The data set illustrated by this stem - and - leaf plot is 25, 26, 27, 53, 58, 62, 67, 69, 96, 96, 123 (option b).
What is a stem and leaf plot?A stem-and-leaf plot is a table that is used to represent a dataset. A stem-and-leaf plot is similar to a histogram. A stem-and-leaf plot divides a number into a stem and a leaf.
The stem is the first number in the digit while the leaf is the last number. For example in the number 25, 2 would be the stem and 5 would be the leaf. A stem-and-leaf plot usually arranges the dataset in ascending order.
An advantage of a stem-and-leaf plot is that it contains all the data in the dataset. A disadvantage of the stem-and-leaf plot is that it can only be used for a small dataset.
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Shawna rented a bike from Arjun's Bikes. It cost $14 plus $3 per hour. If Shawna paid $32 then she rented the bike for how many hours?
Answers
1.9 hours
Step-by-step explanation:
14 plus 3 = 17
32 divide by 17 = 1.9 hours
1 hour 0.9 multiply by 60
1.9= 1 hour 54 minutes
which of the following is a graph of the function shown below?
find the perimeter
side A: x+10y units
side B:7x^2-x+9y units
Step-by-step explanation:
2(x+10y)+2(7x^2-x+9y)
= 2x+20y+14x^2-2x+18y
= (14x^2+38y) units^2
Which of these graphs represents a function?
Answer:
I believe it would be graph Z :)
Step-by-step explanation:
Answer:
it’s graph x
Step-by-step explanation:
vertical line test, put a vertical line through the graph, if it touches more than 1 point(2 or more) it’s not a functions
please help me !!!!!!!!!
The proof to show that ∆AEC and ∆BDC are similar in the blanks is below;
Perpendicular linesReflexive property SASHow to prove that ∆AEC ~ ∆BDC?<BDC and <AEC are right angles by the definition of perpendicular lines and all right angles are congruent, So, <BDC≅AEC. Both ∆AEC and ∆BDC share <C, and <C ≅ <C by the reflexive property. Therefore, ∆AEC ~ ∆BDC by the SAS criterion for proving similar triangles.
A triangle is a three sided polygon. The type of triangles includes:
Right triangleIsosceles triangleEquilateral triangleScalene triangleRead more on triangles:
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A large population has mean 100 and standard deviation 16. What is the probability that the sample mean will be within plusminus 2 of the population mean if the sample size is n = 100? What is the probability that the sample mean will be within plusminus 2 of the population mean if the sample size is n = 400? What is the advantage of a larger sample size?
The probability that the sample mean will be within plus minus 2 of the population mean if the sample size is n = 100 between z-scores of 0 and 2.5 using a z-table.
The standard deviation of the sample distribution, commonly known as the standard error, can be computed using the formula given that the population mean is 100 and the standard deviation is 16:
Standard Error = Standard Deviation / sqrt(sample size)
Let's determine the likelihoods for sample sizes of n = 100 and n = 400:
For n = 100:
Standard Error = 16 / sqrt(100) = 16 / 10 = 1.6
We can determine the z-scores for the upper and lower boundaries to establish the likelihood that the sample mean will be within plus or minus 2 of the population mean:
Lower Bound z-score = (Sample Mean - Population Mean) / Standard Error
Lower Bound z-score = (100 - 100) / 1.6
Lower Bound z-score = 0
Upper Bound z-score = (Sample Mean - Population Mean) / Standard Error
Upper Bound z-score = (104 - 100) / 1.6
Upper Bound z-score = 4 / 1.6
Upper Bound z-score = 2.5
We can calculate the region under the normal distribution curve between z-scores of 0 and 2.5 using a z-table or statistical software. This shows the likelihood that the sample mean will be within +/- 2 standard deviations of the population mean.
For n = 400:
Standard Error = 16/√400
Standard Error = 16/20
Standard Error = 0.8
We determine the z-scores by following the same procedure as above:
Lower Bound z-score = (Sample Mean - Population Mean) / Standard Error
Lower Bound z-score = (100 - 100) / 0.8
Lower Bound z-score = 0
Upper Bound z-score = (Sample Mean - Population Mean) / Standard Error
Upper Bound z-score = (104 - 100) / 0.8
Upper Bound z-score = 4 / 0.8
Upper Bound z-score = 5
Once more, we may determine the region under the normal distribution curve between z-scores of 0 and 5 using a z-table or statistical software.
A larger sample size, like n = 400, has the benefit of a lower standard error. The sampling distribution of the sample mean will be more constrained and more closely resemble the population mean if the standard error is less.
