The integral ∫[0,1] x^(1/3) + x^(2/3) dx is convergent. The integral ∫[1,∞] x^(1/3) + x^(2/3) dx is also convergent. Therefore, the overall integral ∫[0,∞] x^(1/3) + x^(2/3) dx is convergent.
(i) To determine the convergence of ∫[0,1] x^(1/3) + x^(2/3) dx, we can use the Comparison Test. Notice that x^(1/3) + x^(2/3) > x^(1/3) for x > 0. Since the integral ∫[0,1] x^(1/3) dx is convergent (a p-series with p = 3/2), we can conclude that ∫[0,1] x^(1/3) + x^(2/3) dx is also convergent.
(ii) For the integral ∫[1,∞] x^(1/3) + x^(2/3) dx, we can again use the Comparison Test. Notice that x^(1/3) + x^(2/3) < 2x^(2/3) for x > 1. Since the integral ∫[1,∞] 2x^(2/3) dx is convergent (a p-series with p = 2/3), we can conclude that ∫[1,∞] x^(1/3) + x^(2/3) dx is also convergent.
(iii) Based on the results of (i) and (ii), since both ∫[0,1] x^(1/3) + x^(2/3) dx and ∫[1,∞] x^(1/3) + x^(2/3) dx are convergent, the overall integral ∫[0,∞] x^(1/3) + x^(2/3) dx is convergent.
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Most technicians install rebuilt or new power steering pumps rather than overhauling the defective unit in the shop. True or False?
Answer:
Most technicians install rebuilt or new power steering pumps rather than overhauling the defective unit in the shop.
True
Explanation:
It has been established that most technicians, instead of overhauling the defective power steering pumps, prefer to install rebuilt or revamped pumps or even new pumps when they could have overhauled the unit themselves. Some are afraid that leakage could occur again. They are not confident enough to do the overhauling in-house or some claim that they do not have the time and other tools to carry out the overhauling. Acknowledgedly, overhauling a power steering pump is not a job for the novice. They require experienced and skilled hands to do the hard work.
Gypsum products are manufactured with heat to rid of some water and become
Gypsum products are manufactured with heat to rid of some water and become more stable. Gypsum, a naturally occurring mineral, is used in a wide range of applications, from construction to agriculture. The process of manufacturing gypsum products involves heating the mineral at high temperatures to drive off some of its water content, resulting in a more stable product.
One common use of gypsum products is in drywall or plasterboard, which is made by combining gypsum with paper or other materials to create a flat, smooth surface that can be painted or wallpapered. Another use of gypsum is in cement, where it is added to improve the strength and durability of the finished product. The manufacturing process for gypsum products can vary depending on the intended use and desired properties of the final product. In general, however, the process involves crushing and grinding the raw gypsum material into a fine powder, which is then heated in a kiln or oven to remove some of the water content.
The resulting product, known as calcined gypsum or plaster of Paris, is then used to create a variety of different products, such as drywall, plaster, and cement. Overall, gypsum products are an important part of many industries and are widely used in construction, agriculture, and other applications. By removing some of the water content through the process of heating, these products become more stable and can be used in a wider range of applications.
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According to the tds relations, the specific entropy change of air when it is heated from t1 to t2 while executing an isobaric process is:_____.
During an isobaric process, the pressure of the system remains constant. The specific entropy change (Δs) of air can be calculated using the equation:
Δs = Cp * ln(t2/t1)
Where Cp is the specific heat at constant pressure. In this case, since the process is isobaric, Cp remains constant. Therefore, the specific entropy change is directly proportional to the natural logarithm of the ratio of the final temperature (t2) to the initial temperature (t1).
This means that regardless of the actual values of t1 and t2, the specific entropy change during an isobaric process will always be the same. The specific entropy change is solely determined by the ratio of the temperatures and does not depend on the actual values of the temperatures themselves.
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What kind of plan or development of road can be done to avoid traffic?
Answer: Breakdown Lanes
Reason: With breakdown lanes when a car needs to stop it can go to the backdown lane and fix its issue.
Explain the concept quality
Answer:
Hey there!
Explanation:
This is your answer....
The standard of something as measured against other things of a similar kind; the degree of excellence of something.
OR
Quality engineering is the discipline of engineering concerned with the principles and practice of product and service quality assurance and control. In software development, it is the management, development, operation and maintenance of IT systems and enterprise architectures with a high quality standard.
Hope it helps!
