what acts as a bronsted base in water at 298 k and will participate in hydrolysis?
CHOOSE ALL CORRECT ANSWERS; there may be more than one correct answer. 1. Br- 2. ClO4- 3. CN- 4. CIO3- 5. Cl- 6. NH3 7. NO3- 8. ОН- 9. F-
10. CIO-
11. I-

Answer:

i think its convection

Explanation:

The proper way to balancing the given equation is 3Ca(OH)₂+2H₃PO₄→Ca₃(PO₄)₂ +6H₂O

Balanced equations are those reactions in which each atom of reactants and products are present in same quantity on both sides of the equation.

Given chemical reaction is:
Ca(OH)₂ + H₃PO₄ → Ca₃(PO₄)₂ + H₂O

Let we discuss each given reaction to get the perfectly balanced equation:

In the above reaction number of hydrogens, calcium as well as of oxygens are not equal so that it is an unbalanced equation.

In the above equation all atoms are present in equal amount on both sides of the reaction, so that it is a balanced equation.

In the above reaction number of oxygen and hydrogen atoms are not equal so that the given equation is an unbalanced one.

In the above freaction all atoms are unequal so that given equation is an unbalanced equation.

Hence balanced equation is 3Ca(OH)₂ + 2H₃PO₄ → Ca₃(PO₄)₂ + 6H₂O.

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If a racemic mixture of two enantiomers is given, the specific rotation will be zero.

A racemic mixture contains equal amounts of both enantiomers, which have opposite signs of rotation. Therefore, the rotations of the individual enantiomers cancel each other out, resulting in a net rotation of zero.Specific rotation is a measure of the degree of rotation of the plane of polarized light by a chiral substance.

Chiral compounds rotate plane-polarized light in either a clockwise or counterclockwise direction, depending on the orientation of their asymmetric carbon atoms.

Since a racemic mixture contains equal amounts of both enantiomers, it will not rotate the plane of polarized light because the rotations of the individual enantiomers will cancel each other out.

This is because the polarized light will experience the same amount of rotation in the clockwise and counterclockwise directions, leading to a net rotation of zero. Hence, the specific rotation of a racemic mixture is zero.

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The type of immunity that is primarily responsible for combating pathogens found in the extracellular spaces is humoral immunity. Option D is correct.

This is a type of adaptive immunity that involves the production of antibodies by B cells in response to specific pathogens. These antibodies then circulate in the blood and lymphatic system, binding to and neutralizing the pathogens before they can cause harm. In contrast, cellular immunity, which involves the activity of T cells, is more important for combating intracellular pathogens such as viruses and bacteria that have invaded cells. Innate immunity provides a first line of defense against all types of pathogens, but is not specific to particular pathogens. Secondary immunity refers to the immune response that occurs upon subsequent exposure to a pathogen, and can involve both humoral and cellular immunity.

Immunity is the body's capacity to fend off infection; it can be either inherent or learned. Immunity is mostly acquired by cell-mediated, antibody- or humoral-mediated mechanisms.

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The addition of ice at the end of the heating process is important because it increases the solubility of the aspirin product.

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The results for potassium were elevated because the lack of anticoagulant caused hemolysis, which led to the release of potassium from red blood cells.

When a blood specimen is drawn without an anticoagulant, it can cause hemolysis, which is the rupture of red blood cells and the release of their contents into the serum or plasma. Hemolysis can occur due to trauma during the venipuncture or by using a needle that is too small or too large.

One of the main constituents released from red blood cells during hemolysis is potassium, which can lead to falsely elevated potassium levels in the blood. This occurs because potassium is normally present in high concentrations inside the red blood cells, and hemolysis releases this intracellular potassium into the serum or plasma.

Therefore, in this case, the lack of anticoagulant during the blood draw caused hemolysis, which led to the release of potassium from the red blood cells, resulting in falsely elevated potassium levels of 6.0 mmol/L. To obtain accurate potassium levels, blood specimens should be drawn using appropriate techniques and anticoagulants to prevent hemolysis.

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Answer:

225kg.m.s

Explanation:

Momentum equals to mass times velocity

Answer:

The molecules cannot be compared without knowing the mass.

ans:We have to find theoretical yield and percentage yield of the reaction.

Solution : 14.5 g of SO2 reaches with 21 g of O2. and actual yield is 12g.

first we see chemical reaction is SO2 and O2,

2SO2 + O2 ⇒2SO3

we see, 2 moles of SO2 react with 1 mole of O2.

molecular weight of SO2 = 32 + 2 × 16 = 64 g

molecular weight of O2 = 32g

∴ 2 × 64 = 128g of SO2 reacts with 32g of O2.

