Two units of magnetic field named after famous Western scientists are Weber and Gauss.
In electromagnetism, the magnetic field is a vector field that represents the magnetic effects of electric charges in motion. The magnetic field is defined as a field in which an electric charge will experience a magnetic force. It is produced by electric charges and currents. A magnetic field is created by a magnet or a moving electric charge or other magnetic fields.
The strength of a magnetic field is determined by the number of magnetic field lines or magnetic fluxes that pass through a surface placed perpendicular to the direction of magnetic field lines. It is calculated in the unit of Tesla (T). In addition to Tesla, there are two other units of magnetic field named after famous Western scientists: Gauss and Weber. A magnetic field with a strength of one gauss is equivalent to one ten-thousandth (0.0001) of a Tesla.
Gauss is a unit of magnetic flux density and is named after the famous German mathematician Carl Friedrich Gauss. Weber is named after Wilhelm Eduard Weber, and it is a unit of magnetic flux. The Weber is equivalent to the magnetic flux that crosses one square meter of surface area at right angles to a magnetic field of one tesla.
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Which of the following is not an acid? A. HCI B. H2SO4 C.HNO3 D. NaOH
Answer:
NaOH
Explanation:
oxide of a non-metal element is acidic. Na is metal. so NaOH is basic.
Answer:
d is the answer
Explanation:
Swimming in a pool requires that you push back on the water in order to go
forward.
Newton's 1st Law
Newton's 2nd Law
Newton's 3rd Law
Law of Universal Gravitation
Law of Conservation of Momentum
Swimming in a pool requires that you push back on the water in order to go forward is Newton's 3rd Law.
What is Newton's 3rd Law?
Newton's 3rd Law, also known as the law of action and reaction, states that for every action, there is an equal and opposite reaction. This means that if an object A exerts a force on object B, then object B will exert an equal and opposite force on object A.
For example, if you push against a wall, the wall will push back on you with the same force in the opposite direction. This is because every force is a result of an interaction between two objects, and each object exerts an equal and opposite force on the other.
This law is important in understanding how objects interact with each other and is fundamental to many areas of physics, including mechanics, fluid dynamics, and electromagnetism.
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. A boy wishes to make a catapult out of a rubber band of width 9mm and thickness 1.55mm. Determine the length of the band that he must use so that when he stretches it by 0.25 of its natural length and releases it the velocity of pebble of mass 0.006kg will be 30m/s. Take young modulus of the rubber to be 4×10^7 N/m^2
The length of the rubber band that the boy must use is 0.024 m or 24 mm.
What will be the length of the rubber required?To determine the length of the rubber band, we can use the formula for the potential energy stored in a stretched spring, which is also applicable to a stretched rubber band:
U = 1/2 kx²where U is the potential energy stored in the rubber band, k is the spring constant (or in this case, the rubber band constant), and x is the displacement of the rubber band from its natural length.
Since the rubber band is stretched by 0.25 of its natural length, the displacement x is 0.25 times the natural length of the rubber band.
We can solve for the rubber band constant k by using the formula for the velocity of a projectile launched by a spring (or in this case, a rubber band):
v = √(2mk/M)where v is the velocity of the projectile, m is the mass of the rubber band, M is the mass of the projectile, and k is the spring constant. We can rearrange this equation to solve for k:
k = (v² M) / (2 m)
We can now combine the two equations to solve for the length of the rubber band, L:
U = 1/2 k x²
U = 1/2 ((v² M) / (2 m)) (0.25 L)²
U = (v² M L²) / (32 m)
The potential energy stored in the rubber band must be equal to the kinetic energy of the projectile when it is launched:
U = 1/2 M v²
(v² M L²) / (32 m) = 1/2 M v²
L = ((16 m v²) / (k M))
L = ((16 m v²) / ((v² M) / (2 m) M))
L = √(32 m^2 / M)
L = (0.032 M)
Substituting the given values, we get:
L = √(0.032 * 0.006)
L = 0.024 m
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When a car is going at a constant velocity down the freeway, is the net force zero or not zero assuming no friction?
Answer:
Zero
Explanation:
The net force acting on an object moving with constant velocity is zero. This is an accordance with the Newton's first law of motion.
Newton's first law of motion states that a body will continue in its state of rest or constant motion unless it is acted upon by an external force.
Since this body is moving with uniform motion, it is not accelerating. When a body is acceleration, the net force on it is not zero.
But this one is moving with uniform motion. The net force on the body is balanced and zero.
What happens to the temperature of a substance while it is changing state?
A. It increases first and then decreases.
B. It decreases first and then remains constant.
C. It varies randomly.
D. It remains constant.
Answer:
During a phase change, the temperature will remain constant. Obviously all the heat is used in phase transformation. So the correct answer should be D. Forgive me if I'm wrong but I hope this helps!
The temperature of a substance remains constant while it is changing state. Thus, the correct option is D.
What is the relation between state and temperature of substance?Temperature has a direct effect on whether a substance exists in states as a solid, liquid, or gaseous substance. Substances can change their phase often because of a temperature change of the substance. At very low temperature conditions, most of the substances are solid, as the temperature of the substance keeps on increasing, then they become liquid and at very higher temperatures still, they become gaseous substances.
The temperature of a substance remains constant while it is changing its state.
Therefore, the correct option is D.
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. an object is located 14.5 cm in front of a convex mirror, the image being 7.10 cm behind the mirror. a second object, twice as tall as the first one, is placed in front of the mirror, but at a different location. the image of this second object has the same height as the other image. how far in front of the mirror is the second object located?
An object is located 14.5 cm in front of a convex mirror. The image is 7.10 cm behind the mirror. A second object, twice as tall as the first one, is placed in front of the mirror, but at a different location. The image of this second object has the same height as the other image. The second object is located 10.48 cm in front of the mirror.
The formula to calculate the location of an object in front of the convex mirror is as follows
1/f = 1/v + 1/u
where f is the focal length of the mirror, v is the image distance from the mirror, and u is the object distance from the mirror.
The image distance of the first object is given as 7.10 cm behind the mirror; therefore, the object distance from the mirror is 14.5 cm + 7.10 cm = 21.60 cm.
The height of the second object is twice that of the first object; therefore, its image height must also be twice the image height of the first object.
Since the image height of the first object is unknown, we will assume it to be h.
Substituting the values in the formula gives 1/f = 1/v + 1/u
1/f = 1/7.10 + 1/21.60
where u is the object's distance from the mirror
We can solve for f as follows 1/f = 1/7.10 + 1/21.60
1/f = 0.1975f = 5.06 cm
The focal length of the mirror is 5.06 cm.
Substituting the focal length of the mirror in the formula gives 1/5.06 = 1/7.10 + 1/u
Solving for u gives 1/u = 1/5.06 - 1/7.10
1/u = (7.10 - 5.06) / (5.06 * 7.10)
u = 10.48 cm
Therefore, the location of the second object in front of the mirror is 10.48 cm.
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A 0.311 kg tennis racket moving 30.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 19.2 m/s east. Find the velocity of the tennis racket after the collision.
A converging lens forms a real image of an object. if magnification is 2 and the distance between the image and the object is 90.0cm; determine the
(i) Focal length of the lens
(ii) Distance for which the image would be the same size as the object.
(I) The focal length of the lens is 180.0 cm.
(II) The distance for which the image would be the same size as the object is 90.0 cm.
What is the focal length of the lens?We can use the lens equation and the magnification formula to solve for the focal length of the lens and the distance for which the image would be the same size as the object.