Brainliest pls!
Have a good day!^^
A successful bit-flipping attack requires:
A. knowledge of the exact contents of the plaintext
B. a stream cipher
C. knowledge of the exact contents of the ciphertext
D. a Caesar cipher
A successful bit-flipping attack requires knowledge of the exact contents of the ciphertext and a stream cipher.
A bit-flipping attack is a type of cryptographic attack where an attacker tries to change certain bits of the ciphertext to change the corresponding bits of the plaintext. To successfully perform this attack, the attacker needs to know the exact contents of the ciphertext, as they need to know which bits to flip.
Additionally, a stream cipher is required as it allows the attacker to modify specific bits of the ciphertext without affecting the rest of the message. A Caesar cipher, on the other hand, is a simple substitution cipher and not suitable for a bit-flipping attack. Therefore, options A and D are not correct. While knowledge of the exact contents of the plaintext would be helpful, it is not necessary for a successful bit-flipping attack. Hence, option C is also not correct.
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(5 points) Once the attacker gained access to the victim's machine, what executable did they first use to run commands on the host? Cite evidence from 'splunk-exec.csv'.[Example]: The attacker used 'zsh', which is a type of shell. We see this command executing at 05:26:93 PM from the host logs.
Once the attacker successfully gained access to the victim's machine, they utilized the executable 'zsh' as the first tool to run commands on the host system. This information is evident from the 'splunk-exec.csv' file, which contains log data from the host.
The logs show that the command was executed at 05:26:93 PM. 'Zsh' is a shell, which is a type of interface that allows users to interact with the underlying operating system and execute commands. This information provides insight into the tactics and tools utilized by the attacker, and can be used to improve the security of the system and prevent similar attacks in the future.
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procedure for replacing wheel cylinder seals
Before we go into the specifics of the brake job, you should be aware that wheel cylinders are always replaced in pairs, even if one is trouble-free.
What is wheel cylinder?A part of a hydraulic drum braking system is a wheel cylinder. It is a part of every wheel and is often found above the shoes at the top of the wheel.
Its purpose is to apply pressure to the shoes in order to bring them into contact with the drum and cause friction to stop the vehicle.
The Wheel Cylinder applies pressure to the brake shoes in a drum brake system, and the brake shoes' contact with the drum causes the vehicle to slow down and come to a stop.
At the drum brake, raise the car. In the owner's manual, find the drum brake section.Examine your brake seals. Find the brake seals in the owner's manual for your car. Verify whether they are worn out or damaged visually.Remove the brake wheel, step 3.Thus, this can be the procedure to change the wheel cylinder seal.
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Technician A says that rear-wheel drive vehicles usually get better traction than front-wheel drive vehicles. Technician B says that front-wheel drive vehicles get extremely good traction due to the weight of the engine and transaxle. Who is correct?
a
Technician A
b
Technician B
c
Both A & B
d
Neither A or B
Technician A and Technician B both are saying correctly about the rear wheel and front wheel. The correct option is c. Both A & B.
Who is a technician?A technician is a person who works for electronics and other appliances. Technicians repaired these items, and they have general knowledge about these appliances. He studies machines, and he also has knowledge of wheels and cars, as they also contain machines to work or run on roads and traffic.
According to Technician A, vehicles with rear-wheel drive often have more traction than those with front-wheel drive. According to Technician B, the weight of the engine and transaxle gives front-wheel drive vehicles very high traction. Both technicians saying correctly.
Therefore, the correct option is c, Both A & B.
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Five bolts are used in the connection between the axial member and the support. The ultimate shear strength of the bolts is 320 MPa, and a factor of safety of 4.2 is required with respect to fracture. Determine the minimum allowable bolt diameter required to support an applied load of P
Answer:
The minimum allowable bolt diameter required to support an applied load of P = 450 kN is 45.7 milimeters.
Explanation:
The complete statement of this question is "Five bolts are used in the connection between the axial member and the support. The ultimate shear strength of the bolts is 320 MPa, and a factor of safety of 4.2 is required with respect to fracture. Determine the minimum allowable bolt diameter required to support an applied load of P = 450 kN"
Each bolt is subjected to shear forces. In this case, safety factor is the ratio of the ultimate shear strength to maximum allowable shear stress. That is to say:
\(n = \frac{S_{uts}}{\tau_{max}}\)
Where:
\(n\) - Safety factor, dimensionless.
