Use the drop-down menus to complete the statements.
A vertical column of elements in the periodic table is called a .
A horizontal row of elements in the periodic table is called a .
Atoms of elements in the same group have the same .
As you move from left to right on the periodic table, the atomic number .

She is likely to have tip toed as the pressure applied is high.

Pressure is a force per unit area, typically measured in units of Pascal (Pa), atmospheres (atm), or pounds per square inch (psi). It is the result of the force exerted by a gas or liquid against a surface.

We have to note that the pressure that has a value of about  1,500,000 Pa  is quite a large pressure and we can only have such a pressure when we have a small surface area upon which the pressure have been applied.

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Explanation:

If no force is exerted on a moving object, it will continue to move at a constant velocity. This is described by Newton's first law of motion, which states that an object will remain at rest or continue to move at a constant velocity in a straight line unless acted upon by an external force. In other words, if no net force acts on an object, the object will maintain its velocity, neither speeding up nor slowing down.

Answer:

The coefficient of friction is (F/(19.6·m)

Explanation:

The given parameters are;

The force applied to the immovable body = F

The time duration the force acts = t

The time the body spends in motion = 3·t

The acceleration due to gravity, g = 9.8 m/s²

From Newton's second law of motion, we have;

The impulse of the force = F × t = m × Δv₁

Where;

Δv₁ = v₁ - 0 = v₁

The impulse applied by the force of friction, \(F_f\) is \(F_f\) × (3·t - t) =  \(F_f\) × (2·t)

Given that the motion of the object is stopped by the frictional force, we have;

The impulse due to the frictional force = Momentum change = m × Δv₂ = \(F_f\) × (2·t)

Where;

Δv₂ = v₂ - 0 = v₂

Given that the velocity, v₂, at the start of the deceleration = The velocity at the point the force ceased to  act, v₁, we have;

m × Δv₂ = \(F_f\) × (2·t) = m × Δv₁ = F × t

∴ \(F_f\) × (2·t) = F × t

\(F_f\) = F × t/(2·t) = F/2

The coefficient of dynamic friction, \(\mu _k\) = Frictional force/(The weight of the body) = (F/2)/(9.8 × m)

\(\mu _k\) = (F/(19.6·m)

The coefficient of friction, \(\mu _k\) = (F/(19.6·m)

A. Assume incompressible flow

Since volumtric flow rate will be same in both section

Q1 = Q2

A1*V1 = A2*V2

V2 = A1*V1/A2

V2 = 6.9*10^-4*288*10^-2/(3.3*10^-4)

V2 = 6.02 m/sec

B. using bernoulli's equation:

P1/rho + v1^2/2 + g*h1 = P2/rho + v2^2/2 + g*h2

Since pipes are horizontal

h1 = h2

P1/rho + v1^2/2 = P2/rho + v2^2/2

P2 = P1 + (v1^2 - v2^2)*rho/2

P2 = 1.5*10^5 + (2.88^2 - 6.02^2)*1100/2

P2 = 1.35*10^5 Pa

The rate of change in position of an object in any course. Speed is measured because the ratio of distance to the time wherein the distance became included. Speed is a scalar amount because it has handiest route and no significance.

Velocity can be notion of as the rate at which an object covers distance. A quick-moving object has a high speed and covers a notably big distance in a given amount of time, whilst a sluggish-shifting item covers a relatively small amount of distance in the same amount of time.

The primary unit or the S.I. unit of velocity is m/s or ms?¹.

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Answer:

35%

Explanation:

Answer:

its 83

Explanation:

Answer:

To find the work done in moving the particle from the origin to x = 2, we need to integrate the force over the given interval.

The work done (W) is calculated by integrating the force function with respect to displacement (dx) from the initial position (0) to the final position (2):

W = ∫(0 to 2) (10x³ - 5) dx

Integrating the force function, we get:

W = ∫(0 to 2) (10x³ - 5) dx = [2.5x⁴ - 5x] evaluated from 0 to 2

Now, substituting the upper limit (2) and lower limit (0) into the equation:

W = [2.5(2)⁴ - 5(2)] - [2.5(0)⁴ - 5(0)]

 = [2.5(16) - 10] - [0 - 0]

 = 40 - 10

 = 30

Therefore, the work done in moving the particle from the origin to x = 2 is 30 units of work.

