Answer: 165.5%
Step-by-step explanation: The increase from 2 days ago to yeaterday was 65.8 ounces. 65.8 is 165.5% of 43.1.
Sharon is a real estate agent. She receives a weekly salary of $450 plus 8% commission on her real estate sales. Last week, she sold a $225.000 house. How much did Sharon earn last week? Show all working. (3pts)
Answer:
$18,450
Step-by-step explanation:
Weekly salary = $450
This is a fixed amount regardless of whether she sells a house or not
The house she sold last week was $225,000
Her 8% commission works out to 225,000 x 8/100
= $18,000
So total that Sharon earned last week = $18,000 + $450 = $18,450
1. Luzcel real estate owns 8000 square meters of lot area and decides to construct two different styles of houses, B and C. The lot area of house B is 250 sq. m. and house C lot area is 200 sq. m. The construction engineer has a maximum of 6400 man-hours of labor for the construction. Let your variables be the number of units of house B and the number of units of house C to be constructed. a) Write an inequality which states that there are 8000 sq. m. of land available. b) A unit of house B requires 160 man-hour and a unit of house C requires 256 man-hour. Write an inequality that the engineer has at most 6400 man-hour available for construction. c) If material cost 600 thousand pesos for a unit of house B and 800 thousand for a unit of house C, write an inequality stating that the engineer has at least 12 million pesos to spend for materials. d) Labor cost 1.1 million pesos for constructing a unit of house B and 1.3 million pesos for constructing a unit of house C. If a unit of house B sells for 3.5 million and a unit of house C selis for 4 million, how many units of house B and house C should be constructed to obtain the maximum profit? Show the graph.
Inequality stating that there are 8000 sq. m. of land available: Let B be the number of units of house B and C be the number of units of house C.
Therefore,B+C ≤ 8000/200 [Reason: House C requires 200 sq. m. of land]⇒B+C ≤ 40b. Inequality that the engineer has at most 6400 man-hour available for construction:
160B + 256C ≤ 6400c
Inequality stating that the engineer has at least 12 million pesos to spend for materials:
600B + 800C ≤ 12000d
. Let us write down a table to calculate the cost, income and profit as follows:Units of house BLabor Hours per unit of house BUnits of house CLabor Hours per unit of house CTotal Labor HoursMaterial Cost per unit of house BMaterial Cost per unit of house CTotal Material CostIncome per unit of house BIncome per unit of house C
Total IncomeTotal ProfitBC=8000/200-B160CB+256C600000800000+256C12,000,0003,500,0004,000,0003,500,000B+C ≤ 40 160B + 256C ≤ 6400 600B + 800C ≤ 12000 Units of house B requires 160 man-hour and a unit of house C requires 256 man-hour.
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A bag contains 10 yellow cubes, 5 red cubes, and 15 blue cubes. Determine whether the following event is impossible, unlikely, as likely as not, likely, or certain.
A red cube is randomly drawn from the bag.
Answer:
I would say likely.
Step-by-step explanation:
I hope this helps.
1. IF HEIGHTS OF FEMALE COLLEGE STUDENTS ARE NORMALLY DISTRIBUTED WITH A MEAN OF 64 INCHES AND A STANDARD DEVIATION OF 10 INCHES, WHAT IS THE PROBABILITY OF RANDOMLY SELECTING A FEMALE COLLEGE STUDENT WITH A HEIGHT LESS THAN 63 INCHES.
2. WHAT IS THE PROBABILITY OF RANDOMLY SELECTING A FEMALE COLLEGE STUDENT WITH A HEIGHT BETWEEN 61 AND 69 INCHES?
3. WHAT IS THE PROBABILITY OF FINDING AN AVERAGE OF GREATER THAN 65 INCHES WITH A SAMPLE OF 35 FEMALE COLLEGE STUDENTS?
a)0.1587 (or 15.87%)
b)0.6827 (or 68.27%)
c)0.0228 (or 2.28%)
1. Using the Normal Distribution formula with a mean (μ) of 64 inches and standard deviation (σ) of 10 inches, the probability of randomly selecting a female college student with a height less than 63 inches is 0.1587 (or 15.87%).
