A 4 kg block is pushed 2m at an acceleration of 0.2 meter per second square up a vertical wall by constant force f applied at an angle of 37 degree with the horizontal if the coefficient of kinetic friction between the block and the wall is 0.30 find the work done by the applied force the frictional force
The work done by the applied force on the block against the frictional force is 15.75 J.
What is work done?Work done is equal to product of force applied and distance moved.
Work = Force x Distance
Given is a 4 kg block is pushed 2m at an acceleration of 0.2 meter per second square up a vertical wall by constant force f applied at an angle of 37 degree with the horizontal if the coefficient of kinetic friction, μ between the block and the wall is 0.30.
From the equilibrium of forces acting on the block, we have
F - f = ma
where, F is applied force, f is frictional force, m is the mass and a is the acceleration.
Frictional force f = μmgsinθ
Substitute the values, we get
Fcos(37) - μmgsin(37) = ma
Fcos(37) - (0.3)(4)(9.8)sin(37) = 4(0.2)
0.799F - 7.077 = 0.8
F = 9.86 N
Work done by the applied force is
W = Fdcosθ
W = 9.86 x 2 x cos(37)
W = 15.75 J
Thus, the work done by the applied force on the block against the frictional force is 15.75 J.
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. A car starts to move from rest has an acceleration of 3m/s².what will be the velocity and distance travelled by the car after 50sec.
Sure! Here are the steps for calculating the velocity and distance traveled by the car after 50 seconds :
Step 1: Calculate the velocity using the equation:
\(v = u + at\)
where:
- \(v\) is the final velocity
- \(u\) is the initial velocity (0 m/s, as the car starts from rest)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(v = 0 + (3 \, \text{m/s²}) \times (50 \, \text{s})\)
Step 2: Calculate the distance traveled using the equation:
\(s = ut + \frac{1}{2}at^2\)
where:
- \(s\) is the distance traveled
- \(u\) is the initial velocity (0 m/s)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(s = 0 \times (50 \, \text{s}) + \frac{1}{2} \times (3 \, \text{m/s²}) \times (50 \, \text{s})^2\)
Now, let's simplify these equations:
\(v = 3 \times 50\)
\(s = \frac{1}{2} \times 3 \times 50^2\)
Calculating the results:
\(v = 150\) m/s
\(s = 3750\) meters
Therefore, after 50 seconds, the car will have a velocity of 150 m/s and would have traveled a distance of 3750 meters.
Calculate the running costs of a filament lamp with a 60 W bulb and a CFL lamp with a 15 W bulb for 15 hours.
1 kWh costs 10p.
cost = power (kW) × time (hours) × price (per kWh)
Answer:
the cost of running the bulbs is 11.25p
Explanation:
Given;
cost of running 1 kwh = 10 p
power of filament bulb, P = 60 W
power of the CFL bulb, P = 15 W
time of power consumption, t = 15 hours
Total Energy consumed;
E = (60W + 15W) x 15 hours
E = (75)(15)
E = 1125 Wh
E = 1.125 kWh
Cost of 1.125 kWh = 1.125 x 10p
= 11.25p
Therefore, the cost of running the bulbs is 11.25p
If you toss a ball straight upward at 40 m/s with no air resistance, what will be its speed 7 seconds later?
The speed of the ball seven seconds later is 28.6 m/s.
What is the speed of the ball?We have the following information;
initial velocity of the ball = 40 m/s
time taken = 7 seconds
Acceleration of the ball = 9.8 m/s^2
Now;
v = u - gt (the ball is moving upwards)
v = 40 - (9.8 * 7)
v = 28.6 m/s
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HELPPPPPPPO
In the diagram, q1 = +6.60*10^-9 C and
q2 = +3.10*10^-9 C. Find the magnitude
of the total electric field at point P.
Explanation:
is this the full question?
Answer:
1258.46
Explanation:
Acellus
whats the result of rounding 52.8015 into five significant figures
Answer:
52.802
Explanation:
"Significant figures" in Mathematics refer to the digits that give accuracy to the value of a measurement. There are specific rules when it comes to determining the significant figures. For example, all non-zero digits are considered significant and zeroes located in-between non-zero numbers are significant. In the number given above, the digit "0" is located between "8" and "1," therefore, it is significant. All the digits above are significant.
