Type of reaction formed with Na + Cl2

Answer:

2B2 + 3O2 → 2B2O3

Explanation:

Balance The Equation: B2 + O2 = B2O3

1. Label Each Compound With a Variable

  aB2 + bO2 = cB2O3

2. Create a System of Equations, One Per Element

  B: 2a + 0b = 2c

  O: 0a + 2b = 3c

3. Solve For All Variables (using substitution, gauss elimination, or a calculator)

  a = 2

  b = 3

  c = 2

4. Substitute Coefficients and Verify Result

  2B2 + 3O2 = 2B2O3

      L R

  B: 4 4 ✔️

  O: 6 6 ✔️

hope this helps!

Answer:

Explanation:

9.708 mg of CO₂ will contain 12 x 9.708 / 44 = 2.64 g of C .

3.969 mg of H₂O will contain 2 x 3.969 / 18 = .441 g of H .

mg of O in given liquid B = 3.795 - ( 2.64 + .441 ) = .714 mg

ratio of mg of C , H , O in the compound = 2.64 : .441 : .714

ratio of no of atoms  of C , H , O in the compound

= 2.64 / 12 : .441 /1 : .714 / 16

= .22 : .44 : .0446

= .22 / .22 : .44 / .22 : .044 / .22

= 1 : 2 : .2

1 x 5 : 2 x 5 : .2 x 5

= 5 : 10 : 1

empirical formula of the compound = C₅H₁₀O

Volume of 89.8 mL at 1 .00 atm at 200⁰C

volume of gas at 1 atm and 0⁰C = 89.8 x 273 / 473 mL

= 51.83 mL

51.83 mL weighs .205 g

22400 mL will weigh .205 x 22400 / 51.83 g

= 88.6 g

So molecular weight = 88.6

Let molecular formula be (C₅H₁₀O)ₙ

molecular weight = n ( 5 x 12 + 10 + 16 )

= 86 n

86 n = 88.6

n = 1 approx

So molecular formula is same as empirical formula

C₅H₁₀O is molecular formula .

Answer:

hbchbjH j jas a aa  a s ds d as das

Explanation:

Consumers are organisms which depend on the producers or autotrophs for their food and nutrition.

Consumers are also known as heterotrophs, and they feed on the producers (autotrophs or self-feeders or plants) and herbivores (animals that eat plants) for food and energy. They don't produce their own food.

There are four types of consumers:

1) Primary – Herbivores are known as primary consumers and their source of food is plants or the first trophic level of the food chain. Example, Rabbits, Butterflies, Zooplanktons, etc.

2) Secondary – these consumers eat both plants and herbivores and are therefore also known as omnivores. Example, Ants, Crabs, Rats, Humans, etc.

3) Tertiary – these consumers eat primary and secondary consumers. Thus, they can be omnivores as well as carnivores. Example, Hawks, Snakes, Lions, etc.

4) Quaternary – these consumers prey on the tertiary consumers. Example, Polar bear, Alligator, etc.

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The Br are in 25 g CaBr2 will be approximately 203.87 g of Br.

The molar mass of an element's atoms is calculated by multiplying the element's comparative atomic mass by the molar mass constant.

In the given scenario, we need to find the grams of Br in CaBr2.

We know that,

molar mass of Br = 79.904 g/mol

molar mass of CaBr2 = 199.886 g/mol

CaBr2 = 2 Br + Ca

So, by the given data,

199.886 g = 2 x 79.904 g

255 g = X ( i.e., mass of Br )

X = 255 x 2 x 79.904 / 199.886

X = 203.87 g of Br

Thus, the amount of Br is 203.87gm.

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Answer:

4. the egg shell you place in normal water

From the information provided in the question, the mass of NiCl2 required is 0.23 g.

NiCl2(aq) + 2AgNO3(aq) -------> 2AgCl(s) + Ni(NO3)2(aq)

Number of moles of AgCl= Mass/molar mass

Molar mass of AgCl= 143 g/mol

Substituting values;

Number of moles = 503 × 10^-3g/143 g/mol= 0.00352 moles

Since 1 mole NiCl2 precipitates 2 moles of AgCl

x moles of NiCl2 precipitates  0.00352 moles of AgCl

x = 1 mole ×  0.00352 moles/2 moles

x = 0.00176 moles of NiCl2

Mass of NiCl2= 0.00176 moles × 130 g/mol = 0.23 g

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Warmer climate-induced Galetown to have extra extreme rainstorms. while the temperature of an air parcel begins out higher, it'll have to upward thrust higher in the troposphere before the temperature of the air parcel and the encompassing air are equal.