2. Using the Normal Distribution formula with a mean (μ) of 64 inches and standard deviation (σ) of 10 inches, the probability of randomly selecting a female college student with a height between 61 and 69 inches is 0.6827 (or 68.27%).
3. Using the Central Limit Theorem, the probability of finding an average of greater than 65 inches with a sample of 35 female college students is 0.0228 (or 2.28%).
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Okay ive been stuck on this for 30 minutes what is 2+2+?
Reflect triangle A in the line y=1
(a) Cotvert π/4 ndians to degree measure. (b) Convert −30∘ to radian measure in terms of it. radians Arsuver the tollowing, (a) Find an angle between 0∘ and 360∘ that is ccterminal with 1170∘. (b) Find an angle between 0 and 2π that is coterminal with −5π. Give exact values for your answers.
An angle between 0° and 360° that is coterminal with 1170° is 90° and an angle between 0 and 2π that is coterminal with -5π is π.
Convert π/4 radians to degree measure.
We know that 1 radian is equal to 180/π degrees.
Therefore, π/4 radians will be equal to (π/4) × (180/π) degrees=45 degrees
Therefore, π/4 radians is equal to 45 degrees
Convert -30° to radian measure in terms of π.
We know that 180° is equal to π radians.
Therefore, 1 degree is equal to π/180 radians.
So, -30° will be equal to -30 × (π/180) radians= -π/6 radians
Therefore, -30° is equal to -π/6 radians.
We know that angles that differ by multiples of 360° are coterminal.
Therefore, to find an angle between 0° and 360° that is coterminal with 1170°,
we can subtract multiples of 360° from 1170° until we get an angle between 0° and 360°.
1170° - 360° = 810°
810° - 360° = 450°
450° - 360° = 90°
Therefore, an angle between 0° and 360° that is coterminal with 1170° is 90°.
We know that angles that differ by multiples of 2π are coterminal.
Therefore, to find an angle between 0 and 2π that is coterminal with -5π,
we can add or subtract multiples of 2π from -5π until we get an angle between 0 and 2π.
-5π + 2π = -3π
-5π + 4π = -π
Therefore, an angle between 0 and 2π that is coterminal with -5π is π.
In conclusion, we have learned how to convert radians to degrees and degrees to radians, how to find an angle between 0° and 360° that is coterminal with a given angle, and how to find an angle between 0 and 2π that is coterminal with a given angle. These concepts are important in trigonometry, calculus, and other areas of mathematics.
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how many moles are in a 9.00 cm × 9.00 cm × 9.00 cm cube of copper?
There are 11.66 moles of copper in a 9.00 cm x 9.00 cm x 9.00 cm cube.
To determine the number of moles of copper in a cube, we need to know the volume of the cube and the density of copper.
The volume of the cube can be found using the formula for the volume of a cube:
V = l x w x h
where l, w, and h are the length, width, and height of the cube, respectively. In this case, l = w = h = 9.00 cm, so:
V = 9.00 cm x 9.00 cm x 9.00 cm = 729 cm³
Next, we need to find the density of copper. According to the periodic table, the density of copper is 8.96 g/cm³.
Finally, we can use the density and volume to determine the number of moles of copper in the cube. We can do this by multiplying the density by the volume and then dividing by the molar mass of copper:
moles = (density x volume) / molar mass
moles = (8.96 g/cm³ x 729 cm³) / 63.55 g/mol
moles = 11.66 mol
So, there are 11.66 moles of copper in a 9.00 cm x 9.00 cm x 9.00 cm cube.
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Learn what an identity matrix is and about its role in matrix multiplication. ... How do you find the multiplicative inverse of a given matrix?
Answer:
See below
Step-by-step explanation:
\(I_1=[1],\, I_2=\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right],\,I_3=\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right],\,...\) and so on are examples of identity matrices.