The lens equation is:
1/f = 1/do + 1/di
where;
f is the focal length of the lens, do is the distance between the object and the lens, and di is the distance between the image and the lens.We are given that the distance between the image and the object is 90.0 cm and the magnification is 2. The magnification formula is:
m = - di/do
where;
m is the magnification.Substituting these values into the magnification formula, we get:
2 = - di/do
di = -2do
Substituting these values into the lens equation, we get:
1/f = 1/do - 1/2do
Simplifying this equation, we get:
1/f = 1/2do
f = 2do
Substituting the given value of di, we get:
f = 2(-90.0 cm) = -180.0 cm
Since the focal length must be positive for a converging lens, we take the absolute value and get:
f = 180.0 cm
(ii) Distance for which the image would be the same size as the object:
When the image is the same size as the object, the magnification is 1. We can use the magnification formula to solve for the distance di:
m = - di/do
1 = - di/do
di = -do
Substituting the given value of do, we get:
di = -90.0 cm
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The print on the package of 100-watt Wave Electric light bubs states that these bulbs have an average life of 750 hours. Also assume that the lives of all such bulbs have a normal distribution with standard deviation of 50 hours. How many bulbs in a consignment of 700 could be expected to have a life of 710 to 830 hours? 0.7333 0.1571 513 955 110
Option c is correct. Approximately 513 bulbs in the consignment can be expected to have a life between 710 and 830 hours.
For solving this problem, need to calculate the z-scores for the given range of bulb lives and then use these z-scores to find the corresponding probabilities from the standard normal distribution table.
The z-score can be calculated using the formula:
z = (x - μ) / σ,
where x is the value, interested in, μ is the mean, and σ is the standard deviation. In this case, the mean (μ) is 750 hours and the standard deviation (σ) is 50 hours.
For a life of 710 hours:
z = (710 - 750) / 50 = -0.8
For a life of 830 hours:
z = (830 - 750) / 50 = 1.6
Next, look up the probabilities associated with these z-scores in the standard normal distribution table. The probability associated with a z-score of -0.8 is 0.2119, and the probability associated with a z-score of 1.6 is 0.9452.
For finding the number of bulbs expected to have a life between 710 and 830 hours, calculate the difference between these probabilities:
0.9452 - 0.2119 = 0.7333
Therefore, approximately 0.7333 * 700 = 513 bulbs in the consignment can be expected to have a life between 710 and 830 hours.
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Consider the three electronic transitions in hydrogen atom shown here, labeled A; B, and C (a) Three electromagnetic waves all drawn on the same scale; are also shown_ Each corresponds t0 one of the transitions_ Which electromagnetic wave (i) , (ii) ; or (iii) , is associated with electronic transition C? Je" ! 2 ] U = -218 (b) Calculate the energy of the photon emitted for each transition. Calculate the wavelength of the photon emitted for each transition. Do any of these transitions lead to the emission of visible light? If sO which one(s)?
Electronic transition C is associated with electromagnetic wave (iii). Calculate the energy of the photon emitted for each transition, we can use the equation E = hf
Transition A: E = hf = (6.63 x 10^-34 J·s) * (6.5 x 10^14 Hz) = 4.29 x 10^-19 J
Transition B: E = hf = (6.63 x 10^-34 J·s) * (3.5 x 10^14 Hz) = 2.33 x 10^-19 J
Transition C: E = hf = (6.63 x 10^-34 J·s) * (2.5 x 10^14 Hz) = 1.66 x 10^-19 J
To calculate the wavelength of the photon emitted for each transition, we can use the equation λ = c/f, where λ is the wavelength, c is the speed of light (3.0 x 10^8 m/s), and f is the frequency of the electromagnetic wave associated with the transition.
Transition A: λ = c/f = (3.0 x 10^8 m/s) / (6.5 x 10^14 Hz) = 4.62
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when you ride your scooter you have momentum When you ride twice as last you have Select one: a.almost twice the momontum- b.nonc ol the above c.twice the momentum d. four times the momentum
When you ride your scooter, you have momentum which is determined by your mass and velocity. Momentum is a vector quantity, meaning it has both magnitude and direction.
When you ride twice as fast, you have twice the velocity, which results in a change in momentum.The relationship between velocity and momentum is direct. Therefore, when you ride twice as fast, you have twice the momentum. This means that the correct answer is option c. You will have twice the momentum when you ride twice as fast on your scooter.It is important to note that momentum is conserved in a closed system, which means that the total momentum before and after the event remains the same.
Therefore, if you were to ride your scooter into a wall, your momentum would be transferred to the wall, causing you to stop abruptly. When you ride your scooter, you have momentum. Momentum is the product of an object's mass and velocity (p = mv). If you ride twice as fast, your velocity doubles. In this case, your momentum also doubles, since the mass remains the same. Therefore, the correct answer is c. twice the momentum.
