Umm can someone help me with this

To find the probability that the diameter of a selected ball bearing is greater than 127 millimeters, we can use the normal distribution.

Given that the diameter of ball bearings is normally distributed with a mean of 133 millimeters and a variance of 16, we can calculate the probability using the standard normal distribution table or a statistical calculator.

Since the diameter of ball bearings is normally distributed, we can standardize the value 127 using the formula z = (x - μ) / σ, where x is the given value, μ is the mean, and σ is the standard deviation. In this case, the standard deviation is the square root of the variance, which is 4.

Plugging in the values, we get z = (127 - 133) / 4 = -1.5. Now, we can find the probability using the standard normal distribution table or a statistical calculator. The probability of the diameter being greater than 127 millimeters is equal to 1 minus the cumulative probability up to -1.5.

By looking up the cumulative probability for -1.5 in the standard normal distribution table or using a calculator, we find that the cumulative probability is approximately 0.0668. Therefore, the probability that the diameter of a selected ball bearing is greater than 127 millimeters is approximately 0.0668 or 6.68% (rounded to four decimal places).

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Answer:

x = 8

Step-by-step explanation:

All angles of a triangle must add up to 180 degrees.

So 8x + 7 + 6x + 8x - 3 = 180

Combine like terms

22x + 4 = 180

Subtract 4

22x = 176

Divide

22x ÷ 22 = 176 ÷ 22 = x = 8

We can make sure this is correct by plugging in 8 for all x terms.

8(8) + 7 + 6(8) + 8(8) -3

64 + 7 + 48 + 64 - 3 = 180.

X = 8

Hope this helps.

Answer: 108 sq units

Step-by-step explanation:

Multiply

Answer:

Part A Part B Part C explained

Step-by-step explanation:

PART A: Extrema: relative minimums (4,-2) and maybe (7,-3) (uncertain because it’s an endpoint), relative maximums (6,0) and maybe (1,6) (uncertain because it’s an endpoint)

Zeros: (6,0), somewhere between t = 3 and t = 4 since the graph changes from positive to negative, and somewhere possibly between t = 6 and t = 7 unless the graph hits (6,0) and stays negative.

End behavior: We can guess that as x approaches infinity, the functions approaches negative infinity, and as x approaches negative infinity, the function approaches infinity.

Intervals of increase and decrease: Increasing on (4, 6), decreasing on (1, 4) and (6, 7)

PART B: The relative minimums indicate that the two lowest temperatures occurred on day 4 at -2°F and day 7 at -3°F. The relative maximums indicate that the weekly highs were day 1 at 6°F and day 6 at 0°F.

The zeros of the function represent when the temperature in Johnstown was 0°F. This happened sometime between days 3 and 4 and on day 6.

In the context of the problem, it doesn’t make sense to go an infinite number of degrees below zero. And, the end behavior is ignored because of the restricted range.

The intervals of increase indicate when the temperature is rising, and the intervals of decrease indicate when the temperature is dropping. The intervals where the values are positive indicate when the temperature is above 0°F. The intervals where the values are negative indicate when the temperature is below 0°F.

PART C: The domain is restricted to the number of days the town recorded the temperature. So, the domain is [1, 7].

The range represents the range of temperatures of Johnstown over the course of one week. So, the range is [-3, 6].

Answer:

Part A was missing the last so this is the correct answer.

Extrema: relative minimums (4,-2) and maybe (7,-3) (uncertain because it’s an endpoint), relative maximums (6,0) and maybe (1,6) (uncertain because it’s an endpoint)

Zeros: (6,0), somewhere between t = 3 and t = 4 since the graph changes from positive to negative, and somewhere possibly between t = 6 and t = 7 unless the graph hits (6,0) and stays negative.

End behavior: We can guess that as x approaches infinity, the functions approach negative infinity, and as x approaches negative infinity, the function approaches infinity.

Intervals of increase and decrease: Increasing on (4, 6), decreasing on (1, 4) and (6, 7)

Positive and negative intervals: Positive from 1 to somewhere between t = 3 and t = 4, and negative from somewhere between t = 3 and t = 4 to t = 6, and from some point after t = 6 to t = 7.

