Union City Bakery uses a chocolate chip muffin recipe that yields 1/2 cup of milk for every batch of 12 chocolate chip muffins. Based on the recipe:

* How much milk is needed to make each muffin?
* How much milk in needed to make 24 chocolate chip muffins?

Answers

Answer 1

Answer:

Grease bottoms only of 12 muffin cups or line with baking cups. ... I made some changes to the recipe;

Step-by-step explanation:

I added 1 cup milk, 1 cup chips, 1 cup ... was way too much batter for 12 muffins; I ended up making two trays and they were done in 18 minutes. I give it four stars only because of all the changes I had to make


Related Questions

I NEED HELP 20 points and I need step by step explanation

I NEED HELP 20 points and I need step by step explanation

Answers

Answer:

Yes.

Step-by-step explanation:

The answer is yes because there are more plots on the right (increased amount) of data set B, while data set A's plots are more to the left (decreased amount) making it less.

Solve for x:

20- 3x= -3(x-8)​

Answers

Answer:

\(20 - 3x = - 3( x - 8) \\ 20 - 3x = - 3x + 24 \\ - 3x + 3x = 24 - 20 \\ 0 = 4\)

It does not have any answer.

How do I enter this formula into a calculator? ​

How do I enter this formula into a calculator?

Answers

Answer:

Step-by-step explanation:

You can enter the formula P(i/(1-(1+i)^-n)) into a calculator using the following steps:

Enter the value of P

Multiply by i

Divide by (1 - (1 + i)^-n)

If your calculator has a memory function, you can store the value of (1 + i)^-n in memory and recall it when necessary.

For example, let's say P = 1000, i = 0.05, and n = 10. Here are the steps:

Enter 1000

Multiply by 0.05 (resulting in 50)

Enter 1.05 (1 + 0.05)

Raise 1.05 to the power of -10 (resulting in 0.37689)

Subtract 0.37689 from 1 (resulting in 0.62311)

Divide 50 by 0.62311 (resulting in 80.289)

Therefore, P(i/(1-(1+i)^-n)) equals 80.289 when P = 1000, i = 0.05, and n = 10.

Find each length below.

Find each length below.

Answers

a) The length of the secant segment \(HC = 31.5\).

b) The length of the secant segment \(XY = 4.8\)

What is the secant segment?

In geometry, a secant is a line that intersects a circle at two distinct points. A secant segment is part of a secant that lies between its two points of intersection with the circle.

In geometry, a segment is part of a line that is bounded by two distinct endpoints. A segment can be straight or curved. Straight segments are also called line segments, and curved segments are also called arcs.

According to the given information

a) In the figure, HG is a tangent and HD is a secant to the circle, and HC is the length of the secant segment.

We know that the product of the lengths of the two segments of a secant from an exterior point to a circle is equal to the product of the lengths of the entire secant and its external segment. That is,

\(HD*HE =HG^{2}\)

where \(HE\) is the length of the external segment of the secant.

Substituting the given values, we get:

\(31.5*HE =21^{2}\)

\(HE = 21^{2} /31.5 = 14\)

Now, we can use the same property to find \(HC\). That is,

\(HC *HE =HG^{2}\)

Substituting the values we have found, we get:

\(HC*14 = 21^{2} \\HC = 21^{2} /14 = 31.5\)

Therefore, the length of the secant segment \(HC = 31.5\).

b) \(VX*VZ= VY*VW\)

Substituting the given values, we get:

\(14.4*12= VY *36\\VY = (14.4*12)/36 = 4.8\)

Therefore, the length of \(VY, XY = 4.8\)

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Two trains leave the station at the same time, one heading east and the other west. The eastbound train travels 20 miles per hour slower than the westbound train. If the two trains are 360 miles apart after 2 hours, what is the rate of the eastbound train?

