Use the given domain to find the range of each function

According to the given information, the sample period should be from 2010-2020.

a) Model specification

The model specification based on the scenario above is as follows:

SDF= f(T, TI, NL)

Where: SDF= Sustainable Development Framework

T= Tourism

TI= Technological innovation

NL= National leadership

b) Justification for the selection of the dependent and independent variables model:

Dependent variable: The dependent variable in this model is Sustainable Development Framework (SDF). The model seeks to develop a framework for sustainable development that would facilitate growth, environmental and socio-cultural sustainability.

Independent variables:

The independent variables are tourism sustainability, technological innovation, and quality of leadership. These variables drive economic development. The inclusion of tourism sustainability reflects its importance in the global economy and its potential to drive growth.

The inclusion of technological innovation reflects its potential to enhance productivity and create new industries. The inclusion of national leadership reflects the role of governance in promoting sustainable development and managing negative externalities.

c) Justification for the selection of the sample period:

The sample period should be selected based on the availability of data for the variables of interest. Ideally, the period should be long enough to capture trends and patterns in the data. However, it should not be too long that the data becomes obsolete or no longer relevant.

Additionally, the period should also reflect the context and relevance of the research question. Therefore, the sample period for this study should cover the last decade to capture the trends and patterns in the data and reflect the relevance of the research question.

The sample period should be from 2010-2020.

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The average time required for a passenger to pass through security screening is found to be approximately 0.0612 minutes.

(a) The operating characteristics for the screening facility with two screening stations open are as follows:

P0 = 0.0196

Lq = 0.3922

L = 0.4902

Wq = 0.0490 min

W = 0.0612 min

Pw = 0.0909

(b) The two-screening-station system will not be able to meet the facility manager's goal of limiting the average number of passengers waiting in line to 10 or fewer.

The operating characteristics for the screening facility with two screening stations open are calculated as follows:

P0 = 0.0196, Lq = 0.3922, L = 0.4902, Wq = 0.0490 min, W = 0.0612 min, Pw = 0.0909.

Based on these calculations, the two-screening-station system will not be able to meet the facility manager's goal of limiting the average number of passengers waiting in line to 10 or fewer.

(c) The average time required for a passenger to pass through security screening is 0.0612 minutes.

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Answer: 9

Step-by-step explanation: on a number line -9 is before 0 9 is after 0 , and any number to the right of a number is greater.

Answer:

From top to bottom: 1/8, 2 1/2, 3

Step-by-step explanation:

The first number means that it take 8 quarters to equal a toonie and you don't have a toonie with 1 quater

brainliest please

Best guess for the function is

\(\displaystyle f(x) = \sum_{n=1}^\infty \frac{x^n}{n^2}\)

By the ratio test, the series converges for

\(\displaystyle \lim_{n\to\infty} \left|\frac{x^{n+1}}{(n+1)^2} \cdot \frac{n^2}{x^n}\right| = |x| \lim_{n\to\infty} \frac{n^2}{(n+1)^2} = |x| < 1\)

When \(x=1\), \(f(x)\) is a convergent \(p\)-series.

When \(x=-1\), \(f(x)\) is a convergent alternating series.

So, the interval of convergence for \(f(x)\) is the closed interval \(\boxed{-1 \le x \le 1}\).

The derivative of \(f\) is the series

\(\displaystyle f'(x) = \sum_{n=1}^\infty \frac{nx^{n-1}}{n^2} = \frac1x \sum_{n=1}^\infty \frac{x^n}n\)

which also converges for \(|x|<1\) by the ratio test:

\(\displaystyle \lim_{n\to\infty} \left|\frac{x^{n+1}}{n+1} \cdot \frac n{x^n}\right| = |x| \lim_{n\to\infty} \frac{n}{n+1} = |x| < 1\)

When \(x=1\), \(f'(x)\) becomes the divergent harmonic series.

When \(x=-1\), \(f'(x)\) is a convergent alternating series.

The interval of convergence for \(f'(x)\) is then the closed-open interval \(\boxed{-1 \le x < 1}\).

