Using the PhET Balancing Act, discuss the possibilities of balancing two forces acting on one side of a pivot point with a single force of the other. Select the best answer: i. This is possible with a single force at the same distance from the pivot point but on the opposite side of the pivot point as one of the forces. Ii. This is possible with a single force at the same distance as the point half way between the two forces from the pivot point but on the opposite side of the pivot point. Iii. This requires two forces. A

Answer:

a = 4 m/s²

Explanation:  

Given: 28 N, 7 kg  

To find: Acceleration (a)  

Solution: To find (a), divide force by weight  

A = F ÷ m

=  28 ÷  7

= 4 m/s²

Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.

Answer:

i dont know

Explanation:

When both the force and time of contact are doubled, the impulse on an object increases by a factor of four.

When we talk about impulse, we are referring to the change in momentum of an object over a period of time. Impulse is the product of force and time, as given by the formula:
Impulse = Force x Time

the impulse on the ball would be:
Impulse = Force x Time
Impulse = 10 N x 2 s
Impulse = 20 Ns


This would cause the ball to have a momentum of:
Momentum = Mass x Velocity
Momentum = 0.5 kg x (20 N / 0.5 kg) x 4 s
Momentum = 80 Ns
The impulse on the ball increased by a factor of four, and so did the momentum. This shows that the greater the impulse on an object, the greater the change in momentum it will experience.

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Answer:

The thermal efficiency, \(\eta _{reheat}\), of the Rankine cycle with reheat is 36.81%

Explanation:

p₁ = 8 MPa = 80 Bars

T₁ = 450°C = 723.15 K

From steam tables, we have;

v₁ = 0.0381970 m³/kg

h₁ = 3273.23 kJ/kg

s₁ = 6.5577 kJ/(kg·K) = s₂

The p₂ = 0.8 MPa

T₂ = Saturation temperature at 0.8 MPa = 170.414°C = 443.564 K

h₂ = 2768.30 kJ/kg

\(T_{2'}\) = 400°C = 673.15 K

\(h_{2'}\) = at 400°C and 0.8 MPa = 3480.6 kJ/kg

p₃ = 10 kPa = 0.1 Bar

T₃ = Saturation temperature at 10 kPa = 45.805 °C = 318.955 K

h₃ = 2583.89 kJ/kg

h₄ = \(h_{3f}\) = 191.812 kJ/kg

The thermal efficiency, \(\eta _{reheat}\), of a Rankine cycle with reheat is given as follows;

\(\eta _{reheat} = \dfrac{\left (h_{1}-h_{2} \right )+\left (h_{2'}-h_{3} \right )-W_{p}}{h_{1}-\left (h_{4}+W_{p} \right )+\left (h_{2'}-h_{2} \right )}\)

Therefore, we have;

\(\eta _{reheat} = \dfrac{(3273.23 -2768.30 ) + (3480.6 -2583.89 ) - 8.04)}{(3273.23 -(191.812 + 8.04) + (3480.6 -2768.30 ) } = 0.3681\)

Which in percentage is 36.81%.

Answer:

500N up........

.......

The minimum volume that needs to be left empty at filling time so that the tank doesn't rupture as it warms is 1.86 L.

First, we need to determine the change in volume of the gasoline as it warms from -10°C to 20°C. To do this, we can use the formula for the coefficient of volume expansion:

ΔV = βV₀ΔT

where ΔV is the change in volume, β is the coefficient of volume expansion, V₀ is the initial volume, and ΔT is the change in temperature. For gasoline, the coefficient of volume expansion is approximately 0.00095 1/°C.

Plugging in the given values, we get:

ΔV = (0.00095 1/°C)(65.00 L)(20°C - (-10°C))

ΔV = 1.86 L

This means that the volume of the gasoline will increase by 1.86 L as it warms from -10°C to 20°C. Therefore, to prevent the tank from rupturing, we need to leave at least 1.86 L of empty space in the tank when filling it at -10°C.

Part A Answer: 1.86 L

So, the minimum volume that needs to be left empty at filling time so that the tank doesn't rupture as it warms is 1.86 L.

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Answer:

Explanatioit cn:

Answer:

ewwwwwwwwwwww

get it out!

The speed of the object 7 seconds after it is dropped is -68.6 m/s (negative sign indicates downward direction).

The height of the object above the ground at time t is given by the equation h(t) = 625 - 4.9t².