As a result, there is a larger likelihood that the sample mean will be within +/- 2 of the population mean. In other words, the estimate of the population mean gets more accurate and dependable as the sample size grows.
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Which one is the correct answer, a b c d
\(g(f(x))=\sqrt{\frac{2301+100x^2}{23+x^2} }\)
Step-by-step explanation:\(Substitute\ and\ calculate:\\ \downarrow\\ g(f(x))=\sqrt{\frac{2301+100x^2}{23+x^2} }\)
I hope this helps you
:)
The perimeter of a square is 80cm
state the length of one of its side
Answer:
20cm
Step-by-step explanation:
a square has 4 equally long sides.
when we know its perimeter, that means we know the sum of all 4 sides.
since all sides are equality long, we only need to divide the perimeter by 4 to get the length of an individual side.
80/4 = 20cm
Find the greatest common factor of these two expressions 18y^6w^2 and 27y^5 w^4 u^7
Answer:
9\(y^{5}\)\(w^{2}\)
Step-by-step explanation:
Find what both expressions have in common
Find the range of the function y=3-x when the domain is {-2, 0, 3}
Answer:
-3
Step-by-step explanation:
when u look at it or slove it
Answer:
Step-by-step explanation:
The range is going to be the y value in this case.
y = 3 - - 2
y = 5
y = 3 - 0
y = 3
y = 3 - 3
y = 0
(5,3,0)
Vicky ran 300 yards in 74 seconds. Then, she ran 300 yards in 53 seconds how much faster was vickys second time?
Answer:
Vicky was 21 seconds faster the second time!
Step-by-step explanation:
Have a great day :D
Answer:
21
Step-by-step explanation:
74-53=
70-50=20
4-3=1
20+1=21
HELP HELP HELP!!!!!!!!!!!
Answer:
i think it's d
Step-by-step explanation:
Donte’ buys 12 pencil erasers. Each costs $0.85. How much does Donte’ spend on the erasers before tax?
_______ dollars
at a sport camp, there are sufficient food for 72 athletics to last 6 days. if 18 athletics are absent from the camp, how many more days can the food last for the other athletics? state the assumption made.
Answer:
4
Step-by-step explanation:
dived 72 by 18 and you get 4
What is the missing term in the factorization? 1872 -- 32 2(3x+?) (3x – 4) Enter your answer in the box.
Answer:
4
Step-by-step explanation:
..........................
If+the+frequency+of+ptc+tasters+in+a+population+is+91%,+what+is+the+frequency+of+the+allele+for+non-tasting+ptc?
The frequency of the allele for non-tasting PTC in the population is 0.09 or 9%.
To determine the frequency of the allele for non-tasting PTC in a population where the frequency of PTC tasters is 91%, we can use the Hardy-Weinberg equation. The Hardy-Weinberg principle describes the relationship between allele frequencies and genotype frequencies in a population under certain assumptions.
Let's denote the frequency of the allele for taster individuals as p and the frequency of the allele for non-taster individuals as q. According to the principle, the sum of the frequencies of these two alleles must equal 1, so p + q = 1.
Given that the frequency of PTC tasters (p) is 91% or 0.91, we can substitute this value into the equation:
0.91 + q = 1
Solving for q, we find:
q = 1 - 0.91 = 0.09
Therefore, the frequency of the allele for non-tasting PTC in the population is 0.09 or 9%.
It's important to note that this calculation assumes the population is in Hardy-Weinberg equilibrium, meaning that the assumptions of random mating, no mutation, no migration, no natural selection, and a large population size are met. In reality, populations may deviate from these assumptions, which can affect allele frequencies. Additionally, this calculation provides an estimate based on the given information, but actual allele frequencies may vary in different populations or geographic regions.
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The oven that is used To make the pizza is majors temperature in Fahrenheit the baking temperature for the pizza is that buy a new employer to 310° F is this temperature correct if he had been instructed to set the temperature is 180°C use the formula °C=(°F-32°)x1,8]
Answer:
°F = 356
Step-by-step explanation:
°C = (°F - 32) ÷ 1.8
180 = (°F - 32) ÷ 1.8
180×1.8 = °F - 32
324 = °F - 32
°F = 324 + 32
°F = 356
The probability Peanuts will score above 89% on his probability theory homeworks is 0.50. Peanuts will complete twelve homeworks this semester.
(a). What is the probability of Peanuts scores above 89% on exactly six out of the twelve homeworks? (Round your answer to 4 decimal spots
(b). What is the probability of Peanuts will score above 89% on at least 3 out of the twelve homeworks?
the probability of Peanuts scoring above 89% on at least 3 out of the twelve homeworks is approximately 0.9814
(a) To calculate the probability of Peanuts scoring above 89% on exactly six out of the twelve homeworks, we can use the binomial probability formula.