Answers

Answer:

Westbound = x;

Eastbourne = x-20;

So they will have the common rate: 360/2 = 180;

x+x-20 = 180

2x = 200;

x = 100;

So Eastbourne will be 100-20 = 80 miles per an hour;

pls help I'll mark the first person brainliest answer all​

pls help I'll mark the first person brainliest answer all

Answers

Answer:

4

a. 12

b. 8

c. 30

d. 40

Step-by-step explanation:

each exterior = 360/n

30*n=360

divide both side by 30

Answer is 12

The same apply to others to 4d

so first its 4

a. 12

b. 8

c. 30

d. 40

i will try to explain:

each exterior = 360/n

30*n=360

divide both side by 30

Answer is 12

The same apply to others to 4d

Let f:R" + R be a convex function. Show that (i) and (ii) are equivalent definitions for m-strong convexity:(i) f(x) – m. || 2 || 2 is convex.(ii) f (4x + (1 - 1)y) = \f (x) + (1 - 1)f (y) – m (1 – 1)||2 – y||2 for all x, y ER" and [0, 1]. 2If in addition f is differentiable then show (i) and (ii) are equivalent to (iii): т (iii) f(y) > f(x) + f(x)?(y – x) + m || 2 – y||

Answers

For f: R" + R be a convex function (i) and (ii) are equivalent definitions for m-strong convexity because m[||px + (1-p)y||².

Let x, y ∈ \(R^n\) and let 0 < p < 1. Then we have:

||px + (1-p)y|| ≤ ||px|| + ||(1-p)y|| [triangle inequality]

= p||x|| + (1-p)||y|| [since ||cx|| = |c| ||x|| for any scalar c]

Now, since f is convex, we have:

f(px + (1-p)y) ≤ pf(x) + (1-p)f(y)

Using the inequality above, we can substitute the right-hand side of this inequality as follows:

f(px + (1-p)y) ≤ pf(x) + (1-p)f(y)

f(px + (1-p)y) - pf(x) ≤ (1-p)f(y)

f(px + (1-p)y) - pf(x) + p(f(x) - f(y)) ≤ 0

Define h(p) = f(px + (1-p)y) - pf(x) - p(f(x) - f(y))

Then we have h(0) = f(y) - f(x) ≥ 0 and h(1) = f(x) - f(x) = 0.

Moreover, h is differentiable, since f is differentiable, and we have:

h'(p) = ∇\(f(px + (1-p)y)^T\) (x - y)

= \((x - y)^T\) ∇f(px + (1-p)y)

= \((x - y)^T\) [f(px + (1-p)y) - f(x)]

= \((x - y)^T\) [f(px + (1-p)y) - f(px) + f(px) - f(x)]

= \((x - y)^T\) [f(px + (1-p)y) - f(px)] + \((y - x)^T\) [f(px) - f(x)]

= p\((x - y)^T\) ∇f(px) + (1-p)\((y - x)^T\) ∇f(py)

= p\((x - y)^T\) ∇² f(px)(x - y) + (1-p)\((y - x)^T\) ∇² f(py)(y - x)

where the last equality follows from the mean value theorem for differentiation.

Since f is m-strongly convex, we have ∇² f(x) ≥ mI for all x ∈ \(R^n\), where I is the n x n identity matrix. Therefore,

h'(p) ≥ \(p(x - y)^T\) mI(x - y) + (1-p)\((y - x)^T\) mI(y - x)

= m||px + (1-p)y - x||² - m||px - x||² - m||(1-p)y - x||²

= m||px + (1-p)y - x||² - mp²||x||² - m(1-p)²||y||²

= m[p²||x||² - 2p||x||² + ||px + (1-p)y||²] + m[(1-p)²||y||² - 2(1-p)||y||² + ||px + (1-p)y||²]

= m[||px + (1-p)y||² - 2p||x||² - 2(1-p)||y||²]

= m[||px + (1-p)y||² - p²||x||² - (1-p)²||y||²]

= m[||px + (1-p)y||²]

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Solve for N. 5/3 = N/12​

Answers

Answer:

N = 20

Step-by-step explanation:

5/3 = 1 2/3

20/12 = 1 8/20

They are equivalent

N = 20

You get the answer by simplifying both sides of the equation, then isolating the variable.

Hope this helps! :))

Please look at the pic and help!!

Please look at the pic and help!!

Answers

Answer:

4x² + 22x - 12

Step-by-step explanation:

A = bh/2

A = (4x - 2)(2x + 12)/2

A = (8x² + 48x - 4x - 24)/2

A = (8x² + 44x - 24)/2

A = 4x² + 22x - 12

There are 130 people in a sport centre. 76 people use the gym. 60 people use the swimming pool. 32 people use the track. 23 people use the gym and the pool. 8 people use the pool and the track. 20 people use the gym and the track. 6 people use all three facilities. A person is selected at random. What is the probability that this person uses at least 2 facilities?

Answers

Answer:

64

Step-by-step explanation:

Answer:

64

Step-by-step explanation:

Farhan has three pieces of rope with lengths of 140cm, 168cm and 210cm. He wishes to cut all the three pieces of ropes into smaller pieces of equal length and that there is no leftover rope. (i) What is the greatest possible length of each of the smaller pieces of rope? How many smaller pieces of rope can he get altogether?
give correct answer

Answers

Answer:

The greatest possible length is 14 cm.

The total number of smaller pieces is 37.

Step-by-step explanation:

The greatest common factor of these three numbers is 14.

Total number of smaller pieces = 10+12+15 = 37

Best Regards!

Given z, find |z|.

z=-2-6i

Given z, find |z|.z=-2-6i

Answers

Answer:

\( \Large{\boxed{\sf | \sf z| = \sf \sqrt{40} = 2\sqrt{10} }} \)

\( \\ \)

Explanation:

We are given a complex number in algebraic form, and we would like to find its modulus, |z|.

\( \\ \\ \)

Modulus of a complex number

\( \\ \\ \)

Let's recall that a complex number in algebraic form is written as \( \sf z = a + ib \) , where a is its real part and b is its imaginary part.

\( \\ \)

The modulus of said complex number is calculated as follows:

\( \sf | \sf z| = \sqrt{a^2 + b^2} \)

\( \\ \)

\( \hrulefill \)

\( \\ \)

Let's identify our values:

\( \sf z = -2 - 6i \Longleftrightarrow z = \underbrace{\sf -2}_{\sf a} + (\underbrace{\sf -6}_{\sf b})i \)

\( \\ \)

Now, substitute these values into our formula:

\( \sf | \sf z | = \sqrt{(-2)^2 + (-6)^2} = \sqrt{4 + 36} = \boxed{\sf \sqrt{40}} \)

\( \\ \)

While this may be optional, the result can be simplified by using the following property:

\(\green{\begin{gathered}\begin{gathered} \\ \boxed { \begin{array}{c c} \\ \blue{ \star \: \sf{\boxed{ \sf Product \: rule \: of \: square \: roots\text{:}}}} \\ \\ \sf{ \diamond \: \sqrt{ab} = \sqrt{a} \times \sqrt{b} } \\ \end{array}}\\\end{gathered} \end{gathered}}\)

\( \\ \)

\( \sf \sqrt{40} = \sqrt{4 \cdot 10} = \sqrt{4} \cdot \sqrt{10} = \boxed{\boxed{\sf 2\sqrt{10}}} \)

\( \\ \)

\( \hrulefill \)

\( \\ \)

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Help me plz i can't figure this out

Help me plz i can't figure this out

Answers

Answer:

C

Step-by-step explanation:

For C the y axis changes, add 5 to -3 and you get 2. Therefore 5 units away!

Hope this helps, good luck! :)

A basketball roster is shown in the table.

A 4-column table with 7 rows titled Basketball Roster. Column 1 is labeled Player with entries Adams, Brock, Cup, Dennis, Early, Finn, Graham. Column 2 is labeled Grade with entries 11, 12, 11, 10, 12, 11, 12. Column 3 is labeled Position with entries G, F, F, G, C, F, G. Column 4 is labeled height with entries 5 foot 6, 5 foot 8, 5 foot 9, 5 foot 3, 5 foot 11, 5 foot 9, 5 foot 5.

Which variable would be classified as a continuous quantitative variable?

grade
height
player name
position

Answers

Using variable concepts, it is found that the player's height is a continuous quantitative variable.

What are continuous and discrete variables?Continuous variables: Can assume decimal values.Discrete variables: Assume only countable values, such as 0, 1, 2, 3, ...

What are qualitative and quantitative variables?Qualitative variables: Assumes labels or ranks.Quantitative variables: Assume numerical values.

In this problem:

The player name and position are qualitative variables.Grade assumes only integer values, hence it is discrete.The height is quantitative, assuming decimal values in inches, hence it is also continuous.

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Answer:

height

Step-by-step explanation:

noballz

2Find the equation of the line thatis perpendicular to y = –x and3contains the point (4,-8).y =x + [

2Find the equation of the line thatis perpendicular to y = x and3contains the point (4,-8).y =x + [

Answers

A line perpendicular to the given line should have a slope which is a negative reciprocal of the given slope.

In the given, the slope is -2/3. Thus, the new slope should be m=3/2.

To obtain the line with the slope 3/2 and passes through (4,-8), substitute the value of the slope and the coordinates into the point-slope formula and then simplify the right side of the equation.

\(\begin{gathered} y=m(x-x_1)+y_1 \\ y=\frac{3}{2}(x-4)+(-8) \\ y=\frac{3}{2}(x-4)-8 \\ y=\frac{3}{2}x-6-8 \\ y=\frac{3}{2}x-14 \end{gathered}\)

Thus, the values for the blanks should be 3, 2, and -14, respectively.

I need help solving number 4 I have a test tomorrow and this is a review

I need help solving number 4 I have a test tomorrow and this is a review

Answers

We will have the following:

Right away we can see that if we are to plug in x = 35 in one of the expressions, the only one that would give as solution y = 1 is the solution; thus, the solution is the function:

\(y=\frac{1}{35}x\)

0.00000124 as a power of 10

Answers

The scientific notation of the given number is 1.24×10⁻⁶.

The given number is 0.00000124.

Scientific notation is a method for expressing a given quantity as a number having significant digits necessary for a specified degree of accuracy, multiplied by 10 to the appropriate power such as 1.56×10⁷.

Here, 0.00000124=1.24×10⁻⁶.

Therefore, the Scientific notation of the given number is 1.24×10⁻⁶.

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When driving the 9 hour trip home, Sharon drove 390 miles on the interstate and 150 miles on country roads. Her speed on the interstate was 15 mph more than on country roads. What was her speed on country roads? Set up a rational equation and solve.

Answers

Answer:

Speed of Sharon on country roads = 50 mph

Step-by-step explanation:

Let the speed of Sharon on interstate roads was = a mph

And the speed on country roads = b mph

Time taken by Sharon to travel 390 miles on interstate = \(\frac{\text{Distance}}{\text{Speed}}\)

= \(\frac{390}{a}\) hours

Time taken by Sharon to travel 150 miles on country roads = \(\frac{150}{b}\) hours

"Total time for the trip = 9 hours"

\(\frac{390}{a}+\frac{150}{b}=9\)

\(\frac{130}{a}+\frac{50}{b}=3\) --------(1)

"Her speed on interstate was 15 mph more than on country roads".

a = b + 15 ---------(2)

By substituting the value of a from equation (2) to equation (1),

\(\frac{130}{(b+15)}+\frac{50}{b}=3\)

\(\frac{130b+50(b+15)}{b(b+15)}=3\)

180b + 750 = 3b(b + 15)

180b + 750 = 3b² + 45b

3b² + 45b - 180b - 750 = 0

3b² - 135b - 750 = 0

b² - 45b - 250 = 0

b² - 50b + 5b - 250 = 0

b(b - 50) + 5(b - 50) = 0

(b + 5)(b - 50) = 0

b = -5, 50

But the speed can't be negative,

Therefore, b = 50 mph

Speed of Sharon on country roads was 50 mph.

Find each angle measure

Find each angle measure

Answers

Answer:

12.   m∠C = 100° and m∠F = 100°

13.   m∠S = 89° and m∠U = 89°

Step-by-step explanation:

Question 12

The two triangles ΔABC and ΔDEF have two of their angles equal:
m ∠A = m ∠D

m∠B = m∠E

Therefore the third angles must be equal:
m∠C = m∠F

m∠C = (4x²)° and m∠F = (3x² + 25)°

Setting these two right side expressions in parentheses equal to each other gives
4x² = 3x² + 25
4x² - 3x² = 25
x² = 25
x = ±√25 = ±5

Ignoring the negative value we get
x = 5

Therefore
m∠C = (4x²)° = (4 · 5²)° = (4 · 25)° = 100°

Since, m∠F = m∠C ,
m∠F  = 100°

But we can double check
m∠F = (3x² + 25)° = (3 · 5² + 25)° = (3 · 25 + 25) = (75 + 25)° = 100°

Question 13

This is similar to question 12

The quadrilateral RSTU is divided into two triangles ΔRST and Δ RUT

We are given
m∠RTS = m∠TRU

m∠TRS = m∠RTU

Therefore the third angle of ΔRST must be equal to the third angle of Δ RUT

In other words,
m∠S= m∠U

Plugging in the expressions for each of these angles we get

(5x - 11)° = (4x + 9)°

Set the expressions inside parens equal to each other and solve for x:
5x - 11 = 4x + 9

5x - 4x - 11 = 9    (subtract 4x from both sides)
x - 11 = 9

x = 11 + 9  (add 11 both sides)

x = 20

m∠S= (4x + 9)° = (4 · 20 + 9)° = (80 + 9)° = 89°

Therefore m∠RUT is also 89°

but we can double-check
m∠U= (5x - 11)° = (5 · 20 - 11)° = (100 - 11)° = 89°

Find the equation of the line
Use exact numbers

Find the equation of the lineUse exact numbers

Answers

Answer:

  y = (1)x +(-5)

Step-by-step explanation:

You want the slope-intercept equation of the line graphed with y-intercept -5 and x-intercept +5.

Intercept form

The intercept form of the equation for a line with x-intercept 'a' and y-intercept 'b' is ...

  x/a +y/b = 1

Using the given intercept values, a=5, b=-5, the equation is ...

  x/5 +y/(-5) = 1

Slope-intercept form

The desired form of the equation can be found by solving for y:

  -x +y = -5 . . . . . . multiply by -5

  y = x -5 . . . . . . . . add x

The numbers that go in the boxes are 1 and -5.


Los organizadores de la Feria de Alimentos colocan un contenedor de agua que mide 2,76 metros de largo, por 23,5 decímetros de ancho y por 196 centímetros de alto. ¿Cuál es el volumen del contenedor? Expresa la respuesta en metros cúbicos con aproximación a centésimos.

Answers

The volume of the container is approximately 12.9516 cubic meters when rounded to the nearest hundredth.

To find the volume of the container, we need to multiply its length, width, and height. Let's convert the given measurements to meters to ensure consistent units.

The length of the container is 2.76 meters.

The width of the container is 23.5 decimeters, which is equal to 2.35 meters (since 1 decimeter = 0.1 meters).

The height of the container is 196 centimeters, which is equal to 1.96 meters (since 1 meter = 100 centimeters).

Now we can calculate the volume of the container:

Volume = Length × Width × Height

Volume = 2.76 meters × 2.35 meters × 1.96 meters

Volume ≈ 12.9516 cubic meters (rounded to four decimal places)

Therefore, the volume of the container is approximately 12.9516 cubic meters when rounded to the nearest hundredth.

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2, 202, 402, 602 what is the common difference

Answers

-2

Step-by-step explanation:

The difference between second term and first term or third term and second term in an AP series is called common difference.

Hence, in the given sequence −2,−4,−6,......, the common difference is −4−(−2)=

What is cos(tan^-1(-2/3))=

Answers

cos(tan^(-1)(-2/3)) simplifies to 3√13 / 13.

To evaluate the expression cos(tan^(-1)(-2/3)), we can use the trigonometric identity:

cos(tan^(-1)(x)) = 1 / √(1 + x^2)

In this case, x is -2/3. Substituting the value into the identity:

cos(tan^(-1)(-2/3)) = 1 / √(1 + (-2/3)^2)

Now, let's calculate the value:

cos(tan^(-1)(-2/3)) = 1 / √(1 + 4/9)

                   = 1 / √(13/9)

                   = 1 / (√13/3)

                   = 3 / √13

                   = 3√13 / 13

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a customer buys one abc may 60 call at 6 and sells one abc may 17th call at 3 when abc stock is selling at 63%

Answers

the maximum potential loss for this strategy is limited to the net cost of $3 if the stock price stays below the breakeven point of $63, but can be unlimited if the stock price rises significantly above the breakeven point

The maximum potential loss for this strategy can be calculated as the difference between the premiums received and paid. In this case, the customer pays a premium of $6 to buy the ABC May 60 call and receives a premium of $3 for selling the ABC May 17th call. Hence, the total cost for this strategy is $6 - $3 = $3.

 

The breakeven point for this strategy can be calculated as the strike price of the long call plus the net cost of the strategy, which is $60 + $3 = $63.

If the ABC stock price stays below the breakeven point of $63, both options will expire worthless, and the maximum loss for this strategy will be the net cost of $3.

However, if the ABC stock price rises above the breakeven point of $63, the short call option that was sold will be in the money, and the buyer of the option can exercise it, forcing the seller to sell the shares at the strike price of $17. This means that the maximum loss for this strategy will be unlimited if the stock price rises significantly above the breakeven point.

In summary, the maximum potential loss for this strategy is limited to the net cost of $3 if the stock price stays below the breakeven point of $63, but can be unlimited if the stock price rises significantly above the breakeven point. Therefore, it's important to have a risk management plan in place to mitigate potential losses in case the stock price moves against the expected direction.

