The new conditional statement that follows from the given pair of true statements is: "If BD bisects ∠ABC, then m∠ABD = 1/2(m∠ABC)".
The Law of Syllogism states that if we have two conditional statements "if A then B" and "if B then C" that are both true, then we can combine them to form a new conditional statement "if A then C".
Using the Law of Syllogism, we can combine the given statements to form a new conditional statement,
If BD bisects ∠ABC, then m∠ABD = 1/2(m∠ABC).
To see why this is true, let's break down the logic:
Statement 1: If BD bisects ∠ABC, then ∠ABD ≅ ∠CBD (given)
Statement 2: If ∠ABD ≅ ∠CBD, then m∠ABD = 1/2(m∠ABC) (given)
Conclusion: If BD bisects ∠ABC, then m∠ABD = 1/2(m∠ABC) (Law of Syllogism)
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How do I solve this? I’m so confused..
Answer:divide the numbers
Step-by-step explanation:
HURRYYY please pleaseee
Write an equation of the line through (-3,- 6) having slope17/16Give the answer in standard form.The equation of the line is
The equation of a line in Standard form is:
\(Ax+By=C\)Where "A", "B" and "C" are Integers ("A" is positive).
The Slope-Intercept form of the equation of a line is:
\(y=mx+b\)Where "m" is the slope and "b" is the y-intercept.
In this case you know that:
\(m=\frac{17}{16}\)And knowing that the line passes through the point
\(\mleft(-3,-6\mright)\)You can substitute values and solve for "b":
\(\begin{gathered} y=mx+b \\ -6=(\frac{17}{16})(-3)+b \\ \\ \\ -6=-\frac{51}{16}+b \\ \\ -6=-\frac{51}{16}+b \\ \\ -6+\frac{51}{16}=b \\ \\ b=-\frac{45}{16} \end{gathered}\)Then, the equation of this line in Slope-Intercept form is:
\(y=\frac{17}{16}x-\frac{45}{16}\)Now that you have this equation, you can write it in Standard form as following:
\(\begin{gathered} y+\frac{45}{16}=\frac{17}{16}x \\ \\ \frac{45}{16}=\frac{17}{16}x-y \\ \\ \frac{17}{16}x-y=\frac{45}{16} \end{gathered}\)The answer is:
\(\frac{17}{16}x-y=\frac{45}{16}\)The price of a dress is reduced by 17% in a sale. The sale price is £45.65. What was the original price of the dress?
Answer:
\(\Huge \boxed{\£55}\)
________________________________________________________
A 17% reduction means that the dress cost 83% (100 - 17) of the original amount.
Unitary Method\(\large \fbox{\begin{minipage}{8.1 cm}83\% of the original price = \£45.65\\\\$\Rightarrow$1\% of the original price = $\frac{45.65}{83}$\\\\$\Rightarrow$1\% of the original price = 0.55\\\\$\Rightarrow$100\% of the original price = 0.55 \times 100\\\\$\Rightarrow$100\% \text{ of the original price = \£55}\end{minipage}}\)
Inverse operationTo work out 83% of the original price, you multiply by 0.83. We can do the inverse, which is dividing by 0.83.
×0.83
Original Price →→→→→→→→→→→→→ Sale Price
£? ←←←←←←←←←←←←← £45.65
÷0.83
\(\large \boxed{\begin{minipage}{7 cm}Original Price = $\frac{\text{Sale Price}}{0.83}$\\\\$\Rightarrow$Original Price = $\frac{45.65}{0.83}$\\\\$\Rightarrow$Original Price = \£55\end{minipage}}\)
Therefore, the original price of the dress is £55.
________________________________________________________
If x is the number of bags of M&Ms bought at $3 per bag, and y is the number of bags of Kit Kats
bought at $4 per bag, which expression represents the total amount spent on M&Ms and Kit Kats?
Answer:
3x+4y
Step-by-step explanation:
If you buy 2 M&Ms, you would get $6. Plugging in 2 for x would indeed give us 6, which makes sense.
