Under electrostatic conditions, the electric field inside a solid conductor points towards the surface of the conductor.

Answer:

I think C radiation only

Answer:

Electronics (mainly), discovery of quantum mechanics, transistors, element properties, etc.

Explanation:

Great question. I think that it's widely agreed upon that the existence of handheld gadgets, as well as most electronics such as these, came from the advent of quantum mechanics (QM). Quantum mechanics allowed us to look at the behavior of electrons, as they are different from everyday objects. You can think of QM at the interface of chemistry and physics. Quantum mechanics is important, considering it predicts how electrons have to flow through your phone. This was especially helpful in determining their behavior regarding solid materials like the ones that make up your phone. Also, there are several materials that go into a phone, among these certain elements, such as silicon (a semiconductor) and copper/silver, which are great at conducting electrons. Eventually we started using things called transistors, which can amplify and switch electronic signals when needed. These can thought to be a direct product of QM. There are also all kinds of diodes and things that can emit light, among other things.

Also, you have to get the electricity from somewhere, and that can come from a controlled chemical reaction that you can charge right in your phone! That is basically what a battery does, it converts chemical energy (using chemical reactions) into electrical energy that powers your phone. So in short, electronics, chemistry of materials (governed by physics) and especially understanding of how electrons work with tiny transistors in your phone come together to even show you this answer. Wow.

The deceleration experienced by the 1075 N sky diver as he opened his parachute is 13.39 m/s²

Force = mass × acceleration

We know that deceleration is the acceleration of stopping objects. Thus,

Force (F) = mass (m) × deceleration (a)

Thus, we can obtain the deceleration of the sky diver as follow:

Force = mass (m) × deceleration (a)

1469 = 109.69 × a

Divide both sides by 109.69

a = 1469 / 109.69

a = 13.39 m/s²

Thus, the deceleration is 13.39 m/s²

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Answer:

A) R = 190.42 Ω

B) P = 5.325 W

Explanation:

We are given;

Total power;P_tot = 7.1 W

Voltage;V = 26 V

A)We are told that while the battery is still connected, one of the resistors is heated, so that its resistance doubles.

Thus, the power is doubled.

Now, formula for power is;

P = IV

Thus, since power is doubled, we have;

P = 2(IV)

Now, formula for current is; I = V/R

So, P = 2V²/R

Making R the subject, we have;

R = 2V²/P

In this question, P is p_total = 7.1 W

Thus;

R = (2 × 26²)/7.1

R = 190.42 Ω

B) Now, the resistance of the resistors are R and 2R.

Formula for power in this context is;

P = V²/R

Thus,

Total power delivered to the resistors is;

P = V²/R + V²/2R

P = 3V²/2R

P = (3 × 26²)/(2 × 190.42)

P = 5.325 W

The force of gravity between these pairs of objects: a 1-kg mass and a 2-kg mass that are 1 m apart is 13.\(10^{-11}\)34N.

For  2 m apart 6.67\(10^{-11}\)N.

For 2-kg mass that are 2 m apart; and two 2-kg masses that are 1 m apart is 26.68N.

The resultant (vector sum) of two forces is the force of gravity on Earth: (a) the gravitational pull according to Newton's universal law of gravitation; and (b) the centrifugal force, which is the outcome of choosing an earthbound, rotating frame of reference.

Force between two object is calculated f=Gmm/r^2.

G=6,67*10^-7

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The maximum height reached by the baseball is 24.5 meters.

We can use the kinematic equation for the vertical motion:

h = vi*t + (1/2)at^2

where h is the maximum height reached by the baseball,

vi is the initial vertical velocity,

a is the acceleration due to gravity (-9.8 m/s^2),

and t is the time taken for the ball to reach its maximum height.

At the maximum height, the vertical velocity of the ball is zero. Therefore, we can write:

h = (1/2)at^2

We know that the total time for the baseball to travel to the outfield and return is 5 seconds, so the time taken to reach the maximum height is half of that or 2.5 seconds.

After substituting the values we know, we get:

h = (1/2)(-9.8 m/s^2)(2.5 s)^2

h = 24.5 meters

Therefore, the maximum height the baseball reached is approximately 24.5 meters.

