9514 1404 393
Answer:
about 14.34%
Step-by-step explanation:
The percentage change can be found from ...
% change = ((new value)/(old value) -1) × 100%
= (132.17/154.30 -1) × 100%
≈ (0.8566 -1) × 100%
= -14.34%
The decrease was about 14.34%.
The drama club is selling tickets to their play to raise money for the show's expenses. Each student ticket sells for $5 and each adult ticket sells for $10. The auditorium can hold at most 130 people. The drama club must make no less than $900 from ticket sales to cover the show's costs. If
x
x represents the number of student tickets sold and
y
y represents the number of adult tickets sold, write and solve a system of inequalities graphically and determine one possible solution.
The system of inequalities is:
5x + 10y ≥ 900 (total ticket sales must be at least $900)
x + y ≤ 130 (total number of tickets sold must be at most 130)
One possible solution is x = 70 (student tickets) and y = 60 (adult tickets).
To write a system of inequalities based on the given information, we can consider the revenue from ticket sales and the seating capacity of the auditorium:
Let x represent the number of student tickets sold, and y represent the number of adult tickets sold.
Revenue inequality:
The drama club must make no less than $900 from ticket sales, so the revenue equation is: 5x + 10y ≥ 900. This equation ensures that the total revenue from ticket sales is at least $900.
Seating capacity inequality:
The auditorium can hold at most 130 people, so the total number of tickets sold cannot exceed this limit: x + y ≤ 130.
To solve this system of inequalities graphically, we plot the inequalities on a graph. The shaded region where the inequalities overlap represents the feasible region or the possible solutions.
One possible solution within this feasible region could be x = 70 (student tickets) and y = 60 (adult tickets). This combination satisfies both inequalities and fulfills the revenue requirement of at least $900.
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Two sides of a triangle measure 27 inches and 32 inches.
Which could represent the length of the third side?
Answer options:
5 in
59 in
7 in
62 in
Answer:
62 in
Step-by-step explanation:
the Hypotenuse of a triangle is always longer than the two other sides, 27 + 32 is larger than all but one of the options, 62. Making 62 the answer by process of elimination.
Solve and graph the inequality 5x≤ 15.
To solve and graph the inequality 5x ≤ 15, we can start by isolating x on one side of the inequality sign.
Dividing both sides of the inequality by 5, we get:
x ≤ 3
This means that any value of x that is less than or equal to 3 will satisfy the inequality.
To graph the solution, we can plot a closed circle at x = 3 and shade the region to the left of the circle, including the circle itself. This is because any value of x less than or equal to 3 will make the inequality true, and the circle at x = 3 is included in the solution because x can be equal to 3.
So the graph of the solution to the inequality 5x ≤ 15 looks like:
o
/
/
-------o--------
x ≤ 3
The bolded region includes the closed circle at x = 3 and all the values of x to the left of it.
\(\huge\text{Hey there!}\)
\(\mathsf{5x \leq 15}\)
\(\large\textsf{DIVIDE 5 to BOTH SIDES:}\)
\(\mathsf{\dfrac{5x}{5}\leq\dfrac{15}{5}}\)
\(\large\textsf{CANCEL out: \boxed{\bf \dfrac{5}{5}} because it give you 1}\)
\(\large\textsf{KEEP: \boxed{\bf \dfrac{15}{5}} because it help us know what is being compared to the x-value}\)
\(\mathsf{x \leq \dfrac{15}{5}}\)
\(\mathsf{x \leq 3}\)
\(\large\textsf{You have a(n) \boxed{\mathsf{closed}} shaded circle to your \boxed{\mathsf{left}}}\)
\(\huge\text{Therefore, your answer should be:}\\\\\huge\boxed{\mathsf{x \leq 3}}\huge\checkmark\\\\\huge\boxed{\large\huge{\textsf{You have a(n) \boxed{\mathsf{closed}} shaded circle to your \boxed{\mathsf{left}}}}}\huge\checkmark\)
\(\huge\text{Good luck on your assignment \& enjoy your day!}\)
Container A has 300 liters of water, and is being filled at a rate of 6 liters per minute. Container B has 900 liters of water, and is being drained at 2 liters per minute. How many minutes, m, will it take for the two containers to have the same amount of water?
It will take 150 minutes for the two containers to have the same amount of water.
To find the number of minutes it will take for the two containers to have the same amount of water, we need to use the following formula:
m = |A - B| / (a - b)
where m is the number of minutes, A is the initial amount of water in Container A, B is the initial amount of water in Container B, a is the rate at which water is being added to Container A, and b is the rate at which water is being drained from Container B.
