Use the emf series (Appendix D) to arrange the species(b) In order of increasing strength as reducing agents: Hg, Fe, Sn

Enthalpy, in a technical sense, refers to the internal energy needed to create a system as well as the energy needed to create space for it by establishing its pressure, volume, and displacing its surroundings.

In a thermodynamic system, energy is measured by enthalpy. Enthalpy is a measure of a system's overall heat content and is equal to the system's internal energy plus the sum of its volume and pressure.

A state function that is entirely based on state functions P, T, and U is how enthalpy is also described.

Here the equation used is:

q = n × ΔH

n = Mass / Molar mass

n = 253 / 122.55 = 2.064 mol

q =  2.064 × -91 = -187.82 kJ

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The condensed structural formula for the product of the reaction of 2-butene with water and a strong acid catalyst is shown below ,

First write the condensed structural formula of 2-butene and indicate that it reacts with water. Then write the condensed structural formula of 2-butanol after the reaction arrow to indicate that it is the product. Finally, write the formula for the catalyst above the arrow.

The acid first attack at double bonded carbon of 2-butene and produce stable carbocation then water molecule attack on carbocation followed by deprotonation .

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Answer:

oxygen molecule has two oxygen atom . Each O atom share 2 electrons to form two covalent bonds out of which one is sigma bond and other is pi bond . sigma bond is formed by axial overlap 2p atomic orbitals of oxygen and pi bond is formed of lateral overlap of 2p atomic orbitals of oxygen .

The first order rate constant for ¹⁴C can be calculated using the equation:
k = ln(2)/t1/2
where ln represents the natural logarithm, and t1/2 represents the half-life of the radioisotope.

Substituting the values given in the question, we get:
k = ln(2)/5730 years
k ≈ 0.0001209682 years⁻¹

Therefore, the first order rate constant for ¹⁴C is approximately 0.0001209682 years⁻¹.

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Answer:

39.948g Ar, or if you need to round it up then 39.95g

Explanation:

Conversion units: 1 mole is 6.022 x 10^23 molecules, that includes atoms too.

First Step: Convert atoms to moles:

6.022 x 10^23 Ar atoms × \(\frac{1 mole}{6.022 x10x^{23} }\) = 1 mole Ar

Second Step: Convert moles to grams

There is 39.948 grams in one mole of Argon so

1 mole Ar x 39.948g = 39.948g

Answer:

C9H13O3N

Explanation:

Take the atomic mass of C=12.0, H=1.0, O=16.0 and N=14.0.

We can draw a chart (please view this on desktop so to avoid spacing errors):

Let the mass of Epinephrine be 100g.

                             C                       H                          O                              N

mass(g) :              59                      7.15                    26.2                         7.65

no. of moles : 59/12 =4.9167     7.15/1 = 7.15     26.2/16=1.6375 7.65/14=0.5464

(n.o.m. = mass/molar mass)

Ratio:   4.9167/0.5464 =9    7.15/0.5464=13      1.6375= 3      0.5464/0.5464 =1

(divide the n.o.m. by the smallest n.o.m., which is 0.5464 in this case, take the whole numbers)

So, the empirical formula will be: C9H13O3N

But this is still not yet the molecular formula. We have to ensure the molar mass is 183g/mol. Multiply the empirical formula by n.

So, let the molecular formula of Epinephrine be (C9H13O3N)n.

12x9n + 1x13n + 16x3n + 14n = 183

108n + 13n + 48n + 14n = 183

183 n = 183.

n = 1

Hence, the molecular formula is C9H13O3N.

The difference in degrees Fahrenheit between the maximum expected temperatures by the end of the century between the lower and higher emissions scenarios can vary depending on various factors and assumptions.

However, in general, the lower emissions scenario is expected to result in a lower increase in global temperatures compared to the higher emissions scenario.

This means that the maximum expected temperature rise by the end of the century under the lower emissions scenario would be lower than that of the higher emissions scenario.

The specific temperature difference would depend on the specific projections and models used, but it highlights the significant impact that emissions reductions can have on mitigating future temperature increases.

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Answer:

Flerovium

Explanation:

Answer:

Fl or flerovium. Atomic number is the number above the element on a periodic table.

The molar specific heat at constant pressure (Cp) for this particular ideal gas is (9/2) times the gas constant (R).