∴ 14.5g of SO2 reacts with 32/128 × 14.5 = 3.625 g but given O2 is 21g

so, SO2 is limiting reagent.

hence, reaction prefers SO2 to produce SO3

2 moles of SO2 give 2 moles of SO3

∴ 128g of SO2 gives 2 × (32 + 3 × 16) = 160g of SO3

⇒14.5 g of SO2 gives 160/128 × 14.5 g = 18.125 g

so theoretical yield = 18.125 g

but actual yield = 12g

so, percentage yield = actual yield/theoretical yield × 100

= 12/18.125 × 100

= 66.207 %

This is because side reactions and unwanted byproducts are often favored at higher temperatures.

To avoid the formation of a side product in this experiment, the best approach would be to keep the reaction at a low temperature and avoid overheating the product during distillation. This is because side reactions and unwanted byproducts are often favored at higher temperatures. By maintaining a low temperature, the reaction can be controlled to favor the desired product and minimize the formation of side products.

Drying the aqueous layer, using pure sodium iodide, using pure silver nitrate, and venting the gases out of the separatory funnel are not specifically related to preventing the formation of side products in this context. They may be relevant for other aspects of the experiment, but they would not directly address the formation of side products.

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a) The volume of the reactor V0 using the mass balance equation and then use the rate of reaction equation to calculate the reactor size is 66.67 ft³ b) 10 reactors are required for the process to be arranged in series.

Given information:
Rate of feed =100 cfh
Cso=1.5 lbmol/ft³
Forward reaction rate, k=10
Equilibrium constant, Ke=16
Equilibrium conversion= 80%
CT=CU= ½(1.5-CS)
-rS=k[(Cs)² – 0.25(1.5-Cs)²/ke]a) Reactor size calculation:

Let’s use the mass balance equation for the process taking place in the Continuous Stirred Tank Reactor,

Therefore, F = V_0 (C_s)_o

Where, F is the flow rate

V_0 is the volume of the reactor(C_s)_o is the concentration of the reactant initially

This is a reversible reaction that occurs in a Continuous Stirred Tank Reactor or a CSTR. It follows the reaction equation of 2S ⇆ T+U .

Using equilibrium data, we know that the required conversion is 80%. That is, Xeq=0.8Using the equilibrium data equation, we can relate the concentrations of T, U, and S as follows:

[T][U]/[S]²= Ke=16Where,[T], [U] and [S] are the molar concentration of the respective species.

Now, let's use the rate equation for the forward reaction to relate the concentration of S to the rate of the reaction.-r_S=k[(C_S)²-0.25(1.5-C_S)²/Ke]

Now, applying the steady-state assumption, dC_S/dt=0, and considering the fact that CT=CU=0.5(1.5-CS), we can substitute (C_S) with C_T and simplify the rate equation.-r_S=k[((C_T)²-0.25(1.5-C_T)²/Ke)]

Now we can calculate the rate of reaction from the rate equation.

-r_S=k[((C_T)²-0.25(1.5-C_T)²/Ke)]=k[((0.5(1.5-C_T))²-0.25(1.5-0.5(1.5-C_T))²/Ke)]

We can find the volume of the reactor V0 using the mass balance equation and then use the rate of reaction equation to calculate the reactor size.

Therefore,V0=F/(C_S)_o=100/(1.5)=66.67 ft³

So, the reactor size is 66.67 ft³.b) For a given feed rate and the size of the reactors, we can calculate the number of reactors required for the process to be arranged in series using the following equation: N=V1/V2

where, V1 and V2 are the volumes of the reactor in the series.

So, if we want to design an arrangement of vessels having 1/10 the size, we can calculate the size of each reactor in the series.V2=V1/10=6.667 ft³

Now, we can find the number of reactors using the equation: N=V1/V2=66.67/6.667=10

Thus, 10 reactors are required for the process to be arranged in series.

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Answer:

A. The birthrate is higher than the death rate

Explanation:

Gold is found in various ionic compounds, but one of the most well-known and commercially significant compounds is gold chloride, also known as auric chloride or gold(III) chloride.

The chemical formula for gold chloride is AuCl₃. Gold chloride is an ionic compound composed of gold cations (Au³⁺) and chloride anions (Cl-). It is a yellow-orange solid that is highly soluble in water. Gold chloride can be formed by reacting the gold metal with chlorine gas or by dissolving the gold metal in aqua regia, which is a mixture of concentrated nitric acid and hydrochloric acid.

Gold chloride has several uses and applications. It is commonly used in the field of nanotechnology for the synthesis of gold nanoparticles. These nanoparticles have unique optical, electronic, and catalytic properties, making them valuable in various fields such as medicine, electronics, and materials science.

