URGENTTT PLEASE HELPPPP. You put m1 = 1 kg of ice cooled to -20°C into mass m2 = 1 kg of water at 2°C. Both are in a thermally insulated chamber. For water L = 3.33 x 105 J/kg. The specific heat of ice is 2090 J/(kg°C) and of water 4186 J/(kg°C). How much does the ice heat up in order to bring the water down to 0°C?
A. 0.04°C
B. 0.4°C
C. 4°C
D. 10°C
E. 20°C
Answers
Answer:
Explanation:
heat lost by water will be used to increase the temperature of ice
heat gained by ice
= mass x specific heat x rise in temperature
1 x 2090 x t
heat lost by water in cooling to 0° C
= mcΔt where m is mass of water , s is specific heat of water and Δt is fall in temperature .
= 1 x 2 x 4186
8372
heat lost = heat gained
1 x 2090 x t = 8372
t = 4°C
There will be a rise of 4 degree in the temperature of ice.
The increase in the temperature of the ice to bring the water to 0 °C is 4 ⁰C.
The given parameters;
mass of the ice, m₁ = 1 kgtemperature of the ice, t₁ = -20°Cmass of the water, m₂ = 1 kgtemperature of the water, t₂ = 2 °CApply the principle of conservation of energy to determine the increase in the temperature of the ice to bring the water to 0 °C.
Heat absorbed by the ice = Heat lost by water
\(Q_{ice} = Q_{w}\\\\mc\Delta t_{ice} = mc \Delta t_{w}\\\\1 \times 2090 \times \Delta t = 1 \times 4186 \times (2-0)\\\\2090\Delta t = 8372\\\\\Delta t = \frac{8372}{2090} \\\\\Delta t = 4 \ ^0C\)
Thus, the increase in the temperature of the ice to bring the water to 0 °C is 4 ⁰C.
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Related Questions
. A man rows a boat in still water at 6.0km/h, he wishes to
row due north across a river 3.0km wide which is flowing
due east at 2.0km/h. calculate
a. The direction in which he must head the boat
b. The time taken to reach the other bank
Answers
The direction in which he must head the boat is 30° West of North. The time taken to reach the other bank is 0.86 hours.
Velocity of boat with respect to water, \(V_{BW}\) = 6 km / h
Velocity of river, \(V_{W}\) = 2 km / h E
If the boat has to reach the exact opposite side of the river from the starting point, the boat should go upstream.
Velocity of boat in upstream, \(V_{B}\) = \(V_{BW}\) - \(V_{W}\)
\(V_{B}\) = 6 - 2
\(V_{B}\) = 4 km / h
θ = \(sin^{-1}\) ( \(V_{W}\) / \(V_{B}\) )
θ = \(sin^{-1}\) ( 2 / 4 )
θ = \(sin^{-1}\) ( 0.5 )
θ = 30° W of N
cos θ = Adjacent side / Hypotenuse
cos 30° = 3 km / Distance covered by the boat
Distance covered by the boat = 3 / 0.87
Distance covered by the boat = 3.45 km
t = d / v
t = 3.45 / 4
t = 0.86 hr
Therefore,
The direction in which he must head the boat is 30° West of NorthThe time taken to reach the other bank is 0.86 hours.To know more about speed of boat in a river
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Using Newton's second law of motion, calculate the force necessary to accelerate a race car with a mass of 1100 kg to an acceleration of 25 m/s2.
Answers
In order to find the neccessary force, we can use Newton's second law
F = ma
The mass is 1100 Kg and the acceleration required is 25 m/s^2
plugging the numbers in
F = 1100(25) = 27500 Newtons
According to the principal of superposition,
Answers
Answer:
the resultant wave is the algebraic sum of all the waves reaching that particular point at a given time.
