Under what conditions will a moving 0.030 kg marble and a moving 2.43 kg rock have the same kinetic energy

Answer:

When a load resistance is connected, current flows through the cell and a voltage develops across the internal resistance. This voltage is not available to the circuit so it is called the lost volts, .

Explanation:

Answer:

Induced emf = 0

Explanation:

An emf can be induced due to the change in magnetic field. It can be given by :

\(\epsilon=\dfrac{d\phi}{dt}\\\\\because \phi=BA\cos\theta\\\\\epsilon=\dfrac{d(BA\cos\theta)}{dt}\\\\\epsilon=A\cos\theta\dfrac{dB}{dt}\)

As the loop is placed perpendicular to a uniform magnetic field of 1 Tesla. It means that \(\theta=90^{\circ}\) and cos(90) = 0. Hence, the induced emf is equal to 0.

Louis Armstrong's average velocity in the time trial was approximately 1.078 km/min.

To calculate the average velocity, divide the total displacement by the total time taken. In this case, Louis Armstrong rode his bike 55 km to the east in a time trial lasting 51 minutes.

Average Velocity = Displacement / Time

Displacement = 55 km (since he rode 55 km to the east)

Time = 51 minutes

Average Velocity = 55 km / 51 min

To express the average velocity in km/min, convert the time from minutes to minutes.

1 hour = 60 minutes

Average Velocity = 55 km / 51 min × (1 hour / 60 min)

Average Velocity = 55 km / 51 min × (1/60) hour

Simplifying the expression:

Average Velocity = 1.078 km/min

Therefore, Louis Armstrong's average velocity in the time trial was approximately 1.078 km/min.

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Answer:17m/s

Explanation:

In this question we use first law of motion which is

vf=vi+at

By putting values

vf=32+10×-1.5

vf=17m/s

Answer:

yeah its 17m/s

Explanation:

Answer:

a . Long wavelengths and low frequencies

Explanation:

Low energy waves usually show long wavelengths and a low frequency.

Energy of a wave is dependent on the wavelength and frequency of such a wave.  

   The wavelength of a wave is the distance between successive crests and troughs of a wave. The frequency of a wave is the number of waves that passes through a particular point per unit of time.

  Mathematically, wave energy;

               Energy  = h x f

 where h is the planck's constant

             f is the frequency

 Also,

              Energy  = \(\frac{h x speed of light}{wavelength}\)

 A high energy wave will have a high frequency and a long wavelength.

 A low energy wave have a low frequency and a long wavelength

Answer:

Name and describe at least SIX engineering challenges that the Mars copter, Ingenuity, had to overcome in order to be built/to travel to Mars/to function on Mars. BE SPECIFIC with your answers!!

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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The criteria for evaluating the following sentence are as follows: Although the claim is true, the explanation is false.

Using straightforward, honest, acceptable, and highly respectful language to communicate your opinions, feelings, and preferences is known as assertion. "I can't hear the movie while you speak. kindly lower your voice." "When you wear that clothing, I really like it. You look wonderful!"

To guarantee that fiscal records & disclosures are accurate and suitable, assertions are qualities that need to be evaluated. Financial statements are correctly reported when all assertions for pertinent transactions or balances are met.

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Answer:

lowers :)

Explanation:

The speed of the ambulance is 33.35 m/s and the frequency heard after the ambulance passes is 667.07 Hz.

Calculation:-

V = f(344 - 15.6/344 - vs)

740 = 700(344 - 15.6/344 - vs)

344 - V s = 70/74 (344 - 15.6)

344 - V s = 310.64

  V s = 33.35 m/s

After pass

F = 700 ( 344 + 15.6/344 + 33.35)

   = 700 × 359.6/377.35

 F = 667.07 Hz

Frequency is the wide variety of occurrences of a repeating event in line with a unit of time. The time period frequency refers to the variety of waves that pass a set factor in unit time. It additionally describes the number of cycles or vibrations undergone for the duration of one unit of time with the aid of a body in periodic motion.

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The buoyant force can be determined by subtracting the apparent weight of the object in water from its weight in air. In this case, the buoyant force would be 7N - 4N = 3N.

Based on the information provided, since the buoyant force (3N) is less than the weight of the object (7N), the object will not float.

Floating occurs when the buoyant force is greater than or equal to the weight of the object.

In this scenario, the object will experience a net downward force, indicating that it will sink rather than float in water.

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For the pair of fuzzy dice hanging by a string from the rearview mirror, while accelerating from a stop-light to 28 m/s in 6.0 s, the string makes an angle of 25.5 degrees with the vertical.

An angle is the figure formed by two rays, called the sides of the angle, sharing a common endpoint, called the vertex of the angle.

