URGENT!! A 0.057 kg tennis ball and a tennis racket collide. The racket has an initial
momentum of -2.80 kg m/s and a final momentum of -1.97 kg-m/s. The ball
has an initial momentum of 0.02565 kg-m/s. If you assume the collision is
elastic, what is the final velocity of the ball?
O A. -83.26 m/s
O B. -0.80 m/s
O C. -14.11 m/s
O D. -4.75 m/s

1. The force between the two charges is 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of 10 gauge aluminum wire over a 40 ft distance would be 0.506 ohms.

3. The cost of electricity from the automobile battery is 38.6 cents per kWh.

4. The current that would be carried through the body is 0.8 mA if dry.

1. The force between two point charges can be calculated using Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.

Using the values given, the force can be calculated as F = (k * q1 * q2) / r², where k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between them. Plugging in the values, the force can be calculated as 1.78 × 10⁻⁵ pounds, with opposite signs indicating attraction between the charges.

2. The resistance of a wire is determined by its length, cross-sectional area, and resistivity. The resistivity of aluminum is higher than that of copper, so a larger cross-sectional area is required to achieve the same resistance. Using the gauge size conversion chart, 10 gauge aluminum wire has a cross-sectional area of 5.26 mm², which is approximately 83% of the cross-sectional area of 12 gauge copper wire.

Thus, the resistance of 10 gauge aluminum wire over a 40 ft distance can be calculated as R = (rho * L) / A, where rho is the resistivity of aluminum, L is the length, and A is the cross-sectional area. Plugging in the values, the resistance can be calculated as 0.506 ohms.

3. To calculate the cost of electricity per kWh, the total cost and the total amount of energy supplied must be known. Since the battery supplies 12 V and 51 A for one hour, the total energy supplied can be calculated as E = V * I * t, where V is the voltage, I is the current, and t is the time.

Plugging in the values, the total energy supplied can be calculated as 612 watt-hours (Wh). Since one kWh is equal to 1000 Wh, the total energy supplied can be converted to 0.612 kWh. Dividing the total cost by the total energy supplied gives the cost per kWh, which is 38.6 cents.

4. The current through the body can be calculated using Ohm's law, which states that current is equal to voltage divided by resistance. Using the values given, the resistance can be either 100,000 ohms or 300 ohms depending on whether the skin is dry or wet.

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Answer:

did you tried putting it in standard form

Answer:

It may help to round all of the given numbers up to at least 1 or 2 decimal points or you could round up the number you get to 1 or 2 decimal places. For example, for this question round up your answer to 1.9 or 1.94

Explanation:

hope this helps!!

Answer:

longitudinal wave

i guess

sry if its wrong

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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Answer:

V = K Q / R     electric potential due to charge Q at distance R

V = 9.00E9 * 7.6 / .14 = 4.89E11 V

Almost 1 trillion volts due to large charge of 7.60 C

(Find Q needed to provide 100  amp-hour of charge on a 12V car battery)

The momentum, in the x-direction, that was transferred to the more massive cart after the collision is 19.38 kgm/s.

The momentum transfered to the more massive cart is determined by applying the principle of conservation of linear momentum as shown below;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

⁻ΔP₁ = ΔP₂

ΔP₂ = m₂v₂ - m₂u₂

ΔP₂ = m₂(v₂ - u₂)

ΔP₂ = 3m₁(v₂ - u₂)

ΔP₂ = 3 x 3.8 x (1.7 - 0)

ΔP₂ = 19.38 kgm/s

Thus, the momentum, in the x-direction, that was transferred to the more massive cart after the collision is 19.38 kgm/s.

The complete question is beblow

A cart of mass 3.8 kg is traveling to the right (which we will take to be the positive x-direction for this problem) at a speed of 6.9 m/s. It collides with a stationary cart that is three times as massive. After the collision, the more massive cart is moving at a speed of 1.7 m/s, to the right.

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The torque is equal to zero since the coil is in equilibrium. As a result, will also equal zero, indicating that the coil's plane is parallel to the vertical direction at equilibrium.