\(S_{uts}\) - Ultimate shear strength, measured in pascals.
\(\tau_{max}\) - Maximum allowable shear stress, measured in pascals.
The maximum allowable shear stress is consequently cleared and computed: (\(n = 4.2\), \(S_{uts} = 320\times 10^{6}\,Pa\))
\(\tau_{max} = \frac{S_{uts}}{n}\)
\(\tau_{max} = \frac{320\times 10^{6}\,Pa}{4.2}\)
\(\tau_{max} = 76.190\times 10^{6}\,Pa\)
Since each bolt has a circular cross section area and assuming the shear stress is not distributed uniformly, shear stress is calculated by:
\(\tau_{max} = \frac{4}{3} \cdot \frac{V}{A}\)
Where:
\(\tau_{max}\) - Maximum allowable shear stress, measured in pascals.
\(V\) - Shear force, measured in kilonewtons.
\(A\) - Cross section area, measured in square meters.
As connection consist on five bolts, shear force is equal to a fifth of the applied load. That is:
\(V = \frac{P}{5}\)
\(V = \frac{450\,kN}{5}\)
\(V = 90\,kN\)
The minimum allowable cross section area is cleared in the shearing stress equation:
\(A = \frac{4}{3}\cdot \frac{V}{\tau_{max}}\)
If \(V = 90\,kN\) and \(\tau_{max} = 76.190\times 10^{3}\,kPa\), the minimum allowable cross section area is:
\(A = \frac{4}{3} \cdot \frac{90\,kN}{76.190\times 10^{3}\,kPa}\)
\(A = 1.640\times 10^{-3}\,m^{2}\)
The minimum allowable cross section area can be determined in terms of minimum allowable bolt diameter by means of this expression:
\(A = \frac{\pi}{4}\cdot D^{2}\)
The diameter is now cleared and computed:
\(D = \sqrt{\frac{4}{\pi}\cdot A}\)
\(D =\sqrt{\frac{4}{\pi}\cdot (1.640\times 10^{-3}\,m^{2})\)
\(D = 0.0457\,m\)
\(D = 45.7\,mm\)
The minimum allowable bolt diameter required to support an applied load of P = 450 kN is 45.7 milimeters.
We have that the minimum allowable bolt diameter is mathematically given as
d = 26.65mmFrom the question we are told
Five bolts are used in the connection between the axial member and the support. The ultimate shear strength of the bolts is 320 MPa, and a factor of safety of 4.2 is required with respect to fracture. Determine the minimum allowable bolt diameter required to support an applied load of Assuming P to be P = 425 kN.DiameterGenerally the equation for the stress is mathematically given as
\(\mu= 320/4.2 \\\\\mu= 76.190 N/mm^2\)
Therefore
Force = Stress * area
Force = P/2
F= 425,000 N / 2 = 212,500 N
Hence area of each bolt is given as
212,500 = 76.190*( 5* area of each bolt)
area of each bolt = 557.815
Since
area of each bolt=\pi*d^2/4
\pi*d^2/4 = 557.815
d = 26.65mmFor more information on diameter visit
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humans can do more work with machines than without them.
a. true
b. false
The modifications of superheat and reheat for a vapor power plant are specifically better for the operation which of the following components. Pick one and briefly explain.
a.Condenser
b.Boiler
c.Open feedwater heater
d.Turbine
e.Electric generator
The modifications of superheating and reheat for a vapor power plant are specifically better for the operation which of the following components b.Boiler.
What are the primary additives in the vapour strength cycle?There are 5 steam strength cycles: The Carnot cycle, the easy Rankine cycle, the Rankine superheat cycle, the Rankine reheat cycle and the regenerative cycle.
Central to expertise the operation of steam propulsion is the primary steam cycle, a method wherein we generate steam in a boiler, increase the steam via a turbine to extract work, condense the steam into water, and sooner or later feed the water again to the boiler.Reheat now no longer best correctly decreased the penalty of the latent warmness of vaporization in steam discharged from the low-stress quit of the turbine cycle, however, it additionally advanced the first-rate of the steam on the low-stress quit of the mills via way of means of decreasing condensation and the formation of water droplets inside the turbine.Read more about the Boiler:
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onsider a venturi with a throat-to-inlet area ratio of 0.8, mounted on the side of an airplane fuselage. the airplane is in flight at standard sea level. if the static pressure at the throat is 2100 lb/ft2, calculate the velocity of the airplane.