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How harmful are the emissions from cosmetics, hygiene, and cleaning products? Claim
Evidence 1
Evidence 2
Evidence 3
Reasoning
The claim can be Cosmetics, hygiene, and cleaning product emissions may be dangerous.
Evidence 1: Effect of Air Quality
Volatile organic compounds (VOCs), including formaldehyde, benzene, and toluene, can be found in a variety of cosmetic, hygiene, and cleaning goods. These VOCs have the potential to evaportate and cause indoor air pollution.
Environmental impact is evidence number two
Cosmetics, hygiene, and cleaning goods can have a detrimental environmental impact during manufacturing, usage, and disposal. Microplastics and certain chemicals are among the substances present in these items that may find their way into rivers and endanger aquatic life.
Evidence 3: Worker health effects
Occupational health risks can be present for workers who manufacture and produce hygiene, cleaning, and cosmetic items.
Reasoning: It is clear from the research that emissions from cosmetic, hygiene, and cleaning goods have the potential to be harmful.
Thus, this way, harmful are the emissions from cosmetics, hygiene, and cleaning products.
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How can the Earth’s movement be explained?
A The Earth cannot spin on its axis and orbit around the Sun at the same time.
B Earth moves one revolution and then moves one rotation around the Sun.
C The Earth spins on its axis, and it orbits around the Sun at the same time.
D Earth stops every one-fourth of a year to shift its axis towards the Sun.
Answer:
C)
Explanation:
Earth's Rotation
Earth spins around its axis, just as a top spins around its spindle. This spinning movement is called Earth's rotation. At the same time that the Earth spins on its axis, it also orbits, or revolves around the Sun. This movement is called revolution.
Until a train is a safe distance from the station it must travel at 5 m/s. Once the train is on open track it can speed up
to 45 m/s. If it takes a train 8 seconds to reach 45 m/s, what is the acceleration of the train? (Round your answer to
the nearest whole number.)
O 4 m/s2
O 5 m/s2
O 6 ms2
7 m/s2
Answer:
I believe the answer is b
Explanation:
spheres a and b are identical in size and made from the same conducting material. sphere a is attached to an insulating rod, and sphere b is suspended from an insulating thread. sphere a initially has a charge of 10 nc, and sphere b is initially uncharged. question which of the following best represents the distribution of charge on the surfaces of spheres a and b when sphere a is brought near sphere b?
The two metal spheres will reach their equal potential when they come into contact. Additionally, when the metal spheres have the same radius, the identical potential results in the same charges.
The charge distribution at each phase will now be as follows:
Initial values are: A=+6q B=-3q C=0.
A=+1.5q B=+1.5q C=0 Spheres A and B touched and separated. When two spheres touch, charges will be divided equally and the overall charge will be preserved.
After touching, A increases by 0.75q, B increases by 1.5q, and C increases by 0.75q (same logic as above)
When C and B are touched, A = +0.75q, B = +1.125q, and C = 1.125q.
So, qc=+1.125q will be the ultimate charge on sphere C.
Generally speaking, potential describes a skill that is still being developed. The term is used in a wide range of disciplines, from physics to the social sciences, to describe objects that are in a state where they have the capacity to change in a variety of ways, from the straightforward release of energy by objects to the realization of abilities in people.
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A ball weighing 20 newtons rolls 20 meters in a straight line on a leve surface. What is its change in potential energy?
A 0J
B 1J
C 40J
D 400 J
Answer:
A
Explanation:
Potential energy = m g h unless h changes there is zero PE change
The wavelengths of visible light vary from about 300 nm to 700 nm. what is the range of frequencies of visible light in a vacuum?
a) 90 hz to 210 hz
b) 9*10^10 hz to 2.1*10 hz
c) 4.28*10^5 hz to 1*10^6 hz
d) 4.29*10^14 hz to 1*10^15 hz
The range of frequencies of visible light in a vacuum with wavelength between 300 nm to 700 nm is determined as 4.29 x 10¹⁴ Hz to 1 x 10¹⁵ Hz.
