Usage of DC motor and ac motor and galvanometer​

Answers

Answer 1

Answer:

Usage of DC Motor, AC Motor, and Galvanometer

DC Motor:

A DC motor is a type of electric motor that operates on direct current (DC) power. It converts electrical energy into mechanical energy, which can be used to power various machines and devices. Here are some common uses of DC motors:

1. Electric Vehicles: DC motors are commonly used in electric vehicles, such as cars, buses, and trains. They are used to power the wheels and provide motion.

2. Robotics: DC motors are commonly used in robotics, where they are used for movement and manipulation of objects.

3. Industrial Machinery: DC motors are used in various types of industrial machinery, such as conveyor belts, pumps, and cranes.

4. Household Appliances: DC motors are used in many household appliances, such as vacuum cleaners, electric shavers, and blenders.

AC Motor:

An AC motor is a type of electric motor that operates on alternating current (AC) power. It also converts electrical energy into mechanical energy, and it is commonly used in various applications. Here are some common uses of AC motors:

1. Air Conditioning: AC motors are commonly used in air conditioning units, where they are used to power fans and compressors.

2. Industrial Machinery: AC motors are used in various types of industrial machinery, such as pumps, compressors, and blowers.

3. Household Appliances: AC motors are used in many household appliances, such as refrigerators, washing machines, and dishwashers.

Galvanometer:

A galvanometer is a device that is used to detect and measure small electrical currents. It works by using a coil of wire that is suspended in a magnetic field. When an electrical current flows through the coil, it causes the coil to move, and the movement is measured using a scale or pointer. Here are some common uses of galvanometers:

1. Electrical Testing: Galvanometers are commonly used in electrical testing and measurement, such as measuring the current in a circuit.

2. Medical Equipment: Galvanometers are used in medical equipment, such as electrocardiograms (ECGs), where they are used to measure the electrical activity of the heart.

3. Industrial Applications: Galvanometers are used in various industrial applications, such as in welding machines, where they are used to control the current flow.

In conclusion, DC motors, AC motors, and galvanometers are all important devices that are used in various applications. DC motors are commonly used in electric vehicles, robotics, industrial machinery, and household appliances. AC motors are commonly used in air conditioning, industrial machinery, and household appliances. Galvanometers are used in electrical testing, medical equipment, and industrial applications. Understanding the different uses of these devices is essential for designing and building various types of machines and devices.

Explanation:

Answer 2

Answer:

conversation of alternating current into direct current


Related Questions

is power a vector quantity​

Answers

Answer:

Power is a scalar quantity and has a unit,a magnitude(a numerical value) but no direction.

Explanation:

What are the Economic importance of rusting of iron

Answers

Answer:

Rusting is the corrosion of iron which is the most widely used structural metal.

A Motorcycle Jump. You are planning to make a jump with your motorcycle by driving over a ramp that will launch you at an angle of 30.0° with respect to the horizontal. The front edge of the ramp on which you are supposed to land, however, is 25.0 ft lower than the edge of the launch ramp (i.e., your launch height).
(a) Assuming a launch speed of 55.0 mph, at what horizontal distance from your launch point should the landing ramp be placed?
(b) In order to land smoothly, the angle of the landing ramp should match the direction of your velocity vector when you touch down. What should be the angle of the landing ramp?

Answers

a. the landing ramp should be placed at 276.298 ft horizontally from the launch point.

(b) the angle of the landing ramp is 30°.

How do we calculate?