Explanation:

The average rotational latency of a hard drive rotating at 7,200 rpm or 120 revolutions per second is 4.16 ms.

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Answers:

The transportation industry is no stranger to the manipulation of everyday physics. Cars and trains utilize the wheel, which provides a smooth, steady motion.

The ears hear sounds which occur through the movement of air molecules, and the chemistry that drives all of biology depends on the physics of energy and molecules. Every day, for example, plants absorb sunlight, water, and carbon dioxide, creating glucose and releasing oxygen as a byproduct.

Brainlist pls!

Answer:

10 000

Explanation:

According to the question C. The values of ΔG° for each reaction are not shown.

A reaction is a chemical process that takes place within a system and is researched using thermodynamic concepts. The study of energy transfer and the behaviour of systems, especially chemical reactions, is the main emphasis of thermodynamics.

Energy changes, notably in the form of heat and work, are a part of thermodynamic reactions. The response has the ability to work with or be worked on by its environment, as well as to either absorb or emit heat energy from it. Enthalpy (H), entropy (S), and Gibbs free energy (G) are examples of thermodynamic parameters that can be used to measure the energy changes brought about by reactions.

The thermodynamic favorability for each component reaction that the combined reaction in a coupled pair of reactions is crucial to comprehending how coupled reactions function. Because of the combination of the unfavorable disintegration of iron oxide into its constituent parts (G°>0) and the advantageous burning of carbon to produce carbon dioxide (G°0), the blast furnace reaction in this instance is favorable.

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Complete Question:

Answer:

Explanation:

In this problem we are expected to find the weight of the plastic tank and the weight of the equal volume of water

Given that

density of water = 1000 kg/m^3

volume of plastic tank is same as the volume of water= 0.18 m^3

we need to solve for the mass of the water

we know that density is = mass/volume

1000= mass/0.18

mass= 1000*0.18

mass= 180 kg

the total mass of the combined system is

4+180= 184 kg

the weight = mg (assuming g= 9.81 m/s^2)

weight = 184*9.81

weight= 1805.04 N

Answer:

extrusive igneous rock

Explanation:

Centripetal force on the end of a 66.0 m (radius) wind turbine blade that is rotating is calculated as = 1.23 *10^-4 N.

Centripetal force is the force acting on the object in curvilinear motion directed towards axis of rotation or the center of curvature and the unit of centripetal force is newton. It is directed perpendicular to the direction of the displacement of the object.

Given, radius= 66m mass is 3.4 kg

Given 0.47 rev/s

Angular velocity = 0.47 * 2π / 60

= 0.049 m/s

Centripetal force = mass * velocity²/radius

= 3.4 *  0.049² /66

Centripetal force= 1.23 *10^-4 N

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The distance horizontally, from the initial dropping point that the pit hit the ground is 11.2 meters.

The formula of distance is Distance = Speed x Time which is measured in meters.

7. The height of the car window h = 5.0 metres

The velocity of the car is 35 m/s.

The horizontal velocity of the cherry pit when it is released is then the same as that of the car Vx = 35m/s

The dropped cherry pit falls freely under gravity with a vertical downward acceleration equal to the acceleration due to gravity, g

Initially, the pit has no vertical component of velocity.

Therefore the time it takes to reach the ground t = \(\sqrt{} \frac{2h}{g}\)

t = √10/9.8

t= 0.32 seconds

The horizontal component of velocity is a constant, since there are no forces acting in the horizontal direction.