The formula for the probability of exactly k successes in n independent Bernoulli trials with probability p of success is:
P(X = k) = C(n, k) * p^k * (1-p)^(n-k)
Where:
P(X = k) is the probability of exactly k successes,
C(n, k) is the number of combinations of n items taken k at a time,
p is the probability of success on a single trial, and
n is the total number of trials.
In this case:
p = 0.50 (probability of scoring above 89%)
n = 12 (total number of homeworks)
k = 6 (number of homeworks Peanuts scores above 89%)
Using the formula, we can calculate the probability:
P(X = 6) = C(12, 6) * (0.50)^6 * (1-0.50)^(12-6)
Using a calculator or software, we can find:
C(12, 6) = 924
Plugging in the values:
P(X = 6) = 924 * (0.50)^6 * (0.50)^6
P(X = 6) = 924 * (0.50)^12
P(X = 6) ≈ 0.0059
Therefore, the probability of Peanuts scoring above 89% on exactly six out of the twelve homeworks is approximately 0.0059.
(b) To calculate the probability of Peanuts scoring above 89% on at least 3 out of the twelve homeworks, we need to find the sum of probabilities for scoring above 89% on 3, 4, 5, ..., 12 homeworks.
P(X ≥ 3) = P(X = 3) + P(X = 4) + P(X = 5) + ... + P(X = 12)
Using the binomial probability formula, we can calculate each individual probability and sum them up.
P(X ≥ 3) = P(X = 3) + P(X = 4) + P(X = 5) + ... + P(X = 12)
= [C(12, 3) * (0.50)^3 * (1-0.50)^(12-3)] + [C(12, 4) * (0.50)^4 * (1-0.50)^(12-4)] + ... + [C(12, 12) * (0.50)^12 * (1-0.50)^(12-12)]
Using a calculator or software, we can calculate the probabilities and sum them up.
P(X ≥ 3) ≈ 0.9814
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Solve -2(8n - 3) = 43(n + 7). write the solution as an integer or decimal. Show your work (simply).
n = __
Answer:
n = - 5
Step-by-step explanation:
- 2(8n - 3) = 43(n + 7) ← distribute parenthesis on both sides
- 16n + 6 = 43n + 301 ( subtract 43n from both sides )
- 59n + 6 = 301 ( subtract 6 from both sides )
- 59n = 295 ( divide both sides by - 59 )
n = - 5
Answer:
n=7.14
Step-by-step explanation:
-2(8n-3)=43(n+7)
distribute
-16n+6=43n+301
add 16n on both sides
6=43n-301
add 301 on both sides
307=43n
divide both sides by 43
n=7.1395
What nominal interest rate compounded semi-annually is
equivalent to 2.76% compounded quarterly?
% Round to two decimal places
The nominal interest rate compounded semi-annually which is equivalent to 2.76% compounded quarterly is 1.37% (rounded to 2 decimal places).
Here, we are supposed to find the nominal interest rate compounded semi-annually which is equivalent to 2.76% compounded quarterly.
The relationship between a nominal interest rate (i) and the effective interest rate (i’), compounded (n) times a year, is given by;
(1 + i/n)^n
= 1 + i’/m(1)
Where m is the number of times interest is compounded per year.
So, we get the effective interest rate that corresponds to 2.76% compounded quarterly as follows;
Let i' be the effective interest rate that corresponds to 2.76% compounded quarterly.
Then; n = 4 and m = 1 (Quarterly compounding period and 1 year is divided into 4 quarters)i’
= (1 + 0.0276/4)^4 - 1
= 0.02806 (Rounded to 5 decimal places)
Now, to calculate the nominal interest rate compounded semi-annually,
we can use Equation (1);(1 + i/2)^2
= 1 + 0.02806i
= [1 + 0.02806]^(1/2) - 1
= 0.01367
≈ 1.37%(Rounded to 2 decimal places)
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Find the intersection of the parabola y=-x^2+2x+4 and the line 4x-y=-1
Answer
(-3, -11), (1, 5)
Explanation
To solve this, we will solve this, we will equate the expressions for y
y = -x² + 2x + 4
4x - y = -1
y = 4x + 1
y = y
4x + 1 = -x² + 2x + 4
x² + 4x - 2x + 1 - 4 = 0
x² + 2x - 3 = 0
x² + 3x - x - 3 = 0
x (x + 3) - 1 (x + 3) = 0
(x + 3) (x - 1) = 0
x + 3 = 0
x = -3
OR
x - 1 = 0
x = 1
y = 4x + 1
If x = -3
y = 4x + 1 = 4(-3) + 1 = -12 + 1 = -11
If x = 1
y = 4x + 1 = 4(1) + 1 = 4 + 1 = 5
(-3, -11) OR (1, 5)
Hope this Helps!!!
after 5 seconds the height of the ballon is 20 feet
Which expression represents the product of x³ + 2x - 1 and 24x³+3?