(a)

Launch speed = 55.0 mph * (1.467 ft/s)

= 80.685 ft/s

Horizontal distance = Launch speed * Time of flight

Vertical velocity = Launch speed * sin(30.0°)

Time to reach maximum height = Vertical velocity / g

Vertical distance = (1/2) *g * t²

and Time = √(2 * Vertical distance / g)

Total time of flight = 2 * Time to reach maximum height + Time for descent

Horizontal distance = Launch speed * Total time of flight

The Vertical velocity = 80.685 ft/s * sin(30.0°)

= 40.3425 ft/s

Time to reach maximum height = 40.3425 ft/s / 32.2 ft/s²

Time to reach maximum height  = 1.253 s

Time of descent = √(2 * 25.0 ft / 32.2 ft/s²)

Time of descent  = 0.913 s

Total time of flight = 2 * 1.253 s + 0.913 s

Total time of flight = 3.419 s

In conclusion, the horizontal distance = 80.685 ft/s * 3.419 s

horizontal distance = 276.298 ft

b.

the angle of the landing ramp is  30.0 be the same as the launch angle.

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Please help! I'm really desperate.

Could anyone at least give some sketch ideas or advice?

I'm not sure how to set it out..

Please help! I'm really desperate.Could anyone at least give some sketch ideas or advice?I'm not sure

Answers

Answer:

make a pineapple schematic

Explanation:

lesson 14: bisect it cool down: going both ways again explain the difference between these 2 statements: given figure where segment is congruent to segment , prove that: 1. if ray is the angle bisector of angle , and is the midpoint of segment , then ray passes through . 2. if is the midpoint of segment , and ray bisects angle .

Answers

Make a section of a line AB = 5 cm. 2. Draw two arcs, one above and one below AB, with a radius of any bigger than 2.5 cm and with the compass set at A bisects.

A straight line drawn from a triangle's vertex to its opposite side that divides an angle into two equal or congruent angles is called an angle bisector. Triangle Angle Bisector Theorems The internal and exterior angle bisector theorems and their contrapositions are shown in the table below.

A line is divided into two equal halves by a bisector. Therefore, when we refer to the perpendicular bisector of a line segment AB, we mean that it bisects or divides AB into two equal halves.

A line is an angle bisector.

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a ball rolling down a hill was displaced 21.9 m while using uniformly accelerating from rest, If the final velocity was 7.14 m/s, what was the rate of acceleration?

Answers

Answer:

a = 1.16 m/s²

Explanation:

In order to find the rate of acceleration of the ball, we will use third equation of motion, as follows:

2as = Vf² - Vi²

where,

a = rate of acceleration = ?

s = distance covered by the ball = 21.9 m

Vf = Final Velocity of the ball = 7.14 m/s

Vi = Initial Velocity of the ball = 0 m/s (Since, the ball started from rest)

Therefore,

2(a)(21.9 m) = (7.14 m/s)² - (0 m/s)²

a = (50.97 m²/s²)/(43.8 m)

a = 1.16 m/s²

P Flag question
Matt, shown below, is able to move
the large truck because

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Can we please get the picture

Anyone can help me out with this question ? Just number 2,

Anyone can help me out with this question ? Just number 2,

Answers

Answer:

- 21⁰C .

Explanation:

Speed of jet = 2.05 x 10³ km /h

= 2050 x 1000 / (60 x 60 ) m /s

= 569.44 m / s

Mach no represents times of speed of sound , the speed of jet

1.79 x speed of sound = 569.44

speed of sound = 318.12 m /s

speed of sound at 20⁰C = 343 m /s

Difference = 343 - 318.12 = 24.88⁰C

We know that 1 ⁰C change in temperature changes speed of sound

by .61 m /s

So a change in speed of 24.88 will be produced by a change in temperature of

24.88 / .61

= 41⁰C  

temperature = 20 - 41 = - 21⁰C .  

What acceleration did you measure from the video? Does this match the acceleration you calculated in the first step?

Answers

Explanation:

dont know so sorryyyyyyyyy

PLS HELP!!!!!

Which process allows organisms that reproduce asexually to produce offspring that are NOT genetically identical to themselves?

A
mutations

B
fertilization

C
pollination

D
budding

Answers

Process allows organisms that reproduce asexually to produce offspring that are not genetically identical to themselves is mutations.

