URGENT!!!!!!!!!!!!!! help please!!!

The correct answers are: 1. Z-scores are useful because they provide a standardized way of indicating how unusual an observation is. 2. The standard deviation is a natural ruler for comparing values to the mean. 3. Z-scores and the standard deviation are applicable to both symmetric and skewed distributions.

These answers accurately describe the benefits of using Z-scores and the standard deviation in statistical analysis. Z-scores allow us to determine how many standard deviations away from the mean a particular observation is, providing a measure of how unusual or extreme that observation is compared to the rest of the data set.

The standard deviation serves as a measure of dispersion, representing the average amount by which data points vary from the mean. It provides a useful reference point for comparing individual values to the mean. Additionally, both Z-scores and the standard deviation can be applied to distributions with varying shapes, including both symmetric and skewed distributions.

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Select all of the answers that apply. Z-scores are useful because it is a standardized way of saying how unusual an observation is ZZZZZzzzzzzzzzzz <snore snore> WAKE UP you're almost done. the standard deviation is a natural ruler for comparing values to the mean they are applicable to both symmetric and skewed distributions.

Option b is true to match the vector field f with the given plot f(x, y)=x, -y

The earliest known attempts at the concept of functions can be traced back to the work of the Persian mathematicians Al-Biruni and Sharaf al-Din al-Tusi. Originally, functions were idealized dependencies of one variable on another. For example, planetary positions are functions of time. Historically, this concept was developed in calculus towards the end of his 17th century, and the functions studied were differentiable (i.e. they had a high degree of regularity) until his 19th century ).

Given,

f(x, y) = x, -y

gt; at x⇒∞, y⇒-∞ downwards

at x⇒∞, y⇒+∞ downwards

Therefore, option b is true to match the vector field f with the given plot

f(x, y)=x, -y

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The complete question is as follows:

Match the vector field f with the correct plot. f(x, y) = x, −y

Answer: -0.5

Step-by-step explanation: screenshot

Answer:

-0.2

Step-by-step explanation:

So the Equation is -1.4=0.6y-1.1, so to get the variable by itself, you would need to add 1.1 to both sides. Leaving you with -0.3=0.6y. so divide each side by -0.3. Leaving you with -0.2 hope this helps :)

Answer:

66

Step-by-step explanation:

6x + 8y + 6

x=2

y=6

Replace the letters with the numbers:

6(2) + 8(6) +6

= 12 +48 + 6

= 66

Answer:

Circle the -3 or the -2 in the final product

Step-by-step explanation:

If you multiply it out, the last terms are -2 and -3 which equal 6, not negative 6 so, that would be wrong factoring.

The angle bisector from a vertex to the opposite side of a triangle is unique. We get AD = BE by subtracting BD from both sides of AB + BD = BE.

Proposition 4.4 states that in every triangle, there exists an angle bisector from a vertex to the opposite side and the angle bisector is unique.

Proof:

Let ΔABC be the given triangle and suppose AD is the angle bisector from A to BC. To prove that AD is unique, suppose BE is another angle bisector from B to AC.

We need to show that AD = BE.

Construct the incenter I of ΔABC. Draw lines AI and BI. AI bisects ∠A and BI bisects ∠B.

So, ∠AIB = 90° + ½ ∠C (proved in proposition 4.3).

Again, ∠AIB = ∠AID + ∠BIE [angle addition property of equality]

Therefore, ∠AID + ∠BIE = 90° + ½ ∠C...(1)

Since AD is the angle bisector from A to BC, we have

∠BAD = ∠CAD

Also, BE is the angle bisector from B to AC, so

∠EB = ∠EC

Adding these two equations, we get

∠BAD + ∠EB = ∠CAD + ∠EC...(2)

Since ∠A + ∠B + ∠C = 180° (angle sum property of a triangle),

∠C/2 + ∠B/2 + ∠A/2 = 180° (angle bisector property)

Therefore, ∠A/2 + ∠B/2 = 90° - ∠C/2

So, 2∠A/2 + 2∠B/2 = 180° - ∠C...(3)

Adding equations (1), (2), and (3), we get

∠AID + ∠BIE + ∠BAD + ∠EB + 2∠A/2 + 2∠B/2 = 360° - ∠C/2 + 180° + ∠C/2 + 180° - ∠C

∠AID + ∠BIE + ∠BAD + ∠EB + ∠A + ∠B = 360°(simplifying)

Therefore,

∠AID + ∠BIE + ∠BAD + ∠EB = 180°...(4)

Now, consider ΔABD and ΔEBD.

∠ABD = ∠EBD (∵ AD and BE are angle bisectors)

∠BAD = ∠BED [from equation (2)]

Therefore, ΔABD ≅ ΔEBD (∵ SAS congruence criterion)

So, BD = BD [by CPCTC]

Thus, we get AD = BE [by subtracting BD from both sides of AB + BD = BE]

Hence, the angle bisector from a vertex to the opposite side of a triangle is unique.

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Answer:

x = -87

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

PEMDAS is the order of operation and stands for:

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

~

First, subtract 265 from both sides of the equation:

3x + 265 (-265) = 4 (-265)

3x = 4 - 265

3x = -261

Next, divide 3 from both sides:

(3x)/3 = (-261)/3

x = -261/3

x = -87

x = -87 is your answer.

~

Answer:

If you're looking for the value of x, it's -87.

Step-by-step explanation:

1. Subtract 265 from both sides

3x+265-265 = 4-265 = 3x = -261

2. Divide by 3 to get the variable by itself

3x/3 = -261/3. = -87

x = -87

Hope this helps

Answer:

D.

Step-by-step explanation:

it has an x-intercept of –3 and a y-intercept of -4

Answer:

d

Step-by-step explanation:

look at d for a second, just find along the y line where -4 is at and where -3 is at on the x intercept

The given annuity has a deposit of $15,604 made every quarter for a period of 7 years, which is equivalent to 28 quarters. The interest rate is 6.4% compounded quarterly.

Using the formula for the present value of an ordinary annuity, we can calculate the present value (P) as follows:

P = C * (1 - 1 / (1 + r)^n) / r

Substituting the given values into the formula:

P = 15,604 * (1 - 1 / (1 + 0.064)^28) / 0.064

After evaluating the expression, we find:

P ≈ $764,342.64

Therefore, the present value of the annuity with deposits of $15,604 made quarterly for 7 years at a 6.4% interest rate compounded quarterly is approximately $764,342.64.

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Step 1- Write out the Present Value of Annuity formula:

Where

Step 2- Write out the given values and substitute them into the formula:

Substituting the values into the formula, we have:

Therefore,

Dividing both sides by 72.0260, we have:

Hence, the monthly payment is $327.78.

The total amount T paid is given by:

Hence, the interest I is given by:

Therefore, the monthly payment is $327.78 and the interest paid is $7858.08

The expressions that have 3 as the greatest common factor are b + 3 + 6c, 27n + 66p, and 36 - 9j + 6k.

Thus,

b + 3 + 6c         - Yes

-30 - 24z           - No

27n + 66p         - Yes

36 - 9j + 6k       - Yes

From the question, we are to determine if 3 is the greatest common factor of the given expressions

b + 3 + 6c

3(b + 1 + 2c)

The greatest common factor is 3

-30 - 24z

6(-5 -4z)

The greatest common factor is not 3. The greatest common factor is 6

27n + 66p

3(9n + 22p)

The greatest common factor is 3

36 - 9j + 6k

3(12 - 3j + 2k)

Thus, The greatest common factor is 3

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The coefficient of determination, R2, is a measure of how much of the variation in the data is explained by the regression model. It ranges from 0 to 1, with higher values indicating better model fit.

The coefficient of determination, R2, is a measure used to evaluate how well a regression model fits the data. It is a number between 0 and 1, with higher values indicating a better fit. A perfect fit will have an R2 value of 1, while a value of 0 indicates that the model does not explain any of the variation in the data. R2 is calculated as the ratio of the variance explained by the model to the total variance in the data. This measure is often used to compare different models and select the best one for a given data set. It is also used to assess how well a given model fits the data, as a way of determining the accuracy of the model's predictions.

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The expected frequency of east campus and passed is C. 42 students

The table for expected frequency is ,

East Campus West Campus Total

Passed (84*100)/22=42 (84*100)/200 =42 84

Failed (116*100)/200=58 (116*100)/22=58 116

Total 100 100 200

Passed = 84×100/200

= 42

Therefore, the expected frequency of East Campus and Passed is 42 students.

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Answer: I know how to do this but I don't know how to do this one sorry

Step-by-step explanation:

Answer:

Addition

Step-by-step explanation:

By simple addition we can reduce the no. Of steps involved.

