Use the quadratic formula to find both solutions to the quadratic equation given below

No, X or y-axis scale does not have to always start at zero. In a line chart, it's OK to start the axis at a number other than zero

A line that is used to take or mark measurements is known as an axis in mathematics. Two crucial axes of the coordinate plane are the x and y axes. A horizontal number line is the x-axis, while a vertical number line is the y-axis. The coordinate plane is created by the perpendicular intersection of these two axes.

Given,

No, X or y-axis scale does not have to always start at zero.

A line chart encodes data using location (x, y coordinates), whereas a bar chart represents data using length. In a line chart, it's OK to start the axis at a number other than zero despite many claims that they are always misleading since this minute difference influences how a reader utilizes the chart.

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Each model should be produced on a weekly basis to maximize net profit is $75,900.

What is Net profit?

In both business and accounting, net income or profit is an entity's revenue less cost of goods sold, costs, depreciation and amortisation, interest, and taxes for a certain accounting period.

As given,

Number of products sold:

T ≥ 1.5G

Maximize Profit Z = 150T + 130G

Labor Constraint:

Labor hours Available:

Production Department:

Number of labor hours available per day = 58 × 7 = 406

Number of days in a week = 5

Number of lobor ours available per week = 406 × 5 = 2030

Assembly Department:

Number of labor hours available per day = 25 × 7 = 175

Number of days in a week = 5

Number of labor hours available per week = 175 × 5 = 875.

Labor hours Required:

Labor hours required for G1 model:

Labor hours required at Production department = 3.5G

Labor hours required at assembly department = 2G

Labor hours required for T1 model:

Labor hours required at Production department = 4T

Labor hours required at Assembly department = 1.5T

Total labor hours required at Production department = 3.5G + 4T

Total labor hours required at Assembly department = 2G + 1.5T.

Constraint:

Labor hours required ≤ Labor hours Available.

Production department Labor constraint

3.5G + 4T ≤ 2030

Assembly department Labor constraint:

2G + 1.5T ≤ 875

The function:

Maximum Profit Z = 150T +130G

Constraint:

3.5G +4T ≤ 2030

2G + 1.5T ≤ 875

T ≥ 1.5G

Suppose that for example:

10.5G +12T = 6090

 16G + 12T = 7000

Solve both equations simultaneously,

5.5G = 7000 - 6090

5.5G = 910

    G = 910/5.5

    G = 363

Since, T > G

Hence,

T = 363,

G = 165

Calculate Profit:

150T + 130G = 150 × 363 + 130 × 165

                     = 54450 + 21450

                     = 75900

Hence, each model should be produced on a weekly basis to maximize net profit is $75,900.

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An appropriate theorem to show that the given set, W, is a vector space. A specific example can be

\(\left[\begin{array}{ccc}p\\q\\r\end{array}\right]\) , -p- -3q = s  and 3p = -2s - 3r

Sets represent values ​​that are not solutions. B. The set of all solutions of a system of homogeneous equations OC.

The set of solutions of a homogeneous equation. Thus the set W = Null A. The null space of n homogeneous linear equations in the mx n matrix A is a subspace of Rn. Equivalently, the set of all solutions of the unknown system Ax = 0 is a subspace of R.A.

The proof is complete because W is a subspace of R2. The given set W must be a vector space, since the subspaces are themselves vector spaces. B. The proof is complete because W is a subspace of R. The given set W must be a vector space, since the subspaces are themselves vector spaces.

The proof is complete because W is a subspace of R4. The given set W must be a vector space, since the subspaces are themselves vector spaces. outside diameter. The proof is complete because W is a subspace of R3. The given set W must be a vector space, since the subspaces are themselves vector spaces.

Let W be the set of all vectors of the right form, where a and b denote all real numbers. Give an example or explain why W is not a vector space. 8a + 3b -4 8a-7b. Select the correct option below and, if necessary, fill in the answer boxes to complete your selection OA. The set pressure is

S = {(comma separated vectors as required OB. W is not a vector space because zero vectors in W and scalar sums and multiples of most vectors are not in W because their second (intermediate) value is not equal to -4. OC. W is not a vector space because not all vectors U, V and win W have the properties

u +v =y+ u and (u + v)+w=u + (v +W).

