URGENT!!!
what does a reaction between iron(II) sulfate, potassium iodide, and starch look like?

The equilibrium constant for the given reaction is 1.2e4 (option c).

The equilibrium constant (K) is a value that represents the ratio of product concentrations to reactant concentrations at equilibrium. In this case, the equilibrium constant is determined by the expression [NO]^2 * [Cl2] / [ONCl]^2, where [NO], [Cl2], and [ONCl] represent the concentrations of the respective species.

Given that 5.3% of the ONCl has split into NO and Cl2 at equilibrium, we can assume that the concentration of ONCl at equilibrium is reduced by 5.3% (or 0.053) and the concentrations of NO and Cl2 are increased by the same amount. Therefore, at equilibrium, the concentrations of NO and Cl2 are 0.053 and the concentration of ONCl is (1 - 0.053).

Plugging these values into the equilibrium constant expression, we get (0.053)^2 * (0.053) / (1 - 0.053)^2, which simplifies to approximately 1.2e4.

Hence, the equilibrium constant for the given reaction is 1.2e4 (option c).

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This chemical is known as lead (II) nitrate. It is an ionic assembly (salt compound) comprised of lead cations in the +2 oxidation state. With regard to the naming convention, each lead (II) cation is paired with two nitrate anions, each having a charge of -1.

Chemical nomenclature is a set of principles for naming chemical substances in a systematic manner. The International Union of Pure and Applied Chemistry designed and developed the most widely used nomenclature in the world (IUPAC).

The basic goal of chemical nomenclature is to guarantee that no ambiguity exists between a spoken or written chemical name and the chemical compound to which the name refers. Each chemical name should only relate to one substance.

It is required to indicate the charge of these cations or compounds containing these cations when identifying them. Ionic compounds are formed when cations and anions interact. The cation of an ionic compound is named first, followed by the anion. When writing their chemical formulae, they use the same format.

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It will take approximately 170.84 hours to produce 185.0 L of H2 at 1.0 atm and 273 K using an electrolytic cell with a current of 185.0 mA.

To determine the time required to produce 185.0 L of H2 at 1.0 atm and 273 K using an electrolytic cell with a current of 185.0 mA, we need to use Faraday's law of electrolysis and the ideal gas law.

The balanced equation for the electrolysis of water is:

2H2O(l) -> 2H2(g) + O2(g)

From the equation, we can see that 2 moles of H2 are produced for every mole of O2.

First, we need to calculate the number of moles of H2 required to obtain 185.0 L at 1.0 atm and 273 K using the ideal gas law:

PV = nRT

n = PV / RT

= (1.0 atm) * (185.0 L) / (0.0821 L·atm/(mol·K)) * (273 K)

= 14.15 mol

Since the reaction produces 2 moles of H2 for every mole of O2, we need 7.08 moles of H2.

Next, we can use Faraday's law of electrolysis to calculate the time required. The relationship between the amount of substance produced (n) and the current (I) is given by:

n = (I * t) / (nF)

where:

I = current (in amperes)

t = time (in seconds)

n = moles of substance

F = Faraday's constant (96485 C/mol)

Plugging in the values, we have:

7.08 mol = (0.185 A * t) / (2 * 96485 C/mol)

Solving for t, we find:

t = (7.08 mol * 2 * 96485 C/mol) / (0.185 A)

= 615032 s

Converting the time to hours:

t_hours = 615032 s / 3600 s/h

≈ 170.84 hours

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Answer:

Carbon Dioxide

If H₂O is water, CO₂ is CARBON DIOXIDE.

Option (4) is correct. The rate constant of a second order reaction has the unit  L/mole. sec.

In the Second order reaction the rate is proportional to the square of the concentration of one reactant. Rate of Second order reaction  is proportional to the product of the concentrations of two reactants. Such reactions generally have the form,

A + B → products.

Each monomer combines to form a larger molecule is called dimer. For the units of the reaction rate to be moles per liter per second (M/s), the units of a second-order rate constant must be the inverse (M−1·s−1). Because the units of molarity are expressed as mole/L, the unit of the rate constant can also be written as L(mole ·s).

