The magnetic field at the point of the proton moving in the negative direction is equal to 1.84 ×10⁻¹⁴ T.
The magnetic force experienced by the proton moving in the negative direction is equal to 4.71 x 10⁻²⁸ N.
What is the magnetic field due to proton?The magnitude of the magnetic field due to the proton at distance 'r' moving in the negative direction is determined as follows;
F = q.v.B = (kq²)/r²
q.v.B = kq²/r²
B = kq/vr²
Where, k is the coulomb's constant, r is the distance between two protons, q is the charge of the protons, and v is the proton's speed.
Given the charge on the proton, q = 1.602 × 10⁻¹⁹C
The speed of the proton, v = 1.6 × 10⁵ m/s
B = (9 × 10⁹ × 1.602 × 10⁻¹⁹) / (1.6 x 10⁵ m/s × 0.7 × 0.7)
B = 18.39 × 10⁻¹⁵ T
B = 1.84 ×10⁻¹⁴ T
The magnetic force in the negative direction experienced by the proton is calculated as follows;
F = qvB
F = 1.602 × 10⁻¹⁹× 1.6 x 10⁵ × 18.39 × 10⁻¹⁵ T
F = 47.1 × 10⁻²⁹ N
F = 4.71 × 10⁻²⁸ N
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1. Materials through which electricity pass easily are called?
a. Conductors
b. Insulators
c. Non-conductor
d. Metallic
c. Non-conductor
2. Materials that do not transmit electricity and heat are called?
d. Metallic
a. Conductor
b. Insulator
3. When a certain material is considered an insulator? If it
a. Allows the free electrons to tow easily through it.
b. Doesn't allow the tree electron to flow easily through it.
c. Protects the excess electron from getting very hot
d. Gives rise to the production of more electrons
4. How do we describe a conductor of electricity? It is a material that
a. Allows the free electrons to flow easily through it.
b. Has extra free electrons on its surfa
c. Has no free electrons that can move freely
d. Prevents the flow electrons from moving out of the wire.
5. Which of the following group of materials are good conductors of heat and electricity?
a. Copper, silver, gold, glass
b, Iron, copper, silver, gold
c. Wood, paper, cloth, plastic
d. Gold, paper, leather, plastic
6. Why metals are considered good conductors of heat and electricity? Because
a. they are very hard
b. they are heavy
c. they can speedily transfer heat
d. they are smooth
7. Why is copper wire, which is a good conductor covered with rubber?
a. so that it will not melt
b. so that it will look beautiful
c. to make it stronger
d. so that it will not be harmful
8. Which of the following group of materials are good conductors of
electricity?
a. copper, silver, gold, glass, and zinc
b. wood, paper, leather, and plastic
C. iron, copper, silver, gold, and nickel
d.gold, paper, cloth, and plastic
9. Which of the following is most likely to conduct electricity the lastest?
a. wood
b. plastic
d. rubber
C. iron grills
10. The following are good conductors of heat and electricity except.
a. silver spoon
b.golden ring
C. cotton
d. iron bar
Answer:
1. A
2. B
3. B
4. A
5. B
6. C
7. D
8. C
9. C
10. C
Materials through which electricity pass easily are called conductors and material which do not transmit electricity and heat are insulators. Insulators doesn't allow the flow of electrons through it.
What are conductors ?Based on the conductivity of a material, there are three types of materials, namely conductors, semi-conductors and insulators. Conductors are conducting electricity and heat at room temperature. Semi conductors only conduct at higher temperatures or on doping.
The materials which does not conduct electricity and heat are called insulators. Hence, option b is correct. They will never allow the flow of electrons through them and thus why considered as insulators.
Whereas, conductors allow free electrons to flow through them easily. Among the groups , the group of good conductors are Iron, copper, silver, gold.
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EXPLAIN HOW MAGNETIC MATERIALS ARE SEPARATED FROM COAL
A procedure known as magnetic separation can be used to extract magnetic elements from coal.