Differentiating \(f\) once more gives the series

\(\displaystyle f''(x) = \sum_{n=1}^\infty \frac{n(n-1)x^{n-2}}{n^2} = \frac1{x^2} \sum_{n=1}^\infty \frac{(n-1)x^n}{n} = \frac1{x^2} \left(\sum_{n=1}^\infty x^n - \sum_{n=1}^\infty \frac{x^n}n\right)\)

The first series is geometric and converges for \(|x|<1\), endpoints not included.

The second series is \(f'(x)\), which we know converges for \(-1\le x<1\).

Putting these intervals together, we see that \(f''(x)\) converges only on the open interval \(\boxed{-1 < x < 1}\).

Answer: C

Step-by-step explanation:

Another point on the line y = 9/5(x) + 2  is (0, 2).

The correct option is B.

In mathematics, a line's slope, also known as its gradient, is a numerical representation of the line's steepness and direction

If a line passes through two points (x₁ ,y₁) and (x₂, y₂) ,

then the equation of line is

y - y₁ = (y₂- y₁) / (x₂ - x₁) x (x - x₁)

To find the slope;

m =  (y₂- y₁) / (x₂ - x₁)

Given:

The slope of the line is 9/5 and passes through the point (-10, -16).

So, the equation of the line is,

y + 16 = 9/5(x + 10)

y + 16 = 9x/5 + 18

y = 9/5(x) + 2

From the given choices,

Substituting x = 0,

we get,

y = 2

another point on the line is (0, 2).

Therefore, another point on the line is (0, 2).

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15.21 is the answer :)

Answer:

15.21

Step-by-step explanation:

we would be willing to pay no more than $10 to play a game where I pick one bill out of a bag with equal proportions of $10, $20, $50, and $100 bills.

The expected value of the game is $30, so we would not be willing to pay more than that. we would be willing to pay the $10 because there is a chance I could select a $100 bill, and while the probability of this happening is low, the potential reward could be quite high.

So ultimately, the amount we are willing to pay depends on the amount of risk we are willing to take.

Therefore we will be willing to pay no more than $10 to play a game where we pick one bill out of a bag with equal proportions of $10, $20, $50, $100 bills.

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Given a standardized normal distribution​ (with a mean of 0 and a standard deviation of​ 1), we need to determine the following probabilities:

a. P(Z > 1.02) = 0.1539

b. P(Z < -1.96) = 0.025

The value of Z if only 9.68% of all possible​ Z-values are ​larger 1.34.

a. P(Z > 1.02)

We need to find the area under the standard normal distribution curve to the right of the given Z value.

Using a standard normal distribution table, the area to the right of Z = 1.02 is 0.1539.

P(Z > 1.02) = 0.1539 (round to four decimal places as​ needed)

b. P(Z < -1.96)

We need to find the area under the standard normal distribution curve to the left of the given Z value.

Using a standard normal distribution table, the area to the left of Z = -1.96 is 0.025.

P(Z < -1.96) = 0.025 (round to three decimal places as​ needed)

Let Z be the random variable of the standard normal distribution. We need to find the Z-value whose corresponding area is 0.0968 to find the value of Z if only 9.68% of all possible​ Z-values are larger.

Using a standard normal distribution table, the Z-value that corresponds to an area of 0.0968 is 1.34.

Therefore, the value of Z if only 9.68% of all possible​ Z-values are larger is 1.34.

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Answer:

Shannon

Step-by-step explanation:

Cuando se habla de lo que uno tiene, podemos usar números positivos.

Por ejemplo:

Pedro tiene 10 manzanas.

Para el caso de deudas, utilizamos números negativos, por ejemplo:

Pedro tiene -10 manzanas

Lo cual significa que Pedro debe 10 manzanas a alguien.

Entonces si le diéramos a Pedro 12 manzanas, el ahora tendría:

-10 + 12 = 2

Pedro tiene 2 manzanas, porque tuvo que entregar 10 de las 12 que le dimos para pagar su deuda.