Answer:

Subtracting; x = 3/2, y = 8

Step-by-step explanation:

1. Subtracting them from one another because the 1/2y term matches up.

2. when added together:

8x = 12

x = 3/2

plug the x value into one of the equations:

y = 8

The statement cross-tabulation with two variables is known as twice-tabulation is false because there is no such term as "twice-tabulation" in the context of statistical analysis.

Cross-tabulation, also known as contingency table analysis, involves the analysis of categorical variables by creating a table that shows the frequency or distribution of one variable based on the levels of another variable.

It allows for the examination of the relationship between two variables, highlighting any associations or patterns that may exist. Each cell in the cross-tabulation table represents the count or proportion of observations that fall into specific combinations of categories from the two variables.

The term "twice-tabulation" does not exist in statistical literature and is not commonly used to refer to cross-tabulation with two variables. The correct term to describe this statistical technique is simply cross-tabulation or contingency table analysis.

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Answer:

The answers are below

Step-by-step explanation:

1 - 6ft

2 - 8 years

3 - 9ft

1) The gravimetric moisture content of the soil at field capacity is approx 27.62%.

2) The dry bulk density of the sample is approximately 1.193 g/cm^3.

3) The porosity of the sample, as a percentage of the total volume, is approximately 54.96%.

1) The gravimetric moisture content of the soil at field capacity can be calculated using the following formula:

Gravimetric Moisture Content = ((Wet Weight - Dry Weight) / Dry Weight) * 100

Given:

Wet Weight = 274.1 g

Dry Weight = 214.7 g

Using the formula, we can substitute the values:

Gravimetric Moisture Content = ((274.1 - 214.7) / 214.7) * 100

Gravimetric Moisture Content = (59.4 / 214.7) * 100

Gravimetric Moisture Content ≈ 27.62%

The gravimetric moisture content of the soil at field capacity is approximately 27.62%.

The gravimetric moisture content represents the amount of water present in a given mass of soil. By subtracting the dry weight of the soil from the wet weight and dividing by the dry weight, we can determine the proportion of water in the sample. Multiplying by 100 gives the moisture content as a percentage.

1a. The dry bulk density of the sample can be calculated using the following formula:

Dry Bulk Density = Dry Weight / Sample Volume

Given:

Dry Weight = 214.7 g

Sample Volume = 180 cm^3

Substituting the values into the formula:

Dry Bulk Density = 214.7 g / 180 cm^3

Dry Bulk Density ≈ 1.193 g/cm^3

The dry bulk density of the sample is approximately 1.193 g/cm^3.

Dry bulk density refers to the mass of dry soil per unit volume. To calculate it, we divide the dry weight of the soil by the sample volume.

1b. The porosity of the sample can be calculated using the following formula:

Porosity = (1 - (Dry Bulk Density / Particle Density)) * 100

The particle density for soil is usually around 2.65 g/cm^3.

Given:

Dry Bulk Density = 1.193 g/cm^3

Particle Density = 2.65 g/cm^3

Substituting the values into the formula:

Porosity = (1 - (1.193 / 2.65)) * 100

Porosity ≈ 54.96%

The porosity of the sample, as a percentage of the total volume, is approximately 54.96%.

Porosity represents the void space within a soil sample. It is calculated by subtracting the ratio of the dry bulk density to the particle density from 1 and multiplying by 100 to get the percentage. In this case, the particle density of 2.65 g/cm^3 is a typical value for soil.

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Answer:

2n+2

Step-by-step explanation:

the common difference is 4,6,8

again the common difference of 4,6,8 is 2,2

hence its common difference is 2

now, nth term,=a+(n-1) *d

4+(n-1)*2

4+2n-2

2n+2

The absolute value of x minus one is equal to two. Therefore, x must be either one greater than two (x = 3) or one less than two (x = 1).

One less than x results in a value of two in absolute terms. As a result, x minus 1 has an absolute value of 2, which is a positive number. The separation of an integer from zero is its absolute value. As a result, x minus 1 is two units from zero in absolute terms. As x minus one has an absolute value of two, its real value must either be two or a negative two. That is to say, x must either be one more than two (x = 3) or one less than two (x = 1).In order to confirm this, let's look at a few examples. If x = 3, then |x - 1| = |2 - 1| = |1| = 1 which is not equal to two. Therefore, x = 3 is not the answer we are looking for. On the other hand, if x = 1, then |x - 1| = |1 - 1| = |0| = 0 which is not equal to two. Therefore, x = 1 is also not the answer we are looking for. The only two possible solutions for the equation |x - 1| = 2 are x = 3 and x = 1. Therefore, the result of |x - 1| = 2 is that x must be either one greater than two (x = 3) or one less than two (x = 1)

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(C)

Given data:

The given inequalities.