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a customer buys one abc may 60 call at 6 and sells one abc may 17th call at 3 when abc stock is selling at 63% the maximum potential loss is?

2/5 of employees in a company drive to work, 1/3 travel by bus and the rest walk. 1. Find the fraction of who walk.

Answers

Answer:

4/15

Step-by-step explanation:

2/5 drive

1/3 bus

and rest walk

fraction of those who walk is 1-(2/5+1/3)

2/5+1/3=(6+5)/15=11/15

15/15-11/15=4/15

Find the length in each isosceles right triangle.


a. Find the leg if the hypotenuse is 102√



Leg =


b. Find the hypotenuse if the leg is 92√


Hypotenuse =

(33 points)

Answers

The answer of the given question based on the  length in each isosceles right triangle is given below,

What is Isosceles right triangle?

An isosceles right triangle is right triangle in which two legs have the same length, making it isosceles triangle, and one of angles is right angle, making it right triangle.  an isosceles right triangle,  two acute angles are congruent, each measuring 45 degrees, and  hypotenuse is equal in length to legs multiplied by √2.

The isosceles right triangle is special case of  45-45-90 triangle, where  angles measure 45 degrees, 45 degrees, and 90 degrees, respectively. In  45-45-90 triangle, the hypotenuse is equal in length to  legs multiplied by √2.

a. If the hypotenuse is 102√, then each leg is the same length as the hypotenuse divided by √2. Therefore:

Leg = 102√/√2 = 102

b. If one leg is 92√, then the hypotenuse is the length of that leg multiplied by √2. Therefore:

Hypotenuse = 92√ * √2 = 92 * 2 = 184.

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Adam tabulated the values for the average speed on each day of his road trip as 60.5, 63.2, 54.7, 51.6, 72.3, 70.7, 67.2, and 65.4 mph. If Adam wanted to construct a one-sample t-statistic, what would the value for the degrees of freedom be?

Answers

Answer:

7

Step-by-step explanation:

Given the following data:

Average speed : 60.5, 63.2, 54.7, 51.6, 72.3, 70.7, 67.2, and 65.4

To construct a one-sample t - statistic, the value of the degree of freedom will be ;

In a one sample test of known mean, if the number of observations are 4, one can choose to vary at most three of the observations and still obtain the mean, that is the 4th observation must remain fixed.

Degree of freedom = Number of observations (n) - 1. This is the maximum number of independent variables which can be varied.

Nunber of observations or sample size in the data above is 8

Hence,

Degree of freedom = (8 - 1) = 7

Answer:the anwser is 7

Step-by-step explanation:

I need help finding the Single equivalent discount rate, Trade discount, and Net price.​

I need help finding the Single equivalent discount rate, Trade discount, and Net price.

Answers

1) The Single Equivalent Discount Rate is 0.143296.

2) The trade discount is $28.52.

3) The net price is $170.48.

What is a chain discount?

A chain discount refers to a series of discounts allowed from the list price of a good.

An example of a chain discount is 8/4/3.  Based on the series of discounts, a single equivalent discount rate can be computed as below.

The net price is the difference between the list price and the trade discounts granted.

Data and Calculations:

Item            List     Chain     Net Price       Single        Trade         Net Price

                 Price Discount  Equivalent  Equivalent  Discounts

                                                    Discount rate

Samsung  $199    8/4/3      0.856704   0.143296     $28.52         $170.48

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The single equivalent discount rate = 0.143296 (1 - 0.856704)

Trade discount = $28.52 ($199 x 0.143296)

Net Price = $170.48 (($199 x 0.856704)

Single Equivalent Discount Rate:

100 x 8% = 8%

92 x 4% = 3.68%

88 x 3% = 2.64%

Total = 14.32%

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Solve using tangent to find x

Solve using tangent to find x

Answers

\(\tan(28^o )=\cfrac{\stackrel{opposite}{21}}{\underset{adjacent}{x}} \implies x=\cfrac{21}{\tan(28^o)}\implies x\approx 39.50\)

Make sure your calculator is in Degree mode.

What is 10 times larger than the 7 in this number 16372

Answers

Answer:

700

Step-by-step explanation:

I am slightly confused by your wording, but Im assuming you mean the expanded form.

In the base ten system, the second to last digit is the tens place. Therefore, the 7 represents 7*10 = 70

10 times larger than 70 is 700

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