Frequency of the visible light
The frequency of the visible light is determined by using the following formulas relating speed of light and frequency of light.
c = fλ
where;
c is speed of lightf is frequency of lightλ is the wavelengthFrequency of light at 300 nm wavelengthf = c/λ
f = (3 x 10⁸) / (300 x 10⁻⁹)
f = 1 x 10¹⁵ Hz
Frequency of light at 700 nm wavelengthf = c/λ
f = (3 x 10⁸) / (700 x 10⁻⁹)
f = 4.29 x 10¹⁴ Hz
Thus, the range of frequencies of visible light in a vacuum with wavelength between 300 nm to 700 nm is determined as 4.29 x 10¹⁴ Hz to 1 x 10¹⁵ Hz.
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What is the momentum of a 45 kg object that travels a distance of 45m in 9 seconds?
Speed:-
\(\\ \rm\rightarrowtail Speed=\dfrac{45}{9}=5m/s\)
Momentum:-
\(\\ \rm\rightarrowtail 45(5)\)
\(\\ \rm\rightarrowtail 225kgm/s\)
is an essential nutrient that makes up more than 50 percent of your body weight
Answer:water
Explanation:
Water may be a nutrient that makes up 60% of our body weight. it's important in many functions, it's part of every cell in every tissue in the body.
Water carries other nutrients to all or any parts of the body, it carries waste out of the body and it helps to manage body temperature. When you run or play sports your body heats up pretty quickly.
Your body starts to sweat as a way to get rid of the heat. When the sweat evaporates on your skin your body and blood get cool. it's very important to replace the fluid that is lost by sweating so as not to become dehydrated.
If you get dehydrated the body cannot cool itself anymore and your performance will drop. Without enough water, whether you're exercising or sitting all day, you're at risk for dehydration which can be fatal
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Which of the following has the longest wave length and the lowest frequency
A.infrared waves
B.radio waves
C.x-ray waves
D.microwaves
Answer:
B. radio waves
Explanation:
Trust me It's correct
An ideal gas is enclosed in a piston-cylinder apparatus with the piston being freely movable. Given that LaTeX: \DeltaΔE is positive and LaTeX: \DeltaΔH is negative following a process, ____ the system absorbs heat and expands during the process. the system absorbs heat and contracts during the process. the system loses heat and expands during the process. the system loses heat and contracts during the process. the system loses heat but neither expands nor contracts during the process.
Clear question is;
An ideal gas is enclosed in a piston-cylinder apparatus with the piston being freely movable. Given that ΔE is positive and ΔH is negative following a process,
pick one
A) the system absorbs heat and expands during the process.
B) the system absorbs heat and contracts during the process.
C) the system loses heat and expands during the process.
D) the system loses heat and contracts during the process.
E) the system loses heat but neither expands nor contracts during the process.
Answer:
Option A is correct.
Explanation:
In thermodynamics, when the change in energy which is ΔE of a system is positive, it means that the system is undergoing an endothermic process. An endothermic process is simply one where heat is absorbed from the surroundings
Now, when change in enthalpy which is ΔH is negative, it means that it's an exothermic reaction. Exothermic means it releases heat to the surroundings. This means work is positive because the system does work on the surroundings. Thus it will expand.
So the correct answer is;
heat is absorbed from the surroundings and will expand during the process.
Please help me with this question
centripetal acceleration cannot change
of the following, which is the largest compartment for carbon in earth's system
The largest compartment for carbon in Earth's system is the deep ocean, specifically the deep-sea sediments.
These sediments contain vast amounts of organic and inorganic carbon that has accumulated over millions of years.
The amount of carbon stored in these sediments is estimated to be on the order of 40,000 billion metric tons, which is several times more than the amount of carbon stored in the atmosphere, land plants, and soils combined.
The deep ocean plays an important role in the global carbon cycle, as it serves as a long-term storage reservoir for carbon and helps to regulate the concentration of carbon dioxide in the atmosphere over long timescales.
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Hello all, can you please answer this? I am struggling with this. I need this by tommorow. Question is below:
Light waves of frequency 6 x 10^14 Hz have a wavlength of 3.75 x 10^-7 m in water. What is their speed in water?