Extreme storms require three situations to develop: an electricity source, moisture, and volatile air. The hotter the floor or ocean is underneath a storm, the greater energy may be transferred to the storm. huge quantities of water vapor produce precipitation and shipping power, fueling the hurricane.

Whilst liquid water will become warmer it is able to evaporate and emerge as water vapor in the air. All air consists of water. whilst water vapor in an air parcel cools, it can condense into liquid water which can shape a cloud and fall as rain.

Satellites are essential in short-time period forecasting. satellite tv for pc photos can supply an early indication of a developing thunderstorm by displaying which cumulus clouds are forming. Cumulus clouds grow hastily into cumulonimbus clouds if situations are right, and you may sing their boom with the use of satellite pics.

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Answer: 3 qualitative: the word pharmacology is written in blue, the stairs are gray, the tile on the first floor is yellow. 3 quantitative: there are four people wearing yellow, there are Four pink boxes, there are two floors.

Inference: there are many people performing experiments so it’s a lab.

Explanation:

Answer:

Qualitive - The bars are yellow, The floor is green, and the floor has pharmacology on it.

Quantitative - There are 8 support bars, There is 3 gray coats, and there is 27 pills that I can see on that picture.

Inference - There are many people doing experiments because the word pharmacology is on the floor.

Explanation:

This picture tells you that pharmacology is a form of study of medicine and drugs.

Answer:

nitrogen is a gas

Explanation:

nitrogen is a gas which consists of diatomic molecules and about 78%of it occupies the atmosphere

Answer:

below the surface

Explanation:

Answer:

3 p.m most probably.

Explanation:

They found it at Monday 5 pm so its done before that time so its 3 p.m

Answer:

–0.360 M/s

Explanation:

Only Ag2CO3 will precipitate from the solution.

When Na2CO3 is added to the solution, it will react with the Ag^+ and Pb^2+ ions to form precipitates of Ag2CO3 and PbCO3. The Mn^2+ ion concentration is not high enough to form a precipitate with Na2CO3.

First, let's calculate the initial concentration of Ag^+ and Pb^2+ ions in the solution:

Ag^+: 0.00050 M

Pb^2+: 0.00050 M

Next, we need to calculate the concentration of Na2CO3 after it is added to the solution. Since we added 10.00 ml of 1.0*10^-6 M Na2CO3 to a total volume of 500 ml, the final concentration of Na2CO3 is:

[Na2CO3] = (10.00 ml / 500 ml) * 1.010^-6 M

[Na2CO3] = 2.010^-8 M

Now we can use the Ksp values to determine which precipitates will form.

For Ag2CO3:

Ksp = [Ag^+]^2[CO3^2-]

8.110^-12 = (2x)^2 (2x)

8.110^-12 = 4x^3

x = 2.0*10^-4 M

Since the concentration of CO3^2- is higher than the solubility product, Ag2CO3 will precipitate.

For PbCO3:

Ksp = [Pb^2+][CO3^2-]

7.410^-14 = (0.00050 M)(2x)

x = 9.210^-11 M

Since the concentration of CO3^2- is lower than the solubility product, PbCO3 will not precipitate.

Therefore, the only precipitate that will form is Ag2CO3.

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Answer:

melting butter and frying eggs

Explanation:

Hope this helps please mark me brainliest

Following are the effects of acid rain.

What is Acid Rain?

Acid rain is caused by the accumulation of nitric and sulfuric acids in the atmosphere. These compounds are strong acids and are very soluble in water, dissolving in droplets in clouds.

Limestone effect:

Calcium carbonate, [Ca][CO3], is a very common mineral. A limestone is a well-known form of calcium carbonate. The acid contained in acid rain reacts with carbonate ions and promotes the dissolution of calcium carbonate.

This will create a bicarbonate solution. The presence of limestone and other calcium carbonates in lakes and streams helps maintain a constant pH as the mineral reacts with excess acidity. However, acid rain can eventually exceed the buffering capacity of surface waters.

How does acid rain affect buildings made of marble and limestone?

It is mainly affected in 2 ways: dissolution and alteration. Calcite dissolves when sulfuric, sulfuric and nitric acids in polluted air react with calcite in marble and limestone. Exposed areas of buildings and statues show rough surfaces, worn materials, and loss of sculptural detail. Stoneface material can be lost anywhere or only in more reactive areas.

Hence, this is how acid rain affects.

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Answer:

P(H₂ ) =  7.5 atm

Explanation:

Given data:

Mass of hydrogen = 6.00 g

Number of moles of CO₂ = 1.80 mol

Total pressure = 12.0 atm

Partial pressure of H₂ = ?

