use correct alternative to complete the indirect speech sentence​

1.25 cm is the height of the image. 160 cm separates a converging lens with such a 40 cm focal length from a diverging lens with the a -40 cm focal length. The converging lens is 60 cm away from a 2.5 cm tall item.

A lens that conforms a parallel source beam of light is known as a converging lens. One kind of converging lens is a double convex lens. Converging Lens A lens that separates a parallel light beam is known as a diverging lens. Diverging lenses include those that are double concave.

For the diverging lens, this image height corresponds to object height. We obtain h ′D=(20cm40cm)(5.0cm)=1.25cm again for diverging lens as a result.

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The true statement about the accuracy and precision of measuring tools is Tools cannot be both accurate and precise. The correct option is C.

When in an experiment, a value is measured 5 times, then if the values measured are same for most of the time or like three times out of five, it said to be accurate. The phenomenon is accuracy.

Precision is about comparing the values to each other then find them near to each other.

Accuracy compares the experimental value to the theoretical value.

So, when all the values are close to each other but not nearest to the theoretical value, then it is said to be precise but not accurate.

Thus, the correct option is C.

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The student can conclude that in Experiment 1, the ball is following a parabolic path, demonstrated by the best-fit curve line. In Experiment 2, the ball is following a linear path, demonstrated by the best-fit curve line.

What is curve?
A curve is a line in a two-dimensional plane that is bent or curved. It is often used to describe the shape of objects or mathematical functions. It is often used to study changes in data over time and to understand the behavior of functions and equations. Curves can be described using a variety of mathematical equations and equations can be used to predict the behavior of a curve. Additionally, curves can be used to describe the motion of physical objects and to help visualize the relationships between the objects.

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Answer:

1. The electric potential at any point in space, is the work done in moving a unit charge from infinity to that point.

2.The electric potential varies radially by decreasing as the distance from the electric field increases.

Explanation:

1. The electric potential at any point in space, is the work done in moving a unit charge from infinity to that point. It is defined mathematically as, V = W/q where V = electric potential, W = work done in moving charge q into electric field and q = charge. For the work done of moving a charge q into an electric field of charge q' at a distance r between them, W = kqq'/r and work done per unit charge in moving q in electric field is V = W/q = kqq'/r ÷q = kq'/r, Also, for an electric field, E, V = ∫E.dr where r is the direction moved by the charge in the electric field.

2. Since the electric potential V = kq'/r, V ∝ 1/r since k and q' are constant. So, the electric potential varies radially by decreasing as the distance from the electric field increases.

Answer:

5 m per second

Explanation:

Answer:

20 m/s hope this helps ! :) well that what I rounded to technically its 19.81 m/s.

Explanation:

Answer:

The nucleus-containing cells are called eukaryotic cells. Eukaryote means having membrane-bound organelles.

Explanation:

I hope this is what you were looking for?!

Hope this helps!

Have a great day!

-Hailey!

The cells which have a nucleus are called Eukaryotic cells. The cells which do not have a nucleus are called prokaryotic cells.

The nucleus is the controlling center of the body. It performs all the major activities in the cell. The cell which possesses a nucleus is called a eukaryote. The cell which does not have a nucleus is called prokaryote.

A prokaryotic cell is a straightforward, one-celled (unicellular) organism that is devoid of a nucleus or any other organelle that is membrane-bound. The nucleoid, a dark area in the center of the cell, is where prokaryotic DNA is located.

Therefore, The cells which have a nucleus are called Eukaryotic cells. The cells which do not have a nucleus are called prokaryotic cells.

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The distance of the blue car from the edge of the intersection, when it stops, is 35.9 m, the time interval of the blue car within the boundaries of the intersection is 4.04 s, the minimum distance is 45.8 m, and the speed of the car is 22.6 m/s.

From the given,

A) the distance of the blue car from the south edge of the intersection when it stops =?