\(c_{water} = 2.25\times 10^{8}m/s\)
Explanation:
The speed of light in any medium is given by
\(c = \lambda \nu\)
where \(\lambda\) is the wavelength and \(\nu\) is the frequency. In water,
\(c_{water} = \lambda_{water} \nu\)
\(\:\:\:\:\:\:\:\:= (3.75\times 10^{-7}\:m)(6\times 10^{14})\:Hz\)
\(\:\:\:\:\:\:\:\:= 2.25\times 10^{8}\:m/s\)
of all the types of light the sun gives off, it emits the greatest amount of light at visible light wavelengths. if the sun were to cool off dramatically and as a result start giving off mainly light at wavelengths longer than visible light, how would the frequency, energy, and speed of this light given off by the sun also be different? explain your reasoning.
If the sun starts giving off mainly light at longer wavelengths than visible light, the frequency of light would decrease, and the energy of light would also decrease. This means that the light would have less energy than visible light. The speed of light, however, would remain constant, which is 299,792,458 meters per second.
The sun is a star, which is a giant ball of gas that produces light through nuclear fusion. Light is an electromagnetic wave that has a range of wavelengths and frequencies. The wavelengths of light are different and correspond to different colors. The visible light spectrum is the range of wavelengths that are visible to the human eye, and they are the colors that we see. If the sun were to cool off dramatically and as a result start giving off mainly light at wavelengths longer than visible light, the frequency, energy, and speed of this light given off by the sun would be different.
The frequency of light is the number of waves that pass a given point in a second, and it is measured in Hertz (Hz). The energy of light is directly proportional to its frequency. This means that if the frequency of light increases, its energy also increases. The speed of light is a constant and is measured as 299,792,458 meters per second. The frequency and energy of light would both drop if the sun began emitting light mostly at longer wavelengths than visible light.
The light would therefore be less energetic than visible light. Yet, the speed of light, which is 299,792,458 metres per second, would not change.
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Which of the following statements about the implications of Hubble's Law is FALSE?although galaxies move away from each other, they themselves are not expanding in sizeif you were observing the universe from a distant galaxy, you would NOT see all the galaxies (except those in your own group) moving away from YOUthe law implies that the whole universe must be expandingthe law can be used to measure distances to remote galaxies for which we can measure a Doppler shiftthe law does NOT require us to be at the center of the expanding universe
After considering all the statements about the implications of Hubble's Law, the false statement is not present.
The first statement is that although galaxies move away from each other, they themselves are not expanding in size. This statement is true. Hubble's Law states that the distance between galaxies is increasing over time, but it does not imply that the galaxies themselves are expanding in size. Instead, the expansion of the universe is causing the space between the galaxies to stretch out.
The second statement is that if you were observing the universe from a distant galaxy, you would not see all the galaxies (except those in your own group) moving away from you. This statement is also true. Hubble's Law applies to the large-scale structure of the universe, and the motion of individual galaxies within a group or cluster can be influenced by other factors such as gravity. So if you were in a distant galaxy, you would not see all other galaxies moving away from you due to these local effects.
The third statement is that the law implies that the whole universe must be expanding. This statement is true. Hubble's Law provides evidence that the universe is expanding uniformly in all directions, which suggests that the expansion is happening on a global scale rather than being caused by some local effect.
The fourth statement is that the law can be used to measure distances to remote galaxies for which we can measure a Doppler shift. This statement is also true. Hubble's Law relates the distance between galaxies and their recessional velocity, which can be measured using the Doppler shift of their light. By measuring the redshift of light from a distant galaxy, we can determine how fast it is moving away from us and use this information to estimate its distance.
Finally, the fifth statement is that the law does not require us to be at the center of the expanding universe. This statement is true. Hubble's Law is based on the observation that all galaxies are moving away from each other, regardless of their location in the universe. This means that there is no special point in the universe that can be considered the "center" of the expansion.
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Much like scientists study cause and effect, firefighters and fire investigators observe the effects of a fire and try to find out its cause. Read the following example:
An office building caught fire early one morning, just as people were coming to work. Something caused the fire, and fire investigators need to collect data to determine what did it. Place a checkmark next to the data that could be related to the fire in this office building and could help them determine its cause:
A light switch with worn electrical wiring was found on the third floor.
