What acceleration is produced by a force of 250 N acting on a mas
25 kg?

The work needed to change the speed of a 2.7 kg object from 16 m/s to 12 m/s is 151.2 joules.

To change the speed of an object, work must be done on the object. The amount of work required to change the speed of an object is given by the work-energy theorem, which states that the work done on an object is equal to the change in its kinetic energy.

The kinetic energy of an object is given by the equation:

KE = (1/2)mv^2

where KE is the kinetic energy, m is the mass of the object, and v is its velocity.

To change the speed of a 2.7 kg object from 16 m/s to 12 m/s, the change in its kinetic energy is:

ΔKE = (1/2) * 2.7 kg * (12 m/s)^2 - (1/2) * 2.7 kg * (16 m/s)^2

ΔKE = (1/2) * 2.7 kg * (-112) m^2/s^2

ΔKE = -151.2 J

The negative sign indicates that work must be done on the object to decrease its speed.

Therefore, the amount of work required to change the speed of the 2.7 kg object from 16 m/s to 12 m/s is 576.0 joules.

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The maximum height above the ground the ball will reach before falling back down is 20 meters. therefore, the correct option is B.

To find the time it takes for the ball to reach its maximum height, we can use the equation s = ut + 1/2at^2, where s is the distance traveled, u is the initial velocity, a is the acceleration, and t is the time.
Given:
Initial upwards velocity (u) = 20 m/s
Gravity acceleration (a) = -10 m/s^2 (negative because it acts in the opposite direction)
Distance traveled (s) = ?
To find the time it takes for the ball to reach its maximum height, we can use the equation v = u + at, where v is the final velocity.
v = 0 (at the maximum height, the velocity is 0)
0 = u + at
0 = 20 + (-10)t
-20 = -10t
t = 2 seconds
So, the ball will reach its maximum height after 2 seconds.
To find the maximum height (s), we can substitute the time (t) into the distance equation:
s = ut + 1/2at^2
s = 20(2) + 1/2(-10)(2)^2
s = 40 - 20
s = 20 meters
Therefore, the maximum height above the ground the ball will reach before falling back down is 20 meters.
The correct option is b.) The ball will reach its maximum height after 2 seconds, which will be 20 meters above the ground.

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Answer:

violet has the highest frequency

Explanation:

Answer:

Wavelength is the distance fromone crest to another or from one troughtto another of a wave is called wavelength.

 The charge Q is uniformly distributed throughout the sphere. The correct answer is (B)

When a solid conducting sphere is given a positive charge Q, the charge will distribute itself evenly throughout the surface of the sphere due to the repulsion of like charges. This is known as the "Faraday's ice pail experiment".

According to the principle of electrostatics, the charge on a conductor always resides on its surface and distributes itself in a way that the electric field inside the conductor is zero. Since the charge on a conductor always resides on its surface, it follows that the charge Q in this case must be uniformly distributed throughout the surface of the sphere.

Option (A) is not true because the charge is not concentrated at the center of the sphere. If the charge was concentrated at the center of the sphere, the electric field would not be zero inside the conductor, which contradicts the principle of electrostatics.

Option (C) and (D) are not true because the density of the charge does not change radially outward from the center. If the density decreased or increased radially outward, the electric field inside the conductor would not be zero, which again contradicts the principle of electrostatics.

Option (E) is not true because the charge is distributed throughout the entire volume of the sphere, not just on its surface. A solid conductor has free charges that can move throughout its entire volume, so the charge will distribute itself throughout the entire volume of the sphere until the electric field inside the conductor is zero.

Therefore, the correct answer is (B) it is uniformly distributed throughout the sphere.

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The initial speed of the second stone is 38.95 m/s The height of the bridge, h = 43.9 m. Let the initial velocity of the second stone be u2.

The time taken by the first stone to hit the water from the bridge is given by:t1 = √(2h/g) Where g is the acceleration due to gravity.

Therefore, the time taken by the first stone to hit the water is:t1 = √(2h/g) = √(2×43.9/9.8) = 2.01 s.

Time taken by the second stone to hit the water is given by:t2 = t1 - 1 = 2.01 - 1 = 1.01 s.

Using the kinematic equation, we have:h = u2t + (1/2)gt² where h is the height of the bridge, t is the time taken by the second stone to hit the water, and g is the acceleration due to gravity.

Solving for u2, we get:u2 = (h - (1/2)gt²)/t= (43.9 - (1/2)×9.8×(1.01)²)/1.01= 43.9 - 4.95= 38.95 m/s.

Therefore, the initial speed of the second stone is 38.95 m/s.

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The river archetype is a not unusual and powerful symbol in literature that represents the glide of time and the adventure of life. In both the texts, the river serves as a symbolic place that is deeply linked to the events defined within the choices.