Answer:
The first expression is a Trinomial and the second expression is a Binomial
Which product is modeled by the number line below
Answer:
the second option/b
Step-by-step explanation:
because -2*4 equals -8
Answer:The second option beacue -2*4 equal -8
Step-by-step explanation:
5.) Some cats and 29 dogs are in the kennels at the vet. There are 45
animals altogether. How many cats are in the kennels?
Answer:
16 cars
Step-by-step explanation:
Answer:
Easy 45-29=16.
Step-by-step explanation:
The hanger diagram models the equation 2b = 4. Use the diagram to find the
value of b. Show your reasoning.
The value of b is 2.
Since the hanger diagram models the equation 2b = 4, we can see that the bar representing 2b has a length of 4 units.
To find the value of b, we need to divide both sides of the equation by 2. This gives us:
2b/2 = 4/2
b = 2
Therefore, the value of b is 2.
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Plz answer this
(5x^2-3x+1)-(4x+2x^2-2)
y - 1 = 6(x - 1)
Please help me and explain :)
Answer:
y-1=6(x-1)
y-1=6x-6
y-6x=-6+1
y-6x=-5
y-x=-5+6
y-x =0Answer:
y=6x-5
Step-by-step explanation:
y-1=6(x-1)
(distribute 6 to x-1)
y-1=6x-6
(add 1 to both sides)
y=6x-5
$1.29, $1.92, $3.19, $1.79, $3.99, $479, 55.19, $5.29, $5.49
4) Henry had 9 items in his shopping cart with different prices (shown). His mean cost of these items was $5.88. At the register, he added a gift card to his purchase for $40.00. Choose ALL
statements about how the gift card price will affect the mean and median of the items he purchased
A) Both the mean and median will increase.
B) Only the mean of the prices will increase
Only the median of the prices will increase
D) The mean will increase by more than the median
D) Neither the mean nor median of the prices will increase
The conclusion on the mean and median after the gift card is added is:
C: Only the median of the prices will increase
How to find the mean and median of the distribution?The mean (average) of a data set is gotten by adding all numbers in the data set and then dividing by the number of values in the set. The median is the middle value when a data set is ordered from least to greatest.
The mean of the dataset is:
Mean = (1.29 + 1.92 + 3.19 + 1.79 + 3.99 + 479 + 55.19 + 5.29 + 5.49)/9
Mean = $61.91
If he added a $40 gift card, then:
New mean = (1.29 + 1.92 + 3.19 + 1.79 + 3.99 + 479 + 55.19 + 5.29 + 5.49 + 40)/10 = $59.715
Initial median:
1.29, 1.79, 1.92, 3.19, 3.99, 5.29, 5.49, 55.19, 479
Initial median = 3.99
Final median after the gift card of $40:
1.29, 1.79, 1.92, 3.19, 3.99, 5.29, 5.49, 40, 55.19, 479
Final median = (3.99 + 5.29)/2 = $4.64
Thus, only median will increase
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in a high school high jump contest, the height of clearing the bar ranged from 71 inches to 84 inches. the mean height was 76 inches and the standard deviation was 3.5 inches. what percent of the jumpers were in the group jumping below 79.5 inches? (hint: how many standard deviations is 79.5 inches?)
Approximately 84% (34% + 50%) of the jumpers were in the group jumping below 79.5 inches. This can be answered by the concept of Standard deviation.
In a high school high jump contest, the mean height was 76 inches, and the standard deviation was 3.5 inches. To find the percentage of jumpers below 79.5 inches, we first need to determine how many standard deviations away 79.5 inches is from the mean.
To do this, subtract the mean from 79.5 inches and divide by the standard deviation:
(79.5 - 76) / 3.5 = 3.5 / 3.5 = 1
So, 79.5 inches is 1 standard deviation above the mean. According to the empirical rule, approximately 68% of the data falls within 1 standard deviation of the mean in a normal distribution. Since we are looking for jumpers below 79.5 inches, we need to consider the lower half of this 68%, which is 34%. Additionally, 50% of the data is below the mean.
Therefore, approximately 84% (34% + 50%) of the jumpers were in the group jumping below 79.5 inches.
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