A variation in a DNA sequence at particular gene refers to mutation. In asexual reproduction generally there reproduce identical offspring's. in  an asexually reproduce offspring, once  a bad mutation occurs . it will passed on to all offspring at that line. mutation occurs when cell division take place and replicate . the cell division are of two types: mitosis and meiosis. asexual reproduction generally reproduce identical offspring because only single parent is involve.

Thus, Process allows organisms that reproduce asexually to produce offspring that are not genetically identical to themselves is mutations.

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what type of energy transfer occurs when: warm ocean water carries heat from the equator toward the poles


A- Radiation

B- Convection

C- Conduction

Answers

Answer:

radiation

Explanation:

Now that you've done your research on the law of supply, you understand that it basically asserts that how much coffee you'd be willing to supply depends on how much money you can make for each cup.

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i need more info
on this

What is an independent variable?

Answers

The independent variable is the variable that changes or controls
a variable whose variation does not depend on that of another.

PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons

Answers

The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

Why the electron number cannot be used instead?

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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1.) A roller coaster travels on a frictionless track as shown in the illustration.
a.) If the speed of the car at Pt A is 5.0 m/s, what is the speed at Pt B

(More in the photo provided)

1.) A roller coaster travels on a frictionless track as shown in the illustration. a.) If the speed of

Answers

For the roller coaster on a frictionless track:

a. The speed at Point A is 5.0 m/s, the speed at Point B will also be 5.0 m/s.b. The height between Points A and B where kinetic energy equals potential energy is 5.0 m.c. For the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m.d. For the car to reach Point C, the height at Point A must be greater than or equal to 8.0 m.

How to solve speed and height?

a. The speed of the car at Point B can be determined using the principle of conservation of energy. The total mechanical energy (sum of kinetic energy and potential energy) remains constant in the absence of external forces like friction. Therefore, if there is no energy loss, the kinetic energy at Point A is equal to the kinetic energy at Point B.

Given that the speed at Point A is 5.0 m/s, the speed at Point B will also be 5.0 m/s.

Answer: A. 5.0 m/s

b. To find the height at which kinetic energy equals potential energy, we can set the equations for kinetic energy and potential energy equal to each other.

At Point A, the roller coaster has both kinetic energy and potential energy. The total mechanical energy is the sum of these two:

Initial mechanical energy at Point A = Kinetic energy at Point A + Potential energy at Point A

At Point B, the roller coaster will have kinetic energy and potential energy, but we want to find the height at which kinetic energy equals potential energy. Let's call this height "h."

Mechanical energy at Point B = Kinetic energy at Point B + Potential energy at Point B

Since the speed at Point B is the same as the speed at Point A (5.0 m/s), the kinetic energy at both points is the same.

Equating the mechanical energy at Point A to the mechanical energy at Point B:

Initial mechanical energy at Point A = Mechanical energy at Point B

Kinetic energy at Point A + Potential energy at Point A = Kinetic energy at Point B + Potential energy at Point B

Since the kinetic energy is the same at both points, simplify the equation:

Potential energy at Point A = Potential energy at Point B

The potential energy at any point is given by the formula mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.

Therefore, at the height h between Points A and B, the potential energy equals the potential energy at Point A:

mgh = mghA

Since the mass and acceleration due to gravity are the same, cancel them out:

h = hA

This means that the height where kinetic energy equals potential energy is the same as the height at Point A.

Answer: The height between Points A and B where kinetic energy equals potential energy is 5.0 m.

c. To determine if the car will reach Point C, compare the potential energy at Point B with the potential energy at Point C. If the potential energy at Point B is greater than or equal to the potential energy at Point C, the car will reach Point C.

Potential energy at Point B = mghB

Potential energy at Point C = mghC

Given that the height at Point C is 8.0 m, compare the potential energies:

Potential energy at Point B ≥ Potential energy at Point C

mghB ≥ mghC

Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:

hB ≥ hC

Therefore, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m.

d. The minimum speed needed at Point A for the car to reach Point C can be determined by comparing the potential energy at Point A with the potential energy at Point C. If the potential energy at Point A is greater than or equal to the potential energy at Point C, the car will have enough energy to reach Point C.

