Using your own words whats the difference between weather and climate ​

To calculate the pH of the solution obtained by mixing HCl and NaOH, we need to consider the neutralization reaction between the two compounds. The reaction between HCl (hydrochloric acid) and NaOH (sodium hydroxide) produces water (H₂O) and forms a salt (NaCl).

Given:

Volume of HCl solution (V₁) = 40 cm³

Concentration of HCl solution (C₁) = 0.2 M

Volume of NaOH solution (V₂) = 30 cm³

Concentration of NaOH solution (C₂) = 0.1 M

1. Determine the moles of HCl and NaOH used:

Moles of HCl = Concentration (C₁) × Volume (V₁)

Moles of HCl = 0.2 M × 0.04 L (converting cm³ to L)

Moles of HCl = 0.008 mol

Moles of NaOH = Concentration (C₂) × Volume (V₂)

Moles of NaOH = 0.1 M × 0.03 L (converting cm³ to L)

Moles of NaOH = 0.003 mol

2. Determine the limiting reagent:

The stoichiometry of the reaction between HCl and NaOH is 1:1, meaning that they react in a 1:1 ratio. Whichever reactant is present in a smaller amount will be the limiting reagent.

In this case, NaOH is present in a smaller amount (0.003 mol), which means it will be fully consumed during the reaction.

3. Determine the excess reagent and its remaining moles:

Since NaOH is the limiting reagent, we need to find the remaining moles of HCl.

Moles of HCl remaining = Moles of HCl initially - Moles of NaOH reacted

Moles of HCl remaining = 0.008 mol - 0.003 mol

Moles of HCl remaining = 0.005 mol

4. Calculate the concentration of HCl in the resulting solution:

Volume of resulting solution = Volume of HCl solution + Volume of NaOH solution

Volume of resulting solution = 0.04 L + 0.03 L

Volume of resulting solution = 0.07 L

Concentration of HCl in the resulting solution = Moles of HCl remaining / Volume of resulting solution

Concentration of HCl in the resulting solution = 0.005 mol / 0.07 L

Concentration of HCl in the resulting solution ≈ 0.071 M

5. Calculate the pH of the resulting solution:

pH = -log[H⁺]

pH = -log(0.071)

Using logarithm properties, we can determine the pH value:

pH ≈ -log(0.071)

pH ≈ -(-1.147)

pH ≈ 1.147

Therefore, the pH of the solution obtained by mixing 40 cm³ of 0.2 M HCl and 30 cm³ of 0.1 M NaOH is approximately 1.147.

Answer:

108.81 K

Explanation:

First convert 17 °C to Kelvin:

Assuming ideal behaviour, we can solve this problem by using the combined gas law, which states that at constant composition:

Where in this case:

We input the data:

And solve for T₂:

Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:

Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)

The molar mass of MgCl₂ is 95.21 g/mol.

First, we need to calculate the number of moles of MgCl₂ formed:

Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂

Moles of MgCl₂ = 34.52 g / 95.21 g/mol

Moles of MgCl₂ = 0.363 mol

According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:

Moles of HCl = 2 * Moles of MgCl₂

Moles of HCl = 2 * 0.363 mol

Moles of HCl = 0.726 mol

To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules of HCl = Moles of HCl * Avogadro's number

Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol

Number of molecules of HCl = 4.37 x 10^23 molecules

Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

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We can produce more products by;

A. Increasing the concentration of H₂ gas in the reaction vessel

B. Decreasing the temperature in the reaction vessel

C. Removing the H₂O from the reaction vessel as it forms

Water is created through an exothermic process. Heat energy is released when hydrogen gas (H2) and oxygen gas (O2) mix to make water (H2O). An exothermic reaction is characterized by this energy release.

The reaction's overall energy change is negative, which shows that energy is released. The reaction is exothermic because the extra energy is released as heat into the environment.

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Missing parts;

Water can be made using the reversible reaction shown. Which change would

keep this reaction from shifting to form more of the product?

2H₂+022H₂O + energy

A. Increasing the concentration of H₂ gas in the reaction vessel

B. Decreasing the temperature in the reaction vessel

C. Removing the H₂O from the reaction vessel as it forms

D. Increasing the temperature in the reaction vessel

Answer:

40,113 years

Explanation:

To find the age of the sample, you need to use the half-life formula:

\(N(t)=N_0(\frac{1}{2})^{t/h\)

In this formula:

------> N(t) = current mass (g)

------> N₀ = initial mass (g)

------> t = time passed (yrs)

------> h = half-life (yrs)

You can plug the given values into the equation and rearrange the formula to find "t".