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Answer:

okay I might be wrong but it was an answer i had in like fifth grade MAYBE 1,200 meters

Explanation:

Answer:

Her linear velocity (speed) is approximately 2.2 m/sec

Her angular velocity is approximately 1.26 rad/second

Explanation:

The given parameters are;

The diameter of the merry-go-round, d = 3.5 m

The number of revolutions she travels per minute = 12 revolutions per minute

Therefore, we have;

The distance she travels in one revolution =  π·d = π × 3.5 m

The distance of the twelve revolutions  = 12 × π × 3.5 m

The time she takes for the 12 revolutions = 1 minute = 60 seconds

Therefore, her speed = 12 × π × 3.5 m/(60 seconds)  ≈ 2.2 m/sec

Her angular velocity = Angle covered/Time = 12 × 2 × π/60 ≈ 1.26 rad/second.

The water outflow in 30 secs through 200 mm of the capillary tube is mathematically given as

\(Qo=1.6 \times 10^{2} \mathrm{~mL}\)

\(\begin{aligned}\Delta P &=6660 \mathrm{~m} / \mathrm{m}^{2} \\\mu &=8.01 \times 10^{-4} \text { Pas } \\t &=30 \mathrm{~s} \\L &=200 \mathrm{~mm}=200 \times 10^{-3} \mathrm{~m} \\D &=1.5 \mathrm{~mm}=1.5 \times 10^{-3} \mathrm{~m} \Rightarrow \gamma=\frac{1.5 \times 10^{-3}}{2} \mathrm{~m}\end{aligned}\)

Generally, the equation for Rate of flow of Liquid is  mathematically given as

\(\\$$Q=\frac{\pi r^{4} \times \Delta P}{8 \mu L}\)

$$

Where dP is pressure difference r is the radius

\(\mu\) is the viscosity of water

L is the length of the pipe

\(Q=\frac{\pi \times\left(\frac{1.5 \times 10^{-3}}{2}\right)^{4} \times 6660}{8 \times 8.01 \times 10^{-4} \times 200 \times 10^{-3}}\)

\(Q=5.2 \mathrm{~mL} / \mathrm{s}\)

In $30s the quantity that flows out of the tube

\(&Qo=5.2 \times 30 \\&Qo=1.6 \times 10^{2} \mathrm{~mL}\)

In conclusion, the quantity that flows out of the tube

\(Qo=1.6 \times 10^{2} \mathrm{~mL}\)

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Answer:

A.) Oxidation

Explanation:

:p

Hydrogen reacts with oxygen, hydrogen loses electrons. The term

applies to what happens to hydrogen in this reaction is

A. Oxidation

Oxidation is a process where a substance: Loses one or more electrons or gains an oxygen atom or we can say that oxidation is a process which involves the addition of oxygen or any electronegative element or the removal of hydrogen or any electropositive element.

Reduction is the gain of electrons or reduction is a process which involves the addition of hydrogen or any electropositive element or the removal of oxygen or any electronegative element.

A synthesis reaction is a type of reaction in which multiple reactants combine to form a single product. Synthesis reactions release energy in the form of heat and light, so they are exothermic.  

correct option is A. Oxidation

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A load cell is an essential sensor device used for converting a force, torque, pressure, or displacement into an electrical signal. It is a key component in electronic scales, force measuring instruments, and weighing devices. A student who designs an electric scooter uses a simple column type load cell with two strain gauges.

The load cell measures force or weight by converting the tension or compression acting on the load cell into an electrical signal. A load cell typically comprises four strain gauges that are arranged in a Wheatstone bridge configuration. A column type load cell is cylindrical in shape and is designed to measure loads in compression. It typically comprises two columns that are connected by a metal diaphragm. Two strain gauges are attached to the columns, one for measuring the compressive strain and the other for measuring the tensile strain.