To find the speed of the object at 7 seconds, we need to calculate the derivative of the height function with respect to time. The derivative gives us the rate of change of the height, which corresponds to the velocity or speed.

Taking the derivative of h(t) with respect to t:

h'(t) = d(h(t))/dt = d(625 - 4.9t²)/dt = -9.8t.

Now we can substitute t = 7 seconds into the derivative to find the speed at that time:

h'(7) = -9.8 * 7 = -68.6 m/s.

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Answer:

4 is the answer

Explanation:

hope this helps

Answer:

they are transparent to see the content of goods inside but at the same time what cause it to be transparent is because of the fact that they are created with low-density polyethylene and polypropylene, which are transparent polymers.

The available options are:

A. bartenders serving alcohol

B. students identifying their professors.

C. Doctors diagnosing cases of schizophrenia.

D. eyewitnesses identifying suspects from a lineup.

Answer:

A.  bartenders serving alcohol

Explanation:

This is because of the underage rule concerning sale of alcohol. Thus, there are occasional period in which underage person or a minor will want to buy alcohol, and without necessarily asking for the birth certificate or ID card that contains Age information, it is therefore, necessary for bartenders to be able to tell the age of their unfamiliar customers, by mere looking at them, so as not to sell to a minor.

Hemce, Rhodes research in guessing the age of unfamiliar person has important implications for BARTENDERS SERVING ALCOHOL, because it will guide them to determine Underage or Minor, that want to buy alcohol from them.

Answer:

11.25m

Explanation:

Given parameters:

Initial velocity  = 0m/s

Time of running  = 3s

Acceleration  = 2.5m/s²

Unknown:

Displacement = ?

Solution:

To solve this problem, we apply one of the motion equations.

  S  = ut + \(\frac{1}{2}\) at²

   u is the initial velocity

    t is the time taken

    a is the acceleration

 S = (0 x 3)  + ( \(\frac{1}{2}\)  x 2.5 x 3²)   = 11.25m

Answer:

it’s the 2nd one

Explanation:

Answer:

second one

Explanation:

The minority carrier diffusion equation for an n-type semiconductor is:

∂p/∂t = Dp (∂²p/∂x²) - (p - p0)/τp

Where p is the minority carrier concentration, Dp is the diffusion coefficient for minority carriers, p0 is the equilibrium minority carrier concentration, and τp is the minority carrier lifetime.

Assuming steady-state (i.e., ∂p/∂t = 0) and no light, the equation becomes:

Dp (∂²p/∂x²) - (p - p0)/τp = 0

Rearranging and integrating twice with appropriate boundary conditions, we obtain:

p(x) = A exp(-x/Lp) + B exp(x/Lp)

where Lp is the minority carrier diffusion length and A and B are constants determined by the boundary conditions.

This equation describes the spatial variation of minority carrier concentration in an n-type semiconductor in steady state and in the absence of light. The first term represents the diffusion of minority carriers from the surface into the bulk of the semiconductor, while the second term represents the diffusion of minority carriers from the bulk towards the surface. The constants A and B can be determined from the boundary conditions, such as the minority carrier concentration at the surface and/or the bulk of the semiconductor.

Note that this equation assumes a 1D model for minority carrier diffusion, which may not be accurate in all cases.

Overall, the equation predicts that the minority carrier concentration decays exponentially as we move away from the surface of the semiconductor, with a characteristic length scale of Lp. This behavior is due to the recombination of minority carriers with majority carriers in the bulk of the semiconductor, which reduces the minority carrier concentration away from the surface.

The equation can be used to calculate the minority carrier concentration at any point in the semiconductor, and to predict the behavior of minority carriers under different conditions, such as changes in temperature, doping concentration, or applied electric fields.

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The gas is compressed to 1/7 of its original volume, but since the process is horizontal, there is no change in volume. Hence, no work is done during the process A to B.

Therefore, the work done (WAB) during the process A to B is zero.

The work done by or on the gas during the process A - B can be calculated using the following formula: WAB = -∫PdV where P = pressure, and V = volume. To calculate WAB, we need to calculate the integral of PdV. Since B is represented by a horizontal line, the pressure P is constant. Therefore, WAB = -P∫dVWhere, ∫dV is the integral of dV from the initial volume Vi to the final volume Vf.

