Hello!
\(\boxed{1 : 1}\)
The number of field lines in a given area does NOT depend on how far the region is away from a source charge.
The number of field lines depends SOLELY on the strength of the charge of the source. Therefore, the amount of field lines encompassed by a shell of radius 'R' and radius '2R' is the same.
The ONLY thing that changes as a result of increased distance is the spacing between the electric field lines which signifies the decreasing electric field strength as you move farther away from the source charge.
The ratio of the number of field lines through the larger sphere to the number through the smaller sphere is 4:1.
According to Gauss's law, the electric flux through a closed surface is proportional to the enclosed charge. In the case of a point charge surrounded by spherical shells, the electric flux through each shell is proportional to the charge enclosed by that shell.
Let's consider the two spherical shells:
Smaller Sphere (Radius R): The enclosed charge is the same as the point charge, let's call it Q. The electric flux through the smaller sphere is proportional to Q.Larger Sphere (Radius 2R): The enclosed charge is still the same point charge Q. The electric flux through the larger sphere is also proportional to Q.Since the charge enclosed by both spheres is the same (Q), the electric flux through both spheres will be the same.
Now, let's consider the field lines. The electric field lines originate from the point charge and spread out in all directions. As they pass through the spherical shells, they will intersect the shells perpendicularly. Since the electric flux is the product of the electric field and the area, the number of field lines passing through a particular area on the shell is proportional to the area.
The larger sphere has a larger surface area (4 times the surface area of the smaller sphere), but the electric flux through both spheres is the same. This means that the number of field lines through the larger sphere is four times the number of field lines through the smaller sphere.
So, the ratio of the number of field lines through the larger sphere to the number through the smaller sphere is 4:1.
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A piano has a mass of 99 kg. What is the weight of the piano?
Explanation:
weight of the piano = mg
w = 99 x 10 =990 N
HELP
as shown in the diagram, points p,q, and r are located near a positively charged object.
The air to fuel ratio (AFR) is an important metric when discussing the combustion of a hydrocarbon fuel and fired heaters. if a company were to completely combust n-heptane in air for energy, meaning no side reactions occur,
a) find the AFR assuming total combustion
b)find heat of combustion for this reaction at 25°C and 1 atm
c) find AFR assuming 120% excess air in the reaction
d) find the heat of combustion for this reaction assuming 120% excess air at 25°C and 1 atm
a) The air to fuel ratio (AFR) for complete combustion of n-heptane is approximately 14.6:1.
b) The heat of combustion for n-heptane at 25°C and 1 atm is approximately 48.7 MJ/kg.
c) Assuming 120% excess air in the reaction, the AFR would be approximately 17.3:1.
d) The heat of combustion for n-heptane with 120% excess air at 25°C and 1 atm is approximately 48.7 MJ/kg.
The air to fuel ratio (AFR) is the ratio of the mass of air to the mass of fuel required for complete combustion. In the case of n-heptane, a hydrocarbon fuel, if complete combustion occurs, it means that all the fuel reacts with the available oxygen in the air without any side reactions.
a) To find the AFR for complete combustion, we need to consider the stoichiometry of the reaction. For n-heptane, the balanced chemical equation is \(C_7H_1_6 + 11O_2 \geq 7CO_2 + 8H_2O\). From this equation, we can see that 1 mole of n-heptane requires 11 moles of oxygen. Since air contains about 21% oxygen by volume, the AFR can be calculated as 1/(0.21*11) = approximately 14.6:1.
b) The heat of combustion is the amount of heat released when one unit mass of a substance undergoes complete combustion. The heat of combustion for n-heptane at 25°C and 1 atm is approximately 48.7 MJ/kg.
c) Assuming 120% excess air means providing 120% more air than the stoichiometric requirement. In this case, the AFR would be calculated as (1 + 1.2)/(0.21*11) = approximately 17.3:1.
d) The heat of combustion remains the same, regardless of the excess air. Therefore, the heat of combustion for n-heptane with 120% excess air at 25°C and 1 atm is approximately 48.7 MJ/kg.