Solution:

Number of moles of H₂:

Number of moles = mass/molar mass

Number of moles = 6.00 g/ 2 g/mol

Number of moles = 3 mol

Partial pressure of gases:

Total number of moles present = 1.80 mol + 3 mol = 4.80 mol

P(H₂ ) = [ 3 mol/ 4.80 mol] × 12.0 atm

P(H₂ ) = 0.625× 12.0 atm

P(H₂ ) =  7.5 atm

P(CO₂) = [1.80 mol/4.80 mol] × 12.0 atm

P(CO₂) = 0.375 × 12.0 atm

P(CO₂) = 4.5 atm

The partial pressure of hydrogen is equal to 7.5 atm.

Given the following data:

Scientific data:

To determine the partial pressure of hydrogen:

First of all, we would calculate the number of moles of hydrogen:

\(Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{6.00}{2}\)

Number of moles = 3 moles

Next, we would determine the partial pressure of hydrogen:

\(Molefraction \;of \;a \;substance =\frac{No.\; of \; moles \;of \;substance}{Total \;no. \;of \; moles \;of \;substances}\)

Substituting the values, we have:

\(Molefraction \;of \;a \;substance =\frac{3}{4.8} \\\\Molefraction \;of \;a \;substance =0.625\)

For hydrogen:

\(Partial \;pressure = Molefraction \times Total\;pressure\\\\Partial \;pressure = 0.625 \times 12.0\)

Partial pressure of hydrogen = 7.5 atm.

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Answer:

Cccccccccccccccccccccccccccccccccccccccccccc

Answer:

send a pic or more info

Explanation:

Answer:

a. 0.2355052g

Explanation:

a)

1000ml of NaOH contain 0.241moles

24.43ml of NaOH contain (24.43*0.241)/1000 moles

= 0.00588763moles

Relative Molecular Mass of NaOH

= 1*23 + 1*16 + 1*1

= 40

1mole of NaOH weighs 40g

0.00588763moles weigh (0.00588763*40) g

= 0.2355052g

B)

NaOH -> Na+ + -OH

1 mole of NaOH dissociates to form 1 mole of -OH ions

1 mole of a substance contains 6.02*10^23 particles(atoms)

= 0.00588763 * 6.02 *10^23

= ______ions

Answer:

D.)

Explanation:

Water, also known as H2O in chemistry, is a chemical substance.

Water vapor is the gas form of water, also known as the effect of evaporation. Ice is made up of water as well. It is the frozen version of water, or it other terms, the solid form of it.

I hope that this helps.

Answer:

atomic number of phosphorous is 15. It has zero charges because it has equal number of protons and electrons

Explanation:

The mass of hydrogen needed to produce 51.0 grams of ammonia is  ≈ 9.07 grams.

To determine the mass of hydrogen required to produce 51.0 grams of ammonia (NH3) using the Haber process, we need to calculate the stoichiometric ratio between hydrogen and ammonia.

From the balanced chemical equation:

3 H₂(g) + N₂(g) → 2 NH₃(g)

We can see that for every 3 moles of hydrogen (H₂), we obtain 2 moles of ammonia (NH₃).

First, we need to convert the given mass of ammonia (51.0 grams) to moles. The molar mass of NH₃ is 17.03 g/mol.

Number of moles of NH₃ = Mass / Molar mass

                     = 51.0 g / 17.03 g/mol

                     ≈ 2.995 moles

Next, using the stoichiometric ratio, we can calculate the moles of hydrogen required.

Moles of H₂ = (Moles of NH₃ × Coefficient of H₂) / Coefficient of NH₃

           = (2.995 moles × 3) / 2

           ≈ 4.493 moles

Finally, we can convert the moles of hydrogen to mass using the molar mass of hydrogen (2.02 g/mol).

Mass of H₂ = Moles × Molar mass

          = 4.493 moles × 2.02 g/mol

          ≈ 9.07 grams

Therefore, approximately 9.07 grams of hydrogen is needed to produce 51.0 grams of ammonia in the Haber process.

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ClO(4)− is regarded as perchlorate ion and are produced commercially in most situations as salts via industries and in the laboratory.

This ion is referred to as a monovalent inorganic anion and is obtained by deprotonation of perchloric acid. It is composed of chlorine and oxygen atoms in the ratio 1 to 4 respectively.

This has  32 valence electrons available in the Lewis structure and is used in the commercial production of solid rocket fuel.This ion has a molar mass of 99.451 g mol−1 and is used in different processes such as an oxidizer and to control static electricity during the process of food preservation in industries.