The width of the intersection = 28m

Acceleration = -2.10 m/s²

time interval = 3.10 s

By using the equation

x = x₀ + v₀t + 1/2 (at²)

28 = 0 + v₀(3.10) + 1/2 (-2.10 ×(3.10)²)

v₀ = 12.3 m/s

v² = v₀² + 2a (x-x₀)

(x-x₀) = Δx = v²-v₀² / 2a

  Δx  = 35. 9m

B) the time interval=?

distance covered by the blue car = 4.52 + 28 = 32.52 m

By using the relation,

x = x₀ + v₀t + 1/2 (at²)

32.52 = 0 + (12.3)t + 1/2 (-2.10)t²

-1.05t²+12.3t-32.52 = 0

This is the quadratic equation. By solving it, time t= 4.04s,7.66s. The desired time is t = 4.04 s, and the tail of the blue car leaves the intersection.

C) the minimum distance is=?

x = x₀ + v₀t + 1/2 (at²)

  = 0 + 0 + 1/2 (5.60 (4.04)²)

 = 45.8 m

The minimum distance of the blue car is 45.8m

D) speed of the car=?

the velocity equation

v = v₀ + at

= 0 + (5.60 ×4.04)

= 22.6 m/s

The velocity of the car is 22.6 m/s.

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Answer:29.1

Explanation:

acellus!!!!

Answer:

F = 2389.603 N

Explanation:

Given:

Mass m = 1,369.4 kg

Initial velocity u = 28.9 m/s

Final velocity v = 20 m/s

Time t = 5.1 s

Find:

Net force

Computation:

a = (v - u)/t

a = (20 - 28.9)/5.1

a = -1.745 m/s²

F = ma

F = (1369.4)(1.745)

F = 2389.603 N

The net electric force on particle 2 is -21.7 N.

The net force on particle q₂ is determined by applying Coulomb's law of electrostatic force.

F = kq₁q₂ / r²

where;

The force  between particle 2 and particle 1 is calculated as;

F = -( 9 x 10⁹ x 8 x 10⁻⁶ x 3.5 x 10⁻⁶ ) / (0.1)²

F = - 25.2 N

The force  between particle 2 and particle 3 is calculated as;

F = ( 9 x 10⁹ x 2.5 x 10⁻⁶ x 3.5 x 10⁻⁶ ) / (0.15)²

F = 3.5 N

The net force on particle 2 = 3.5 N - 25.2 N = -21.7 N

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The average speed of the baseball is  option  a. 40 m/s .

To calculate the average speed of the baseball, we use the formula:

Average Speed = Distance / Time

Given:

Distance = 18.4 m

Time = 0.46 s

Plugging in the values, we have:

Average Speed = 18.4 m / 0.46 s = 40 m/s

Therefore, the average speed of the baseball is 40 m/s.

Option a, 40 m/s, is the correct answer. This means that the baseball traveled an average distance of 40 meters per second from the pitcher's mound to home plate.

Average speed is a scalar quantity that represents the total distance traveled divided by the total time taken. It gives us an idea of how fast an object is moving on average over a given distance.

In this case, the baseball covered a distance of 18.4 meters in a time of 0.46 seconds. Dividing the distance by the time gives us the average speed of 40 m/s.

It's important to note that average speed is a measure of the overall rate of motion and does not provide information about the direction of motion. Therefore, negative values such as option b (-40 m/s) or extremely small values such as option c (0.03 m/s) are not appropriate in this context.

Option d (8.5 m/s) is also incorrect as it does not match the calculated average speed of 40 m/s.

Therefore, the correct answer is option a, 40 m/s, as it accurately represents the average speed of the baseball.

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Answer:

A sound mind in a sound body implies that you're capable of positive thinking for a better quality of life and physical functioning. When you exercise, your body releases endorphins, a chemical that triggers a positive response in the body. This shows that the more you sweat, the better you feel about yourself.

Explanation:

the right answer for this question would be dispositional

Answer:

dispositional

Explanation:

Answer:

Isaac Newton came up with the 3 Laws of Motion

Answer:

Isaac Newton came up with three laws of motion

The height and position of the image are both 2 cm. An upright, laterally inverted, identically sized, and distant behind the mirror as the item in front of it is generated by a plane mirror.

The image position is 14 cm and the image height is 2 cm.

The image size as the object, real and inverted.