The river archetype is a powerful symbol in many cultures and mythologies, representing the flow of life and the journey of the human soul. The river is often seen as a source of vitality and renewal, as well as a path toward transformation and self-discovery.

In literature and mythology, the river often serves as a metaphor for the passage of time and the inevitability of change. The river can be calm and gentle, or wild and dangerous, reflecting the ups and downs of life and the challenges we face on our journey. The river archetype can also represent the collective unconscious, the deep wellspring of human experience and wisdom that connects us all.

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In Rutherford's famous set of experiments, the fact that some alpha particles were deflected at large angles indicated that the atom contains a dense, positively charged nucleus.

Rutherford conducted experiments where he bombarded a thin gold foil with alpha particles. According to the prevailing model at the time, the Thomson model, it was believed that the positive charge in an atom was spread uniformly throughout the atom, much like plum pudding.

However, Rutherford's observations revealed that some alpha particles experienced significant deflections and even bounced back at large angles. This unexpected result could not be explained by the Thomson model.

Rutherford proposed a new atomic model known as the nuclear model, suggesting that the atom consists of a tiny, dense, positively charged nucleus at the center and the majority of the atom is empty space. This explained the deflection of alpha particles, as they were repelled or deflected by the positive charge concentrated in the nucleus.

The deflection of alpha particles at large angles indicated the presence of a compact and positively charged nucleus within the atom, leading to a fundamental revision of the understanding of atomic structure.

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Based on the given information, the most appropriate classification for the state of the volcano would be "Active-Dormant."

The volcano's history of generating multiple lava flows over the past 10,000 years indicates that it has been active in the relatively recent past. The presence of lava flows that have spread over large areas suggests ongoing volcanic activity, although not necessarily in the immediate present.

Additionally, the mention of very little tephra (volcanic ash and fragments) indicates that the volcano is not currently experiencing explosive eruptions. Instead, it has been primarily characterized by effusive eruptions that produce lava flows.

The fact that people in the nearby town remember the last eruption, which caused some forest fires, further supports the classification of the volcano as active-dormant. While the volcano may not be actively erupting at the moment, the memory of the recent eruption and the potential for future volcanic activity suggests that it is still in a state of activity, albeit in a relatively dormant phase.

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Answer:Adolescent chastity can be defined as the absolute abstinence from sex and anything related to sex, such as, kissing, touching, fondling

Explanation:

To determine the convergence or divergence of the given series:

∞

Σ (6 · 13 · 20 · · (7n − 1))/(7 · 15 · 23 · · (8n − 1))

n = 1, We can apply the ratio test, which helps determine the convergence or divergence of a series by considering the ratio of consecutive terms. Let's denote the nth term of the series as aₙ:

aₙ = (6 · 13 · 20 · · (7n − 1))/(7 · 15 · 23 · · (8n − 1))

aₙ₊₁ / aₙ = [(6 · 13 · 20 · · (7(n+1) − 1))/(7 · 15 · 23 · · (8(n+1) − 1))] / [(6 · 13 · 20 · · (7n − 1))/(7 · 15 · 23 · · (8n − 1))]

= [(7(n+1) − 1)/(8(n+1) − 1)] / [(7n − 1)/(8n − 1)]

aₙ₊₁ / aₙ = [(7n + 6)/(8n + 7)] / [(7n − 1)/(8n − 1)]

= [(7n + 6)(8n − 1)] / [(7n − 1)(8n + 7)]

= (56n² + 34n - 6) / (56n² + 55n - 7)

Now, let's take the limit as n approaches infinity:

lim (n→∞) (56n² + 34n - 6) / (56n² + 55n - 7)

By evaluating this limit, we can determine whether the series converges or diverges. If the limit is less than 1, the series converges. If the limit is greater than 1 or infinite, the series diverges.

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y-components of the force on the particle at y=0 m, 1 m, and 2 m are 0 N, -12 N, and -48 N, respectively.

Energy held by an object because of its position relative to other objects is known as potential energy.

Force on a particle is related to potential energy through the gradient: F = - ∇U

∇ is gradient operator and U is potential energy. For a particle moving along the y-axis, the force can be expressed as: F = - dU/dy * j

j is unit vector in the y-direction.

Potential energy U = 4y³, so the force on particle can be calculated as:

F = - dU/dy * j = - 12y² * j

At y=0 m, the force is zero, since the derivative of U with respect to y is zero at this point.

At y=1 m,  force is: F = - 12(1)² * j = -12j

At y=2 m, force is: F = - 12(2)² * j = -48j

Therefore, the y-components of the force on the particle at y=0 m, 1 m, and 2 m are 0 N, -12 N, and -48 N, respectively.

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: A particle moving along the y-axis has the potential energy u =4y3j, where y is in m. what is the y-component of the force on the particle at y=0 m, 1 m, and 2 m?

a) True, the ratio of potential energies Us1 / Us2 only depends on the ratio of the distances that the spring is compressed, which is l1 / l2. It does not depend on k.

b) This means that if we compress the spring by half as much, the potential energy will be four times as small.

(a) True. The potential energy stored in a spring that is compressed by a distance l is given by Us = 1/2 k l^2, where k is the spring constant. This formula tells us that the potential energy is proportional to the square of the distance that the spring is compressed. Therefore, if we compress the spring by twice as much, the potential energy will be four times as much, regardless of the spring constant. So, the ratio of potential energies Us1 / Us2 only depends on the ratio of the distances that the spring is compressed, which is l1 / l2. It does not depend on k.

(b) To find the ratio of potential energies Us1 / Us2, we can simply plug in the given values into the formula for potential energy:

Us1 = 1/2 * 10 N/m * (0.070 m)^2 = 0.0245 J

Us2 = 1/2 * 10 N/m * (0.14 m)^2 = 0.098 J

So, Us1 / Us2 = 0.0245 J / 0.098 J = 0.25 (numerical answer to two significant figures). This means that if we compress the spring by half as much, the potential energy will be four times as small.

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Answer:

false

Explanation:

A) The elastic potential energy stored in the spring is 25 J. B) The speed of the mass as it passes through the equilibrium point is 2.58 m/s.

A) To find the elastic potential energy stored in the spring, use the formula:
Elastic potential energy (PE) = (1/2)kx^2
Where k is the spring constant (500 N/m) and x is the displacement from the equilibrium length (0.1 m).
PE = (1/2)(500)(0.1)^2
PE = 25 J
B) The elastic potential energy will be converted to kinetic energy when the spring is released. Use the formula:
Kinetic energy (KE) = (1/2)mv^2
Where m is the mass (0.75 kg) and v is the velocity.
Since PE = KE, we can find the velocity:
25 J = (1/2)(0.75 kg)v^2
Solve for v:
v = 2.58 m/s

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When a person focuses on an object at a very far distance from the eye, the focal length of the eye at that time is approximately infinity.

The human eye is a complex optical system that can adjust its focus to objects at different distances. The lens of the eye changes its shape to allow for accommodation, enabling the eye to focus on objects at varying distances. However, when a person looks at an object located at an extremely far distance, such as a distant mountain or star, the light rays entering the eye can be considered nearly parallel.

In this scenario, the lens of the eye becomes relatively flat and reaches its least curved state. As a result, the focal length of the eye approximates infinity. Essentially, the eye's focusing mechanism is optimized for parallel light rays, allowing the incoming light to converge at a point that is virtually at an infinite distance from the eye. This enables clear vision and sharp focus on objects situated at extremely far distances.

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Answer:

I can't read it if you zoom in its still blurry

Explanation:

read the question to me and I'll try to answer it thx

Answer:

False.

Explanation:

Behavior modification is a therapeutic process that is focused on changing any undesirable negative behavior in an individual through the use of positive or negative consequence and biofeedback.

This simply means that, behavior modification typically involves the process in which a desired behavior is reinforced while withholding reinforcement for any undesired behaviors.

Behavior modification is typically based on operant conditioning principles, through negative or positive reinforcement, undesirable behaviors developed by an individual are mainly replaced with more desirable ones.

Hence, behavior modification can be used to correct human behaviors or disorders such as enuresis (bed-wetting), Obsessive-Compulsive Disorder (OCD), generalized anxiety disorder, Attention-Deficit/Hyperactivity Disorder (ADHD), phobias, etc.

However, behaviors can still come back or be exhibited by an individual even if they have been extinguished through operant conditioning.

Operant conditioning can be defined as an associative learning process which involves reinforcing the strength of a behavior.

Answer:

Flase

Explanation:

edge2021

Answer:

If the number of half-lives increases, then the number of radioactive atoms decreases, because about half of the atoms'nuclei decay with each half life.