Ahora vamos a resolver el problema:

La cuenta de Sally tiene un saldo de:

S = -$200.90

El signo negativo quiere decir que Sally tiene una deuda de $200.90

La cuenta de su amiga Shannon tiene un saldo de:

S' = -$240.55

De vuelta, el signo negativo quiere decir que Shannon tiene una deuda de $240.55

Con esto ya podemos concluir que la deuda de Shannon es mayor, por lo tanto Shannon es la que tiene más deuda.

The amount of tax that is added to the cost of the computer is £182.41

Tax can be described as a financial contribution that is levied on the citizens on a country. It could be a payment that is paid at a particular period of time.

The computer costs £986

The tax is 18.5%

The amount of tax that is added to the cost of the computer can be calculated as follows

= 18.5/100 × 986

= 0.185 × 986

= 182.41

Hence the amount of tax added to the cost of the computer is £182.41

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The explained variation, or regression sum of squares, is equal to 0 when there is no linear relationship between the independent and dependent variables in a given dataset.

In this case, the best-fit line would be a horizontal line, and the slope of the regression line would be 0. This indicates that changes in the independent variable do not have any impact on the dependent variable, resulting in an explained variation of 0.

To summarize, the explained variation (regression sum of squares) is equal to 0 when there is no linear relationship between the independent and dependent variables in the dataset.

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Using the Cramer's Rule, the solution of the given system of equation is (-17/11, 48/11)

The given system of equations are

10x+4y=2

-6x+2y=18

Solving the equations by using Cramer's rule.

We know that, the solution of a system of linear equations in two unknowns

a(1)x+b(1)y = c(1)

a(2)x+b(2)y = c(2)

is given by ∆x=∆1, and ∆y=∆2.

where,

\(\Delta=\text{det}\left [ \begin{matrix} a(1)&b(1) \\ a(2) & b(2)\end{matrix} \right ], \Delta(1)=\text{det}\left [ \begin{matrix} c(1)&b(1) \\ c(2) & b(2)\end{matrix} \right ]\text{ and }\Delta(2)=\text{det}\left [ \begin{matrix} a(1)&c(1) \\ a(2) & c(2)\end{matrix} \right ]\)

Since the given equations are;

10x+4y=2

-6x+2y=18

Now,

\(\Delta=\text{det}\left [ \begin{matrix} 10&4 \\ -6 & 2\end{matrix} \right ]\)

∆ = [(10×2)-(-6×4)]

∆ = 20+24

∆ = 44

\(\Delta(1)=\text{det}\left [ \begin{matrix} 2&4 \\ 18 & 2\end{matrix} \right ]\)

∆(1) = [(2×2)-(18×4)]

∆(1) = 4-72

∆(1) = -68

\(\Delta(2)=\text{det}\left [ \begin{matrix} 10&2 \\ -6 & 18\end{matrix} \right ]\)

∆(2) = [(10×18)-(-6×2)]

∆(2) = 180+12

∆(2) = 192

By Cramer's Rule,

∆x = ∆(1)

44 × x = -68

x = -68/44

x = -17/11

Now,

∆y = ∆(2)

44 × y = 192

y = 192/44

y = 48/11

Hence, the solution of the given system of equation is (-17/11, 48/11).

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The right question is:

Solve the system if possible by using Cramer's rule. If Cramer's rule does not apply, solve the system by using another method. Write all numbers as integers or simplified fractions.

10x+4y=2

-6x+2y=18

Divide distance by time:

690 meters / 6 minutes = 115 meters per minute

Speed = 115 meters per minute

Answer:

\(\huge\boxed{\sf v = 1.92\ m/s}\)

Step-by-step explanation:

Given Data:

Distance = S = 690 meters

Time = t = 6 min = 6 * 60 = 360 seconds

Required:

Speed = v = ?

Formula:

v = S / t

Solution:

v = 690 / 360

v = 1.92 m/s

\(\rule[225]{225}{2}\)

Hope this helped!

Answer:

8000

Step-by-step explanation:

8000

10^6-2*7.2/9

72000/9 = 8000

Answer:

D

Step-by-step explanation:

cause Mary needs to know how much fencing to get.