What is the primer coating that protects the metal from rusting on a Aftermarket part.. Flat Primer
Primer Sealer
Shipping Primer
A large plane wall has a thickness L=50 cm and thermal conductivity k = 25 W/m. K. On the left surface (x = 0), it is subjected to a uniform heat flux q_0 while the surface temperature T_0 is constant. On the right surface, it experiences convection and radiation heat transfer while the surface temperature is T_6 =225 degree C and the surroanding temperature is 25 degree C. The emissivity and the convection heat transfer coefficient on the right surface are 0. 7 and 15 W/m^2. K, respectively, (a) Obtain the variation of temperature in the wall (T(x) in terms of Also determine the value of heat flux (q_n) and the temperature of the left surface of the wall (at x = 0)
The variation of temperature in the wall is T(x)= (q_0x) /(kL) + T_0. The heat flux q_n is -28.1 W/m^2 and the temperature of the left surface of the wall is T_0 = 300 degree C.
B. To obtain the variation of temperature in the wall, we need to use the heat conduction equation, which states that the rate of heat flow through a solid is proportional to the temperature gradient.
The equation is given by q_x = -kdT/dx. Since we know the heat flux q_0 at the left surface, we can integrate this equation from x = 0 to x = L to obtain the temperature distribution T(x) in terms of q_0 and the thermal conductivity k.
On the right surface, we can use the equation for heat transfer by convection and radiation, which is given by
q_n = h(T_6 - T_surrounding) + esigma(T_6^4 - T_surrounding^4)
where h is the convection heat transfer coefficient, e is the emissivity, sigma is the Stefan-Boltzmann constant, T_6 is the surface temperature and T_surrounding is the surrounding temperature.
Plugging in the given values we can find out the value of heat flux q_n and the temperature of the left surface of the wall (at x = 0).
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Which of the following are consequences of burning coal for energy? (mark all that apply) Check All That Apply A. increased levels of CO2 in the atmosphere B. increased heavy metals (lead and mercury) released into the air C. acidified rain D. increased radicals that deplete ozone in the stratosphere:
The following are consequences of burning coal for energy increased levels of CO2 in the atmosphere, increased heavy metals (lead and mercury) released into the air and Acidified rain. The correct options are a, b and c.
Burning coal produces a number of main emissions: Sulphur dioxide (SO2), which causes respiratory conditions and acid rain, Nitrogen oxides (NOx), which cause respiratory diseases and smog, Particulates that cause lung sickness, respiratory diseases, fog, and haze, The main greenhouse gas produced by burning fossil fuels (coal, oil, and natural gas) is carbon dioxide (CO2).
Mercury and other heavy metals have been associated with developmental and neurological harm in both humans and other animals. Power stations produce bottom ash and fly ash as byproducts of burning coal.
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what is the relationship of waste management and bioremediation?
Answer:
In the simplest terms, bioremediation is a waste management process using live organisms to neutralize or remove harmful pollutants from contaminated areas. Bioremediation is an environmental science that amplifies natural biological actions to remedy or remediate polluted groundwater and contaminated soil.
Explanation:
In the simplest terms, bioremediation is a waste management process using live organisms to neutralize or remove harmful pollutants from contaminated areas. Bioremediation is an environmental science that amplifies natural biological actions to remedy or remediate polluted groundwater and contaminated soil.
identifies potential new customers and preserves favorable business relationships with past customers
❎❎❎❎❎❎❎ sorry but that didn't help me that much
What is the meaning of beauty and completeness? In relation to these what are the attributes a Muslim should adopt?
ᴄᴏᴍᴘʟᴇᴛᴇɴᴇꜱꜱ ᴍᴇᴀɴꜱ ᴛʜᴇ ꜱᴛᴀᴛᴇ ᴏꜰ ʙᴇɪɴɢ ᴄᴏᴍᴘʟᴇᴛᴇ ᴀɴᴅ ᴇɴᴛɪʀᴇ; ʜᴀᴠɪɴɢ ᴇᴠᴇʀʏᴛʜɪɴɢ ᴛʜᴀᴛ ɪꜱ ɴᴇᴇᴅᴇᴅ.
ʙᴇᴀᴜᴛʏ ᴍᴇᴀɴꜱ combination of qualities, such as shape, colour, or form, that pleases the aesthetic senses, especially the sight.
to be considered a complete warm up cycle, the engine must reach a temperature of
To be considered a complete warm-up cycle, the engine must reach a temperature that is optimal for its efficient and safe operation.