But other than that everything else was correct and thank you.

Step-by-step explanation:

Price of $160 produces the maximum revenue.

We are given with information of 50 cycles being selled for $220 each. For each decrease in unit price there is increase in no. of units by 10. These two relations

can be expressed asAmount - (220-20x)

No. of cycles - (50+10x)

We have to establish a quadratic equation between both these constraints ,we

multiply both of them to get an equation and let r(x) be equal to it.

r(x)=(220-20x)(50+10x)

r(x)=11000+2200x-1000x-200x²

r(x)= -200x²+1200x+11000

Which is the required quadratic relation.

Now we know a quadratic equation obtain maximum value at -b/2a

So x= -b/2a = -1200/2(-200)=3

So for x= 3 we have maximum value of r(x)

r(x) = -200(9)+1200(3)+11000

= $12,800

I.e  $12,800 will be maximum revenue each unit valued at

(220-20(3)) = $160

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Answer:

146304 marbles

Step-by-step explanation:

We do not need to worry about the color part, at least right now

One box contains 576 marbles

To find how many are in 2 boxes we would do 576 * 2

To find 254, we would do 576 * 254

Now, I would suggest using lattice multiplication here. If you do not know how to do that, long multiplication works fine.

I can't show that here, but I can show the answer:

576 * 254 = 146304

So, there are 146304 marbles is 254 boxes

The area between the two curves will be around 17/6 square units.

Let's start by setting the two equations equal to each other:

|+3|−2 = 1−(1/3)|−2|

Case 1: +3≥0

In this case, the equation simplifies to:

+3−2 = 1−(1/3)|−2|

Simplifying further, we get:

= 1

Case 2: +3<0

In this case, the equation simplifies to:

−(+3)−2 = 1−(1/3)|−2|

Simplifying further, we get:

= −2

two curves intersect at =−2 and =1.

we need to integrate the difference between the two curves with respect to , from =−2 to =1:

∫−2¹ [(1−(1/3)|−2|)−(|+3|−2)] d

Simplifying the absolute values,

∫−2¹ [(1−(1/3)(−2))−(|+3|−2)] d

Next, we can break up the integral into two parts:

∫−2¹ [1−(1/3)(−2)] d − ∫−2¹ (|+3|−2) d

Simplifying, (7/3) + (1/2) = 17/6

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Answer:

C

Step-by-step explanation:

Plug in two different numbers in the x coordinate and see if the y coordinate matches up with the same line.

The minors of the 2 x 3 matrix are -3, -2, -1, 9, -2, -3, 6, and 5. The cofactors are -18, 16, 5, -3, -18, 18, 3, -12, and -5.

Minor of 2: -3

Cofactor of 2: -18

Minor of -8: -2

Cofactor of -8: 16

Minor of 5: -1

Cofactor of 5: 5

Minor of 3: 9

Cofactor of 3: -3

Minor of 9: -2

Cofactor of 9: -18

Minor of 6: -3

Cofactor of 6: 18

Minor of -1: -3

Cofactor of -1: 3

Minor of -2: 6

Cofactor of -2: -12

Minor of -3: 5

Cofactor of -3: -5

The minors of the 2 x 3 matrix are -3, -2, -1, 9, -2, -3, 6, and 5. The cofactors are -18, 16, 5, -3, -18, 18, 3, -12, and -5.

The given 2 x 3 matrix is composed of the values 2, -8, 5, 3, 9, 6, -1, -2, and -3. The minors of the matrix can be found by using the Laplace expansion formula and removing the row and column of the element in question. This yields the minors -3, -2, -1, 9, -2, -3, 6, and 5. The cofactors of the matrix can be calculated by taking the determinant of the minor and multiplying it by the sign of the element in question. This results in the cofactors -18, 16, 5, -3, -18, 18, 3, -12, and -5.

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The surface area of the solid obtained by rotating the area enclosed by the graphs of \(\( f(x)=-x+4 \) and \( g(x)=x^{2}-x+3 \)\)about the line x = 4 is 67π/3.

The graphs of the two functions are shown below: graph{x^2-x+3 [-5, 5, -2.5, 8]--x+4 [-5, 5, -2.5, 8]}Notice that the two graphs intersect at x = 2 and x = 3. The line of rotation is x = 4. We need to consider the portion of the curves from x = 2 to x = 3.

To find the volume of the solid of revolution, we can use the formula:\($$V = \pi \int_a^b R^2dx,$$\) where R is the distance from the line of rotation to the curve at a given x-value. We can express this distance in terms of x as follows: R = |4 - x|.

Since the line of rotation is x = 4, the distance from the line of rotation to any point on the curve will be |4 - x|. We can thus write the formula for the volume of the solid of revolution as\(:$$V = \pi \int_2^3 |4 - x|^2 dx.$$\)

Squaring |4 - x| gives us:(4 - x)² = x² - 8x + 16. So the integral becomes:\($$V = \pi \int_2^3 (x^2 - 8x + 16) dx.$$\)

Evaluating the integral, we get\(:$$V = \pi \left[ \frac{x^3}{3} - 4x^2 + 16x \right]_2^3 = \frac{11\pi}{3}.$$\)

Therefore, the volume of the solid obtained by rotating the area enclosed by the graphs of \(\( f(x)=-x+4 \) and \( g(x)=x^{2}-x+3 \)\) about the line x = 4 is 11π/3.

The formula for the surface area of a solid of revolution is given by:\($$S = 2\pi \int_a^b R \sqrt{1 + \left( \frac{dy}{dx} \right)^2} dx,$$\) where R is the distance from the line of rotation to the curve at a given x-value, and dy/dx is the derivative of the curve with respect to x. We can again express R as |4 - x|. The derivative of f(x) is -1, and the derivative of g(x) is 2x - 1.

Thus, we can write the formula for the surface area of the solid of revolution as:\($$S = 2\pi \int_2^3 |4 - x| \sqrt{1 + \left( \frac{dy}{dx} \right)^2} dx.$$\)

Evaluating the derivative of g(x), we get:\($$\frac{dy}{dx} = 2x - 1.$$\)

Substituting this into the surface area formula and simplifying, we get:\($$S = 2\pi \int_2^3 |4 - x| \sqrt{1 + (2x - 1)^2} dx.$$\)

Squaring 2x - 1 gives us:(2x - 1)² = 4x² - 4x + 1. So the square root simplifies to\(:$$\sqrt{1 + (2x - 1)^2} = \sqrt{4x² - 4x + 2}.$$\)

The integral thus becomes:\($$S = 2\pi \int_2^3 |4 - x| \sqrt{4x² - 4x + 2} dx.$$\)

To evaluate this integral, we will break it into two parts. When x < 4, we have:\($$S = 2\pi \int_2^3 (4 - x) \sqrt{4x² - 4x + 2} dx.$$\)

When x > 4, we have:\($$S = 2\pi \int_2^3 (x - 4) \sqrt{4x² - 4x + 2} dx.$$\)

We can simplify the expressions under the square root by completing the square:\($$4x² - 4x + 2 = 4(x² - x + \frac{1}{2}) + 1.$$\)

Differentiating u with respect to x gives us:\($$\frac{du}{dx} = 2x - 1.$$\)We can thus rewrite the surface area formula as:\($$S = 2\pi \int_2^3 |4 - x| \sqrt{4u + 1} \frac{du}{dx} dx.\)

Evaluating these integrals, we get\(:$$S = \frac{67\pi}{3}.$$\)

Therefore, the surface area of the solid obtained by rotating the area enclosed by the graphs of \(\( f(x)=-x+4 \) and \( g(x)=x^{2}-x+3 \)\)about the line x = 4 is 67π/3.

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1. The peak value of a waveform is the highest value of a waveform, whereas the peak-to-peak value of a waveform is the difference between the maximum positive and maximum negative values of a waveform.

2. The statement "For expressions that are time-dependent or that represent a particular instant of time, an uppercase letter such as V or I is used." is false.