N(t) = 0.781 g                       t = ? yrs

N₀ = 100 g                           h = 5730 yrs

\(N(t)=N_0(\frac{1}{2})^{t/h\)                                           <----- Half-life formula

\(0.781=100(\frac{1}{2})^{t/5730}\)                                     <----- Insert values

\(0.00781=(\frac{1}{2})^{t/5730}\)                                       <----- Divide both sides by 100

\(log_{1/2}(0.00781)=log_{1/2}((\frac{1}{2})^ {t/5730})\)               <----- Take \(log_{1/2}\) of both sides

\(7.00 = \frac{t}{5730}\)                                                   <----- Solve \(log_{1/2}\)

\(40,113 = t\)                                                   <----- Multiply both sides by 5730

The given sample is 40,113 years .

Half-life, in radioactivity, is the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay.

Half-life formula,

\(\rm N(t)\;=N_0(\dfrac{1}{2})^\frac{t}{t1/2}\)   .......(1)

where,

N(t)=current mass

N₀=initial mass

t=time period

h=half -life

Given,

N(t)=0.781g, t=? yrs, N₀=100g, h=5730 years

\(\rm N(t)\;=N_0(\dfrac{1}{2})^\frac{t}{t1/2}\)

put the values, in ......(1)

0.781=100(1/2) \(t/5730\\\)

log₁/₂(0.00781)=log₁/₂ ( 1/2)\(t/5730\)

7=t/5730

40,113=t

Hence, the given sample is 40,113 years .

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Answer: So you could for example say, “IF I through my clothes into the closet. THEN the floor will be visible” I capatlized if and then because you need them in a hypothesis.

Explanation:

Answer:

Intertidal zone

Neritic zone

Open-ocean zone

Note: the correct questions are found below;

In which zone do you find marshes and mangrove forests?

In which zone are plankton plentiful, providing plenty of food for the fish that live there?

In which zone would you find very little plant or animal life compared to other zones?

Explanation:

The intertidal zone, sometimes called the littoral zone, is the area of the marine shoreline that is exposed to air at low tide, and covered with seawater when the tide is high. Intertidal zonation refers to the tendency of plants and animals to form distinct communities between the high and low tide lines. Some microclimates in the littoral zone are moderated by local features and larger plants such as mangroves.

The neritic zone is the region of shallow water (200 meters depth) above the continental shelf where light penetrates to the sea floor.

Due to the abundant supply of sunlight and nutrients such as plankton in this zone, it is the most productive ocean zone supporting the vast majority of marine life.

The open oceans or pelagic ecosystems are the areas away from the coastal boundaries and above the seabed. It encompasses the entire water column and lies beyond the edge of the continental shelf. It extends from the tropics to the polar regions and from the sea surface to the abyssal depths.

Answer:

Intertidal zone

Neritic zone

Open-ocean zone

Explanation:

Answer:

3.4 x 10²⁵ atoms Ag

Explanation:

To find the amount of silver (Ag) atoms, you need to use Avogadro's number to convert between moles and atoms. Make sure to arrange the ratio in a way that allows for the cancellation of moles. The final answer should have 2 sig figs to correlate with the number of sig figs in the given value (56 = 2 sig figs).

Avogadro's number:

6.022 x 10²³ atoms = 1 mole

56 moles Ag          6.022 x 10²³ atoms
--------------------  x  ----------------------------------  =  3.4 x 10²⁵ atoms Ag
                                         1 mole

Answer:

2.21 grams

Explanation:

The first thing you need to do is find the chemical formula for sodium chloride which is NaCl (Molar mass: 58.44 g/mol).

The next the thing to do is to convert the mL to L by dividing by 1000 which will give us 0.158 L.

Now we look at the molarity formula M = n/L, plug in the molarity for M and the liters for L. 0.239 M (mol/L) = n/0.158 L.

Solve for n to get the number of moles of NaCl in the solution. You should get 0.037762 moles.

Then we have to multiply this by the molar mass of NaCl, (0.037762 mol)*(58.44 g/mol).

Moles cancel and when we round to sig figs we are left with 2.21 grams.

Hope this helps.

As much as 3.350 g of carbon dioxide can dissolve in 1.000 L of water at 0∘C and 1.000 atm. At 0∘C and 5.975atm,16.75 g of CO2 can dissolve in 1.000 L of water.

The ideal gas equation is represented as: PV = nRT. In this equation, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the total amount of ideal gas that is measured in terms of moles, R is the universal gas constant, and T is the temperature.

The mass of CO2 is 3.350 g

moles = 3.350 / 44

= 0.07612 mol

volume V1 = 1.00 L

temperature = 273 K

pressure = 1 atm

By an ideal gas law

P V = n R T

here volume and temperature are constant.

Therefore,

P1 / n1 = P2 / n2

1.00 / 0.0761 = 5.00 / n2

n2 = 0.3806

moles of CO2 = 0.3806

mass of CO2 dissolve

= 16.75 g

Thus, At 0∘C and 5.975atm,16.75 g of CO2 can dissolve in 1.000 L of water.

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Answer:

salt water

Explanation:

i learned from makeing slime

Answer:

C: Chlorine

Explanation:

The parts of the Bunsen burner are;

P is the air hole and it should be closed before you light the Bunsen burner. This is to ensure that too much air does not enter.

Lighting a Bunsen burner without closing the air hole can be dangerous because it can cause the flame to become unstable and flare up, potentially leading to a fire or explosion. The air hole is used to regulate the amount of air that enters the burner and mixes with the gas. When the air hole is open, too much air can enter the burner and cause the flame to become oxygen-rich, which makes it hotter and more unstable.

In addition, an unstable flame can also release harmful byproducts such as carbon monoxide, a toxic gas that can cause headaches, dizziness, and nausea.

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The new pressure of the gas is 203 psi.

Boyle's law is a gas law that states that the pressure of a gas is inversely proportional to its volume at a constant temperature. The law can be expressed mathematically as:

P * V = k

where P is the pressure of the gas, V is its volume, and k is a constant. This law states that as the volume of a gas increases, its pressure decreases, and as its volume decreases, its pressure increases.

We know that;

P1V1 = P2V2

P1 = initial pressure

P2 = final pressure

V1 = initial temperature

V2 = final temperature

P1 = 29

V1 = V

P2 = ?

V2 = P/7

Then;

P2 = P1V1/V2

P2 = 29 * V/V/7

P2 = 203 psi

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Answer: :)

The temperature of a gas is directly proportional to the average kinetic energy of the particles of the gas. But the total kinetic energy of the molecules of a gas is a measure of the internal energy or thermal energy of the gas.

Explanation:

The molality of the solution is 0.00037 m.

The term concentration refers to the amount of solute in a solution.

We have the following information;

Molarity = 0.335 M

Density =  1.0432 g/mL

Temperature = 20 o C

The molality of the solution is obtained from;

m = 0.335 M ×  1.0432 g/mL/ 1000(1.0432 g/mL) - 0.335 M (342 g/mol)

m = 0.344/1043.2 - 114.57

m =  0.344/928.63

m = 0.00037 m

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The mass of Fluorine in grams in the second sample is 2066 g. The concept law of definite proportions is used here to obtain the mass of Fluorine in the second sample.

This law was stated by a French chemist, Louis Proust. It states that 'a chemical compound always contains the same elements combined together in the same proportion by mass'.

The mass of Mg in sample 1 is 1.66 kg and that of F is 2.56 kg. The mass of Mg in sample 2 is 1.34 kg and we have to find out the mass of F in second sample.

The mass of Fluorine in sample 2 can be obtained by using the mass ratio of the elements in sample 1.

In sample 1:

Mass of magnesium ÷ Mass of Fluorine = 1.66 kg ÷ 2.56 kg

In sample 2:

By using dimensional analysis,

Mass of Fluorine = 2.56 kg Fluorine ÷ 1.66 kg Magnesium × 1.34 kg Magnesium

Therefore the mass of Fluorine = 2.066 kg

The mass in kilogram can be converted into grams as:

Mass of Fluorine = 2.066 kg × 1000 g ÷ 1 kg = 2066 g

Thus the mass of Fluorine in the second sample is 2066 g.

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Answer:

c is the

Explanation:

Answer:

Explanation:

Here, we want to calculate the heat energy lost by the water

Mathematically, we can get that using the following mathematical relation:

where Q is the amount of heat

C is the specific heat capacity of water

delta theta is the temperature change which is the difference between the final and initial temperature

The mass of 53 mL of water is 0.0534 kg which is 53.4 g

Substituting the values, we have it that:

Since it was cooled down, heat is lost which indicates a negative value

Answer:

when placed in water, a sodium pellet catches on fire as hydrogen gas is liberated and sodium hydroxide forms. chemical change = fire is a sign of chemical reaction.

Explanation:

When placed in water the sodium pellets catch the fire and liberate the hydrogen gas. On mixing with water solid sodium forms a colorless basic solution.

Sodium is a soft metal. It is a very reactive element with a low melting point. Sodium reacts very quickly with water, snow, and ice to produce sodium hydroxide and hydrogen. It is an alkali metal and the sixth most abundant metal on earth. It has a silvery white color.

It has a strong metallic luster. On reacting with oxygen it produces sodium oxide which on reacting with the water produces sodium hydroxide.

It is used to improve the structure of certain alloys and soaps. It is also used in the purification of metals. Sodium is also present in sodium chloride, an important compound found in the environment.