If you buy 2 KitKats, you would get $8. Plugging in 2 for y would indeed give us 8, which makes sense.
Therefore, we can plug in x and y for the unknowns and add them together to find the total amount spent on both candies.
PLEASE ANSWER ASAP!!!!!!!!!!!!!
Hey there! :)
Answer:
m∠LOM = 44°
Step-by-step explanation:
OL ⊥ ON, therefore:
m∠LOM + m∠MON = 90°.
Solve:
3x + 38 + 9x + 28 = 90°
Combine like terms:
12x + 66 = 90°
Subtract both sides by 66:
12x = 24°
x = 2°
Plug in x into the equation for m∠LOM:
m∠LOM = 3(2) + 38
m∠LOM = 6 + 38
m∠LOM = 44°
Answer:
44
Step-by-step explanation:
Angle MON + angles LOM = 90
So, 3x + 38 + 9x + 28 = 90
12x + 66 = 90
12x = 24
x = 12
So, LOM = 3x + 38(substitute) = 44
Hope this helps
The distribution of random variable r has mean 10 and standard deviation 4. The distribution of random variable s has mean 7 and standard deviation 3. If r and s are independent, what are the mean and standard deviation of the distribution of r−s ?.
If \(X,Y\) are independent, we have the properties for expectation and variance,
\(\Bbb E[aX + bY] = a\,\Bbb E[X] + b\,\Bbb E[Y]\)
\(\Bbb V[aX + bY] = a^2\,\Bbb V[X] + b^2\,\Bbb V[Y]\)
where \(a,b\in\Bbb R\) are fixed.
Then
\(\Bbb E[R - S] = \Bbb E[R] - \Bbb E[S] = 10 - 7 = \boxed{3}\)
and
\(\Bbb V[R - S] = \Bbb V[R] + (-1)^2\, \Bbb V[S] = 4^2 + 3^2 = \boxed{5}\,{}^2 = 25\)
(recall that standard deviation = √(variance))
Solve -2/3x > 8 or -2/3x -12 or x -6} 3. {x | -12 < x < -6}
what is the equation of a circle with center (2,-3) and radius 3?
Answer: The answer is A
Step-by-step explanation:
Equation of a circle: (x-a)^2+(y-b)^2=r^2, where a and b are the coordinates of a center, r - radius
So, you have (2,-3) as a center, and radius r is 3.
Then, your equation is (x-2)^2+(y+3)^2=9
the equation of a circle with center at (h,k) and radius of r is
(x-h)^2+(y-k)^2=r^2
so
(2,-3) and radius is 3
(x-2)^2+(y-(-3))^2=3^2
(x-2)^2+(y+3)^2=9
Jordan works for a landscape company during his summer vacation. He is paid $12 per hour for mowing lawns and $14 per hour for planting gardens. He can work a maximum of 40 hours per week, and would like to earn at least $250 this week. If m represents the number of hours mowing lawns and g represents the number of hours planting gardens, which system of inequalities could be used to represent the given conditions?
Answer:
m+g\(\leq\)40
12m + 14g\(\geq\)250
Step-by-step explanation:
Jordan is paid $12 per hour for mowing lawns and $14 per hour for planting gardens.
Let m represents the number of hours mowing lawns and g represents the number of hours planting gardens.
He can work a maximum of 40 hours per week, and would like to earn at least $250 this week.
Then, the system of the inequality becomes
m+g\(\leq\)40
12m + 14g\(\geq\)250
1) Explain the problem of unit root in standard regression and in time-series models and Explain how to use the Dickey-Fuller and augmented Dickey-Fuller tests to detect this. In clearly and detailed . Kindly type your answers . Course Econometrics
The problem of unit root in standard regression and time-series models arises when a variable exhibits a non-stationary behavior, meaning it has a trend or follows a random walk. Unit root tests, such as the Dickey-Fuller and augmented Dickey-Fuller tests, are used to detect the presence of a unit root in a time series. These tests examine whether the coefficient on the lagged value of the variable is significantly different from one, indicating the presence of a unit root.
In standard regression analysis, it is typically assumed that the variables are stationary, meaning they have a constant mean and variance over time. However, many economic and financial variables exhibit non-stationary behavior, where their values are not centered around a fixed mean but instead follow a trend or random walk. This presents a problem because standard regression techniques may produce unreliable results when applied to non-stationary variables.
Time-series models, such as autoregressive integrated moving average (ARIMA) models, are specifically designed to handle non-stationary data. They incorporate differencing techniques to transform the data into a stationary form, allowing for reliable estimation and inference. Differencing involves computing the difference between consecutive observations to remove the trend or random walk component.
The Dickey-Fuller test and augmented Dickey-Fuller test are commonly used to detect the presence of a unit root in a time series. These tests examine the coefficient on the lagged value of the variable in a regression framework. The null hypothesis of the tests is that the variable has a unit root, indicating non-stationarity, while the alternative hypothesis is that the variable is stationary.
The Dickey-Fuller test is a simple version of the test that includes only a single lagged difference of the variable in the regression. The augmented Dickey-Fuller test extends this by including multiple lagged differences to account for potential serial correlation in the data. Both tests provide critical values that can be compared to the test statistic to determine whether the null hypothesis of a unit root can be rejected.
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Which graph does not represent a function?
Answer:
the full circle one
Step-by-step explanation:
use the vertical line test. Hold up a pen on any given spot in the graph (the pen has to be vertical) and if it goes through the line in 2 or more different places its not a function
$60 invested at 7% compounded continuously after a period of 2 years, after 2 years the investment results in?
Answer: 8.40 dollars worth of intrest
Step-by-step explanation:
Which set of ordered pairs represents a function? \{(2, 9), (5, 9), (1, -6), (-5, 5)\}{(2,9),(5,9),(1,−6),(−5,5)} \{(6, 6), (6, 8), (-8, -7), (-3, -8)\}{(6,6),(6,8),(−8,−7),(−3,−8)} \{(1, 8), (9, -3), (7, -4), (7, -6)\}{(1,8),(9,−3),(7,−4),(7,−6)} \{(-5, -1), (-3, -7), (-5, 3), (-7, -4)\}{(−5,−1),(−3,−7),(−5,3),(−7,−4)}
Given:
The set of ordered pairs.
To find:
Which set of ordered pairs represents a function?
Solution:
A set of ordered pairs represents a function, if there exist unique output value for each input value.
In option A,
{(2, 9), (5, 9), (1, -6), (-5, 5)}
It is a function because all input has unique outputs.
In option B,
{(6, 6), (6, 8), (-8, -7), (-3, -8)}
For x=6, there exist two outputs y=6 and y=8. So, it is not a function.
In option C,
{(1, 8), (9, -3), (7, -4), (7, -6)}
For x=7, there exist two outputs y=-4 and y=-6. So, it is not a function.
In option D,
{(-5, -1), (-3, -7), (-5, 3), (-7, -4)}
For x=-5, there exist two outputs y=-1 and y=3. So, it is not a function.
Therefore, the correct option is A.
From the given option, the set of ordered pairs that represents a function is {(2, 9), (5, 9), (1, -6), (-5, 5)\}
Ordered pair of a functionA coordinate is known to represents a function if all the domain values have a unique value in the codomain.
The x-coordinate point should not be repeated for the coordinate to be a function, otherwise it is not a function.
From the given option, the set of ordered pairs that represents a function is {(2, 9), (5, 9), (1, -6), (-5, 5)\}
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beyond struggling pls help
FIND THE FOLLOWING MEASUREMENTS
Check the picture below.
well, ∡CED is the same as ∡CEA and those are right-angles so those are pretty much given, now
\(\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ a^2+o^2=c^2\implies o=\sqrt{c^2 - a^2} \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{29}\\ a=\stackrel{adjacent}{20}\\ o=\stackrel{opposite}{CE} \end{cases} \\\\\\ CE=\sqrt{ 29^2 - 20^2}\implies CE=\sqrt{ 841 - 400 } \implies CE=\sqrt{ 441 }\implies \boxed{CE=21} \\\\\\ \stackrel{\textit{since we know the radius CB=29}}{CB-CE = EB\implies }\boxed{EB=8}\)
Answer:
angle CED 90°. CE = 21. EB = 8.
Step-by-step explanation:
angle CED = 90° (right angle).
the radius (centre to edge) is the same right around the circle.
so that means that distance CD = 29.
draw a line from C to D. notice how that has just become an hypotenuse?
we know that DE = 20.
we have a right-angled triangle.
CE² = hypot² - DE²
= 29² - 20²
= 841 - 400
= 441
CE = √441 = 21.
EB must be radius subtract CE. that is, 29 - 21 = 8.
Which of the following values are in the range of the function graphed below? Check all that apply.
Given:
The graph of a function.
To find:
The range of the function.
Solution:
Domain is the set of input values for which the function is defined.
Range is the set of output values or y-values.
From the given graph it is clear that the function is defined between -2 and 1.
The graph of the function is a horizontal line and it gives the value 1 for each input between -2 and 1.
It means the range of the graphed function is 1.
Therefore, the correct option is C.
Answer:1
Step-by-step explanation:
Sorry, I feel so dumb but the x in 18x2 is not a variable right?
Answer:
32
Step-by-step explanation:
the x is not a variable
Slove for x ,
:2x + 3=11 ??
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\(2x + 3 = 11\)
Subtract sides 3
\(2x + 3 - 3 = 11 - 3\)
\(2x = 8\)
Divide sides by 2
\( \frac{2}{2} x = \frac{8}{2} \\ \)
\(x = 4\)
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Is 7 a A is a binomial?
The expression 7a+a is not a binomial. It is a monomial.
What is monomial and binomial?Monomial: The term "monomial" refers to algebraic expressions with only one term. In other words, it is a statement that includes any number of terms that are similar. For instance, 3x + 9x + 2x is a monomial because it equals 14x when the like terms are added.Binomial: The term "Binomial" refers to algebraic statements with two dissimilar terms. For instance, 2x + 6x^2 is a binomial expression because it combines the two dissimilar terms 2x and 6x^2.The expression 7×a+a can be expressed as 7a + a which is equal to 8a, and thus has only one term.
Hence, the expression is a monomial and not a binomial.
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complete Question-
Is 7a+a a binomial?
katie wants to buy a sundress priced at $40.00. if the sales tax is 6% what is the toyal amount she must pay for the sundress?
katie wants to buy a sundress priced at $40.00. if the sales tax is 6% what is the toyal amount she must pay for the sundress?
we know that
100%+6%=106%=106/100=1.06
so
Multiply $40.00 by 1.06
total amount=40.00*1.06=$42.40
Problem N 2
the brown's bill at a restaurant is 60.00 how much money should mr.brown leave as a tip if he plans to tip 15%
we know that
15%=15/100=0.15
Multiply 60.00 by 0.15
so
amount tip=60*0.15=$9.00now that
15%=
The Pressure in the bulb of a constant volume gas thermometer 82cm at 0degree 105.2 cm at loo°c and 68.4cm. When the bulb is surrounded by solid Carbon(iv ) oxide calculate the temperature of the Carbon (iv )
Oxide
The temperature of the Carbon (IV) Oxide surrounding the thermometer is approximately -46.83 °C (226.32 K).
What is the temperature of the Carbon (IV) Oxide?We can use Charles's Law and Boyle's Law to relate the pressure of the gas in the thermometer to the temperature of the surrounding Carbon (IV) Oxide. Since the volume of the gas in the thermometer is constant, we can assume that the pressure is directly proportional to the absolute temperature.
Therefore, we can use the following equation:
P₁/T₁ = P₂/T₂
where;
P₁ and T₁ are the pressure and temperature at the first measurement (0 °C), and P₂ and T₂ are the pressure and temperature at the second measurement (100 °C).Solving for T₂, we get:
T₂ = (P₂/P₁) * T₁
T₂ = (105.2/82) * 273.15 K
T₂ = 348.85 K
Similarly, we can use the pressure at the third measurement (68.4 cm) and the temperature we just calculated (348.85 K) to find the temperature of the surrounding Carbon (IV) Oxide using the same equation:
T₃ = (P₃/P₁) * T₁
T₃ = (68.4/82) * 273.15 K
T₃ = 226.32 K
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What is the supplement of a 30° angle?
Answer:
150˚
Step-by-step explanation:
To find the supplement of a 30˚ angle, we need to know what an supplement in geometry is.
A supplement is when two angles add up that results in 180
So what value adds to 30˚ will get 180?
To find out that we just subtract 180 with 30
Which is 150
Thus the Supplement of a 30˚ angle is 150˚
Hope this helps!
I need help please with 6, 7 and 8
6. Solution for |2x-3| = |x| are x = 1,3
7. Solution for 8 + |4v - 7| ≥ 17 is,
v ≥ 4 , v ≤ -1/2
8. Number of computer meets in the condition = 6
Average:
Average of given number is given by sum of all numbers divided by total number of numbers.
6. |2x-3| = |x|
Case I :
when x<0
|2x-3| = |x|
-(2x-3) = -x
-2x + 3 = -x
2x - x = 3
x = 3 ( Not possible as x<0 )
No solution in this case.
Case II :
when 0< x< 3/2
|2x-3| = |x|
-(2x -3) = x
-2x + 3 = x
2x +x = 3
3x = 3
x =1 (Valid solution)
Case III :
when x>3/2
|2x-3| = |x|
2x-3 = x
2x -x =3
x = 3 (Valid solution)
Thus solution for |2x-3| = |x| are x = 1,3
7.
8 + |4v - 7| ≥ 17
|4v - 7| ≥ 17 -8
|4v - 7| ≥ 9
⇒ 4v - 7 ≥ 9
4v ≥ 9+7
v ≥ 4
and,
4v - 7 ≤ - 9
4v ≤ -2
v ≤ -1/2
Thus solution for 8 + |4v - 7| ≥ 17 is,
v ≥ 4 , v ≤ -1/2
8.
We know,
Average of quantity = sum of quantity / Number of quantity
For the given question,
Sum of price of all computer = $ (890+650+ 660+450+ 725+750+370+670+650+825)
= $ 6640
and Number of computer = 10
Average price of computer = $ 6640/10
= $ 664
Absolute deviation is $100
So i can pay price between
($ 664 - $100) to ($ 664 + $100)
that is $564 to $764
Number of computer meets in this condition = 6
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College Graduates Starting Salaries. According to the National Association of Colleges and Employers, the 2015 mean starting salary for new college graduates in health sciences was $51,541. The mean 2015 starting salary for new college graduates in business was $53,901 (National Association of Colleges and Employers website). Assume that starting salaries are normally distributed and that the standard deviation for starting salaries for new college graduates in health sciences is $11,000. Assume that the standard deviation for starting salaries for new college graduates in business is $15,000
The mean starting salary for new college graduates in health sciences was $51,541, and the mean starting salary for new college graduates in business was $53,901. (National Association of Colleges and Employers website).
Starting salaries for new college graduates in health sciences and business are normally distributed with standard deviations of $11,000 and $15,000, respectively.
In the context of salary distributions, the mean represents the average or central value of the salaries, while the standard deviation measures the variability or spread of the salaries around the mean.
It is important to note that the assumption of normal distribution allows us to make certain statistical inferences and calculations.
For example, we can estimate the proportion of graduates earning salaries within specific ranges, calculate the probability of earning a certain salary, or compare salaries between different groups.
The standard deviations of $11,000 and $15,000 indicate that there is more variability in starting salaries for new college graduates in business compared to health sciences.
This means that the salaries in the business field are more spread out, with a wider range of values, while the salaries in the health sciences field are relatively less variable and more tightly clustered around the mean.
Overall, these statistics provide valuable information about the starting salaries for college graduates in health sciences and business, allowing for comparisons and analysis of the salary distributions in these fields.
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The length of a rectangle is the same as its width. If the perimeter is 32 M what is its area?
The perimeter of a rectangle is calculated using the formula:
\(P=2(l+w)\)The question gives that the length and width of the rectangle are equal. This means that:
\(l=w\)Therefore, the perimeter will be calculated to be:
\(\begin{gathered} P=2(l+l)=2(2l) \\ P=4l \end{gathered}\)The perimeter is given to be 32 m. Therefore, the length of the rectangle will be:
\(\begin{gathered} 32=4l \\ l=\frac{32}{4} \\ l=8 \end{gathered}\)Using the formula for the area:
\(A=l^2\)Therefore, the area will be:
\(\begin{gathered} A=8^2 \\ A=64\text{ m}^2 \end{gathered}\)The area is 64 square meters.
find the slope of the line that passes through (13,7 ) and (13,11)
Answer:
Check pdf
Step-by-step explanation:
show your work in simplifying m⁹•m⁰
Answer:
m⁹
Step-by-step explanation:
(m*m*m*m*m*m*m*m*m) * (1)
m*m*m*m*m*m*m*m*m*m
m⁹
A vendor buys x kg of peanuts and kg of cashew nuts.
(a) To get a good bargain, she must buy a minimum of 10 kg of peanuts and a minimum of 5 kg of cashew nuts.
(i)Write TWO inequalities which satisfy these conditions.
(ii) She buys no more than 60 kg of nuts. Peanuts cost $4.00 per kg and cashew nuts cost $8.00 per kg and she spends at least $200.
Write Two inequalities which satisfy these conditions.
The inequalities that satisfy this condition is 4x + 8y ≥ 200 and x + y ≤ 60
What is an inequality?
An inequality is an expression that shows the non equal comparison between two or more numbers and variables.
Let x represent the number of peanuts and y represent the number of cashew nuts.
She must buy a minimum of 10 kg of peanuts and a minimum of 5 kg of cashew nuts. Hence:
x ≥ 10, y ≥5
Also:
x + y ≤ 60
And:
4x + 8y ≥ 200
The inequalities that satisfy this condition is 4x + 8y ≥ 200 and x + y ≤ 60
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20 POINTS
someone pls double check me because it says I'm wrong
Question: evaluate 7[h(-2)] -6 if h (x) = 11-x ^2
Answer I got: 14x^2-160
Answer:
Step-by-step explanation:
your right there wrong
the university of montana ski team has eight entrants in a men's downhill ski event. the coach would like the first, second, and third places to go to the team members. in how many ways can the eight team entrants achieve first, second, and third places?
There are 336 ways for the 8 team entrants to achieve the desired outcome of first, second, and third place positions.
The problem involves selecting 3 individuals out of 8 to fill the 1st, 2nd, and 3rd place positions. Since the order in which the individuals are selected matters, we need to use the permutation formula to determine the total number of ways to achieve the desired outcome.
The formula for permutation is:
P(n,r) = n! / (n-r)!
Where n is the total number of individuals, and r is the number of positions to be filled.
In this case, we need to select 3 individuals out of 8 to fill the 1st, 2nd, and 3rd place positions. Using the permutation formula, we get:
P(8,3) = 8! / (8-3)!
= 8! / 5!
= (8 x 7 x 6 x 5 x 4 x 3 x 2 x 1) / (5 x 4 x 3 x 2 x 1)
= 8 x 7 x 6
= 336
In other words, the coach has 336 possible ways to select three team members for the podium, assuming all team members have an equal chance of winning.
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