The graph of the given inequalities is shown below.

Answer:

x= 3.2

Step-by-step explanation:

Answer:

Step-by-step explanation: The first one would be -40 X 30. The parentheses around -25 turns it into a positive. And 5 make you round up

For 2, the -18 turns into a positive 18 bc of the parentheses. So round up to 20. Round 38 up to 40. 20 x 40

For 3, the negative 16 turns positive, making the equation -21 x 9 x 16. Round them to -20, 10, and 20. The equation is -20 x 10 x 20. Hope this helps!

The answers are : mean = 0, standard deviation = 1, skewed to the right.

And the correct option is A.

The square root of the variance is used to calculate the standard deviation, a statistic that expresses how widely distributed a dataset is in relation to its mean.

Given:

The mean finish time for 48 racers who finished the grueling 50 km cross-country ski race at the Olympics is 2.164 hours,

and the standard deviation is 0.85 hours.

That means, we have;

μ = 2.164 and σ = 0.85

So, the z-score;

z = (\(\bar x\) - μ) / σ

z =  (\(\bar x\) - 2.164) / (0.85)

The mean of z-score is,

E(z) = E (\(\bar x\)) - μ / σ

E(z) = μ  - μ / σ

E(z) = 0 / σ

E(z) = 0

SD of z-score is,

SD (z) = SD(\(\bar x\)) - μ / σ

SD (z) = SD(\(\bar x\)) - 0 / σ

SD (z) = SD(\(\bar x\)) / σ

SD (z) = σ / σ

SD (z) = 1

Median of the distribution \(\bar x\) ≈ 2.13.

It responds to cumulative relative frequency of 0.50.

Median < mean

The coefficient of skewness is given by;

S = 3 (median - mean) / σ

S = 3 (2.164 - 2.13) / σ

S > 0

That means, the shape of the distribution of z - score is skewed to the right.

Therefore,  mean = 0, standard deviation = 1, skewed to the right.

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Answer:

1,1.1,1.25,1.5,1.7,9

The measurement of the angle OP is 39

The given parameters that will help us to answer the question are

R is mid point of OQ

S is mid point of PQ

RS = 3x + 38

OP = 4x- 14

R is mid point of OQ and S is mid point of PQ;

By using mid point theorem

[1/2][OP] = RS

This implies that So,

[1/2][3x + 38] = [4x- 14]

[3x+38] = 2[4x- 14]

Opening the brackets we have

3x+38=8x-28

Collecting like terms

3x-8x=-28-38

-5x=-66

Making x the subject of the relation we have

x = -66 / -5

x = 13.2

Therefore RS = 3(13.2) + 38 = -11.4

OP = 4(13.2)- 14=38.8

Measurement of OP = 39 approximately

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Based on the given data, it is advisable for management at Kelsh to eliminate the North Division in order to avoid the traceable fixed expenses associated with it, while keeping the total common corporate expenses unaffected.

When considering the elimination of a division, it is crucial to analyze the impact on expenses and overall profitability. In this case, the information states that if the North Division is eliminated, its traceable fixed expenses can be avoided. Traceable fixed expenses refer to the costs that are directly associated with a specific division or segment of a company. By eliminating the North Division, Kelsh can avoid incurring these interests, potentially improving the company's financial performance.

Furthermore, the data states that the total common corporate expenses would be unaffected by the elimination of the North Division. Common corporate expenses are costs incurred at the corporate level that are not directly attributable to any specific division or segment.

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Answer:

\( 10 \: { \: m}^{2} \)

Step-by-step explanation:

area of the shaded region = Area of triangle formed in rectangle with base (10 - 6 = 4) 4m and height 2 m + Area of triangle formed in square with base 2 m and height 6 m

\( = \frac{1}{2} \times 4 \times 2 +\frac{1}{2} \times 2\times 6 \\ \\ = 4+6 \\ \\ = 10 \: { \: m}^{2} \)

Answer:

shaded region = 10 m squared

Step-by-step explanation:

Area square = 6x6 = 36    Area reatangle 4x2 = 8

both areas = 44

Now lets subtract some white parts to obtain the shaded parts

1/2 of 4x6 = 12

1/2 of 6x6 = 18

1/2 of 4x2 =4

12+18+4= 34

44-34 = 10