Use the net to find the surface area of the regular pyramid. I’ll mark brainliest if correct

The store clerk is stocking the shelves. He places on the shelf a box of cereal that weighs 850 grams, a box of granola bars that weighs 385 grams, and a box of crackers that weighs 435 grams. The total weight in kilograms is 1.67 kilograms.

Given:

The weight of the box of cereal = 850 grams.

The weight of the box of granola bars = 385 grams.

The weight of the box of crackers = 435 grams.

The total weight in kilograms of the above boxes.

Total weight of the boxes = 850 + 385 + 435 grams= 1670 grams.

To convert grams to kilograms, we divide it by 1000.

So, the weight in kilograms= 1670/1000= 1.67 kilograms.

Hence, the total weight in kilograms of the above boxes is 1.67 kilograms.

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The error involved in approximating the sum of the given series by the sum of the first five terms of the series is `R5 = 1/6³ + 1/7³ + ...`.

To estimate the error that is made by approximating the sum of the given series by the series the first 5 terms 1/k³, we can use the remainder term of a convergent series.

The given series is ∑ 1/k³ from k = 1 to infinity.We have to find the error involved in approximating the sum of the given series by the sum of the first five terms of the series.

That is, we need to find the difference between the actual sum of the series and the sum of the first five terms of the series.

The sum of the series is given by: `S = 1/1³ + 1/2³ + 1/3³ + 1/4³ + ... + 1/n³ + ...` We can use the remainder term of the series to find the error in approximation.

The remainder term `Rn` is given by: `Rn = Sn - S` where `Sn` is the sum of the first `n` terms of the series. Thus, we have to find the remainder term for `n = 5`.

The remainder term `Rn` is given by: `Rn = S - Sn = 1/6³ + 1/7³ + ...` Since the given series is convergent, the remainder term `Rn` tends to zero as `n` tends to infinity.

So, if we take the sum of the first five terms of the series, the error involved in approximation is given by the remainder term `R5`.

The error involved in this approximation is very small and can be neglected.

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Answer:

2.025, 2.25, 2.2582, 2.4

Step-by-step explanation:

The combined height of the flower pot and the shelf is 345 cm

Given the height of the flower pot is 85 cm and the height of the shelf is 260 cm, we are to find the combined height of the flower pot and shelf.

To find the combined height, we need to add the height of the flower pot and the height of the shelf.

So, Combined height of flower pot and shelf = Height of the flower pot + Height of the shelf Combined height of flower pot and shelf = 85 cm + 260 cm

Combined height of flower pot and shelf = 345 cm

Therefore, the combined height of the flower pot and the shelf is 345 cm.

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The point P is (9, 2, 12).

To find the point P, we need to add the vector v = PQ to the given point 0.

Given that v = PQ has the components (7, 6, 9) and the point 0 has the components (2, -4, 3), we can calculate the coordinates of point P as follows:

P = 0 + v = (2 + 7, -4 + 6, 3 + 9) = (9, 2, 12)

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Answer:

2 cube into 3 into 5 into 13 into 7

The Car journey from Lagos to Abuja took approximately 10 hours and 22 minutes.

The time taken for the car journey from Lagos to Abuja, we need to calculate the time difference between the departure time and the arrival time, taking into account any time zone differences.

First, let's convert the departure time from 16:39 to 24-hour format: 16:39 is the same as 4:39 PM in 12-hour format, and 16:39 in 24-hour format.

Next, we need to convert the arrival time from 03:01 to 24-hour format: 03:01 is the same as 3:01 AM in 12-hour format, and 03:01 in 24-hour format.

Now we can calculate the time difference between the departure time and the arrival time, taking into account any time zone differences.

The journey time is the difference between the arrival time and departure time, but we also need to take into account that the journey is overnight, which means we need to add 24 hours to the arrival time to account for the change in date.

Therefore, the total journey time is:

Arrival time (in minutes) = (3 x 60) + 1 = 181 minutes

Departure time (in minutes) = (16 x 60) + 39 = 999 minutes

Total journey time = (181 + 1440) - 999 = 622 minutes

Finally, we can convert the journey time from minutes to hours and minutes:

Total journey time in hours = 622 / 60 = 10.37 hours (rounded to two decimal places)

So the journey took approximately 10 hours and 22 minutes (rounded to the nearest minute).

Therefore, the car journey from Lagos to Abuja took approximately 10 hours and 22 minutes.

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The remaining solutions of the cubic equation x^3 + 2x^2 - 11x - 12 = 0 with one root -4 is x= 3 and x=-1 (Option c)

To find the roots of the cubic equation x^3 + 2x^2 - 11x - 12 = 0 other than -4 ,

Perform polynomial division or synthetic division using -4 as the divisor,

        -4 |  1   2   -11   -12

            |     -4      8      12

        -------------------------------

           1  -2   -3      0

The quotient is x^2 - 2x - 3.

By setting the quotient equal to zero and solve for x,

x^2 - 2x - 3 = 0.

Factorizing the quadratic equation using the quadratic formula to find the remaining solutions, we get,

(x - 3)(x + 1) = 0.

Set each factor equal to zero and solve for x,

x - 3 = 0 gives x = 3.

x + 1 = 0 gives x = -1.

Therefore, the remaining solutions are x = 3 and x = -1.

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Answer:

The x axis is horizontal, the y axis is vertical.

Step-by-step explanation:

If you look at it on a plane, the x axis runs horizontally and the y axis runs vertically.

Answer:

The x axis is horizontal and the y is vertical

Step-by-step explanation:

:)

Answer:

0

8

10

Then make thoes ordered pairs so;

(0,0)

(4,8)

(5,10)

Answer:

0,8,10 i think you plug in 0 for x and do the same for the

others

Answer:(2x+3)(2x+3)

Step-by-step explanation:

Question will be like this Factorize the following polynomial.

4x\({2}\) +12x +9

4x\(2\) +6x+6x+9

⇒2x(2x+3)+3(2x+3)

⇒(2x+3)(2x+3)

To learn more about managerial turnover, additional data should be gathered, including employee demographics, job satisfaction surveys, performance metrics, and exit interview data.

To gain deeper insights into managerial turnover, several additional data points should be collected. Firstly, employee demographics such as age, gender, educational background, and tenure can provide valuable information about turnover patterns and potential disparities. Analyzing turnover rates among different demographic groups can help identify any systemic issues or biases that may contribute to turnover.

Secondly, conducting regular job satisfaction surveys can help gauge employees' perceptions of their roles, work environment, and job-related factors. This data can shed light on the factors that influence managerial turnover, such as job dissatisfaction, lack of growth opportunities, inadequate compensation, or poor work-life balance.

Thirdly, tracking the performance metrics of managers can provide insights into the relationship between performance and turnover. Assessing metrics like performance evaluations, sales figures, customer satisfaction ratings, and team productivity can help determine whether managerial performance plays a role in turnover rates.

Lastly, analyzing data from exit interviews can be invaluable. Exit interviews allow departing managers to provide feedback on their reasons for leaving, including factors like organizational culture, leadership effectiveness, communication issues, or lack of support. This qualitative data can offer valuable insights into the specific reasons behind managerial turnover and help identify areas for improvement within the organization.

By gathering these additional data points, organizations can gain a more comprehensive understanding of managerial turnover and develop targeted strategies to address the underlying causes, improve retention, and create a more supportive and engaging work environment.

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Answer: 21

Step-by-step explanation:

Answer:

I couldn't

The ones I used to be friends with now all hate me lol ;-;

Step-by-step explanation:

Answer:

Qué es la pregunta

La opción correcta es el menor de todos es E. opción C

Veamos partes por partes lo que tenemos:

1. A es mayor que B: entonces se escribe A > B

2. C es menor que D: entonces se escribe C < D

3. E es menor que C: entonces se escribe E < C

4. B es mayor que D: entonces se escribe B > D

5. Unimos 1 y 2: A > B  > D

6. Unimos 5 y 2: A > B  > D > C

7. Unimos 6 y 3: A > B  > D > C > E

B es el menor de todos: falso, D, C, E son menores que B, D es el menor de todos falso, C y E son menores que D, E es el menor de todos verdadero, D es menor que C falso D es mayor que C.

The average change in the volume of water per day is obtained as 0.625  litres.

The rate change of volume is the change of volume with respect to time.

For instantaneous change the derivative of the expression of volume can be taken.

The average change in the volume of water can be obtained as follows,

Average change = Volume of water ÷ Number of days

                            = 2.5 ÷ 4 = 0.625

Hence, the average change in water volume is given as  0.625 liters per day.

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Answer:

127+(-112)=15

Step-by-step explanation:

If you subtract 112 from 127, you can find the difference. Since 112 is Mya's weight, and the total is 127, we need to find out how much weight is left over after we take away Mya's weight, which would be the cat's weight. So if you follow the expression, which is 127+(-112), you would get a sum of 15 pounds. Since this is an addition problem, the expression would be 127+(-112) instead of 127-112. I hope you understand. The difference between 127 and 112 is the cat's weight, so the cat weighs 15 pounds.

\(f(x) = 2 {x}^{2} + 2x - 24 \)

\(f(x) = 2( {x}^{2} + x - 12) \)

\(0 = 2( {x}^{2} + x - 12)\)

Divided sides by 2

\( {x}^{2} + x - 12 = 0 \)

\((x + 4)(x - 3) = 0\)

_________________________________

\(x + 4 = 0\)

\(x = - 4\)

_________________________________

\(x - 3 = 0\)

\(x = 3\)

Thus the actual roots are -4 and 3.....

And we're done.

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Answer:

x= 3, -4

Step-by-step explanation:

Set  2 x ² +  2 x  −  24  equal to  0 .

   2 x   ² +  2 x  −  24  =  0

Solve for  x .

Factor the left side of the equation.

2 ( x²   +  x  −  12 )  =  0

Factor  

x  ² +  x  − 12  using the AC method.

2 ( x  −  3 ) ( x  +  4 )  =  0

If any individual factor on the left side of the equation is equal to  0 , the entire expression will be equal to  0 .

x − 3 = 0

x + 4 = 0

Add  3  and subtract 4 to both sides of the equation.

x = 3

x = -4

The polar equation r = 2 sin θ is equivalent to the rectangular equation y = x tan θ.

The polar equation is r=2sinθ. To convert it into rectangular form, we can use the identities x = r cos θ and y = r sin θ.

Replacing r with 2 sin θ, we get x = 2 cos θ sin θ and y = 2 sin^2 θ. Simplifying these expressions using the identity sin^2 θ + cos^2 θ = 1, we get the rectangular equation y = x sin θ / cos θ, which can also be written as y = x tan θ.

Thus, the polar equation r = 2 sin θ is equivalent to the rectangular equation y = x tan θ.

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The inverse Laplace transforms of the given functions are as follows: 5. \( F_{1}(s)=\frac{1}{s^{2}(s+1)} \) has the inverse Laplace transform \( f_{1}(t) = t - e^{-t} \). 6. \( F_{2}(s)=\frac{39}{(s+2)^{2}\left(s^{2}+4 s+13\right)} \) has the inverse Laplace transform \( f_{2}(t) = \frac{13}{\sqrt{11}} e^{-2t} \sin(\sqrt{11}t) \). 7. \( F_{3}(s)=\frac{3 e^{-s}}{s(s+3)} \) has the inverse Laplace transform \( f_{3}(t) = 3(1 - e^{-3t}) \).

5. To find the inverse Laplace transform of \( F_{1}(s)=\frac{1}{s^{2}(s+1)} \), we observe that the given function can be expressed as the sum of partial fractions: \( F_{1}(s) = \frac{A}{s} + \frac{B}{s^2} + \frac{C}{s+1} \). Solving for A, B, and C, we obtain A = 1, B = -1, and C = -1. Taking the inverse Laplace transform of each term, we get \( f_{1}(t) = t - e^{-t} \).

6. For \( F_{2}(s)=\frac{39}{(s+2)^{2}\left(s^{2}+4 s+13\right)} \), we can rewrite it as a sum of partial fractions: \( F_{2}(s) = \frac{A}{s+2} + \frac{B}{(s+2)^2} + \frac{Cs+D}{s^2+4s+13} \). Solving for A, B, C, and D, we find A = -\frac{13}{\sqrt{11}}, B = \frac{26}{\sqrt{11}}, C = \frac{3}{\sqrt{11}}, and D = 0. Taking the inverse Laplace transform, we get \( f_{2}(t) = \frac{13}{\sqrt{11}} e^{-2t} \sin(\sqrt{11}t) \).

7. Finally, for \( F_{3}(s)=\frac{3 e^{-s}}{s(s+3)} \), we can simplify it as \( F_{3}(s) = \frac{A}{s} + \frac{B}{s+3} \), where A = 3 and B = -3. Taking the inverse Laplace transform, we obtain \( f_{3}(t) = 3(1 - e^{-3t}) \).

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Answer:

7 or 6

Step-by-step explanation:

The slope of the tangent line to the polar curve r = 2 - sin(θ) at the point specified by θ = π/3 is -1/2.

To find the slope of the tangent line to the polar curve r = 2 - sin(θ) at the point specified by θ = π/3, we need to first find the derivative of r with respect to θ, and then evaluate it at θ = π/3.

Differentiating both sides of the polar equation with respect to θ, we get:

dr/dθ = d/dθ(2 - sinθ)

dr/dθ = -cosθ

So, the derivative of r with respect to θ is -cosθ.

Evaluating this derivative at θ = π/3, we get:

dr/dθ|θ=π/3 = -cos(π/3) = -1/2

Therefore, the slope of the tangent line to the polar curve r = 2 - sin(θ) at the point specified by θ = π/3 is -1/2.

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Answer:

Step-by-step explanation:he amount of simple interest earned on an investment can be determined ... For example, for an annual interest rate of 5% compounded monthly, ... Rank these rates from greatest to least return on an investment of $20000 for a term of 2 years. ... savings account and invested the entire amount in a 10 year GIC that earned ...

Given:

The given vector is:

\(v=9i-6j\)

To find:

The unit vector in the direction of the given vector.

Solution:

If a vector is \(v=ai+bj\), then the unit vector in the direction of the this vector is

\(\hat v=\dfrac{v}{|v|}\)

Where, \(|v|=\sqrt{a^2+b^2\)

We have,

\(v=9i-6j\)

Here, \(a=9\) and \(b=-6\). So,

\(|v|=\sqrt{9^2+(-6)^2}\)

\(|v|=\sqrt{81+36}\)

\(|v|=\sqrt{117}\)

\(|v|=3\sqrt{13}\)

Now, the unit vector in the direction of the given vector is:

\(\hat v=\dfrac{9i-6j}{3\sqrt{13}}\)

\(\hat v=\dfrac{9i}{3\sqrt{13}}-\dfrac{6j}{3\sqrt{13}}\)

\(\hat v=\dfrac{3}{\sqrt{13}}i-\dfrac{2}{\sqrt{13}}j\)

Therefore, the required unit vector is \(\hat v=\dfrac{3}{\sqrt{13}}i-\dfrac{2}{\sqrt{13}}j\).

Answer:

B

There is no friction

Step-by-step explanation:

if the object is stationary , it's not moving, no forces acting on it how can it produces friction ?

Answer:

sin 105 = sin (45 + 60) = sin 45 cos 60 + cos 45 sin 60, or

                                    = (1 / √2)(1 / 2)        + (1 / √2)(√3 / 2)

                                         1 + √3

                                    = -------------

                                           2√2

Step-by-step explanation:

Answer:

Well 40.21/12.5=3.217 so it is about $3.22 per sqr ft.

Step-by-step explanation:

Answer:

13(2b-1)

Step-by-step explanation:

Both have the factor 13.

13(2b-1)

The probability that the mean is going to have to differ from the mean of this population by more than 2.9 kg is given as 0.0142

We have the following values to solve the problem with

mean = 75

σ² = 144

σ = 12

n = 103

the probability that is required can be gotten by getting the following interval

= 75 - 2.9 and 75 + 2.9

= 1 - P (72.1 <x< 77.9)

Then we would have for the lower limit

\(\frac{72.1 -75}{12/\sqrt{103} }\)

= -2.45

For the upper limit we would have

\(\frac{77.9 -75}{12/\sqrt{103} }\)

= 2.45

we would have

1 - P(-2.45 < z < 2.45)

using the standard normal table we would have

z < 2.45 = 0.9929

z < -2.45 = 0.0071

Then the probability would be 1 - (0.9929 - 0.0071)

= 1 - 0.9858

= 0.0142

Therefore the probability that the sample mean would differ by 2.9 kg is given as 0.0142 or 1.42%

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