Therefore the horizontal distance travelled by the pit by the time it hits the ground is Vx * time

= 35 x 0.32

= 11.2 meters

attached is a picture of the situation above, where Vx = 35m/s

h = 5.0 meters

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The required,

a) \(N'/N_0\) ≈ 0.408 (40.8%)

b) Approximately 40.8% of the atoms are in the excited state.

c) \(N'/N_0\) ≈ 0.066 (6.6%)

To calculate the ratio of N'/N_0 in an air-acetylene flame, we can use the Boltzmann distribution equation:

\(N'/N_0 = (g'/g_0) * exp^{(-\triangle E/kT)}\)

a) Calculate the ratio of \(N'/N_0\) in an air-acetylene flame (2500 K):

Given:

\(g_0 = 1\) (degeneracy of the ground state)

\(g' = 3\) (degeneracy of the excited state)

\(\triangle E = 8.68 * 10^{(-19)}\)J/atom (energy difference between the excited and ground states)

T = 2500 K (temperature)

\(N'/N_0 = (3/1) * e{(-8.68 * 10^{19} / (1.38 * 10^{-23} * 2500 ))\)

Calculating the exponential term:

exp(-8.68 x 10⁻¹⁹ J/atom / (1.38 x 10⁻²³ J/K * 2500 K)) ≈ 0.136

Therefore, the ratio of \(N*/N_0\) in an air-acetylene flame is:

\(N'/N_0\) ≈ (3/1) * 0.136 ≈ 0.408

b) To determine the percent of atoms in the excited state, we can multiply the ratio \(N'/N_0\) by 100:

Percent in excited state = \(N'/N_0 * 100\)

Percent in excited state ≈ 0.408 * 100 ≈ 40.8%

Therefore, 40.8% of the atoms will be in the excited state.

Similarly,

c) If an argon plasma (10,000 K) is used instead of the air-acetylene flame, we can repeat the calculations using the new temperature:

The ratio of \(N*/N_0\) in an argon plasma is:

N'/N0 ≈ (3/1) * 0.022 ≈ 0.066

To determine the percent of atoms in the excited state:

Percent in excited state = \(N'/N_0 * 100\)

Percent in excited state ≈ 0.066 * 100 ≈ 6.6%

Therefore, 6.6% of the atoms will be in the excited state in an argon plasma.

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Answer:

B) 4 m/s²

Explanation:

\( \boxed{ \sf{ F= m \times a}}\)

Here,

Substituting the respective values for F and m:

==> 220 = 55 × a

==> 220 = 55 × a

dividing the equation by 55:

==> 4 = a

Therefore, an object of 55 kg when pulled across a frictionless surface by a force of 220 N accelerates at 4 (m/s)/s

Answer:What is the acceleration of a car that moves from rest to 15.0 m/s in 10.0 s? Vi=0, vf= 15.0 m/s,t=10.0s, a=? a= vf =vi/tA=15.0m/s-0m/s/10.0s = 15.0s/10.0s m/s*1/s =1.50 m/s^2 11.

Explanation:

Answer:

F = 32 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = forces applied [N] (units of Newtons)

m = mass = 40 [kg]

a = acceleration = 0.8 [m/s²]

Now replacing:

\(F=m*a\\F = 40*0.8\\F = 32 [N]\)

Answer:

Explanation:

A change in an object’s motion—such as Xander speeding up on his scooter—is called acceleration. Acceleration occurs whenever an object is acted upon by an unbalanced force. The greater the net force acting on the object, the greater its acceleration will be, but the mass of the object also affects its acceleration. The smaller its mass is, the greater its acceleration for a given amount of force. Newton’s second law of motion summarizes these relationships. According to this law, the acceleration of an object equals the net force acting on it divided by its mass.

The maximum torque on a flat current-carrying loop occurs when the angle between the plane of the loop's area and the magnetic field vector is 90 degrees.

When a current-carrying loop is placed in a magnetic field, a torque is exerted on the loop.

This torque is given by the formula τ = μ x B x sinθ,

where τ is the torque,

μ is the magnetic moment of the loop (equal to the product of the current and the area of the loop),

B is the magnetic field strength, and θ is the angle between the loop's area and the magnetic field vector.