In this case, the initial amount of water in Container A is 300 liters, the initial amount of water in Container B is 900 liters, the rate at which water is being added to Container A is 6 liters per minute, and the rate at which water is being drained from Container B is 2 liters per minute. Substituting these values into the formula, we get:
m = |300 - 900| / (6 - 2)
m = |-600| / 4
m = 600 / 4
m = 150 minutes
Therefore, it will take 150 minutes for the two containers to have the same amount of water.
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(50 points) please help! no links, brainliest, extra points.
I understand if you need points, you can go to my old questions and answer them for points, please only answer if your 100% sure you're correct. I've redone this over 20 times, asked over 50, and failed all those times. thank uu.
The dot plot below shows the number of vacations taken by the sixth-grade students at Walker Junior High one year.
What is the interquartile range of the data set shown?
A. 4
B. 3
C. 1
D. 2
Answer:
B. 3
Step-by-step explanation:
The 3q - 1q = IQR
3q= 4,
1q= 1
4-1 = 3
Answer:
2
Step-by-step explanation:
Please help :solve the inequality: 6p-20>-36+10p
Answer:
c.p<-1
Step-by-step explanation:
im good at math
if you charge too ______, customers will assume your quality is_____.
Answer:
Cheap; Bad
Step-by-step explanation:
According to the experience in the real world.
Select the correct answer.
Which function has an inverse function?
Answer:
d
Step-by-step explanation:
so the first part is multiplication and the second part is division bc it's a fraction hope this helps <3
Graph the set of points. Which model is most appropriate for the set?
(-2,3), (-1,-3), (0, -5), (1, -3), (2,3)
Model B is the most appropriate for the set (-2,3), (-1,-3), (0, -5), (1, -3), (2,3).
What is Linear, Quadratic, & Exponential Models?A mathematical model that may be expressed as a series of quadratic equations or as a quadratic equation, such as Y = aX2 + bX + c. When a quadratic equation is graphed, the connection between the variables is represented by a parabola.The y-values in a linear connection differ by an equal amount. The y-values have identical ratios in an exponential relationship.First differences are constant in linear functions. Second differences in quadratic functions are always the same. A constant ratio characterises exponential functions.Based on an equation like: where Y = deterioration, T = time, and A and B = parameters to be calculated by the regression approach based on historical data, the exponential model represents the degradation failure process.Learn more about Linear, Quadratic, & Exponential Models refer to :
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Simplify the following expression:
√-36+√-100+ 7
O A. 7+ 16i
OB. 7+√136i
O C. 16
C. 16 - 7i
O D. 23 + 0i
What is the constant in 12r + r/2-19
Answer:
constant is - 19
Step-by-step explanation:
the constant is the term in an expression with no variable attached to it.
12r + \(\frac{r}{2}\) - 19
the only term without the variable r attached to it is - 19
then the constant term is - 19
raiz cuadrada de -200
The following transactions were completed by Winklevoss Inc., whose fiscal year is the calendar year:
Year 1
July 1 Issued $71,900,000 of 20-year, 6% callable bonds dated July 1, Year 1, at a market (effective) rate of 7%, receiving cash of $64,222,669. Interest is payable semiannually on December 31 and June 30.
Oct. 1 Borrowed $420,000 by issuing a six-year, 5% installment note to Nicks Bank. The note requires annual payments of $82,747, with the first payment occurring on September 30, Year 2.
Dec. 31 Accrued $5,250 of interest on the installment note. The interest is payable on the date of the next installment note payment.
31 Paid the semiannual interest on the bonds. The bond discount amortization of $191,933 is combined with the semiannual interest payment.
Year 2
June 30 Paid the semiannual interest on the bonds. The bond discount amortization of $191,933 is combined with the semiannual interest payment.
Sept. 30 Paid the annual payment on the note, which consisted of interest of $21,000 and principal of $61,747.
Dec. 31 Accrued $4,478 of interest on the installment note. The interest is payable on the date of the next installment note payment.
31 Paid the semiannual interest on the bonds. The bond discount amortization of $191,933 is combined with the semiannual interest payment.
Year 3
June 30 Recorded the redemption of the bonds, which were called at 98. The balance in the bond discount account is $6,909,599 after payment of interest and amortization of discount have been recorded. Record the redemption only.
Sept. 30 Paid the second annual payment on the note, which consisted of interest of $17,913 and principal of $64,834.
Required:
1. Journalize the entries to record the foregoing transactions. Round all amounts to the nearest dollar. Refer to the Chart of Accounts for exact wording of account titles.