The specific temperature required for a complete warm-up cycle may vary depending on the engine type, fuel used, and other factors. Generally, the engine should reach its normal operating temperature, which is typically around 195-220 degrees Fahrenheit (90-105 degrees Celsius) for most gasoline-powered vehicles. This temperature allows the engine to operate efficiently, burn fuel effectively, and minimize wear and tear on engine components. However, it's important to consult the manufacturer's guidelines or the vehicle's owner's manual for the recommended warm-up temperature specific to your engine model.
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air at 35 ∘c and 78 kpa enters a well‑insulated nozzle with a velocity of 2.00 m/s. the inlet area of the nozzle is 0.0400 m2. the nozzle contains an operating 500.0 w electrical resistance heater. air exits the nozzle at 110.00 kpa and 119.00 m/s. assume ideal gas behavior with a constant specific heat: ????p
The specific heat at constant pressure (Cp) of the air can be determined using the given information and the ideal gas law.
How can we calculate the specific heat at constant pressure (Cp) of the air?To calculate the specific heat at constant pressure (Cp), we can use the ideal gas law equation:
\[PV = nRT\]
Where:
P = Pressure (in Pa)
V = Volume (in m^3)
n = Number of moles of gas
R = Ideal gas constant (8.314 J/(mol·K))
T = Temperature (in Kelvin)
First, we need to convert the given temperatures to Kelvin. The initial temperature is 35 °C, so it becomes 35 + 273.15 = 308.15 K. The final temperature is not given, but since the process is adiabatic (well-insulated), we assume no heat transfer and therefore the final temperature is the same as the initial temperature.
Since the nozzle is well-insulated, we can assume that the process is adiabatic, which means no heat transfer occurs. Thus, the equation becomes:
\[P_1V_1^\gamma = P_2V_2^\gamma\]
Where γ is the ratio of specific heats (Cp/Cv) for the air.
Given the initial and final pressures (78 kPa and 110 kPa), we can use the equation to calculate γ. Rearranging the equation gives:
\[\gamma = \frac{{\log(\frac{{P_2}}{{P_1}})}}{{\log(\frac{{V_1}}{{V_2}})}}\]
We can determine the ratio of volumes (V1/V2) using the inlet and outlet velocities of the air. Since the nozzle is well-insulated, we can assume no mass flow rate change, and therefore the ratio of areas (A1/A2) is equal to the ratio of velocities (V1/V2). Thus:
\[\frac{{A_1}}{{A_2}} = \frac{{V_1}}{{V_2}}\]
Given the inlet area (0.0400 m^2) and the inlet velocity (2.00 m/s), we can calculate the outlet velocity (V2) and subsequently the ratio of volumes (V1/V2). Substituting these values into the equation for γ, we can determine its value.
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if a plcs input indicators are correct but expected outputs are not produced what is the first step to troubleshoot the problem
The first step to troubleshoot the problem is: If a PLC's input indicators are correct but expected outputs are not produced, the first step to troubleshoot the problem is to check the program or ladder logic to see if it is correct.
A programmable logic controller (PLC) is an industrial computer system that is designed to perform automation functions, particularly for controlling and managing manufacturing processes. The main function of a PLC is to monitor inputs and control outputs to perform a specified operation based on the programmed logic. PLCs are used to perform different functions, such as controlling various motors, pumps, valves, and sensors.The following are the steps to troubleshoot the problem if a PLC's input indicators are correct but expected outputs are not produced:Check the program or ladder logic to see if it is correctCheck the wiring between the output module and the device that the PLC is supposed to control.
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prescription eye protection suitable for an electrician should always include
Answer:
If prescription lenses are required, they must be covered by protective goggles or the lenses and frames must be ANSI approved.
Explanation:
this includes side shields for angular protection. Goggles and safety glasses are primary protectors. Goggles fit around the area of the face near the eye. hope this helps you :)
It is supposed that a machine, used for filling plastic bottles with a net volume of 16.0 oz, on average, does not perform according to specifications. An engineer will collect 15 measurements and will reset the machine if there is evidence that the mean fill volume is different from 16 oz. The resulting data from a random sample yield \overline{x}=16.0367x=16.0367 and s=0.0551. Should the engineer reset the machine with a level of significance 5%? Find also the pp-value.
