write two numbers that multiply to 100 and add to 20
Answer:
10*10
Step-by-step explanation:
There are n cities in a OneWayCountry (country in which every road is a One-Way road). Every pair of cities is connected by exactly one direct one-way road. Show that there exists a city which can be reached from every other city either directly or via at most one other city.
The cities such that this path is \(C_{1}\) → \(C_{2}\) → \(C_{3}\) . . . → \(C_{n}\). Now, if all roads are going towards \(c_{n}+1\), then add \(c_{n}+1\) at the end of this path. Otherwise, let \(C_{i}\) be the first city in this path such that there is a road from \(C_{i}\)-1 to \(c_{n}+1\) and from \(c_{n}+1\) to \(C_{i}\). Place \(c_{n}+1\) between \(C_{i}\)−1 and \(C_{i}\) to get the desired path.
What is mathematical induction method?Mathematical Induction is a technique of proving a statement, theorem or formula which is thought to be true, for each and every natural number n. By generalizing this in form of a principle which we would use to prove any mathematical statement is 'Principle of Mathematical Induction'.
The question says that between any two cities X and Y, either there’s an
one-way road from X to Y or from Y to X, but not both. Then show that
there is a path from some city A which visits all the cities exactly once.
This problem is very similar to the Football league problem #7 in Homework 1. This problem can be modeled as a directed graph in which cities
are represented as vertices and there’s an edge from vertices X to Y if
there’s a road from cities X to Y. And then, our goal is to find a path
in this graph which visits every vertex in the graph.
The rest of the solution is very similar to the argument in Problem 7 of
homework 1. We use induction of number of cities, say n.
As a base case, if n = 2, there are only two cities X and Y and the path
is simply the edge between X and Y.
For induction hypothesis, assume that the statement is true for any set
of n cities. That is’ for any set of n cities, we can find a path which visits
all the cities exactly once.
Let’s prove the statement for n + 1 cities. Leave out n + 1 th city (say,
\(c_{n}+1\)) and for the remaining n cities, by induction hypothesis, we can find a path which visits all these n cities exactly once. Let us label the cities such that this path is \(C_{1}\) → \(C_{2}\) → \(C_{3}\) . . . → \(C_{n}\). Now, if all roads are going towards \(c_{n}+1\), then add \(c_{n}+1\) at the end of this path. Otherwise, let \(C_{i}\) be the first city in this path such that there is a road from \(C_{i}\)-1 to \(c_{n}+1\) and from \(c_{n}+1\) to \(C_{i}\). Place \(c_{n}+1\) between \(C_{i}\)−1 and \(C_{i}\) to get the desired path.
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factorise (6²+28ab+196a²)
Which of the following are true statements? Select all that apply.
All integers are rational numbers.
Repeating decimals are not rational numbers.
StartFraction 715 over negative 14 EndFractionis not a rational number.
Terminating decimals are rational numbers.
0.278254….. is a terminating decimal, therefore it is a rational number.
Answer:
A . All integers are rational numbers.
D . Terminating decimals are rational numbers
E 0.278254….. is a terminating decimal, therefore it is a rational number.
Step-by-step explanation:
Please mark brainiest please
What is the product of d−9 and 2d2+11d−4 ?
The product of the terms \((d - 9)\) and \((2d^{2} + 11d -4)\) will be \((2d^{3} - 7d^{2} - 103d + 36)\).
We have to find the product of two terms.
First term = (d - 9)
Second term = \((2d^{2} + 11d -4)\)
To find the product of these two terms, we will be using the distributive property. According to the distributive property, when we multiply the sum of two or more addends by a number, it will give the same result as when we multiply each addend individually by the number and then add the products together.
We have to find : \((d - 9) (2d^2 + 11d -4)\)
Using the distributive property,
\(d * 2d^{2} + d * 11 + d * (-4) - 9 * 2d^2 - 9 * 11d - 9 * (-4)\)
After further multiplication, we get
\(2d^{3} + 11d^2 - 4d - 18d^{2} - 99d + 36\)
Now, combine all the like terms.
\(2d^{3} + 11d^{2} - 18d^{2} - 4d - 99d + 36\)
\(2d^{3} - 7d^{2} - 103d + 36\)
Therefore, the product of d-9 and 2d^2 + 11d -4 is \(2d^{3} - 7d^{2} - 103d + 36\)
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Simplify the equation 6/x-1-5x/4
Step-by-step explanation:
The answer with explanation is in the image.