The problem is only asking for "five" significant figures. We can do this by counting from the left to the right. By this means, we know that the number will be rounded off to the nearest thousandths, which is "1." The number after 1 is 5, which means that 1 digit will be added to number 1, thus, making the digit into "2." The last digit (5) will then be removed.
Explanation:
five significant of 52.8015=52.801 ..
If the velocity of sound in air at 16°C is 340ms. What will it be when the pressure is double and its temperature raised to 127°C? A. 400ms! B. 8,000ms C. 160,000 Ms¹ D. 4,000ms¹
The velocity of sound in air depends on the temperature and pressure of the air. The relationship between the velocity of sound, temperature, and pressure is given by the formula:
v = (k * T / μ)^(1/2)
where v is the velocity of sound, T is the temperature in Kelvin, k is the adiabatic constant of the gas (for air it is about 1.4), and μ is the molecular mass of the gas. To solve this problem, we need to find the new velocity of sound when the pressure is double and the temperature is raised to 127°C (which is 400K). First, we need to convert the temperature to Kelvin:
T = 127°C + 273 = 400K
Now, we need to find the new value of μ, which is the molecular mass of air. This value does not change with pressure or temperature, and it is approximately 28.97 g/mol.
Next, we need to find the new value of k, which is the adiabatic constant of the gas. This value also does not change with pressure or temperature, and it is approximately 1.4 for air.
Now we can use the formula to calculate the new velocity of sound:
v = (k * T / μ)^(1/2)
v = (1.4 * 400 / 28.97)^(1/2)
v = 446.8 m/s
Therefore, the new velocity of sound is 446.8 m/s. The answer is not one of the options given, but the closest option is D. 4,000 ms^-1, which is approximately 4,000 m/s. An item will have some horizontal and vertical velocity when projected at an angle, depending on the angle of projection. Since there is no horizontal motion, the projectile's horizontal component stays the same. At every position, the vertical component is different.
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Question 7.
When can a mouse have the same momentum as an elephant?
د ن ه ه
A. when the mouse has a large velocity and the elephant has a small velocity
when the mouse has a small velocity and the elephant has a large velocity
a mouse cannot have the same momentum as an elephant
D. when they both have the same velocity
A mouse have the same momentum as an elephant when the mouse has a large velocity and the elephant has a small velocity. The correct option is A.
What is momentum?The momentum is the product of the mass of the object and its velocity.
Mouse has mass very less than the elephant. In order to make their momentum same, the velocity of the mouse must be greater than the elephant.
Mm x Vm = Me x Ve
A mouse have the same momentum as an elephant when the mouse has a large velocity and the elephant has a small velocity.
Thus, the correct option is A.
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How much work is done when a car is pushed 8 m with 160 N of force?
Answer: 1280 J
Explanation: Work is calculated by multiplying the displacement (8m) by the force (160 N) which will give you 1280 J (joule)
What type of specialized cell in the eye is used for detecting low levels of light?
Answer:
There are about six to seven million cones in a human eye and are most concentrated towards the macula. Cones are less sensitive to light than the rod cells in the retina (which support vision at low light levels), but allow the perception of color.
Answer:
Rods
Explanation:
There are about six to seven million cones in a human eye and are most concentrated towards the macula. Cones are less sensitive to light than the rod cells in the retina (which support vision at low light levels), but allow the perception of color.
If a hydroxide dissolves in water what is it called
Answer:
Strong Electrolyte
Explanation:
Prove that for any division algebra D over k, the transpose map Mn(D^op) → (Mn(D))^op, X -> X^T is an algebra isomorphism.
To prove that for any division algebra D over k, the transpose map Mn(D^op) → (Mn(D))^op, X -> X^T is an algebra isomorphism, we need to show that the map preserves both the algebra structure and the vector space structure. 1. Vector space structure:
Since the transpose operation does not affect scalar multiplication and matrix addition, it preserves the vector space structure over k. 2. Algebra structure: We need to show that the map preserves the product, meaning (AB)^T = B^T A^T for all A, B in Mn(D^op).Using the definition of the product in D^op, we have:
(AB)^T = (a_ij b_jk)^T = (b_jk)^T (a_ij)^T = (b_jk^op)(a_ij^op) = B^T A^T This shows that the map preserves the algebra structure. Therefore, the transpose map Mn(D^op) → (Mn(D))^op, X -> X^T is an algebra isomorphism.About AlgebraAlgebra is a branch of mathematics that studies symbols and the rules for manipulating those symbols. Algebra covers a wide range of topics, such as linear algebra, abstract algebra, universal algebra and elementary algebra. Algebra comes from the Arabic word "al-jabr" which means "to put together the broken parts".