Explanation:
imagine two or three waves reaching a particular particle x at the same time. The particle will vibrate those waves and give out or transmit a resultant wave which is the algebraic sum of the incoming two waves. If both the waves have the same amplitude and phase, the resultant wave will be amplified. However if the waves have the same amplitude and equal but opposite phase then the resultant wave will be a straight line
A ball rolls from x = -9.8 m to x = 11.0 m in 5.0 seconds what was its average velocity
Answers
Explanation:
avg velocity = total displacement / total time taken = (11 - (-9.8)) / 5.0 = 4.16m/s to the right when taken right to be positive
1)What is the pressure at point D in kPa ?
2)Temperature at point D
3)What is the net work done on the gas as it is taken through four cycles?
4)What is the internal energy of the gas when it is at point A?
5)What is the total change in internal energy of this gas during four complete cycles?
Answers
The answer is 1) The pressure at point D is 80 kPa. 2) The temperature at point D is 800 K. 3) The net work done on the gas over four cycles is zero. 4) The internal energy of the gas at point A is 100 J. 5) The total change in internal energy during four complete cycles is zero.
The total change in internal energy of this gas during four complete cycles is zero. The given diagram represents the Carnot cycle involving four stages. The four stages of the Carnot cycle are reversible and follow an ideal gas that is placed in a cylinder with a movable piston.Let's solve each question asked one by one.1) From the graph, it can be observed that the pressure at point D is 0.08 M Pa, which is equal to 80 kPa. Hence, the pressure at point D in kPa is 80 kPa.2) Temperature at point D The isotherm at point D is about 800 K. Hence, the temperature at point D is 800 K.3) The net work done on the gas as it is taken through four cycles is zero because the Carnot cycle is a cycle that has four stages. In each cycle, the net work done is the area enclosed by the cycle. Therefore, for a complete cycle, the net work done is zero because the area enclosed is a loop.4) The internal energy of the gas when it is at point A is 100 J because the internal energy of the gas is directly proportional to the temperature and volume. Here, at point A, the temperature is 500 K, and the volume is 2 m³, so the internal energy of the gas when it is at point A is 100 J.5) The Carnot cycle is a reversible cycle that is used to determine the efficiency of heat engines. It is a closed cycle that does not involve any net energy exchange with the surroundings. Therefore, the total change in internal energy of this gas during four complete cycles is zero since the initial and final states are the same. Hence, the total change in internal energy of this gas during four complete cycles is zero.For more questions on the Carnot cycle, click on:
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A simple pendulum is constructed by attaching a 1.0 kg mass to a length L of fishing line. At the equilibrium point the pendulum bob has a kinetic energy of 2.0 joules and an angular velocity about the pivot point of 0.66 radians/sec. What is the period of the pendulum?
Answers
The period of the pendulum, given that the pendulum has an angular velocity about the pivot point of 0.66 radians/sec is 9.52 seconds
How do i determine the period of the pendulum?First, we shall list out the given parameters from the question. This is shown below:
Mass (m) = 1.0 KgKinetic energy (KE) = 2.0 joules Angular velocity (ω) = 0.66 radians/secPeriod of pendulum (T) =?The period and angular velocity are related according to the following formula:
ω = 2π/ T
Inputting the given parameters, we can obtain the period of the pendulum as follow:
0.66 = (2 × 3.14) / T
0.66 = 6.28 / T
Cross multiply
0.66 × T = 6.28
Divide both sides by 0.66
T = 6.28 / 0.66
T = 9.52 seconds
Thus, we can conclude that the period of the pendulum is 9.52 seconds
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An organ pipe of length L has one end closed but the other end open. What is the wavelength of the fundamental node emitted?
a. Slightly smaller than 4 L
b. Slightly larger than 4 L c. Roughly equal to 3/2
d. Slightly larger than 2 L
Answers
Answer:analize a afirmacao a seguir e tudo que envolve o gerenciamento da marca e que ultrapassa as acoes com objetivos economicos e refere se a cultura principios e valores
Explanation:
Rihanna can go from 0-60 miles per hour in 3.5 seconds. Calculate the acceleration.
Please show ALL work and CIRCLE your answer.
