Wayne charges the following for repairing washing machines:
£28 call-out charge + £16 for each half-hour he spends on the repair
What will the total cost be for a repair which takes one and a half hours?

Answer:

Hi! im not sure about the always sometimes one but i could help on the never intersect.

Step-by-step explanation:

so the picture below is 2 lines crossing over each other the never intersect is these 2 lines cannot touch i think, so if they dont touch they would be parallel so one line is exactly the same right next to it so there not touching. i hope this helps :p

Answer:

Sometimes, it depends. They intersect when when the point is on the line

Answer:

x = 24.8

Step-by-step explanation:

2x + 12.8 + 117.6 = 180

Then solve.

2x + 130.4 = 180

2x = 4.6

x = 24.8

Answer:

24.8

Step-by-step explanation:

you just told me to say something so i did.

Answer:

Because every outcome is equally likely, and the probability of the sample space must be 1, we can prove that each outcome must have probability: P ( an outcome ) = 1 | S | Where |S| is the size of the sample space, or, put in other words, the total number of outcomes of the experiment.

Step-by-step explanation:

Answer:

5/9

Step-by-step explanation:

we add all of the values and divide by the total number in this case 9, all of them add to make 5 so we do 5÷9 to get 5/9

The final values of the angles are:

C0 = A0 = 2

C1 = B1 = -7

theta1 = 0 degrees

C2 = B2 = -7

theta2 = 0 degrees

Here, we have,

To determine the values of C0, C1, theta1 (in degrees), C2, and theta2 (in degrees), we need to match the given expressions for x(t) with the given values for A0, A1, B1, A2, B2, and w.

Comparing the expressions:

x(t) = C0 + C1sin(wt+theta1) + C2sin(2wt+theta2)

x(t) = A0 + A1cos(wt) + B1sin(wt) + A2cos(2wt) + B2sin(2w*t)

We can match the constant terms:

C0 = A0 = 2

For the terms involving sin(wt):

C1sin(wt+theta1) = B1sin(w*t)

We can equate the coefficients:

C1 = B1 = -7

For the terms involving sin(2wt):

C2sin(2wt+theta2) = B2sin(2wt)

Again, equating the coefficients:

C2 = B2 = -7

Now let's determine the angles theta1 and theta2 in degrees.

For the term C1sin(wt+theta1), we know that C1 = -7. Comparing this with the given expression, we have:

C1sin(wt+theta1) = -7sin(wt)

Since the coefficients match, we can equate the arguments inside the sin functions:

wt + theta1 = wt

This implies that theta1 = 0.

Similarly, for the term C2sin(2wt+theta2), we have C2 = -7. Comparing this with the given expression, we have:

C2sin(2wt+theta2) = -7sin(2w*t)

Again, equating the arguments inside the sin functions:

2wt + theta2 = 2wt

This implies that theta2 = 0.

Therefore, the final values are:

C0 = A0 = 2

C1 = B1 = -7

theta1 = 0 degrees

C2 = B2 = -7

theta2 = 0 degrees

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Farmer Ed has 3,000 meters of fencing and wants to enclose a rectangular plot that borders on a river.The largest area that can be enclosed is 750,000 square meters.

To get the largest area that can be enclosed, we have to find the dimensions of the rectangular plot. Let's assume that the width of the rectangle is x meters.The length of the rectangle can be found by subtracting the width from the total length of fencing available:L = 3000 - x. The area of the rectangle can be found by multiplying the length and width:Area = L × W = (3000 - x) × x = 3000x - x²To find the maximum value of the area, we can differentiate the area equation with respect to x and set it equal to zero.

Then we can solve for x: dA/dx = 3000 - 2x = 0x = 1500. This means that the width of the rectangle is 1500 meters and the length is 3000 - 1500 = 1500 meters.The area of the rectangle is therefore: Area = L × W = (3000 - 1500) × 1500 = 750,000 square meters. So the largest area that can be enclosed is 750,000 square meters.

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Answer:

1.12

Step-by-step explanation:

100+12=112

112÷100=1.12

Answer =1.12

Answer:

45

Step-by-step explanation:

25 = 700

Y = 1260

Now you need to do cross multiplication .

25 X 1260=700Y

Since it's in a multiplying form you can simplify by dividing 700 by 25

1260=700Y/25

1260=28Y

Y=45

The number of push-ups did sara did during gym class if for every 7 push-ups Dulce can do, Sara can do 6 is 24 push ups.