Parameters given include:

velocity: 28,/s time= 6.0 seconds

a = v/t = 28m/s / 6.0s = 4.667 m/s²

Taking into account the forces acting on the dice...there is a force of gravity acting straight down with a magnitude of mg.

so we have that

Angle = tan-1(a/g)

Angle = tan-1(4.667 / 9.8) =  25.5 degrees.

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For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:

a. The volume is 24 m³.

b. weight is 240,000 N,

c. mass is 24,490 kg, and

d. pressure is 23,530 Pa.

a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:

Volume = Length x Width x Depth

Given:

Length = 4 m

Width = 3 m

Depth = 2 m

Substituting the values into the formula, we have:

Volume = 4 m x 3 m x 2 m

Volume = 24 m³

Therefore, the volume of paraffin in the tank is 24 cubic meters.

b) The weight of the paraffin can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:

Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²

Weight = 240,000 N

Therefore, the weight of the paraffin in the tank is 240,000 Newtons.

c) The mass of the paraffin can be calculated using the formula:

Mass = Density x Volume

Substituting the given values:

Mass = 10,000 kg/m³ x 24 m³

Mass = 24,490 kg

Therefore, the mass of the paraffin in the tank is 24,490 kilograms.

d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:

Pressure = Weight / Area

The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:

Area = 4 m x 3 m

Area = 12 m²

Pressure = 240,000 N / 12 m²

Pressure = 20,000 Pa

Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).

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The length of wire whose resistivity is 3 x 10^-6ohm, and radius is 0.2 mm, with a given value of 15.552 resistance is 6.5268 m.

Given data: r = 0.2 mm = 0.2 x 10^-3m Resistivity = 3 x 10^-6 ohm R = 15.552 ohm

Formula Used: Resistivity (ρ) = (RA)/L

Where, R is resistance, A is the area of cross-section, L is the length of the wire.

Resistance (R) = ρ (L/A)

Multiplying A on both sides, we get

Resistance (R) x A = ρ L ... equation (1)

Area of the cross-section of a wire of radius (r) is given by, A = πr^2

where, π is a constant whose value is 3.14

Substituting the given values, we get

A = πr^2= π (0.2 x 10^-3m)^2= 1.2566 x 10^-7 m^2

Substituting the values of R, A and ρ in equation (1), we get

Length of wire (L) = (Resistance x Area) / Resistivity= (15.552 ohm x 1.2566 x 10^-7 m^2) / (3 x 10^-6 ohm)= 6.5268 m

Therefore, the length of wire whose resistivity is 3 x 10^-6ohm, and radius is 0.2 mm, with a given value of 15.552 resistance is 6.5268 m.

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The efficiency of the engine is 17%.

Given the following data:

To find the efficiency of the engine:

Mathematically, the efficiency of an engine is calculated by using the formula:

\(Efficiency = \frac{E_O}{E_I}\) × \(100\)

Where:

Substituting the given parameters into the formula, we have;

\(Efficiency = \frac{201}{1176}\) × \(100\)

\(Efficiency = 0.171\) × \(100\)

Efficiency = 17%

Therefore, the efficiency of the engine is 17%.

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Heat emitted from a candle, Microwaves from a microwave oven, Radio waves transmitted between towers, Sound waves from a car radio.

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Answer:

I believe the answer is D) 4

Explanation:

Subduction is the sideways and downward movement of the edge of a plate of the earth's crust into the mantle beneath another plate.

Answer: point 4

Explanation:

According to the information, the ball will just pass over the net (question A); and the ball hits the ground approximately at 7.04 meters from the player and after a time of flight of approximately 1.31 seconds (question B).

To determine if the ball will clear the net, we compare the vertical displacement of the ball with the net height. The ball's initial height is 1.1 meters, and it reaches its highest point during flight. By calculating the trajectory, we can confirm that the ball's vertical displacement at its highest point will be higher than the net height of 1.81 meters, ensuring it clears the net.

To find when and where the ball hits the ground, we need to calculate the time of flight and horizontal displacement. Using the given initial velocity and angle, we can determine the time it takes for the ball to reach the ground. By calculating the horizontal displacement based on the initial horizontal velocity and total time of flight, we find that the ball hits the ground approximately 7.04 meters from the player. The time of flight is approximately 1.31 seconds. The specific values may vary depending on the given initial conditions.

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The power used, given that a force of 20 N is used to push the shopping cart 3.5 m in 2 seconds is 35 W

First, we shall determine the work done in pushing the cart. Details below:

Wd = Fd

Wd = 20 × 3.5

Wd = 70 J

Finally, we shall determine the power used in pushing the cart. Details below:

P = Wd / t

P = 70 / 2

P = 35 W

Thus, we can conclude that the power used is 35 W

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The pressure of the gas in the deodorant can when it is heated to 900 K is 9 atm.

Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.

It is expressed as;

P₁/T₁ = P₂/T₂

From the data:

We substitute our values into the expression above and solve for final pressure.

P₁/T₁ = P₂/T₂

P₁T₂ = P₂T₁

P₂ = P₁T₂  / T₁

P₂ = ( 3 atm × 900 K ) / 300 K

P₂ = 9.0 atm

Therefore, the final pressure is 9.0 atm.

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The efficiency of motor is 90.58%.To determine the efficiency of the motor, we need to calculate the input power and the output power, and then divide the output power by the input power

The input power can be calculated using the formula:

Input Power = Voltage × Current

Given that the voltage is 230 V and the current is 24 A, we have:

Input Power = 230 V × 24 A

Input Power = 5520 W (or 5.52 kW)

The output power of the motor is given as 5 kW (since it is a 5 kW motor).

Now, we can calculate the efficiency:

Efficiency = (Output Power / Input Power) × 100%

Efficiency = (5 kW / 5.52 kW) × 100%

Efficiency ≈ 90.58%

Therefore, the efficiency of this motor is approximately 90.58%.

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The equation for r can be written as, r = k e²/ m( n h/ 2π r)².

The Bohr model shows atom as a central nucleus containing protons and neutrons with the electrons in circular orbitals at specific distances from  nucleus. Angular momentum of an electron by Bohr is given by m v r or n h/2π ( v is the velocity, n is orbit in which electron is revolving, m is mass of electron, and r is  radius of nth orbit).

Given, m v r= n h/2π

So, v= n h/ 2π m r

substitute this value of v in mv²/r= k e²/r²(given)

So, r= m( n h/ 2π m r)/r = k e²/r²

r = k e²/ m( n h/ 2π r)²

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Since the box rests on the table, net force is zero, both forces are balanced.

Those forces are:

The Gravitational force that points downwards, (weight)

The normal force that reacts to the gravitational force.

Answers:

Normal force

Gravitational force

At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.

The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:

vrms = √(3kT/m)

Where:

vrms is the rms speed

k is the Boltzmann constant (1.38 x 10^-23 J/K)

T is the temperature in Kelvin

m is the molar mass of the gas in kilograms

To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:

m = 16 g/mol = 0.016 kg/mol

Substituting the values into the formula, we have:

vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))

Calculating this expression yields the rms speed of the oxygen sample:

vrms ≈ 482.34 m/s

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Answer:

That people are motivated by a series of five universal needs.

Explanation:

Answer: i don’t know the answer but

Explanation:

Divide the distance by the speed. That gives the travel time.

t = d/v = (4200 km) / (800 km/hr) = ? hrs

Answer:

In short no , there is always minimum 2 forces.

Explanation:

First force: Weight force ( The force of gravity on the object attracting the block of masse m to earth)

Second force: Normal reaction ( This force is perpendicular to the surface )

Answer:

no

Explanation:

if only single force acts on the block it will stay at rest and it will accelarate in direction of force

Answer:

the mass of the air in the classroom = 2322 kg

Explanation:

given:

A classroom is about 3 meters high, 20 meters wide and 30 meters long.

If the density of air is 1.29 kg/m3

find:

what is the mass of the air in the classroom?

density = mass / volume

where mass (m) = 1.29 kg/m³

volume = 3m x 20m x 30m = 1800 m³

plugin values into the formula

  1.29 kg/m³   =        mass    

                             1800 m³

mass =  1.29 kg/m³  ( 1800 m³ )

mass = 2322 kg

therefore,

the mass of the air in the classroom = 2322 kg

If A classroom is about 3 meters high, 20 meters wide and 30 meters long. If the density of air is 1.29 kg/m3, then the mass of the air in the classroom is 2322Kg.

Density is the ratio of mass to volume. it tells how much mass a body is having for its unit volume. for example egg yolk has 1027kg/m³ of density, means if we collect numbers of egg yolk and keep it in a container having volume 1 m³ then total amount of mass it is having will be 1027kg. Density is a scalar quantity. when we add egg yolk into the water, egg yolk has greater density than water( 997 kg/m³), because of higher density of egg yolk it contains higher mass in same volume as water. hence due to higher mass higher gravitational force is acting on the egg yolk therefore it goes down on the inside the water. water will float upon the egg yolk. same situation we have seen when we spread oil in the water. ( in that case water has higher density than oil. thats why oil floats on the water).

Given,

Height = 3 m

Width = 20 m

length= 30 m

Density of air = 1.29kg/m³

The  volume of the room = 3×20×30 m³

Volume V = 1800m³

By formula,

Density = Mass/Volume

1.29kg/m³ = Mass/1800m³

Mass of the air = 1.29×1800 = 2322 Kg

The mass of the air is classroom is 2322Kg.

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