Answers
Answer:
7.66 m/s²
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 0 mph
Final velocity (v) = 60 mph
Time (t) = 3.5 s
Acceleration (a) =.?
Next, we shall convert mile per hour (mph) to metre per second (m/s). This can be obtained as follow:
Recall:
1 mph = 0.447 m/s
Initial velocity (u) = 0 mph
Initial velocity (u) = 0 × 0.447 = 0 m/s
Final velocity (v) = 60 mph
Final velocity (v) = 60 × 0.447 = 26.82 m/s.
Finally, we shall determine the acceleration of Rihanna as follow:
Initial velocity (u) = 0 m/s
Final velocity (v) = 26.82 m/s.
Time (t) = 3.5 s
Acceleration (a) =.?
a = (v – u) /t
a = (26.82 – 0) / 3.5
a = 26.82 / 3.5
a = 7.66 m/s²
Thus, the acceleration of Rihanna is 7.66 m/s²
An insect lands 0.1m from the centre of a turn table while the record is turning at 55 rev/min at what linear speed will the insect be carried
collision with the near stationary photograph
Answers
The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.
What is speed?
Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Given that an insect lands 0.1m from the center of the turn table.
Rotational speed of the turn table = 55 rev/min
= (55×2π/60) rad/second
= 5.759 rad/second.
Hence, the speed of the insect be = Rotational speed × length
= 5.759 rad/second × 0.1 M.
= 0.5759 meter/second.
Therefore, the speed of the insect be 0.5759 meter/second.
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If a student were to measure the ball's speed at each position above, at which position would
the ball be traveling the fastest?
A
B
C
D
Answers
Hope I helped :)
Compute the gravitational attraction force between the sun and the earth(the mass of the sun is 2×10³⁰kg, that of the earth is 6×10²⁴kg and their separation is d=1.5×10¹¹m.
Answers
Answer:
35.57 x 10²¹ N
Explanation:
m(s) = 2 x 10³⁰ kg
m(e) = 6 x 10²⁴ kg
d = 1.5 x 10¹¹
G = 6.67 x 10⁻¹¹
F = Gm1m2/d²
= 6.67 x 10⁻¹¹ x 2 x 10³⁰ x 6 x 10²⁴ / 2.25 x 10²²
= 80.04 x 10⁴³ / 2.25 x 10²²
= 35.57 x 10²¹ N
At the top of a flight of stairs, a woman is 16m above the ground and has 9094J of potential energy. What is the mass of the woman?
Answers
Answer:
Mass = 56.83 Kg
Explanation:
\(PE = mgh\\9094 J = 16m*10 m/s^2*mass\\mass = \frac{PE}{g*h} \\mass = \frac{9094 J}{16*10} = 56.83 kg\)
find the velocity vof the block as a function of time.express your answer in terms of some or all of the variables: k, m, a, and t.
Answers
The expression "velocity as a function of time" refers to the change in an object's velocity over time, which can be observed by graphing the velocity against time on a graph.
Speed and time are related in the first equation of motion. V = u + at represents the first motion equation. Here, u denotes the starting velocity, a the acceleration, and t the duration, whereas v denotes the end velocity. The derivative of x with respect to time, or v(t)=ddtx, represents the instantaneous velocity of an object. It is the limit of average velocity as the time approaches zero (t). V (t) equals d d t x (t). Instantaneous velocity has a dimension of length per time, just like average velocity does.
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My experience as a learner
learner in a science class.
My experience
as a learner in a
technology class,
Answers
So I'm guessing that the question is describing your experiences in both these classes? Nobody else knows how you experienced these classes because it was your experience, not mine or anyone else's. You'll have to explain how you felt about the class, and whether it was difficult or not, etc.
I’ve been struggling with this question, help!
Answers
The masses of the two objects MA and MB in the binary system are 4 Mo respectively.
How can the masses of the binary systems be calculated?The masses of binary systems can be calculated using Kepler's laws of planetary motion and observations of the system.