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Two balls at the ends of two strings are moving at the same
speed in horizontal circular paths. One string is three times
as long as the other. Compare the magnitudes of the two
centripetal accelerations.
Answer:
Fc = M v^2 / R centripetal acceleration
Fc2 / Fc1 = R1 / R2 since M and v are the same for both
If R2 = 3 R1 then the centripetal acceleration for particle 2 will be 1/3 of that of innermost (R1) particle
if you immerse an object into a known mass of water, the measured mass of the water will _____, and will be equal to the mass of the water displaced by the immersed object.
Answer: decrease
Explanation: it does
2A 5-kilogram rocket is projected upward from rest by an engine/applied force equivalent to 80-Newtons. After firing for 4-seconds the engine turns off. A. Draw and label all of the forces acting on the rocket at each of the intervals shown above. B. Determine the initial upward acceleration of the rocket during the first 4-seconds.
Answer:
(A). The force acting on the rocket is mg.
(B). The initial upward acceleration of the rocket is 6.2 m/s²
Explanation:
Given that,
Mass of rocket = 5 kg
Force = 80 N
Time = 4 sec
(A). We need to draw the figure
The force acting on the rocket at each of the intervals is shown in figure.
The force acting on the rocket is mg.
(B). We need to calculate the initial upward acceleration of the rocket
Using balance equation
\(ma=F-mg\)
\(a=\dfrac{F-mg}{m}\)
Put the value in the equation
\(a=\dfrac{80-5\times9.8}{5}\)
\(a=6.2\ m/s^2\)
Hence, (A). The force acting on the rocket is mg.
(B). The initial upward acceleration of the rocket is 6.2 m/s²
How does a concave mirror form an image
A) it bends the light toward a focal point
B) it bends the light away focal point
C) it bounces the light towards a focal point
D) it bounces the light away from a focal point
Answer:
The correct option is (c) "it bounces the light towards a focal point"
Explanation:
There are two types of spherical mirrors i.e. concave and convex.
A concave mirror is a type of spherical mirror that is curved inwards. For this type of mirror the rays of light are bounced back and converge to the focal point of the mirror.
So, the correct option is (c).
Answer:
c
Explanation:
A massive light hangs over the table in Jeremy's dining room. The light is supported by four strong chains which make an angle of 72° with the horizontal. The force in each chain is 36.4 N. Determine the mass of the light in kilograms (kg). Use the approximation g ≈ 10 m/s^2.
Given
A massive light hangs over the table in Jeremy's dining room. The light is supported by four strong chains which make an angle of 72° with the horizontal.
The force in each chain is F=36.4 N.
To find
The mass of the light in kg
Explanation
Let the mass of the light be m
The weight of the light acts downwards.
To balance thisi force the force on the string vertically upward is considered
In equillibrium
\(\begin{gathered} mg=4Fsin72^o \\ \Rightarrow10m=4\times36.4\times sin72^o \\ \Rightarrow m=13.84\text{ kg} \end{gathered}\)Conclusion
The mass of the light is 13.84 kg
In which region of the electromagnetic spectrum does 1280nm radiation occur?
A. Ultraviolet
B. Infrared C. Visible
D. Microwaves
Infrared region of the electromagnetic spectrum does 1280nm radiation occur.
1280 nm radiation occurs in the infrared region of the electromagnetic spectrum. Infrared radiation has wavelengths longer than those of visible light, but shorter than those of microwaves. It is often referred to as "heat radiation" because it is associated with the thermal energy of an object.
Infrared radiation is used in a wide range of applications such as thermal imaging cameras, remote sensing, and in the production of heat lamps. It is also used in communication systems such as TV remote controls and in some fiber optic communications. In addition, infrared radiation is used in medical applications such as infrared thermography, where it is used to detect and diagnose a range of medical conditions.
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The Earth's diameter at the equators is ____ its diameter at the poles.
equal to
less than
greater than
which two technologies use waves to determine the location and velocity of objects
Lenses
X Rays
Sonar
Radar
Answer: sonar and radar
Explanation:
Picture
You have a working electrical parallel circuit with three light bulbs, then 1 bulb burns
out.