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6. A book that weighs 48N and is lifted 11.6m from the floor to a tabletop. How much work is required to
accomplish this task?
How does 'g' vary from place to place?
Explanation:
The acceleration g varies by about 1/2 of 1 percent with position on Earth's surface, from about 9.78 metres per second per second at the Equator to approximately 9.83 metres per second per second at the poles.
How would a weaker jet stream help to cause extreme flooding?(1 point)
Answer:
It would allow storm systems to stall in an area.
Answer: A weaker jet stream would allow storm systems to stall in one area.
Explain how energy is conserved during chemical reactions
In a chemical reaction, energy is conserved because it is neither created nor destroyed during the chemical reaction
What is conservation of energy?The law of conservation of energy states that energy cannot be created or destroyed but can be changed from one form to another.
In a chemical reaction, energy is used to break the bonds of the reactant and it's released when products are formed.
Therefore, In a chemical reaction, energy is conserved because it is neither created nor destroyed during the chemical reaction.
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SOMEONE HELP
Perform the following conversion.
0.09 km to dam
Answer:9
Explanation:
state 8/15 as a decimal correct to four decimal places
Answer:
8/15=0.53..., since the 3 is repeating, just stop at the 4th decimal place, thus
0.5333
Explanation:
A wave has a period of 4 seconds. Find it’s frequency.
Answer:
4 x the frequncy
Explanation:
So 4 x the number
Why is rust formed on iron
URGENT : need this for tmmr
2.2cm^3
As per the statement the given measurement of different volumes
Let consider
V1 = 2.1cm^3
V2 = 2.1cm^3
V3 = 2.4cm^3
Now, we are supposed to find the mean value
mean value = submission of total number observation÷ sum of no. of observation
mean value = 2.1+2.1+2.4÷ 3
mean value = 6.6÷3
mean value= 2.2cm^3
The central tendency of data is measured by the term "mean." It is a value that, in general, may be used to express the primary value of a group of data. It is determined by adding up all of the data set's observations and dividing the result by the total number of observations.To know more about mean value visit : https://brainly.com/question/12513463
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Asking why and how about various things in life is a way to develop which life skill?
Answer:
Learning skills
Explanation:
Remember, life skills refer to essential mental and physical abilities needed by a person to successfully face challenges of everyday life.
Therefore, an individual who inquires why and how about the various things in life is developing his learning skill, thereby also increasing his critical thinking abilities.
A diffraction grating has 45,000 slits/cm. What is the distance between adjacent slits?.
The distance between adjacent slits in this diffraction grating is approximately 2.22 × 10^-3 meters or 2.22 micrometers.
The distance between adjacent slits in a diffraction grating can be found using the formula:
d = 1/N
where d is the distance between adjacent slits and N is the number of slits per unit length. In this case, N = 45,000 slits/cm. Converting to slits/m, we have:
N = 45,000 slits/cm x (1 m/100 cm) = 450 slits/m
Substituting into the formula, we get:
d = 1/N = 1/450 slits/m ≈ 2.22 × 10^-3 m/slit
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In addition to the anti-VEGF antibody, Marie has decided to also add a VEGFR primary antibody. At which position do you expect the band for VEGFR to appear? Remember that in SDS-PAGE proteins are separated according to their molecular weight. a) VEGFR runs at a lower molecular weight than VEGF b) VEGF and VEGFR run at the same molecular weight c) VEGFR cannot be detected by Western blotting d) VEGFR runs at a higher molecular weight than VEGF
VEGFR runs at a higher molecular weight than VEGF. In the position, VEGFR is expected to appear band. Hence, option (c) is correct.
What is VEGFR?A chemical that binds to vascular endothelial growth factor (VEGF) receptors, which may be present on some cancer cells. This might stop cancers from forming the new blood vessels they require to grow.
Anti-VEGFR monoclonal antibodies of various sorts are being researched for the treatment of cancer. These chemicals fall within the categories of monoclonal antibodies and antiangiogenesis agents.
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A cyclist and his bicycle have a combined mass of 88 kg and a combined weight of 862. 4 N. The cyclist accelerates at 1. 2 m/s?. After 2 seconds he reaches a speed of 2. 4 m/s. What is his momentum at this point?