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Let:

A = Annual income

M = Monthly income

N = Number of months in the year

So, the annual income will be given by the monthly income multiplied by the number of months:

Solve for M:

Divide both sides by 12:

Answer:

$2875

The probability that student chosen at random is 16 years is 0.28.

The table shows the distribution of student by age in a high school with 1500 students. Therefore, the probability that randomly chosen student is  16 years can be found as follows:

Therefore,

probability = number of favourable outcome to age / total number of possible outcome

Hence,

probability that student chosen at random is 16 years =  420 / 150

probability that student chosen at random is 16 years = 0.28

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We assume that G is a connected planar graph with no vertex of degree <= 5. We will use e <= 3v - 6 to prove that G is not a planar graph. By handshaking lemma, we know that 2e = sum of degrees of all vertices. Let d be the maximum degree of G.

Qa. Contrapositive of an implication is a new implication formed by negating both the hypothesis and the conclusion.

The contrapositive of the implication "If G is a connected planar graph, then G has at least one vertex of degree <= 5" is "If G has no vertex of degree <= 5, then G is not a connected planar graph."

Qb. Proof: We assume that G is a connected planar graph with no vertex of degree <= 5.

We will use e <= 3v - 6 to prove that G is not a planar graph. By handshaking lemma, we know that 2e = sum of degrees of all vertices.

Let d be the maximum degree of G. Since G has no vertex of degree <= 5, then d >= 6.

Thus, the sum of degrees of all vertices in G is greater than or equal to 6v/2, which is equal to 3v.

Hence, 2e >= 3v.

Substituting this inequality in e <= 3v - 6, we get 2e >= 3e - 6, which implies that e >= 6.

Since e >= 6, it follows that G is not planar.

Qc. Proof: We use proof by induction on the number of vertices of G. For a graph with one vertex, the statement is trivially true.

For a graph with n > 1 vertices, assume that every planar graph with at most n - 1 vertices can be colored with 6 (or less) colors.

Let G be a planar graph with n vertices.

By part (a), there exists a vertex v of G with degree <= 5.

We remove v and all its edges from G to get a new graph G' with n - 1 vertices.

By the induction hypothesis, we can color G' with 6 (or less) colors.

We add back v and its edges to G.

Since v has degree <= 5, at most 5 colors are used on its adjacent vertices.

We use a new color for v.

Thus, G can be colored with 6 (or less) colors.

Therefore, by induction, the statement is true for all planar graphs.

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Answer:

∠ RST = 68°

Step-by-step explanation:

Since RT = ST then the triangle is isosceles with 2 base angles congruent

∠ RST = \(\frac{180-44}{2}\) = \(\frac{136}{2}\) = 68°

File name: “TestClass.java” import java.util.Scanner; public class TestClass {

A recursive function is one that generates a series of terms by iterating over or using its foregoing terms as input. This function is typically understood in terms of an arithmetic-geometric series with terms that share similar differences.

File name: “TestClass.java”

import java.util.Scanner;

public class TestClass {

     //Define main() method

     public static void main(String[] args) {

           // Construct a Scanner object

           Scanner scr = new Scanner(System.in);

           //Ask the user to enter a decimal number

           System.out.print("Enter a decimal number: ");

           //Get the decimal number from the user

           int decinum = scr.nextInt();

           // Display the binary number

           System.out.println("The binary equivalent of the decimal value"

                 + decinum + " is " + dec2Bin(decinum));

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Answer:

-3

Step-by-step explanation:

-9 divided by +3 can be written as -9 divided by 3, because when you have a positive number, you don't have to write a plus sign in front of it. Next, we can just do 9/3 and then add the negative sign to the result to get our answer. 9 divided by 3 is equal to 3, and when you add the negative sign, you get -3.

Answer:

Line kinda flat, going up (from left to right) goes right through the 3 on the y-axis. Through the points (0,3) and (5,5) The third image.

Step-by-step explanation:

The slope of 2/5 means go UP2 and OVER5. Only one graph has a line the goes UP2 and OVER5.

One line actually goes down (from left to right), that has a negative slope. So that's not it.