Describe how electric current flows through the parallel circuit after 1 of the 3 bulbs
burns out?
Answer:
but the answer should be no as if 3 bulbs are connected together if one burns out the whole circuit will stop .hope you understood
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which gmaw electrode wire is most commonly used and works great with co2
The most commonly used GMAW electrode wire that works great with CO₂ is ER70S-6.
Gas Metal Arc Welding (GMAW), also known as MIG (Metal Inert Gas) welding, uses an electrode wire to create an arc that melts and fuses the base metal. The electrode wire, also referred to as the filler wire, plays a crucial role in the welding process.
ER70S-6 is a widely used electrode wire in GMAW applications and is particularly suitable for welding with CO₂ as the shielding gas. It is a solid wire composed of mild steel with specific chemical compositions to provide excellent welding performance and desirable mechanical properties.
The "ER" in the designation stands for Electrode or Rod, "70" represents the tensile strength in ksi (kilo-pounds per square inch), and "S-6" indicates its suitability for general-purpose welding.
ER70S-6 wire offers good arc stability, smooth bead appearance, and low spatter levels, making it highly versatile and suitable for various welding projects. When used with CO₂ as the shielding gas, it provides good penetration, strong welds, and high deposition rates. CO₂ is a commonly used shielding gas in GMAW due to its availability and affordability.
It's important to note that the choice of electrode wire may vary depending on the specific welding application, base metal, and desired welding characteristics. Consulting welding guidelines and considering factors such as material type, joint design, and welding parameters will help determine the most appropriate electrode wire for a particular welding task.
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How is a projectile different from an object in free fall
Answer:
Explanation:
Projectile Motion. Projectile motion is different than free fall: it involves two dimensions instead of one. ... Balls traveling in two dimensions, only one of which experiences acceleration, require two sets of equations: one set for the x-direction and the other for the y-direction.
a man has a mass of 70kg. Calculate his weight on earth where the gravitational strength is 10 N/kg
Answer:
So the weight of the body is 700N
Explanation:
mass of the object=70kg
force of gravity=10N/kg
weight of the object=w-?
as we know that
weight=mass × force of gravity
weight=70kg × 10N/kg
WEIGHT OF THE BODY=700N
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The correct answer is 700 N.
Object mass = 70 kg
Gravity = 10N / kg
Weight = Mass x Gravity
Weight = 70kg x 10N / kg
Weight = 700 N
What is the gravity for a mass of 10kg?Mass is more basic because it is a unique property of the object. Weight varies from place to place depending on the acceleration of gravity. If the mass on the earth is m = 10kg, the weight is W = mg = 10 x 10 = 100N.
The strength of the Earth's gravitational field is 10 Newtons (N / kg) per kilogram. This means that there is a force of 10 Newtons per kilogram on Earth. Mass is the amount of substance that makes up an object.
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An object with a mass of 25 kg is on a free fall from a plane.
a. Calculate the force attracting it to the Earth. Would this force be different in Mars?
Gravitational field strength: 10 N/kg
Answer:
a) F = 250 [N]
Explanation:
Force can be calculated by means of Newton's second law, which tells us that force is the product of mass by acceleration.
a)
F = m*a
where:
F = force [N]
m = mass = 25[kg]
a = gravity acceleration = 10 [m/s²]
F = 25*10 = 250 [N]
Yes, this force would be different on Mars, since the gravitational acceleration of Mars is different from that of Earth.
gm = Martian gravity = 3.72 [m/s²]
Fm = 3.72*25 = 93 [N]
A wire is placed between the poles of a horseshoe magnet. There is a current in the wire in the direction shown, and this causes a force to act on the wire.
What way is more effective when trying to make magnets repel further/faster, using strong magnets over weak magnets or putting the magnets closer together?
Answer:
north pole of a magnet repels the north pole of another magnet no matter of their shape , size , weakness , strength ,etc .
Explanation:
The 60-mm-diameter shaft is made of 6061-T6 aluminum. if the allowable shear stress is τallow = 80 mpa , and the angle of twist of disk a relative to disk c is limited so that it does not exceed 0.050 rad , determine the maximum allowable torque t .