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Explanation:

Electronic Configuration of First 30 Elements with Atomic Numbers

Atomic Number Name of the Element Electronic Configuration

18 Argon (Ar) [Ne] 3s2 3p6

19 Potassium (K) [Ar] 4s1

20 Calcium (Ca) [Ar] 4s2

21 Scandium (Sc) [Ar] 3d1 4s2

26 more rows

Explanation:

NUMBER ELEMENT ELECTRON CONFIGURATION

1 Hydrogen 1s1

2 Helium 1s2

3 Lithium [He]2s1

4 Beryllium [He]2s2

5 Boron [He]2s22p1

6 Carbon [He]2s22p2

7 Nitrogen [He]2s22p3

8 Oxygen [He]2s22p4

9 Fluorine [He]2s22p5

10 Neon [He]2s22p6

11 Sodium [Ne]3s1

12 Magnesium [Ne]3s2

13 Aluminum [Ne]3s23p1

14 Silicon [Ne]3s23p2

15 Phosphorus [Ne]3s23p3

16 Sulfur [Ne]3s23p4

17 Chlorine [Ne]3s23p5

18 Argon [Ne]3s23p6

19 Potassium [Ar]4s1

20 Calcium [Ar]4s2

Answer:

False,not all chemicals pollute the enviorment

Explanation:

Hope this helps!

Brainliest?

Answer:

False

Explanation:

Oxygen?

The recommendation that is least likely to reduce the amount of sulfur released into the air from impurities in hydrocarbons is to increase the use of fossil fuels without any modifications.

This is because impurities in hydrocarbons, such as sulfur-containing compounds, can be released into the air during the combustion process. Sulfur dioxide (SO2) is a common byproduct of burning fossil fuels that contain sulfur impurities. When released into the atmosphere, SO2 can react with other chemicals to form sulfuric acid (H2SO4), a major component of acid rain, and contribute to the formation of smog.

To reduce the amount of sulfur released into the air, there are several recommendations that can be followed, including:

Using cleaner burning fuels: This can involve using low-sulfur fuels or alternative fuels, such as natural gas or renewable energy sources like solar and wind power.

Using emission control technologies: Technologies such as catalytic converters or scrubbers can help reduce the amount of sulfur released into the air.

Improving vehicle maintenance: Regular vehicle maintenance, such as changing air filters and spark plugs, can help improve the efficiency of combustion and reduce emissions.

Implementing regulations: Government regulations can require industries to reduce their sulfur emissions through various means, such as setting limits on sulfur content in fuels or requiring the use of emission control technologies.

In summary, the recommendation that is least likely to reduce the amount of sulfur released into the air is to increase the use of fossil fuels without any modifications, as this will result in the continued release of sulfur-containing compounds into the atmosphere.

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Answer:

It is the temperature at which water is frozen or is pure ice

"Absolutely zero" temperature is the coldest temperature possible. It's so cold that everything stops moving and has no energy left. Scientists use a special scale called Kelvin to measure temperature, and absolute zero is at 0 Kelvin or -273.15 degrees Celsius (-459.67 degrees Fahrenheit). We can't actually reach absolute zero in real life, but scientists have come very close in laboratories using special cooling methods.

The name of the fatty acid according to the nomenclature we discussed in class, i.e., 18:2trans,cis,trans-\( \Delta^{1,3} \) \( -\Delta \) is trans-Δ9,12-octadecadienoic acid.

The naming of fatty acids is based on the number of carbon atoms present in the chain and the position of the double bond.The fatty acid, 18:2trans,cis,trans-\( \Delta^{1,3} \) \( -\Delta \), is an 18-carbon chain with two double bonds. The first double bond is present in the 9th position in the trans configuration, and the second double bond is present in the 12th position in the cis configuration. Octadecadienoic acid is a natural product found in Zanthoxylum beecheyanum, Dipteryx lacunifera, and other organisms with data available. The \( \Delta^{1,3} \) \( -\Delta \) notation is used to represent the position of the double bond with the carboxyl group being assigned the number 1.

Therefore, the name of the fatty acid is trans-Δ9,12-octadecadienoic acid.