Number of push ups Dulce can do : number of push ups Sara can do

Let

number of push ups Sara does = x

7 : 6 = 28 : x

7/6 = 28/x

cross product

7 × x = 28 × 6

7x = 168

divide both sides by 7

x = 168/7

x = 24

Therefore, Sara does 24 push ups during the gym class.

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Answer:

the horizontal line through y = 1.5

Step-by-step explanation:

The equation ax + by = c becomes 0x + 1y = 1.5 when a = 0, b = 1 and c = 1.5 are substituted.

0x + 1y = 1.5 becomes y = 1.5.

The graph of this equation is the horizontal line through y = 1.5.

Answer:

18.41

Step-by-step explanation:

We want to solve for x (adjacent) with given measurement and hypotenuse. Set up the equation of cosine:

\(\displaystyle{\cos 64^{\circ} = \dfrac{x}{42}}\)

We know that cosine is adjacent to hypotenuse so that's how we set up the equation above. Then solve for x:

\(\displaystyle{42\cos 64^{\circ} = x}\\\\\displaystyle{18.41=x}\)

Therefore, x = 18.41

Answer:

p+0.25=272.5

Step-by-step explanation:

just add 0.25 on both off the equation

the answer is 0 because -5 -(-3) equals 8 which cancels out when u add negative 8 :)

Answer:

5/8

Step-by-step explanation:

apple trees to pear trees=5/2 to peach trees=(5/2)/4=5/8

The  measure of each exterior angle of a regular polygon of 12 sides is equal to 30° option D.

A polygon's exterior angles are generated by extending one of its sides and extending the other side. The sum of a polygon's outside angles equals 360 degrees. You've probably heard of the phrase polygon. A polygon is an enclosed flat shape made up of three or more line segments. The line segments are referred to as sides, and the location where two sides intersect is referred to as the polygon's vertex.

Adjacent sides are a pair of sides that meet at the same vertex. The inner angle is the angle formed by one of the vertices. For all polygons, the interior and external angles at each vertex vary.

We know that the sum of a polygon's outer angles is 360.

As a result, the exterior angle of a regular polygon with 12 sides Equals 360/ 12 = 30.

So, The  measure of each exterior angle of a regular polygon of 12 sides is equal to 30°.

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Answer:

19$

Step-by-step explanation:

Because 19$ 20% off=15.20 and you added taxes]

Have a great day :}

The required △QST is similar to △URT by the AAA similarity postulate.

Similar triangles are those triangles that have similar properties,i.e. angles and proportionality of sides.

Here,

The question seems to be incomplete, assuming that triangles are equilateral triangles.

Consider the triangle,
△QST and △URT.
∠Q = ∠U     [as meaure of angle is 60°]
∠S = ∠R      [as meaure of angle is 60°]
∠T = ∠T      [as meaure of angle is 60°]

So,
△QST ~△URT by AAA similarity postulate.

So,
QS/UR = ST/RT  = QT/UT

Thus, the required △QST is similar to △URT by the AAA similarity postulate.

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Answer:

1 is false

2 is false

3 is true

Step-by-step explanation:

The correlation coefficient between x and f(x) is approximately 0.39. This suggests a weak positive correlation between the cost per seat and the profit the airline makes.

The precise metric used in a correlation analysis to quantify the strength of the linear relationship between two variables is the correlation coefficient.

To calculate the correlation coefficient between x and f(x), we need to calculate several quantities first:

mean of x:

\($\overline{x}\) = {50+35+60+65+70+75+80}{7} = {435}/{7}

= 62.14

mean of f(x):

\($\overline{f(x)}\)= {1,272 + 1,884.5 + 2,322 + 2,584.5 + 2,672 + 2,584.5 + 2,322}/{7}

= 2,112.86

and, standard deviation of x:

\($s_x\)=\(\sqrt{\frac{\sum_{i=1}^n (x_i - \overline{x})^2}{n-1}}\)

= \(= \sqrt{\frac{(50-62.14)^2 + (35-62.14)^2 + (60-62.14)^2 + (65-62.14)^2 + (70-62.14)^2 + (75-62.14)^2 + (80-62.14)^2}{6}} \\\approx 17.27$\)

and, standard deviation of f(x):

\($s_{f(x)} = \sqrt{\frac{\sum_{i=1}^n (f(x_i) - \overline{f(x)})^2}{n-1}}\)