In a 2011 article in North Carolina Law Review, M. Radelet and G. a logistic prediction equation for death penalty verdicts in North Carolina. Let Y denote whether a subject convicted of murder received the death penalty (1 = yes), for defendant's race h (h = 1, black; h = 2, white), victim's race i (i = 1, black; i = 2, white), and number of additional factors j (j = 0, 1, 2). For the model = = - logit[P(Y = 1)] = a + BR +BY+B they reported â = -5.26, BP = 0.00, B2 = 0.17, BY = 0.00, BY = 0.91, B6 0.00, B 9 = 2.02, B5 = 3.98. a. Estimate the probability of receiving the death penalty for the group most likely to receive it. = LOGISTIC REGRESSION = b. If, instead, parameters used constraints B? = By = B = c. If, instead, parameters used constraints En BR = ŹBY = £; B = 0, report : 0, report the estimates. h the estimates.
Based on the given information, we can estimate the probability of receiving the death penalty for the group most likely to receive it by substituting the values of the coefficients into the logistic prediction equation:
P(Y = 1) = exp(a + B1R + B2Y + B3 + B4h + B5i + B6j + B7h*i)
where:
a = -5.26
B1 = 0.00
B2 = 0.17
B3 = 0.00
B4 = 0.91
B5 = 0.00
B6 = 2.02
B7 = 3.98
Assuming that the group most likely to receive the death penalty is a black defendant (h = 1), with a white victim (i = 2), and no additional factors (j = 0), we can plug in these values into the equation:
P(Y = 1) = exp(-5.26 + 0.00R + 0.17Y + 0.00 + 0.911 + 0.002 + 2.020 + 3.981)
P(Y = 1) = exp(-5.26 + 0.91 + 3.98)
P(Y = 1) = exp(-0.37)
Using the exponential function, we can calculate the estimated probability:
P(Y = 1) = 0.691
So, the estimated probability of receiving the death penalty for the group most likely to receive it (a black defendant with a white victim and no additional factors) is approximately 0.691 or 69.1%.
If the constraints B1 = By = B = 0 are used instead, the estimates for the coefficients would be different and would need to be calculated accordingly.
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William is planning a party. He spent $110.74 to buy 9.8 pounds of candy for favors. What was the cost per pound of the candy? (Do not include the $ sign in your answer.)
Answer: $11.30 per pound
Step-by-step explanation:
William spent $110.74 to buy 9.8 pounds of candy.
To find the cost per candy, divide the amount spent by the quantity of candy:
=Amount spent on candy / Quantity of candy
= 110.74 / 9.8
= $11.30 per pound
write a function myMedian that takes a vector as input and returns the median of the vector as output. Do not use the built-in function median. Use myMedian function in the command window
and verify the result by comparing with the output of built-in function median
In order to write a function myMedian that takes a vector as input and returns the median of the vector as output, we can follow these steps:
Step 1: Define a function named myMedian that takes a vector as input.
Step 2: Sort the elements of the vector in ascending order.
Step 3: Find the length of the vector.
Step 4: If the length of the vector is even, then calculate the average of the middle two elements.
Step 5: If the length of the vector is odd, then return the middle element.
Step 6: Display the median of the vector as output. We can use the myMedian function in the command window and verify the result by comparing with the output of the built-in function median.
Here's the code for the function myMedian in MATLAB:
```function med = myMedian(vector)
sortedVector = sort(vector);
n = length(sortedVector);
if mod(n, 2) == 0
med = (sortedVector(n/2) + sortedVector(n/2 + 1)) / 2;
else
med = sortedVector((n+1)/2);
end
end```
To verify the output, we can run the following code in the command window:```
v = [2, 5, 1, 7, 3];
m1 = myMedian(v) % output should be 3
m2 = median(v) % output should be 3
```Here, we have created a vector v and passed it to the myMedian function. We have stored the output in m1 variable. We have also used the built-in median function to calculate the median of the vector v and stored it in m2 variable. Finally, we have displayed both the medians and compared them. They should be equal.