The current-carrying coil in a magnetic field is given by:

τ = μ * B * I * A * sin(θ)

where:

τ = torque (in Nm)

μ = magnetic moment of the coil (in Am^2)

B = magnetic field strength (in T)

I = current flowing through the coil (in A)

A = area of the coil (in m^2)

θ = angle between the plane of the coil and the magnetic field (in radians)

μ = N * A * I

N = number of turns of the coil

A = area of the coil (in m^2)

I = current flowing through the coil (in A)

the equations to calculate the angle θ:

m = 0.100 kg (mass of the wire)

L = 4.00 m (total length of the wire)

side length = 0.100 m

I = 3.80 A (current flowing through the coil)

B = 0.0100 T (magnetic field strength)

Calculations:

A = side length^2 * N = 0.100^2 * 1 = 0.0100 m^2

μ = N * A * I = 1 * 0.0100 * 3.80 = 0.0380 Am^2

Now we can rearrange the equation for torque to solve for θ:

θ = arcsin(τ / (μ * B * I * A))

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Answer:

The order = \(\mathbf{\sqrt{\dfrac{h}{2 \pi m}} \sqrt[4]{\dfrac{H}{g}} \sqrt[4]{\dfrac{1}{2}} }}\)

Explanation:

To miss the crack at a given distance is apparently not the same as the uncertainty that occurred in the distance while falling from the tower. However, it is believed that the uncertainties in both cases appear to be the same.

So, let's work it out together

According to Heisenberg's uncertainty principle:

\(\Delta s. \Delta p =\dfrac{h}{2} =\dfrac{h}{4 \pi}\)

Also; if we recall from the equation of motion that:

\(v = u + at ---(1) \\ \\ v^2 - u^2 = 2as --- (2) \\ \\ s = ut + \dfrac{1}{2}at^2 --- (3)\)

So, if u = 0 and a = g

Then;

\(v = gt --- (1) \\ \\ v^2 = 2gs - - - ( 2) \\ \\ s = \dfrac{1}{2}gt^2 --- (3)\)

From (2)

Making (s) the subject, we have:

\(s = \dfrac{v^2}{2g}\)

\(s = \dfrac{p^2}{2gm^2}\)

By differentiation;

\(ds = d (\dfrac{p^2}{2gm^2})\)

\(ds = \dfrac{2pdp}{2gm^2}\)

\(\Delta \ s = \dfrac{p \Delta p}{gm^2 }\)

where;

\(\Delta p = \dfrac{h}{4 \pi \Delta \ s}\) from uncertainty principle

This implies that:

\(\Delta s = \dfrac{p(\dfrac{h}{4 \pi \Delta s }) }{gm^2}\)

\(\Delta s = p(\dfrac{h}{4 \pi gm^2 }) \times \dfrac{1}{ \Delta s}}\)

\((\Delta s)^2 = \dfrac{hmv} {4 \pi gm^2 }\)

here;

v = 2gH

So;

\((\Delta s)^2 = \dfrac {h \sqrt{2gH} }{4 \pi gm }\)

\(\mathbf{(\Delta s)^2 = \sqrt{\dfrac{h}{2 \pi m}} \sqrt[4]{\dfrac{H}{g}} \sqrt[4]{\dfrac{1}{2}} }\)

Thus, the order = \(\mathbf{\sqrt{\dfrac{h}{2 \pi m}} \sqrt[4]{\dfrac{H}{g}} \sqrt[4]{\dfrac{1}{2}} }}\)

Answer:

The Moon blocks the suns light from hitting the surface of the earth

Answer:

The Moon blocks the Sun's light from hitting the surface of the Earth.

Answer:

dgfggddhdbxbxjxddhsnsxnc

Answer:

multiply the volume by the length and width of the aluminum

Answer:

Explanation:

Using the Newtons law of motion;

\(\sum Fx = ma_x\\Fm - Ff = ma_x\)

Fm is the moving force = 400N

Ff is the frictional force = μR

μ is the coefficient of kinetic friction

R is the reaction = mg

m is the mass

a is the acceleration

The equation becomes;

\(Fm - \mu R = ma_x\\Fm - \mu mg = ma_x\\400- \mu (25)(9.8) = 25(9)\\400 - 254.8 \mu = 225\\- 254.8 \mu = 225 - 400\\- 254.8 \mu = -175\\ \mu = \frac{-175}{- 254.8} \\\mu = 0.69\)

Hence the coefficient of kinetic friction between the box and floor is 0.69

The coefficient of kinetic friction between the box and the floor is 0.714.

Friction: This can be defined as the force that tends to oppose two surfaces in motion.

The question above can be solved using the formula

F-ma = mgμ................. Equation 1

Where F = Force applied to push the box, m = mass of the box, a = acceleration of the box, μ = coefficient of kinetic friction, g = acceleration due to gravity.

make μ the subject of the equation

μ = (F-ma)/mg................ Equation 2

From the question,

Given: F = 400 N, m = 25 kg, a = 9 m/s²,

Constant: g = 9.8 m/s²

Substitute these values into equation 2

μ = [400-(25×9)]/(25×9.8)

μ = (400-225)/245

μ = 175/245

μ = 0.714

Hence, the coefficient of kinetic friction between the box and the floor is 0.714.

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The work-done by the wind as the bug undergoes the displacement is 80 J.

The given parameters;

The work-done by the wind as the bug undergoes the displacement is obtained by finding the dot product of the force and the displacement;

Work done = F. r

Work done = (4.0 î – 6.0j) x 10⁻² . (8.0î - 8.0j)

Work done = (32i²) + (48j²)

Work done = 32(1) + 48(1)

Work done = 80 J.

Thus, the work-done by the wind as the bug undergoes the displacement is 80 J.

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Sound will travel fastest in air at 15°C.

The speed of sound in air, given in the range of 100 degrees Celsius and 0 degree Celsius include;

Air at 100°C 387 m/s

Air at 0°C 331 m/s

From the date above, the speed of sound in air increases with increases in temperature. Thus, Sound will travel fastest in air at 15°C.

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The density of a thing is determined by the spacing between its constituent molecules. Less dense materials are those in which their molecules are dispersed and spaced farther apart.

On the reverse hand, items with molecules arranged closely together have higher densities.

The ability to float or sink is caused by this disparity in densities.

Because it has a lower density than liquid B, liquid A will be floating on top of it since it's lighter.

The mass-to-volume ratio is known as density. Due to the fact that they contain less debris, low population materials have a low mass cubic per centi meter.   Density can be defined as a substance's weight for a given quantity. Ground water has a density of 1 gram per millilitre, however this can vary.

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The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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The Sound Pressure Level of an absolute pressure of 8 * \(10^{-7}\) is - 28 dB

SPL = 20 * log ( P / \(P_{ref}\) )

SPL = Sound Pressure Level

P = Absolute pressure

\(P_{ref}\) = Reference value of sound pressure

P = 8 * \(10^{-7}\) Pa

\(P_{ref}\) = 2 * \(10^{-5}\) Pa

SPL = 20 * log ( 8 * \(10^{-7}\) / 2 * \(10^{-5}\) )

SPL = 20 * log ( 0.04 )

SPL = 20 * ( - 1.4 )

SPL = - 28 dB

Sound Pressure Level is the measure of pressure level of sound in decibels. The reference pressure level of sound in air is 2 * \(10^{-5}\) Pa

Therefore, the Sound Pressure Level of an absolute pressure of 8 * \(10^{-7}\) is - 28 dB

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The interaction between the Corn plants and milkweed plants demonstrates as competition.

Competition is typically considered to refer to the detrimental consequences that neighbors' presence has on a plant's fitness or growth, typically through lowering the resources available.

In addition to resources, disturbance, herbivory, and mutualisms, competition can be a significant factor in controlling plant populations. The resource involved is depending on the species and the region, as all plants require a few fundamental ingredients.

As corn plants and milkweed plants grow in the same area, the interaction between the Corn plants and  milkweed plants demonstrates competition.

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When an object is thrown at an angle from the horizontal, the path followed by the body is called the projectile motion. The duration in seconds that the object is above the height of 14 m is 4.698 s.

Speed is the time rate at which velocity is changing.

Vertical speed component is

V₀y = 52sin 30°= 26 m/s

Given is the height h=14m

Using second equation of motion,

S=ut+ 1/2 at²

Substituting the values, we get

14 = 26t - 4.9t²

4.9t² - 26t +14 =0  

Solving the quadratic equation, we get the time as

taking the positive sign, t =4.698 s

taking the negative sign , t = 0.6082 s

Thus, the duration in seconds that the object is above the height of 14 m is 4.698s.

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The momentum of the gold ball that represents the force exerted on the ball at the three moments described is vector B.