The gas is compressed from state A to state B. Therefore, the initial volume Vi = 7.0 dm³ and the final volume Vf = 1/7 * 7.0 dm³ = 1.0 dm³.WAB = -P ∫dV = -P(Vf - Vi)WAB = -200 kPa (1.0 dm³ - 7.0 dm³) = 1200 JThe work done by the gas during the process A - B is -1200 J.

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The answer is five dots.

sorry i  meant three dots not five

Answer:

D.Earth was the center of the universe

Explanation:

In the geocentric model of the solar system, the earth was the center of the universe and the sun and planets orbited around it. As the oldest model that sought to understand the functioning of the solar system, it was little contested due to the difficulty of scientific resources for further investigation.

Gradually this model was shaping and being restructured, as new studies, equipment and technologies appeared that could help astronomers and physicists to develop the current theory, that in reality the sun is the center of the solar system.

Answer:

D

Explanation:

The centripetal component of the ball's acceleration is eighteen m/s².

Acceleration is the fee of alternate of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given through the orientation of the net pressure performing on that item.

Calculation:-

A. The centripetal acceleration of the ball is as follows

a = v²/r

  = (3.00)²/0.500 m

  = 18 m/s²

B. given that there may be no force performing at the ball within the tangential acceleration direction,

The tangential acceleration of the ball is zero.

C. the peak at which the ball is rotating is

tan θ = r/h

rg/v² = r/h

h = v²/g

= (three.00 m/s)²/9.eight

= 0.ninety two m  

Acceleration is the price at which velocity modifications with time, in terms of each velocity and course. A component or an object moving in a straight line is accelerated if it accelerates or slows down. motion on a circle is prolonged no matter the reality that the rate is steady due to the fact the path is continually converting.

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A. The expression for the centripetal acceleration of the ball is as follows:

ac = v2 / r

=(3.00 m/s) / 0.500 m

= 18 m/s2

C. The height at which the ball is rotating is as follows:

tan ∅ = r / h

rg / v2 = r/h

=h = v2 / g

=(3.00 m/s)2 / 9.8 m/s2

= 9.2m/s2

The charge of trade of position of an object in any course. Speed is measured by the ratio of distance to the time wherein the space changed into blanketed.

The equation for speed is easy: distance divided by time. You're taking the distance traveled (as an instance three meters), and divide it by the point (3 seconds) to get the speed (one meter in keeping with second)

In case you understand the gap an object travels in a positive quantity of time,  the rate of the object. As an example, if a automobile travels 70 miles in one hour, the car is visiting at a speed of 70 miles/hour (miles per hour).

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Answer:

49k

Explanation:

yes you can go with me

Answer:

there is no graphic

Explanation:

Answer:

67408*10-11m3kg-1s-2

Answer:

6.673×10^-11

Explanation:

The spring constant of each individual spring is approximately 588 N/m.

To find the spring constant of the combination, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. The equation for Hooke's Law is given as:

\(F = -kx\)

Where F is the force applied to the spring, k is the spring constant, and x is the displacement from the equilibrium position.

For the combination of springs, we can treat them as a single spring with an equivalent spring constant. Since the springs are hooked end to end, the total displacement of the combination is the sum of the individual displacements.

Given that the combination of springs stretches 0.15 m beyond its relaxed length with a 6.0-kg brick, we can calculate the spring constant of the combination using the formula:

\(F = k_combined * x_combined\)

Where F is the weight of the brick (mg) and x_combined is the total displacement of the combination.

\(F = (6.0 kg) * (9.8 m/s^2) = 58.8 N\)

\(x_combined = 0.15 m\)

Therefore, we can rearrange the equation to solve for the spring constant of the combination:

\(k_combined = F / x_combined\)

\(k_combined = 58.8 N / 0.15 m ≈ 392 N/m\)

The spring constant of the combination is approximately **392 N/m**.

Now, let's calculate the spring constant of each individual spring. Since the top spring stretches 0.10 m, we can use the same equation:

\(k_top = F / x_top\)

\(F = (6.0 kg) * (9.8 m/s^2) = 58.8 N\)

\(x_top = 0.10 m\)

\(k_top = 58.8 N / 0.10 m = 588 N/m\)

The spring constant of each individual spring is approximately 588 N/m.