The molar specific heat at constant pressure (Cp) for an ideal gas can be related to its molar specific heat at constant volume (Cv) using the equation: Cp = Cv + R, where R is the gas constant.

Given that Cv = 7/2 R, we can substitute this value into the equation:

Cp = (7/2)R + R

To simplify, we combine the terms with a common factor of R:

Cp = (7/2 + 2/2)R

= (9/2)R

Therefore, the molar specific heat at constant pressure (Cp) for this particular ideal gas is (9/2) times the gas constant (R). This means that Cp is larger than Cv, indicating that the gas absorbs more heat when kept at constant pressure compared to when kept at constant volume.

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0.8 grams of CH4 are needed to react with 3.2 grams of O2.

To determine how many grams of CH4 are needed to react with 3.2 grams of O2, we'll first need to use stoichiometry and the balanced chemical equation for the reaction between methane (CH4) and oxygen (O2):

CH4 + 2O2 → CO2 + 2H2O

Step 1: Calculate moles of O2

First, convert grams of O2 to moles using its molar mass (32 g/mol):

3.2 g O2 × (1 mol O2 / 32 g O2) = 0.1 mol O2

Step 2: Use stoichiometry

According to the balanced equation, 1 mol of CH4 reacts with 2 mol of O2. Therefore, find the moles of CH4 needed to react with 0.1 mol O2:

0.1 mol O2 × (1 mol CH4 / 2 mol O2) = 0.05 mol CH4

Step 3: Convert moles of CH4 to grams

Finally, convert moles of CH4 to grams using its molar mass (16 g/mol):

0.05 mol CH4 × (16 g CH4 / 1 mol CH4) = 0.8 g CH4

So, 0.8 grams of CH4 are needed to react with 3.2 grams of O2.

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Answer:

Although all organic compounds contain carbon, and almost all have hydrogen, most of them contain other elements as well. The most common other elements in organic compounds are oxygen, nitrogen, sulfur, and the halogens.

Explanation:

I hope this helped!

Answer:

I think they use water,shovel,and rake.

Explanation:I was in ag in 8th grade and first we used a rake and raked all the stuff up. Then we waterd the dirt. Then dug a hole and planted the plant and waterd it after.

I hoped this help have a nice day! Comment if you need more help.

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Among the given options, SO2, SO3, and SO32- can exhibit delocalized bonding.

Delocalized bonding is a type of bonding where the electrons are not localized between two atoms but rather are shared among multiple atoms in a molecule. This type of bonding is characterized by the presence of resonance structures and is commonly observed in molecules that contain pi bonds.

SO2 has a bent structure with a lone pair of electrons on the sulfur atom. The double bond between sulfur and oxygen involves the overlap of a p orbital on sulfur and a p orbital on one of the oxygen atoms. This results in a pi bond and a sigma bond. The pi electrons are delocalized between the sulfur and oxygen atoms, and resonance structures can be drawn to show the delocalization.

SO3 has a trigonal planar structure with all three sulfur-oxygen bonds being identical. The sulfur atom in SO3 uses its three 3p orbitals to form three sigma bonds with the three oxygen atoms. The remaining 3p orbital on sulfur overlaps with the p orbitals on the three oxygen atoms to form three pi bonds. The pi electrons are delocalized over all three sulfur-oxygen bonds.

SO32- has a resonance structure in which the negative charge is delocalized over the sulfur and two oxygen atoms. The two sulfur-oxygen double bonds can be described as a combination of one strong sigma bond and one weaker pi bond, resulting in the delocalization of electrons over the sulfur-oxygen bonds.

In summary, SO2, SO3, and SO32- can exhibit delocalized bonding due to the presence of pi bonds and the ability to form resonance structures.

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Answer:

I'm sorry, I cannot provide exact temperature, salinity, or density values for specific ocean locations without further information. The values of these properties can vary greatly depending on many factors such as water depth, water circulation patterns, and local weather conditions. It is also worth noting that ocean temperature, salinity, and density can change over time and can fluctuate on a daily or seasonal basis.

Regarding the similarity in salinity in both areas, ocean salinity is primarily controlled by the balance between the input of freshwater from precipitation, rivers, and glaciers, and the output of salt through processes such as evaporation and the formation of sea ice. The similarity in salinity between two locations could be due to the presence of similar sources of freshwater or similar ocean circulation patterns that mix water from different sources and distribute salt and other dissolved substances evenly across the ocean. However, it is also possible that the salinity could be different due to other factors such as differences in ocean currents, water mixing, or local weather patterns.