The multiplicative inverse of a 2x2 matrix is \(\displaystyle A^{-1}=\frac{1}{ad-bc}\left[\begin{array}{ccc}d&-b\\-c&a\\\end{array}\right]\) where ad-bc represents the determinant. Multiplying this with the original matrix will produce the identity matrix as described previously. Usually, you'll mostly deal with 2x2 matrices when it comes to this topic, but don't worry too much.
The parallelogram shown below has an area of 54 units
9
8
h
Find the missing height.
h =
units
Answer:
h = 6 units
Step-by-step explanation:
area of a parallelogram = bh
where:
area = 54 sq. units
b = 9 units
h = ? units
plugin values into the formula:
54 = 9 (h)
h = 54 / 9
h = 6 units
A security car is parked 25 ft from a movie theater. Find at what speed the reflection of the security strobe lights is moving along the wall of the movie theater when the reflection is 30 ft from the car. The strobe lights are rotating with the speed 2 revolutions per second.
Answer:
v=20π ft/s
Step-by-step explanation:
Given:
Distance from the security car to the movie theater, D=25 ft
Distance of the reflection from the car, d=30 ft
Speed of rotation of the strobe lights, 2 rev/s
To find the speed at which the reflection of the security strobe lights is moving along the wall of the movie theater, we need to calculate the linear velocity of the reflection when it is 30 ft from the car.
We can start by finding the angular velocity in radians per second. Since the strobe lights rotate at 2 revolutions per second, we can convert this to radians per second.
ω=2πf
=> ω=2π(2)
=> ω=4π rad/s
The distance between the security car and the reflection on the wall of the theater is...
r=30-25= 5 ft
The speed of reflection is given as (this is the linear velocity)...
v=ωr
Plug our know values into the equation.
v=ωr
=> v=(4π)(5)
∴ v=20π ft/s
Thus, the problem is solved.
The speed of the reflection of the security strobe lights along the wall of the movie theater is 2π ft/s.
To solve this problem, we can use the concept of related rates. Let's consider the following variables:
x: Distance between the security car and the movie theater wall
y: Distance between the reflection of the security strobe lights and the security car
θ: Angle between the line connecting the security car and the movie theater wall and the line connecting the security car and the reflection of the strobe lights
We are given:
x = 25 ft (constant)
y = 30 ft (changing)
θ = 2 revolutions per second (constant)
We need to find the speed at which the reflection of the security strobe lights is moving along the wall (dy/dt) when the reflection is 30 ft from the car.
Since we have a right triangle formed by the security car, the movie theater wall, and the reflection of the strobe lights, we can use the Pythagorean theorem:
x^2 + y^2 = z^2
Differentiating both sides of the equation with respect to time (t), we get:
2x(dx/dt) + 2y(dy/dt) = 2z(dz/dt)
Since x is constant, dx/dt = 0. Also, dz/dt is the rate at which the angle θ is changing, which is given as 2 revolutions per second.
Plugging in the known values, we have:
2(25)(0) + 2(30)(dy/dt) = 2(30)(2π)
Simplifying the equation, we find:
60(dy/dt) = 120π
Dividing both sides by 60, we get:
dy/dt = 2π ft/s
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PLS HELP!! What is the value of x?
Answer:
Generally, the algebraic expression should be any one of the forms such as addition, subtraction, multiplication and division. To find the value of x, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to find the result. Therefore, the value of x is -10.
Step-by-step explanation:
I hope you can please mark me as
Solve the inequality 3x + 8 = 5x
2
O2 < -5
O x < 5
Os > 5
OX > -5
The function below represents the annual interest Charlotte earns on a savings account. Identify the term that represents the interest rate.
f(x) = 1,000(1 + 0.04)x
a:1000
b:1
c:0.04
d:x
Answer: C.
Step-by-step explanation:
0.04 is the interest rate because it is equivalent of 4%.
Answer: 0.04
Step-by-step explanation:
What is the ratio of 2000g : 5kg
The ratio of two numbers can be calculated as the division of those two numbers, expressed in simplest form.