Let's denote the masses of the two objects as MA and MB, where MA is the mass of object A and MB is the mass of object B. We know that the total mass of the binary system is 8 Mo, so:
MA + MB = 8 Mo
We also know that the ratio of the distances between the two objects is 1/3. Let's denote the distance between the two objects as d, so we have:
d(A to B) / d(Binary System) = 1/3
We can simplify this equation by using the fact that the distances between the objects and the binary system add up to the total distance between the objects:
d(A to B) + d(B to binary system) = d(Binary system)
Since we know the ratio of the distances, we can substitute 1/3d for d(B to binary system):
d(A to B) + 1/3d = d(Binary system)
3d(A to B) + d = 3d(Binary system)
Substituting d(A to B) for d(Binary system) - d(B to binary system), we get:
3d(A to B) + d = 3(d(A to B) + d(B to binary system))
2d(A to B) = 2d(B to binary system)
d(A to B) / d(B to binary system) = 1
So the two objects are at the same distance from the binary system center of mass. This means that the masses of the two objects are equal:
MA = MB
Substituting this into the first equation, we get:
2MA = 8 Mo
MA = MB = 4 Mo
Therefore, the mass of each object is 4 Mo.
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Ajani is trying to experimentally measure Planck's constant h. He does this by shining different wavelengths of monochro- matic (i.e., single-wavelength) EM radiation on a metal plate with unknown work function W, and then measuring the stop- ping voltage required to bring the ejected electrons to a halt. When he uses λ1= 400 nm, he finds that a stopping voltage of V1 = 0.7 V is required. When he uses λ2 = 500 nm, he finds that a stopping voltage of V2= 0.2 V is required. Based on these two data points, what is Ajani's measurement of Planck's constant?
Answers
Answer:
h = 1.01 x 10⁻³⁴ J.s
Explanation:
The energy applied by the voltage must be equal to the energy associated with the wavelength of light:
\(eV = \frac{hc}{\lambda}\\\)
where,
e = charge on electron = 1.6 x 10⁻¹⁹ C
V = stopping potential
h = Planck's Constant = ?
c = speed of light = 3 x 10⁸ m/s
λ = wavelength of light
For λ = 400 nm = 4 x 10⁻⁷ m, V = 0.7 V:
\((1.6\ x\ 10^{-19}\ C)(0.7\ V) = \frac{h(3\ x\ 10^8\ m/s)}{4\ x\ 10^{-7}\ m}\\\)
h = 1.49 x 10⁻³⁴ J.s
For λ = 500 nm = 5 x 10⁻⁷ m, V = 0.2 V:
\((1.6\ x\ 10^{-19}\ C)(0.2\ V) = \frac{h(3\ x\ 10^8\ m/s)}{5\ x\ 10^{-7}\ m}\\\)
h = 0.53 x 10⁻³⁴ J.s
Taking average of both values:
\(h = \frac{(0.53+1.49)\ x\ 10^{-19}\ J.s}{2}\)
h = 1.01 x 10⁻³⁴ J.s
if a 0.08kg cell phone falls of a table at 15 m/s then what is its kinetic energy right before it hits the ground?
Answers
The Kinetic energy of the cell phone of mass 0.08 kg is 9 J.
What is kinetic energy?Kinetic energy is the energy of a body in motion.
To calculate the kinetic energy of the cell phone, we use the formula below.
Formula:
K.E = mv²/2............. Equation 1Where:
K.E = Kinetic energy of the cell phonem = Mass of the cell phonev = Velocity of the cell phoneFrom the question,
Given:
m = 0.08 kgv = 15 m/sSubstitute these values into equation 1
K.E = 0.08×15²/2K.E = 9 JHence, the Kinetic energy of the cell phone is 9 J.
