Using two to three sentences, summarize what you investigated and observed in this lab.
You completed three terra forming trials. Describe the how the sun's mass affects planets in a solar system. Use data you recorded to support your conclusions.
In this simulation, the masses of the planets were all the same. Do you think if the masses of the planets were different, it would affect the results? Why or why not?
How does this simulation demonstrate the law of universal gravitation?
It is the year 2085, and the world population has grown at an alarming rate. As a space explorer, you have been sent on a terraforming mission into space. Your mission to search for a habitable planet for humans to colonize in addition to planet Earth. You found a planet you believe would be habitable, and now need to report back your findings. Describe the new planet, and why it would be perfect for maintaining human life.

Answer: A red light is reflected

Explanation:

40,000 kg

density=mass/volume

then mass=density×volume

= 8000× 5

=40,000 kg

When two rope segments pull up on the load in the single movable pulley, the optimal mechanical advantage is 2. This sort of pulley does not change the direction of the applied force, but it does increase it by a factor of two.

There are two methods for calculating a pulley system's mechanical advantage.

The mechanical advantage may be calculated simply by counting the number of falls (or active lifting ropes) that are really attached to the load. You may also split the effort distance by the load distance.

Assuming an ideal rope and pulley system with a mechanical advantage of  \(2.00\) , the output load that can be lifted with an input force of \(200 N\) can be calculated using the formula:

Output force = Input force x Mechanical advantage

Where the mechanical advantage is given as \(2.00\)  .

Thus, the output force is:

Output force \(= 200 N \times 2.00 = 400 N\)

Therefore, with an input force of \(200 N\)  , the rope and pulley system can lift an output load of up to \(400 N\) .

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During each section of the cooling curve, different types of energy changes occur. Kinetic energy decreases during the solid-to-liquid and liquid-to-gas phase transitions, while potential energy decreases during the gas-to-liquid and liquid-to-solid phase transitions.

A cooling curve is a graph of temperature versus time that depicts the cooling of a substance. The curve is divided into four distinct sections: (i) from solid to liquid, (ii) from liquid to gas, (iii) from gas to liquid, and (iv) from liquid to solid. During each section of the cooling curve, energy changes occur.

Types of energy changes that occur during each section of the cooling curve: Solid to liquid: During this phase transition, the temperature of the substance remains constant, while the potential energy increases.Liquid to gas: During this phase transition, the temperature of the substance remains constant, while the potential energy increases.

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Answer:

Geomagnetic Field

Explanation:

If you look at the tip of a pencil ,0.553 m the distance of the image from the lens of your eye will be 0.024m.

The human eye has a focal length of about 22 mm, but this is deceiving because

(i)our eyes have curved backs,

(ii) our peripheral vision has gradually less detail than our central vision,  (iii) the scene we see is a combination of what our two eyes see.

Since the coronary muscles are flexible, they allow our lenses to alter in focus length in response to the amount of light entering our eyes. This characteristic of the eye is known accommodation.

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Answer: Yes, it can be  possible that an object have non zero angular momentum.

Explanation:

There is a concept of frame of reference.

When your frame of reference is not on that straight line where the object is moving then the object will have non zero angular momentum .

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In a fire piston, the temperature of the gas inside the piston increases due to adiabatic compression.

In physics, pressure is a measure of the force per unit area that a fluid (liquid or gas) exerts on its surroundings. It is defined as the force F acting perpendicular to a surface divided by the area A over which the force is distributed: pressure = F/A. The SI unit of pressure is the Pascal (Pa), which is defined as one Newton per square meter (N/m²). Other common units of pressure include pounds per square inch (psi), atmospheres (atm), and bar (bar). Pressure is an important concept in many areas of physics, including fluid mechanics, thermodynamics, and atmospheric science. It describes the behavior of fluids in pipes and channels, the operation of hydraulic systems, and the behavior of gases in sealed containers. The pressure of a fluid is related to its density and temperature, and can be influenced by factors such as gravity, elevation, and the motion of the fluid itself.

Here,

When the piston is rapidly pushed down into the cylinder, it compresses the gas inside the cylinder. This rapid compression causes the gas molecules to collide with each other more frequently and with greater force, which in turn increases the temperature of the gas.

Because the compression is adiabatic (i.e., no heat is allowed to enter or leave the system), the increase in temperature is due solely to the work done on the gas by the piston. This increase in temperature is known as adiabatic heating.