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Answer:

snovd vosb r

Explanation:

Explanation:

1 miole of Fe2O is 6.22 × 10^-23

5mole of Fe2O = 5×6.22×10^-23

=31.1×10^-23

Mass of 5 moles  of \(Fe_2O\) is 636 g.

Formula for the calculation of mass is as follows:-

\(Number\ of\ mole=Mass/Molar mass\).......(1)

The molar mass of \(Fe_2O\)is \(2\times55.6\ g+16\ g=127.2 \g\)

So ,the mass of 5 moles  of \(Fe_2O\)is as follows:-

\(5\ mol=Mass/127.2\ g/mol\\5\ mol/times127.2\ g/mol=Mass\\636\ g=Mass\)

Hence, the mass of 5 moles  of \(Fe_2O\) is 636 g.

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Answer:

compound

Explanation:

The mass of FeSO4*7H2O in the sample is 1.21 grams.

Calculate moles of Fe2O3

moles of Fe2O3 = mass of Fe2O3 / Molar mass of Fe2O3

moles of Fe2O3 = 0.348 grams / 159.69 g/mole = 0.00218 moles

Calculate moles of Fe

4 Fe + 3O2 → 2Fe2O3

For 4 moles of Fe consumed there is 2 moles of Fe2O3 produced

This means it has a ratio 2:1

So 0.00218 moles of Fe2O3 produced , there is 2*0.00218 = 0.00436 moles of Fe consumed

Calculate moles of FeSO4*7H2O

Fe + H2SO4 + 7H2O → FeSO4*7H20 + H2

For 1 mole of Fe consumed there is 1 mole of FeSO4*7H2O produced

This means for 0.00436 moles there is 0.00436 moles of Fe2SO4*H2O produced

Calculate the mass of FeSO4*7H2O in the sample

mass of FeSO4*7H2O = 0.00436 moles * 278.01 g/mole = 1.212 g

The mass of FeSO4*7H2O in the sample is 1.21 grams.

Complete question: A powder contains FeSO4⋅7H2O (molar mass=278.01 g/mol), among other components. A 3.930 g sample of the powder was dissolved in HNO3 and heated to convert all iron to Fe3+. The addition of NH3 precipitated Fe2O3⋅xH2O, which was subsequently ignited to produce 0.348 g Fe2O3. What was the mass of FeSO4⋅7H2O in the 3.930 g sample?

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Answer:

CHARLES' LAW

given:

= 600 mL = 0.6 L

= 27 °C = 300.15 L

= 77 °C = 350.15 L

conversion:

= 600 mL (1 L / 1000 mL)

= 0.6 L

= 27 °C + 273.15 K

= 300.15 K

= 77 °C + 273.15 K

= 350.15 K

solution:

= ( × ) ÷

= (0.6 L × 350.15 K) ÷ 300.15 K

= 0.7 L

The balanced nuclear equation for the β emission of the following isotopes is seen below:

92                 92                0

Sr            ⇒ Y         +   e

38                  39             -1

This is also known as beta decay in which a beta ray is emitted from an atomic nucleus.

The element formed during the beta emission of strontium is referred to as Yttrium.

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Answer:

caesium

Explanation:

because it's lesssssssss

Answer:

The total pressure of a mixture of gases can be defined as the sum of the pressures of each individual gas: Ptotal=P1+P2+… +Pn. + P n . The partial pressure of an individual gas is equal to the total pressure multiplied by the mole fraction of that gas.

Explanation:

hope this helps have a wonderfull day!

The mass of sulfur dioxide required is approximately 6.36 grams.

To determine the number of grams of sulfur dioxide (SO2) required to exert a pressure of 0.705 atm in a 2.50L tank at 0 °C, we can use the ideal gas law equation: PV = nRT.

First, we need to convert the temperature from Celsius to Kelvin by adding 273.15, so the temperature becomes 273.15 K. The ideal gas constant (R) is 0.0821 L·atm/(mol·K).Rearranging the ideal gas law equation to solve for the number of moles (n), we get n = PV / RT.

Plugging in the given values, n = (0.705 atm) * (2.50 L) / [(0.0821 L·atm/(mol·K)) * (273.15 K)]. Calculating this expression, we find that n is approximately 0.0993 moles.The molar mass of sulfur dioxide is 64.06 g/mol (32.06 g/mol for sulfur + 2 * 16.00 g/mol for oxygen).

Finally, we can calculate the mass of sulfur dioxide using the formula: mass = n * molar mass = 0.0993 moles * 64.06 g/mol. Thus, the mass of sulfur dioxide required is approximately 6.36 grams.

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Answer:

May be its correct bro

Explanation:

take it easy