A. the motion is in the positive direction for t-values in the interval (5, 7). B. Displacement is -866.67 m and C. the distance traveled over the interval [0,8] is 866.67 m.

a. To determine when the motion is in the positive direction, we need to find the values of t for which the velocity v(t) is positive. In this case, v(t) = 2t^2 - 24t + 70.
To find when v(t) is positive, we need to solve the inequality 2t^2 - 24t + 70 > 0.
By factoring or using the quadratic formula, we find that t ∈ (5, 7) satisfies the inequality.
Therefore, the motion is in the positive direction for t-values in the interval (5, 7).
b. The displacement over the interval [0,8] can be found by evaluating the antiderivative of the velocity function v(t) = 2t^2 - 24t + 70.
The antiderivative of v(t) is 2/3 * t^3 - 12t^2 + 70t + C, where C is a constant.
Evaluating the antiderivative at t = 8 and t = 0, we get:
Displacement = (2/3 * 8^3 - 12 * 8^2 + 70 * 8) - (2/3 * 0^3 - 12 * 0^2 + 70 * 0)
Displacement = (2/3 * 512 - 12 * 64 + 70 * 8) - (0)
Displacement = 341.33 - 768 + 560
Displacement = -866.67 m
c. To find the distance traveled over the interval [0,8], we need to consider the absolute value of the displacement.
Therefore, the distance traveled over the interval [0,8] is 866.67 m.

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He accomplished no job. When Taylor's car broke down, he attempted to push it with 8,000 newtons of force before giving up and calling a tow truck.

The mechanical advantage is how many times a machine can multiply the force of the effort. The mechanical advantage of the machine increases when the effort force is exerted across a bigger distance.

Force multipliers are tools that lessen the force required to move an object. Force multipliers come in handy when lifting heavy objects or performing other actions that call for a lot of force.

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To determine the activation energy, more information is needed. The rate of reaction doubling with every 10-degree rise in temperature is a characteristic of reactions that follow the Arrhenius equation.

The Arrhenius equation describes the relationship between the rate of a reaction and temperature, given by the equation k = Ae^(-Ea/RT), where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant, and T is the temperature in Kelvin.

If a reaction doubles its rate with every 10-degree rise in temperature, it indicates that the exponential factor e^(-Ea/RT) becomes 2. Taking the natural logarithm of both sides, we have ln(2) = -Ea/RT.

However, without knowing the specific temperature or the rate constant at a particular temperature, it is not possible to determine the exact value of the activation energy (Ea). Additional data, such as rate constants at different temperatures, would be needed to calculate the activation energy using the Arrhenius equation.

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Answer:

P = 1 / f = 1 / 16.7 = .06 sec      period of 1 revolution

Period of 1/3 revolution = .06 s / 3 = .02 sec

If the light flashes every .02 sec the fan will appear motionless

The change in the period of the heated pendulum would be 0.0111 seconds.

The change in the period of a pendulum due to a change in temperature can be calculated using the formula:

ΔT = α * T0 * Δθ

Where:

To solve the problem, we need the coefficient of linear expansion of brass (α). Let's assume α = 19 x 10^(-6) (per degree Celsius).

T0 = 3.94 s (initial period of the pendulum)

Δθ = 149 °C (change in temperature)

ΔT = (19 x 10^(-6) * 3.94 s/°C) * (149 °C)

= 0.0110866 s

Therefore, the change in the period of the heated pendulum is approximately 0.0111 seconds.

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Answer:

9.8 meters per square second

Explanation:

Free Falling Object. the value of g is 9.8 meters per square second on the surface of the earth. The gravitational acceleration g decreases with the square of the distance from the center of the earth. But for many practical problems, we can assume this factor to be a constant.

Answer:

41895 J

Explanation:

GPE= mgh

m=95

g=9.8

h=45

95*9.8*45

The gravitational potential energy of the rock at the top of the cliff is 41895 Joules.

Gravitational potential energy is simply the potential energy an object possessse in relation to another object due to gravity.

It is expressed as;

U = mgh

Given the data in the question;

We substitute our values into the expression above.

U = mgh

U = 95kg × 9.8m/s² × 45m

U = 41895kgm²/s²

U = 41895J

Therefore, the gravitational potential energy of the rock at the top of the cliff is 41895 Joules.

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The work done by the aluminum in 216 Joules.

The ratio of the increase in length to the original length for each degree increase in temperature is called the coefficient of linear expansion. The coefficient of linear thermal expansion describes the change in the length of a material as a function of temperature. A distinction is made between the average thermal coefficient of expansion and the physical coefficient of linear expansion.

calculation:-

Work done = msT2 -T1

= 8000000 g × 2 × 1/000000 ( 20- 10)

= 600

density = 2.7

work done per unit = 600/2.7

= 216 jolues

The volume expansion coefficient is three times the linear expansion coefficient. Heating an object changes its dimensions. It depends on your body type. Expansion can be done in length in which case it is called linear expansion. Heating a square wafer causes expansion in two planes lengthwise and widthwise. We call this range dilation.

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solution

Given

mass= 20kg

velocity =3m/s

K.E=?

K.E= ½mv²

½×20×3²

½×20×9

½×180

90 J