Then, to calculate the ratio of 2000g : 5kg, we express 2000g as 2 Kg, then the ratio is:
2kg/5kg = 2/5
Answer: 2:5
Step-by-step explanation: 2000:5000= 2000/5000= 2/5= 2:5
what does it mean to say that an event has a timebox? (choose the best answer) a. the event must happen by a given time. b. the event must happen at a set time. c. the event must take at least a minimum amount of time. d. the event can take no more than a maximum amount of time.
The correct option d. the event can take no more than a maximum amount of time, described the an event has a timebox.
Define the term timebox?A timebox is a set amount of time during which a work must be completed in agile software development.
Timeboxes are frequently employed to control risk in software development. Development teams are frequently given a deadline of a certain number of weeks and requested to produce a releaseable update to software.Giving an activity a set, maximum amount of time is known as timeboxing. A time box is the name of that unit of time. The purpose of timeboxing is to specify and set a time restriction for each task. Timeboxing is a technique used by Scrum to concretely define ambiguous or open-ended tasks as well as for all Scrum events.Thus, when an event has a timebox, it signifies that the event can only last a certain length of time.
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Express 660 parts per million as a percentage (answer must be numeric, no units or commas, include a leading zero when answer is less than 1)
When expressed as percentage, 660 parts per million will equal to 0.0066%.
Part per million (ppm) should be multiplied by 0.001 of it could be divided by 10000 to convert it into percentage. In order to convert 660 ppm to a percentage, divide it by 10,000, which yields 0.066.
This needs to be multiplied by 100 to achieve the final result of 0.066%, which is how we may describe it as a percentage. Because the answer is less than 1%, you'll see that we added a leading zero.
As a result, the answer is 0.066%.
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Write an equation in slope-intercept form which has a slope of 1/4 and crosses the Ÿ-axis at (0,7)
Answer:
y= 1/4 x +7
Step-by-step explanation:
The slope intercept form of a line is
y = mx + b where m is the slope and b is the y intercept
the slope is 1/4 and the y intercept is 7
y= 1/4 x +7
Determine whether the relationship is an inverse variation or not. Explain
X y
2 630
3 420
5 252
.A.The product xy is constant, so the relationship is an inverse variation.
B.The product xy is not constant, so the relationship is an inverse variation.
C.The product xy is not constant, so the relationship is not an inverse variation.
D.The product xy is constant, so the relationship is not an inverse variation
The correct answer is option A: "The product xy is Constant, so the relationship is an inverse variation."
To determine whether the relationship between the values of x and y in the given table is an inverse variation or not, we need to examine the behavior of the product xy.
Let's calculate the product xy for each pair of values:
For x = 2, y = 630, xy = 2 * 630 = 1260.
For x = 3, y = 420, xy = 3 * 420 = 1260.
For x = 5, y = 252, xy = 5 * 252 = 1260.
From the calculations, we can observe that the product xy is constant and equal to 1260 for all the given values of x and y.
Based on this information, we can conclude that the relationship between x and y in the table is an inverse variation. In an inverse variation, the product of the variables remains constant. In this case, regardless of the specific values of x and y, their product xy consistently equals 1260.
Therefore, the correct answer is option A: "The product xy is constant, so the relationship is an inverse variation."
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someone please help me!!!!!
Answer:
5.8
Step-by-step explanation:
2x + 9.4 = 21
2x = 21 - 9.4
2x = 11.6
x = 11.6/2
x = 5.8
What is the value of this expression when t = -12? -3|t − 8| + 1.5
Answer:
-59.5
Step-by-step explanation:
We are given the expression
-3|t − 8| + 1.5
t = -12
Subtituting -12 for t in the expression, we have:
-3|-12 - 8| + 1.5
-3|-20| + 1.5
Note : |-20| = 20
-3 × 20 + 1.5
= -60 + 1.5
= -59.5
The value of the expression = -59.5
What is the area of the shaded sector giving circle Q has a diameter of 10
Answer:
A
Step-by-step explanation:
dont know just trust me
quick im sweatinggggggg
Answer:
The answer is 10^5
Step-by-step explanation:
10^5 is 100,000 and 1200 divided by 100,000 equals 0.012.