Potential energy at Point A = mghA

Potential energy at Point C = mghC

Given that the height at Point A is 5.0 m, compare the potential energies:

Potential energy at Point A ≥ Potential energy at Point C

mghA ≥ mghC

Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:

hA ≥ hC

Therefore, for the car to reach Point C, the height at Point A must be greater than or equal to 8.0 m.

To summarize, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m, and the height at Point A must also be greater than or equal to 8.0 m.

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24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.

Answers

The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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1. Two small, identical conducting spheres A and B are a distance R apart; each carries the same charge Q. What is the force sphere B is exerting on sphere A? (2 marks) b. An identical sphere with zero charge, sphere C, makes contact with sphere A and is then moved very far away. What is the net force now acting on sphere A? (3 marks) c. Sphere C next makes contact with sphere A and is then moved far away. What is the force on sphere A in this third case? (2 marks) ​

Answers

Answer:

the same question I want to know

a. Spheres A and B carry the same charge \(\rm \( Q \)\), the force can be written as:

\(\rm \[ F = \frac{k Q^2}{R^2} \]\), b. The net force on sphere A now is the force due to sphere B, which is: \(\rm \[ F = \frac{k \frac{Q}{2} \cdot Q}{R^2} = \frac{k Q^2}{2R^2} \]\), c. The magnitude of the force on sphere A in this third case is \(\rm \( \frac{3}{8} \)\) of the original force.

a) The magnitude of the force (F) sphere B exerts on sphere A can be calculated using Coulomb's law:

\(\rm \[ F = \frac{k Q_1 Q_2}{R^2} \]\)

where:

k is Coulomb's constant \(\rm \( k = \frac{1}{4\pi\epsilon_0} \)\) where \(\rm \( \epsilon_0 \)\) is the vacuum permittivity constant),

\(\rm \( Q_1 \)\) and \(\rm \( Q_2 \)\) are the charges on spheres A and B respectively, and

\(\rm \( R \)\) is the distance between the two spheres.

Since both spheres A and B carry the same charge \(\rm \( Q \)\), the force can be written as:

\(\rm \[ F = \frac{k Q^2}{R^2} \]\)

b) When an identical sphere C makes contact with sphere B, they share the charge equally. Sphere B now carries \(\rm \( \frac{Q}{2} \)\) charge, and sphere C carries \(\rm \( \frac{Q}{2} \)\) charge.

When sphere C is moved far away, it exerts no force on sphere A. So, the net force on sphere A now is the force due to sphere B, which is:

\(\rm \[ F = \frac{k \frac{Q}{2} \cdot Q}{R^2} = \frac{k Q^2}{2R^2} \]\)

c) When sphere C makes contact with sphere A, they both share the charge equally. Each sphere now carries \(\rm \( \frac{Q}{2} \)\) charge.

When sphere C is moved far away, the net force on sphere A now is the force due to the charge on sphere A itself, which is:

\(\rm \[ F = \frac{k \frac{Q}{2} \cdot \frac{Q}{2}}{R^2} \\\\\rm = \frac{3}{8} \frac{k Q^2}{R^2} \]\)

So, the magnitude of the force on sphere A in this third case is \(\rm \( \frac{3}{8} \)\) of the original force.

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what is capasistanceb​

Answers

\(\sf\huge\underline\pink{Answer:-}\)

Capacitance is the ratio of the change in the electric charge of a system, to the corresponding change in its electric potential.

\(\rightarrow\)The capacitance of any capacitor can be either fixed or variable depending on their usage.

\(\rightarrow\)Capacitance is expressed as the ratio of the electric charge on each conductor to the potential difference (i.e., voltage) between them.

\(\rightarrow\)The capacitance value of a capacitor is measured in farads (F), units named for English physicist Michael Faraday (1791–1867).