To find the maximum torque, we need to maximize the value of sinθ.

The maximum value of sinθ is 1, which occurs when the angle θ is 90 degrees (sin90° = 1).

Therefore, the maximum torque on a flat current-carrying loop occurs when the angle between the plane of the loop's area and the magnetic field vector is 90 degrees.

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The moment of inertia of the flywheel is 2.63 kg-\(m^{2}\)

It is given that,

The maximum energy stored on the flywheel is given as

E=3.7MJ= 3.7×\(10^{6}\) J

Angular velocity of the flywheel is 16000\(\frac{rev}{min}\) = 1675.51\(\frac{rad}{sec}\)

So to find the moment of inertia of the flywheel. The energy of a flywheel in rotational kinematics is given by :

E = \(\frac{1}{2}\)\(Iw^{2}\)

By rearranging the equation:

I = \(\frac{2E}{w_{2} }\)

I = 2.63 kg-\(m^{2}\)

Thus the moment of inertia of the flywheel is 2.63 kg-\(m^{2}\).

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The separates inner planets from outer planets in our solar system is their location relative to the asteroid belt.

The inner planets, also known as terrestrial planets, consist of Mercury, Venus, Earth, and Mars. These planets are located closer to the Sun and are characterized by their solid, rocky surfaces, small size, and relatively high densities. On the other hand, the outer planets, also called gas giants or Jovian planets, include Jupiter, Saturn, Uranus, and Neptune. These planets are situated beyond the asteroid belt, which is a region filled with numerous small celestial bodies and debris.

Outer planets are much larger, have lower densities, and are primarily composed of gases such as hydrogen and helium, with possible solid cores. Additionally, inner planets have fewer moons and no ring systems, while outer planets possess numerous moons and distinct ring systems. The differences in composition, size, and other characteristics between inner and outer planets are a result of their distinct formation processes and positions within the solar system. So therefore the separates inner planets from outer planets in our solar system is their location relative to the asteroid belt.

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Answer:

Load = 80 Newton

Explanation:

Given the following data:

Effort = 20 N

Load arm = 15 cm

Effort arm = 60 cm

Conversion:

100 cm = 1 meters

15 cm = 15/100 = 0.15 meters

60 cm = 60/100 = 0.6 meters

To calculate the load, we would use the expression;

Effort * effort arm = load * load arm

Substituting into the expression, we have;

20 * 0.6 = load * 0.15

12 = load * 0.15

Load = 12/0.15

Load = 80 Newton

Answer:

Speed is constant but velocity is changing

Explanation:

Speed is a scalar quantity, meaning magnitude only. Velocity is a vector quantity, meaning magnitude and direction. If you're moving in a circle at a constant speed, the speed is constant but the direction is constantly changing. Therefore, the speed is constant but velocity changes.

Complete Question:

A student has been assigned to measure the density of an irregularly shaped piece of metal.

Which apparatus would be most appropriate to carry out this task?

Group of answer choices

A. ruler, balance

B. beaker, crucible

C. flask, Bunsen burner

D. graduated cylinder, balance

Answer:

D. graduated cylinder, balance

Explanation:

In this scenario, A student has been assigned to measure the density of an irregularly shaped piece of metal.

The apparatus which would be most appropriate to carry out this task is a graduated cylinder and balance.

A graduated cylinder can be defined as a measuring cylinder used for the measurement of the volume of an irregularly shaped piece of metal or liquids. It is typically marked with horizontal lines on its side as units of measurement for volume. The balance is then used to weigh the metals mass.

The potential, kinetic and total energy at the top are 2.38 x 10⁷ Joule,  0 Joule, 23.8 x 10⁶ Joule respectively and the potential, kinetic and total energy at the bottom are 0 Joule, 2.448 x 10⁶ Joule, 2.448 x 10⁶ Joule  respectively. moreover the total energies are not same as not all potential energy converting into Kinetic energy of vertically drop of ride as the ride moves straight afterwards so that also need some energy which is again coming from potential energy.