2. Indicate the amount of the interest expense in (a) Year 1 and (b) Year 2.
3. Determine the carrying amount of the bonds as of December 31, Year 2.
1. The journal entries recording the transactions for Winkelvoss Inc. are as follows:
Journal Entries:Year 1:
July 1: Debit Cash $64,222,669
Debit Bonds Discount $7,677,331
Credit Bonds Payable $71,900,000
Oct. 1: Debit Cash $420,000
Credit Bank Notes Payable $420,000
Dec. 31 Debit Interest Expense $5,250
Credit Installment Note Interest Payable $5,250
Dec. 31 Debit Interest Expense $2,708,433
Credit Cash $2,516,500
Credit Bond Amortization $191,933
Year 2:
June 30 Debit Interest Expense $2,516,500
Credit Cash $2,324,567
Credit Bond Amortization $191,933
Sept. 30 Debit Interest Expense $15,750
Debit Installment Note Interest Payable $5,250
Debit Notes Payable $61,747
Credit Cash $82,747
Dec. 31 Debit Interest Expense $4,478
Credit Installment Note Interest Payable $4,478
Dec. 31 Debit Interest Expense $2,708,433
Credit Cash $2,516,500
Credit Bond Amortization $191,933
Year 3:
June 30 Debit Bonds Payable $64,990,401
Debit Bond Redemption Premium $5,471,599
Credit Cash $70,462,000
Sept. 30 Debit Interest Expense $13,435
Debit Installment Note Interest Payable $4,478
Debit Notes Payable $64,834
Credit Cash $82,747
2. The amounts of the interest expense in Year 1 and Year 2 are as follows:
Year 1 Year 2
Total interest $2,713,683 $2,72,8661
3. The bond's carrying amount as of December 31, Year 2, is $64,798,468.
Transaction Analysis:Year 1:
July 1: Cash $64,222,669 Bonds Discount $7,677,331 Bonds Payable $71,900,000
Oct. 1: Cash $420,000 Bank Notes Payable $420,000
Dec. 31 Interest Expense $5,250 Installment Note Interest Payable $5,250
Dec. 31 Interest Expense $2,708,433 Cash $2,516,500 Bond Amortization $191,933
Year 2:
June 30 Interest Expense $2,516,500 Cash $2,324,567 Bond Amortization $191,933
Sept. 30 Interest Expense $15,750 Installment Note Interest Payable $5,250 Notes Payable $61,747 Cash $82,747
Dec. 31 Interest Expense $4,478 Installment Note Interest Payable $4,478
Dec. 31 Interest Expense $2,708,433 Cash $2,516,500 Bond Amortization $191,933
Year 3:
June 30: Bonds Payable $64,990,401 Bond Redemption Premium $5,471,599 Cash $70,462,000
Sept. 30 Interest Expense $13,435 Installment Note Interest Payable $4,478 Notes Payable $64,834 Cash $82,747
Interest Expenses:Year 1 Year 2
Bonds Payable $2,708,433 $2,708,433
Notes Payable $5,250 $15,750
Notes Payable $4,478
Total interest $2,713,683 $2,72,8661
Carrying amount of the bonds December 31, Year 2:July 1: $64,222,669
Dec. 31 Bond Amortization $191,933
June 30 Bond Amortization $191,933
Dec. 31 Bond Amortization $191,933
Dec. 31 Year 2 Carrying Amont = $64,798,468
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An experiment was used to test a new migraine medicine. Each participant took either the new medicine or a placebo
then waited for one hour to see if the headache went away or remained. The results are compiled in the contingency
table below. Use the table to answer the questions.
Went Away| Medicine| Placebo
Remained|. 120. |. 68
18. | 44
Your answers should be exact numerical values.
There were
participants whose headache remained.
The probability of randomly selecting an individual whose headache remained is
There were
participants whose headache remained and took a placebo.
The probability of randomly selecting an individual whose headache remained and took a placebo is
1) Number of participants whose headache remained is: 62
2) The probability of randomly selecting an individual whose headache remained is: 0.4133
3) The probability of randomly selecting an individual whose headache remained and took a placebo is: 0.2933
How to find the probability of random selection?From the table, we have the parameters as:
Number of participants that took medicine and headache went away = 120
Number of participants that took placebo and headache went away = 68
Number of participants that took and headache remained = 18
Number of participants that took placebo and headache remained = 44
1) Number of participants whose headache remained = 18 + 44 = 62
2) The probability of randomly selecting an individual whose headache remained is:
62/(62 + 120 + 68)
= 62/150
= 0.4133
3) The probability of randomly selecting an individual whose headache remained and took a placebo is:
44/150 = 0.2933
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Question 51 ptsThe point (-4,-2) lies on a circle. What is the length of the radius of this circle if thecenter is located at (-8, -10)?O 4√5O 2√54080PreviousNext ▸
Given,
The coordinates of the point on the circle is (-4, -2).