Answer:
Explanation:
The null hypothesis is that the mean fill volume is 16 oz, and the alternative hypothesis is that the mean fill volume is different from 16 oz. The level of significance is 5%, and the sample size is 15. The test statistic is t=0.0367t=0.0367. The p-value is 0.9738.
Since the p-value is greater than the level of significance, we fail to reject the null hypothesis. Therefore, there is not enough evidence to conclude that the mean fill volume is different from 16 oz. The engineer should not reset the machine.
```
The test statistic is calculated as follows:
t = (x - μ) / s / sqrt(n)
= (16.0367 - 16) / 0.0551 / sqrt(15)
= 0.0367
The p-value is calculated using the t-distribution with 14 degrees of freedom.
p-value = 2 * t.cdf(-0.0367, 14)
= 0.9738
```
If A = 10 and B = 20, then A>b and A = B is (True or False). Group of answer choices True False
Answer:
........
....... False
2. If the voltage is doubled and the resistance is not changed, what will happen to
the current in a resistive circuit?
Answer:
Remember Ohms law (the holy grail of electronics): V=IR
Explanation:
V=IR, where:
V=Voltage
I=Current
R=Resistance.
Looking at the equation (V=IR),
if R remains constant, but V is double, that means that the current has to also double, in order to keep the equation true.
Answer: the Current will double if voltage is doubled and resistance is kept constant.
how to fill osprey hydraulics lt
To refill the reservoir:
Disengage the Slide-Seal™ mechanism and unfurl the PourShield™, allowing it to fulfill its purpose.Gently compress the PourShield™ with one hand, generating a broad aperture, while maintaining stability by grasping the carry handle with your other hand.Reinstate the Slide-Seal™ to its rightful position and invert the reservoir, diligently inspecting for any insidious leaks. Moreover, expel surplus air to curtail superfluous agitation within the reservoir.What are hydraulics?Hydraulics, a mechanical function that operates through liquid pressure. Within the realm of hydraulics-driven systems, the captivating dance of mechanical motion unfolds, intricately woven by the sheer might of encapsulated, propelled fluid.
It is this symphony of forces that breathes vitality into machinery, propelling the very essence of motion through the graceful interplay of hydraulic cylinders, orchestrating the eloquent journey of pistons.
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An ideal reheat Rankine cycle with water as the working fluid operates the boiler at 15,000 kPa, the reheater at 2000 kPa, and the condenser at 100 kPa. The temperature is 4508C at the entrance of the high-pressure and lowpressure turbines. The mass flow rate through the cycle is 1.74 kg/s. Determine the power used by pumps, the power produced by the cycle, the rate of heat transfer in the reheater, and the thermal efficiency of this system
Answer:
See the explanation below.
Explanation:
First find the enthalpies h₁, h₂, h₃, h₄, h₅, and h₆.
Find h₁:
Using Saturated Water Table and given pressure p₁ = 100 kPa
h₁ = 417.5 kJ/kg
Find h₂:
In order to find h₂, add the \(w_{p}\) to h₁, where \(w_{p}\) is the work done by pump and h₁ is the enthalpy computed above h₁ = 417.5 kJ/kg.