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To determine how far a marble will travel before stopping in water at 20°C, we can consider the balance between the drag force acting on the marble and its kinetic energy. The drag force is determined by the viscosity of water, the size of the marble, and its velocity. The kinetic energy depends on the mass and velocity of the marble. By equating the drag force to the kinetic energy, we can solve for the distance traveled.

The drag force can be calculated using the formula:
F = 6πηrv
The kinetic energy of the marble is given by:
KE = (1/2)mv^2

6πηrv = (1/2)mv^2

We can solve this equation for the distance traveled by rearranging it as:
d = (1/2)mv^2 / (6πηr)

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Answer : Lipids and carbohydrates are both made from carbon, hydrogen, and oxygen, but lipids have less oxygen (Option B)

Carbohydrates are biomolecules composed of carbon (C), hydrogen (H), and oxygen (O) in a 1:2:1 ratio, respectively.

Carbohydrates can be divided regarding the number of monomers in the biomolecule into monosaccharides, disaccharides, and polysaccharides.

Explanation:

hope this answer will helps you !

Answer:

The difference between a solid and a liquid at the molecular level lies in the strength of the intermolecular attraction.

Explanation:

Solids and liquids have similar densities, so the tightness of the packing is not the difference.

The difference lies in the strength of the intermolecular (between different molecules) attraction. In solids, the intermolecular attractions are strong enough to hold the same molecules together with their neighbors, despite the random thermal vibrations. The same group of nearest neighbor molecules and second nearest and third nearest, and so on out to very large numbers, stays together. So the molecules are stationary, except for vibrations around an average position. That's solid.

the intermolecular forces are strong enough in liquids to keep nearest neighbors together only for short times before the thermal vibrations break apart the groupings. Thus the molecules are always close to each other, but don’t stay next to any particular other molecules, so the whole collection of it can easily flow, but with a specific volume. That’s a liquid.

In a gas, the intermolecular forces are too weak to hold the molecules near each other and the thermal random motion quickly splits up any short-term pairs. So it flows easily with no specific volume - the molecules are all approximately independent from each other.

In ionic solids, there are no specific molecules, but replace “molecules” above with “ions of opposite charge”

The time it takes the car to stop is 1.34 s.

The initial speed of the car is 77.46 ft/s

The given parameters;

acceleration of the car, a = 24 ft/s²

distance traveled by the car, s = 125 ft

The initial speed of the car is calculated as;

When the car stops, the final velocity will be zero,

\(v^2 = u^2 + 2as\\\\0 = u^2 + 2(-24\times 125)\\\\u^2 = 6000\\\\u = \sqrt{6000} \\\\u = 77.46 \ ft/s\)

The time taken for the car to stop is calculated as;

\(s = ut + \frac{1}{2} at^2\\\\125 = 77.46t + 0.5\times 24\times t^2\\\\125 = 77.46t + 12t^2\\\\12t^2 + 77.46t - 125 = 0\\\\solve \ the \ quadratic \ equation \ using \ formula \ method;\\\\a = 12, \ b = 77.46, \ c = - 125\\\\t = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\t = \frac{-77.46 \ \ +/- \ \ \sqrt{(77.46)^2 - 4(12\times -125)} }{2(12)}\\\\t = 1.34 \ s\)

Thus, the time it takes the car to stop is 1.34 s.

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A pulsar is a neutron star that sweeps a beam of radiation past the Earth each time it rotates. So, option D is correct.

A pulsar is a highly magnetized, rotating neutron star that emits beams of electromagnetic radiation. It is formed from the remnants of a massive star that has undergone a supernova explosion.

As the neutron star spins rapidly, its intense magnetic field causes beams of radiation to be emitted from its magnetic poles. These beams are observed as regular pulses of radiation as the pulsar rotates.

Pulsars are characterized by their precise and regular periods of pulsation, which can range from milliseconds to several seconds.

The emission of radiation occurs along the magnetic axis of the neutron star, and if this axis is not aligned with the rotation axis, the beams of radiation sweep across space like a lighthouse, leading to periodic pulses of radiation detected on Earth.

The discovery of pulsars in 1967 by Jocelyn Bell Burnell and Antony Hewish provided evidence for the existence of neutron stars and opened up new avenues for studying stellar remnants and extreme astrophysical phenomena.

Pulsars are important objects in astrophysics and continue to be studied for their contributions to our understanding of stellar evolution, gravity, and the behavior of matter under extreme conditions.

So, option D is correct.

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