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The empirical formulas of four binary ionic compounds formed from the given ions are:

The empirical formula of a compound represents the simplest ratio of the elements present in it. In this case, we have three ions: Mg\(_{2}\)+, Au\(_{3}\)+, and I-. To form a binary ionic compound, the positive and negative charges of the ions need to balance.

For the first compound, magnesium iodide (MgI\(_{2}\)), two iodide ions (I-) are needed to balance the charge of one magnesium ion (Mg\(_{2}\)+).

For the second compound, gold(III) oxide (Au\(_{2}\)O\(_{3}\)), three oxide ions (O\(_{2}\)-) are required to balance the charge of two gold ions (Au\(_{3}\)+).

The third compound is magnesium oxide (MgO), where one oxide ion (O\(_{2}\)-) combines with one magnesium ion (Mg\(_{2}\)+).

Lastly, for gold(I) iodide (AuI), one iodide ion (I-) is required to balance the charge of one gold ion (Au+).

These empirical formulas represent the simplest combination of ions in these ionic compounds.

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The final temperature of the bomb calorimeter is 30.9°C.

Combustion reactions are those reactions in which a compound completly decompose in to carbon dioxide and water molecule.

The final temperature will be calculated by using the equation:

Q = mc(T₂ – T₁), where

Q = relesed heat from calorimeter = 24kJ = 24000J

m = mass of calorimeter = 1.30kg = 1300g

c = specific heat of calorimeter = 3.41 J/(g°C)

T₁ = initial temperature of calorimeter = 25.5°C

T₂ = final temperature of calorimeter = to find?

On putting all these values on the above equation and calculate for T₂, we get

T₂ = 24000/(1300)(3.41) + 25.5

T₂ = 30.9°C

Hence, correct option is (1) i.e. 30.9°C.

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Answer:

30.9

Explanation:

right on edge 2022

The article aims to highlight the most recent improvements in the PCET procedures for electrocatalysis at clearly characterized electrode–electrolyte interfaces.

Aim : Here, we focus on the most recent developments in the PCET methods for electrocatalysis at clearly defined electrode–electrolyte interfaces.

Method: Since the groundbreaking and ongoing studies made by Frumkin and his colleagues initiated in the 1930s, non-covalent interaction, which is controlled by the cation/anion features, is known to play a crucial role in the interfacial water and adsorbate environments correlated to electrode–electrolyte catalytic properties.

The microscopic perspective of this interaction is still a significant scientific mystery, nevertheless. Recent research based on the well-defined surface and solid-liquid interfacial structure of single-crystal model electrodes revealed novel characteristics of the cation effect.

Practical usage: Designing high-performance electrode and electrolyte materials requires an understanding of the roles played by the electrical double layer (EDL) structure in proton-coupled electron transfer (PCET) electrode processes.

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To answer this question, we have to divide the amount of heat released by the change in temperature:

It means that the correct answer is the last choice 5.652kJ/°C.

Dialect is referred to the characteristic features of vocabulary, syntax, or

pronunciation that distinguish speech used by a group.

Dialect is a type of language that helps to provide more information as to

where an individual is from. This is usually done by observing how the

individual pronounces words.

The characteristic features of vocabulary and syntax helps to distinguish

speech used by a group of people. The accent the individual uses also

serves as the major determinant in deducing the origin of an individual.

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The covalent molecule is methane. Option C, methane (CH4) is the right answer.

Methane (CH4) is a covalent molecule that contains four hydrogen atoms and one carbon atom. Each is C, methane (CH4).

Methane (CH4) is a covalent molecule that contains four hydrogen atoms and one carbon atom. Each hydrogen atom shares one electron with the carbon atom, and the carbon atom shares one electron with each hydrogen atom, for a total of eight shared electrons. However, each bond involves two electrons, so there are only four covalent bonds and six shared electrons.

Ammonia (NH3) contains eight shared electrons, chlorine (Cl2) contains two covalent bonds and four shared electrons, and water (H2O) contains ten shared electrons.

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The covalent molecule is ammonia

A covalent molecule is a molecule in which two or more atoms share electrons through covalent bonds. Covalent bonding is a type of chemical bonding in which atoms share one or more pairs of valence electrons in order to attain a more stable electron configuration.