By defining the state space and transition rates, we have modeled the workshop with 3 machines as a continuous-time Markov chain (CTMC).

To model the workshop with 3 machines as a continuous-time Markov chain (CTMC), we need to define the state space, which represents the number of working machines, and the transition rates, which represent the rates of machine failure and repair.

State space: The state space S is defined as S = {0, 1, 2, 3}, where each state represents the number of working machines at any given time.

Transition rates: The transition rates depend on the failure rate λ and repair rate μ. The transition rates are as follows:

q(1, 0): The rate at which 1 working machine fails and becomes 0 (all machines fail).

q(1, 2): The rate at which 1 failed machine is repaired and becomes 2 (1 machine is repaired).

q(2, 1): The rate at which 1 of the 2 working machines fails and becomes 1 (1 machine fails).

q(2, 3): The rate at which 1 failed machine is repaired and becomes 3 (1 machine is repaired).

q(3, 2): The rate at which 1 of the 3 working machines fails and becomes 2 (1 machine fails).

The transition rates are given in terms of the failure rate λ and repair rate μ, representing the probabilities of machines failing or being repaired.

These transition rates determine the probabilities of transitioning between different states of the Markov chain.

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If the person is actually a height of 150 cm, the by use of scale factor, the building is actually a height of 3000 cm tall.

The scale factor can be defined as a specific number by which the size of geometrical figures / some shape can be altered when compared to the original size it had.

Now, we see from the question that the picture showed a height of 10 cm for the building. However, the person beside that building in the picture has a height of 0.5cm.

Now, we are told that the real height of the person physically is 150 cm and this means that the picture represents a scaled height of the person. Therefore, the scale factor will be; 150/0.5 = 300

Thus;

True length of building physically = 10cm * 300 = 3000 cm or 3 meters

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A line segment of length 8.6 cm, when bisected the length of each half is  4.3cm.

Draw a straight line and mark two points A and B that are 8.6 cm apart.

With A as centre and radius more than half of AB, draw arcs on both sides of AB.

With the same radius and B as centre, draw arcs on the both sides of AB, cutting the previous two arcs.

Label the intersection points of the two arcs as E and F.

Draw a straight line connecting points E and F. This is the line of symmetry and bisects the line segment AB.

The length of each part of the bisected line segment is equal. To measure the length of each part, we can use a ruler to measure the distance from point A to the intersection point C and from point B to the intersection point D. Each of these distances should be approximately 4.3 cm, which is half the length of the original segment.

we get: AC=BC=4.3 cm.

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____The given question is incomplete, the complete question is given below:

Draw a line segment of length 8.6 cm. Bisect it and measure the length of each part.  

"Every linear transformation is a matrix transformation." This is false. Not all linear transformations are matrix transformations, even if all matrix transformations are linear transformations.

A point, line, or geometric object can be changed in four different ways that are all referred to as transformations. The Pre-Image refers to the object's initial shape, and the Image, after transformation, refers to the object's ultimate shape and location.

Bring out the pattern blocks, tangrams, and geoboards for another low-prep, high-engagement method of teaching geometric transformations. Students can produce an original design and then hand it off to a partner so that they can add a reflection, rotation, or translation to it.

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Answer:

7/25

Step-by-step explanation:

Probability = # of favorable outcomes / # of possible outcomes

Favorable outcomes = # of blue and yellow marbles

There are 3 yellow marbles and 4 blue marbles

There are 7 blue and yellow marbles so the favorable outcome is 7

Possible outcomes = total number of marbles

12 + 3 + 6 + 4 = 25

There are a total of 25 marbles

So possible outcomes = 25

If probability= favorable outcomes / possible outcomes then the probability of pulling a blue or yellow marble is 7/25

Answer:

B

Step-by-step explanation:

B is the only choice that has both all of the steps, and all of the steps in the right order.

Answer:

21

Step-by-step explanation:

Component 3 must be started on day 197 to meet the delivery date of day 200.