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A block with mass 0.50 kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.20 m . When released, the block moves on a horizontal tabletop for 1.00 m before coming to rest. The spring constant k is 100 N/m. What is the coefficient of kinetic friction between the block and the tabletop
Answers
Answer:
μ = 0.41
Explanation:
\(\frac{1}{2} kx^2 = \mu mgd\)
\(\mu = (\frac{1}{2} kx^2)/mgd\)
\(\mu = (\frac{1}{2} (100)(0.2)^2)/(0.5)(9.81)(1)\)
\(\mu = 0.41\)
The coefficient of kinetic friction between the block and the tabletop is 0.41.
The given parameters;
mass of the block, m = 0.5 kgextension of the spring, x = 0.2 mspring constant, K = 100 N/mThe coefficient of kinetic friction between the block and the tabletop by applying the principle of conservation of energy as shown below.
Fd = Uₓ
μmgd = ¹/₂kx²
where;
μ is the coefficient of kinetic frictionThe coefficient of kinetic friction between the block and the tabletop;
\(\mu_k = \frac{kx^2}{mgd} \\\\\mu_k = \frac{100\times 0.2^2}{2\times 0.5\times9.8 \times 1 } \\\\\mu_k = 0.41\)
Thus, the coefficient of kinetic friction between the block and the tabletop is 0.41.
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Does a communications or weather satellite that is orbiting Earth follow Kepler's laws? Kepler's Laws of Motion These laws are true for any orbit: a planet orbiting a star, a moon orbiting a planet, or an artificial satellite orbiting the Earth.
Answers
Yes, a communication or weather satellite that is orbiting Earth follows Kepler's laws. Kepler's laws describe the motion of objects in orbit around a central body, such as a planet or a star.
These laws are based on the principles of gravity and the conservation of energy, and they describe the elliptical shape of an object's orbit, the relationship between the size of the orbit and the time it takes to complete one revolution, and the relationship between an object's distance from the central body and its orbital velocity.
Since a communication or weather satellite orbiting the Earth is subject to the laws of gravity, it follows Kepler's laws, just like any other object in orbit around a central body. This means that its orbit is elliptical, its orbital velocity changes based on its distance from the Earth, and it follows the other principles described by Kepler's laws.
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which situation best represents a closed environment?
two balls colliding on a pool table
two balls colliding in midair
two balls colliding in deep space
two balls colliding under water
Answers
Answer:
deep space ✔️✔️✔️✔️✔️✔️✔️✔️✔️✔️✔️✔️✔️✔️✔️✔️✔️✔️✔️✔️✔️
Please help me with just question 1
Find the magnitude and direction of the resultant of the five concurrent forces
acting on a bolt.
Answers
The magnitude and direction of the resultant of the five concurrent forces acting on a bolt is 390.58 N and -82.8 ⁰ respectively.
What is the magnitude and direction of the five forces?The magnitude and direction of the resultant of the five concurrent forces acting on a bolt is calculated as follows;
The sum of the x component of the five forces is calculated as;
F₁ₓ = -80 N x cos (27) = -71.28 N
F₂ₓ = -400 N x cos (22) = - 370.87 N
F₃ₓ = -150 N x cos (22 + 46) = -56.2 N
F₄ₓ = 300 N x cos (45) = 212.13 N
F₅ₓ = 250 N x cos (18) = 237.76 N
∑Fₓ = -48.98 N
The sum of the y component of the five forces is calculated as;
F₁y = -80 N x sin (27) = -36.32 N
F₂y = 400 N x sin (22) = 149.84 N
F₃y = 150 N x sin (22 + 46) = 139.1 N
F₄y = 300 N x sin (45) = 212.13 N
F₅y = -250 N x sin (18) = -77.25 N
∑Fy = 387.5 N
The magnitude of the resultant force;
F = √ (387.5² + 48.98²)
F = 390.58 N
The direction of the force;
θ = tan⁻¹ ( Fy / Fₓ )
θ = tan⁻¹ ( 387.5 / -48.98 )
θ = -82.8 ⁰
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45:56
Which of these is an example of acceleration?
a bicyclist turning around a corner
a car traveling south with its cruise control set
a bus traveling north at 25m/s
a helicopter waiting to take off
Answers
Answer:
A car traveling south with its cruise control set
Explanation:
Turning could cause anything to slow down but going forward could mean that anything could go faster.