Therefore ClO₄− is also regarded as perchlorate ion and is the most appropriate choice.

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Answer:

the Balogna could carry  19 passengers if filled with Hydrogen.

the Balogna could carry  17 passengers if filled with Helium.

Explanation:

Given that:

the radius of the cylinder r = 4.0 cm

the height h = 40 m

the volume of the cylinder will be:

\(V = \pi r^2 h\)

V = π (4.0 m)² (40)

V = 2010.62 m³.

where the density of the air = 1.23 kg/m³

the mass of the displaced air = Volume V ×density of the air

= 2010.62 m³ × 1.23 kg/m³

= 2473.0626 kg

To calculate how many passengers the Balogna could carry if it were filled with hydrogen, we have the following:

We are given the density of H₂ to be = 0.090 kg/m³

Therefore, the mass of Helium in the balloon = Volume V × density of the hydrogen

= 2010.62 m³ × 0.090 kg/m³

= 180.9558 kg

The total mass of the balloon = mass of H₂ + mass of empty balloon.

The total mass of the balloon = (180.9558+ 750) kg

= 930.9558 kg

Now, the Mass difference = mass of the air displaced -total mass of the balloon.

the Mass difference =  (2473.0626 - 930.9558 ) kg

the Mass difference =  1542.1068 kg

∴

number of persons = mass difference/ mass of passenger

the number of persons = 1542.1068 kg /80 (kg/person)

the number of persons = 19.27 persons

the number of passengers \(\simeq\) 19 passengers.

To calculate how many passengers the Balogna could carry if it were filled with helium, we have the following:

We are given the density of Helium to be =  0.18 kg/m³

Therefore, the mass of Helium in the balloon = Volume V × density of the hydrogen

= 2010.62 m³ × 0.18 kg/m³

= 361.9116 kg

The total mass of the balloon = mass of Helium + mass of empty balloon.

The total mass of the balloon = (361.9116 + 750) kg

= 1111.9116 kg

Now, the Mass difference = mass of the air displaced -total mass of the balloon.

the Mass difference =  (2473.0626 - 1111.9116 ) kg

the Mass difference =  1361.151 kg

∴

number of persons = mass difference/ mass of passenger

the number of persons =  1361.151 kg /80 (kg/person)

the number of persons = 17.01 persons

the number of passengers \(\simeq\) 17 passengers.

Answer:

C - Extrusive igneous

Explanation:

Rhyolite is an extrusive igneous due to the high silica content, the lava is very dangerous.

Answer:

Its C

Explanation:

A P E X

Answer:

Alkanes

Explanation:

Alkanes are hydrocarbons containing only C-H and C-C single bonds. They're saturated compounds and they form a homologous series with the general formula CₙH₂ₙ₊₂, where n is the number of carbon atoms. Example of members in this group are

Methane = CH₄

Ethane = C₂H₆

Propane = C₃H₈

All alakane compounds ends with with the suffix "-ane" and this differentiate them during naming from other compounds.

Answer:

3600J

Explanation:

Q = mc∆T

= 50 x 0.9 x (100 - 20)

= 3600J

At the usual working conditions of 101.5 kPa and 21°C, the chemical oxygen generator system would generate roughly 220.84 litres of oxygen using 500 g of LiClO4.

We may use the ideal gas law and stoichiometry to calculate how many litres of oxygen are created by the chemical oxygen generator system employing 500 g of LiClO4.

We must first determine the moles of LiClO4. LiClO4 has a molar mass of approximately 106.39 g/mol. As a result, 4.704 mol of LiClO4 are produced from 500 g of LiClO4 using the formula: 500 g / 106.39 g/mol

We can see from the chemical equation that 1 mole of LiClO4 results in 2 moles of O2. 4.704 mol of LiClO4 will therefore result in:

2 mol O2 / 1 mol LiClO4 4.704 mol LiClO4 = 9.408 mol O2

The moles of O2 under the specified conditions must then be converted to volume. The ideal gas law, which goes as follows:

PV = nRT

Where:

P = pressure = 101.5 kPa

V = volume (in liters)

n = moles of gas = 9.408 mol

R = ideal gas constant = 8.314 J/(mol·K)

T = temperature = 21°C = 294 K (converted to Kelvin)

Rearranging the equation to solve for V:

V = (nRT) / P

V = (9.408 mol × 8.314 J/(mol·K) × 294 K) / (101.5 kPa × 1000 Pa/kPa)

Simplifying the units:

V = (9.408 × 8.314 × 294) / 101.5

V ≈ 220.84 liters

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