3. The statement "The sine wave is the only alternating waveform whose shape is not altered by the response characteristics of a pure resistor, inductor, or capacitor" is true.

1. The peak value of a waveform refers to the maximum value reached by the waveform in one direction, while the peak-to-peak value refers to the difference between the highest and lowest points of the waveform.

2. For expressions that are time-dependent or that represent a particular instant of time, a lowercase letter such as v or i is used. The uppercase letter is used to represent the RMS or average value of a waveform.

3. The sine wave is the only alternating waveform that maintains its shape when passing through a pure resistor, inductor, or capacitor because the impedance of a pure resistor, inductor, or capacitor is frequency-independent whereas other waveforms, such as square waves or triangular waves, can be altered by the frequency-dependent characteristics of reactive components like inductors and capacitors.

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Answer:

x = -33

Step-by-step explanation:

2/3(x+6)=-18

Multiply each side by 3/2

3/2*2/3(x+6)=-18*3/2

x+6 = -27

Subtract 6 from each side

x+6-6 = -27-6

x = -33

Let the unit digit be x

and the tens digit be x-2

The Sum of digits is x + x - 2  

                              = 2x - 2

Now,

   ⇒ 10(x - 2) + x

    ⇒ 10x + 20 + x

    ⇒ 11x - 20

Now, According to Question

    ⇒ 11x - 20 - 27

    ⇒ 11x - 2x = -2 + 47

    ⇒ 9x = 45

    ⇒ x = 5

Now,

The tens digit ⇒  x - 2

putting the value of x in equation

   ⇒ 5 - 2 = 3

So, the product of the digits is  3 × 5

The possible values of angles A and C are;

60° and 70° or 55° and 75°

An acute triangle is a triangle that has all the measures of its angles to be less than 90°.  This means that none of the angles is greater than 90°

Since sum of the angles in a triangle is equal to 180°, then it means that;

∠A + ∠B + ∠C = 180°

We are given that;

∠B = 50°

Thus;

50° + ∠A + ∠C = 180°

∠A + ∠C = 180° - 50°

∠A + ∠C = 130°

It should be noted that all the angles of the acute triangle are also different.

Thus, the possible values of A and C are 60° and 70° or 55° and 75° because their sum must be equal to 130°

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The rate of interest applied on the amount is 15%.

According to the statement

we have given that the sum of money amounts to Rs. 2175 in 3 years and to Rs. 2625 in 5 years.

And we have to find the rate of interest on this money.

So, For this purpose,

The given equation is:

Money in 3 years = 2175

Money in 5 years = 2625

Amount increased in 2 years = 2625-2175

Amount increased in 2 years = 450

And amount increased per year = 450/2

Amount increased per year = 225.

SI in 3 years=450/2 *3=Rs. 675

Principal amount= 2175-675=1500

so again,

R=(I*100)/(P*T)

R=15%

So, The rate of interest applied on the amount is 15%.

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Answer:

Step-by-step explanation:

➡️ Volume = r³

➡️ 2³

➡️ 8

= Sisi × Sisi × Sisi

= 2 Cm × 2 Cm × 2 Cm

= 4 Cm × 2 Cm

= 8 Cm .

Maka, volumenya 8 Cm.

Answer:

2.48

Step-by-step explanation:

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Answer:

Step-by-step explanation:

How we come up with the equation is first off by plugging in x and why which looks like this:

0.9=x(0.1)

Then we do 0.9 divided by 0.1 which gives us an answer of 9

hopefully, that helps :)

The mass of a single washer can be calculated by dividing the total mass of the box (1.2314 kg) by the number of washers (1000). The mass of a single washer is expressed in milligrams.

To calculate the mass of a single washer, we divide the total mass of the box (1.2314 kg) by the number of washers (1000).

1.2314 kg divided by 1000 washers equals 0.0012314 kg per washer.

To convert the mass from kilograms to milligrams, we need to multiply by the appropriate conversion factor.

1 kg is equal to 1,000,000 milligrams (mg).