Gasoline was stored in the basement of the building.
The building is in the downtown area of a big city.
It took firefighters 45 minutes to put out the fire.
The fire started on the third floor of the building.
People coming to work turned on the lights in the building.
People smoking in bed can start fires.
Oily rags were kept in an open container on the first floor.
The data that could be related to the fire in the office building and help determine its cause are: a light switch with worn electrical wiring found on the third floor, the fire started on the third floor of the building, and oily rags were kept in an open container on the first floor. Option 1, 5 and 8 are correct.
Fire investigators collect data to determine the cause of a fire. In this example, the fire started on the third floor of the building, and a light switch with worn electrical wiring was found on the same floor. This data suggests that the fire could have been caused by an electrical issue. Additionally, oily rags were kept in an open container on the first floor, which could have potentially contributed to the spread of the fire.
The fact that gasoline was stored in the basement or that the building is located in a downtown area may not be directly related to the cause of the fire. The time it took firefighters to put out the fire and people smoking in bed are also not directly relevant to the cause of the fire in this specific building. Option 1, 5 and 8 are correct.
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Answer: Correct answers is 1, 2, 4, 5, 6, and 8
Explanation: A light switch with worn electrical wiring was found on the third floor. Gasoline was stored in the basement of the building. It took firefighters 45 minutes to put out the fire. The fire started on the third floor of the building. People coming to work turned on the lights in the building. Oily rags were kept in an open container on the first floor. All these choices are a possible cause for the fire, including the time the firefighters took to put the fire out.
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in 2004 a blazar of 10 billion solar masses was discovered at a distance of 12.5 billion ly. what was particularly intriguing about this discovery?
what was particularly intriguing about the discovery of the blazar of 10 billion solar masses at a distance of 12.5 billion ly in 2004 was that it challenged the existing theories of how such massive objects form and evolve in the universe.
Blazars are a type of active galactic nuclei that emit intense radiation across the entire electromagnetic spectrum, including gamma rays, X-rays, and radio waves. They are powered by supermassive black holes that are millions to billions of times more massive than the sun. However, the discovery of a blazar with a mass of 10 billion solar masses at such a large distance was unexpected and raised questions about the formation and growth mechanisms of supermassive black holes.
According to current theories, supermassive black holes can grow by accreting matter from their surrounding regions or by merging with other black holes. However, the formation of such a massive object within a relatively short period of time, considering the age of the universe, is difficult to explain. Therefore, this discovery has provided new insights into the formation and evolution of supermassive black holes and their associated blazars.
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The direction of an electric field is the direction of the force exerted on: a molecule. a neutral test charge. an electron. a proton. an atom.
The direction of an electric field is the direction of the force exerted on a positive test charge. Therefore, the statements that the direction of an electric field is the direction of the force exerted on a molecule, a neutral test charge, an electron, a proton, or an atom are all false.
An electric field is a region in which electric forces are exerted on charged particles. The direction of the electric field is defined as the direction of the force experienced by a positive test charge placed in the field. The force experienced by a charged particle depends on the charge of the particle and the direction of the electric field.
A molecule may or may not have an overall charge, so the force experienced by a molecule will depend on its specific charge distribution, and it is not necessarily aligned with the direction of the electric field.
A neutral test charge has no charge, so it does not experience any force in an electric field.
Electrons and protons are charged particles, and they experience a force in the direction opposite to the direction of the electric field. The force on an electron is in the opposite direction of the electric field, while the force on a proton is in the same direction as the electric field.
An atom is composed of positively charged protons, negatively charged electrons, and neutral neutrons. The net force on an atom will depend on the overall charge distribution and is not necessarily aligned with the direction of the electric field.
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A factory line moves parts for an automobile at a constant speed of 0.22 m/s. How long does it take the parts to move 8.5 m along the line? A. 1.9 s B. 12 s C. 39 s D. 56 s
Answer: C. 39 s
Explanation:
We know the constant speed is 0.22 m/s. We have to get to 8.5 m. We divide 8.5 m by 0.22 = 38.6. After we estimate, 6 is greater than 5, so 39 s.