The fire piston is a simple but effective tool for starting a fire in the wilderness, and it demonstrates the principles of adiabatic compression and the relationship between pressure, volume, and temperature in a gas.

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Answer:

\(R_s = 0.093 \Omega\)

Explanation:

Voltage of the car battery = 12.0 V

Voltage drop in the battery = 3.4 V

The remainder of the voltage is the starter voltage, that is:

Starter voltage = Initial battery voltage - voltage drop

Starter voltage = 12.0 - 3.4

Starter voltage, \(V_{s}\) = 8.6 V

Current drawn by starter, \(I_s\) = 93 A

According to Ohm's law: \(V_s = I_s R_s\)

Starter Resistance, \(R_s\) = \(V_s/I_s\)

\(R_s = 8.6/93\\R_s = 0.093 \Omega\)

Answer:

The hill is a total of 150 meters tall

Explanation:

30×5=150

Answer:

1.) A simple harmonic oscillator has an amplitude of 3.50 cm and a maximum speed of 26.0 cm/s. What is its speed when the displacement is 1.75 cm? 2.) Both pendulum A and B are 3.0 m long. The period of A is T. Pendulum A is twice as heavy as pendulum B. What is the period of B? 3.) The time for one cycle of a periodic process is called the _ ? 4.) In simple harmonic motion, the acceleration is proportional to? 5.) The position of a mass that is oscillating on a spring is given by x= (18.3 cm) cos [(2.35 s-1)t]. What is the frequency of this motion?

Explanation:

Answer:

Because it’s imposible

The focal length of the mirror will be 0.33 m

Focus is defined as the point through which the reflected light rays pass (or appear to pass) when incident light rays are parallel to the principal axis. It is located at the midpoint of pole and center of curvature. The distance between the pole and the focus of the mirror is called the focal length of the mirror.

F =2R or focal length of a mirror is half of its radius of curvature.

The radius of curvature of convex or concave mirror is equal to two times of the focal length of convex or concave mirror. The radius of curvature is the radius of sphere formed by the convex or concave mirror. It is also equal to the distance between the pole and center of curvature.

F = 1/R

R = 3 m (given )

F = 1 / 3 = 0.33 m

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The driver sees a barrier ahead. if the car takes 95 m to come to rest, what is the magnitude of the average force necessary to stop66,666.67 N

To find the magnitude of the average force necessary to stop the car, we can use the equation:

Force = (mass × change in velocity) / time

The change in velocity is the initial velocity (28 m/s) since the car comes to rest, and the time is given as 95 m. Rearranging the equation, we have:

Force = (mass × (-28 m/s)) / 95 m

Substituting the mass of 500 kg and calculating, we find the magnitude of the average force necessary to stop the car is approximately 66,666.67 N.

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1.428 s is the calculated time.

distances relative to the earthly acceleration do not take any initial distance or initial speed if you set the origin of your referential on the origin of your movement and assume that your ball has no initial speed as it is. The most amazing and unexpected truth about falling things is that, in a given location, all items fall toward the center of the Earth with the same constant acceleration, regardless of their mass, if air resistance and friction are low.

So here is the most straightforward formula for this:

+(1/2) *(9.81 m/s^ (2)) *t^ (2) = +10 m.

The result is that t = √ (20 m/ (9.81 m/s (2)))

=√ (2.039 s2)

distances relative to the earthly acceleration do not take any initial distance or initial speed if you set the origin of your referential on the origin of your movement and assume that your ball has no initial speed as it is. The most amazing and unexpected truth about falling things is that, in a given location, all items fall toward the center of the Earth with the same constant acceleration, regardless of their mass, if air resistance and friction are low.

vertical (and only) axis of a drawing must be pointed downward.

So here is the most straightforward formula for this:

+(1/2)*(9.81 m/s^(2))*t^(2) = +10 m.

The result is that t = √ (20 m/(9.81 m/s(2)))

= √(2.039 s2)

=1.428 s.

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The angular momentum of earth is

7×10^33 kgm^2/sec

Given:

mass of earth = 5.98×1024 kg

radius of earth = 6.38×10^6 m

To Find:

angular momentum

Solution:

For earth we have moment of inertia as

I = 2/5mR^2

and angular velocity as ω = 2π/T

Thus angular momentum is given as

L= 2/5mR^2*2π/T

L = 2/5*5.98×10^24*(6.38×10^6)^2*2*3.14/86400s

L = 7 × 10^33 kg/m^2/sec

So, angular momentum of earth is

So, angular momentum of earth is 7×10^33 kgm^2/sec

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Answer:

(a) At U = 3, 9 , v = 4, 2, the projection of u onto v is w1=<2,8>

(b)At U = 3, 9 , v = 4, 2,  the vector component of u orthogonal to v is w2 = <4,-1>

Explanation:

A

The projection of u onto v is given by:

w1= projvu = (u⋅v||v||2)v

Given that  u= <6,7> and v=<1,4>, we can find the projection of u onto v as shown below:

w1= projvu = (u⋅v||v||2v=(<6,7>⋅<1,4><1,4>⋅<1,)

=(6⋅1+7⋅41⋅1+4⋅4)<1,4>

=3417<1,4>

=<2,8>

Part B

The vector component of u orthogonal to v is given by:

Using the given vectors and the projection found in part (a), we can find the vector component of u orthogonal to v as shown below:

w2=u−projvu

=<6,7≻<2,8>

=<(6−2),(7−8)>

=<4,−1>

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Answer:

a 15.6voltz

i Hope this helps

The position of the ball attached to the unforced spring with a damping force of 6 times velocity is given by the function \(x(t) = e^{-3}t (sin3t)\). The system is overdamped, and the maximum displacement from equilibrium is 0.1573 meters.

a) Solve for the position of the ball.

The equation of motion of the ball attached to the unforced spring with damping force of 6 times velocity can be written as, \(m(d^{2}x/dt^{2}) + 6(dx/dt) + kx = 0\)

The given values are,

As we are supposed to find the position of the ball, we will solve the differential equation by assuming the position x as the solution and by integrating the given equation two times.

\(m\left(\frac{{d^2x}}{{dt^2}}\right) + 6\left(\frac{{dx}}{{dt}}\right) + kx = 0\)

This is the standard form of a second order homogeneous linear differential equation. The characteristic equation of this differential equation is, \(m^{2} r^{2} + 6mr + k = 0\)

Solving the above quadratic equation, we get, \(r = -3 \pm \sqrt{9 - \frac{4k}{m^2}} / 2m\)

Here, \(k/m = 9/1 = 9\). So, \(r = -3 \pm \sqrt{9 - 36} / 2 = -3 \pm 3i\)

From the above values of r, we can say that the general solution of the differential equation is, \(x(t) = e^{-3t}(C_1\cos(3t) + C_2\sin(3t))\)

Let's find the values of constants C1 and C2 using the initial values of the ball position and velocity.

At

So,

Substituting these values in the general solution of \(x(t),x(t) = e^{-3}t (sin3t)\)

Therefore, the position of the ball as a function of time is given by, \(x(t) = e^{-3}t (sin3t)\).

b) The damping force in the given equation is, b = 6 times the velocity.Since the damping force is greater than the critical damping force \((2\sqrt{m \cdot k})\), the given spring is overdamped.

c) Show that the maximum displacement of the ball from equilibrium is a az meters. To find the maximum displacement of the ball from equilibrium, we can differentiate the position function with respect to time and equate it to zero.

d). \((x(t)) / dt = e^{-3}t (3cos3t - sin3t)\)

When the above derivative of the position function is zero, the position of the ball is at the maximum or minimum from the equilibrium.

Substituting the values of t in the above equation, we get,cos3t = sin3t

Therefore, \(\tan(3t) = 1 \quad t = \frac{\pi}{12}, \frac{5\pi}{12}, \frac{9\pi}{12}, \frac{13\pi}{12}, \frac{17\pi}{12}, \ldots \quad \text{For } t = \frac{\pi}{12}\), the position of the ball is at maximum from equilibrium.

Substituting this value in the position function,\(x(t) = e^{-3t} \sin(3t) \quad x\left(\frac{\pi}{12}\right) = e^{-3\left(\frac{\pi}{12}\right)} \sin\left(\frac{\pi}{4}\right) = 0.1573 \, \text{m}\)

Therefore, the maximum displacement of the ball from equilibrium is \(0.1573\) meters.

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Energy is conserved by energy being transformed through one form or different forms.

Energy can change from one form to another, but cannot be destroyed.

Energy cannot be created or destroyed.

Similar to this, according to the rule of conservation of energy, energy cannot be generated or destroyed. For instance, kinetic energy is converted to potential energy when a toy vehicle is rolled down a ramp and collides with a wall.

There are three fundamental quantities in mechanics that are preserved. They are power, forward motion, and angular momentum. It can come as a surprise to you that energy is a conserved quantity if you've read instances in prior pages, such the kinetic energy of charging elephants.

Solar heat energy from the sun is used by us.

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Answer:

8.9*10^5

Explanation:

as we know that  

K.E =1/2 mv²

where m is mass and v is velocity

given mass= 1120 kg

given velocity =40 m/s

so K.E=1/2 (1120)(40)²

K.E=1792000/2

K.E=896000

K.E=8.9*10^5

Answer:

8.9* 10^5

Explanation:

Answer:

x = 1/2

Explanation:

5x/x + 2 = 3x/x + 1

do cross multiplication

(x + 2) * 3x = (x + 1) * 5x

3x^2 + 6x = 5x^2 + 5x

6x - 5x = 5x^2 - 3x^2

x = 2x^2

x/x^2 = 2

1/x = 2

1 = 2x

1/2 = x

The type of lens that spreads parallel light is a the type of lens that spreads parallel light is a Diverging lenses

When a lens in the path of a beam of parallel rays causes the rays to diverge after refraction, it is referred to as a diverging lens. It always creates a virtual image and has a thinner core than its boundaries. Concave lenses(diverging lenses) function as diverging lenses because they cause light rays to diverge as they pass through them. Therefore, when used with air as the operating medium, a concave lens can be thought of as a diverging lens. The concave lens has several applications, including in telescopes, cameras, lasers, glasses, binoculars, and other optical devices.

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Answer:

Explanation:

Considering the fact that we ave been given an angle of inclination here, we best use it! That means that the velocity of 23 m/s is actually NOT the velocity we need; I tell my students that it is a "blanket" velocity but is not accurate in either the x or the y dimension of parabolic motion. In order to find the actual velocity in the dimension in which we are working, which is the y-dimension, we use the formula:

\(v_{0y}=v_0sin\theta\) and filling in:

\(v_{0y}=23sin(25)\) which gives us an upwards velocity of 9.7 m/s. So here's what we have to work with in its entirety:

\(v_{0y}=9.7m/s\)

a = -9.8 m/s/s

t = 2.8 seconds

Δx = ?? m

The one-dimensional motion equation that utilizes all of these variables is

Δx = \(v_0t+\frac{1}{2}at^2\) and filling in:

Δx = \(9.7(2.8)+\frac{1}{2}(-9.8)(2.8)^2\) I am going to do the math according to the correct rules of significant digits, so to the left of the + sign and to 2 sig fig, we have

Δx = 27 + \(\frac{1}{2}(-9.8)(2.8)^2\) and then to the right of the + sign and to 2 significant digits we have

Δx = 27 - 38 so

Δx = -11 meters. Now, we all know that distance is not a negative value, but what this negative number tells us is that the ball fell 11 meters BELOW the point from which it was kicked, which is the same thing as being kicked from a building that is 11 meters high.

Answer:

The Production Possibilities Curve (PPC) is a model that captures scarcity and the opportunity costs of choices when faced with the possibility of producing two goods or services. Points on the interior of the PPC are inefficient, points on the PPC are efficient, and points beyond the PPC are unattainable.

Explanation:

Answer:

V = (S2 - S1) / t

V = 8 m / 1 s = 8 meters /second

Answer:

If and then for example: If you get at least 6 hours of sleep, you will do better on tests than if you get less sleep.

Explanation:

Answer:

Density= 2.78 g/cm³

Relative density=2.8

Explanation:

To calculate the density of the cube we have to use the formula ρ=mass/volume

ρ stands for density.

So now we don't have the volume of the cube and to find the volume of the cube we have to use the formula a³

3³= 9 cm³

Now plug in the values. ρ= 25 g/9 cm³

ρ= 2.78 g/cm³

To find the relative density, we have to use the formula ρsample/ρH20

The sample means the density of the substance earlier. We do not know the density of water but it is constant at 997 kg/m³.

Now we have to make the units same so you change the unit of the density of cube to kg/m³

So, 25/1000= 0.025 kg

9/100×100×100 (because cm³ which means that there should be 3 meters to change the unit and to conver cm to meter we need to divide by 100 so 9cm/100, 9cm²/100×100, 9cm³/100×100×100)

=0.000009 m³

The new density= 0.025 kg/ 0.000009 m³

= 2777.78 kg/m³

Now plug the values into the formula:

relative density= 2.777.78 kg/m³ / 997 kg/m³

=2.8

There is no unit since kg/m³ and kg/m³ cancels