Image distance:

The image distance is calculated using equations;

1/v=1/f-1/u

where;

f is the focal length

v is the image distance

u is the object distance

1/v= 1/20-1/14

1/v= -3/140

v=  140/-3

Magnification of the image,

m=v/u

m= 140/14x(-3)= 30

Thus, the image size as the object, real and inverted.

1. To determine the total number of pixels in the image, multiply its width and height in pixels. 2. To determine the image size in bytes, multiply the total number of pixels by 3.

Distance is the distance covered by an object travelling in any direction or even changing direction. Position refers to an object's location inside a frame of reference. Positions can be displayed using a number line for motion in a straight line.

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The possible temperature of the system after the iron has been added to the beaker is 52°C.

option B.

A system is said to be in thermal equilibrium when there is no temperature difference between system and surroundings. Temperature, as you know, measures how hot or cold a body is with respect to a standard object.

When a system ( cold and hot body) reaches thermal equilibrium or equilibrium temperature, the heat lost by the hot body will be equal to the heat gained by the cold body.

heat gained by the water = heat lost by the iron

The equilibrium temperature will be greater than the initial temperature of the cold body but less than the final temperature of the hot.

Thus, the only possible answer for the equilibrium temperature of mixture is 52⁰C.

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The work-energy theorem states that the change in the kinetic energy of an object will be equal to the net work done on the object.

Mathematically, it can be expressed as;

ΔKE = W

Where; ΔKE represents the change in kinetic energy of the object,

W represents the net work done on the object.

This theorem states that when work is done on an object, it results in a change in its kinetic energy. If work is done on an object, its kinetic energy increases, and if work is done by an object, its kinetic energy decreases.

This theorem is a fundamental principle in physics that relates the concepts of work and energy, and it is often used to analyze the motion and behavior of objects in various physical systems.

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Answer:

simply because they all have direction

Explanation:

vector quantities are quantities which have both magnitude and direction.Force,acceleration and velocity have both magnitude and direction.

The statement that is NOT true is "the spaces between the particles increased.

option D.

If we consider the solids and liquids, when the temperature increases the molecules gain energy and start moving in all directions. This expands the substance and the volume of the substance increases.

Similar, when the ball is heated, the volume of the ball increases due to thermal expansion.

As the temperature increases, the average kinetic energy of the particles within the ball also increases, causing them to move faster.

However, the spaces between the particles do not necessarily increase. In fact, the expansion of the ball occurs due to the particles themselves moving farther apart, but the intermolecular spacing within the ball remains relatively constant.

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The stationary spectator hears a frequency of approximately 175 Hz as the car approaches, and the stationary spectator hears a frequency of approximately 146 Hz as the car moves away.

Frequency refers to the number of cycles of a periodic waveform that occur in a unit of time, usually measured in Hertz (Hz). It is a fundamental concept in physics and is used to describe a wide range of phenomena, from sound waves to electromagnetic radiation.

a) The frequency heard by a stationary spectator as the car approaches can be calculated using the formula:

f' = f * (v + v_s) / (v + v_source)

where f is the frequency emitted by the source (engine), v is the speed of sound in air (approximately 343 m/s), v_s is the speed of the spectator (assumed to be zero), and v_source is the speed of the source (engine).

Substituting the given values, we get:

f' = 160 * (343 + 0) / (343 + 40) ≈ 175 Hz

Therefore, the stationary spectator hears a frequency of approximately 175 Hz as the car approaches.

b) The frequency heard by a stationary spectator as the car moves away can also be calculated using the same formula:

f' = f * (v - v_s) / (v - v_source)

where v_s is still zero, but v_source is now negative since the car is moving away from the spectator. Substituting the given values, we get:

f' = 160 * (343 - 0) / (343 - (-40)) ≈ 146 Hz

So, the stationary spectator hears a frequency of approximately 146 Hz as the car moves away.

Therefore, When the car is coming closer, the stationary observer hears a frequency of about 175 Hz, and when it is leaving, they hear a frequency of about 146 Hz.

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Answer:

20.96 m/s^2 (or 21)

Explanation:

Using the formula (final velocity - initial velocity)/time = acceleration, we can plug in values and manipulate the problem to give us the answer.

At first, we know a car is going 8 m/s, that is its initial velocity.

Then, we know the acceleration, which is 1.8 m/s/s

We also know the time, 7.2 second.