The maximum allowable torque for a 60-mm-diameter shaft made of 6061-T6 aluminum, given that the allowable shear stress is τallow = 80 MPa and the angle of twist of disk a relative to disk c is limited so that it does not exceed 0.050 rad is 218.1 Nm.
Explanation:
Given parameters: Diameter of shaft = 60 mm, Shear stress allowable = τallow = 80 MPa, Angle of twist of disk a relative to disk c is limited so that it does not exceed 0.050 rad.
The formula used: The equation for torque is given as, T = (π/16) * τallow * d³ * (θ/L) Where, T = maximum allowable torqueτallow = allowable shear stress = diameter of the shaftθ = angle of twist, L = length of the shaft. According to the problem, the diameter of the shaft is 60 mm. So, the radius will be 30 mm or 0.03 m.
The angle of twist is limited to 0.050 rad. Let's consider the length of the shaft to be 1 m. So, using the formula we get the maximum allowable torque, T = (π/16) * τallow * d³ * (θ/L)T = (π/16) * 80 * (0.06)³ * 0.050/1T = 218.1 NmTherefore, the maximum allowable torque is 218.1 Nm.
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Convert the SI unit:
1000 meters equal to
how many km.
Answer:
1000m=1km
simple :) . . .
Raul ha a cloed container of a ga. He put it in a refrigerator. When it cool, it condene and become a liquid. What happen to the denity of the ga when it condene?
The density of the ga when it condense while put it in a refrigerator, When it cool, it condense and become a liquid, has decreases.
The mass of a material substance per unit volume is referred to as its density. The formula d = M/V, where d stands for density, M for mass, and V for volume, describes density. The measurement for density is grams per cubic centimeter. For instance, water has a density of 1 grams per cubic centimeter as opposed to Earth's density of 5.51 grams. Kilograms per cubic meter is another way to measure density (in meter-kilogram-second or SI units). Density makes it simple to calculate the relationship between mass and volume. For instance, M = Vd is the formula for calculating a body's mass, while V = M/d is the formula for calculating a body's volume.
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A drone drops a package on a target from a height of 2.40\,\text m2.40m2, point, 40, start text, m, end text. The drone is traveling horizontally at a speed of 1.50\,\dfrac{\text m}{\text s}1.50 s m 1, point, 50, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction.
Answer:
1.05m
Explanation:
To get this answer, you must first know how long it takes the ball to reach the ground. In order to figure that out, the process is simple:
First: Multiply the object's height by 2.
2.4x2=4.8
Next: Divide that answer by the speed of Gravity, 9.8 or 9.81m/s^2
(I prefer to use the method used by engineers, attend to precision, so I keep the same number of decimals in each number I am calculating.)
4.8/9.8=0.48979591836734693877551020408163m/s^2
Next: Square Root this answer.
=0.69985421222376517091350973563025
Last: Multiply your square rooted answer by your forward velocity.
0.69985421222376517091350973563025x1.5=
1.0497813183356477563702646034454 or, since Khan Academy only wants three significant digits, round up to 1.05.
Answer:
1.05
Explanation:
what the other guy said trust
Katie is walking in an orange grove. She looks at all of the orange trees. She wants to find out how many seeds are in each orange.
What can she do to collect data?
A.
Measure each tree to see how tall it is.
B.
Gather a few oranges and see how many seeds are in each.
C.
Plant an orange seed and see how much fruit grows on the tree.
D.
Count the number of trees in the grove.
Answer:
What she can do to collect the data is;
B. Gather a few oranges and see how many seeds are in each
Explanation:
The quantity Katie wants to find out is the number of seeds contained in each orange
Therefore, the required population = The number of seeds in a given orange
The method of estimation of the number of seeds per orange is sampling method, whereby the number of seeds in each of the orange in the sample is used to as an hypothesis as to the number of seeds expected in each orange of the entire population.
Therefore, in order to collect the data, she can gather a few oranges and see how many seeds are in each.
What is mass formula?