So, multiplying 0.0012314 kg by 1,000,000 gives us 1231.4 mg.

Therefore, the mass of a single washer is 1231.4 milligrams (mg).

Note: In scientific notation, this would be written as 1.2314 x 10^3 mg, where the exponent of 3 represents the milli prefix.

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Answer:

91

Step-by-step explanation:

Answer:

la reponse a la question et 91

The dual problem of the given linear programming problem involves converting the objective function and constraints. The feasibility of the solution is determined by checking if the optimal values.

To find the dual problem of the given linear programming problem, we start by converting the maximization objective function into the minimization form. The coefficients of the variables in the objective function become the constants in the dual problem, and vice versa. Therefore, the dual problem can be stated as follows:

min w = 2a + 4b

subject to:

a + b ≥ 8

a + 2b ≥ 2

a, b ≥ 0

The dual problem has two constraints corresponding to the original variables x and y, and the objective function is constructed using the constants from the original problem.

To sketch the feasible region, we plot the constraints on a coordinate plane. The feasible region is the intersection of the shaded regions satisfying all the constraints. In this case, the feasible region will be a bounded region.

To determine whether the solution is feasible or not, we need to check if the objective function values in the feasible region satisfy the constraints of the dual problem. If the optimal solution of the dual problem yields non-negative values for the variables a and b, then the solution is feasible. Otherwise, if negative values are obtained, the solution is not feasible.

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There are variations in the participation prices of boys and girls across unique sports, with boys having decreased representation in varsity soccer, better representation in freshman basketball, and identical illustration in varsity tennis compared to ladies.

Based on the given statements:

The percentage of boys who play varsity soccer is much less than the share of ladies who play varsity football.

The share of boys who play freshman basketball is extra than the share of girls who play freshman basketball.

The percentage of boys who play varsity tennis is the same as the variety of women who play varsity tennis.

We can finish subsequent:

Boys have a lower representation in varsity football as compared to ladies.

Boys have a higher representation in freshman basketball in comparison to ladies.

The percentage of boys playing varsity tennis is identical to the proportion of women playing varsity tennis.

These statements suggest differences in participation fees and proportions between boys and women in unique sports activities.

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The correct question is:

"The percentage of boys who play varsity soccer is ✔ less than the percentage of girls who play varsity soccer. the proportion of boys who play freshman b-ball is ✔ greater than the proportion of girls who play freshman b-ball. the percentage of boys who play varsity tennis is ✔ the same as the number of girls who play varsity tennis.

What can you conclude from the above statements?"

The angle ZEHF is equal to 90°, indicating a right angle.

Since ABCD is inscribed in a circle, opposite angles are supplementary. From this, we can deduce that angle ACD is equal to angle ABC.By considering the intersecting lines AB and CD at point E, we can conclude that angle ZED is equal to angle ZEA due to vertical angles. Similarly, angle ZFB is equal to angle ZFA.

Now, let's examine the triangles AFD and BFC. These triangles share the common side FD.Since angles AFD and BFC are subtended by arcs AD and BC respectively, and we know that arcs AD and BC are equal, we can conclude that angles AFD and BFC are equal.

Angles ZEA, ZFA, ZEH, and ZFH are all subtended by the same arcs, which are arcs AD and BC.Since angles ZEA and ZFA are equal,So, we can deduce that angles ZEH and ZFH are also equal as well.

By combining these conclusions, we find that angles ZEHF form a

cyclic quadrilateral with opposite angles that are supplementary. Hence, angle ZEHF must be equal to 90°, forming a right angle.

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Answer:

1,495 cents a liter

We need to calculate the 8% of $45

The total charge will be

ANSWER

The total charge is $48.60

Answer: 50.24 cm^2

Step-by-step explanation:

This can be translated to:

An old coin is kept in a cubic box in such a way that the outline of the coin touches the 4 walls of the box, if the base of the box has a perimeter of 24 cm. What is the area of ​​the coin?

The fact that the coin touches the interior of the box means that the diameter of the coin is equal to the side lenght of the box.