= (1,272-2,112.86)² + (1,884.5-2,112.86)² + (2,322-2,112.86)² + (2,584.5-2,112.86)² + (2,672-2,112.86)²+  (2,584.5-2,112.86)² + (2,322-2,112.86)²}/ 6

= 385.09

Now, covariance of x and f(x):

\($cov(x,f(x)) = \frac{\sum_{i=1}^n (x_i - \overline{x})(f(x_i) - \overline{f(x)})}{n-1}\)

= {(50-62.14)(1,272-2,112.86) + (35-62.14)(1,884.5-2,112.86) + (60-62.14)(2,322-2,112.86) + (65-62.14)(2,584.5-2,112.86) + (70-62.14)(2,672-2,112.86) + (75-62.14)(2,584.5-2,112.86) + (80-62.14)(2,322-2,112.86)} / 6

= 762.36

Using these values, we can calculate the correlation coefficient:

\($r = \frac{cov(x,f(x))}{s_x s_{f(x)}} = \frac{762.36}{17.27 \cdot 385.09} \approx 0.39$\)

Therefore, the correlation coefficient between x and f(x) is approximately 0.39. This suggests a weak positive correlation between the cost per seat and the profit the airline makes.

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Answer:

Explanation:

Here, we want to solve for the missing parts of the triangle

we have the value of a as 5 and b as 12

What we have is a right triangle since one of the internal angles is 90 degrees

We can start by getting the value of c

Mathematically, we can get this by the use of Pythagoras' theorem

c faces the right angle and thus, it is the hypotenuse of the triangle

Mathematically, the square of the length of the hypotenuse equals the sum of the squares of the length of the two other sides of a right anlged triangle

We have this as:

Now, we need to get the other internal angles

We can use the appropriate trigonometric ratios here

The question specifically asks to get the value of internal angle A

From what we have, A faces a and that makes a the opposite

The trigonometric ratio that compares the opposite and the hypotenuse is the sine

It is the ratio of the length of the opposite to the length of the hypotenuse

Mathematically, we have this as:

The solution are,

angle P = 130 degrees

arc SF = 50 degrees

Angle may be mentioned as a figure which can be defined as that is formed by two rays or lines that shares a common endpoint is called an angle. The two rays are called the sides of an angle, and the common endpoint is called the vertex.

here, we have,

from the given diagram we get,

angle P = 130 degrees because it is alternate adjacent to 130 degrees.

now, we have,

130 = 1/2(210+SF)

130 = 105+1/2SF

1/2SF = 25

arc SF = 50 degrees

Hence, The solution are,

angle P = 130 degrees

arc SF = 50 degrees

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\(c(g) = 7g + 52 \\ c(0) = 52\)

\(g(x) = x {}^{2} - 7x + 12 \\ g(x) = 0 \\ x = 3 \: \: \: \: \: \: \: \: x = 4\)

Let's see

#1

So

x intercepts

True

#2

Option C

#3

Option D

#4

I solved it in your another question , Can't add that answer here due to copyright restrictions

Answer:

y = -2/3x - 11

Step-by-step explanation:

Steps to find the perpendicular bisector:

1) Find the midpoint of line PQ

Midpoint formula: (\(\frac{x_{1} + x_{2} }{2} \\\), \(\frac{y_{1} + y_{2}}{2}\))

Midpoint of line PQ = (6, -2)

2) Find the slope of line PQ

Slope formula: \(\frac{y_{2} - y_{1}}{x_{2} - x_{1}}\)

Slope of line PQ = 3/2

3) Find the negative reciprocal of the slope of PQ

To find the negative reciprocal just swap the numerator and denominator and add a negative sign. If it is already negative it will become positive.

In this case it will be -2/3

4) Write the equation of line PQ in slop-intercept form.

Slope-intercept form: y = mx + b

This is what it will look like for line PQ: y = \(\frac{3}{2}\)x + b

5) Plug the points of the midpoint into the line and solve for the intercept (b)

This is what it will look like: -2 = \(\frac{3}{2}\)(6) + b

-2 = 18/2 + b

-2 = 9 + b

-11 = b

6) Write the equation of the perpendicular bisector

m = the negative reciprocal of the slope of PQ = -2/3

This is what the equation will look like: y = -2/3x - 11

Hope this helped! Please give Brainliest!

The linear equation formed from the  perpendicular bisector of PQ is y = -2/3 x + 2

The standard equation of a line is expressed as y = mx + b

m is the slope

b is the y-intercept

Given the coordinate points P(10,4 ) and Q(2,-8), find the slope of the line passing through the points.

m = -8-4/2-10

m = -12/-8

m = 3/2

The slope of the perpendicular bisector will be -2/3

Get the y-intercept.

Using the midpoint of the coordinates P(10,4 ) and Q(2,-8) and m = -2/3 into the formula y = mx + b

\(m = (\frac{10+2}{2},\frac{4-8}{2} )\\m=(6, -2)\)

-2 = -2/3(6) + b

-2 = -4 + b

b = 2

Hence the linear equation formed from the  perpendicular bisector of PQ is y = -2/3 x + 2

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Finite-state machines for given inputs: (a) 0s multiple of 3: 3-state machine. (b) At least four 1s: 4-state machine. (c) Exactly one 1: 2-state machine. (d) Begins with 000: 3-state machine. (e) Second is 0, fourth is 1: 4-state machine. (f) 01 pairs or 2 1s + 0s: 3-state machine. (g) Ends in 110: 3-state machine.

To construct finite-state machines that act as recognizers for the given inputs, we can follow these guidelines:

(a) For the set of all strings where the number of 0s is a multiple of 3, we can use a finite-state machine with three states. Start with the initial state, and transition to the next state whenever a 0 is encountered. After three transitions, go back to the initial state. If the machine ends in the accepting state, output 1.
(b) For the set of all strings containing at least four 1s, we can use a finite-state machine with four states. Start with the initial state, and transition to the next state whenever a 1 is encountered. If the machine enters the final state after four transitions, output 1.

(c) For the set of all strings containing exactly one 1, we can use a finite-state machine with two states. Start with the initial state and transition to the final state when the first 1 is encountered. Output 1 only if the final state is reached.

(d) For the set of all strings beginning with 000, we can use a finite-state machine with three states. Start with the initial state and transition to the next state whenever a 0 is encountered. If the machine reaches the final state after three transitions, output 1.

(e) For the set of all strings where the second input is 0 and the fourth input is 1, we can use a finite-state machine with four states. Start with the initial state and transition to the next state based on the inputs. Output 1 only if the machine reaches the final state.

(f) For the set of all strings consisting entirely of any number (including none) of 01 pairs or consisting entirely of two 1s followed by any number (including none) of 0s, we can use a finite-state machine with three states. Start with the initial state and transition based on the inputs. Output 1 only if the final state is reached.

(g) For the set of all strings ending in 110, we can use a finite-state machine with three states. Start with the initial state and transition based on the inputs. Output 1 only if the final state is reached.

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Finite-state machines (FSMs) can be constructed to act as recognizers for specific patterns in input strings. These are examples of how to construct FSMs as recognizers for different patterns in input strings. Each FSM is designed to produce an output of 1 when the input received matches the description provided.

Let's consider the given cases and construct FSMs for each one.

(a) The set of all strings where the number of Os is a multiple of 3:
To construct an FSM for this, we can keep track of the number of Os encountered so far. Initially, set the count to zero. When an O is encountered, increment the count by one. If the count becomes a multiple of 3, the FSM outputs 1; otherwise, it outputs 0. Reset the count to zero whenever a 1 is encountered.

(b) The set of all strings containing at least four 1s:
To create an FSM for this, we can keep track of the number of 1s encountered so far. Initially, set the count to zero. When a 1 is encountered, increment the count by one. If the count becomes equal to or greater than four, the FSM outputs 1; otherwise, it outputs 0.

(c) The set of all strings containing exactly one 1:
To build an FSM for this, we can have two states: a "no 1 encountered" state and a "1 encountered" state. Initially, start in the "no 1 encountered" state. Whenever a 1 is encountered, transition to the "1 encountered" state. If another 1 is encountered in the "1 encountered" state, transition to a third "more than one 1 encountered" state. In this case, the FSM outputs 0. Otherwise, if no additional 1s are encountered, the FSM outputs 1.

(d) The set of all strings beginning with 000:
To create an FSM for this, start in an initial state. When a 0 is encountered, transition to a second state. If two consecutive 0s are encountered in the second state, transition to a third state. Finally, if a third 0 is encountered in the third state, the FSM outputs 1; otherwise, it outputs 0.