The momentum of the cyclist is 211.2 kg m/s. It is calculated by multiplying the mass of the cyclist and the bicycle (88 kg) by their velocity (2.4 m/s).
The momentum of the cyclist can be calculated using the formula:
momentum = mass x velocity
We know the combined mass of the cyclist and bicycle is 88 kg, and the cyclist accelerates from rest to a speed of 2.4 m/s in 2 seconds at a rate of 1.2 m/s². We can calculate the distance traveled using the formula:
distance = 0.5 x acceleration x time²
distance = 0.5 x 1.2 m/s² x (2 s)² = 2.4 m
Now, we can use the distance traveled to calculate the average velocity during the acceleration:
average velocity = distance / time = 2.4 m / 2 s = 1.2 m/s
Finally, we can calculate the momentum of the cyclist using the formula:
momentum = mass x velocity
momentum = 88 kg x 2.4 m/s = 211.2 kg m/s
Therefore, the momentum of the cyclist at this point is 211.2 kg m/s.
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When using the general multiplication rule, P(A and B) is equal to _____.a. P(A|B)P(B)b. P(A)P(B)c. P(B)/P(A)d. P(A)/P(B)
When using the general multiplication rule, P(A and B) is equal to P(A|B)P(B). (A)
What is multiplication rule of probability?The multiplication rule of probability states that the probability of two independent events occurring together is equal to the product of the probability of each event occurring separately. In other words, if two events, A and B, are independent, then the probability of both A and B occurring is P(A) * P(B).
The universal multiplication rule is used to calculate the likelihood of two events occurring concurrently, or the intersection of two ongoing events, or the union of the two events.
It asserts that the chance of both occurrences happening at the same time is equal to the likelihood of one event happening given that the other event has happened multiplied by the probability of the other event that occuring in the nature.
Therefore, the correct answer is P(A|B)P(B). (A)
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a hollow sphere of radius 0.15 m, with rotational inertia 1 : 0.040 kg ' m2 about a line through its center of mass, rolls without slipping up a surface inclined at 30' to the horizontal. at a certain initial position, the sphere's total kinetic energy is 20 j. (u) how much of this initial kinetic energy
19.778 J of the initial kinetic energy is transformed into potential energy as the sphere rolls up the incline.
Radius of the sphere = 0.15 m
Rotational inertia = 1: 0.040 \(kg /m^{2}\)
Inclination = 30 degrees
total kinetic energy = 20 J
(a) The total energy of the system at the initial position is:
E_i = K_i = 20 J
At the highest point, the kinetic energy will be zero. The potential energy is almost equal to the initial kinetic energy.
E_f = U_f = K_i = 20 J
The potential energy of the sphere at the highest point is calculated by:
U_f = mgh
h = (2/3) R (1 - cos(theta))
h = (2/3)(0.15 m)(1 - cos(30°)) = 0.0675 m
The final potential energy of the system is:
U_f = mgh
U_f = (1/2) mv_\(f^2\)
U_f = 20 J
K_f = (1/2)*(1)*(9.8 \(m/s^2\))*(0.0675 m)
K_f = 0.222 J
Therefore, the initial kinetic energy is converted into potential energy,
Delta K = K_i - K_f
Delta K = 20 J - 0.222 J
Delta K = 19.778 J
Therefore we can conclude that 19.778 J of the initial kinetic energy is converted to potential energy as the sphere rolls up the incline.
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The amount of initial kinetic energy converted into rotational kinetic energy is 10 J.
How much of the initial kinetic energy is converted into rotational kinetic energy?When a hollow sphere rolls without slipping up an inclined surface, both translational and rotational motion contribute to its kinetic energy. The initial kinetic energy of the sphere is divided between its translational and rotational components. In this case, since the sphere rolls without slipping, the rotational kinetic energy is given by the equation 1/2 * I * ω^2, where I is the rotational inertia and ω is the angular velocity.
To find the amount of initial kinetic energy converted into rotational kinetic energy, we need to determine the angular velocity of the sphere. Since the sphere is rolling without slipping, the linear velocity v and angular velocity ω are related by the equation v = ω * R, where R is the radius of the sphere.
Given the radius of the sphere as 0.15 m, the rotational inertia as 0.040 kg•m^2, and the total initial kinetic energy as 20 J, we can use the equation for rotational kinetic energy and the relationship between linear and angular velocity to solve for the rotational kinetic energy.