Plugging all of these values in shows us that we need to solve for final velocity. We can do so by manipulating the formula.

(final velocity - initial velocity) = time * acceleration

final velocity = time*acceleration + initial velocity

After plugging the found values in, we get 20.96 m/s/s, or 21 m/s

#A

Mass=4.4kg

acceleration=-1.74m/s^2

Use newtons second law

\(\\ \rm\longmapsto Force=ma\)

\(\\ \rm\longmapsto Force=4.4(-1.74)\)

\(\\ \rm\longmapsto Force=-7.656N\)

#B

initial velocity=u

Final velocity=v=0

Acceleration=a=-1.74m/s^2

Time=t=1.27s

\(\\ \rm\longmapsto a=\dfrac{v-u}{t}\)

\(\\ \rm\longmapsto u=v-at\)

\(\\ \rm\longmapsto u=0-(-1.74)(1.27)\)

\(\\ \rm\longmapsto u=1.74(1.27)\)

\(\\ \rm\longmapsto u=2.2m/s\)

Hi there!

Recall the equation for the magnetic field produced by a solenoid:

\(B = \mu_0 ni\)

B = Magnetic field (T)
n = number of turns per unit length (103 turns/m)

i = Current in solenoid (In this instance, changes with respect to time)

Using Faraday's Law:

\(\epsilon = -N\frac{d\Phi_B}{dt}\)

ε = Induced emf (V)
N = Number of loops in coil (15 turns)

\(\frac{d\Phi_B}{dt}\) = Change in magnetic flux with respect to time (Wb/s)

We know that magnetic flux is equal to:
\(\Phi_B = \oint B \cdot dA = B\cdot A\)

Since the cross-sectional area remains constant, we can take it out of the time-derivative. Since the current in the solenoid varies with time, we know that its magnetic field must also vary.

\(\frac{d\Phi_B}{dt} = A * \frac{dB}{dt}\)

Solving for dB/dt, since the solenoid's current is the only thing changing with respect to time:
\(\frac{dB}{dt} = \mu_0 n * \frac{di}{dt}\)

We must first differentiate I(t) using trig and chain derivative rules.

If:
\(f(x) = \alpha sin(\beta t)\\\\f'(x) = (\alpha * \beta) cos(\beta t)\)

Therefore:
\(\frac{di}{dt} = (5 * 120)cos(120t)\\\\\frac{di}{dt} = 600cos(120t)\)

So, dB/dt equals:

\(\frac{dB}{dt} = \mu_0 n\frac{di}{dt}\\\\\frac{dB}{dt} = (4\pi * 10^{-7})(103)(600cos(120t))\\\\\frac{dB}{dt} = 0.0777cos(120t)\)

Now, substituting this expression into the equation for Faraday's Law:
\(\epsilon = -N_{coil} * A * \frac{dB}{dt} \\\\\epsilon = -15 * \pi(0.02^2) * 0.0777cos(120t)\\\\\epsilon = \boxed{-0.001464cos(120t) \text { V}}\)

**For 'A', I used the cross-sectional area of the solenoid because there is no magnetic field produced by the solenoid in the exterior of its opening. Thus, the magnetic field remains confined to an area of A = π(0.02²) = 0.00126 m², which is the value used to calculate the magnetic flux rather than the cross-sectional area of the coil.

**Also, the (-) sign in front of the function of the induced emf simply shows how the induced E-field and consequentially emf opposes the change in the solenoid's current.

Forensic Entomology is the study of life cycles of insects that feed on the flesh of dead, to establish time of death and occasionally identify chemicals present in a person's body at time of death

The scientific study of the colonization of dead body by arthropods is called forensic entomology .

Larvae and adults feed on dry skin and hairs of corpse and arrive later in decomposition process : Carpet Beetles

Time since death : postmortem Interval.

Rove Beetles : Arrive a few hours after death and are active throughout decomposition process. They feed on larvae and other insects rather than the corpse itself.