The student designing an electric scooter uses a load cell to measure the weight of the rider and other loads on the scooter. The load cell is typically placed at the bottom of the scooter's frame, and the weight of the rider and the scooter is applied to it. The load cell measures the weight by converting the compression force acting on it into an electrical signal. The two strain gauges attached to the columns of the load cell measure the compressive and tensile strains, respectively. These strains are converted into an electrical signal using a Wheatstone bridge circuit, and the output of the bridge is proportional to the weight applied to the load cell.The student designing the electric scooter needs to select the right load cell for the application. The load cell must be able to measure the maximum weight that the scooter can carry. The column type load cell is suitable for measuring loads in compression, which is ideal for measuring the weight of the rider and the scooter. The two strain gauges attached to the columns of the load cell help to increase the sensitivity and accuracy of the load cell. The Wheatstone bridge circuit helps to convert the strain measurements into an electrical signal that can be processed by the scooter's control system.

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Answer:

La fuerza ejercida sobre el piso del elevador hacia abajo es aproximadamente 1,004.075 N

Explanation:

Fuerza = Masa × Aceleración

El peso de la caja = 800 N

La velocidad hacia abajo = 5.0 m / s

Tomando la aceleración debida a la gravedad, g = 9,8 m / s²

La masa del cuerpo, m = 800 N / g = 800 N / (9,8 m / s²) ≈ 81,63 kg

La fuerza ejercida sobre el piso del ascensor durante la aceleración hacia arriba, 'N', se da como sigue;

N = m · g + m · a

a = 2,5 m / s²

∴ N = 81,63 kg × 9,8 m / s² + 81,63 × 2,5 m / s² = 800 N + 81,63 × 2,5 m / s² ≈ 1,004,075 N

La fuerza ejercida sobre el piso del ascensor hacia abajo ≈ 1,004.075 N

Causes of Earthquake

An earthquake is caused by a sudden slip on a fault. The tectonic plates are always slowly moving, but they get stuck at their edges due to friction.

Five causes of earthquake?

1. Volcanic Eruptions. The main cause of the earthquake is volcanic eruptions.

2. Tectonic Movements. The surface of the earth consists of some plates, comprising of the upper mantle

3. Geological Faults

4. Groundwater extraction – decrease in pore pressure.

5. Groundwater – increase in pore pressure.

6. Heavy rain.

7. Pore fluid flow.

8. High CO2 pressure.

9. Building dams.

Explanation:

Now, Boundaries between tectonic plates are made up of faults. which are associated with the various types of fault, normal, reverse and strike-slip faults

More so, Plate boundaries are always faults, but not all faults are plate boundaries.

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The tension in the cable is approximately 11000 N (Newtons), expressed to three significant figures.

To calculate the tension in the cable, we need to consider the forces acting on the steel beam. The system is in equilibrium, which means the net torque on the beam is zero. We can set up a torque equation to find the tension T in the cable.
Let's denote the distance from the worker to the pivot point as x and the total length of the beam as L. In this case, x = 1.5 m and L = 6.0 m. The weight of the construction worker is W_worker = 74 kg * 9.81 m/s², and the weight of the steel beam is W_beam = 1450 kg * 9.81 m/s².
The torque equation is:
T * L = W_worker * x + W_beam * (L/2)
Now we can calculate the tension T in the cable:
T = (W_worker * x + W_beam * (L/2)) / L
Plug in the values:
T = ((74 kg * 9.81 m/s²) * 1.5 m + (1450 kg * 9.81 m/s²) * (6.0 m / 2)) / 6.0 m
T ≈ 11000 N
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Answer is c, they are equal:

Explanation:

Answer:

The answer is

Explanation:

The acceleration of an object given the force acting on the object and it's mass is given by

\(acceleration = \frac{force}{mass} \\ \)

From the question

net force = 18 N

mass = 450 kg

The acceleration is

\(acceleration = \frac{18}{450} = \frac{1}{25} \\ \)

We have the final answer as

Hope this helps you

Answer:

0.04 m/s²

Explanation:

The acceleration of an object given the force acting on the object and it's mass is given by

From the question

net force = 18 N

mass = 450 kg

The acceleration is

We have the final answer as

0.04 m/s²

1. There must have been tectonic activity, including active volcanoes, on the Moon.

A significant rock of the lunar highlands is called lunar anorthosite, which developed as a result of plagioclase flotation in the lunar magma ocean (LMO). A key to understanding the early magmatic history of the terrestrial planets is to place restrictions on the necessary circumstances that led to the creation of a thick pure anorthosite (mode of plagioclase >95 volume%). Plagioclase must have separated from the magma ocean with a low crystal percentage in order to produce pure lunar anorthosite.