But first we need to compute \(w_{p}\) To computer
Pressures:
p₁ = 100 kPa
p₂ = 15,000 kPa
and
Using saturated water pressure table, the volume of water \(v_{f}\) = 1.0432
Dividing 1.0432/1000 gives us:
Volume of water = v₁ = 0.001043 m³/kg
Compute the value of h₂:
h₂ = h₁ + v₁ (p₂ - p₁)
= 417.5 kJ/kg + 0.001043 m³/kg ( 15,000 kPa - 100 kPa)
= 417.5 + 0.001043 (14900)
= 417.5 + 15.5407
= 433.04 kJ/kg
Find h₃
Using steam table:
At pressure p₃ = 15000 kPa
and Temperature = T₃ = 450°C
Then h₃ = 3159 kJ/kg
The entropy s₃ = 6.14 kJ/ kg K
Find h₄
Since entropy s₃ is equal to s₄ So
s₄ = 6.14 kJ/kgK
To compute h₄
s₄ = \(s_{f}\) + \(x_{4} s_{fg}\)
\(x_{4} = s_{4} -s_{f} /s_{fg}\)
\(x_{4}\) = 6.14 - 2.45 / 3.89
\(x_{4}\) = 0.9497
The enthalpy h₄:
h₄ = \(h_{f} +x_{4} h_{fg}\)
= 908.4 + 0.9497(1889.8)
= 908.4 + 1794.7430
= 2703 kJ/kg
This can simply be computed using the software for steam tables online. Just use the entropy s₃ = 6.14 kJ/ kg K and pressure p₄ = 2000 kPa
Find h₅
Using steam table:
At pressure p₅ = 2000 kPa
and Temperature = T₅ = 450°C
Then h₅ = 3358 kJ/kg
Find h₆:
Since the entropy s₅ = 7.286 kJ/kgK is equal s₆ to So
s₆ = 7.286 kJ/kgK = 7.29 kJ/kgK
To compute h₆
s₆ = \(s_{f}\) + \(x_{6} s_{fg}\)
\(x_{6} = s_{6} -s_{f} /s_{fg}\)
\(x_{6}\) = 7.29 - 1.3028 / 6.0562
\(x_{6}\) = 0.988
The enthalpy h₆:
h₆ = \(h_{f} +x_{6} h_{fg}\)
= 417.51 + 0.988 (2257.5)
= 417.51 + 2230.41
h₆ = 2648 kJ/kg
This can simply be computed using the software for steam tables online. Just use the entropy s₅ = 7.286 kJ/kgK and pressure p₅ = 2000 kPa
Compute power used by pump:
\(P_{p}\) is found by using:
mass flow rate = m = 1.74 kg/s
Volume of water = v₁ = 0.001043 m³/kg
p₁ = 100 kPa
p₂ = 15,000 kPa
\(P_{p}\) = ( m ) ( v₁ ) ( p₂ - p₁ )
= (1.74 kg/s) (0.001043 m³/kg) (15,000 kPa - 100 kPa)
= (1.74 kg/s) (0.001043 m³/kg) (14900)
= 27.04
\(P_{p}\) = 27 kW
Compute heat added \(q_{a}\) and heat rejected \(q_{r}\) from boiler using computed enthalpies:
\(q_{a}\) = ( h₃ - h₂ ) + ( h₅ - h₄ )
= ( 3159 kJ/kg - 433.04 kJ/kg ) + ( 3358 kJ/kg - 2703 kJ/kg )
= 2726 + 655
= 3381 kJ/kg
\(q_{r}\) = h₆ - h₁
= 2648 kJ/kg - 417.5 kJ/kg
= 2232 kJ/kg
Compute net work
W\(_{net}\) = \(q_{a}\) - \(q_{r}\)
= 3381 kJ/kg - 2232 kJ/kg
= 1150 kJ/kg
Compute power produced by the cycle
mass flow rate = m = 1.74 kg/s
W\(_{net}\) = 1150 kJ/kg
P = m * W\(_{net}\)
= 1.74 kg/s * 1150 kJ/kg
= 2001 kW
Compute rate of heat transfer in the reheater
Q = m * ( h₅ - h₄ )
= 1.74 kg/s * 655
= 1140 kW
Compute Thermal efficiency of this system
μ\(_{t}\) = 1 - \(q_{r}\) / \(q_{a}\)
= 1 - 2232 kJ/kg / 3381 kJ/kg
= 1 - 0.6601
= 0.34
= 34%
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R1 = 7926 Ω, R2 = 327 Ω, and R3 = 5802 Ω, and 600 V is applied between A and B. What is the current flow through R3?
You add up the individual resistances to determine the total overall resistance of several resistors connected in this manner.The formula used for this is as follows:Total R = R1 plus R2 plus R3 and so on
Solve the problem ?According to symmetry a and b are at same potential. So current in R3 is zero.The following equation can be used to calculate the TOTAL RESISTANCE in a parallel circuit: 1/Rt = 1/R1 + 1/R2 + 1/R3 "Remember what we stated at the beginning of this section before we begin the calculations: "A parallel circuit's total resistance is not equal to the sum of its resistors (like in a series circuit). The current through R2 is V2/R2 because R2 appears to be grounded (to source V2), and the current through R3 is V3/R3 because R3 appears to be grounded.The voltage drop in RF, and consequently the output voltage, are equal to (Iin + V2/R2 V3/R3)RF, much like for current sources.Diagram 30-11. The electric potential difference (V) across each resistor in a parallel circuit is the same.Ohm's law states that I = V / R applies to the current in a resistor.The current will be lowest where the resistance is highest since the V is the same for each resistor.To learn more about resistances refer
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