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Answer:

f = 15/4 = 3.75

Explanation:

During the nuclear change we can expect to see different chemical symbols before and after the change

Chemical and nuclear reactions are quite different from one another. Atoms can share electrons with other atoms or participate in an electron transfer to increase their stability in chemical reactions. In nuclear reactions, the atom's nucleus stabilizes itself by going through some sort of alteration. Compared to the energies involved in chemical reactions, the energies produced in nuclear reactions are many orders of magnitude higher. Environmental factors like temperature or pressure do not significantly affect nuclear reactions like they do with chemical ones.

Nuclear reactions involve a change in an atom's nucleus, usually producing a different element. Chemical reactions, on the other hand, involve only a rearrangement of electrons and do not involve changes in the nuclei

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Answer:

a) 19536 joules of work are done.

b) The work is done by the engine on the structure of the cart.

c) There are three options:  (i) Keeping the engine and changing the travelled distance, (ii) Changing the engine and keeping the travelled distance, (iii) Changing the engine and the travelled distance.

d) 24442 joules of work are done.

e) We may change for a bigger engine if it allows a greater acceleration and higher peak speed.

f) The bigger engine uses more gas to go 22 meters.

g) An empty semi truck uses more gas than a car since the first has much more mass than a car and is designed for moves big loads and for being fast.

Explanation:

a) If force applied in the cart is uniform, that is, constant in magnitude and direction and is parallel to distance travelled by the car, the work done on the cart is defined by the following equation:

\(W = F\cdot \Delta s\) (1)

Where:

\(F\) - Force applied by the cart, measured in newtons.

\(\Delta s\) - Distance travelled by the car, measured in meters.

\(W\) - Work done on the cart, measured in joules.

If we know that \(F = 888\,N\) and \(\Delta s = 22\,m\), then the work done on the cart is:

\(W =(888\,N)\cdot (22\,m)\)

\(W = 19536\,J\)

19536 joules of work are done.

b) The work is done by the engine on the structure of the cart.

c) There are three options:  (i) Keeping the engine and changing the travelled distance, (ii) Changing the engine and keeping the travelled distance, (iii) Changing the engine and the travelled distance.

d) If we know that \(F = 1111\,N\) and \(\Delta s = 22\,m\) , then the work on the cart is:

\(W = (1111\,N)\cdot (22\,m)\)

\(W = 24442\,N\)

24442 joules of work are done.

e) We may change for a bigger engine if it allows a greater acceleration and higher peak speed.

f) The gas consumption is directly proportional to the square of velocity and mass of the cart and, hence, to the work done on the cart. In consequence, we conclude that the bigger engine uses more gas to go 22 meters.

g) An empty semi truck uses more gas than a car since the first has much more mass than a car and is designed for moves big loads and for being fast.

a. The amount of work done by the go cart engine is 19,536 Nm.

b. Work is being done by the go cart engine i.e the engine installed on the go cart.

c. The amount of work will increase if the driver wants to go further because work done is directly proportional to the distance covered. No, you don't need a bigger engine to go further.

d. The amount of work done when a bigger engine is used is 24,442 Nm.

e. The reason why a bigger engine is used is, so that the engine can easily do more work in the same amount of distance.

f. Since we know that work requires a change in energy, the bigger engine would use more gas to go 22 meters.

g. An empty semi truck uses much more gas than a car because it has more weight (mass) and as such requires more energy, in accordance with the law of inertia.

Given the following data:

a. To determine the amount of work done by the go cart engine:

Mathematically, the work done by an object is given by the formula;

\(Work\;done = Force \times distance\)

Substituting the given parameters into the formula, we have;

\(Work\;done = 888 \times 22\)

Work done = 19,536 Nm.

b. Work is being done by the go cart engine i.e the engine installed on the go cart.

c. The amount of work will increase if the driver wants to go further because work done is directly proportional to the distance covered. No, you don't need a bigger engine to go further.

d. To determine the amount of work done when a bigger engine is used:

\(Work\;done = Force \times distance\)

\(Work\;done = 1111 \times 22\)

Work done = 24,442 Nm.

e. The reason why a bigger engine is used is, so that the engine can easily do more work in the same amount of distance.

f. Since we know that work requires a change in energy, the bigger engine would use more gas to go 22 meters.

g. An empty semi truck uses much more gas than a car because it has more weight (mass) and as such requires more energy, in accordance with the law of inertia.

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