In addition to gold chloride, gold can also form other ionic compounds with different anions, such as gold bromide (AuBr), gold iodide (AuI), gold sulfide (Au2S), and gold cyanide (AuCN). These compounds have their own unique properties and applications.

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The three molecules you built, with the correct central atoms, have different bond angles.

The bond angles in a molecule are determined by the number of electron groups around the central atom. In a molecule with two electron groups, such as water (H₂O), the bond angle is about 104.5°.

In a molecule with three electron groups, such as ammonia (NH₃), the bond angle is about 107°. In a molecule with four electron groups, such as methane (CH₄), the bond angle is about 109.5°. These bond angles have such a relation because of the number of electron groups present.

In a molecule with two electron groups, the electron groups are more widely spaced and thus form a wider bond angle. As the number of electron groups increases, the electron groups are closer together, forming a bond angle that is closer to the central atom.

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The volume of 2.00 M MgSO₄ is 20.0 mL.

Parameter

If we added water to the first solution, the concentration changed but the mole in that solution didn't change.

Formula between mole, volume, and concentration (molarity)

\(M = \frac{n}{V}\)

n = M×V

n₁=n₂

M₁×V₁ = M₂×V₂

2.000×V₁ = 0.400×100.0

2.000×V₁ = 40.0

\(V_1 = \frac{40.0}{2.000}\)

V₁ = 20.0 mL

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Answer:  Heterogeneous Catalyst

Explanation:  The word heterogeneous means "different phases" or insoluble in science.  

Answer:

Examples of pure substances include tin, sulfur, diamond, water, pure sugar (sucrose), table salt (sodium chloride) and baking soda (sodium bicarbonate). Crystals, in general, are pure substances. Tin, sulfur, and diamond are examples of pure substances that are chemical elements. All elements are pure substances.

Explanation:

PLEASE MARK ME AS BRAINLIEST

The correct statement related to moles and concentration is: The number of particles of solute in a solution is measured in moles.

The correct option is 2.

Moles are used to express the amount of a substance in a given sample. In the context of solutions, concentration refers to the amount of solute present in a certain volume of the solution. The most common unit for expressing concentration is moles per liter (mol/L) or molarity (M).

Concentration can be calculated by dividing the number of moles of solute by the volume of the solution in liters. By measuring the number of moles of solute, we can determine the concentration of a solution and compare it to other solutions or determine if it has reached its saturation point, where no more solute can dissolve.

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Answer:

Multivalent Ionic

Explanation:

The type of bond formed between the atoms of two elements can easily be deduced from the magnitude of electronegativity difference between the two bonding atoms.

A summary of electronegativity differences and corresponding types of bonds are shown below as adapted from chemlibretexts, where Δχ is the difference in electronegativity ;

ionic if Δχ ≥ 2.0

polar if 2.0 > Δχ > 0.5

nonpolar if 0.5 > Δχ

To determine the type of bond between Hg and F. Hg has an electronegativity of 2 while F has an electronegativity of 4. the difference in electronegativity (Δχ) is 4 - 2 = 2

This corresponds to a multivalent ionic bond because mercurous ion is the  

Hg2^2+  ion and this leads to the formation of Hg2X2 (mercury I fluoride).

To determine the amount of water and methane needed, we can set up a system of equations based on the desired composition of the mixture. you should use 36 gallons of water and 54 gallons of methane to obtain a mixture of 90 gallons with a methane concentration of 60%.

Let's assume x represents the number of gallons of water and y represents the number of gallons of methane. We have the following information: The total volume of the mixture is 90 gallons: x + y = 90. The mixture should be 60% methane: (y / (x + y)) * 100 = 60. Simplifying the second equation: y / (x + y) = 0.6. Now we can solve the system of equations: From equation 1, we can express x in terms of y: x = 90 - y. Substituting this into equation 2: y / ((90 - y) + y) = 0.6. Simplifying further: y / 90 = 0.6. Solving for y: y = 0.6 * 90. y = 54. Now we can find x using equation 1: x = 90 - y. x = 90 - 54. x = 36. Therefore, you should use 36 gallons of water and 54 gallons of methane to obtain a mixture of 90 gallons with a methane concentration of 60%.

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Explanation:

Given that,

Mass of metal cube, m = 20 g

Volume of cube, V =5 mL

We need to find the density of the cube. Mass per unit volume equals density.

\(d=\dfrac{m}{V}\\\\d=\dfrac{20\ g}{5\ mL}\\\\d=4\ g/mL\)

So, the density of the cube is 4 g/ml.

We know that the density of Aluminium is 4 g/mL.

So, the cube is not Aluminium cube.