The coordinates of the center of the circle is (-8, -10).
Reuired
The length of the center of the circle.
By using the distance formula, the radius of the circle can be calculated.
The distance formula is,
\(Distance=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\)Substituting the value of the coordinates of the points,
\(\begin{gathered} Distance=\sqrt{(-10-(-2))^2+(-8-(-4))^2} \\ =\sqrt{(-10+2)^2+(-8+4)^2} \\ =\sqrt{(-8)^2+(-4)^2} \\ =\sqrt{64+16} \\ =\sqrt{80} \\ =\sqrt{4\times4\times5} \\ =4\sqrt[]{5} \end{gathered}\)Hence,
The price of a desk was originally $80. The desk is now on sale for 16% off. What is the sale price of the desk? Use y to represent the sale price of the desk and write an equation to represent the problem.
Just write me the equation
Which of the following sets of ordered pairs represents a function?
{(10,5), (10,-5), (5,10), (5,-10)}
{(10,5), (-10,-5), (5,10), (-5,-10)}
{(-6,-1), (13,8), (1,6), (1,-10)}
{(3,5), (-17,-5), (3,-5), (-17,5)}
The sets of ordered pairs that represents a function are {(10,5), (-10,-5), (5,10), (-5,-10)} and {(-6,-1), (13,8), (1,6), (1,-10)}
Ordered pair of a functionOrdered pairs are written as a coordinate (x, y). For the given x coordinate points to be a function, the value of its x coordinates (domain) must not be repeated.
From the given ordered pairs, {(10,5), (10,-5), (5,10), (5,-10)} and {(3,5), (-17,-5), (3,-5), (-17,5)} are not functions since there is repetition in their domains.
Hence the sets of ordered pairs that represents a function are {(10,5), (-10,-5), (5,10), (-5,-10)} and {(-6,-1), (13,8), (1,6), (1,-10)}
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What is the surface of a area of the square 10m 10m 8m
Answer: The area is (800)
Step-by-step explanation: (10x 10= 100)
(100 x 8= 800)
FINAL ANSWER: 800m
~ i really hope this is correct, have a gr8 day/night my friend!~
the quotient of h and 26 is -52
Answer: h= -1352
Step-by-step explanation: 1. Translate the expression into algebra. The quotient of h and 26 =-52 is h/26=-52
2. multiply 26 to both sides.
3. h= -1352
y is inversely proportional to X. when y=4,X=16 work out X when y=8
Answer:
\(x = 8\)
x = 8 when y = 8
Step-by-step explanation:
explanation is in the image
The solution is 8
The value of x is from the proportion equation is x = 8
What is Proportion?
The proportion formula is used to depict if two ratios or fractions are equal. The proportion formula can be given as a: b::c : d = a/b = c/d where a and d are the extreme terms and b and c are the mean terms.
The proportional equation is given as y ∝ x
And , y = kx where k is the proportionality constant
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Given data ,
Let the proportionality constant be represented as k
Y is inversely proportional to X
So , y ∝ 1/x
y = k/x be equation (1)
where k is the proportionality constant
k = yx
when y = 4 , x = 16
Substitute the values in the equation , we get
k = 4 x 16
k = 64
Now , when y = 8
x = k/y
Substitute the value of y in the equation , we get
x = 64 / 8
x = 8
Therefore , the value of x is 8
Hence , the value of x from the equation is x = 8
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The locker's combination code
consists of one letter and 3 digits.
How many possible different codes
exist, if the letter can be A or C and
must come first, and the digits can
be repeated?
The number of different codes as the letters A or C must come first and digits can be repeated is 2000
Permutation and Combination:Permutations and combinations are a subset of the study of finite, discrete structures that are known as combinatorics. Combinations include the selection of items without respect to order, whereas permutations are precise selections of elements within a set where the order of the elements is significant.
Here we have,
The locker combination code consists of one letter and 3 digits
Here we need to find the number of different codes If the letter A or C must come first and digits can be repeated.
Given that the first letters are A and C
Here number of ways that A and C can be chosen at first = 2
As we know Number of digits = 10 [ including 0, 0 to 9 ]
Number of arrangements that can be chosen from 10 digits
= 10 × 10 ×10 [ Since repetition is allowed ]
Therefore,
The possible number of different codes = 2 × 10 × 10 ×10 = 2000
Therefore
The number of different codes as the letters A or C must come first and digits can be repeated is 2000
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Plz help I need help
Answer:
drop 180 feet
Step-by-step explanation:
(110-65)+135=180
What is the vertex of the graph of y = 2(x + 5)2 - 2?