4. 48 × 105. 480Which property is used to go from Step 1 to Step 2?A.Commutative Property of MultiplicationB.Distributive PropertyC.Associative Property of AdditionD.Associative Property of Multiplication
Answer:
The answer is A).
Step-by-step explanation:
The equation swaps 48 from 25
you are solving a measurement problem where the numbers 5.07 x 109 and 1.087 x 10−4 are divided. how many significant digits should the quotient have?
The division of the two numbers in scientific notation 5.07 × 10⁹ ÷ 1.087 × 10⁻⁴ is 4.664 × 10¹³
Scientific NotationScientific notation is a means in which we use to represent numbers based on a standard measure.
In this problem, we have to perform a mathematical operation with two numbers expressed in scientific notation.
To divide 5.07 × 10⁹ by 1.087 × 10⁻⁴;
We need to divide 5.07 by 1.087
The result given is 5.07 ÷ 1.087 = 4.664
The second step is to note that when 10⁹ ÷ 10⁻⁴,
Using law of indices, it becomes 10⁹ ÷ 10⁻⁴ = 10⁽⁹⁺⁴⁾ = 10¹³
We can now rewrite our answer as
5.07 × 10⁹ ÷ 1.087 × 10⁻⁴ = 4.664 × 10¹³
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Here is a list of five numbers.98^53 98^64 98^73 98^88 98^91Find the lowest common multiple of these five numbers.
Answer:
98^91
Step-by-step explanation:
Since the base of all the numbers is 98,
the LCM is simply the one with the greatest exponent
example
98^53 * 98^38 = 98^91
Divide. Write your answer as a fraction or mixed number in simplest form.
9 1/6 divided by 5
Answer:
Answer = 3 1/30
Step-by-step explanation:
91/6 x 1/5 = 91/30
divide = 3 1/30
In the form of mixed number we can write the statement as - \($1\frac{5}{6}\).
We have \(9\frac{1}{6}\) divided by 5.
We have to write the answer as fraction in mixed form.
What is a Mixed Number?A number consisting of an integer and a proper fraction is called a Mixed Number.
According to the question, we have - \(9\frac{1}{6}\) divided by 5
Let A = \(9\frac{1}{6}\) divided by 5.
Now -
A = \(9\frac{1}{6}\) divided by 5
A = \(\frac{55}{6}\) ÷ 5
A = \($\frac{\frac{55}{6} }{5}\)= \(\frac{11}{6}\) = \($1\frac{5}{6}\)
Hence, in the form of mixed number we can write the statement as - \($1\frac{5}{6}\).
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Let there be two players in a game, Player 1 and Player 2. Consider a jar containing 3 snakes. 2 of the snakes in the jar are venomous, while the remaining 1 is non-venomous. In the game, both the players have to put their hand in the jar one after the other and pick a snake out. Each snake, if picked out of the jar, will bite the player's hand. The event of picking a venomous snake, or equivalently, a venomous snake's bite will earn the player zero points. On the other hand, the event of picking a non-venomous snake, or equivalently, a non-venomous snake's bite will earn the player one point. Let X denote Player 1's pick and let y denote Player 2's pick. Suppose Player 1 is the first to pick out a snake. The expected value of Player 1's pick is: E(X)= (Express your answer as a fraction or round your answer to two decimal places.) The expected value of Player 2's pick is: E(Y)= (Express your answer as a fraction or round your answer to two decimal places.) Which of the following statements describes the relationship between E(X) and E(Y) in this example? O A. E(Y) is greater than E(X) as there is a greater possibility that Player 1 picks up a venomous snake. B. E(X) is greater than E(Y) because Player 1 has an advantage of picking first. C. E(X) and E(Y) are independent of each other. Their values do not reflect anything about their relationship. D. E(X) and E(Y) are equal, so the order in which the players pick a snake is irrelevant.