This method makes use of the magnetic characteristics of some materials to distinguish them from non-magnetic materials like coal. A description of how magnetic separation can be used to remove magnetic components from coal is given below:
Putting a magnetic field around the coal and magnetic material mixture is the first step in the magnetization process. This can be achieved by creating an electromagnetic field or by putting the mixture close to a powerful magnet.
Magnetism: Magnetic materials, such as iron atoms or magnetite that are frequently found in coal, will be drawn to the magnetic field and become magnetized. They line up their magnetic moments with the magnetic field's direction.
Separation: The magnetic coal components can be physically separated from the non-magnetic coal once they have been magnetized. To create this separation, there are numerous techniques:
Magnetic Drum Separator: Using this technique, the mixture is run through a spinning, magnetized drum. The non-magnetic coal can now go along the conveyor belt without being interfered with by the magnetic materials, which adhere to the surface of the drum and are removed from the coal. Magnetic Pulley Separator: This method involves mounting a magnetic pulley at the discharge end of a conveyor belt that is transporting the mixture. The magnetic pulley draws in and gathers the magnetic elements as the belt moves, sending them to a different location for collecting.Magnetic fluid separation includes floating the mixture in a liquid medium and using a magnetic field to draw and separate the magnetic particles. By using filtration or decantation, the magnetic materials can be separated from one another.Learn more about coal from the given link:
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А bus has started to move from
the rest with an acceleration of
0.25 m/s². find its final velocity
During a certain nuclear reaction the total mass of the products is less than the total mass of reactants what happened to the missing mass
Answer: it turns into energy
Explanation: In a nuclear fusion reaction, two reactants combine, and form new products. But the mass of the products is less than total mass of the reactants. This is because a part of mass is lost as energy. This can be seen in an example shown below. You can see that mass is of the products is less than that of the reactants.
Hope This Helps :)
2. If a car is accelerating under a net force of 3674 N, what force must the
brakes exert to cause the car to have constant velocity?*
Answer:
I don't do physics but I think the answer would be -3674
Explanation:
Newton's 2 law of motion
10 points!! Name one type of group of plants that have vascular tissue.
A: tree
B: mosses
which one is right
Answer:
mooses .
Explanation:
because i searched it up for you
Answer:
A. Trees
Explanation:
got 100 on progress learning because im just that guy.
Relationship between Animal and land
A circle has a radius of 20 cm and a central angle that measures 216° find the length of the arc defined by the central angle
Answer:
4320cm
Explanation:
(length of the arc)/(length of the radius)=central angle
lengthof the arc/20=216
lengthof the arc=216×20
length of the arc=4320cm
hope this helps, let me know if I'm right!
The length measured along the arc is called length of the arc. The length of the arc defined by the central angle is 4320cm.
What is central angle?Central angle is the angle subtended by the arc at the center of circle.
central angle = length of the arc / length of the radius
216 = length of the arc/20
length of the arc = 216×20
length of the arc = 4320cm
Thus, the length of the arc defined by the central angle is 4320cm.
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A bug slides back and forth in a bowl 12 cm deep, starting from rest at the top, as shown in Fig. 7.20. The bowl is frictionless except for a 1.8-cm-wide sticky patch on its flat bottom, where the coefficient of friction is 0.83. How many times does the bug cross the sticky region?
The bug will cross the sticky region once in each cycle of its motion, where a cycle is defined as one complete round trip from the top of the bowl to the bottom and back to the top.
To find the number of cycles the bug goes through, we can use conservation of mechanical energy. At the top of the bowl, the bug has only potential energy, which is converted to kinetic energy as it slides down the bowl. At the bottom of the bowl, all of the potential energy has been converted to kinetic energy, and as the bug slides up the other side of the bowl, the kinetic energy is converted back into potential energy. At the top of the bowl again, the bug has only potential energy, and the cycle repeats.
Because there is no friction (except for the sticky patch), the total mechanical energy of the system is conserved. Therefore, the potential energy at the top of the bowl is equal to the potential energy at the bottom of the bowl, and the kinetic energy at the bottom of the bowl is equal to the kinetic energy at the top of the bowl.
We can set the potential energy at the top of the bowl to zero, and use the conservation of energy to find the potential energy at the bottom of the bowl:
mgh = (1/2)mv^2
where m is the mass of the bug, g is the acceleration due to gravity, h is the depth of the bowl, and v is the speed of the bug at the bottom of the bowl.
Solving for v, we get:
v = sqrt(2gh)
Plugging in the numbers, we get:
v = sqrt(29.810.12) = 0.775 m/s
The time it takes for the bug to slide from the top of the bowl to the bottom and back up to the top is twice the time it takes to slide from the top to the bottom:
t = 2sqrt(2h/g) = 2sqrt(2*0.12/9.81) = 0.774 s
Therefore, the frequency of the bug's motion is:
f = 1/t = 1/0.774 = 1.29 Hz
Since the bug completes one cycle in each oscillation, the bug will cross the sticky region 1.29 times per second, or approximately once every 0.78 seconds.
At 3:00 P.M., a bank robber is spotted driving north on I-15 at milepost 124. His speed is 133.0 mi/h. At 3:37 P.M., he is spotted at milepost 181 doing 101.0 mi/h. (Assume a straight highway). Assume north to be positive.What is the bank robber’s displacement during this time interval? Enter a positive value if the displacement is toward north and enter a negative value if the displacement is toward south.
The displacement of an object is defined as a change in the position of the object. If the final position is x_f and the initial position is x_i, the displacement is given by:
\(\Delta x=x_f-x_i\)Since the driver is spotted at the milepost 124 and then at the milepost 181, then the final position is 181 miles, and the initial position is 124 miles.
Substitute those values into the equation to find the displacement:
\(\Delta x=181mi-124mi=57mi\)Then, the change in position was 57 miles towards the North.
Therefore, during that time interval, the bank robber's displacement was 57 miles towards the North. Then, the answer is: 57.
Which correctly describes latent heat?
A. The heat of molecules that are under pressure
B. The heat held inside of ice crystals colder than -2°C
C. The heat absorbed or lost by a substance while it's changing state
D. The heat used to change the temperature of a liquid
Option C. The heat absorbed or lost by a substance while it's changing state correctly describes latent heat
Latent heat is the heat absorbed or lost by a substance while it is changing state.
The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.
For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.
Latent heat is not associated with a temperature change; rather, it's associated with a change of state.
For instance, the temperature of water remains at 100°C while boiling.
When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.
When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.
Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.
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help!!!
middle school physics also please explain :)
Answer:
hope its helps
good luck
Answer:
0.1 cm/s
Explanation:
16 min 40 second = 1000 sec
1m = 100cm
100/1000 = 0.1 (speed = distance/time)
What is the distance Covered by a Car If its accelerator with 5m/s² for 10 sec at Initial Velocity of 3 m/s.
Answer:
To solve for the distance covered by the car, we need to use the kinematic equation:
distance = initial velocity x time + (1/2) x acceleration x time^2
We know that the initial velocity, u, is 3 m/s, the time, t, is 10 sec, and the acceleration, a, is 5 m/s². Substituting these values gives:
distance = (3 m/s) x (10 sec) + (1/2) x (5 m/s²) x (10 sec)^2
distance = 30 m + (1/2) x 5 m/s² x 100 sec²
distance = 30 m + 250 m
distance = 280 m
Therefore, the car covers a distance of 280 meters if its accelerator with 5m/s² for 10 sec at an initial velocity of 3 m/s.
Explanation:
Assume the pipe in the bathroom has a radius 34 cm and the pipe in the chamber has a radius of 45cm.
The Velocit,y Height and flow rate is is mathematically given as
v2= 1.92m/sh=2.06m F= 700kg/sWhat is the flow rate?Generally, the equation for the Continuity equation is mathematically given as
A1v1=A2v2
Therefore
\(v2=\frac{r1^2}{r2^2}v1\)
v2= 1.92m/s
Generally, the equation for Pressure is mathematically given as
the difference is related by
\(P=\rho g h\)
Therefore
\(h=P / \rho g\)
(1000)(9.81)(h)=2*10100
h=2.06m
Generally, the equation for Flow rate is mathematically given as
\(F=\rho Av\)
Therefore
\(F=(1000)\pi (0.45)^2 1.1\)
F= 700kg/s
In conclusion, The resulting solutions are
v2= 1.92m/s
h=2.06m
F= 700kg/s
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. Acylinder contains 1 mole of oxygen at
a temperature of 27 °C. The cylinder
is provided with a frictionless piston
which maintains a constant pressure
of 1 atm on the gas. The gas is heated
until its temperature rises to 127 °C.
(a) How much work is done by the
piston in the process?
(b) What is the increase in internal
energy of the gas?
(c) How much heat was supplied
to the gas?
(C = 7.03 calmol-¹°C¯¹;
R = 1.99 calmol-¹°C-¹;
1cal = 4.184 J)
a}The work is done by the piston in the process is 199 cal.
b) The increase in internal energy of the gas is 703 cal
c) The heat was supplied to the gas is 3771 J
(a) To calculate the work done by the piston, we can use the formula:
Work = P * ΔV
Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:
Work = P * (\(V_2 - V_1\))
Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:
PV = nRT
\(V_1 = (nRT_1) / P_1\)
\(V_2 = (nRT_2) / P_2\)
Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).
Substituting the values into the equation, we have:
V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal
V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal
Therefore, the work done by the piston is:
Work = 1 atm * (796 cal - 597 cal) = 199 cal
(b) The increase in internal energy of the gas can be calculated using the equation:
ΔU = n * C * ΔT
Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).
Substituting the values into the equation, we have:
ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal
(c) The heat supplied to the gas can be calculated using the equation:
Q = ΔU + Work
Substituting the values calculated in parts (a) and (b), we have:
Q = 703 cal + 199 cal = 902 cal
Since 1 cal = 4.184 J, the heat supplied to the gas is:
Q = 902 cal * 4.184 J/cal ≈ 3771 J
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The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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ou have a summer job as an assistant technician for a telephone company in california. during a recent earthquake, a 1.0-mile long underground telephone line is crushed at some point. this telephone line is made up of two parallel copper wires of the same diameter and same length, which are normally not connected. at the place where the line is crushed, the two wires make contact. your boss wants you to find this place so that the wire can be dug up and fixed. you disconnect the line from the telephone system by disconnecting both wires of the line at both ends. you then go to one end of the line and connect one terminal of a 6.0-v battery to one wire, and the other terminal of the battery to one terminal of an ammeter. when the other terminal of the ammeter is connected to the other wire, the ammeter shows that the current through the wire is 1.0 a. you then disconnect everything and travel to the other end of the telephone line, where you repeat the process and find a current of 1/3 a.
The point where the wires make contact is located at a distance of 0.5 miles from the first end of the line or 1.5 miles from the second end of the line. The telephone line can now be dug up and fixed at the location of the point of contact.
The two parallel copper wires of the telephone line act as a closed circuit when they make contact at the point where the line is crushed. By connecting one wire to one terminal of a 6.0-V battery and the other terminal of the battery to an ammeter, the current flowing through the wire can be measured. The current through the wire depends on the voltage of the battery and the resistance of the wire.
At the first end of the line, the current through the wire is 1.0 A when the ammeter is connected to the other wire. By using Ohm's law, we can determine the resistance of the wire at the first end:
Resistance = Voltage / Current = 6.0 V / 1.0 A = 6.0 ohms
At the second end of the line, the current through the wire is 1/3 A when the ammeter is connected to the other wire. Using Ohm's law again, we can determine the resistance of the wire at the second end:
Resistance = Voltage / Current = 6.0 V / (1/3 A) = 18.0 ohms
The resistance of the wire is higher at the second end because the distance between the battery and the point of contact is longer, resulting in greater overall resistance.
To find the location of the point where the wires make contact, we can use the fact that the two wires have the same length and diameter, and are made of the same material. Therefore, the resistance per unit length is the same for both wires. We can set up an equation using the resistance values at each end and the length of the wire to solve for the distance to the point of contact:
Resistance per unit length = Resistance / Length
Using the resistance values we found, we have:
Resistance per unit length = (18.0 ohms - 6.0 ohms) / 1.0 mile = 12.0 ohms/mile
Solving for the distance to the point of contact, we have:
Distance to point of contact = Resistance / (Resistance per unit length)
At the first end, the distance to the point of contact is:
Distance = 6.0 ohms / 12.0 ohms/mile = 0.5 miles
At the second end, the distance to the point of contact is:
Distance = 18.0 ohms / 12.0 ohms/mile = 1.5 miles
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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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Two speakers placed 0.94 m apart produce pure tones in sync with each other at a frequency of 1630 Hz. A microphone can be moved along a line parallel to the line joining the speakers and 9.4 m from it. An intensity maximum is measured a point P0 where the microphone is equidistant from the two speakers. As we move the microphone away from P0 to one side, we find intensity minima and maxima alternately. Take the speed of sound in air to be 344 m/s, and you can assume that the slits are close enough together that the equations that describe the interference pattern of light passing through two slits can be applied here.
Required:
a. What is the distance, in meters, between Po and the first intensity minimum?
b. What is the distance, in meters, between Po and the first intensity maximum?
c. What is the distance, in meters, between Po and the second intensity minimum?
d. What is the distance, in meters, between Po and the second intensity maximum?
Answer:
a. approximately \(1.1\; \rm m\) (first minimum.)
b. approximately \(2.2\; \rm m\) (first maximum.)
c. approximately \(3.4\; \rm m\) (second minimum.)
d. approximately \(4.7\; \rm m\) (second maximum.)
Explanation:
Let \(d\) represent the separation between the two speakers (the two "slits" based on the assumptions.)
Let \(\theta\) represent the angle between:
the line joining the microphone and the center of the two speakers, andthe line that goes through the center of the two speakers that is also normal to the line joining the two speakers.The distance between the microphone and point \(P_0\) would thus be \(9.4\, \tan(\theta)\) meters.
Based on the assumptions and the equation from Young's double-slit experiment:
\(\displaystyle \sin(\theta) = \frac{\text{path difference}}{d}\).
Hence:
\(\displaystyle \theta = \arcsin \left(\frac{\text{path difference}}{d}\right)\).
The "path difference" in these two equations refers to the difference between the distances between the microphone and each of the two speakers. Let \(\lambda\) denote the wavelength of this wave.
\(\displaystyle \begin{array}{c|c} & \text{Path difference} \\ \cline{1-2}\text{First Minimum} & \lambda / 2 \\ \cline{1-2} \text{First Maximum} & \lambda \\\cline{1-2} \text{Second Minimum} & 3\,\lambda / 2 \\ \cline{1-2} \text{Second Maximum} & 2\, \lambda\end{array}\).
Calculate the wavelength of this wave based on its frequency and its velocity:
\(\displaystyle \lambda = \frac{v}{f} \approx 0.211\; \rm m\).
Calculate \(\theta\) for each of these path differences:
\(\displaystyle \begin{array}{c|c|c} & \text{Path difference} & \text{approximate of $\theta$} \\ \cline{1-3}\text{First Minimum} & \lambda / 2 & 0.112 \\ \cline{1-3} \text{First Maximum} & \lambda & 0.226\\\cline{1-3} \text{Second Minimum} & 3\,\lambda / 2 & 0.343\\ \cline{1-3} \text{Second Maximum} & 2\, \lambda & 0.466\end{array}\).
In each of these case, the distance between the microphone and \(P_0\) would be \(9.4\, \tan(\theta)\). Therefore:
At the first minimum, the distance from \(P_0\) is approximately \(1.1\; \rm m\).At the first maximum, the distance from \(P_0\) is approximately \(2.2\; \rm m\).At the second minimum, the distance from \(P_0\) is approximately \(3.4\; \rm m\).At the second maximum, the distance from \(P_0\) is approximately \(4.7\;\rm m\).Interference is the result when two or more waves combine
The distance between P₀ and
a. The first intensity minimum is approximately 1.06 m
b. The first intensity maximum is approximately 2.165 m
c. The second intensity minimum is approximately 3.36 m
d. The second intensity minimum is approximately 4.72 m
The reasons the above values are correct are given as follows:
The known parameters are;
The distance between the two speakers = 0.94 m
Frequency of the tone produced by the two speakers = 1,630 Hz (in sync)
The line along which the microphone moves is parallel to the line between the two speakers
The distance between the parallel lines above = 9.4 m
The speed of sound in air, v₀ = 344 m/s
The interference pattern of light passing between two slits is to be applied
a. Based on the arrangement, we have;
P₀ = 9.4 × tan(θ)
Where;
θ = The angle formed formed by the line from the microphone to the midpoint of the distance between the two speakers and the perpendicular bisector to the line joining the two speakers
Based on Young's double-slit experiment, we have;
\(sin(\theta) = \dfrac{Path \ difference}{d}\)
Where;
d = The distance between the two speakers representing the slits
The path difference for a minimum is n × λ/2
Where n = 1, 3, 5,...,(set of odd numbers)
The path difference for a maximum intensity sound is n·λ
Where n = 1, 2. 3, ..., n (n is an integer)
The wavelength, is given as follows;
\(\lambda = \dfrac{v}{f}\)
Therefore;
\(\lambda = \dfrac{344}{1,630} = \dfrac{172}{815} \approx 0.211\)
The wavelength, λ ≈ 0.211
Therefore, the angle, θ, for the first minima, θ, ≈arcsine(0.211/(2×0.94))
First minima, λ/2, P₀ =9.4 × tan(arcsine(0.211/(2×0.94))) ≈ 1.06
First maxima, λ, P₀ =9.4 × tan(arcsine(0.211/(94))) ≈ 2.165
Second minima, 3·λ/2, P₀ = 9.4 × tan(arcsine(3*0.211/(2×0.94))) ≈ 3.36
Second maxima, 2·λ, P₀ = 9.4 × tan(arcsine(2*0.211/(0.94))) ≈ 4.72
Therefore;
a. The distance between P₀ and the first intensity minimum is ≈ 1.06 m
b. The distance between P₀ and the first intensity maximum is ≈ 2.165 m
c. The distance between P₀ and the second intensity minimum is ≈ 3.36 m
d. The distance between P₀ and the second intensity minimum is ≈ 4.72 m
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In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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Fossil clues are one of the _____________ clues that support the theory of continental drift.
A. crust B. resource C. climate D. rock
Answer:
a
Explanation:
I think don't get mad if I'm wrong
If someone tells a friend that it is 75 degrees outside, that number represents the
Answer:
Temperature
Explanation:
Commonly when speaking about the temperature outside we will refer to it as --degrees Fahrenheit or Celsius. So if I were to tell my friend that it is currently 68 degrees outside, that would mean that the current temperature is 68 degrees Fahrenheit or Celsius outside.
-Hope this helped
In 7.0 s, a car accelerates uniformly from rest to a velocity at which its wheels are turning at 6.0 rev/s. If the tires of the car have a diameter of 42 cm, and they rolled on the ground without slipping, how far did the car go in those 7.0 s?
The car has traveled a distance of approximately 55.44 m.
In 7.0 s, a car accelerates uniformly from rest to a velocity at which its wheels are turning at 6.0 rev/s. If the tires of the car have a diameter of 42 cm, and they rolled on the ground without slipping, the car will travel a distance of approximately 50.9 meters in those 7.0 seconds.
To calculate the distance, we must first determine the car's final velocity. The angular velocity of the wheels is given by 6.0 rev/s. Since the diameter of the tires is 42 cm, the circumference is:πd = π(0.42 m) = 1.32 m. The velocity of the car can be calculated by multiplying the circumference by the angular velocity: v = 6.0 rev/s × 1.32 m/rev = 7.92 m/s.
Now that we know the final velocity of the car, we can use the formula:d = (vf + vi)t/2where vi = 0 m/s (since the car is initially at rest), vf = 7.92 m/s, and t = 7.0 sd = (7.92 m/s + 0 m/s)(7.0 s)/2 = 27.72 m. The car traveled approximately 27.72 m in the first half of the trip (from rest to the final velocity), and 27.72 m in the second half of the trip (from the final velocity to a complete stop).
Therefore, the total distance traveled by the car in those 7.0 s is approximately 27.72 m + 27.72 m = 55.44 m. However, this is the distance that the wheels have rolled, not the distance that the car has traveled. Since the wheels are not slipping, the distance that the car has traveled is equal to the distance that the wheels have rolled.
So, the car has traveled a distance of approximately 55.44 m. Rounding to the appropriate significant figures, the distance is approximately 50.9 meters.
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What normal force does a horizontal table exert on a 3.5 kg book that sits at rest?
Answer:
34.3N
Explanation:
The normal force, denoted by F(N), is the force exerted on an object by a surface. The normal force in this case is acting in an opposite manner but equal magnitude to the force of gravity.
F(N) = Fg
Where;
F(N) = Normal force
Fg = gravitational force
Fg = mg
Where;
m = mass (kg)
g = acceleration due to gravity
F(N) = mg
F(N) = 3.5kg × 9.8m/s²
F(N) = 34.3N
Hence, the normal force acting on the object is 34.3N.
QUESTION 3
Suppose you have a 100-kg wooden crate resting on a wood floor. Assume that the maximum force you can exert horizontally on the crate without moving it
is 588 N. If you continue to exert this force once the crate starts to move, what will be the magnitude of its acceleration (in m/s 22 Note: Use Table 5.1
in
Chapter 5 to determine the coefficient of friction for this problem.
Wood on wood static friction = 0.5
Wood on wood kinetic friction = 0.3
The force of frictions is opposed to relative motion.
The acceleration of the crate is approximately 2.937 m/s².
Reason:
The given parameters are;
The mass of the wood, m = 100 kg
The force which can move the wood, F = 588 N
Wood on wood static friction, \(\mu_s\) = 0.5
Wood on wood kinetic friction, \(\mu_k\) = 0.3
Solution;
The force of friction, \(F_f\), acting when the crate is moving is given as
follows;
\(F_f\) = m × g × \(\mu_k\)
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
Therefore, we have;
\(F_f\) = 100 × 9.81 × 0.3 = 294.3
The force of friction, \(F_f\) = 294.3 N
The force with which the crate moves, F = 588 - 294.3 = 293.7
The force with which the crate moves, F = 293.7 N
Force = Mass, m × Acceleration, a
\(a = \dfrac{F}{m}\)
Therefore;
\(a = \dfrac{293.7 \ N}{100 \ kg} = 2.937\)
The acceleration of the crate, a ≈ 2.937 m/s².
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Describe 2 ways in which a giant boulder by the ocean may change over time.
Answer:
I'm not sure if they're right but...
1. It would erode because of the water
2. It would probably become a home for the ocean creatures
The two (2) ways in which a giant boulder by the ocean may change over time are:
1. The ocean water would change the boulder's appearance and texture.
2. The giant boulder would be transformed into sediments due to erosion and weathering through dissolution.
A boulder can be defined as a large (giant) rounded mass of rock fragment that is formed through its detachment from a parent consolidated rock, especially due to erosion and weathering.
Basically, the size of a boulder is greater than 256 millimeters (25.6 centimeters or 10.1 inches) in diameter.
The reason why giant (large) boulders are present in steep mountain streams or oceans is mainly because they are usually too heavy for them to be moved by the body of water.
This ultimately implies that, water cannot move a giant (large) boulder that is present in an ocean because of its size and weight.
However, a giant (large) boulder that is present in an ocean would be affected in these two (2) ways:
Ocean water would change the boulder's appearance and texture. The giant boulder would be transformed into sediments due to the actions of erosion and weathering through dissolution.
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Which of the following is true at the point where you reach the top of your jump on a trampoline?
The mechanical energy is zero
he potential energy is at maximum
The kinetic energy and potential energy are equal.
The potential energy is zero.
The potential energy is at the maximum when you reach the top of your jump on a trampoline. The correct answer is option B.
What is Potential EnergyPotential Energy is the type of energy an object possesses by virtue of its position relative to others, stresses within itself, electric charge, and other factors. Potential energy exists in various forms, including gravitational potential energy, elastic potential energy, chemical potential energy, and electrical potential energy.
This type of energy can be converted into another type of energies. Examples, a charged battery has potential energy and it can be used as electrical potential energy. Petrol, diesel and and gas have chemical potential energy and be used as kinetic energy.
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Examine the boxes below. Both boxes are identical to one another. The mass of each box is concentrated in the very center, so the center of mass is in the
middle of the box. (Remember that mass is similar to weight) The arrows represent gravity pulling down on the center of mass of each box. Which of the boxes
represents a stable system? if you were to give that box a small push, what would happen to its state of equilibrium? Describe how a disturbance to this box
would affect it. Use the terms center of mass and equilibrium in your response.
Which correctly describes a different evolutionary stage of a star like the sun?
A) it’s forms from a cold, dusty molecular cloud
B) During a yellow giant stage, it burns carbon in its core and helium in the shell surrounding the core.
C) After leaving the main sequence, its core is stable due to electron degeneracy
D) It becomes a white dwarf after exploding as a supernova
E)During a red giant stage, its core contracts and cools
Answer:
Explanation:
The correct option that describes a different evolutionary stage of a star like the sun is:
D) It becomes a white dwarf after exploding as a supernova
This is because a star like the sun does not have enough mass to undergo a supernova explosion. After it has exhausted all the fuel in its core, it will evolve into a red giant and then a planetary nebula, leaving behind a small, hot, dense remnant known as a white dwarf. Supernovae occur in much more massive stars that have cores that can collapse to form a neutron star or black hole.
A pet store surveyed 625 people to see how many own a bird, how many own a dog, and how many own a cat.
The Venn diagram below shows the results. (Each number gives the number of people who fall into that Venn diagram category.)
All people in the survey-
Own a
bird
Own a
dog
115
103
49
138
61
33
34
Own a
cat
92
(a) How many of the people own exactly two of the three types of animals?
people
(b) How many of the people don't own a dog?
people
(c) How many of the people own neither a cat nor a bird, but do own a dog?
people.
The people who own all the three animals are 33 , (b) People who don't own a dog are 244 and (c) People who neither own a cat nor a bird but own a dog are 34 in number.
What is a Venn diagram?A Venn diagram is a representation of data in terms of figure. Where each circle represents a set of data, intersection of two or more circles shows that there is a common entity in both the sets.
What is a universal set in Venn diagram?A universal set contains all the possible elements. In Venn diagram a universal set is represented by a rectangle.
Given:
Total number of the people surveyed = 625
People who one a cat = 115
People who own a bird = 103
People who own a dog = 34
1) To find the number of people who own all the three animals we will have to find the intersection of C, B and D.
Where,
C represents set of cat
B represents set of bird
D represents set of dog
// Represents intersection
:: Represents union
From the given data
C//B//D = 33
i.e. people who own all the three animals = 33
2) People who don't own a dog.
Now carefully look at the given diagram you will notice:
34 own D only
138 own D and C
92 own D and B
33 own all the three
Now to find who doesn't own a dog we will find who owns a dog and then minus that from total people who owns animals.
Total people who own an animal= (115+103+34+138+61+92-2×33)
Total people who own an animal = 475
Now people who own a dog = 34+138+92-33
People who own a dog = 231
People who don't own a dog = 475-231
People who don't own a dog = 244
3) People who neither own a cat nor a bird but own a dog = 34
Therefore, the people who own all the three animals are 33 , People who don't own a dog are 244 and People who neither own a cat nor a bird but own a dog are 34 in number.
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