Answer:
The vertex is (-5, -2)
Step-by-step explanation:
y = 2(x + 5)^2 - 2
The vertex form of a parabola is
y =a(x-h)^2 +k where (h,k) is the vertex
y = 2(x - -5)^2 - 2
The vertex is (-5, -2)
Find the HCF of 2, 4 and 4/5.
(A) 1/20 (B) 1/40 (C) 20 (D) 15
Answer:
1/20
Step-by-step explanation:
You can find the HCF (Highest Common Factor), also known as GCF, by dividing the numbers by the list of answers. And, if they all come out as whole numbers, then the answer you chose will be the answer. But, if there is another answer that also comes out as whole numbers for all of them, we choose the biggest one (HCF):
2 ÷ 1/20 = 40
4 ÷ 1/20 = 80
4/5 ÷ 1/20 = 16
So, 1/20 is definitely one of the answers, but we should check the other ones too:
2 ÷ 1/40 = 80
4 ÷ 1/40 = 160
4/5 ÷ 1/40 = 32
So, even though we also got whole numbers for this one, it isn't the answer because 1/20 is bigger than 1/40 so far. Let's try the last two answers:
2 ÷ 20 = 0.1
So, we already got our answer. We don't need to check the rest of the numbers, because the first one is already not a whole number. Let's try the final answer:
2 ÷ 15 = 0.13333333
This is not the right one either. So, our answer is 1/20 because it is the biggest one that came out as all whole numbers.
May I have Brainliest please? My next rank will be the highest one: A GENIUS! Please help me on this journey to become top of the ranks! I only need 3 more brainliest to become a genius! I would really appreciate it, and it would make my day! Thank you so much, and have a wonderful rest of your day!
solve the following wquations for y.
Answer:
first equation: (-3x/2)+6
second equation: (13/2)-(5x/2)
Step-by-step explanation:
What is the rise and the run please help
Answer:
-1
Step-by-step explanation:
Rise=2
Run=-2
2/-2=
-1
please help will mark brainlyiest
-3.3 x -6/7
Answer:
the answer is 2.828 or 99/35
Step-by-step explanation:
we convert -3.3 to fraction
-33/10*-6/7
we multiply
198/70
2.8285
2.83
Least multiple of 5 and 25
Answer:
25
Step-by-step explanation:
25 is a multiple of 5, so is the least multiple of both 5 and 25.
Answer:
Hey there!
That would be 25.
Hope this helps :)
What type of association does the graph show?
A. positive nonlinear
B. positive linear
C. negative nonlinear
D. negative linear
Answer:
B. Positive linear
Step-by-step explanation:
First, this graph is a linear graph because a linear graph is a straight line. The graph in the diagram is also a straight line, so it is linear.
Also, notice how as x increases, y increases. This means that the graph is positive
You will purchase 700 frozen treat's the cost to you should be at most 400 your goal is to make a profit of at least $800. Explain to Omar how your decision meets each of the criteria. Include the number of each type of treat in your explanation
The decision meets each of the criteria by: Buying 500 popsicles at $0.50 each and 200 ice cream sandwiches at $1.50 each enables the purchase of 700 frozen delights within the $400 budget and satisfies the objective of producing at least $800 in profit.
How did your decision meets each of the criteria?I have made the decision to buy 500 popsicles at $0.50 each and 200 ice cream sandwiches at $1.50 each in order to fulfil the requirement of buying 700 frozen delights at a price of no more than $400.
Cost of purchasing 500 popsicles = (500 * $0.50)
Cost of purchasing 500 popsicles = $250
Cost of purchasing 200 ice cream sandwiches =(200 * $1.50)
Cost of purchasing 200 ice cream sandwiches = $300
So, Total cost of purchasing all 700 frozen treats is $550 ($250 + $300) which is within the budget of $400.
I intend to sell the popsicles for $1.50 each and the ice cream sandwiches for $3.00 each in order to meet the requirement of turning a profit of at least $800. This would bring in $1350 in income for the ice cream sandwiches and $750 for the popsicles (500 * $1.50 and 200 * $3.00 respectively).
The objective of producing a profit of at least $800 is met after deducting the expense of buying the frozen treats from the overall income.
Net profit =($1350 - $550)
Net profit = $800
Therefore purchasing 500 popsicles at $0.50 each and 200 ice cream sandwiches at $1.50 each satisfies the objective of producing at least $800 in profit.
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