Momentum is a vector quantity resulted from the mass of a particle and its velocity. Momentum represents the force acting on the particle. Momentum is the implication of Newton's Second Law. Momentum can be formulated as:

P = m.v

where:

P = momentum

m = mass

v = velocity

Following the three moments, we can identify the vector that represent the force exerted on each moment. Let's discuss them further.

Once the golf ball is hit by a club from its stationary position, the force exerted on the golf ball will be in the same direction to the club movement. We assume in this case that the club hits the ball from the left to right. The force will move the ball from its stationary position to the right.

Once the ball is at maximum compression, the force is also at its maximum point. The direction of the force remains as the previous moment.

Lastly, once the ball starts to expand, the force declines. The ball will come to its end position once the momentum of the force becomes zero (0). The momentum of the force will decline since the force direction changes to the left as resulted of the frictional force from the air.

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Complete Question:

A stationary golf ball is hit by a club. while the club is in contact with the ball, the ball compresses, the club exerts maximum force when the ball is at maximum compression, and then the ball expands. the momentum of the golf ball after contact with the club is represented by the vector above. which of the following groups of vectors could represent the force exerted on the ball at the three moments described?

(Please refer to the picture attached below)

Answer:

True

Explanation:

For signs of such collisions on the moons of the outer planets, look for craters, ray systems, fissures and fractures, melted or evaporated material, and changes in the moon's surface composition.

Huge fragments of the newly discovered comet Shoemaker-Levy 9 (SL9) collided with Jupiter over a period of days from July 16 to 22, 1994, leaving vast, dark scars in the planet's atmosphere and lofting superheated plumes into its stratosphere.

Dust was also left floating on top of Jupiter's clouds after the collision. The movement of the planet's dust allowed researchers to trace Jupiter's high-altitude winds for the first time.

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19,600 Newtons (about 4,400 pounds).

On Earth only.

Different in other places.

Answer:

15 seconds

Explanation:

Given that the initial speed of a cannon ball is 0.20 km/s. If the ball is to strike a target that is at a horizontal distance of 3.0 km from the cannon. The minimum time of flight for the ball can be calculated by using the formula for speed

speed = distance / time

Where

speed = 0.2 km/s

distance = 3 km

Substitute the two parameters into the formula

0.2 = 3 / t

make t the subject of the formula

t = 3/0.2

t = 15 s

Therefore, the minimum time of flight for the ball is 15 seconds

The total distance covered by the car is 4 kilometers, this is because we are taking into account displacement and not just distance.

Displacement is defined as the change in the position of an object while distance is an object's overall movement in a directionless fashion.

There are many different units that can be used to measure distance (inches, feet, miles, kilometers, and centimeters), but the meter is the SI unit. It is a scalar amount because it does not consider

On the number line, we can see the movement as follows

1 0 -1 -2 -3= 4km

Distance is always positive and never gets smaller as you move. Displacement can be negative, positive, or zero because it refers to the change in the position of an object with respect to its original location.

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The net force acting on the object is 12N

The mass of the object, m = 4 kg

The acceleration, a = 3 m/s²

The net force acting on the object is calculated as:

F = ma

F = 4(3)

F = 12 N

The net force acting on the object is 12N

Solving Gaussian integration with polar coordinates involves converting the integral into polar coordinates, finding the mean and standard deviation of the function, substituting them into the Gaussian distribution formula, and integrating it over the range of the function in polar coordinates.

Gaussian integration with polar coordinates is the process of finding the integral of a function using polar coordinates and the Gaussian distribution. The polar coordinate system is a two-dimensional coordinate system that uses the radius and angle to locate a point in a plane. The Gaussian distribution is a probability distribution that is often used to describe random variables in statistics.
To solve the Gaussian integration with polar coordinates, we need to convert the integral into polar coordinates. The conversion is done using the following equations:
x = r cos(θ)
y = r sin(θ)
r² = x² + y²
θ = tan⁻¹(y/x)
Once the integral is converted into polar coordinates, we can use the Gaussian distribution to solve it. The Gaussian distribution is given by the following formula:
f(x) = (1/σ√(2π))e^(-(x-μ)²/2σ²)
where μ is the mean of the distribution and σ is the standard deviation. To use this formula, we need to first find the mean and standard deviation of the function we are integrating.
After finding the mean and standard deviation, we can substitute them into the Gaussian distribution formula and integrate it over the range of the function in polar coordinates. The result of the integration will be the value of the integral.
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