The first image is positive slope, but if you look at the two points, you go UP5 and OVER2 so that is wrong also. That is the slope 5/2.

The last image has slope 2/7, bc you go UP2 OVER7 to get from one point to the next. It is wrong also.

Only the third image, Line kinda flat, going up (from left to right) goes right through the 3 on the y-axis. Through the points (0,3) and (5,5) has a slope of 2/5

Answer:

x=14 y=37

Step-by-step explanation:

The solution for the expression {8 ( 29 - 7 * 4 ) / ( 7 + 4 - 8 + 1 } - 3 ( 2 ) / 6 will be 1.

We are given the expression:

{8 ( 29 - 7 * 4 ) / ( 7 + 4 - 8 + 1 } - 3 ( 2 ) / 6

We will solve this expression by using the property of PEMDAS:

Solving the expression , we get

{8 (29 - 28) / 11 - 8 + 1} - 3 (2) / 6

= (8 × 1) / 4  -( 6 / 6)

= 2 - 1

= 1

Therefore, the solution for the expression {8 ( 29 - 7 * 4 ) / ( 7 + 4 - 8 + 1 } - 3 ( 2 ) / 6 will be 1.

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Answer:

it would be A

Step-by-step explanation:

places are capitalized, an the first letter of a sentence is always capitalized

The product rule must be used to find the number of strings of four decimal digits, that have exactly three digits that are 9s.

What is product rule ?

The Product Rule says that the derivative of a product of two functions is the first function times the derivative of the second function plus the second function times the derivative of the first function.

To obtain the number of strings of 4 decimal digits that have exactly 3 digits that are 9s ; we use the product rule,

In first digit 1 possible way between 0 to 9

In second digit 1 possible way between 0 to 9

In third digit 1 possible way between 0 to 9

In fourth digit 9 possible ways between 0 to 9

That's mean 1 * 1* 1* 9* 4 = 36

Thus 36 possible ways.

The product rule must be used to find the number of strings of four decimal digits.

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Answer:

c.) b = a - 5

Step-by-step explanation:

To know how to do it, just plug in a and b into the equations

Ex: 0 = 5-5

1 = 6-5

2 = 7-5

an example of a matrix A and a vector b such that the solution set of Ax=b is a line in R3 that does not contain the origin will be= 1 0 0 0 ,0 1 0 0 , 0 0 0 0]

\(AX = \left[\begin{array}{ccc}1&1&1\\1&2&3\\1&4&7\end{array}\right]\) \(\left[\begin{array}{ccc}x\\4\\2&\end{array}\right]\)

and b = \(\left[\begin{array}{ccc}6\\14\\30&\end{array}\right]\)

the augmented matrix is [A:B] = \(\left[\begin{array}{ccc}1&1&1\\1&2&3\\1&4&7\end{array}\right]\) \(\left[\begin{array}{ccc}6\\14\\30&\end{array}\right]\)

we shall reduced the augmented matrix [A;B] to echelon form by applying elementary row transformation only.

operating  \(R_{2} , R_{2} - R_{1} , R_{3} ,R_{3} -R_{1}\)

\([A:B] = \left[\begin{array}{ccc}1&1&1\\0&1&2\\0&3&6\end{array}\right]\) \(\left[\begin{array}{ccc}6\\8\\24&\end{array}\right]\)

operating \(R_{3} , R_{3} - 3R_{2}\)

      ≈ \(\left[\begin{array}{ccc}1&1&1\\0&1&2\\0&0&0\end{array}\right]\) \(\left[\begin{array}{ccc}6\\8\\0&\end{array}\right]\)

which is the row echelon form of the matrix [A:B].

A matrix that has gone through the Gaussian end is supposed to be in column echelon form or, all the more appropriately, "decreased echelon form" or "line diminished echelon form." Such a matrix has the accompanying qualities:

1. Every one of the zero columns are at the lower part of the matrix

2. The main passage of each nonzero column after the first happens to one side of the main section of the past line.

3. The main passage in any nonzero column is 1.

4. All sections in the segment above and under a main 1 are zero.

One more typical meaning of echelon form just requires zeros beneath the main ones, while the above definition additionally requires them over the main ones.

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First, let's find the total cost of all the apples:

Now, we divide this by the total amount of apples bought. In our case, we know that there were 10 Granny Smith apples and 15 Golden Delicious, for a total of 25 apples.

Therfore, we can conclude that the average cost per apple was $0.68

The numbers would have to be added to complete the square is x = \(\frac{9+\sqrt{185} }{2}\) and x = \(\frac{9-\sqrt{185} }{2}\)

The quadratic equation is

\(x^2\) - 9x - 26 = 0

Add both side of the equation by 26

\(x^2\) - 9x - 26 + 26 = 26

\(x^2\) - 9x = 26

\(x^2\)  - 2(9/2)x = 26

Take the coefficient of x and take square of the term and add both side of the equation

\(x^2\)  - 2(9/2)x + 81/4 = 81/4 + 26

Add the terms

\(x^2\)  - 2(9/2)x + 81/4 = 185/4

Form the left side of the equation in the form of \((a-b)^2\)

Then the equation will be

\((x-\frac{9}{2} )^2\) = 185/4

x - 9/2 =± \(\frac{\sqrt{185} }{2}\)

x =  \(\frac{\sqrt{185} }{2}\) +  9/2

x = \(\frac{9+\sqrt{185} }{2}\)

Then

x = - \(\frac{\sqrt{185} }{2}\) +  9/2

x = \(\frac{9-\sqrt{185} }{2}\)

Hence, the numbers would have to be added to complete the square is x = \(\frac{9+\sqrt{185} }{2}\) and x = \(\frac{9-\sqrt{185} }{2}\)

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The width of the rectangle is 9 meter.

Now, According to the question:

The perimeter of a rectangle is defined as the sum of all the sides of a rectangle. For any polygon, the perimeter formulas are the total distance around its sides. In case of a rectangle, the opposite sides of a rectangle are equal and so, the perimeter will be twice the width of the rectangle plus twice the length of the rectangle and it is denoted by the alphabet “p”.

Now, Solving the problem:

Perimeter of rectangle is 50 meter sq.

Length of the rectangle(L) is 16 meter.

We have to find the width (W) of the rectangle.

We know that,

Perimeter of rectangle is = 2 (L + W)

50 = 2(16 + W)

50 = 32 + 2W

2W = 50 - 32

2W = 18

W = 18/2

W = 9

Hence, The width of the rectangle is 9 meter.

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Answer:

Nope.  It would take 32 and 4/13 minutes, which is longer than 30 min.

Step-by-step explanation:

The distance is 35 miles and the speed 65 miles/hour

Dividie the distance by the speed to obtian the time required,

(35 miles)/(65 miles/hour) = 0.538 hours

No, 35 miles at the speed limit of 65 mph would require 0.538 hours, 0.038 hours more than 1/2 hour.  2 and 4/13 minutes more than 30 minutes.

Answer:

20^4

Step-by-step explanation:

2^4x10^4=160000

20^4=160000

Step-by-step explanation:

let eqn be y - y1 = m(x - x1)

m = (9 - 1)/(-3 - (-7))

m = 2

sub (-7, 1):

y - 1 = 2(x + 7)

therefore, the equation is y - 1 = 2(x + 7)

Topic: coordinate geometry

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Answer:

x<2

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Given

56 - 10x > 20 + 8x ( add 10x to both sides )

56 > 20 + 18x ( subtract 20 from both sides )

36 > 18x ( divide both sides by 18 )

2 > x , thus

x < 2 → D

Answer:

7

Step-by-step explanation:

√50 is close to √49

49 is a perfect square, 50 is close to 49.

√49 = 7

√50 ≈ 7.071068

Answer:

7

Step-by-step explanation:

\(\sqrt{50} =7.07\)

Hope this helps  

Answer:

930 in^2

Step-by-step explanation:

Area of a parallelogram is Base x Height.

so, 30 x 31 = 930.

Answer: 930 in ^2

Step-by-step explanation:

Area is width x height.

Width = 30

Height = 31

30x31 = 930

Answer:

okay but what is should we help u with

Answer:

Hi, you did not ask a question sooo I can’t really help you because there is no question or picture. I hope you managed to get right whatever you needed help with!

Step-by-step explanation:

Also it’s only 50 points that I got.