The perimeter of the box is 24 cm, and the perimeter of a square is equal to:

P = 4*L

where L is the side lenght of the square.

24 cm = 4*L

L = 24cm/4 = 8cm

Now we know that the diameter of the coin is 8cm

Now, the area of a circle (the coin) is equal to:

A = 3.14*(d/2)^2

where d is the diameter, so we have:

A = 3.14*(4cm)^2 = 50.24 cm^2

The problem can be solved using the simplex method, and the solution can be verified using the graphical method. The optimal solution is X1 = 6, X2 = 0, X3 = 6, Z = 24.

The problem can be solved using the simplex method, and verified using the graphical method. Here are the steps:

Convert the problem to standard form by introducing slack variables:
Min Z = -2X1 - 4X2 - 3X3 + 0S1 + 0S2 + 0S3
St. X1 + 3X2 + 2X3 + S1 = 30
X1 + X2 + X3 + S2 = 24
3X1 + 5X2 + 3X3 + S3 = 60
Xi, Si >= 0

Set up the initial simplex tableau:
| 1 3 2 1 0 0 30 |
| 1 1 1 0 1 0 24 |
| 3 5 3 0 0 1 60 |
| 2 4 3 0 0 0 0 |

Identify the entering variable (most negative coefficient in the objective row): X2

Identify the leaving variable (smallest ratio of RHS to coefficient of entering variable): S1

Pivot around the intersection of the entering and leaving variables to create a new tableau:
| 0 2 1 1 -1 0 6 |
| 1 0 0 -1 2 0 18 |
| 0 0 0 5 -5 1 30 |
| 2 0 1 -2 4 0 36 |

Repeat steps 3-5 until there are no more negative coefficients in the objective row. The final tableau is:
| 0 0 0 7/5 -3/5 0 18 |
| 1 0 0 -1/5 2/5 0 6 |
| 0 0 1 1/5 -1/5 0 6 |
| 0 0 0 -2 4 0 24 |

The optimal solution is X1 = 6, X2 = 0, X3 = 6, Z = 24.

To verify the solution using the graphical method, plot the constraints on a graph and find the feasible region. The optimal solution will be at one of the corner points of the feasible region. By checking the values of the objective function at each corner point, we can verify that the optimal solution found using the simplex method is correct.

In conclusion, the problem can be solved using the simplex method, and the solution can be verified using the graphical method. The optimal solution is X1 = 6, X2 = 0, X3 = 6, Z = 24.

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Given: Differential equation of the form: \($\frac{dx}{dt}+ax=b$\)

This is a first-order, linear, ordinary differential equation with a constant coefficient. To solve this differential equation we need to follow the steps below:

First, find the homogeneous solution of the differential equation by setting \($b=0$.$\frac{dx}{dt}+ax=0$\)

Integrating factor, \($I=e^{\int a dt}=e^{at}$\)

Multiplying both sides of the differential equation by \($I$.$\frac{d}{dt}(xe^{at})=0$\)

Integrating both sides.\($xe^{at}=c_1$\)

Where \($c_1$\) is a constant.

Substituting the initial condition,\($x(0)=x_0$.$x=e^{-at}c_1$\)

Next, we need to find the particular solution of the differential equation with the constant \($b$.\)

In the present case, \($b=constant$\)

Therefore, the particular solution of the differential equation is also a constant.

Let this constant be \($c_2$.\)

Then, \($\frac{dx}{dt}+ax=b$ $\implies \frac{dc_2}{dt}+ac_2=b$ $\implies c_2=\frac{b}{a}$\)

Thus, the general solution of the differential equation is,\($x(t)=e^{-at}c_1+\frac{b}{a}$\)

Where\($c_1$\) is the constant obtained from the initial condition,

and \($e$\)is the exponential constant.

If the initial condition is \($x(t_0)=x_0$ then,$x(t)=e^{-a(t-t_0)}c_1+\frac{b}{a}$\)

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Answer:

\(\sqrt{17}\)

Step-by-step explanation:

\(\sqrt{4^2 + 1^2}\)

\(\sqrt{17}\)