\(\sf\large\underline\blue{Formula:-}\)

➢ \(\sf\green{q = CV}\)

Where,

\(\rightarrow\sf{q = charge}\)

\(\rightarrow\sf{C = capacitance}\)

\(\rightarrow\sf{V = voltage}\)

_______________________________

How do motion and Newton's laws apply to your everyday life? (all of the laws)​

Answers

Answer:

This may help

Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

Explanation:

describe fluid friction and static friction in your own words

Answers

Answer:

friction

Explanation: The resistance that one surface or object encounters when moving over another.

What force acts on a projectile in the horizontal direction?

Answers

The force that acts on a projectile in the horizontal direction is Gravitational force.


A projectile is an object upon which the only force is gravity. Gravity acts to influence the vertical motion of the projectile, thus causing a vertical acceleration. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity.

Due to the absence of horizontal forces, a projectile remains in motion with a constant horizontal velocity. Horizontal forces are not required to keep a projectile moving horizontally. Hence, The only force acting upon a projectile is gravity.


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Calculate the absolute pressure at an ocean depth of 1.0 x 10³ m. Assume that the density of the water is 1.025 x 10³ kg/m³ and that Po = 1.01 x 10^5 Pa.

Answers

The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.

What is hydrostatic pressure?

Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.

The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:

P = ρgh + Po

where:

P is the absolute pressure at the given depth

ρ is the density of the water

g is the acceleration due to gravity (assumed to be 9.81 m/s²)

h is the depth of the ocean

Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)

Substituting the given values, we get:

P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa

P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa

P = 1.002 x 10^8 Pa.

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To understand the basic principles underlying interference.
One of the most important properties of waves is the principle of superposition. The principle of superposition for waves states that when two waves occupy the same point, their effect on the medium adds algebraically. So, if two waves would individually have the effect "+1" on a specific point in the medium, then when they are both at that point the effect on the medium is "+2." If a third wave with effect "-2" happens also to be at that point, then the total effect on the medium is zero. This idea of waves adding their effects, or canceling each other's effects, is the source of interference.
Part C
In talking about interference, particularly with light, you will most likely speak in terms of phase differences, as well as wavelength differences. In the mathematical description of a sine wave, the phase corresponds to the argument of the sine function. For example, in the function y=Asin(kx), the value of kx at a particular point is the phase of the wave at that point. Recall that in radians a full cycle (or a full circle) corresponds to 2? radians. How many radians would the shift of half a wavelength from the previous part correspond to?
Express your answer in terms of ?.

Answers

Shift of half a wavelength from the previous part correspond to π radian.

What is the principle of interference?

Interference is a phenomenon in which two waves combine by adding  displacement together at every single point in the space and time, to form a resultant wave of greater, lower, or same amplitude.

The superposition principle explains that when two or more waves overlap in space, then the resultant disturbance is equal to the algebraic sum of  individual disturbances

Given, Wavelength= λ

We have to find the phase difference when  wavelength is half of the initial wavelength.

So, the path difference= Δx = λ/2

As, phase difference= 2π/λ * Δx

So, phase difference= 2π/λ * λ/2

Thus, phase difference= π radian

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state archimedes principle​

Answers

Answer:

Kindly check explanation

Explanation:

Archimedes principle is a very important concept in fluid mechanics which is credited to the Greek mathematician called Archimedes. The law simply states that; When an object is fully or partially immersed in a fluid , the immersed body experiences an upthrust(Weight loss) which is equal to the weight of fluid displaced by the immersed object.

In essence, the upthrust or volume of Displacement experienced by the object will be equal to the volume of the the object which is immersed in the fluid. Such that the force of buoyancy matches the weight of object immersed in the fluid.

One of the most common illustrations of Archimedes is in the navigation of ships whose upthrust increases as the weight of the ship increases such that the upthrust force balances the weight of the ship in water.

Answer:

Archimedes principle states that"When a body is totally or partially immersed in a liquid,it experience an upthrust which is equal to the weight of the liquid displaced"

Suppose the woman in the figure is 54kg , and the board she is standing on has a 10kg mass. What is the reading on each of the scales?