A hockey puck slides across the ice and eventually comes to a stop. Why did the puck stop?
Answers
Answer: the total energy of the puck, ice surface, and surrounding air decreases to zero
Explanation:
A hockey puck slides across the ice and eventually comes to a stop because of friction between surface of the puck and ice surface.
What is Friction ?Friction is a resistance to motion of the object. for example, when a body slides on horizontal surface in positive x direction, it has friction in negative x direction and that measure of friction is a frictional force. frictional force is directly proportional to the Normal(N). i.e. \(F_{fri}\) ∝ N
\(F_{fri}\) = μN where μ is called as coefficient of the friction. It is a dimensionless quantity.
When a body is kept on horizontal surface, its normal will be straight upward which is reaction of mg. i.e. N=mg.
Frictional force is equal to
\(F_{fri}\) = μmg
When hockey puck slides across the ice, friction between surface of puck and surface of ice produces resistance to the motion of the puck, due to resistance puck slow down slowly and eventually come to a stop. Motion and frictional force are opposite to each other. we can calculated the exact value of frictional force when we know the coefficient of friction between puck and ice surface.
hence due to friction, puck come to a stop
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A cat is looking into a concave mirror that is 12.0cm from her nose. I see her focused real image 16.8cm from the mirror. Determine the focal length and radius of curvature of the mirror.
Answers
1/di + 1 /do = 1/ f
di = 16.8 cm
d0= 12 cm
1/ 16.8 + 1 /12 = 1/f
f = 7 cm
focal lenght = 7 cm
r = 2f = 2* 7 = 14 cm
Answers:
Focal lenght= 7cm
Radius = 14 cm
How did earth change about 2.5 billion years ago when many organisms began using photosynthesis to make food
A. The amount of oxygen in the atmosphere increased
B. Mass extinctions occurred
C. The oceans became larger
D. Rainfall increased
Answers
2. A ball is thrown 45 m into the air. It takes the ball 5 s to hit the ground. What is the
velocity of the ball when it hits the ground?
Answers
Answer:
9m/s
Explanation:
45m÷5s=9m/s
Hope it helps!!!
What is the spring constant for a spring that stretches by 27 cm when a load of 200 N is suspended from it?1) 0.135 N/m2) 54 N/m3) 740 N/m4) 7.4 N/m
Answers
Given data:
Force;
\(F=200\text{ N}\)Stretching;
\(\begin{gathered} x=27\text{ cm} \\ =0.27\text{ m} \end{gathered}\)The force is given as,
\(F=kx\)Here, k is the force constant.
The expression for the force constant is given as,
\(k=\frac{F}{x}\)Substituting all known values,
\(\begin{gathered} k=\frac{200\text{ N}}{0.27\text{ m}} \\ =740.74\text{ N/m} \end{gathered}\)Therefore, the force constant of the spring is 740.74 N/m. Hence, option (3); 740 N/m is the best choice.
MISSION REQUIREMENTS:
1. Design your Gigafood
Name your Gigafood and your food company (school appropriate)
Consider the components of your Gigafood
Sources of all of the essential nutrients
Macro: Carbohydrates, fats, proteins
Micro: Vitamins and minerals (don’t have to
include ALL of the different vitamins and
minerals)
Must contain at least 2 sources of antioxidants
2. Provide rationale (an explanation) for your Gigafood design
What is the purpose of each macro and micro nutrient?
What nutrient does each component provide?
How much of your Gigafood should someone eat?
(consider daily values)
3. Design your advertisement. You want to convince the world
that your Gigafood is the only food they will ever need.
Come up with a catchy slogan
Disclaimer to eating your Gigafood:
What are the health benefits?
Are there any risks?