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Need the answer to this math question pls
Answer:
B
Step-by-step explanation:
1. Add the nine over on the k side. So it will be 9+k
2. Divide both sides by 4.
4x-9=k
4x=9+k
x=k+9/4
:)
3x-7-8+5x2 -x given x=-3
Answer:
-46
Step-by-step explanation:
-9-7-8-15-6-1 equals -46
Find a point slope form for the line that satisfies the stated condition
Slope 3,passing through (-4,3)
What is the equation of the line in point-slope form?
Answer:
y - 3 = 3(x + 4)Step-by-step explanation:
The equation of the line that passing through point (x₁, y₁) and has a slope of m is y - y₁ = m(x - x₁)
slope: m = 3
point: (-4, 3) ⇒ x₁ = -4, y₁ = 3
Therefore, the equation of the line in point-slope form:
y - 3 = 3(x - (-4))
y - 3 = 3(x + 4)
A rectangle with an area of 24 square inches is formed by cutting strips of equal width from a rectangular piece of paper. Find the dimensions of the new rectangle if the original rectangle measures 8 inches by 6 inches.
Answer: 4 inches by 6 inches or 8 inches by 3 inches.
Step-by-step explanation:
The area of a rectangle is A = W*L
where L is the width and L is the lenght.
Now, the original rectangle has a measure of 8 in by 6 in.
if 8in is the lenght and 6 in is the width.
We want to divide only one of those measures in equal parts, such that when we take the product of the end results is equal to 24 in.
If we divide the lenght by half (so both parts will have the same width as this did not change), we now have that the lenght is 8in/2 = 4in and the width is 6in.
Now the area is 4in*6in = 24in, which is the area that we where looking for.
We also could cut the width in half, and get the dimensions 8 inches by 3 inches.
a club sells 40 tickets to a raffle. issac bought one ticket. the probability that he will win the raffle is
Isaac has a 1/40 chance of winning the raffle, or a 2.5% chance. This indicates that he has a 2.5% probability of having his ticket chosen out of the 40 tickets that were sold.
Isaac has a 1/40 chance of winning the raffle, or a 2.5% chance. This indicates that he has a 2.5% probability of having his ticket chosen out of the 40 tickets that were sold. This is because there is only one raffle winner and it is impossible to predict which ticket will be picked.
It's also crucial to remember that his odds of winning are entirely independent of those of any other ticket holder; nobody else's ticket will affect the outcome of the raffle. As a result, Isaac has the same chance of winning as any other ticket holder. It's also vital to remember that regardless of how many tickets are sold, the likelihood of winning stays the same. Therefore, regardless of how many raffle tickets are sold, there is a 2.5% chance of winning.
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can someone please help me with this?
What is the equation of a vertical line passing through (-5, -2)?
O y = -2
O x = -5
O y = -3
O x = -7
Answer:
x=-5
Step-by-step explanation:
if point the line is passing through is -5, -2 and the line is vertical than x would have to stay the same no matter where the y is because it's vertical.
p 2 + m; use m = 1, and p = 5
Answer:
26
Step-by-step explanation:
p²+m
=> 5²+1
=> 25 + 1
=> 26
Answer:
26
Step-by-step explanation:
Substitute the given values into the expression
p² + m
= 5² + 1
= 25 + 1
= 26
Please solve I need it quick
Answer:
g(f(x)) = 36\(x^{4}\) - 54x² + 12
Step-by-step explanation:
Substitute x = f(x) into g(x) , that is
g(6x²)
= (6x²)² - 9(6x²) + 12
= 36\(x^{4}\) - 54x² + 12
Use the given information to find the equation of the quadratic function. Write the function in standard form f(x) ax² + bx + c.
The zeros of the function are x = 8 and x = -2. Use the fact that f(2)=-72 to find a.
f(x)=
The equation of the quadratic function is: f(x) = 3x² - 18x - 48
To find the equation of a quadratic function in standard form, we need to use the zeros of the function and one additional point.
Given that the zeros are x = 8 and x = -2, we can write the equation in factored form as:
f(x) = a(x - 8)(x + 2)
To find the value of "a," we can use the fact that f(2) = -72.