Energies at the top:-

Potential energy = mgh

Potential energy  = 3.4 x 10⁴  × 10 × 70 Joule

Potential energy  = 2.38 x 10⁷ Joule

Kinetic Energy = (1/2) mv²

Kinetic Energy = (1/2) × 3.4 x 10⁴ × 0²

Kinetic Energy = 0 Joule

Total Energy = Potential Energy + Kinetic Energy

Total Energy = ( 23.8 x 10⁶ Joule ) + ( 0 Joule )

Total Energy = 23.8 x 10⁶ Joule

Energies at the bottom:-

Potential energy = mgh

Potential energy  = 3.4 x 10⁴  × 10 × 0 Joule

Potential energy  = 0 Joule

Kinetic Energy = (1/2) mv²

Kinetic Energy = (1/2) × 3.4 x 10⁴ × 12²

Kinetic Energy = 2.448 x 10⁶ Joule

Total Energy = Potential Energy + Kinetic Energy

Total Energy = ( 0 Joule ) + ( 2.448 x 10⁶ Joule )

Total Energy = 2.448 x 10⁶ Joule

The total energies are not the same since not all potential energy is converted into Kinetic energy of the vertical drop of the ride as the ride travels straight thereafter thus that also requires some energy which is again derived from potential energy.

So we have calculated the potential, kinetic and total energy at top and bottom both, and also stated the reason of why total energy at the top is not equal to the total energy at the bottom.

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Answer:

Trabajo realizado = 600 Nm

Explanation:

Dados los siguientes datos;

Fuerza = 200 Newton

Distancia = 3 metros

Para encontrar el trabajo realizado; Trabajo realizado = fuerza * distancia

Sustituyendo en la ecuación, tenemos; Trabajo realizado = 200 * 3

Trabajo realizado = 600 Nm

The equivalent resistance of the circuit will be option (D) 80.0 Ω

According to Ohm's law, the voltage across two places is precisely proportional to the current flowing through a conductor between them.

The obstruction to current flow in an electrical circuit is measured by resistance. The Greek letter omega (Ω) represents the unit of measurement for resistance, known as ohms. Georg Simon Ohm is the name given to ohms.

Since in the given figure the resistance are in series so there equivalent resistance will be sum of the two resistance. If they were in parellal connection then we will add reciprocal of their resistance.

Let R1 = 60 Ω and R2 = 20 Ω. So their equivalent resistance will be as follow:

R = R1 + R2

R = 60 + 20

R = 80 Ω

Hence the equivalent resistance of the circuit will be 80 Ω

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We need to use Coulomb's Law to find the force between q1 and q3 and between q2 and q3. Then, we can use vector addition to find the net force on q1 and set it equal to 7.00 N in the negative x direction. Finally, we can solve for the position of q3.

The force between two point charges q1 and q3, separated by a distance r, is given by:

F = k*q1*q3/r^2

Where k is the Coulomb constant (9.0 x 10^9 N*m^2/C^2). Similarly, the force between q2 and q3 is given by:

F = k*q2*q3/(0.200 mm + r)^2

Where we have added 0.200 mm to the distance between q2 and q3 to account for the fact that q2 is not at the origin.

To find the net force on q1, we need to add up the forces from q3 and q2. Since the forces are vectors, we need to take into account their directions. Let's assume that q3 is located at a distance x from the origin and that the direction of the force from q3 on q1 is to the left (negative x direction). Then:

F_net = F_q3 + F_q2

Where:

F_q3 = -k*q1*q3/x^2 (to the left)

F_q2 = -k*q2*q3/(0.200 mm + x)^2 (to the right)

Setting F_net equal to 7.00 N in the negative x direction, we get:

7.00 N = -k*q1*q3/x^2 - k*q2*q3/(0.200 mm + x)^2

Plugging in the values for q1, q2, and q3, and solving for x, we get:

x = 0.124 m

Therefore, q3 is located at a distance of 0.124 m from the origin, in the negative x direction.

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