Player 1's expected value (E(X)) is lower than Player 2's expected value (E(Y)) in the snake-picking game due to the higher probability of Player 1 picking a venomous snake. Therefore, statement A is correct, stating that E(Y) is greater than E(X) because there is a greater possibility of Player picking up a venomous snake.
The expected value of Player 1's pick (E(X)) in the snake-picking game can be calculated, and the expected value of Player 2's pick (E(Y)) can also be determined. The relationship between E(X) and E(Y) depends on the probabilities associated with picking a venomous or non-venomous snake.
In this scenario, Player 1 has the advantage of picking first. To calculate E(X), we need to consider the probabilities of picking a venomous snake (earning zero points) or a non-venomous snake (earning one point). Since there are 2 venomous snakes and 1 non-venomous snake, the probability of Player 1 picking a venomous snake is higher. Therefore, E(X) will be less than E(Y).
The correct answer is A. E(Y) is greater than E(X) as there is a greater possibility that Player 1 picks up a venomous snake. The order in which the players pick the snakes affects the probabilities and, consequently, the expected values. Player 2 has a better chance of picking a non-venomous snake since Player 1 might have already picked a venomous snake, increasing the likelihood of E(Y) being higher than E(X).
Thus, the relationship between E(X) and E(Y) in this example is that E(Y) is greater than E(X) due to the higher possibility of Player 2 picking a non-venomous snake after Player 1's turn.
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for hayabusa Brainly
\( \frac{1}{3} \times \frac{2}{7} \)
_________
\( \: \)
\( \frac{1}{3} \times \frac{2}{7} = ...\)
\( = \frac{1 \times 2}{3 \times 7} \)
\( = \bold{ \frac{2}{21}} \)
Note :
Thanks
_________
\( \: \)
\( \frac{1}{3} \times \frac{2}{7} = ...\)
\( = \frac{1 \times 2}{3 \times 7} \)
\( = \bold{ \frac{2}{21}} \)
Note :
Thanks
Question 3 The bus impedance matrix of a four-bus network with values in per unit is j0.15 j0.08j0.04 j0.07 j0.08 j0.15 j0.06j0.09 Z bus j0.04 j0.06 j0.13 j0.05 j0.07 j0.09 j0.05 j0.12 have their subtransient reactances Generators connected to buses and included in Zbus. If prefault current is neglected, find the subtransient current in per unit in the fault for a three-phase fault on bus 4. Assume the voltage at the fault is 1.0/0° per unit before the fault occurs. Find also the per-unit current from generator 2, whose subtransient reactance is 0.2 per unit. =
To find the subtransient current in per unit for a three-phase fault on bus 4, we need to calculate the fault current using the bus impedance matrix.
Given bus impedance matrix Zbus:
| j0.15 j0.08 j0.04 j0.07 |
| j0.08 j0.15 j0.06 j0.09 |
| j0.04 j0.06 j0.13 j0.05 |
| j0.07 j0.09 j0.05 j0.12 |
To find the fault current on bus 4, we need to find the inverse of the Zbus matrix and multiply it by the pre-fault voltage vector.
The pre-fault voltage vector V_pre-fault is given as:
| 1.0/0° |
| 1.0/0° |
| 1.0/0° |
| 1.0/0° |
Let's calculate the inverse of the Zbus matrix:
Zbus_inverse = inv(Zbus)
Now, we can calculate the fault current using the formula:
I_fault = Zbus_inverse * V_pre-fault
Calculating the fault current, we have:
I_fault = Zbus_inverse * V_pre-fault
Substituting the values and calculating the product, we get:
I_fault = Zbus_inverse * V_pre-fault
= Zbus_inverse * | 1.0/0° |
| 1.0/0° |
| 1.0/0° |
| 1.0/0° |
Please provide the values of the Zbus matrix and the pre-fault voltage vector to obtain the specific values for the fault current and the per-unit current from generator 2.
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