To illustrate the backward schedule, we need to start from the delivery date (day 200) and work our way backward, taking into account the lead times and dependencies of each operation.

(a) Backward schedule:

Operation    |  Work Center  |  Time (hours)  |  Start Day

--------------------------------------------------------

Final Assembly |   Work Center 1  |        1       |     200

Sub-assembly 1 |   Work Center 2  |        2       |     199

Component 4     |   Work Center 3  |        3       |     197

Component 2     |   Work Center 4  |        4       |     196

Component 3     |   Work Center 5  |        3       |     ????

(b) To identify when component 3 must be started to meet the delivery date, we need to consider its dependencies and lead times.

From the backward schedule, we see that component 3 is required for sub-assembly 1, which is scheduled to start on day 199. The time required for sub-assembly 1 is 2 hours, which means it should be completed by the end of day 199.

Since component 3 is needed for sub-assembly 1, we can conclude that component 3 must be started at least 2 hours before the start of sub-assembly 1. Therefore, component 3 should be started on day 199 - 2 = 197 to ensure it is completed and ready for sub-assembly 1.

Hence, component 3 must be started on day 197 to meet the delivery date of day 200.

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The probability of getting 'p' success when a die rolled 12 times with 'x' success that has binomial distribution is equal to ¹²Cₓ pˣ ( 1 - p )¹²⁻ˣ.

Number of times die to be rolled = 12

In this scenario, a trial refers to a single roll of the 20-sided die.

Here , 'x' represents the the number times the die lands on a green square.

A success would be defined as landing on a green square,

And a failure would be landing on any other color.

Since the die will be rolled 12 times, there are 12 trials in total.

This implies, the number of times the die lands on a green square, x, has a binomial distribution.

With parameters n = 12 the number of trials and p the probability of success  which is landing on a green square.

Probability = ⁿCₓ pˣ ( 1 - p )ⁿ⁻ˣ

Therefore, the probability of rolling a die 12 times with 'x' success which has binomial distribution and 'p' probability of success is equal to ¹²Cₓ pˣ ( 1 - p )¹²⁻ˣ.

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Answer: the answer is $9,600

Step-by-step explanation:

option A = 40(24)   =  option B = x (.1)       where x is her gross sales

40(24) = x(.1)

40(24)/.1 = x = sales = $9600

Given,

The set is {2, {3}}.

The cardinity of the set is the number of elements in the set.

Consider,

A = {2, {3} }

The cardinity of the set is,

Hence, the cardinality of the set is 2.

In equilateral triangles, 7.0 mm is the length of each edge of the diamond.

The equilateral triangle's definition?

An equilateral triangle is a triangle whose three sides are all the same length, commonly referred to as a "regular" triangle.

                                       A triangle with all three sides equal and interior angles of 60 degrees is said to be equilateral. Triangle with an equal number of sides is known as an isosceles triangle.

V = 0.4783 S³  = 161

   S³   =  161/0.47

       = ∛ 161/0.47

       ≈ 7.0 mm

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Answer:

4

Step-by-step explanation:

Given the expression 2/? > 4/12, to find the value of ? that will make the expression true, we will cross multiply first

On cross multiplying:

2×12 > 4 × ?

24 > 4 × ?

Divide both sides by 4

24/4 > 4×?/4

6 > ?

This means that ? < 6

The answer will be a value that is less than 6. According to the option, the only value less than 6 is 4. Hence the correct answer is 4.

Answer: 4

Step-by-step explanation:

Converting a random variable to a z-value standardizes it for easier interpretation and analysis, enabling the use of techniques assuming normality.

calculating the z-score and interpreting the standardized value. The z-score is obtained by subtracting the mean from the observed value and dividing by the standard deviation. The z-score represents the number of standard deviations an observation is away from the mean.

A positive z-value indicates being above the mean, while a negative value suggests being below it. The z-value's interpretation relies on the standard normal distribution, where a z-value of 0 corresponds to the mean.

Converting variables to z-values allows for comparison on a standardized scale, enabling assessment of relative position and significance based on the standard normal distribution.

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