The worldwide magma ocean and the formation of a hot, youthful Moon are both suggested by the massive impact theory for the genesis of the Moon. A floatation crust made of plagioclase crystals or anorthosite crust might result from such a magma ocean. Because they anticipated interstitial melt would freeze, early predictions of the projected anorthosite concentration of the lunar highlands crust did not match first observations of Apollo samples, and more subsequent calculations have not matched Clementine measurements or SELENE data. We examine a physical model of a magma ocean with an accumulating floatation lid and discover that, even when credible compaction viscosities are taken into account as a potential inhibitor, considerable melt escape is still possible for appropriate physical parameters and melt migration durations.

This model supports data by allowing more nearly pure lunar anorthosites. This suggests that impact mixing and tidal heating are required to account for the disparity. The model has considerable trouble describing the ejection of melt for the near-surface crust (up to five kilometers in depth).

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Answer:

9800N

Explanation:

Since it is falling freely, the only force on it is its weight, w. w = m ⋅ g = 1000kg ⋅ 9.8ms2 = 9800N

Answer:

a bus would have 12 meters

Answer:

A School Bus

Explanation:

Answer: 52 kj/gm

Explanation:

the heat of combustion of ethane, c2h6, is 1560 kj/mol. what is the heat of combustion of ethane, in kj per gram?

ethane is C2H6 and has a molecular mass of (2X12) + (6X1) = 30m

1 mole of ethane = 30 gmsso

1560 kj/moe = 1560 kj/30gm =

52 kj/gm

The power factor of zero leading in a circuit that is entirely capacitive, with the current 90 degrees ahead of the voltage.

An electric circuit's power source exerts pressure known as voltage on charged electrons (current), causing them to flow through a conducting loop and perform tasks like lighting a lamp. Voltage is measured by volts and is simply equal to pressure (V).

Voltage, commonly referred to as electromotive force, is merely the amount of energy contained in one charge. The difference of electric voltage between two places is what is referred to as voltage, in other words. Simple electric charge flow rate is known as current.

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The charge of a newly formed oxygen ion would be -2

Hope this helps :)

A.  scale reading in Newtons is 2250 N

B.  scale reading compared with his weight is 735.8 N

C. The final speed is too small for an elevator is unreasonable.

The given data is as follows:

Weight of person = 75kg

Acceleration = 30.0 m/s

Time period = 2.00 seconds

a. The scale reading in Newtons is calculated by using

F(net) = mass*acceleration

F(net) = 75kg * 30.0 m/s

F(net)  = 2250 N

b.  scale reading compared with his weight is calculated by using

Force(gravity) = m*g

Let's assume that g is the acceleration due to gravity - 9.8m/s^2

Force(gravity) = 75.0 * 9.81 m/s^2 = 735.8 N

The scale reading compared with the person's weight calculated by,

person's weight = 2250 N / 735.8 N = 3.06

C. UNREASONABLE option is:

The final speed is too small for an elevator. This is because elevators can get different speeds relying on their structure and purpose.

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Answer:

A. The range of A and B are equal.

Explanation:

Let u be the initial speed of both the projectile.

The gravitational force acting in the projectile is in the downward direction, sp the speed of the projectile in the horizontal direction remains constant and equals to the initial horizontal speed.

For projectile, a projectile having initial velocity u at an angle \theta with the horizontal direction,

The speed in the horizontal direction \(= u\cos\theta\)

and the speed in the vertical direction is \(= u\sin\theta\) upward.

For A:

The speed in the horizontal direction \(= u\cos75^{\circ}\)

and the speed in the vertical direction is \(= u\sin75^{\circ}\) upward.

For B:

The speed in the horizontal direction \(= u\cos15^{\circ}\)

and the speed in the vertical direction is \(= u\sin15^{\circ}\) upward.

Let \(t_A\) and \(t_B\) are the time of flight for projectile A and B respectively.

As the range is the horizontal distance traveled by the projectile, so

The range for the projectile A \(= u\cos75^{\circ}\times t_A\cdots(i)\)

The range for the projectile B = \(u\cos15^{\circ}\times t_B\cdots(ii)\)

At the highest point, the vertical velocity is 0.