(e) The set of all strings where the second input is 0 and the fourth input is 1:
To construct an FSM for this, start in an initial state. When the first input is read, transition to a second state. In the second state, transition to a third state if the second input is 0. In the third state, transition to a fourth state if the third input is not 0. Finally, in the fourth state, if the fourth input is 1, the FSM outputs 1; otherwise, it outputs 0.

(f) The set of all strings consisting entirely of any number (including none) of 01 pairs or consisting entirely of two Is followed by any number (including none) of Os:
To create an FSM for this, we can have multiple states to represent different scenarios. We start in an initial state and transition to a second state when a 0 is encountered. In the second state, transition back to the initial state if a 1 is encountered. If a 1 is encountered in the initial state, transition to a third state. In the third state, transition to a fourth state if an O is encountered. Finally, if an O is encountered in the fourth state, the FSM outputs 1; otherwise, it outputs 0.

(g) The set of all strings ending in 110:
To construct an FSM for this, start in an initial state. Transition to a second state if a 1 is encountered. In the second state, transition to a third state if a 1 is encountered again. Finally, if a 0 is encountered in the third state, the FSM outputs 1; otherwise, it outputs 0.

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The test statistic for the given test is t = 2.59.

What is a standard deviation?

The standard deviation in statistics is a measure of the amount of variation or dispersion in a set of values. A low standard deviation indicates that the values are close to the set's mean, whereas a high standard deviation indicates that the values are spread out over a larger range.

Given data:

                    \(\bar D\) = 4.1, Sd = 5, n = 10, μd = 0

Now the test statistic can be computed as

                \(t=\frac{\bar D-\mu_d}{S_d/\sqrt{n} }\)

                \(t=\frac{4.10-0}{5/\sqrt{10}} \\\\t=2.59\)

Hence, the test statistic for the given test would be t = 2.59.

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Answer:

B 42

Step-by-step explanation:

2 pounds = 32 ounces so there is 48 ounces left, then she ate 6 ounces, 48 - 6 = 42 :)

Answer:

7

Step-by-step explanation:

opposite value of -7 is 7

Part (a)

-----------------------

Work Shown:

We'll apply the sine rule since we have a known opposite side of AB = 10 and an unknown hypotenuse we want to find BD.

Focus on triangle ABD

sin(angle) = opposite/hypotenuse

sin(D) = AB/BD

sin(56) = 10/x

x*sin(56) = 10

x = 10/sin(56)

x = 12.062179

x = 12.1

Make sure your calculator is in degree mode.

===================================================

Part (b)

-----------------------

Work Shown:

Draw an xy coordinate grid.

Place point A at the origin (0,0).

Point B is 10 units above this, so B is at (0,10).

Point C is at (18,10) since we move 18 units to the right of B.

Point D is at approximately (6.745085, 0). The 6.745085 is from solving tan(56) = 10/x for x.

Refer to the diagram below.

Apply the distance formula for the points C and D.

\(C = (x_1,y_1) = (18,10)\\\\D = (x_2,y_2) \approx (6.745085,10)\\\\\)

\(d = \text{ distance from C to D}\\\\d = \sqrt{ (x_1-x_2)^2+(y_1-y_2)^2}\\\\d \approx \sqrt{ (18-6.745085)^2+(10-0)^2}\\\\d \approx \sqrt{ 226.673112 }\\\\d \approx 15.055667\\\\d \approx 15.1\\\\\)

Segment CD is roughly 15.1 cm long.

a) The length of BD to 1 decimal place is 12.1

b) The length of CD to 1 decimal place is 15.1

Any closed figure made by 4 line segments joined end to end in series is called a quadrilateral.

Given ABCD is a trapezium AD and BC are parallel

we have a known opposite side of AB = 10 and an unknown hypotenuse we want to find BD.

on triangle ABD

sin(angle) = opposite/hypotenuse

sin(D) = AB/BD

sin(56) = 10/x

xsin(56) = 10

x = 10/sin(56)

x = 12.062179

x = 12.1 degree

Let xy coordinate grid. Place point A at the origin (0,0).

Point B is 10 units above this, B is at (0,10).

Point C is at (18,10) since we move 18 units to the right of B.

Point D is at approximately (6.745085, 0).

The 6.745085 solving tan(56) = 10/x for x.

Apply the distance formula for the points C and D.

D = √(18 - 6.745085)² + (10 -0)²

D = 15.1

Thus Segment CD is roughly 15.1 cm long.

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