What diseases or conditions will it help with?
Why should people consume your Gigafood?
4. A visual representation of your Gigafood and the advertisement
All of the components of your Gigafood should be visible
and labeled
Your advertisement should be visually appealing and
easily noticeable (see examples below)
TIPS FOR SUCCESS:
● Imagine that you are NOT limited by money or materials. You are
building your DREAM Gigafood!
● No ridiculous claims; your Gigafood cannot be the cure for cancer, or
make someone live forever.
● OPTIONAL: You MAY consider dietary restrictions, but if you consider
all the possibilities (ex. celiac, dairy free, vegetarian) you may have a
tough time constructing a food.
● Your Gigafood will likely contain 3-6 components (depending on your
choices) to include all of the necessary nutrients
Answers
I believe that Gigafood is the future of food. It is a healthy, convenient, and sustainable way to get all the nutrients our bodies need. I am excited to see how Gigafood can change the way people eat.
How to explain the foodName: Gigafood
Company: Gigafood, Inc.
Components:
Whole wheat flourOatmealSoybeansEggsBerriesNutsNutrients:Macronutrients:Carbohydrates: 45%Fat: 25%Protein: 30%Micronutrients:Vitamins: A, B12, C, D, EMinerals: Calcium, Iron, Magnesium, Potassium, ZincAntioxidants: Berries and nutsGigafood is a complete and balanced meal that provides all the essential nutrients the body needs.
Macronutrients: Carbohydrates are the body's main source of energy. Fats provide essential fatty acids and help the body absorb vitamins. Protein is necessary for building and repairing tissues.
Micronutrients: Vitamins and minerals are essential for many bodily functions, including growth, development, and immunity.
Antioxidants: Berries and nuts are rich in antioxidants, which help protect the body against damage from free radicals.
Slogan: Gigafood: The only food you'll ever need.
Disclaimer: Gigafood is a healthy and nutritious food, but it is not a cure for any disease. It is important to eat a balanced diet and get regular exercise.
Health benefits:
Improved energy levelsWeight loss or maintenanceReduced risk of chronic diseases such as heart disease, stroke, and cancerImproved immunityIncreased lifespanDiseases or conditions that Gigafood can help with:
Heart diseaseStrokeCancerDiabetesObesityAlzheimer's diseaseGigafood is a convenient and delicious way to get all the nutrients your body needs.
Gigafood is a healthy and sustainable choice for the environment.
Gigafood is a great way to save time and money on food.
The advertisement should be visually appealing and easily noticeable. It should use bright colors and simple graphics to capture attention. The advertisement should also include the Gigafood logo and slogan.
I believe that Gigafood is the future of food. It is a healthy, convenient, and sustainable way to get all the nutrients our bodies need. I am excited to see how Gigafood can change the way people eat.
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leafy greens are considered the healthiest vegetable because of their ___ nutrients profile
Answers
Dense because food do be dense tho
In a grassland ecosystem, grass is the producer. The grass is eaten by rabbits. The rabbits are eaten by foxes. And the foxes
koal
are eaten by hawks. If the grass produces 83,721 of energy, how much energy will the apex predator receive? (1 point)
m²yr
O 83.721
O 837.21 kcal
m²yr
kcal
m²yr
O 8,372.1 kcal
m³yr
8.3721
keal
m³yr
Answers
Based on the given food chain, the energy flows from the producer (grass) to the primary consumer (rabbits), to the secondary consumer (foxes), and finally to the tertiary consumer (hawks), which is the apex predator.
Each level of the food chain typically follows the 10% rule, where only about 10% of the energy from the previous level is transferred to the next level. Therefore, to calculate the energy received by the apex predator, we need to multiply the energy produced by the grass by the product of the energy transfer efficiency across all levels in the food chain:
83,721 x 0.1 x 0.1 x 0.1 = 837.21 kcal/m²/yr
Therefore, the apex predator (hawks) will receive approximately 837.21 kcal/m²/yr of energy.