Bu using the equation of motion \(v^2=u^2 +2a s.\)

Here, the final velocity v=0, the initial velocity \(u = u \sin \theta\) , h= vertical distance up to the highest point, and \(a= -g\) (as per sign convention).

So, \(s= \frac{u^2\sin^2 \theta}{2g}\)

For projectile A: The maximum height attained.

\(s_A= \frac{u^2\sin^2 75^{\circ}}{2g}\)

For projectile B: The maximum height attained.

\(s_B= \frac{u^2\sin^2 15^{\circ}}{2g}\)

As \(\sin^2 75^{\circ} > \sin^2 15^{\circ}\), the height of A is attained by A is more than the heigHt attained by B.

Now, the times required to reach the highest point from the ground and again form the highest point to the ground are the same.

So, the total time of flight = 2 x (Time to reach the highest point)

In a similar way, by using the equation of motion v=u+at,

The time to reach the highest point \(=\frac {u\sin\theta}{g}\)

where g is the acceleration due to gravity.

So, the total time of flight

\(= 2 \times \frac {u\sin\theta}{g}\)

The total time of flight for A

\(=2 \times \frac {u\sin75^{\circ}}{g}\)

The total time of flight for A

\(=2 \times \frac {u\sin15^{\circ}}{g}\)

Now, from equations (i) and (ii),

The range for the projectile A =

\(u\cos75^{\circ}\times \frac {2u\sin75^{\circ}}{g}=\frac {u^2 \sin 150^{\circ}}{g}= \frac {u^2 \sin 30^{\circ}}{g}\)

The range for the projectile B =

\(u\cos15^{\circ}\times \frac {2u\sin15^{\circ}}{g}=\frac {u^2 \sin 30^{\circ}}{g}.\)

Both the projectile have the same range.

Hence, option (A) is correct.

The statement is True. The derivative of a polynomial is also a polynomial. This is because the derivative of a polynomial involves taking the derivative of each term in the polynomial using the power rule of differentiation.

Since each term in the polynomial is a constant multiplied by a power of x, the derivative of each term will be a constant multiplied by a power of x, which is also a polynomial. When we add up all the derivatives of the individual terms, we get the derivative of the entire polynomial, which is also a polynomial. Therefore, the derivative of a polynomial is always a polynomial.

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The friction between the b;ock and surface is given by mass and accelerartion.

Force = mass * acceleration

a simple lifting machine consisting of a rope which unwinds from a wheel on to a cylindrical drum or shaft joined to the wheel to provide mechanical advantage. reeeeeeeeeeeeeeeeeeeeeeeeee

To determine the speed at which the astronaut must travel relative to Earth to reach the Andromeda galaxy, we need to calculate the velocity using the distance and time provided. The astronaut must travel at an average velocity of approximately 6.320 × 10^10 meters per year relative to the Earth in order to reach the Andromeda galaxy in 30.0 years.

Given:
Distance to Andromeda galaxy (d) = 2.00 × 10⁶ light-years
Time for the trip (t) = 30.0 years
The formula to calculate velocity is:
Velocity (v) = Distance (d) / Time (t)
Converting the distance from light-years to meters:
1 light-year = 9.461 × 10¹⁵ meters
Therefore, the distance to the Andromeda galaxy is:
d = 2.00 × 10⁶ light-years × (9.461 × 10¹⁵ meters/light-year)
Substituting the values into the velocity formula:
v = (2.00 × 10⁶ × 9.461 × 10¹⁵) / (30.0 × 365 × 24 × 60 × 60)=6.320 × 10^10 meters per year

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The magnitude of charge that requires is 0.1 C.

Given data:

Potential difference between two points, V = 10 volts

Magnitude of charge that requires, Q = ?

Formula:

Potential difference can be calculated by the formula V = W/Q,

where V is the potential difference, W is the work done, and Q is the magnitude of charge that requires to move between two points.

According to the question, a potential difference of 10 volts exists between two points and b within an electric field.

Let's calculate the magnitude of charge that requires:

V = W/Q10 = W/Q

The value of work done W = 1 JQ = W/VQ = 1 J/10 VQ = 0.1 C

Therefore, the magnitude of charge that requires is 0.1 C.

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