In a covalent molecule, the shared electrons are attracted to the positively charged nuclei of the atoms involved in the bond, holding them together. Covalent molecules tend to have relatively low melting and boiling points, and they are typically not good conductors of electricity

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We must take into account the suggested mechanism mentioned in your previous mail in order to anticipate the rate equation for the reaction between chlorine atoms (Cl) and ozone (O3):

ClO + O3 Cl + 2O2 (rapid step), step 1.

Step 2 (slow step): ClO + Cl Cl2 + O2.

The whole response can be expressed as follows:

2O3 → 3O2

By taking into account the rate-determining step, which is the slowest step in the suggested mechanism, we may formulate the rate equation for the total reaction. It is Step 2 in this instance:

Rate = k[ClO][Cl]

Where:

k is the rate constant for the reaction

[ClO] is the concentration of ClO

[Cl] is the concentration of Cl

Rate = k[ClO][Cl]

Where: [ClO] is the concentration of ClO [Cl] is the concentration of Cl, and k is the reaction's rate constant

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Answer:

Explanation:

Here, we want to calculate the initial volume of the container

Mathematically, we know that volume and pressure are inversely related. What this means is that as volume increases, pressure is expected to decrease and as pressure increases, volume is expected to decrease

A mathematical link between these two is as follows:

The above is according to Boyles' law.

The values with subscript 1 are the initial values, while the values with the subscript 2 are the final values

Thus:

V1 = ?

P1 = 1.25 atm

V2 = 1L

P2 = 3.75 atm

From the relation:

The two ways in which the physical state of matter can be changed are melting and freezing.

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Answer:

It is a combustion reaction

Explanation:

In the kinetic-molecular theory of gases, at high temperatures, particles of a gas tend to move faster and collisions between them are more frequent and energetic.

This is because at higher temperatures, the kinetic energy of the gas particles increases, causing them to move faster and collide more frequently. Additionally, as the temperature increases, the average distance between gas particles increases, allowing them to move more freely and collide with less resistance.

These collisions are also more energetic, as the increased kinetic energy of the particles results in greater force upon impact. Overall, the behavior of gas particles at high temperatures is characterized by increased movement and more frequent and energetic collisions.

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The partial pressure of oxygen in the mixture if the total pressure is 705 mmHg is 427.935 mmHg

mO2 =100g - 35.8% = 64.2 g

We shall use the molar masses of both masses to convert them to moles.

N2 = 35.8*1mol/28.00=1.29mol

O2=64.2, *1 mol/32.00, or 2 mol.

O2's mole fraction is:

O2 = nO2 + nN2 + nO2 = 2/ 1.29 + 2 = 0.607

We can use the following expression to determine the partial pressure of oxygen given the total pressure (P) is 705 mmHg.

pO2= P* O2

= 705 * 0.607

=427.935

a gaseous mixture of oxygen and nitrogen with a mass percentage of 35.8% nitrogen and a total pressure of 705 mmHg.

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Answer:

i aint go the f 40

Explanation:

swervin how u look so perfect on ur worst day

Answer:

lose

Explanation:

its lose because if its positive, assume the electron is a person who has already eaten, theyre full and dont want more, therefore they would want to lose the weight, so its lose.

The concentration in volume-volume percent of the solution is: 1.6 %

To solve this problem the formula and the procedure that we have to use is:

% v/v = v(solute)/v(solution) * 100

Where

Information about the problem:

Applying the concentration formula  we get:

% v/v = v(solute)/v(solution) * 100

% v/v = (4 ml/250 ml) * 100

% v/v = 0.016 *100

% v/v =1.6 %

In chemistry a solution is known as a homogeneous mixture of two or more components called:

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The location of the nucleus within an atom can be determined by measuring half the distance between the nuclei of two bonded atoms.

The Covalent radius can be described as a value used to understand the covalently bonded atoms, while the atomic number can be described as the number of protons and neutrons that are present in the atomic nucleus, which permits us to get the relative distance between one atom and other atoms.

The atomic number is useful in order to determine different elements since they are made of a variable number of positively charged protons and neutrons, as well as the number of negatively charged electrons around the nucleus.

Therefore, the Covalent radius and atomic number are fundamental in order to determine the number of protons and neutrons. The covalent radius can be used to determine the location of the nucleus within an atom.

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