Substituting x = 2 into the equation, we have:
-72 = a(2 - 8)(2 + 2)
Simplifying, we get:
-72 = a(-6)(4)
-72 = -24a
Dividing both sides by -24, we find:
3 = a
Now that we know the value of "a," we can rewrite the equation in standard form:
f(x) = 3(x - 8)(x + 2)
So, the equation of the quadratic function is:
f(x) = 3x² - 18x - 48
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There is a relationship between the expected number of tickets sold for a raffle and the dollar value of the prize for the raffle. The equation t - 6p = 100 describes this relationship, where t is the expected number of tickets sold, and p is the dollar value of the raffle prize. Suppose the expected ticket sales for a certain raffle are 1900. Determine the dollar value of the raffle prize. A. $11,500 c. $1800 b. $300 d. $250 please select the best answer from the choices provided a b c d.
The amount in dollars for the raffle prize is $300.
There is a relationship between the expected number of tickets sold for a raffle and the dollar value of the prize for the raffle. The equation t - 6p = 100 describes this relationship, where t is the expected number of tickets sold and p is the dollar value of the raffle prize. The expected ticket sales for a certain raffle are 1900. We need to determine the dollar value of the raffle prize.
The equation is given below.
t - 6p = 100
We are given that the number of tickets sold is 1900.
t = 1900
We will substitute this value into the equation and find out the value of p.
1900 - 6p = 100
6p = 1800
p = 300
Hence, the dollar value of the raffle prize is $300.
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The digits in the product of 0.48 and a decimal number between 350 and 400 are 182136. Explain how to correctly place the decimal point without knowing the other factor. Then Place place the decimal point in the product.
The decimal point is to be placed three places to the left.
What are decimal numbers?
When we divide a whole number into smaller parts, we get decimals. Then, there are two parts to a decimal number: a whole number part and a fractional part. The whole component of a decimal number has the same decimal place value system as the complete number. After the decimal point, however, when we proceed to the right, we obtain the fractional portion of the decimal number.
Given that, in the question, the product of a decimal number between 350 and 400 and 0.48 results in the numbers 182136. As 0.48 is just 48/100, let's take a decimal number between 350 and 400.
If the number is 370.1, for example, we can write it as 3701/10 because it has one decimal point.
Our denominator will be 1000, because both the denominators are 100 and 10, which is equivalent three decimal places to the left of the result when we multiply 48/100 by 3701/10.
The result provided to us should therefore be written as 182.136, with the decimal point moved three spaces to the left.
The decimal point is to be placed three places to the left.
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Shanika and Vanesa are comparing their electric bills for the past month. Shanika is on a standard use plan and Vanesa is on an interval use plan. Each person’s usage is listed on the chart below: Standard Use Plan Interval Use Plan 7. 5 cents/kWh for the first 400 kWh 10 cents/kWh for the next 400 kWh 12. 5 cents/kWh for anything over 800 kWh On-peak hours - 15 cents/kWh Off-peak hours - 3 cents/kWh Both women use 1,325 kWh for the given 30 day period. Vanesa uses 500 kWh during on-peak hours and 825 during off-peak hours. Which person ends up paying more for their utilities? How much more? a. Vanesa pays $35. 88 more than Shanika. B. Vanesa pays $99. 75 more than Shanika. C. Shanika pays $35. 88 more than Vanesa. D. Shanika pays $99. 75 more than Vanesa.
Shanika ends up paying more for her utilities, and she paid $35.875 more than Vanesa.
Given to us1. Standard Use Plan
7.5 cents/kWh for the first 400 kWh 10 cents/kWh for the next 400 kWh 12. 5 cents/kWh for anything over 800 kWh2. Interval Use Plan
On-peak hours - 15 cents/kWh Off-peak hours - 3 cents/kWh3. Both women use 1,325 kWh for the given 30 day period
Shanika's BillAs given to us Shanika is using the Standard use plan, and her usage is 1,325 kWh. so,
Shanika's first 400 kWh will be charged 7. 5 cents/kWh\(400\times 7.5\\=3,000\ \rm cent\)
Shanika's next 400 kWh will be charged 10cents/kWh because she has already consumed 400kWh of energy,\(400\times 10\\=4,000\ \rm cent\)
Rest of the kWh will be charged as 12. 5 cents/kWh, as she has already consumed 800 kWh of energy,\((1325-800)\times 12.5\\= 525 \times 12.5\\= 6,562.5\ cent\)
Total bill of ShanikaThe total bill of Shanika
\(3,000\cent + 4,000\ cent +6,562.5\ cent\\= 13,562.5\ cent\\= \$135.625\)
Thus, the total bill of Shanika is $135.625.
Vanesa's BillAs given to us Vanesa is using the Interval use plan. Also, Vanesa uses 500 kWh during on-peak hours and 825 during off-peak hours.
Bill amount for the on-peak hours= Amount of electricity used x Rate of electricity
= 500 kWh x 15 cents/kWh
= 7,500 cent
Bill amount for the off-peak hours= Amount of electricity used x Rate of electricity
= 825 kWh x 3 cents/kWh
= 2,475 cent
Total bill of VanesaThe total bill of Vanesa
= 7,500 cent + 2,475 cent
= 9,975 cent
= $99.75
Thus, the total amount paid by Vanesa is $99.75.
Therefore, the amount paid by Shanika is more.
Difference between the bill amount
The difference between the bill amount of both the womens
= total bill of Shanika - total bill of Vanesa
= $135.625 - $99.75
= $35.875
Hence, Shanika ends up paying more for her utilities, and she paid $35.875 more than Vanesa.
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Answer:c
Step-by-step explanation:
Which decimal is the largest?
A.0.02
B. 0.2
C. 0.19
D. 0.029
HURRRYYYYYYY
Answer:
It's B!
Step-by-step explanation:
optimaization methods
Solve using Simplex Method
Maximize Z = 5x1 + 7x2
Subject to
x1 + x2 ≤ 4
3x1 – 8x2 ≤ 24
10x1 + 7x2 ≤ 35
and x1 ≥ 0, x2 ≥ 0
The given optimization problem is Maximize Z = 5x1 + 7x2Subject tox1 + x2 ≤ 4 …(1)3x1 – 8x2 ≤ 24 …(2)10x1 + 7x2 ≤ 35 …(3)x1 ≥ 0, x2 ≥ 0
As the optimization problem contains two variables x1 and x2, it can be solved using graphical method, however, it is a bit difficult to draw a graph for three constraints, so we will use the Simplex Method to solve it.
The standard form of the given optimization problem is: Maximize Z = 5x1 + 7x2 + 0s1 + 0s2 + 0s3Subject tox1 + x2 + s1 = 43x1 – 8x2 + s2 = 2410x1 + 7x2 + s3 = 35and x1, x2, s1, s2, s3 ≥ 0Applying the Simplex Method, Step
1: Formulating the initial table: For the initial table, we write down the coefficients of the variables in the objective function Z and constraints equation in tabular form as follows:
x1 x2 s1 s2 s3 RHSx1 1 1 1 0 0 4x2 3 -8 0 1 0 24s1 0 0 0 0 0 0s2 10 7 0 0 1 35Zj 0 0 0 0 0 0Cj - Zj 5 7 0 0 0 0The last row of the table shows that Zj - Cj values are 5, 7, 0, 0, and 0 respectively, which means we can improve the objective function by increasing x1 or x2. As x2 has a higher contribution to the objective function, we choose x2 as the entering variable and s2 as the leaving variable to increase x2 in the current solution. Step 2:
Performing the pivot operation: To perform the pivot operation, we need to select a row containing the entering variable x2 and divide each element of that row by the pivot element (the element corresponding to x2 and s2 intersection).
After dividing, we obtain 1 as the pivot element as shown below: x1 x2 s1 s2 s3 RHSx1 1/8 -3/8 0 1/8 0 3s2 5/8 7/8 0 -1/8 0 3Zj 35/8 7/8 0 -5/8 0 105/8Cj - Zj 25/8 35/8 0 5/8 0 0.
The new pivot row shows that Zj - Cj values are 25/8, 35/8, 0, 5/8, and 0 respectively, which means we can improve the objective function by increasing x1.
As x1 has a higher contribution to the objective function, we choose x1 as the entering variable and s1 as the leaving variable to increase x1 in the current solution. Step 3: Performing the pivot operation:
To perform the pivot operation, we need to select a row containing the entering variable x1 and divide each element of that row by the pivot element (the element corresponding to x1 and s1 intersection). After dividing, we obtain 1 as the pivot element as shown below:
x1 x2 s1 s2 s3 RHSx1 1 -3/11 0 1/11 0 3/11x2 0 7/11 1 -3/11 0 15/11s2 0 85/11 0 -5/11 0 24Zj 15/11 53/11 0 -5/11 0 170/11Cj - Zj 50/11 56/11 0 5/11 0 0
The last row of the table shows that all Zj - Cj values are non-negative, which means the current solution is optimal and we cannot improve the objective function further. Therefore, the optimal value of the objective function is Z = 56/11, which is obtained at x1 = 3/11, x2 = 15/11.
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HELP PLEASE ASAP
15 points!!!
(03.04 MC)
Solve
(7)x-3--62.
O21
O 39
O45
059
Answer:
x = - 23.57 (appx)
Step-by-step explanation:
\(( \frac{ - 7}{3} )x - 3 = 52\)
\( = > ( \frac{ - 7}{3} )x = 52 + 3 = 55\)
\( = > x = 55 \div ( \frac{ - 7}{3} )\)
\( = > x = \frac{55 \times 3}{ - 7} = \frac{165}{ - 7} = - 23.57(appx)\)
Magnus has to play 15 games in a chess tournament. At some point during the tournament Magnus has: ● Won half the games he has played ● Lost one-third of the games he has played ● 2 games have ended in a tie How many games does Magnus have left to play?
Magnus still has 3 games left to play
Anais bought 2% yards of ribbon. She had 1 feet 6 inches of ribbon left after trimming some curtains. How many
inches of ribbon did Anais use to trim the curtains?
Answer:
18 inches of ribbon
Step-by-step explanation:
that is the procedure above
Plot the points in a coordinate plane and sketch ∠ XYZ. Then classify it as right, acute, or obtuse.
X(5,-3), Y(4,-1), Z(6,-2)
The points X(5,-3), Y(4,-1) and Z(6,-2) can be plotted as given below. From the obtained graph ∠XYZ is the obtuse angle.
The given coordinates are X(5,-3), Y(4,-1) and Z(6,-2).
We need to classify ∠XYZ whether it is right, acute, or obtuse.
How to plot the points in a cartesian plane?A cartesian plane or coordinate plane can be defined as a plane formed by the intersection of two coordinate axes that are perpendicular to each other. The horizontal axis is called the x-axis and the vertical one is the y-axis. These axes intersect with each other at the origin whose location is given as (0, 0). Any point on the cartesian plane is represented in the form of (x, y). Here, x is the distance of the point from the y-axis and y is the distance from the x-axis.
Now, X(5,-3), Y(4,-1) and Z(6,-2) can be plotted as given below:
The given points X(5,-3), Y(4,-1) and Z(6,-2) have positive x-coordinate and negative y-coordinate.
In the cartesian plane, the fourth quadrant positive x-coordinate and negative y-coordinate.
So, all points X(5,-3), Y(4,-1) and Z(6,-2) lie in the fourth quadrant.
From the graph, we can see that the two lines make an obtuse angle, which is more than 180° and less than 360°.
From the obtained graph ∠XYZ is the obtuse angle.
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Juan starts at 10:30 AM and drives at a constant speed. At 12 noon he has traveled for 105 miles. If he continues at this constant speed for another five hours how far will he travel altogether?
Will mark brainly if you help
P.s this is 6th grade math
Answer:
525 i think
Step-by-step explanation:
Since he 105 times 5 is 125
Answer:
10:152
Step-by-step explanation:
what is the greatest possible product of a four digit number and a three digit number obtained from seven distinct digits
the greatest possible product of a four-digit number and a three-digit number obtained from seven distinct digits is 2,463,534.
To find the greatest possible product of a four-digit number and a three-digit number obtained from seven distinct digits, we can start by considering the largest possible values for each digit.
Since we need to use seven distinct digits, let's assume we have the digits 1, 2, 3, 4, 5, 6, and 7 available.
To maximize the product, we want to use the largest digits in the higher place values and the smallest digits in the lower place values.
For the four-digit number, we can arrange the digits in descending order: 7, 6, 5, 4.
For the three-digit number, we can arrange the digits in descending order: 3, 2, 1.
Now, we multiply these two numbers to find the greatest possible product:
7,654 * 321 = 2,463,534
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