The density of Aluminium is 2.7 g/mL.  The cube is not the Aluminium cube.So, option B and E is correct

Mass of metal cube, m = 20 g

Volume of cube, V =5 mL

The formula for density is as follows:-

\(Density=\frac{Mass}{Volume} \\\\\)......(1)

Substitute 20 g for mass, and 5 ml for volume in the above equation as follows:-

\(Density=\frac{20\ g}{5\ mL} \\\\=4\ g/mL\)

So, the density of the cube is 4 g/ml.

We know that the density of Aluminium is 2.7 g/mL.  So, the cube is not the Aluminium cube. So option B and E are correct.

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Answer:

Measure so that the line you are reading is even with the center of the meniscus. For water and most liquids, this is the bottom of the meniscus. For mercury, take the measurement from the top of the meniscus. In either case, you are measuring based on the center of the meniscus.

Explanation:

The concentration of Ca(OH)2 in the solution is approximately 1.33 x 10^(-6) M.

To find the concentration of Ca(OH)2 in a solution with a pH of 8.57, we need to use the concept of pOH, which is the negative logarithm of the hydroxide ion concentration ([OH-]). The pOH can be calculated by subtracting the pH from 14, which gives us 14 - 8.57 = 5.43.

Since Ca(OH)2 produces two OH- ions for every molecule of Ca(OH)2 that dissolves, the concentration of OH- ions will be twice the concentration of Ca(OH)2. Thus, we have [OH-] = 2x, where x represents the concentration of Ca(OH)2.

Taking the antilogarithm of the pOH, we find that [OH-] = 10^(-pOH) = 10^(-5.43).

Since [OH-] = 2x, we can write 2x = 10^(-5.43) and solve for x.

x = (10^(-5.43))/2 ≈ 1.33 x 10^(-6) M

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Use Relationship between C and V

Answer:

C several elements make up an atom.

We need to add 0.43 moles of NaOH to the buffer. This is equivalent to adding 2.59 L of 6.01 M NaOH to the buffer.

To calculate the amount of 6.01 M NaOH required to raise the pH of the buffer, we first need to determine the current pH of the buffer. Using the Henderson-Hasselbalch equation, we can calculate that the pH of the buffer is 4.76. To raise the pH to 5.75, we need to add enough NaOH to increase the [OH-] concentration by a factor of 10.

This means we need to add 10 times the amount of H+ ions in the buffer solution. From the balanced chemical equation for the ionization of acetic acid, we know that for every mole of acetic acid that ionizes, it produces one H+ ion. Therefore, we need to add 0.43 moles of NaOH to the buffer. This is equivalent to adding 2.59 L of 6.01 M NaOH to the buffer.

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Answer:

D

Explanation:

answer is in photo above

Answer:

Strongest intermolecular force

Hydrogen Bonding (H-Bonding)

Hydrogen bonds are caused by highly electronegative atoms. They only occur between hydrogen and oxygen, fluorine or nitrogen, and are the strongest intermolecular force.

Hydrogen bonds have the largest dissociation energy.

Hydrogen bond is formed when hydrogen is attached to some electronegative elements like O, N and F.

The dissociation energy is the energy required to break a bond and form two atomic or molecular fragments, each with one electron of the shared pair.

Hydrogen bonds are caused by highly electronegative atoms. They only occur between hydrogen and oxygen, fluorine or nitrogen and are the strongest intermolecular force.

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The new boiling point of a 3.20 m Ca(NO3)2 solution in acetic acid is  128.4°C.

To calculate the new boiling point of a solution, we can use the formula:

ΔTb = Kb x m

where ΔTb is the change in boiling point, Kb is the molal boiling point elevation constant, and m is the molality of the solute.

First, we need to calculate the molality of the Ca(NO3)2 solution. We know that the solution is 3.20 m, which means that there are 3.20 moles of Ca(NO3)2 dissolved in 1 kg of acetic acid solvent.

Molar mass of Ca(NO3)2 = 164.1 g/mol

3.20 moles of Ca(NO3)2 = 3.20 x 164.1 g = 531.12 g

Mass of acetic acid solvent = 1000 g (since we have 1 kg of solvent)

Molality of the solution = moles of solute / mass of solvent in kg

Molality = 3.20 / 1 = 3.20 m

Now we can use the formula to calculate the change in boiling point:

ΔTb = Kb x m

ΔTb = 3.08°C/m x 3.20 m

ΔTb = 9.856°C

The change in boiling point is 9.856°C. To find the new boiling point, we add this to the original boiling point of acetic acid:

New boiling point = 118.5°C + 9.856°C

New boiling point = 128.356°C

Therefore, the new boiling point of a 3.20 m Ca(NO3)2 solution in acetic acid is approximately 128.4°C using ΔTb = Kb x m.

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