Answer:
The mass formula is given as
Mass = ρ × v
Where,
ρ = density and
v = the volume
The weight mass formula is given as
m = w / g
Where,
w= weight
m = mass
g = gravity
The mass formula is also given as
m = F / a
If acceleration itself is the gravity, then
M = F / g
Where,
F = force
G = gravity
According to Einstein’s mass-energy relation
m = (E / c2)
Where,
m = mass
E = energy
c = speed of light (3×108 m/s)
The kinetic energy mass formula is given as
K.E = ½ mv2
Where,
m = mass,
v = velocity.
Explanation:
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Draw a diagram to represent conical pendulum in a non inertial frame of reference and state the equation of centrifugal force on the Bob
As the pendulum moves around the circle, the centripetal acceleration remains constant in magnitude but changes in direction. This is because the tangential velocity of the bob changes direction as it moves around the circle, but its speed remains constant.
The centripetal acceleration experienced by the bob of the conical pendulum is given by the formula \(a = v^2/r\),
Since the pendulum is rotating with a constant angular velocity, the tangential velocity is also constant, given by:
v = 2πr/T,
where T is the period of one revolution. The period is 60/20 = 3 seconds since the pendulum makes 20 revolutions per minute.
Thus, v = 2π*2/3 = 4.19 m/s.
Therefore, the centripetal acceleration is \(a = 4.19^2/2 = 8.77 m/s^2.\)
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--The complete Question is, A conical pendulum is set up in a non-inertial frame of reference that is rotating with a constant angular velocity. The length of the string is 2 meters, and the mass of the bob at the end of the string is 0.5 kg. The pendulum makes 20 revolutions per minute. What is the centripetal acceleration experienced by the bob, and how does this acceleration change as the pendulum moves around the circle?--
David drove the first 6 hours of his journey at 65 km / hour and the last 3 hours of his journey at 80 km / hour . How far is the whole journey in km ?
Answer:
630 km.
Explanation:
To obtain the total distance travelled by David, we shall calculate the distance travelled in each, then sum them together.
Case 1:
Speed 1 (S₁) = 65 km / hour
Time 1 (t₁) = 6 hours
Distance 1 (d₁) =?
Speed = Distance /time
S₁ = d₁ / t₁
65 = d₁ / 6
Cross multiply
d₁ = 65 × 6
d₁ = 390 Km
Case 2:
Speed 2 (S₂) = 80 km / hour
Time 2 (t₂ ) = 3 hours
Distance 2 (d₂) =?
Speed = Distance /time
S₂ = d₂ / t₂
80 = d₂ / 3
Cross multiply
d₂ = 80 × 3
d₂ = 240 Km
Finally, we obtained the total distance travelled by David as follow
Distance 1 (d₁) = 390 Km
Distance 2 (d₂) = 240 Km
Total Distance travelled (dₜ) =?
Total distance = distance 1 + distance 2
dₜ = d₁ + d₂
dₜ = 390 + 240
dₜ = 630 km
Therefore, the total distance travelled by David is 630 km
In 2D kinematics, which of the following variables is not a vector and therefore cannot be split into x and y components? 1) Displacement 2) Time 3) Acceleration 4) Velocity
A vector is a mathematical element that represents the segment of a line, with a given orientation, and are usually written like:
v = <x, y>
Here the vector has 2 components, but it can have more.
The correct option is 2: time.
Now we want to see which ones of these can't be written as a vector, let's analyze each one.
1) Displacement.
We can "break" the displacement into displacement in the x-direction and displacement in the y-direction, thus this can be written as a vector.
2) Time.
Time is an independent variable, and it is not a vector (time has a single dimension).
3) Acceleration.
We can break acceleration into an acceleration in the x-direction and acceleration in the y-direction, thus acceleration is a vector.
4) Velocity.
Exactly similar to acceleration, velocity is a vector.
Then the only correct option is 2, Time.
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Place the following into scientific notation...(.000635)
*
What are the two goals of the Artemis Mission?
Answer:
The Artemis program is a U.S. government-funded international human spaceflight program that has the goal of landing the first woman and the next man on the Moon, specifically at the lunar south pole region, by 2024.
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Hyperkinetic means too little movement true or false?
Answer:
false
Explanation: