unit of the 53.14 is.  But whatever it is, the force of friction is the same 53.14 of them.

The only way the box can move with constant velocity is if the forces acting on it all add up to zero. So the force of friction to the left, holding it back, must be exactly equal to the force pushng it forward to the right.

Notice that none of this depends on the mass of the box, or WHAT the constant velocity IS.  None of that information matters, or makes any difference. It's only included in the question to confuse and distract us.  

When two forces act in opposite directions, the resultant force can be calculated by subtracting the smaller force from the larger force. The formula for calculating the resultant force is: resultant force = force1 - force2.

When two forces act in opposite directions, the resultant force can be calculated using the following formula:

resultant force = force1 - force2

Where force1 is the larger force and force2 is the smaller force acting in the opposite direction.

For example, suppose there are two forces acting on an object: 10 Newtons to the left and 5 Newtons to the right. To find the resultant force, you would subtract the smaller force from the larger force:

resultant force = 10 N - 5 N

resultant force = 5 N to the left

So in this case, the resultant force is 5 Newtons to the left.

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Answer:

If there is a net force acting on an object, the object will have an acceleration and the object's velocity will change. ... Newton's second law states that for a particular force, the acceleration of an object is proportional to the net force and inversely proportional to the mass of the object.

Explanation:

If the motion of an object changes, the net force on the object is greater than zero or the forces acting on the object is unbalanced.

According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object. The object will move in the direction of the applied force.

When the net force on an object is zero, the object will be remain at rest.

However, when the net force on object is greater than zero, the object will move in the direction of the greater force.

Thus, we can conclude that if the motion of an object changes, the net force on the object is greater than zero or the forces acting on the object is unbalanced.

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Answer: Sounds are made when objects vibrate. The vibration makes the air around the object vibrate and the air vibrations enter your ear, You hear them as sounds

Explanation:

Deposition occurs when the agents (wind or water) of erosion lay down sediment. Deposition changes the shape of the land. Erosion, weathering, and deposition are at work everywhere on Earth. Gravity pulls everything toward the center of Earth causing rock and other materials to move downhill

The energy stored in a 2.60-cm-diameter, 14.0-cm-long solenoid that has 150 turns of wire and carries a current of 0.780 a is 0.016 joules.

The energy stored in a solenoid is given by the equation:

U = (1/2) * L * I²

where U is the energy stored, L is the inductance of the solenoid, and I is the current flowing through it.

The inductance of a solenoid can be calculated using the equation:

L = (μ * N² * A) / l

where μ is the permeability of the medium (in vacuum μ = 4π × 10⁻⁷ H/m), N is the number of turns of wire, A is the cross-sectional area of the solenoid, and l is the length of the solenoid.

First, let's calculate the inductance of the solenoid:

μ = 4π × 10⁻⁷ H/m

N = 150

A = πr² = π(0.013 m)² = 0.000530 m²

l = 0.14 m

L = (4π × 10⁻⁷ H/m * 150² * 0.000530 m²) / 0.14 m = 0.051 H

Now, we can calculate the energy stored in the solenoid:

I = 0.780 A

U = (1/2) * L * I^2 = (1/2) * 0.051 H * (0.780 A)² = 0.016 J

Therefore, the energy stored in the solenoid is 0.016 joules.

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