First, we calculate the linear velocity using the equation v = ω * R:
v = ω * R
v = ω * 0.15 m
Next, we substitute the value of linear velocity into the equation for total kinetic energy to solve for the angular velocity:
20 J = 1/2 * I * ω^2 + 1/2 * m * v^2
Since the sphere is rolling without slipping, the linear velocity v can be written as v = ω * R:
20 J = 1/2 * I * ω^2 + 1/2 * m * (ω * R)^2
Now we substitute the given values and solve for ω:
20 J = 1/2 * 0.040 kg•m^2 * ω^2 + 1/2 * m * (ω * 0.15 m)^2
Simplifying the equation and solving for ω:
20 J = 0.020 kg•m^2 * ω^2 + 1/2 * m * (0.15 m)^2 * ω^2
20 J = 0.020 kg•m^2 * ω^2 + 0.01125 kg * ω^2
Combining like terms:
20 J = (0.020 kg•m^2 + 0.01125 kg) * ω^2
20 J = 0.03125 kg•m^2 * ω^2
Now, we isolate ω^2:
ω^2 = 20 J / 0.03125 kg•m^2
ω^2 ≈ 640
Finally, we take the square root of ω^2 to find the angular velocity ω:
ω ≈ √640
ω ≈ 25.3 rad/s
Now that we have the angular velocity ω, we can calculate the rotational kinetic energy:
Rotational kinetic energy = 1/2 * I * ω^2
Rotational kinetic energy = 1/2 * 0.040 kg•m^2 * (25.3 rad/s)^2
Rotational kinetic energy ≈ 10 J
Therefore, approximately 10 J of the initial kinetic energy is converted into rotational kinetic energy.
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How much time does a car with an acceleration of 2 m/s2 take to go from 10 m/s to 30 m/s?
Answer: 10 seconds for the car to go from a velocity of 10 m/s to 30 m/s with an acceleration of 2 m/s^2.
Explanation:
To calculate the time it takes for a car with an acceleration of 2 m/s^2 to go from a velocity of 10 m/s to a velocity of 30 m/s, we can use the equation:
time = (final velocity - initial velocity) / acceleration
In this case:
time = (30 m/s - 10 m/s) / 2 m/s^2
time = 20 m/s / 2 m/s^2
time = 10 s
Therefore, it takes 10 seconds for the car to go from a velocity of 10 m/s to 30 m/s with an acceleration of 2 m/s^2.
Carbon dioxide concentrations are often used as proxy for temperature. What does this mean? Atmospheric CO2 concentrations and global temperature are indirectly related, so when CO2 rises, temperature drops Atmospheric CO2 concentrations and global temperature are directly related, so when CO2 rises, so does temperature Atmospheric CO2 concentrations and global temperature fluctuate independently
Atmospheric CO2 concentrations and global carbon temperature are directly related, so when CO2 rises, so does temperature.
On the other hand, when CO2 concentrations decrease, this leads to a decrease in the greenhouse effect and less heat being trapped, causing temperatures to drop.
So, to answer your question, atmospheric CO2 concentrations and global temperature are indirectly related, meaning that when CO2 rises, temperature also rises.
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in a liquid with a density of 1100 kg/m3 , longitudinal waves with a frequency of 430 hz are found to have a wavelength of 7.80 m . calculate the bulk modulus of the liquid.
The bulk modulus of the liquid is 13.31 GPa.
The bulk modulus of a substance is the degree of ways immune to compression the substance is. it's miles defined because of the ratio of the infinitesimal stress boom to the ensuing relative decrease of the volume.
Young's Modulus is the ability of any fabric to withstand the change along its duration. Bulk Modulus is the potential of any fabric to face up to the alternate in its extent. once in a while known as incompressibility, the majority modulus is a degree of the potential of a substance to withstand changes in extent while underneath compression on all aspects. it is the same to the quotient of the implemented strain divided by the relative deformation.
Calculation:-
ρ = 1300 kg/m3 , f = 400 Hz , \small \lambda = 8 m
We know that speed can be given as :
v = \small \lambda*f
i.e. calculating speed as :
v = (8 m)*(400 Hz) = 3200 m/s
The relation between speed, Bulk modulus, and density is :
v = \small \sqrt(K/\small \rho)
Calculating Bulk modulus as :
K = v2*\small \rho
= (3200 m/s)2*(1300 kg/m3)
= 13.31× 109 Pa = 13.31 GPa
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