The comparison between the class barometer data and the air pressure shown in the weather report serves as a means to evaluate the accuracy and effectiveness of the barometer's measurements.

The comparison between the data from the class barometer and the air pressure shown in the weather report revealed a correlation between the two measurements. The class barometer readings were likely taken at the same time as the weather report's air pressure measurement to ensure accurate comparison.

If the class barometer readings closely matched the air pressure indicated in the weather report, it would suggest that the barometer was functioning correctly and providing reliable measurements. This would indicate that the class barometer could be used as a reliable tool for monitoring air pressure changes.

However, if there were significant discrepancies between the class barometer readings and the air pressure reported in the weather report, it could indicate a calibration issue with the barometer or potential inaccuracies in its measurements. In such a case, it would be necessary to investigate the reasons behind the discrepancies and determine the reliability of the class barometer for future use. It helps to determine the barometer's reliability as a tool for monitoring air pressure changes in the local environment.

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Answer:

1.476 mol molecules

Explanation:

Number of moles of NaCl are present in aqueous solution is 0.0139 moles.

We create a solution for a lab,

Weight of NaCl = 0.81 g

Nacl is dissolved in water to form an aqueous solution.

The volume of the resulting aqueous NaCl solution = 12. 2 ml

The molar mass of NaCl is 58. 443 g/mol.

Now, we need to calculate the number of moles of NaCl in aqueous solution.

The relation between number of moles , given mass and molecular mass is given below:

number of mole = ( given mass / molecular mass )

number of moles of NaCl = ( 0.81/58.443 )

number of moles of NaCl = 0.0139

Thus, we can conclude that 0.0139 moles of NaCl are present in aqueous solution.

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Based on the given information and the densities provided in the table, the unknown element in the alloy is most likely Beryllium. option(a)

To identify the unknown element in the alloy, we need to compare the density of the alloy with the densities of the elements listed in the table.

The density of the alloy can be calculated using the given information. We know that 10.0 grams of the alloy has a volume of 4.20 cm³. Density is defined as mass divided by volume, so we can calculate the density of the alloy as:

Density = Mass / Volume = 10.0 g / 4.20 cm³ ≈ 2.38 g/cm³

Now, we compare the calculated density of the alloy (2.38 g/cm³) with the densities listed in the table. From the given options, the closest density is that of aluminum, which is 2.70 g/cm³. The alloy's density is lower than the density of aluminum, which means it must contain an element with a lower density than aluminum.

The unknown element in the alloy is most likely Beryllium (option A) with a density of 1.85 g/cm³. The combination of 62% aluminum and 38% beryllium in the alloy would result in a density close to the calculated value of 2.38 g/cm³. option(a)

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If the current moon phase is full moon, then 14 days later the moon phase would be a new moon. This is because the lunar cycle lasts approximately 29.5 days, and half of that is 14.75 days, which rounds down to 14 days.

After a full moon, the moon goes through its waning phases and eventually becomes a new moon.

A first-quarter moon is so named because it has completed one-quarter of its lunar cycle, which lasts around 29.5 days. The right side of the moon is lighted during this phase, giving it the appearance of a "D" shape.

The moon will transition to its next phase, known as "waning gibbous," around 7 days later. The moon is now partially illuminated, but as it approaches the "full moon" phase, it becomes less illuminated.

It is significant to note that due to the intricate connections between Earth's orbit around the sun and the moon's orbit around the planet, the precise time of the various lunar phases might change somewhat from month to month.

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When gasoline evaporates from a fuel gas can energy is released. Therefore, the correct option is option A.

Energy, which is observable in the execution of labour as well as through the emission of heat and light, is the quantitative quality which gets transmitted to a body as well as to a physical system in physics. Energy is a preserved resource; according to the rule of conservation of energy, energy can only be transformed from one form to another and cannot be created or destroyed.  When gasoline evaporates from a fuel gas can energy is released.

Therefore, the correct option is option A.

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Answer:

matter should be the answer

Explanation:

Hope this helps!

Answer:

matter because matter makes up everything in the world EVERYTHING like this computer ri am typing on? matter. what ever device you are using to view this? matter. everything is made of matter. matter is starting to sound weird now so I'm gonna stop saying it and this is the end of the answer remember THAT ANSWER IS MATTERR!!!!!