Suppose the woman in the figure is 54kg , and the board she is standing on has a 10kg mass. What is the

Answers

The reading on each of the scales on the right is 421.4 N.

The reading on each of the scales on the left is 156.8 N.

What is the reading on each scale?

The reading on each scale is determined from the distribution of the weight of the woman.

The weight of the board is distributed uniformly and each scale with have equal reading of the weight of the board.

weight of the board = 10 kg x 9.8 m/s² = 98 N

Reading of each due to weight of the board is calculated as;

W₁ = ¹/₂ (98 N) = 24.5 N

The distribution of the weight of the woman on the right scale is calculated as;

W (R) = ( 1.5 m / 2 m) x ( 54 x 9.8 )

W (R) =  396.9 N

The distribution of the weight of the woman on the left scale is calculated as;

W (L) = ( 0.5 m / 2 m) x ( 54 x 9.8 )

W (L) =  132.3 N

Total reading on the scale on the right = 396.9 N + 24.5 N = 421.4 N

Total reading on the scale on the left = 132.3 N + 24.5 N = 156.8 N

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An ultraviolet wave traveling through a vacuum has wavelength of 4.0 x 10^-7 m. The waves frequency, written in scientific notation to two significant figures, is ? X10^14Hz.

Answers

Answer:

λ = c / f     or    f = c / λ

f = 3.0E8 / 4.0E-7 = .75E15 / sec = 7.5E14 / sec = 7.5 X 10^14 /sec

How big is Earth’s gravitational field

Answers

9.8 m/s² (this is what i found lol)

Answer:

Earth's gravity goes back as how old it is, so 4.5 billion light years.

Explanation:

The velocity time graph of an object mass 50 g is shown in figure study graph and answer
1)calculate force acting on object in time interval 0-3 seconds
2)calculate the force acting on the object in the time interval 6-10 seconds 
3)Is there any time interval in which no force acts on object.Justify

The velocity time graph of an object mass 50 g is shown in figure study graph and answer1)calculate force

Answers

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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2) If the current in any circuit reach to infinity then its resistance becomes

Answers

Given that,

Current = ∞

We know that,

Ohm's law :

Ohm's law is defined as,

The voltage of the circuit is directly proportional to the current of the circuit.

\(V\propto I\)

Or,

The voltage of the circuit is equal to the product of current and resistance.

In mathematically,

\(V=IR\)

Where, V = voltage

I = current

R = resistance

According to ohm's law,

The current in the circuit is

\(I=\dfrac{V}{R}\)

If the current is very less then the resistance will be infinity.

If the is reach to infinity then the resistance will be very low.

Hence, The resistance becomes very low.

Penguins in Gold Harbour love to communicate with other members of their penguin family. Here in Sanford, the speed of sound in air is about 344.0 m/s. Calculate the speed of sound (in m/s) in Gold Harbour, on a day when the air temperature is -2.7 °C.

Round to the nearest hundredth.
Please show all work!!!!

Penguins in Gold Harbour love to communicate with other members of their penguin family. Here in Sanford,

Answers

The speed of sound in Gold Harbour, on a day when the air temperature is -2.7 °C, is 331.5 + 0.6 * (-2.7) = 328.65 m/s.

What is Gold Harbour?

Gold Harbour is a small settlement located on Antarctic's King George Island. It is home to a Chilean research base, which is operated by the Chilean Antarctic Institute. It also acts as a summer base for the Chilean Navy, and provides support for the scientific research conducted by other countries, including the United States, United Kingdom, and Russia. The area is known for its stunning natural beauty, with mountains, glaciers, and icebergs all in close proximity. It is also an important habitat for several species of wildlife, including penguins, seals, and sea birds.

The speed of sound in air is affected by temperature, and the formula for calculating the speed of sound in air is v = 331.5 + 0.6 * (air temperature in °C).
Therefore, the speed of sound in Gold Harbour, on a day when the air temperature is -2.7 °C, is 331.5 + 0.6 * (-2.7)
= 328.65 m/s.

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