Answer:

A. oxygen, silicon, aluminum, iron, calcium, sodium, potassium, magnesium

Explanation:

The milliliters of 1.51 mol/L H₂SO₄(aq) are required to completely neutralize 30.9 mL of 1.51 mol/L KOH is 15.45 mL.

The balanced equation for the reaction:

H₂SO₄(aq)   +   2KOH(aq)    ----->   K₂SO₄(aq)     +    2H₂O(l)

Given that:

Molarity of H₂SO₄ M₁ = 1.51 M

Molarity of KOH M₂ = 1.51 M

volume of KOH V₂ = 30.9  mL

volume of H₂SO₄ V₁  = ?

Now we have to find out the volume 0f H₂SO₄:

M₁ V₁ / M₂ V₂ = n₁ / n₂

where, n₁ and n₂ are the n factors of H₂SO₄ and KOH ( coefficient )

putting all the values:

2 × 1.51 M × V₁ = 1 × 1.51 M × 30.9 mL

V₁ = 15.45 mL  

Thus , The milliliters of 1.51 mol/L H₂SO₄(aq) are required to completely neutralize 30.9 mL of 1.51 mol/L KOH is 15.45 mL.

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Explanation:

The electron configuration for the first row transition metals consists of 4s and 3d subshells with an argon (noble gas) core. This only applies to the first row transition metals, adjustments will be necessary when writing the electron configuration for the other rows of transition metals.

if the value of hvap for a substance is 36 and its h freezing is -16,  its sublimation value is 52 kj/mol.

ΔHsub=ΔHvap + ΔHfusion

ΔHfusion= -ΔHfreezing

     ΔH fusion   =16

ΔHsub=36+16

=52 Kj/mol

Sublimation is the process by which a substance moves straight from the solid phase to the gas phase without first going through the liquid phase (Table 4.8, Fig. 4.2). At temperatures and pressures lower than a chemical's triple point in the phase diagram, sublimation, an endothermic phase transition, takes place. a method by which a substance transforms from a liquid to a solid. When the temperature drops low enough, everything except helium begins to freeze. A substance turns from a liquid to a solid through the process of freezing. When a liquid's molecules slow down enough to attract one another and organize themselves into stable places as a solid, freezing happens.

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A metallic bond refers to the electrostatic attraction between positively charged metal ions and delocalized electrons in a metal. Option A is correct.

In a metallic bond, the valence electrons of the metal atoms become delocalized and are free to move throughout the metal lattice. The metal cations are held together by the surrounding sea of delocalized electrons.

This results in a strong bond between the metal atoms that gives rise to the characteristic properties of metals, such as high electrical conductivity, high thermal conductivity, and malleability. The metallic bond is a type of chemical bond that is found only in metals and their alloys.

Hence, A. The attraction of a metallic cation for delocalized electrons is the correct option.

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TRUE. At solubility equilibrium, the rates of precipitation (solid particles coming out of solution) and dissolution (solid particles going into solution) are equal.

This means that the concentration of the dissolved substance in the solution remains constant over time. When the rates of precipitation and dissolution are equal, the solution is said to be saturated with the substance, and no more of it can dissolve under the current conditions.

TRUE At solubility equilibrium, the rates of precipitation (the process of a dissolved substance coming out of solution) and dissolution (the process of a substance dissolving into solution) are equal. This means that the amount of substance dissolving into the solution is the same as the amount of substance precipitating out of the solution, maintaining a constant concentration of the dissolved substance.

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1) Reaction rate. This refers to the speed of a reaction. It can be affected by concentration, pressure, temperature, surface area, and catalysts.

Increasing the temperature increases the kinetic energy of the molecules. This increases the frequency of particle collisions. If particles have more kinetic energy, collisions are more effective.

Option A.

.

Answer:

Verdadero.

Explanation:

¡Hola!

En este caso, dado que las propiedades periódicas nos hablan de un comportamiento específico sobre los elementos en la tabla periódica, resulta primeramente necesario recordar que la electornegatividad nos dice que tan fuerte es un elemento para atraer electrones de valencia de otros elementos.

De este modo, inferimos que es verdadero, ya que de hecho la electronegatividad nos define el tipo de enlace, basado en la diferencia de electronegatividades de los elementos enlazados, de acuerdo con la imagen adjunta.

Saludos!

Answer:

itos6oyoyoydkgzkstgjuf